delete the consecutive occurrence of string

version: Oracle Database 11 g Enterprise Edition Release 11.2.0.3.0 - 64 bit Production

Hi I want to do, remove the consecutive occurrence of string

Example I/P: 'POWELL POWELL BRIAN K AND BONNIE POWELL JARRELL JARRELL'
to O/P : 'POWELL BRIAN K AND BONNIE POWELL JARRELL'
I tried the code below works fine, but I wanted to do this by using the Regexp or any other method better
WITH T
       AS (    SELECT   LEVEL RN,
                        REGEXP_SUBSTR (
                           'POWELL POWELL BRIAN K AND BONNIE POWELL JARRELL JARRELL',
                           '[^ ]+',
                           1,
                           LEVEL
                        )
                           NAME
                 FROM   DUAL
           CONNECT BY   LEVEL <=
                           LENGTH(REGEXP_REPLACE (
                                     'POWELL POWELL BRIAN K AND BONNIE POWELL JARRELL JARRELL',
                                     '[^[:space:][:punct:]]*'
                                  ))
                           + 1)
SELECT   LISTAGG (NAME, ' ') WITHIN GROUP (ORDER BY Rn) AS name
  FROM   (SELECT   RN, NAME, LEAD (NAME, 1, 0) OVER (ORDER BY RN) Lead_name
            FROM   T)
 WHERE   name != lead_name;

Hello

1006112 wrote:
Hello
The solution does not work for this channel.

SELECT REGEXP_REPLACE ('ZHOU JIANCHUAN AND ESTABROOK- ZHOU DESIREE ','([^ ]+)( \1)+', '\1') Word1,
regexp_replace('ZHOU JIANCHUAN AND ESTABROOK- ZHOU DESIREE', '(\w+)(\W+\1)+', '\1')Word1,
regexp_replace('ZHOU JIANCHUAN AND ESTABROOK- ZHOU DESIREE', '(\w+\W+)\1+', '\1')Word3
from dual ;

SELECT REGEXP_REPLACE ('STATTELMAN J J JR AND MARGAR ','([^ ]+)( \1)+', '\1') Word1,
regexp_replace('STATTELMAN J J JR AND MARGAR', '(\w+)(\W+\1)+', '\1')Word1,
regexp_replace('STATTELMAN J J JR AND MARGAR', '(\w+\W+)\1+', '\1')Word3
from dual

Your original solution looking better all the time! This problem is more complicated than I thought.
It is probably more effective than CONNECT BY:

SELECT    TRIM ( REGEXP_REPLACE ( REGEXP_REPLACE ( ' ' || REPLACE ( str
                                                             , ' '
                                          , '  '
                                          )
                                     || ' '
                                      , ' ([^ ]+)( +\1)+ '
                                , ' \1'
                               )
                    , ' +'
                    , ' '
                     )
            )     AS no_consecutive_dups
FROM      table_x
ORDER BY  str
;

I tested it using this table:

CREATE TABLE  table_x
(   str     VARCHAR2 (80)
);

INSERT INTO  table_x (str) VALUES ('POWELL    POWELL BRIAN K AND BONNIE POWELL JARRELL JARRELL');
INSERT INTO  table_x (str) VALUES ('ZHOU JIANCHUAN AND ESTABROOK- ZHOU DESIREE ');
INSERT INTO  table_x (str) VALUES ('STATTELMAN J J JR AND MARGAR');
INSERT INTO  table_x (str) VALUES ('DO DO SOL SOL LA LA SOL');

Output:

NO_CONSECUTIVE_DUPS
--------------------------------------------------------------------------------
DO SOL LA SOL
POWELL BRIAN K AND BONNIE POWELL JARRELL
STATTELMAN J JR AND MARGAR
ZHOU JIANCHUAN AND ESTABROOK- ZHOU DESIREE

It compresses the spaces; in other words, the original str can contain multiple consecutive spaces or spaces main and/or end, but the output will not.
Here's how it works:
The REGEXP_REPLACE at the heart of this solution search a sequence that begins and ends with a space. otherwise, he'll be fooled by things like "J J JR", where the "J" in "JR" could be confused with a 3rd 'J '. However, this means that a single space between two recurring motifs in 'DO DO GROUND GROUND' can only mark the end of "DOING" pattern or the Spiderbeam of the 'GROUND FLOOR' trend, but not both. The above query that bypasses by replacing all the spaces with 2 spaces, so space may mark the end of 'DOING' and the other may mark the beginning of "GROUND FLOOR".

Tags: Database

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    Patient

    Patient portal page

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    Edited by: 1001076 on 28 may 2013 18:42

    Handle: 1001076
    Status level: Beginner
    Join date: April 18, 2013
    Messages total: 12
    Total Questions: 4 (3 pending)

    I offer you my condolences; Since you rarely get your questions answered here.

  • Deleting the same files of many virtual machines remotely

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    foreach ($nic as $_.) Guest.Nics) {}
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    }
    }
    foreach ($i in $a)
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    }

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    Thank you very much!

    Best regards

    To solve the problem with the quotes, you can use double quotes inside the string. Like this:

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    I need to display a series of words consecutively on a black background. A new Word presented whenever you press the Enter key (it is necessary that it is the same key IE each time the Enter key). The words are arranged in a table. I created a function for each button press and a listener. Also, as the previous word is replaced by the following, I have a removeChild() to get rid of the the last word.

    I have a set removeEventListener in place too, to avoid problems with listeners. To this, I've been long without success. It must be an earpiece problem (IE I do not have the doors correctly listeners?) or a display problem. It always shows only one. Please find below the code for the display of two of the words in the table called cvcwords. The main problem is that the words are not displayed one after the other (actually not at all, except for the first) when you press the Enter key. Very much as a powerpoint presentation, that's the idea anyway. I have just a sample of the code below. any help appreciated.

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    this. stage.addEventListener (KeyboardEvent. ) KEY_DOWN, modKeyDown);

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    if (e.keyCode is keyboard. ( ENTER) {

    removeChild (myText);               / / to remove back Word of screen

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    addChild (myText);

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    myText.text = "try again";

    addChild (myText);

    this. stage.removeEventListener (KeyboardEvent. ) KEY_DOWN, modKeyDown);

    }

    }

    this. stage.addEventListener (KeyboardEvent. ) KEY_DOWN, hudKeyDown);

    Function hudKeyDown (e: KeyboardEvent): void {}

    if (e.keyCode is keyboard. ( ENTER) {

    removeChild (myText);  to delete the previous word of the screen

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    addChild (myText);

    } else If (e.keyCode == keyboard. ) SPACE) {}

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    addChild (myText);

    this. stage.removeEventListener (KeyboardEvent. ) KEY_DOWN, hudKeyDown);

    }

    }


    From what I see of your code, the following is everything you need...

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    var count: int = 0;

    stage.addEventListener (KeyboardEvent.KEY_DOWN, modKeyDown);

    function modKeyDown(e: KeyboardEvent): void {}
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    counter ++;
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    Hello

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    If present, then rename it and create another directory with the original name.

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    Fabien

    try adding a space after the run.bat. It is a common mistake when trying dynamic query in a string, so always print your final string on the screen or elsewhere to see if the syntax is correct.

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  • Cannot delete the row

    Hello

    I am trying to implement page 664 of the dev guide which is delete row from the table.
    My page displays the data for a row.

    I added a submitbutton delete my page.

    Here is my code:

    IDI int = Integer.parseInt (id.toString ());
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    Line XxVORowImpl = null;
    int fetchedRowCount = vo.getFetchedRowCount ();
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    If (fetchedRowCount > 0)
    {
    deleteIter.setRangeStart (0);
    deleteIter.setRangeSize (fetchedRowCount);
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    {
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    getTransaction () .commit ();
    break;
    }
    }
    }
    deleteIter.closeRowSetIterator ();


    My problem is that fetchedRowCount is 0. But there are about 100 rows in my table.
    And my VO is just a simple select * from myTable.

    So I do not understand why fetchedRowCount is still 0?

    Help thank you
    Dan

    Dan

    You don't create a page of dialogue Yes No button when you click on the delete icon. For dialog page, please see the dev guide or my refer below code snippet that you may need to change little

       else if ("delete".equals(pageContext.getParameter(EVENT_PARAM)))
{
// The user has clicked a "Delete" icon so we want to display a "Warning"
// dialog asking if she really wants to delete the employee. Note that we
// configure the dialog so that pressing the "Yes" button submits to
// this page so we can handle the action in this processFormRequest( ) method.
String employeeNumber = pageContext.getParameter("empNum");

String employeeName = pageContext.getParameter("empName");
MessageToken[] tokens = { new MessageToken("EMP_NAME", employeeName)};
OAException mainMessage = new OAException("AK",
"FWK_TBX_T_EMP_DELETE_WARN", tokens);
// Note that even though we're going to make our Yes/No buttons submit a
// form, we still need some non-null value in the constructor's Yes/No
// URL parameters for the buttons to render, so we just pass empty
// Strings for this.
OADialogPage dialogPage = new OADialogPage(OAException.WARNING,
mainMessage, null, "", "");
// Always use Message Dictionary for any Strings you want to display.
String yes = pageContext.getMessage("AK", "FWK_TBX_T_YES", null);
String no = pageContext.getMessage("AK", "FWK_TBX_T_NO", null);
// We set this value so the code that handles this button press is
// descriptive.
dialogPage.setOkButtonItemName("DeleteYesButton");
// The following configures the Yes/No buttons to be submit buttons,
// and makes sure that we handle the form submit in the originating
// page (the "Employee" summary) so we can handle the "Yes"
// button selection in this controller.
dialogPage.setOkButtonToPost(true);
dialogPage.setNoButtonToPost(true);
dialogPage.setPostToCallingPage(true);
// Now set our Yes/No labels instead of the default OK/Cancel.
dialogPage.setOkButtonLabel(yes);
dialogPage.setNoButtonLabel(no);
// We need to keep hold of the employeeNumber, and the OADialogPage gives us a
// convenient means of doing this. Note that the use of the Hashtable is
// really more appropriate for passing multiple parameters, but we've used
// it here for illustration purposes. See the OADialogPage javadoc for an
// alternative when dealing with a single parameter.
java.util.Hashtable formParams = new java.util.Hashtable(1);
formParams.put("empNum", employeeNumber);
formParams.put("empName", employeeName);
dialogPage.setFormParameters(formParams);
pageContext.redirectToDialogPage(dialogPage);
}
else if (pageContext.getParameter("DeleteYesButton") != null)
{
// User has confirmed that she wants to delete this employee.
// Invoke a method on the AM to set the current row in the VO and
// call remove() on this row.
String employeeNumber = pageContext.getParameter("empNum");
String employeeName = pageContext.getParameter("empName");
Serializable[] parameters = { employeeNumber };
OAApplicationModule am = pageContext.getApplicationModule(webBean);
am.invokeMethod("deleteEmployee", parameters);
// Now, redisplay the page with a confirmation message at the top. Note
// that the deleteEmployee() method in the AM commits, and our code
// won't get this far if any exceptions are thrown.
MessageToken[] tokens = { new MessageToken("EMP_NAME", employeeName) };
OAException message = new OAException("AK",
"FWK_TBX_T_EMP_DELETE_CONFIRM", tokens, OAException.CONFIRMATION, null);
pageContext.putDialogMessage(message);
}

    Thank you
    AJ

  • How to get the substring of this string

    Hi friends,

    "ERF/11/414/KWT/IRC762.

    in this I need the string after C...

    I have to select the channel and finds the first occurrence of C in the last string and get the number after C every time
    what the chain can be

    I always check the first occurrence of C in the last... and retrun the number after the C

    How to make

    pls let me know

    He should give me the chain until the IRC avoiding 762

    This?

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/
NUM
----------------------------
ERFC/11/414/KWT/IRC

  • Delete the work of nto lines button code.

    Hello
    I developed a table in a custom page and I added the deletion icon to that one. If I click on delete, records are deleting application but don't not removing database table... I used following code to delete the records... Pls suggest.


    Controller of

    Boolean isAuthorisedDelete = pageContext.getParameter
    ("DeleteAuthorisedToYes")! = null |
    pageContext.getParameter ("DeleteAuthorisedToNo")! = null;



    If (pageContext.getParameter (OAWebBeanConstants.EVENT_PARAM)
    . Equals ("deleteauthorisedrow"))
    {
    System.out.println ("in XXIosCO.processFormRequest ()," +)
    "deleteauthorisedrow event fired");
    deleteauthorisedrow (PageContext, AM);
    }

    If (pageContext.getParameter ("DeleteAuthorisedToYes")! = null) {}
    String rowRef = pageContext.getParameter ("rowRef");
    String rowRef = pageContext.getParameter (OAWebBeanConstants.EVENT_SOURCE_ROW_REFERENCE);
    System.out.println ("In XXWorkOrderAMImpl.delete1" +)
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    am.invokeMethod ("deleteauthorisedrow",
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    }


    Private Sub deleteauthorisedrow (pageContext, OAPageContext,
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    System.out.println ("In XXWorkOrderAMImpl.delete2" +)
    (".rowRef:" + rowRef);
    String default = "";
    Object addNewRecord = am.invokeMethod
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    If (addNewRecord! = null & & addNewRecord.toString (.equals("Y"))) {}
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    } else {}
    Default = "you sure you want to delete the record?
    }

    OAException = message
    New OAException (default, OAException.WARNING);
    OADialogPage = dialog
    new OADialogPage (OAException.WARNING, message, null, "", "");

    dialog.setOkButtonItemName ("DeleteAuthorisedToYes");
    dialog.setNoButtonItemName ("DeleteAuthorisedToNo");
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    dialog.setNoButtonToPost (true);
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    dialog.setOkButtonLabel ("Yes");
    dialog.setNoButtonLabel ("No");
    Hashtable deleteParam = new Hashtable (1);

    deleteParam.put ("rowRef", rowRef);
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    dialog.setFormParameters (deleteParam);

    pageContext.redirectToDialogPage (dialog);

    }


    AM

    public void deleteauthorisedrow (String rowRef)
    {
    XXIosAuthorisedVORowImpl = rowToDelete
    (XXIosAuthorisedVORowImpl) findRowByRef (rowRef);
    If (rowToDelete! = null)
    {
    System.out.println ("In XXWorkOrderAMImpl.deleteauthorisedrow ()" +)
    (".rowRef:" + rowRef);
    IsAddRowRecord = Boolean
    rowToDelete.getaddNewRecord ()! = null & &
    rowToDelete.getaddNewRecord (.equals("Y"));
    rowToDelete.remove ();
    if(!isAddRowRecord)
    {
    getOADBTransaction () .commit ();
    }
    }
    }

    public String getAuthorisedRecordStatusByRowRef (String rowRef)
    {
    String recordStatus = null;
    XXIosAuthorisedVORowImpl line =.
    (XXIosAuthorisedVORowImpl) findRowByRef (rowRef);
    If (line! = null)
    {
    recordStatus = row.getaddNewRecord ();
    }
    RecordStatus return;
    }
    Thanks in advance,
    Roxanne.

    Roxanne

    You can try the workaround instead of using rowRef, create the parameter in the settings property fire action and get this value to check what the line clicked and delete this line.

    Thank you
    -Anil
    http://oracleanil.blogspot.com

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