find the first occurrence of a digital data in a string

Similar Questions

• Find the first occurrence of a Word

  I have a script which detects and counts all occurrences of a Word.

  I need the script to find the FIRST occurrence of a Word only.

  Can any advise please how do I change the script to find the first occurrence of the word?

  Script as follows:

  {

  numWords = this.getPageNumWords var (0);

  for (var i = 0; i < numWords; i ++)

  {

  var ckWord = this.getPageNthWord(0,i);

  If (ckWord is 'MATERIAL')

  {

  / * Script going here based on the finds the first occurrence of the word 'MATTER ' * /.

  }

  }

  }

  I tried var CKWord = this.getPageNthWord (0,0); but reports from the rear console is UNDEFINED?

  numWords = this.getPageNumWords var (0);

  var number = 0;

  for (var i = 0; i)
  var ckWord = this.getPageNthWord(0,i);
  If (ckWord == "ISSUED") {}
  Count ++;
  If (count == 2) {}
  var = this.mouseX Coord.

  var annot = this.addAnnot({)
  page: 0.
  type: "Stamp."
  name: "AppStamp."
  Rect: [coord + 1000, 2300, 30, 2820]
  rotation: 90,.
  ({AP: '#C94cHAFFa42U1gTH5Tug5C'});
             
  break;
  / * this.flattenPages (); */
  }
  }
  }

• How to replace the first occurrence of a substring

  How to replace the first occurrence of a substring of my original string? everything built in features in PL/SL?
  EX: Original string: "webinweb" I need the output of string as: "xyzinweb" simply replace occuarnce first of 'web' by "xyz".

  SQL> select   regexp_replace('webinweb','web','xyz',1,1) from dual
  /
  REGEXP_R
  --------
  xyzinweb
  

• To find the first Summit for data channel

  Hey guys,.

  I need a little help. I wrote a script to process some data. Basically, what the script does is calculate the linear accelerations peak, peak of the angular speeds, HIC values and IF. But there is a problem with my script that I need help. In my script, I use the ChnPeakFind command to find the pics in my chains. This command works fine to find the peak value, but what I want to do is find the FIRST Summit in the data, without worrying whether or not it is a maximum. I always encountered data that varies in which my first pic (impact analysis) may or may not be the highest point in the channel. As you can see in the Graphs.png that I have attached, the ChnPeakFind command found the 2nd Summit (red circle #2) in my chain of angular velocity (ARS resulting). But what I report is the first peak value (red circle #1). I've also attached a screenshot of the section in my code where I calculate the angular velocity. The 'i' in the calculation is just the channel group number. In this case, it is 1. Anyone know how to change the code or have another suggestion how to find the first Summit in a channel without having to stop and go to the tab analysis to manually find the pic?

  Thank you!

  Hello

  If it please see my littl below escript and let me know if this could work for you

  Dim     oChnResultant
  
  Call Data.Root.Clear)
  
  Call DataFileLoad ("E:\Customer_Examples\01_Head_Impact\Head Impact Data.tdm", "CT", "Load")
  
  Set oChnResultant = data. Root.ActiveChannelGroup.Channels.Add ("Result", DataTypeChnFloat64)
  
  Call ChnXYZAbsValue ("[1] / ARS X","[1] / ARS Y","[1] / ARS Z", oChnResultant)
  
  "Use the filter twice to get rid of the jig
  
  Call ChnSavitzkyGolayFilter (oChnResultant, oChnResultant, 1, 12)
  
  Call ChnSavitzkyGolayFilter (oChnResultant, oChnResultant, 1, 12)
  
  ' Delete few maxima to the beginninf of the signal.
  
  Calculate the call ("R = IIF (R)<>
  
  'Research for first peak.
  
  Call ChnPeakFind ("[1] / Time axis","[1]/Resultant","/PeakX","/PeakY",1,"Max.Peaks","Time")
  
  

• Oracle sql for data after the first occurrence of the hyphen

  Hi, I need oracle sql get data after the first occurrence of the hyphen.
  
  source of the string:
  ABCD - efgh
  
  I just want everything after the ' - '.
  
  someone help me please...
  
  Edited by: 1001076 on 28 may 2013 18:42

  Handle: 1001076
  Status level: Beginner
  Join date: April 18, 2013
  Messages total: 12
  Total Questions: 4 (3 pending)

  I offer you my condolences; Since you rarely get your questions answered here.

• Topics by opening the first occurrence in the table of contents

  Background: I created HTML5 Responsive help using HR 2015 for a web application. I organized the Hep role, then pages with these roles, users can access, and then by the tasks users can perform on this page. In many cases, a subject is listed under multiple roles and reuse and efficiency, I just dragged the same theme in the list of the topic in the table of contents as appropriate.

  I also used the text conditionalized on table of contents by role level. Using the example below, I have conditions for physician, nurse, and Patient, but I don't think that this is part of the issue well. Conditionalized roles were created for filtering purposes.

  Question: I have the overview topics that include hyperlinks to headings in red in the example below for each role. When a user clicks the hyperlink in this topic of presentation, he brings them to the FIRST occurrence of this topic in the table of contents, not the link that is associated with their role. When a user with the role of the Patient is in the topic view of their role and click the hyperlink 'Research for patients', help opens on this subject, but the "Searching for patients" in the topic role of physician in the table of contents on the left is highlighted.  Not a show-stopper, but it is confusing for users.

  Also, we had originally planned to use the filter feature to filter role help topics. When I filter to view only a specific role (nurse) and do the steps above, by clicking on the Preview 'Search for patients' hyperlink opens but there is no highlighting in the table of contents because this first occurrence is hidden in all the subjects physician.

  Note: This problem does not occur when I generate the content as WebHelp.

  What I want to do: When the nurse click on the hyperlink for 'Research for patients' of their overview topic, researching topic of patients is open and the search for patients is highlighted in the table of contents under the nurse, not the first occurrence (doctor).

  Questions: Is this a bug or is it repairable? And is it possible to fix it without creating the specific role of topics such as finding doctors for Patients, nursing research for Patients and so forth? I tried to delete the table of contents and start again, but the problem persists.

  Here is an example:

  Doctor

  Patient portal page

  Overview (contains links to sections below - view patient demograhic data, looking for patients, to renew orders)

  Display of the demographics of the patients

  Looking for patients

  Renewal of prescriptions

  Nurse

  Patient portal page

  Overview (contains links to sections below)

  Display of the demographics of the patients

  Looking for patients

  Display of orders

  Patient

  Patient portal page

  Overview (contains links to sections below)

  Update your demographic data

  Display of your prescrpitions

  My opinion would be that this is the expected behavior. My theory is that there is no information within the syntax of hyperlinks. A hypertext link is encoded such that when you click on it, you are taken to the landing page, as if sending the message "find the page named and post it by the specified parameters. What is happening is that the hyperlink goes to the first instance of the HTML page in your table of contents (.hhc file). There is no intelligence, he doesn't "know" that you are in the doctor or the nurse section - section he knows only that the page specified in the table of contents is listed in the file and thus, it only takes you there. The syntax of hyperlinks don't "know" where you are in the help system.

  I just also wanted to report the fault of strike in the Patient section, look a your orders of your example, assuming that you have copied and pasted into this thread.

• Find the first empty cell

  OK so I use numbers to design a "schedule" for lack of a better word for a flight instructor course. On the summary page, I need to be able to identify the next sequence of flight for each student. I have a sheet that contains all flights that each student must perform and the date which they filled. So what I need on the summary page is someway to watch flight logs and determine what the next flight is to find the first empty cell under each name of students. I have no idea how to go about that though, so if you have any ideas I would be grateful

  Hello j,

  Here are two possibilities, both illustrate below. They are independent of each other and can be used alone or together.

  If students all sequences in chronological order, and the dates in columns are values of Date and real time, you should be able to locate the first empty line using MATCH and MAX.

  Because all dates entered will be 'today' or 'before today', a conditional highlighting rule could be used to color the background of the cell to a cell where a date has been entered.

  

  Table 1 gives the master record. Table 2 shows the following sequence for the student and the line of table 1, which the sequence is listed.

  Two formulas are used:

  Table 2::B3 and filled with right: = MATCH (MAX (table 1: B), Table 1: B, 0) + 1

  Table 2::B2 and filled with right: = OFFSET (table 1: $A$ 1, B3-1, 0)

  This method is based on the sequences being completed in the order listed, as it seems the most recent (that is to say date the "bigger").

  The rule of conditional formatting applied to all cells in columns B, C and D of table 1 fills every cell that contains a date before the next day with yellow, giving a visual indication of where all the next vacant cell.

  This indicator is independent of the order of the sequences, because it depends on only that there is a date or before 'today' in each cell to be highlighted.

  Kind regards

  Barry

• How to find the first day of the month following two years one year from now?

  Hello

  I need to find the first day of the month following two years ago, based on the current date.

  For example: If today is the 31/08/2015 so I need to find the date range between 31/08/2015 and on 09/01/2013. How can I write an SQL which allows to automate this calculation instead of hard-coding the values. Please do help me out with this so that I can build the SQL that can produce the desired result.

  Thank you

  Dhilip

  find the start of the month - 2 years in advance, early - 2 years + 1 months in advance and go back 1

  Select trunc (add_months(sysdate,24), 'MM'), trunc (add_months(sysdate,25), 'MM') - 1 double;

• How to find the first Sunday and the second Saturday of each month

  Hi all

  How to find the first Sunday and the second Saturday of each month

  Thank you

  Oracle Database 11 g Enterprise Edition Release 11.1.0.7.0 - 64 bit Production

  994122 wrote:

  Hello

  I need to pass the months parameter how to do this? like Jan, Feb etc... (one of those)

  Do you have a procedure?

  Should you output only for the months you passed in the parameter?

  The easiest way is to set the parameter as date. When you go such as p_date as DATE ' 2014-10-01', then you can

  PROCEDURE two_dates)

  p_date IN DATE

  p_first_sunday DATE

  p_second_saturday DATE

  )

  IS

  BEGIN

  p_first_sunday: = NEXT_DAY (TRUNC (p_date, 'MM') - 1, TO_CHAR (DATE ' 2014-10-12', 'DAY'));

  p_second_saturday: = NEXT_DAY (TRUNC (p_date, 'MM') - 1, TO_CHAR (DATE ' 2014-10-11', 'DAY')) + 7;

  END two_dates;

  Or you describe what you need.

• Find the first day of the third quarter of next year

  Hello

  I'm writing a sql to find "the first day of the third quarter of the year (from the current year) next»

  I am able to get the first and the last day of the current quarter:

  Select trunc (sysdate, 'Q'), trunc (add_months (sysdate, + 3), 'Q')-1 double

  But, how to find the first day of the third quarter of the year next (from the current year) based on any date entry (i.e. sysdate)

  for example if my entry date = 12/01/2001 should be released 07/01/2015

  If my entry date = 07/04/2005 should be released 07/01/2015

  If my entry date = 20/02/2013 should be released 07/01/2015

  ... etc.

  Thanks in advance

  Hello

  The 1st day of the 3rd quarter of next year is:

  ADD_MONTHS (TRUNC (SYSDATE, 'YEAR')

  18 = 12 + 6

  )

  TRUNC (SYSDATE, 'YEAR') is the 1st day of the 1st quarter of this year

  The first day of the new year is 12 months after that, and the first day of quarter 3 is another 6 months after that.

  user634169 wrote:

  ... But, how to find the first day of the third quarter of the year next (from the current year) based on any date entry (i.e. sysdate)

  for example if my entry date = 12/01/2001 should be released 07/01/2015

  If my entry date = 07/04/2005 should be released 07/01/2015

  If my entry date = 20/02/2013 should be released 07/01/2015

  ... etc.

  Thanks in advance

  You did some errors above?

  If the effective date in 2001, why is the output in 2015, not 2002?

  If the output is based only on the date of the day (currently in 2014), why even mention a start date?

• Script works only on the first occurrence of a masterpage

  I adopted a dynamic shape on LiveCycle to maintain and update. I have no programming experience, but are working with LiveCycle for over three months to know that I'm going every day.

  I have a problem of script that I don't know how to handle. I use javascript. I currently have a script that will look at the < State > tag to an xdp. If the value < status > is a certain State, then a text in the subform 'footer' of a master page will be hidden while another text with a larger font becomes visible.

  if (xfa.datasets.data.job.data.state.value, == , "NJ") { }

  jobs. MasterPages.Liability_Continued.footer.liabilityFooterBig.presence = 'visible ';

  jobs. MasterPages.Liability_Continued.footer.liabilityFooter.presence = "invisible";

  }

  My problem is that the script only works on the first instance of the master page. On all other occurrences, it always displays the text smaller.

  I tried the script on initialization, enter, exit, calculate, validate, validation status, presave, postsave, preprint, post-press, presubmit, postsubmit, docready, docclose, form ready, ready, available and index change the subform "footer" events, but these events have not worked at all, or only worked on the first occurrence of the subform.

  How can I get the visibility of these text objects to change all occurrences of the subform?

  Hello

  There are two possible options. We need to loop through all instances of the Master Page and change the presence of objects on each instance. The other would be to have the script in the event layout: ready for each of the objects referring to this.presence = "invisible";

  Thus, for example, if your Master Page named Page1, then this should work:

  var oMaster = xfa.resolveNodes("Page1"); 
  
  for (var i=0; i
  The exact reference in the script would be according to your hierarchy.
  Niall
  		   

• To find the months and days between 2 dates

  Hello

  I want to find the months and days between 2 dates.

  For example.

  1 - Date: August 25, 2013

  2 - Date: October 23, 2013

  If we consider each month 30 days, it should give

  August 25, 2013 to August 30, 2013 = 6 days

  01-Sep-2013-30-Sep-2013 = 1 month

  October 23, 2013 to October 30, 2013 = 8 days

  Total = 1 month and 14 days.

  Kindly help as soon as possible.

  Thanks and greetings

  Suresh

  Assuming that d2 > d1,.

  where d)

  Select sysdate d1, sysdate + 56 double d2

  Union all select to_date (March 1, 2013 ',' dd-mon-yyyy "") d1, to_date (March 31, 2013 ',' dd-mon-yyyy ') d2 double

  Union all select to_date (5 February 2013 ',' dd-mon-yyyy ') d1, to_date (March 31, 2013 ',' dd-mon-yyyy "") double d2

  Union all select to_date (February 25, 2013 ',' dd-mon-yyyy "") d1, to_date (March 23, 2013 ',' dd-mon-yyyy ') d2 double

  Union all select to_date (February 25, 2013 ',' dd-mon-yyyy ') d1, to_date (March 31, 2013 ',' dd-mon-yyyy "") double d2

  Union all select to_date (August 2, 2013 ',' dd-mon-yyyy "") d1, to_date (29 October 2013 ',' dd-mon-yyyy ') d2 double

  Union all select to_date (February 1, 2013 ',' dd-mon-yyyy "") d1, to_date (May 31, 2013 ',' dd-mon-yyyy ') d2 double

  Union all select to_date (25 August 2013 ',' dd-mon-yyyy "") d1, to_date ('03-Sep-2013', 'Mon-dd-yyyy') d2 double

  Union all select to_date (July 30, 2013 ',' dd-mon-yyyy "") d1, to_date (August 31, 2013 ',' dd-mon-yyyy ') d2 double

  Union all select to_date (July 31, 2013 ',' dd-mon-yyyy ') d1, to_date (August 30, 2013 ',' dd-mon-yyyy "") double d2

  Union all select to_date (July 31, 2013 ',' dd-mon-yyyy ') d1, to_date (3 August 2013 ',' dd-mon-yyyy "") double d2

  Union all select to_date (3 July 2013 ',' dd-mon-yyyy "") d1, to_date (August 31, 2013 ',' dd-mon-yyyy ') d2 double

  Union all select to_date ('31-08-2013', ' dd-mm-yyyy'), to_date('05-10-2013','dd-mm-yyyy') of the double

  Union all select to_date ('05-02-2013', ' dd-mm-yyyy'), to_date('31-03-2013','dd-mm-yyyy') of the double

  Union all select to_date ('05-02-2013', ' dd-mm-yyyy'), to_date('05-03-2013','dd-mm-yyyy') of the double

  Union all select to_date ('05-02-2013', ' dd-mm-yyyy'), to_date('05-02-2013','dd-mm-yyyy') of the double

  )

  Select d1, d2,

  1 + 30 * trunc (months_between (d2, d1)) + LESS (extract (day of d2), 30)-LESS (excerpt (d1 day), 30)

  + CASE when extracted (d2 day)< extract(day="" from="" d1)="" then="" 30="" else="" 0="" end ="">

  d

  D1 D2 DAYSBETWEEN

  ----------- ----------- -----------

  October 10, 2013 5 December 2013 56

  March 1, 2013 30 March 31, 2013

  5 February 2013 March 31, 2013 56

  February 25, 2013 March 23, 2013 29

  February 25, 2013 March 31, 2013 36

  August 2, 2013 29 October 2013 88

  February 1, 2013 may 31, 2013 120

  August 25, 2013 03 - Sep-2013 9

  July 30, 2013 31 August 31, 2013

  July 31, 2013 August 30, 2013 31

  July 31, 2013 3 August 2013 4

  July 3, 2013 August 31, 2013 58

  31 August 2013 5 October 2013 36

  5 February 2013 March 31, 2013 56

  5 February 2013 March 5, 2013 31

  February 5, 2013 February 5, 2013 1

  In my view, which corresponds to your rules.

• I can't find the first Pro app on my list of app off CC, help, please / / no encuentro application Premier Pro en mi lista of applications of CC, ayuda, por favor

  There are other apps here, but I Don t know how to find the first. I tried selecting filter audio/video and it doesn´t appear. Help me, please

  You MUST have a 64-bit computer what is your computer?

  Adobe http://helpx.adobe.com/premiere-pro/system-requirements.html MINimums

  -Programs does not appear if they are not installed on your computer

  -http://helpx.adobe.com/creative-cloud/kb/all-apps-displayed-aam.html

• Find the first row of each column

  Hi all

  Request:

  I want to find the first line in the text frame columns.

  Bug:

  If the active document contains a single column, two columns, and multiple column text blocks. In this case, I'm not able to get my result

  Try the script:

  myDoc = app.activeDocument var

  var myTextFrames = myDoc.textFrames.everyItem () .getElements)

  for (i = 0; i < myTextFrames.length; i ++)

  {

  var myTextColumns1 = myTextFrames [i] .textColumns [1] .lines [0] .silence

  Alert (myTextColumns1)

  }

  Attached, I have attached the error file.

  If the active document contains only two block of text column, script executed successfully.

  If the active document contains the single column text block and the sampling error two columns of text as below:

  

  Could someone find solution for my application.

  Thanks in advance

  BEGINNER

  Try this,

  myDoc = app.activeDocument var

  var myTextFrames = myDoc.textFrames.everyItem () .getElements)

  for (i = 0; i

  {

  for (var j = 0; j)

  {

  var myTextColumns1 = myTextFrames [i] .textColumns [j] .lines [0] .silence

  $.writeln (myTextColumns1)

  }

  }

• How to find the first max value for each item

  Hello
  
  I have the me_result of the table as below,
  
  SELECT * FROM me_result;
  
  ID     ||| ELITE     ||||||||||| FREQ_ITEM | COMBINED_STR | SUP
  1     ||; 1; 10; 2; 3; 4; 5; 7; 8. 1     ||||||||||||||; 1; 10; 2; 3; 4; 5; 7; 8 ||| 2
  2     ||; 1; 10; 2; 3; 4; 5; 7; 8. 2     ||||||||||||||; 1; 10; 2; 3; 4; 5; 7; 8 ||| 2
  3     ||; 1; 10; 2; 3; 4; 5; 7; 8. 3     ||||||||||||||; 1; 10; 2; 3; 4; 5; 7; 8 ||| 2
  4     ||; 1; 10; 2; 3; 4; 5; 7; 8. 4     ||||||||||||||; 1; 10; 2; 3; 4; 5; 7; 8 ||| 2
  5     ||; 1; 10; 2; 3; 4; 5; 7; 8. 5     ||||||||||||||; 1; 10; 2; 3; 4; 5; 7; 8 ||| 2
  6     ||; 10; 2; 3; 4; 5; 8; 9. 1     ||||||||||||||; 10; 2; 3; 4; 5; 8; 9; 1 ||| 1
  7     ||; 10; 2; 3; 4; 5; 8; 9. 2     ||||||||||||||; 10; 2; 3; 4; 5; 8; 9 ||| 2
  8     ||; 10; 2; 3; 4; 5; 8; 9. 3     ||||||||||||||; 10; 2; 3; 4; 5; 8; 9 ||| 2
  9     ||; 10; 2; 3; 4; 5; 8; 9. 4     ||||||||||||||; 10; 2; 3; 4; 5; 8; 9 ||| 2
  10     ||; 10; 2; 3; 4; 5; 8; 9. 5     ||||||||||||||; 10; 2; 3; 4; 5; 8; 9 ||| 2
  
  
  I need to find the first COMBINED_STR max for each element of the ELITE,
  I mean, max value is the max REGEXP_COUNT (combined_str,' ;')))
  
  really, I try to write down, but I had a lot of values for each ELITE and I need only the first, that
  SELECT * from me_result
  WHERE (ELITE, REGEXP_COUNT (combined_str,' ;')))) IN
  (SELECT ELITE, MAX (REGEXP_COUNT (combined_str,' ;'))))) ME_RESULT ELITE GROUP);
  
  I need the result to be as below.
  
  1; 1; 10; 2; 3; 4; 5; 7; 8-1; 1; 10; 2; 3; 4; 5; 7; : p
  6; 10; 2; 3; 4; 5; 8; 9 1; 10; 2; 3; 4; 5; 8; 9; 1 1
  
  any help please,.
  
  Published by: user11309581 on July 10, 2011 22:03

  Can be

  with t as
  (select 1     ID, ';1;10;2;3;4;5;7;8'     ELITE, 1     FREQ_ITEM, ';1;10;2;3;4;5;7;8' COMBINED_STR, 2 SUP from dual union all
  select 2     ,';1;10;2;3;4;5;7;8'     ,2     ,';1;10;2;3;4;5;7;8'     ,2 from dual union all
  select 3     ,';1;10;2;3;4;5;7;8'     ,3     ,';1;10;2;3;4;5;7;8'     ,2 from dual union all
  select 4     ,';1;10;2;3;4;5;7;8'     ,4     ,';1;10;2;3;4;5;7;8'     ,2 from dual union all
  select 5     ,';1;10;2;3;4;5;7;8'     ,5     ,';1;10;2;3;4;5;7;8'     ,2 from dual union all
  select 6     ,';10;2;3;4;5;8;9'     ,1     ,';10;2;3;4;5;8;9;1'     ,1 from dual union all
  select 7     ,';10;2;3;4;5;8;9'     ,2     ,';10;2;3;4;5;8;9'     ,2 from dual union all
  select 8     ,';10;2;3;4;5;8;9'     ,3     ,';10;2;3;4;5;8;9'     ,2 from dual union all
  select 9     ,';10;2;3;4;5;8;9'      ,4     ,';10;2;3;4;5;8;9'     ,2 from dual union all
  select 10     ,';10;2;3;4;5;8;9'     ,5     ,';10;2;3;4;5;8;9'     ,2 from dual
  )
  select ID,ELITE,FREQ_ITEM,COMBINED_STR,SUP
  from (
    SELECT ID,ELITE,FREQ_ITEM,COMBINED_STR,SUP, ROW_NUMBER() over (PARTITION BY ELITE order by id) RN
    FROM t
    WHERE (ELITE,REGEXP_COUNT(combined_str,';')) IN
      (SELECT ELITE,MAX(REGEXP_COUNT(combined_str,';')) FROM t GROUP BY ELITE)
  ) where RN=1
  order by id
  
  ID                     ELITE             FREQ_ITEM              COMBINED_STR      SUP
  ---------------------- ----------------- ---------------------- ----------------- ----------------------
  1                      ;1;10;2;3;4;5;7;8 1                      ;1;10;2;3;4;5;7;8 2
  6                      ;10;2;3;4;5;8;9   1                      ;10;2;3;4;5;8;9;1 1