Different output for the same query in SQL Server and Oracle

I have two tables table1 and table2

-table1 has two columns c1 int and varchar c2. There are no constraints added in it. It contains data as shown below

C1 c2
-------------------
d 6
5 d
102 g
6%
f 103
5.
501 j
1 g
601 n
2 m

-table2 has only a single column c1 int. There is no added in constraints. It contains data as shown below

C1
----
6
1
4
3
2

now when I run below, given the query in sql server and oracle it gives me different results

Select *.
FROM table1
table2 on table2.c1 = table1.c1 inner join (SELECT ROW_NUMBER() (any ORDER by ASC c1) AS c1 from table2)

output of SQL server
------------------------
C1 c2 c1
--------------------------------
1 g 1
2 m 2
3 h 3
4 g 4
5 d 5

release of Oracle
----------------------
C1 C2 C1
---------------------------------
5 d 5
4 g 4
3 h 3
1 g 1
2 m 2

If you notice the first column in the two outputs. It is sorted in sql server and no oracle.

Why he behaves differently in oracle? Is there a way I can fix this problem in oracle?

Thank you
Jigs

It is NOT a behavior "differently" in Oracle; you did not specify just an order that you expect of your results, so you'll get output in what order the fantasies of the database showing (ie. no guaranteed order). It is an artifact of the way the database chooses to collect the data and databases (or same sets of data within the same database) can and will most likely behave differently.

Same SQL Server will not be guaranteed to always get your data in an orderly manner if you exclude the order by clause, even if you think that there always display the data in an orderly manner.

Your solution is to add an order by clause, in the TWO databases, to force the order of the data output.

Tags: Database

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SQL > col COLUMN_NAME format a20

SQL > select index_name, column_name, position_colonne from user_ind_columns where table_name = 'LOAN_RUNNING_DETAILS_SOUTH"of order 1.

INDEX_NAME COLUMN_NAME POSITION_COLONNE

------------------------------ -------------------- ---------------

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He explained.

SQL > SQL > set line 200

@?/rdbms/admin/utlxpls.sql

SQL >

PLAN_TABLE_OUTPUT

--------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------

Hash value of plan: 3659874059

------------------------------------------------------------------------------------------------------------------

| ID | Operation | Name                       | Lines | Bytes | Cost (% CPU). Time | Pstart. Pstop |

------------------------------------------------------------------------------------------------------------------

|   0 | SELECT STATEMENT |                            | 1448K |    58 M | 21973 (2) | 00:04:24 |       |       |

|* 1 | FILTER |                            |       |       |            |          |       |       |

|   2.   PARTITION LIST ALL |                            | 1448K |    58 M | 21973 (2) | 00:04:24 |     1.    11.

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------------------------------------------------------------------------------------------------------------------

PLAN_TABLE_OUTPUT

--------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------

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---------------------------------------------------

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16 selected lines.

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INDEX_NAME COLUMN_NAME POSITION_COLONNE

------------------------------ -------------------- ---------------

DATE_IND1_S LOANDATETIME 1

IND_MSI_LN_LNS1_S MSISDN 1

IND_MSI_LN_LNS1_S LOANDATETIME 2

IND_MSI_LN_LNS1_S LOANSTATUS 3

LAST_INDEX L_INDX_MSISDN_S 1

MSISDN L_INDX_MSISDN_S 2

SQL > select decode (status, 'N/a', 'Part Hdr', 'Global') ind_type, index_name, NULL nom_partition, status

2 from user_indexes where table_name = 'LOAN_RUNNING_DETAILS_SOUTH '.

Union

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5 to user_ind_partitions where index-name in (select index_name in user_indexes where table_name = 'LOAN_RUNNING_DETAILS_SOUTH')

6 order of 1,2,3;

IND_TYPE INDEX_NAME NOM_PARTITION STATUS

-------- ------------------------------ ------------------------------ --------

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SQL > set line 200

@?/rdbms/admin/utlxpls.sql

SQL >

PLAN_TABLE_OUTPUT

--------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------

Hash value of plan: 1161680601

----------------------------------------------------------------------------------------------------------------------------------

| ID | Operation | Name                       | Lines | Bytes | Cost (% CPU). Time | Pstart. Pstop |

----------------------------------------------------------------------------------------------------------------------------------

|   0 | SELECT STATEMENT |                            |     2.    84.     5 (0) | 00:00:01 |       |       |

|* 1 | FILTER                             |                            |       |       |            |          |       |       |

|* 2 |   TABLE ACCESS BY INDEX ROWID | LOAN_RUNNING_DETAILS_SOUTH |     2.    84.     5 (0) | 00:00:01 | ROWID | ROWID |

|* 3 |    INDEX RANGE SCAN | DATE_IND1_S |     2.       |     3 (0) | 00:00:01 |       |       |

----------------------------------------------------------------------------------------------------------------------------------

PLAN_TABLE_OUTPUT

--------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------

Information of predicates (identified by the operation identity card):

---------------------------------------------------

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2 - filter ("LOANTYPE" = 1)

3 - access("LOANDATETIME">SYSDATE@!-15 AND "LOANDATETIME"<=SYSDATE@!-2)

17 selected lines.

Reg,
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Hi , HemantKChitale,

I also update statistics manual as you say, but not see 'TABLE ACCESS FULL' good result

What should I do? my need of production tuning, but I cannot able tune this...

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He explained.

SQL > set line 200

@?/rdbms/admin/utlxpls.sql

SQL >

PLAN_TABLE_OUTPUT

--------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------

Hash value of plan: 3659874059

------------------------------------------------------------------------------------------------------------------

| ID | Operation | Name                       | Lines | Bytes | Cost (% CPU). Time | Pstart. Pstop |

------------------------------------------------------------------------------------------------------------------

|   0 | SELECT STATEMENT |                            | 1874K |    75 M | 19626 (2) | 00:03:56 |       |       |

|* 1 | FILTER |                            |       |       |            |          |       |       |

|   2.   PARTITION LIST ALL |                            | 1874K |    75 M | 19626 (2) | 00:03:56 |     1.    11.

|* 3 |    TABLE ACCESS FULL | LOAN_RUNNING_DETAILS_SOUTH | 1874K |    75 M | 19626 (2) | 00:03:56 |     1.    11.

------------------------------------------------------------------------------------------------------------------

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--------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------

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---------------------------------------------------

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This issue was raised before also, but still not able to find the real cause of this.

Thread1:
Re: Research of fragmentation of the table in Oracle 8.1.6.3.0

Thread2:
CBC latch and buffer busy await you on the same table.

It comes, sometimes hammers server 100% CPU utilization with free latch and buffer busy wait events.

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My doubt is how to sql even with different literal values execution plan changes and causes a prob.

select count(*),event from v$session_wait group by event;
  COUNT(*) EVENT
---------- ----------------------------------------------------------------
       165 SQL*Net message from client
         1 SQL*Net message to client
         3 buffer busy waits
         2 db file parallel read
        18 db file sequential read
        10 latch free
         5 log file sync
         1 pmon timer
         6 rdbms ipc message
         1 smon timer

SQL> select sid from v$session_wait where event='db file sequential read';
       SID
----------
        26
        58
        82
       107
       116
       223
       212
       203
       192
       173
       161
       157
       150
       147
       254
       238
       229
       112
       101
        81
        68

SQL> select spid, sid, s.serial#, p.program from v$session s, v$process p where paddr=addr and sid=&SID;
Enter value for sid: 161
old   1: select spid, sid, s.serial#, p.program from v$session s, v$process p where paddr=addr and sid=&SID
new   1: select spid, sid, s.serial#, p.program from v$session s, v$process p where paddr=addr and sid=161

SPID             SID    SERIAL# PROGRAM
--------- ---------- ---------- ------------------------------------------------
4231             161      49569 oracle@tfrdb3 (TNS V1-V3)


SQL> select sql_text
from v$process a,
     v$session b,  2    3
     v$sql c
where a.addr = b.paddr and
     b.sql_hash_value = c.hash_value and
    a.spid = &PID;  4    5    6    7
Enter value for pid: 4231
old   7:     a.spid = &PID
new   7:     a.spid = 4231

SQL_TEXT
--------------------------------------------------------------------------------
SELECT ERROR,TIME_STAMP,O_RESOURCE,QUEUE,NEW_QUEUE FROM LOG WHERE ID = '09292AMR
10B41FE' AND TYPE IN (11, 28, 25, 18, 60, 13) AND (LOG_SEQ>'234225222' OR TYPE =
 18 AND LOG_SEQ='234225222') ORDER BY TIME_STAMP ASC

SQL> set autotrace traceonly exp
SQL> SELECT ERROR,TIME_STAMP,O_RESOURCE,QUEUE,NEW_QUEUE FROM amrwf1.LOG WHERE ID = '09292AMR10B41FE' AND TYPE IN (11, 28, 25, 18, 60, 13) AND (LOG_SEQ>'234225222' OR TYPE =18 AND LOG_SEQ='234225222') ORDER BY TIME_STAMP ASC;

Execution Plan
----------------------------------------------------------
   0      SELECT STATEMENT Optimizer=CHOOSE (Cost=11 Card=2 Bytes=126)
   1    0   SORT (ORDER BY) (Cost=11 Card=2 Bytes=126)
   2    1     CONCATENATION
   3    2       TABLE ACCESS (BY INDEX ROWID) OF 'LOG' (Cost=4 Card=1
          Bytes=63)

   4    3         INDEX (UNIQUE SCAN) OF 'PK_LOG_LOG_SEQ' (UNIQUE) (Co
          st=3 Card=1)

   5    2       TABLE ACCESS (BY INDEX ROWID) OF 'LOG' (Cost=4 Card=1
          Bytes=63)

   6    5         INDEX (RANGE SCAN) OF 'PK_LOG_LOG_SEQ' (UNIQUE) (Cos
          t=3 Card=1)


SQL> select spid, sid, s.serial#, p.program from v$session s, v$process p where paddr=addr and sid=&SID;
Enter value for sid: 147
old   1: select spid, sid, s.serial#, p.program from v$session s, v$process p where paddr=addr and sid=&SID
new   1: select spid, sid, s.serial#, p.program from v$session s, v$process p where paddr=addr and sid=147

SPID             SID    SERIAL# PROGRAM
--------- ---------- ---------- ------------------------------------------------
6255             147      38306 oracle@tfrdb3 (TNS V1-V3)

SQL> select sql_text
from v$process a,
     v$session b,
     v$sql c  2    3
where a.addr = b.paddr and
     b.sql_hash_value = c.hash_value and
    a.spid = &PID;  4    5    6    7
Enter value for pid: 6255
old   7:     a.spid = &PID
new   7:     a.spid = 6255

SQL_TEXT
--------------------------------------------------------------------------------
SELECT ERROR,TIME_STAMP,O_RESOURCE,QUEUE,NEW_QUEUE FROM LOG WHERE ID = '09273AMR
62B4894' AND TYPE IN (11, 28, 25, 18, 60, 13) AND (LOG_SEQ>'223324996' OR TYPE =
 18 AND LOG_SEQ='223324996') ORDER BY TIME_STAMP ASC


SQL> set autotrace traceonly exp
SQL> SELECT ERROR,TIME_STAMP,O_RESOURCE,QUEUE,NEW_QUEUE FROM amrwf1.LOG WHERE ID = '09273AMR62B4894' AND TYPE IN (11, 28, 25, 18, 60, 13) AND (LOG_SEQ>'223324996' OR TYPE =18 AND LOG_SEQ='223324996') ORDER BY TIME_STAMP ASC;

Execution Plan
----------------------------------------------------------
   0      SELECT STATEMENT Optimizer=CHOOSE (Cost=1538 Card=736 Bytes=
          46368)

   1    0   SORT (ORDER BY) (Cost=1538 Card=736 Bytes=46368)
   2    1     TABLE ACCESS (BY INDEX ROWID) OF 'LOG' (Cost=1527 Card=7
          36 Bytes=46368)

   3    2       INDEX (RANGE SCAN) OF 'LOG_ID' (NON-UNIQUE) (Cost=32 C
          ard=736)



SQL> select spid, sid, s.serial#, p.program from v$session s, v$process p where paddr=addr and sid=&SID;
Enter value for sid: 82
old   1: select spid, sid, s.serial#, p.program from v$session s, v$process p where paddr=addr and sid=&SID
new   1: select spid, sid, s.serial#, p.program from v$session s, v$process p where paddr=addr and sid=82

SPID             SID    SERIAL# PROGRAM
--------- ---------- ---------- ------------------------------------------------
6172              82      45378 oracle@tfrdb3 (TNS V1-V3)


SQL> select sql_text
from v$process a,
     v$session b,
     v$sql c
where a.addr = b.paddr and
     b.sql_hash_value = c.hash_value and  2
  3      a.spid = &PID;  4    5    6    7
Enter value for pid: 6172
old   7:     a.spid = &PID
new   7:     a.spid = 6172

SQL_TEXT
--------------------------------------------------------------------------------
INSERT INTO LOG (ID,TIME_STAMP,TYPE,ERROR,INSTANCE,RULE_NUM,RULE_TYPE,PRIORITY,F
LAGS,NAME,BATCH,O_RESOURCE,QUEUE,NEW_QUEUE,SERVER,FORM,WORKSET) VALUES (:V001,:V
002,11,0,0,3,1,0,1,:V003,:V004,:V005,:V006,:V007,:V008,:V009,:V010)

INSERT INTO LOG (ID,TIME_STAMP,TYPE,ERROR,INSTANCE,RULE_NUM,RULE_TYPE,PRIORITY,F
LAGS,NAME,BATCH,O_RESOURCE,QUEUE,NEW_QUEUE,SERVER,FORM,WORKSET) VALUES (:V001,:V
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INSERT INTO LOG (ID,TIME_STAMP,TYPE,ERROR,INSTANCE,RULE_NUM,RULE_TYPE,PRIORITY,F
LAGS,NAME,BATCH,O_RESOURCE,QUEUE,NEW_QUEUE,SERVER,FORM,WORKSET) VALUES (:V001,:V
002,11,0,0,3,1,0,1,:V003,:V004,:V005,:V006,:V007,:V008,:V009,:V010)

SQL_TEXT
--------------------------------------------------------------------------------

INSERT INTO LOG (ID,TIME_STAMP,TYPE,ERROR,INSTANCE,RULE_NUM,RULE_TYPE,PRIORITY,F
LAGS,NAME,BATCH,O_RESOURCE,QUEUE,NEW_QUEUE,SERVER,FORM,WORKSET) VALUES (:V001,:V
002,11,0,0,3,1,0,1,:V003,:V004,:V005,:V006,:V007,:V008,:V009,:V010)

INSERT INTO LOG (ID,TIME_STAMP,TYPE,ERROR,INSTANCE,RULE_NUM,RULE_TYPE,PRIORITY,F
LAGS,NAME,BATCH,O_RESOURCE,QUEUE,NEW_QUEUE,SERVER,FORM,WORKSET) VALUES (:V001,:V
002,11,0,0,3,1,0,1,:V003,:V004,:V005,:V006,:V007,:V008,:V009,:V010)

INSERT INTO LOG (ID,TIME_STAMP,TYPE,ERROR,INSTANCE,RULE_NUM,RULE_TYPE,PRIORITY,F
LAGS,NAME,BATCH,O_RESOURCE,QUEUE,NEW_QUEUE,SERVER,FORM,WORKSET) VALUES (:V001,:V

SQL_TEXT
--------------------------------------------------------------------------------
002,11,0,0,3,1,0,1,:V003,:V004,:V005,:V006,:V007,:V008,:V009,:V010)

INSERT INTO LOG (ID,TIME_STAMP,TYPE,ERROR,INSTANCE,RULE_NUM,RULE_TYPE,PRIORITY,F
LAGS,NAME,BATCH,O_RESOURCE,QUEUE,NEW_QUEUE,SERVER,FORM,WORKSET) VALUES (:V001,:V
002,11,0,0,3,1,0,1,:V003,:V004,:V005,:V006,:V007,:V008,:V009,:V010)

How to avoid this... why its different execution plan using (I mean bad index PK)

Is it possible to avoid this?

If any details please check out some of my previous post on this specific URL (above)

-Yasser

My doubt is how to sql even with different literal values execution plan changes and causes a prob.

Different literal values cause analysis difficult.
Hard analysis includes the re-evaluation of the best path.
Literal value is included in the assessment of the selectivity for the scan interval (log_seq >...)

See
http://www.centrexcc.com/A%20Look%20under%20The%20Hood%20Of%20CBO%20-%20The%2010053%20Event.ppt.PDF
http://www.centrexcc.com/fallacies%20Of%20The%20Cost%20Based%20Optimizer.PDF
more the book of Jonathan Lewis which other threads, I believe that you already have.

You must lower your CPU.
Previous discussions, if the situation is still the same, it sounded like hard analysis particularly with this SELECTION against the NEWSPAPER plays an important role in that.

How to avoid this... why its different execution plan using (I mean bad index PK)

The points raised in the previous discussion remain valid.
-Do you have access to this SQL to change?
for example using bind variable or trick it if necessary due to problems caused by data as discussed in the previous thread.
- Or you could it repoint the view to a view and a hint?
-If a particular user makes this sql, could affect you cursor_sharing just for this user. If not, you should consider implementing pan-Canadian database.

Oracle 8.1.6 still?

Different results from the same calculations between SQL and PL/SQL
This SQL statement:
```
select 1074 * (4 / 48) from dual;
```
Gives the 89.5 result.
However this PL/SQL block
```
declare
    tmp     NUMBER;
begin
    SELECT 1074 * (4 / 48) into tmp from dual;
    dbms_output.put_line('Result '||tmp);
end;
```
Gives a different result:
Result 89.49999999999999999999999999999999999996

If I change and give my variable tmp, a precision and scale, (38.36) say the result is 89.5.

Ed. I did about 10g (10.2.0.4.0) and 11g (11.1.0.7.0) with the same result in both.

Published by: kendenny on July 9, 2010 10:19 for more information
What is your current value of NUMLARGEUR in SQL * more (I assume that you use as your tool)?
```
SQL> set numwidth 50
SQL> select 1074 * (4 / 48) from dual;

                                       1074*(4/48)
--------------------------------------------------
         89.49999999999999999999999999999999999996
```

Different users calling different numbers for the same account

Hello

As a society, we have a single account which allows us to make phone calls. We know that more than one user, we can access the same account at the same time, however, could both users make calls at the same time? I mean the different calls.

Example:

The user has call + 39 02xxxxxxx

User B calls + 44 95xxxxxx

(both at the same time)

Thanks in advance!

Simone

Hi, Simone1984, and welcome to the community,

I recommend a careful review of the conditions of use of Skype and the policies of fair use for subscriptions, according to these apply to your business:
If I were an anti-fraud filter and I detected mulitple calls taking place at the same time, I would immediately take action, thinking that the account has been abused...

Kind regards

Elaine

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Two different front for the same VI?

Hello world!

For a project in my school, I need to use labview to project a grid on a projector and a camera to capture this control grid. I know it is possible to 'send' of frontage on a second screen (the projector in my case), but is it still possible to have a different front panel on the main screen? Do I need to use a Subvi for this?

Thanks in advance!

Lionel Schmied

I did something similar to this from LV 5. The 'projection' VI can be a Subvi, which runs in parallel with the main VI or a regular Subvi which is called in a loop in the Main VI whenever the value on the screen should be updated. The Subvi contains a hidden control for main entries and an indicator of picture for the image to be projected - no code is running inside the Subvi. The main Panel VI is on the computer screen and may be sued for control or monitor, which is expected. I have also written a 'Slide Show' program that behaves in the same way.

Lynn

Different output for the same query in SQL Server and Oracle

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