Different plan for the same sql id

Similar Questions

• Why I have two different execution plans for the same query on two different servers

  Hello everyone.

  I need your help to solve the problem quickly.

  In a nutshell, we have two servers that have the same version of Oracle RDBMS (11.2.0.4 EE). One of them for purposes of development and another is a production one.

  We have therefore two different execution plans for the same query executed on both servers. The only case of execution is OK and another is too slow.

  So I have to slow down the work of query using the same scheme to explain that young.

  Fence wire.

• explain plan for the same query diff

  Hi experts,

  Please, help me understand explain the plan.  I have tow Server (server and two server). The server are same table, even the type of database, even version Oracle (gr 11 (2), same operating system (linux Redhat 5.5) and same table and index.

  but when I explain the plan for the same query on the two server. I got diff--diff to explain the plan. reason it has different, according to my understanding, it should be same. explain please, I share the explain plan and lower indices for the two server.

  Server a

  SQL > col COLUMN_NAME format a20

  SQL > select index_name, column_name, position_colonne from user_ind_columns where table_name = 'LOAN_RUNNING_DETAILS_SOUTH"of order 1.

  INDEX_NAME COLUMN_NAME POSITION_COLONNE

  ------------------------------ -------------------- ---------------

  DATE_IND1_S LOANDATETIME 1

  IND_MSI_LN_LNS1_S MSISDN 1

  IND_MSI_LN_LNS1_S LOANDATETIME 2

  IND_MSI_LN_LNS1_S LOANSTATUS 3

  LAST_INDEX L_INDX_MSISDN_S 1

  MSISDN L_INDX_MSISDN_S 2

  SQL > select decode (status, 'N/a', 'Part Hdr', 'Global') ind_type, index_name, NULL nom_partition, status

  2 from user_indexes where table_name = 'LOAN_RUNNING_DETAILS_SOUTH '.

  3 union

  4. Select 'Local' ind_type, index_name, nom_partition, status

  5 to user_ind_partitions where index-name in (select index_name in user_indexes where table_name = 'LOAN_RUNNING_DETAILS_SOUTH')

  6 order of 1,2,3;

  IND_TYPE INDEX_NAME NOM_PARTITION STATUS

  -------- ------------------------------ ------------------------------ --------

  Global DATE_IND1_S VALID

  Global IND_MSI_LN_LNS1_S VALID

  Global L_INDX_MSISDN_S VALID

  SQL > explain plan for the small circle of MSISDN, TID, of LOAN_RUNNING_DETAILS_SOUTH where LOANDATETIME < = sysdate-2 and LOANDATETIME > sysdate-15 and LOANTYPE = 1;

  He explained.

  SQL > SQL > set line 200

  @?/rdbms/admin/utlxpls.sql

  SQL >

  PLAN_TABLE_OUTPUT

  --------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------

  Hash value of plan: 3659874059

  ------------------------------------------------------------------------------------------------------------------

  | ID | Operation | Name                       | Lines | Bytes | Cost (% CPU). Time | Pstart. Pstop |

  ------------------------------------------------------------------------------------------------------------------

  |   0 | SELECT STATEMENT |                            |  1448K |    58 M | 21973 (2) | 00:04:24 |       |       |

  |*  1 |  FILTER |                            |       |       |            |          |       |       |

  |   2.   PARTITION LIST ALL |                            |  1448K |    58 M | 21973 (2) | 00:04:24 |     1.    11.

  |*  3 |    TABLE ACCESS FULL | LOAN_RUNNING_DETAILS_SOUTH |  1448K |    58 M | 21973 (2) | 00:04:24 |     1.    11.

  ------------------------------------------------------------------------------------------------------------------

  PLAN_TABLE_OUTPUT

  --------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------

  Information of predicates (identified by the operation identity card):

  ---------------------------------------------------

  1 - filter(SYSDATE@!-2>SYSDATE@!-15)

  3 - filter("LOANTYPE"=1 AND "LOANDATETIME">SYSDATE@!-15 AND "LOANDATETIME"<=SYSDATE@!-2)

  16 selected lines.

  Second server

  SQL > select index_name, column_name, position_colonne from user_ind_columns where table_name = 'LOAN_RUNNING_DETAILS_SOUTH"of order 1.

  INDEX_NAME COLUMN_NAME POSITION_COLONNE

  ------------------------------ -------------------- ---------------

  DATE_IND1_S LOANDATETIME 1

  IND_MSI_LN_LNS1_S MSISDN 1

  IND_MSI_LN_LNS1_S LOANDATETIME 2

  IND_MSI_LN_LNS1_S LOANSTATUS 3

  LAST_INDEX L_INDX_MSISDN_S 1

  MSISDN L_INDX_MSISDN_S 2

  SQL > select decode (status, 'N/a', 'Part Hdr', 'Global') ind_type, index_name, NULL nom_partition, status

  2 from user_indexes where table_name = 'LOAN_RUNNING_DETAILS_SOUTH '.

  Union

  3 4 Select 'Local' ind_type, index_name, nom_partition, status

  5 to user_ind_partitions where index-name in (select index_name in user_indexes where table_name = 'LOAN_RUNNING_DETAILS_SOUTH')

  6 order of 1,2,3;

  IND_TYPE INDEX_NAME NOM_PARTITION STATUS

  -------- ------------------------------ ------------------------------ --------

  Global DATE_IND1_S VALID

  Global IND_MSI_LN_LNS1_S VALID

  Global L_INDX_MSISDN_S VALID

  SQL > explain plan for the small circle of MSISDN, TID, of LOAN_RUNNING_DETAILS_SOUTH where LOANDATETIME < = sysdate-2 and LOANDATETIME > sysdate-15 and LOANTYPE = 1;

  SQL > set line 200

  @?/rdbms/admin/utlxpls.sql

  SQL >

  PLAN_TABLE_OUTPUT

  --------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------

  Hash value of plan: 1161680601

  ----------------------------------------------------------------------------------------------------------------------------------

  | ID | Operation | Name                       | Lines | Bytes | Cost (% CPU). Time | Pstart. Pstop |

  ----------------------------------------------------------------------------------------------------------------------------------

  |   0 | SELECT STATEMENT |                            |     2.    84.     5 (0) | 00:00:01 |       |       |

  |*  1 |  FILTER                             |                            |       |       |            |          |       |       |

  |*  2 |   TABLE ACCESS BY INDEX ROWID | LOAN_RUNNING_DETAILS_SOUTH |     2.    84.     5 (0) | 00:00:01 | ROWID | ROWID |

  |*  3 |    INDEX RANGE SCAN | DATE_IND1_S |     2.       |     3 (0) | 00:00:01 |       |       |

  ----------------------------------------------------------------------------------------------------------------------------------

  PLAN_TABLE_OUTPUT

  --------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------

  Information of predicates (identified by the operation identity card):

  ---------------------------------------------------

  1 - filter(SYSDATE@!-2>SYSDATE@!-15)

  2 - filter ("LOANTYPE" = 1)

  3 - access("LOANDATETIME">SYSDATE@!-15 AND "LOANDATETIME"<=SYSDATE@!-2)

  17 selected lines.

  Reg,

  Hard

  Hi , HemantKChitale,

  I also update statistics manual as you say, but not see 'TABLE ACCESS FULL' good result

  What should I do? my need of production tuning, but I cannot able tune this...

  SQL > exec dbms_stats.gather_table_stats (-online 'ttt' ownname, tabname => 'LOAN_RUNNING_DETAILS_SOUTH', cascade => TRUE, estimate_percent => NULL, method_opt => 'for all columns size 254', => of degree 4);

  PL/SQL procedure successfully completed.

  SQL > explain plan for the small circle of MSISDN, TID, of LOAN_RUNNING_DETAILS_SOUTH where LOANDATETIME<=sysdate-2 and="" loandatetime="">sysdate-15 and LOANTYPE = 1;

  He explained.

  SQL > set line 200

  @?/rdbms/admin/utlxpls.sql

  SQL >

  PLAN_TABLE_OUTPUT

  --------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------

  Hash value of plan: 3659874059

  ------------------------------------------------------------------------------------------------------------------

  | ID | Operation | Name                       | Lines | Bytes | Cost (% CPU). Time | Pstart. Pstop |

  ------------------------------------------------------------------------------------------------------------------

  |   0 | SELECT STATEMENT |                            |  1874K |    75 M | 19626 (2) | 00:03:56 |       |       |

  |*  1 |  FILTER |                            |       |       |            |          |       |       |

  |   2.   PARTITION LIST ALL |                            |  1874K |    75 M | 19626 (2) | 00:03:56 |     1.    11.

  |*  3 |    TABLE ACCESS FULL | LOAN_RUNNING_DETAILS_SOUTH |  1874K |    75 M | 19626 (2) | 00:03:56 |     1.    11.

  ------------------------------------------------------------------------------------------------------------------

  PLAN_TABLE_OUTPUT

  --------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------

  Information of predicates (identified by the operation identity card):

  ---------------------------------------------------

  1 - filter(SYSDATE@!-2>SYSDATE@!-15)

  3 - filter("LOANDATETIME">SYSDATE@!-15 AND "LOANTYPE"=1 AND "LOANDATETIME")<>

  16 selected lines.

• Set a style different cases for the same placeholder (data fusion) used two times in the same text

  Hello.

  I have a document with some parties updated with the fusion of data (via placeholders). Is it possible to set a style of different cases for the same placeholder in the same text. See the example:

  Mike runs its < < vehicule_placeholder > > in the city. But its < < VEHICULE_PLACEHOLDER > > is meant to be shared.

  If the value of this placeholder in the file merger is 'bike', the sentence should be:

  Mike runs his bike in the city. But his BIKE is meant to be shared.

  Is this possible? How?

  Thank you.

  You can do it. A character style for this configuration placeholder text, set in all caps.

• Plans of multiple executions for the same SQL statement

  Dear experts,
  
  awrsqrpt. SQL shows several plans for a single SQL statement executions. How is it possible that a single SQL statement will be several Plans of executions within the AWR report.
  
  Here is the output of the awrsqrpt for your reference.
  
  

  WORKLOAD REPOSITORY SQL Report
  
  Snapshot Period Summary
  
  DB Name         DB Id    Instance     Inst Num Release     RAC Host
  ------------ ----------- ------------ -------- ----------- --- ------------
  TESTDB          2157605839 TESTDB1               1 10.2.0.3.0  YES testhost1
  
                Snap Id      Snap Time      Sessions Curs/Sess
              --------- ------------------- -------- ---------
  Begin Snap:     32541 11-Oct-08 21:00:13       248     141.1
    End Snap:     32542 11-Oct-08 21:15:06       245     143.4
     Elapsed:               14.88 (mins)
     DB Time:               12.18 (mins)
  
  SQL Summary                            DB/Inst: TESTDB/TESTDB1  Snaps: 32541-32542
  
                  Elapsed
     SQL Id      Time (ms)
  ------------- ----------
  51szt7b736bmg     25,131
  Module: SQL*Plus
  UPDATE TEST SET TEST_TRN_DAY_CL = (SELECT (NVL(ACCT_CR_BAL,0) + NVL(ACCT_DR_BAL,
  0)) FROM ACCT WHERE ACCT_TRN_DT = (:B1 ) AND TEST_ACC_NB = ACCT_ACC_NB(+)) WHERE
   TEST_BATCH_DT = (:B1 )
  
            -------------------------------------------------------------
  
  SQL ID: 51szt7b736bmg                  DB/Inst: TESTDB/TESTDB1  Snaps: 32541-32542
  -> 1st Capture and Last Capture Snap IDs
     refer to Snapshot IDs witin the snapshot range
  -> UPDATE TEST SET TEST_TRN_DAY_CL = (SELECT (NVL(ACCT_CR_BAL,0) + NVL(AC...
  
      Plan Hash           Total Elapsed                 1st Capture   Last Capture
  #   Value                    Time(ms)    Executions       Snap ID        Snap ID
  --- ---------------- ---------------- ------------- ------------- --------------
  1   2960830398                 25,131             1         32542          32542
  2   3834848140                      0             0         32542          32542
            -------------------------------------------------------------
  
  
  Plan 1(PHV: 2960830398)
  -----------------------
  
  Plan Statistics                        DB/Inst: TESTDB/TESTDB1  Snaps: 32541-32542
  -> % Total DB Time is the Elapsed Time of the SQL statement divided
     into the Total Database Time multiplied by 100
  
  Stat Name                                Statement   Per Execution % Snap
  ---------------------------------------- ---------- -------------- -------
  Elapsed Time (ms)                            25,131       25,130.7     3.4
  CPU Time (ms)                                23,270       23,270.2     3.9
  Executions                                        1            N/A     N/A
  Buffer Gets                               2,626,166    2,626,166.0    14.6
  Disk Reads                                      305          305.0     0.3
  Parse Calls                                       1            1.0     0.0
  Rows                                        371,735      371,735.0     N/A
  User I/O Wait Time (ms)                         564            N/A     N/A
  Cluster Wait Time (ms)                            0            N/A     N/A
  Application Wait Time (ms)                        0            N/A     N/A
  Concurrency Wait Time (ms)                        0            N/A     N/A
  Invalidations                                     0            N/A     N/A
  Version Count                                     2            N/A     N/A
  Sharable Mem(KB)                                 26            N/A     N/A
            -------------------------------------------------------------
  
  Execution Plan
  ------------------------------------------------------------------------------------------------
  | Id  | Operation                    | Name            | Rows  | Bytes | Cost (%CPU)| Time     |
  ------------------------------------------------------------------------------------------------
  |   0 | UPDATE STATEMENT             |                 |       |       |  1110 (100)|          |
  |   1 |  UPDATE                      | TEST            |       |       |            |          |
  |   2 |   TABLE ACCESS FULL          | TEST            |   116K|  2740K|  1110   (2)| 00:00:14 |
  |   3 |   TABLE ACCESS BY INDEX ROWID| ACCT            |     1 |    26 |     5   (0)| 00:00:01 |
  |   4 |    INDEX RANGE SCAN          | ACCT_DT_ACC_IDX |     1 |       |     4   (0)| 00:00:01 |
  ------------------------------------------------------------------------------------------------
  
  
  
  
  Plan 2(PHV: 3834848140)
  -----------------------
  
  Plan Statistics                        DB/Inst: TESTDB/TESTDB1  Snaps: 32541-32542
  -> % Total DB Time is the Elapsed Time of the SQL statement divided
     into the Total Database Time multiplied by 100
  
  Stat Name                                Statement   Per Execution % Snap
  ---------------------------------------- ---------- -------------- -------
  Elapsed Time (ms)                                 0            N/A     0.0
  CPU Time (ms)                                     0            N/A     0.0
  Executions                                        0            N/A     N/A
  Buffer Gets                                       0            N/A     0.0
  Disk Reads                                        0            N/A     0.0
  Parse Calls                                       0            N/A     0.0
  Rows                                              0            N/A     N/A
  User I/O Wait Time (ms)                           0            N/A     N/A
  Cluster Wait Time (ms)                            0            N/A     N/A
  Application Wait Time (ms)                        0            N/A     N/A
  Concurrency Wait Time (ms)                        0            N/A     N/A
  Invalidations                                     0            N/A     N/A
  Version Count                                     2            N/A     N/A
  Sharable Mem(KB)                                 26            N/A     N/A
            -------------------------------------------------------------
  
  Execution Plan
  ---------------------------------------------------------------------------------------------
  | Id  | Operation                    | Name         | Rows  | Bytes | Cost (%CPU)| Time     |
  ---------------------------------------------------------------------------------------------
  |   0 | UPDATE STATEMENT             |              |       |       |     2 (100)|          |
  |   1 |  UPDATE                      | TEST         |       |       |            |          |
  |   2 |   TABLE ACCESS BY INDEX ROWID| TEST         |     1 |    28 |     2   (0)| 00:00:01 |
  |   3 |    INDEX RANGE SCAN          | TEST_DT_IND  |     1 |       |     1   (0)| 00:00:01 |
  |   4 |   TABLE ACCESS BY INDEX ROWID| ACCT         |     1 |    26 |     4   (0)| 00:00:01 |
  |   5 |    INDEX RANGE SCAN          | INDX_ACCT_DT |     1 |       |     3   (0)| 00:00:01 |
  ---------------------------------------------------------------------------------------------
  
  
  
  Full SQL Text
  
  SQL ID       SQL Text
  ------------ -----------------------------------------------------------------
  51szt7b736bm UPDATE TEST SET TEST_TRN_DAY_CL = (SELECT (NVL(ACCT_CR_BAL, 0) +
                NVL(ACCT_DR_BAL, 0)) FROM ACCT WHERE ACCT_TRN_DT = (:B1 ) AND PB
               RN_ACC_NB = ACCT_ACC_NB(+)) WHERE TEST_BATCH_DT = (:B1 )

  Your contribution is very much appreciated.
  
  Thank you for taking your time to answer my question.
  
  
  Concerning

  Oracle Lover3 wrote:
  How will I know (from Plan 1 and Plan 2) whose execution plan chose for the current run?

  Since you're already on 10.2, you can identify the actual execution plan by checking in V$ SESSION SQL_ID and SQL_CHILD_NUMBER column. This can be used to identify the plan in V$ SQL_PLAN (columns SQL_ID and CHILD_NUMBER) and in 10g, you can use the convenient DBMS_XPLAN. Function DISPLAY_CURSOR for the information of the real plan using these two parameters.

  Kind regards
  Randolf

  Oracle related blog stuff:
  http://Oracle-Randolf.blogspot.com/

  SQLTools ++ for Oracle (Open source Oracle GUI for Windows):
  http://www.sqltools-plusplus.org:7676 /.
  http://sourceforge.NET/projects/SQLT-pp/

• Both inputs of printer with different names for the same printer

  I try to add a new printer in Windows 7 64 bit laptop.  I chose to add a printer in printers and peripherals and selected add a network, wireless or Bluetooth printer.  I have two tickets for the same printer

  

  Why are there 2 inputs and one which should I use?

  These entries are actually at the same network address (192.168.1.10).  The second address Specifies a particular port (3910).  Software print server HP Jetadmin 'web-based' uses the 3910 port to receive the print requests.  See http://h20564.www2.hp.com/hpsc/doc/public/display?docId=emr_na-c03975926

  The second is probably 'discovery of Web Services' (see http://en.wikipedia.org/wiki/WS-Discovery).  You probably don't want to use it from the "Add printer" Wizard

  I suggest to select the first entry.  This is the normal way to network printers appear in the add a Printer Wizard.  For example:

  

  If you have any problems with printing, post back and I'll see if I can diagnose the things for you.

• Different output for the same query in SQL Server and Oracle

  I have two tables table1 and table2
  
  -table1 has two columns c1 int and varchar c2. There are no constraints added in it. It contains data as shown below
  
  C1 c2
  -------------------
  d 6
  5 d
  102 g
  6%
  f 103
  5.
  501 j
  1 g
  601 n
  2 m
  
  -table2 has only a single column c1 int. There is no added in constraints. It contains data as shown below
  
  C1
  ----
  6
  1
  4
  3
  2
  
  now when I run below, given the query in sql server and oracle it gives me different results
  
  Select *.
  FROM table1
  table2 on table2.c1 = table1.c1 inner join (SELECT ROW_NUMBER() (any ORDER by ASC c1) AS c1 from table2)
  
  output of SQL server
  ------------------------
  C1 c2 c1
  --------------------------------
  1 g 1
  2 m 2
  3 h 3
  4 g 4
  5 d 5
  
  
  release of Oracle
  ----------------------
  C1 C2 C1
  ---------------------------------
  5 d 5
  4 g 4
  3 h 3
  1 g 1
  2 m 2
  
  
  If you notice the first column in the two outputs. It is sorted in sql server and no oracle.
  
  Why he behaves differently in oracle? Is there a way I can fix this problem in oracle?
  
  Thank you
  Jigs

  It is NOT a behavior "differently" in Oracle; you did not specify just an order that you expect of your results, so you'll get output in what order the fantasies of the database showing (ie. no guaranteed order). It is an artifact of the way the database chooses to collect the data and databases (or same sets of data within the same database) can and will most likely behave differently.

  Same SQL Server will not be guaranteed to always get your data in an orderly manner if you exclude the order by clause, even if you think that there always display the data in an orderly manner.

  Your solution is to add an order by clause, in the TWO databases, to force the order of the data output.

• Different users calling different numbers for the same account

  Hello

  As a society, we have a single account which allows us to make phone calls. We know that more than one user, we can access the same account at the same time, however, could both users make calls at the same time? I mean the different calls.

  Example:

  The user has call + 39 02xxxxxxx

  User B calls + 44 95xxxxxx

  (both at the same time)

  Thanks in advance!

  Simone

  Hi, Simone1984, and welcome to the community,

  I recommend a careful review of the conditions of use of Skype and the policies of fair use for subscriptions, according to these apply to your business:

  • http://www.Skype.com/en/legal/TOU/
  
  
  • http://www.Skype.com/en/legal/business-TOU/
  
  
  • http://www.Skype.com/en/legal/fair-usage/

  If I were an anti-fraud filter and I detected mulitple calls taking place at the same time, I would immediately take action, thinking that the account has been abused...

  Kind regards

  Elaine

  __________________________________________________________________________________________________
  Your question has been answered? Please click on the link to accept as a Solutionfor everyone can quickly find what works! As a post or want to say, 'Thank You ' -? Click on the button of congratulations!
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• Two different front for the same VI?

  Hello world!

  For a project in my school, I need to use labview to project a grid on a projector and a camera to capture this control grid. I know it is possible to 'send' of frontage on a second screen (the projector in my case), but is it still possible to have a different front panel on the main screen? Do I need to use a Subvi for this?

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  Lionel Schmied

  I did something similar to this from LV 5.  The 'projection' VI can be a Subvi, which runs in parallel with the main VI or a regular Subvi which is called in a loop in the Main VI whenever the value on the screen should be updated. The Subvi contains a hidden control for main entries and an indicator of picture for the image to be projected - no code is running inside the Subvi.  The main Panel VI is on the computer screen and may be sued for control or monitor, which is expected.  I have also written a 'Slide Show' program that behaves in the same way.

  Lynn

• Why do I get different results for the same resolution but different boxes of Windows, Windows 7 and XP

  I use an .exe on two different windows boxes, in Windows 7 and XP.  I put both for resolution 1024 x 768.

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  Has anyone go through this before?

  System for XP and Vista/Win7 fonts are different.

  See

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  http://forums.NI.com/T5/LabVIEW/what-can-affect-the-size-of-a-front-panel-object-between/m-p/1058607...

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• PPID different BBM for the same user

  Hello! I found that my app is having a weird behavior when I get the ppid of the user. I try to use the ppid as a key into a table of users in a database for my application, and I noticed that I have two different ppid, even thoug I am the only one using my app (it is still in development).

  What I find weird is that I have 2 versions of my application, I can dounload the store (it is in draft mode) and one I directly load on my camera on my development machine. These 2 apps get the ppid 2 different to the same user BBM.

  PPID does has something to do with my application being downloaded from the store or loaded directly? Has anyone dealt a similar problem?

  Thanks in advance!

  Reedd.

  What is expected.  PPID is unique user ID of BBM in the context of the application, which means same user PPID will be different for each application stored on the device.

  The identifiers used to register with BBM are different depending on whether you load the application or install the application for the BlackBerry World.  When you side load application name UUID / provider are used.  When you install BlackBerry World the application ID and SKUS are used.  This will give you two groups of users (two sets of PPID), one for testing and one for production.

  Also, if you change an item as your UUID or SKU you will also cause a new PPID to create.

• Different encryption data on different machines for the same input data

  Hello
  I have 2 windows 64-bit machines and I run an application on two of them exporting an Excel with encrypted data. I am using the same data is encrypted in application that gets encrypted, but differs from the (encrypted) encryption algorithm occurs on these 2 machines.
  Can anyone help identify the root cause?
  Version of the application, the version of windows etc. are all the same on both machines.
  This issue is beyond the scope of this site (for consumers) and to be sure, you get the best (and fastest) reply, we have to ask either on Technet (for IT Pro) or MSDN (for developers)
  http://social.technet.Microsoft.com/forums/en-us/home s/fr-U.S./Accueil
  http://social.msdn.Microsoft.com/Forum
  
  
  If you give us a link to the new thread we can point to some resources it

• content of the different session for the same session, CF9

  Two URLS:

  http://domain/zshowsession.cfm

  http://domain/institutes/Office/zshowsession.cfm

  The DOMAIN part is identical.  Same site.  Same server see

  The two files contain this code:

  < cfdump var = "#session #" >

  A poster this:

  

  The other displays this:

  

  You can see it's the same cfid and cftoken, but the session content is different.  It causes me problems.

  Someone is aware of any legitimate reason, why this is happening?  Maybe some configurations weird CF in the CFIDE or something?  I already checked the two relevant Application.cfc files (one in /, one in institutes) and there is nothing that changes the session.

  I fixed it.  The problem was that both Application.cfc files have different values for myIdName.  When I made them equal session data becomes synchronized.

• How do I put 4 different RADIUS for the same element?

  I work with a rectangle and I need to set the radius of the top left corner at 100 and 10 other 3 corners.

  Hello

  Unfortunately, this is not possible. You can have two different RADIUS for corner, to the same rectangle. You can only activate/RADIUS for each corner. But if they are enabled, all the corner will have the same RADIUS.

• different results for the same statement 9i / 10g why?

  Hi all
  
  I have problem in the SQL statement that it worked very well in oracle 9i, once I upgrade to 10g, this statement does not work
  
  I create a table:
  create table TEST_TAB (colA tank (6));
  
  insert into TEST_TAB values ('A');
  
  now when I run the following statement in oracle 9i
  
  Select count (*)
  of TEST_TAB
  where colA as "A";
  
  
  Count (*)
  ---------------
  1
  
  But in oracle 10g
  
  It gives
  Count (*)
  -----------
  0
  
  I know I can fix education by adding % at the end to bring data or triming CLC, but I can't because that statement use frequently in the application source
  
  My question, how can I solve this problem, what the related setting for this I check all the nls_... setting, it's the same in oracle 9i
  
  
  all boards

  Yes, it's Bug 2883715 possible bad results of AS against a column of type CHAR with no wildcard

  [Bug 2883715| https://metalink.oracle.com/metalink/plsql/showdoc?db=NOT&id=2883715.8]

  If you have everything you need to tell the developers what needs to be done.