Disadvantages of the default tablespace using to store data from the partitioned table?

Similar Questions

• Create index partition in the partition table tablespace

  Hello
  
  I am running a work custom that
  
  * Creates a tablespace by day
  * Creates the daily table partition in the created tablespace
  * Removes the days tablepartition X
  * Removes the storage space for this partition of X + 1 day.
  
  The work above works perfectly, but it has problems with the management of the index for these partitioned tables. In the old database (10g - single node), all indexes and partitions exist in a BIG tablespace and when I imported the table creation script in the new database, I changed all the partitions table & index to go in their respective space.
  
  For example:
  
  Table_name... Nom_partition... Index_Part_name... Tablespace_name
  ============...================............====================...........=================
  TABL1... TABL1_2012_07_16... TABL1_IDX_2012_07_16... TBS_2012_07_16
  TABL1... TABL1_2012_07_15... TABL1_IDX_2012_07_15... TBS_2012_07_15
  
  
  But now, when the job is run, it creates the index in the tablespace TBS_DATA default.
  
  Table_name... Nom_partition... Index_Part_name... Tablespace_name
  ============...================.............====================...........=================
  TABL1... TABL1_2012_08_16... TABL1_IDX_2012_08_16... TBS_DATA
  TABL1... TABL1_2012_08_15... TABL1_IDX_2012_08_15... TBS_DATA
  
  
  I can issue alter index rebuild to move the index to its tablespace default, but how can I make sure that the index is created in the designated tablespace?
  
  NOTE: the partition/tablespace management work that I run only creates the partition of the table and not the index.
  
  
  The new env is a cluster of CARS of 2 nodes 11 GR 2 on Linux x86_64.
  
  
  Thanks in advance,
  aBBy.

  try something like this

  ALTER table tab_owner.tab_name add the partition v_new_part_nm
  values less (to_date('''|| v_new_part_dt_formatted ||'') ((', "DD-MON-YYYY)) tablespace ' | part_tbs
  update the index (ind1_name (partition ind_partition_name tablespace ind_part_tbs)
  ind2_name (partition tablespace ind_part_tbs ind_partition_name))
  ;

• How to configure the partition table for SSD?

  Drive: 32 GB SSD

  I accidentally delete without backup partition table information and would like to know how to put the partition table, I can access the tools of partition table, but do not know how to define.

  Does anyone have any suggestions?

  Thanks in advance for your suggestions

  Hello

  Thanks for posting your query in Microsoft Community.

  The SSD could be seen in the disk management window, and you could name and set up as another hard drive internal. To create a partition or volume on a hard disk, you must be logged in as an administrator, and there must be unallocated disk space or free space in an extended hard disk partition. To repartition your hard drive, please consult the following link and check if it helps.

  I can I repartition my hard disk?

  Additional information:

  Create a new Partition on a hard disk in Windows 7

  Hope this information is useful. Let us know if you need more help, we will be happy to help you.

• Assistance button works do not (= does ' t start VAIO Care Rescue) after having lost and recover the partition table / MBR

  Hello

  For some reason that I lost my patition table but I was able to get it back and I'm rewriting MBR. I'll be back all my partition and files contain the VAIO recovery partition except files on the operating system partition ("C:\ »). It's an unformatted partition. VAIO Care rescue didn't work so I had to format "C:\". "and reinstall windows 7 and now all is good.

  I have VAIO Care Rescue. I think that it is enough to change the partition table / MBR. What exactly is the problem and is it possible to fix the problem of button Assist?

  
  And if one removes all xxxx (include VAIO Recovery) and creates new ones, is it possible, software or image of the recovery restore partition and Assist button start VAIO Care Rescue?

  My laptop model: VPCEA25FG

  Thank you

  You can restore your computer back to factory with all the pre program and software installed by using recovery discs. For further assistance, please recommend contacting Sony's Support Center in your area at http://www.sony-asia.com/support/product/VPCEA25FGfor your model of Asia-Pacific computer. Thank you.

  If my post answered your question, please mark it as "accept as a Solution.

• Desperately need help - "the partition table on device sda was unreadable." Erase all data?

  I'm forced to install CentOs on my Macbook using a machine virtual (VMWare, which is what I downloaded my teacher recommended). It's for my first class of operating systems, so bare with me because I don't know anything about operating systems (except about how to use Windows and my Macbook). I am also a daughter, what makes my same technical knowledge that much more rare. However, I am eager to learn...

  In any case, I downloaded them both. When I launch Fusion, I choose the file> New> install Windows or another OS on a virtual machine> continue without disk> click on the button that says 'Operating system installation disc using image file'> then I select the appropriate iso CentOS (CentOS - 5.4 - i386-bin-1of6) file> continue> drop down lists, I choose LINUX as operating system and Red Hat Enterprise Linux 5 as my Version> continue-> finish (no customization settings). It appears the screen of CentOS and I am invited by a text asking me if I want to install in text or graphics mode. (Don't know what to do here, but I select the graph). A bunch of white text scroll a screen of black background, then a blue screen shows up saying: 'Welcome to CentOS' at the top and a gray screen that says "to start testing CD media before installation OK press. Choose Ignore to ignore the media test and launch the installation. "I click on the red button (even once, if it is incorrect, let me know). A few rows of white text on black background (from anaconda... something on a video card...) then a nice graphic display of CentOS which I click NEXT. I then select English as my tongue (twice) and I gives me the message:

  "The partition table on device sda (VMware, VMware Virtual S 20473 MB) was unreadable. To create new partitions, it must be initialized, cauing the loss of all DATA on this drive. This operation will replace all choice on what players to ignore previous installation. You would like to initialize this drive, erasing all THE DATA? »

  I have no idea what to do here. I googled the message and others have been too, but they can talk about some hard file (and I have no idea what it is, and I can't seem to find mine).

  I can't lose what's on my hard drive (my school, music, photos, applications, files etc.). Clicking YES will erase my HD? I'm terribly afraid. I need to get this thing installed so I can do my operating systems class work, but I don't know if I did the installation correctly so far and especially, what to click at this point. Can someone help me out please (I spent 4 hours on this one today. "I have no one else to ask)? Finally, the installation is almost done after this step?

  Any help at all would be so greatly appreciated.

  I do not use Fusion, but I have VMware Workstation on Windows. I went through the same process that you went through. The answer to your question is that when you choose the operating system you install and you choose the option for the installation disc, it creates a virtual hard drive for you, size 20 GB. When they ask you to erase the hard drive, it's clear that virtual you create, not your actual computer hard drive. You can check by looking at the properties of the hard drive on your computer. It's probably 250 GB or 500 GB or something big like this. The CentOS WARNING speaks of a 20 GB hard drive, which is the size of the disk that VMware Fusion (and Workstation) create for CentOS.

• Why the partitioned table cannot create?

  Why the partitioned table cannot successfully create?

  SQL> create table hr.gps_log_his
    2  (id number,
    3  name varchar2(10),
    4  time date)
    5  tablespace ts_log_his
    6  PARTITION BY RANGE (TIME)
    7  (PARTITION udp_part2009110707 VALUES LESS THAN (TO_DATE('2009110708','yyyymmddhh24')),
    8  PARTITION udp_part2009110708 VALUES LESS THAN (TO_DATE('2009110709','yyyymmddhh24')),
    9  PARTITION udp_part2009110709 VALUES LESS THAN (TO_DATE('2009110710','yyyymmddhh24')),
   10  );
  )
  *
  Error in line 10:
  ORA-14004: Missing PARTITION key word.

  Hello

  Your problem is the comma ending line 9. Delete this.

  Concerning
  Peter

• query the partition tables

  Hi all
  
  I want to query the partition tables that are over 1 GB in size?
  
  How can I ask questions?

  Salvation;

  You can also try with dba_tab_partitions view

  Respect of
  HELIOS

• How to find the size of the partitioned tables?

  How to find the size of the partitioned tables?

  Select nom_segment, sum (bytes) /(1024*1024) 'Size in MB' from dba_segments
  where owner = 'owner name' and segment_type like '% PARTITION % '.
  Group by nom_segment;

• Store data from the Serial Port in the buffer and then take action?

  Hello! Everyone,

  I'm new to LabVIEW and I take assistance from various videos and stuffs available online to get started with LabVIEW.

  But I have a duty, therefore needing help.

  initially I see some of the tutorial videos and learned about the LabVIEW interface, and does a little project to communicate with the Port series (receiving and sending data).

  Happens to my task.

  My LabVIEW application will send a few State request packets on my device or control and based on the response packet that I have to display values.

  The Structure of package is as

  Header, length, Op_Code, data Checksum

  There is no terminator as newline or carriage return or anything else.

  In C language, I read the data from the Serial Port, and based on the length, I conclude that I got the full package or not, and then by recalculating the checksum value, the integrity of the package is verified and then based on that Op-Code has been sent will be decided.

  (I'm dealing with hexadecimal data)

  But how can I do this in LabVIEW.
  A tutorial or any referece will be useful for me.

  1. I suggest that you learn to use Shift Registers instead of local and global variables.  They are much more efficient (memory and execution speed) and make it much easier to read the schema.

  2. you don't need this inside the loop property node.  Is there a way to configure a Serial Port to turn off the stop character.

  3. you don't need to wait for playback VISA will limit the rate of loop if no data is coming.

  4. Once you have the length, you simply read the rest of the entire message and process it at a time.  This will make things a LOT faster.

  5. you should really do this enum a def type so that you can ensure that all your enum constants have the same values.  If you need to add a State later, simply update your enum in the same place then.

  

• Load data from an intermediate table into a real table by using the value of the indicator

  I need a code quick and dirty pl/sql to read the intermediate table ' STG_TABLE, line by line and load data into a PROD_TABLE.» The load should fail altogether, is a restoration should occur when he there an error occurs during registration to insert into a table of production using a flag value of Y as outcome and N as a failure.
  Any suggestions?

  Hello

  It seems that if you want something like:

  BEGIN
      :ok_flag := 'N';
      INSERT INTO  prod_table (col1, col2, ...)
       SELECT               col1, col2, ...
       FROM     stg_table;
      :ok_flag := 'Y';
  END;
  

  RESTORATION is done automatically in case of error.

  Instead of a link to ok_flag variable, you can use another type of variable that is defined outside the scope of this PL/SQL code.

  Published by: Frank Kulash, June 5, 2012 22:47

• Which service API should I use to retrieve data from Eloqua 'Integration of the internal queue'?

  In my Eloqua Sandbox environment, I managed to create several "external Test calls complete" that appear on the tab 'Reports of the integration of queue internally'. Can someone tell me what Eloqua API or services are required to recover the data of this "Internal queue" Eloqua? I guess that's the way to connect the dots of data updates occurring in Eloqua to an external system. My ultimate goal is personalized with a non-native CRM integration.

  Thank you

  Heath

  Hi Heath,

  The post following (How to recover data from activity through the API) describes how to extract data from the queue inside.

  Hope this helps and please let me know if you need more information.

  Thank you

  Fred

• I want to loop through the data from two different tables using for loop where the query should be replaced at runtime, please help me

  I have the data into two table with the structure of similar column, I want to loop through the data in these two tables

  based on some condition and runtime that I want to put the query in loop for example, the example is given, please help me

  create table ab (a number, b varchar2 (20));

  Insert into ab

  Select rownum, rownum. "" sample "

  of the double

  connect by level < = 10

  create table bc (a number, b varchar2 (20));

  Insert into BC.

  Select rownum + 1, rownum + 1 | "" sample "

  of the double

  connect by level < = 10

  declare

  l_statement varchar2 (2000);

  Boolean bool;

  Start

  bool: = true;

  If it is true, then

  l_statement: =' select * ab ';

  on the other

  l_statement: =' select * from bc';

  end if

  I'm in execute immediate l_statement - something like that, but I don't know

  loop

  dbms_output.put_line (i.a);

  end loop;

  end;

  Something like that, but this isn't a peace of the code work.

  Try this and adapt according to your needs:

  declare

  l_statement varchar2 (2000);

  c SYS_REFCURSOR;

  l_a number;

  l_b varchar2 (20);

  Boolean bool;

  Start

  bool: = true;

  If it is true, then

  l_statement: = "select a, b, AB;

  on the other

  l_statement: = "select a, b from bc;

  end if;

  --

  Open c for l_statement;

  --

  loop

  extract the c in l_a, l_b;

  When the output c % notfound;

  dbms_output.put_line (l_a |') -' || l_b);

  end loop;

  close c;

  end;

  /

• Why not all the partition tables

  Hello
  
  In our project we propse to all partition tables (even if they are small, in MBs) in order to use the feature partiion exchange.
  But our DBAs say that maintenance will be a problem if create us partitions for each table. We said, only tablespace is fine for all partitions that we thought to maintain storage different is a problem.
  But always DBA are not approved.
  I just want to know what are the disadvantages of partitioning. Why DBA are generally against the idea of creating partitions. If we use the same storage space for all of the partitions is there any side down for creating partitions for each table?
  Is there is disadvantage?
  
  
  
  Thank you
  Pramod Garre

  Pramod Garre wrote:
  We plan to use range partitioning (in the quarters).
  There is a duty to remove a quarter of the table data, then refresh with new data as and when the user update some recored of frontend.this should arrive in real-time.

  Looks like you are having the app trigger partition management... which doesn't seem a good idea.
  It also looks like you really don't have justification for partitioning on a few tables. Far from being the "all" tables you inquired. And even that looks like your concept of the use of these scores may be wrong.

  Why not work with your databases instead of look at foreigners for the justification to fight them. Sounds to me like they are doing exactly what they were hired to do.

  We thought instead of delete and insert, if we use excahnge partitions, it will be real quick as Exchange just updated partition in the dictionary.
  On these lines, do you think that it be the disadvantages of the use of partitioning?

  Note: Delete and Insert works OK (2 minutes) compared to the swap partition (20 ms).

  And Yes, each table has PK.

  Thank you
  Pramod Garre

• Unique key on the partitioned table range

  Hello
  
  We use a range of composite range-hash partitioned table
  
  Use index - try to do this have same tablespace to the local partitions but not liking it
  
  ALTER table RETAILER_TRANSACTION_COMP_POR
  Add primary key constraint RETAILER_TRANSACTION_COMP_PK (DWH_NUM)
  using index
  LOCAL
  
  
  ORA-14039: partitioning columns must be a subset of the columns in a unique index key
  
  Without local then fine but does not have same tablespace to walls and don't want to make this part of the partition key.
  
  Range Tbal partitioned - it's just a UK to avoid duplicates

  [oracle@localhost ~]$ oerr ora 14039
  14039, 00000, "partitioning columns must form a subset of key columns of a UNIQUE index"
  // *Cause:  User attempted to create a UNIQUE partitioned index whose
  //          partitioning columns do not form a subset of its key columns
  //          which is illegal
  // *Action: If the user, indeed, desired to create an index whose
  //          partitioning columns do not form a subset of its key columns,
  //          it must be created as non-UNIQUE; otherwise, correct the
  //          list of key and/or partitioning columns to ensure that the index'
  //          partitioning columns form a subset of its key columns
  

• Try to convert the partitioned Table of interval in the range... Swap partition...

  Requirement:
  
  Interval of replacement partitioned Table by range partitioned Table
  

  DROP TABLE A;
  
  CREATE TABLE A
  (
     a              NUMBER,
     CreationDate   DATE
  )
  PARTITION BY RANGE (CreationDate)
     INTERVAL ( NUMTODSINTERVAL (30, 'DAY') )
     (PARTITION P_FIRST
         VALUES LESS THAN (TIMESTAMP ' 2001-01-01 00:00:00'));
  
  
  INSERT INTO A
       VALUES (1, SYSDATE);
  
  INSERT INTO A
       VALUES (1, SYSDATE - 30);
  
  INSERT INTO A
       VALUES (1, SYSDATE - 60);

  I need to change this partitioned Table apart to a partitioned range Table. I can do using the EXCHANGE PARTITION. Like if I use the classic method to create another table range partitioned, then:
  
  

  DROP TABLE A_Range
  CREATE TABLE A_Range
  (
  a NUMBER,
  CreationDate DATE
  )
  PARTITION BY RANGE (CreationDate)
     (partition MAX values less than (MAXVALUE));
  
  Insert  /*+ append */  into A_Range Select * from A; --This Step takes very very long..Trying to cut it short using Exchange Partition.

  Problems:
  
  I can't do
  

   ALTER TABLE A_Range
    EXCHANGE PARTITION MAX
    WITH TABLE A
    WITHOUT VALIDATION;
   

  ORA-14095: ALTER TABLE CHANGE requires a not partitioned table nonclustered
  This is because the tables are partitioned. So it does not allow me.
  
  If I instead:
  
  
  Create a table that is not partitioned for exchanging data by partition.
  

    Create Table A_Temp as Select * from A;
    
     ALTER TABLE A_Range
    EXCHANGE PARTITION MAX
    WITH TABLE A_TEMP
    WITHOUT VALIDATION;
     
    select count(*) from A_Range partition(MAX);
   

  -The problem is that all the data is in MAX Partition.
  Even after the creation of a large number of partitions by walls of separation, the data is still in MAX Partition only.
  
  So:
  
  -What we cannot replace a partitioned Table to the Table partitioned using the EXCHANGE PARTITION range interval. that is, we have to insert in...
  -We can do it, but I'm missing something here.
  -If all the data is in MAX Partition due to "WITHOUT VALIDATION", can say us be redistributed in the right type of range partitions.

  You must pre-create the partitions in a_range and then swap one for one for a tmp, and then to arange. With the help of your sample (thanks to proviing code, incidentally).

  SQL> CREATE TABLE A
    2  (
    3     a              NUMBER,
    4     CreationDate   DATE
    5  )
    6  PARTITION BY RANGE (CreationDate)
    7     INTERVAL ( NUMTODSINTERVAL (30, 'DAY') )
    8     (PARTITION P_FIRST
    9         VALUES LESS THAN (TIMESTAMP ' 2001-01-01 00:00:00'));
  
  Table created.
  
  SQL> INSERT INTO A VALUES (1, SYSDATE);
  
  1 row created.
  
  SQL> INSERT INTO A VALUES (1, SYSDATE - 30);
  
  1 row created.
  
  SQL> INSERT INTO A VALUES (1, SYSDATE - 60);
  
  1 row created.
  
  SQL> commit;
  
  Commit complete.
  

  You can find the form of existing partitions assistance:

  SQL> select table_name, partition_name, high_value
    2  from user_tab_partitions
    3  where table_name = 'A';
  
  TABLE_NAME PARTITION_NAME HIGH_VALUE
  ---------- -------------- --------------------------------------------------------------------------------
  A          P_FIRST        TO_DATE(' 2001-01-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA
  A          SYS_P44        TO_DATE(' 2013-01-28 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA
  A          SYS_P45        TO_DATE(' 2012-12-29 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA
  A          SYS_P46        TO_DATE(' 2012-11-29 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA
  

  You can then create the table a_range with apporopriate partitions. Note that you may need to create additional in a_range partitions because the partitioning interval does not create the partitions has no data for, even if that leaves 'holes' in the partitioning scheme. So, on that basis:

  SQL> CREATE TABLE A_Range (
    2     a NUMBER,
    3     CreationDate DATE)
    4  PARTITION BY RANGE (CreationDate)
    5     (partition Nov_2012 values less than (to_date('30-nov-2012', 'dd-mon-yyyy')),
    6      partition Dec_2012 values less than (to_date('31-dec-2012', 'dd-mon-yyyy')),
    7      partition Jan_2013 values less than (to_date('31-jan-2013', 'dd-mon-yyyy')),
    8      partition MAX values less than (MAXVALUE));
  
  Table created.
  

  Now, create a regular table to use in the constituencies:

  SQL> CREATE TABLE A_tmp (
    2     a              NUMBER,
    3     CreationDate   DATE);
  
  Table created.
  

  and all partitions in Exchange:

  SQL> ALTER TABLE A
    2    EXCHANGE PARTITION sys_p44
    3    WITH TABLE A_tmp;
  
  Table altered.
  
  SQL> ALTER TABLE A_Range
    2    EXCHANGE PARTITION jan_2013
    3    WITH TABLE A_tmp;
  
  Table altered.
  
  SQL> ALTER TABLE A
    2    EXCHANGE PARTITION sys_p45
    3    WITH TABLE A_tmp;
  
  Table altered.
  
  SQL> ALTER TABLE A_Range
    2    EXCHANGE PARTITION dec_2012
    3    WITH TABLE A_tmp;
  
  Table altered.
  
  SQL> ALTER TABLE A
    2    EXCHANGE PARTITION sys_p46
    3    WITH TABLE A_tmp;
  
  Table altered.
  
  SQL> ALTER TABLE A_Range
    2    EXCHANGE PARTITION nov_2012
    3    WITH TABLE A_tmp;
  
  Table altered.
  
  SQL> select * from a;
  
  no rows selected
  
  SQL> select * from a_range;
  
           A CREATIOND
  ---------- ---------
           1 23-NOV-12
           1 23-DEC-12
           1 22-JAN-13
  

  John