Display the success Message in a Popup Style

Apex 4.2

Is it possible to display success messages in a popup style.

For example, as the apex notification plugin

Gus

Hi Gus,

Gus C wrote:

Hello

I got this job using the third link above

Process using notification plugin success message

I have a few questions.

When I save the changes, the notification appears, but is the standard message.

If I uncheck the display success message box in the branch, or poster then.

How can I just have the display of notification

How can I get this to work, when you use the Skillbuilders Page modal plugin

Gus

Do not turn off the indicator of successful display, instead of this message you can remove the standard success message by adding the following to your Page-> Execute attributes when the charges article page:

$("div#success-message").hide();

More better if you add this to zero page if you prefer to use throughout the application.

About, Skillbuilders Modal plugin Page I would say please submit more information or if possible set up for example in apex.oracle.com.

I hope this helps!

Kind regards

Kiran

Tags: Database

Similar Questions

  • How to display the success Message on the left side of the screen

    I have a message for success of the process after the process of ApplyMRU * #MRU_COUNT # line (s) update *. By default, this message is displayed in the center of the screen. I want to show this message to the left of the screen.

    I use APEX 4.0; Sand theme - 10. I tried to change the position of success message alignment in the Page template - level tabs, HTML Body section. But I'm not having any luck.

    Someone know how to change/replace the default position for the success message?

    Thank you

    Hello DP,.

    Try this...

    
    

    Thank you
    Machaan

  • The separate display - process success Message - for INSERT/UPDATE/DELETE

    Hello

    When we either Insert/update/delete records of shape of the APEX, it fires the Page - processing of automatic line (DML) process and displays the following message - process success Message

    -File has been processed.

    Is there a way for each of them, we can change this message...
    I mean, if the creation of a new record - message should be - record has been created... his way... If update... * manual has been updated *... and so on...

    Thank you
    Deepak

    Hello

    One way is to create a component hidden from this page and calculation value according page submit the request.
    for example if the application is updated then the item value record has been updated.

    Then put this point to the message of successful treatment of automatic line (DML) as & Px_YOUR_ITEM.

    Hope this helps

    BR, Jari

  • Not displaying not success message

    I'll put the success message in a process page using
    apex_application.g_print_success_message := 'Something here'
    But it does not appear when the page is sent. The process runs without a doubt and it seems that #SUCCESS_MESSAGE # is in the page template. The model looks like:
    <td  valign="top" id="t14ContentMiddle"><div id="t14Messages">#GLOBAL_NOTIFICATION##SUCCESS_MESSAGE##NOTIFICATION_MESSAGE#</div>
    #BOX_BODY#</td>
    And the region of messages displays on Firebug as:
    <div id="t14Messages"/>
    It seems that everything is OK... no matter what else I need to check?

    Try just checking the box show message in your branch.

    Gus

  • Line break in the success message

    I want to display messages of success in this way:
    Message1
    Message2
    Message3
    ...

    But it is currently displayed in this way:
    Message1Message2Message3...

    I tried to combine my processes in a single process like this
    declare
       v_vc_message   varchar2(200);
    begin
       -- process 1
       /* my process*/
       v_vc_message := 'Succes message1';
       
       -- process 2
       /* my process*/
       
       if v_vc_message is null then
          v_vc_message := 'Succes message2';
       else
          v_vc_message := v_vc_message || *[char_for_line_break]* || 'Succes message2';
       end if;
       
       :P17_MESSAGE_PR := v_vc_message;
    exception when others then 
       :P17_MESSAGE_PR := 'Error message';
    end;
    and then I put &. P17_MESSAGE_PR in my message of error and success

    I tried different things to get a line break.
    I tried
    '<br>'
    '&# 60;br&# 62;'  (without the spaces)
    chr(10) || chr(13)
    Can someone help me?

    Thank you

    Max,

    I tested on my application using
    , and Interestingly, it has to do with what type of element that you choose to use

    If: P9_MSG (yours is: P17_MESSAGE_PR) is just a hidden element or text, it won't work. But if it's "View only" type, it will work.

    Note that you can conditionally display the item forever, so that you won't see it.

    DECLARE
     v1 varchar2(30) := 'Succes message1';
     v2 varchar2(30) := 'Succes message2';
     v3 varchar2(40) := to_char(sysdate,'hh24:mi:ss');
    BEGIN
     :P9_MSG := v1 || '
    ' || v2 || '
    ' || v3; END;

    Then it's what in the success message

    & P9_MSG.

    Sample is at
    http://Apex.Oracle.com/pls/OTN/f?p=51832:9

    Published by: Alphonse on March 12, 2009 22:49

  • Unable to display the error message using the controller extension

    Hello

    I am trying to extend standard iproc CheckoutDistsCO. I have to display the error message when the quantity entered is '0 '. So I wrote logical when you click on the apply"" button. I created an extension CheckoutDistsCOEx & written logic here... but I am able to see messages in the log file, but no error message on screen.

    After having many forums I place super.processFormRequest (pageContext, webBean); at the end. It start always error message.

    Standard CheckoutDistsCO has a logic in the button apply. I think it is the substitution of the extension code... How can I fix? Pointers appreciated please

    package xxtr.oracle.apps.icx.por.req.webui;

    Import oracle.apps.fnd.framework.OAApplicationModule;

    Import oracle.apps.fnd.framework.OAException;

    Import oracle.apps.fnd.framework.OAFwkConstants;

    Import oracle.apps.fnd.framework.OARow;

    Import oracle.apps.fnd.framework.OAViewObject;

    Import oracle.apps.fnd.framework.webui.OAPageContext;

    Import oracle.apps.fnd.framework.webui.beans.OAWebBean;

    Import oracle.apps.fnd.framework.webui.beans.table.OAAdvancedTableBean;

    Import oracle.apps.icx.por.req.webui.CheckoutDistsCO;

    Import oracle.jbo.domain.Number;

    java.lang.String import;

    public class CheckoutDistsCOEx

    extends from {CheckoutDistsCO}

    {} public processRequest Sub (pageContext OAPageContext, OAWebBean webBean)

    super.processRequest (pageContext, webBean);

    }

    {public processFormRequest (pageContext OAPageContext, OAWebBean webBean) Sub

    super.processFormRequest (pageContext, webBean);

    OAApplicationModule am = pageContext.getApplicationModule (webBean);

    pageContext.writeDiagnostics (this, 'seized in PFR method", OAFwkConstants.STATEMENT);

    If (pageContext.getParameter ("Return")! = null) {}

    String applyevent = pageContext.getParameter (EVENT_PARAM);

    If (applyevent.equalsIgnoreCase ("return")) {}

    pageContext.writeDiagnostics (this, "clicked the Apply-back button" + applyevent, OAFwkConstants.STATEMENT ");

    OAException message = new OAException ("clicked on Apply-back put the message in the dialog box" + applyevent, OAException.INFORMATION);

    pageContext.putDialogMessage (message);

    OAViewObject poreqdistvo = (OAViewObject) am.findViewObject ("PoReqDistributionsVO");

    pageContext.writeDiagnostics (this, "display object = >" + poreqdistvo, OAFwkConstants.STATEMENT);

    OAAdvancedTableBean xxProjectDistsAdvTable = (OAAdvancedTableBean) webBean.findChildRecursive("ProjectDistsAdvTable");

    Line OARow = (OARow) poreqdistvo.getCurrentRow ();

    If (line! = null) {}

    pageContext.writeDiagnostics (this, "line Found"+ row, OAFwkConstants.STATEMENT);

    Number of xxtrqty = (Number) row.getAttribute ("ReqLineQuantity");

    pageContext.writeDiagnostics (Thi, "get attribute reqlinequantity" + xxtrqty, OAFwkConstants.STATEMENT);

    If (xxtrqty.intValue () == 0) {}

    pageContext.writeDiagnostics (this, "in comparing to 0 xxtrqty" + xxtrqty.intValue (), OAFwkConstants.STATEMENT);

    throw new OAException ("Enter valid amount", OAException.ERROR);

    }

    }

    else {}

    throw new OAException ("no line Found Else", OAException.ERROR);

    }

    }

    else {}

    throw new OAException ("not in"apply button", OAException.ERROR);

    }

    super.processFormRequest (pageContext, webBean);

    }

    }

    Thank you

    TR

    For example, when you comment on the super. PFR, you receive the error message on the right of the screen?

    Can you try this code and paste the debug log.

    public class CheckoutDistsCOEx extends CheckoutDistsCO {
        public void processRequest(OAPageContext pageContext, OAWebBean webBean) {
            super.processRequest(pageContext, webBean);
        }
    
       public void processFormRequest(OAPageContext pageContext, OAWebBean webBean) {
      //super.processFormRequest(pageContext, webBean);
            OAApplicationModule am = pageContext.getApplicationModule(webBean);
            pageContext.writeDiagnostics(this, " ----> Entered into PFR Method", OAFwkConstants.STATEMENT);
            String applyevent = pageContext.getParameter(EVENT_PARAM);
      pageContext.writeDiagnostics(this, " ----> applyevent: " + applyevent, OAFwkConstants.STATEMENT);
            if (applyevent.equalsIgnoreCase("return")){
      pageContext.writeDiagnostics(this, " ----> Inside If", OAFwkConstants.STATEMENT);
                OAViewObject poreqdistvo = (OAViewObject)am.findViewObject("PoReqDistributionsVO");
                OARow row = (OARow)poreqdistvo.getCurrentRow();
      pageContext.writeDiagnostics(this, " ----> row : "+ row, OAFwkConstants.STATEMENT);
                if (row != null) {
      Number xxgesqty = (Number)row.getAttribute("ReqLineQuantity");
      pageContext.writeDiagnostics(this, " ----> xxgesqty : "+ xxgesqty, OAFwkConstants.STATEMENT);
                    if (xxgesqty.intValue() == 0) {
      pageContext.writeDiagnostics(this, " ----> throwing errro : ", OAFwkConstants.STATEMENT);
      throw new OAException("Enter Valid Quantity ",OAException.ERROR);
      }
      }
                else {
      pageContext.writeDiagnostics(this, " ----> No Row Error", OAFwkConstants.STATEMENT);
      throw new OAException("No Row Found Else ",OAException.ERROR);
      }
      }
      pageContext.writeDiagnostics(this, " ----> Calling Super", OAFwkConstants.STATEMENT);
            super.processFormRequest(pageContext, webBean);
        }
    }
    

    See you soon

    AJ

  • Name of the application is not running, the success message appears always

    Hello

    I use 11.1.2 and config application form in formsweb.cfg as below, the problem is when I call this link... I show the success message (never call application form, always see the success message wile I change the name of the application that never).

    any suggestion?

    [LOCALjpi]

    applet_name = FormsID

    jpi_download_page = http://w-CPC-IT-018.CPC.gov.AE:9001/Forms/Java/Download/JDK-6u25-Windows-i586.exe

    jpi_classid = clsid:CAFEEFAC-0016-0000-0017-ABCDEFFEDCBA

    jpi_codebase = http://Java.Sun.com/products/plugin/AutoDL/jinstall-1_6_0-Windows-i586.cab#version=1, 6,0,17

    jpi_mimetype = application/x-java-applet

    separateFrame = FALSE

    width = 1166

    height = 780

    colorScheme = titanium

    pageTitle = TEST

    UserID=usename/Password@Conn

    Form=D:\Project\apps\Forms\menu_new.FMX

    WebUtilLogging = off

    WebUtilLoggingDetail = normal

    WebUtilErrorMode = alert

    WebUtilDispatchMonitorInterval = 5

    WebUtilTrustInternal = true

    WebUtilMaxTransferSize = 16384

    imageBase codeBase =

    splashScreen = Loading.gif

    enableJavascriptEvent = true

    Archive = frmall.jar, laf_11112.jar, Jacob.jar, frmwebutil.jar, icons.jar, SimpleAppletBrowser.jar, jdic.jar

    WebUtilArchive = frmwebutil.jar, jacob.jar, frmall.jar, lablediconbutton.jar

    Hello

    This community is to discuss specific issues of Oracle Application Server, you can publish this request in for a better response:

    Forms

    Kind regards

    Prakash.

  • vCenter Server displays the error message: unable to connect to the host

    vCenter Server displays the error message: unable to connect to the host

    Symptoms

    • vCenter Server cannot connect to a host when you perform operations such as:

    o Storage vMotion

    o cold migration

    o cloning a virtual machine

    o the model deployment

    • Newspapers vpxd that contains an entry similar to:

    [2009-06-04 19:27:16.326 error "App" 4444] [VpxdInvtHost] IP address change for 10.223.122.143 to 10.223.127.197 unhandled, verification of the SSL certificate is not enabled.

    • You see errors similar to:

    Unable to connect to the host o

    o [2009-06-04 19:27:09.952 'Libs' 3902384 WARNING] [NFC ERROR] NfcNewAuthdConnectionEx: unable to connect to peer (numRetries = 2). Error: Unable to connect to the host 10.223.122.143: connection timed out

    • vCenter Server shows the VMS as being disconnected then connected.

    Hello

    Resolution

    Cause

    This problem can occur if an ESX host's IP address is changed while being managed by vCenter Server.

    Check the cause

    To check the cause of the problem:

    1. Log in as root to the ESX host using a SSH client.
    1. In the file etc/opt/vmware/vpxa/vpxa.cfg, find the IP address of the host. The entry looks like:


      10.21.48.121

      Note: for more information about editing the files, see installation in VMware ESX configuration files (1017022).

    Troubleshooting

    If the IP address is incorrect, perform the following steps in order. If the operation does not resolve the problem, continue to the next step. Don't skip a step.

    1. Disconnect and then reconnect the host:
    1. Right click on the ESX host in vCenter Server and click Disconnect.
    1. Reconnect the ESX host in vCenter Server.
    1. Restart the VirtualCenter agent on the ESX host:
    1. Stop the service of vpxa with the command:

      # service vmware-vpxa stop

    1. Open the /etc/opt/vmware/vpxa/vpxa.cfg file in a text editor and correct the IP address of the ESX host.
    1. Start the service of vpxa with the command:

      # service vmware-vpxa start

      Note: for VMware ESXi, you may have to restart all the management agents. For more information, see restart the agents on an ESX or ESXi Server (1003490) management .

    1. Rebuild the VirtualCenter agent on the ESX host configuration file:

      Attention: this step removes all the Statistics counters historical host and the virtual machine. If VMware ESX host is running in virtual machines that starts in a permitted CVS environment, you maybe won't be able to add the host without stopping the virtual machines first.

    1. Right click on the ESX host in vCenter Server and click Disconnect.
    1. Remove the ESX host disconnected from vCenter Server.
    1. Backup the file vpxa.cfg with the command:

      # mv /etc/opt/vmware/vpxa/vpxa.cfg /etc/opt/vmware/vpxa/vpxa.oldcfg

    1. Add the ESX host disconnected to the server vCenter inventory.
    1. Run the following command to view the contents of /etc/opt/vmware/vpxa/vpxa.cfg and confirm that the host IP address is correct:

      # cat /etc/opt/vmware/vpxa/vpxa.cfg

  • Hello, I have problems with the digital signature on the software. It displays the error message: 2148073510. Could someone help me?

    Hello, I have problems with the digital signature on the software. It displays the error message: 2148073510. Could someone help me?

    Hello

    I would ask you go through the next thread once and see if that fixes the problem.

    Error 2148073513 when you try to digitally sign Acrobat 11 standard

    Concerning

    Sukrit diallo

  • How to delay or not to fade the success message?

    Hello

    I use Apex version 4.2.2. I noticed that error messages do not fade and disappear only if we click on the 'x '. How could I achieve this with the success message? I would like to know how I could delay AND remove the auto fade. After that, I would be able to decide who is best for me. I tried referring here to make the delay, but it doesn't seem to work:

    https://forums.Oracle.com/message/11159689#11159689

    Would it be possible and if yes, where I was able to change?

    Thank you.

    Hello

    I had a situation in which, to have changed the fade time of success messages. You can find the code here: https://gist.github.com/vincentdeelen/7516812

    In the setTimeout of this function, the 4000 is the time in mili seconds that the message remains on the screen. You can change this value at your convenience.

    If you don't want the successmessage to fade at all, you can create an overload of the function like this:

    autoFadeSuccess = function() {return true ;};}

    Kind regards

    Vincent

  • Set the width of the text in order to display the entire message

    I put a dynamic text (multiline) on stage with 91.3 width and height 21.9.
    The name of the instance of the text is "txtdirection".

    On the other hand, I have a variable called "mymessage."

    And my code is as follows:

    myMessage = "turn right... » ;
    _root.txtdirection.TextWidth = myMessage.Length;
    _root.txtdirection.text = myMessage;

    But it does not display the entire message...
    And I tried to replace the second line with the following statements, but it still not working...

    _root.txtdirection.length = myMessage.Length;
    _root.txtdirection.TextWidth = myMessage.textWidth;
    _root.txtdirection._width = myMessage._width;
    _root.txtdirection.TextWidth = myMessage._width;

    Is there something wrong?

    If you want your textfield to be 'just' the text of the size, use the textfields autoSize property.

  • change the success message in the APEX

    Hello

    I would like to show the user that the process is a success or a failure. I can do this easily by writing a text in the boxes provided for the success message and the failure message but everytime I get a sign 'X' as well as these messages. Is it possible to avoid that?

    Thanks and greetings
    VG

    Hello

    Just to be a little more specific... If you change your model page and scroll down to sub-model section, you will find models from 'Success Message' and 'Notification '. You will see something like this:

    #SUCCESS_MESSAGE#

    To remove the "X", you need to remove this part of the code:

    
    

    --
    Paulo Vale
    http://Apex-notes.blogspot.com

  • JDev 11.1.2.1 custom Popup to display the error message

    I'm able to programmatically display a popup when an error condition occurs. However, I can't understand how to complete the popup with a simple message such as:

    "0001 b bank account is overdrawn"

    It occurs when I have to fill in the popup with the number of account and then display the pop-up window for the user.

    Thanks for your help, Steve
        public String Ok() {
            // Add event code here...
            BindingContainer bindings = getBindings();
            OperationBinding operationBinding =
                bindings.getOperationBinding("calling method which is wrote in Application Module");
    
            Object result = operationBinding.execute();
    
            String docNo = operationBinding.getResult().toString();  //here
            if (!operationBinding.getErrors().isEmpty()) {
                FacesContext ctxs = FacesContext.getCurrentInstance();
                FacesMessage fms =
                    new FacesMessage(FacesMessage.SEVERITY_WARN, "Doc are not Created Sucessfully",
                                     "");
                ctxs.addMessage(null, fms);
            } else {
                FacesMessage fm =
                    new FacesMessage("Doc is created Successfully" + " - " + docNo); /here
                fm.setSeverity(FacesMessage.SEVERITY_INFO);
                FacesContext context = FacesContext.getCurrentInstance();
                context.addMessage(null, fm);
            }
            return null;
        }
    

    just give me a sample. You can change the code snip you want. and one not enough information from your post. When you get 0001 'b' and also no version jdev

  • Preserve carriage returns in the success Message

    Apex 3.2

    I have a page process that calls a procedure in the database.

    The procedure of database returns that a message with carriage returns.

    My page process is as follows

    Declare
    v_message varchar2 (4000);
    number of v_bmiid;
    V_bmikey varchar2 (128);
    number of v_dmatid;

    Begin

    p_vpeapx.pr10_update_bmi (p_ldeid = >: F300_LDEID,)
    p_bmiextkey = >: P10_BMI_EXTKEY,.
    p_promextkey = >: P10_BMI_PROM_EXTKEY,.
    p_bmilongdescr = >: P10_BMI_LONGDESCR,.
    p_bmishortdescr = >: P10_BMI_SHORTDESCR,.
    p_bmiid = >: P10_BMIID,.
    p_bmikey = > v_bmikey,
    p_dmatid = > v_dmatid,
    p_process = > 'update BMI. "
    po_message = > v_message.
    p_checksum = >: P10_CHECKSUM);

    : P10_MESSAGE: = v_message.

    End;

    I then use P10_MESSAGE as my message of success of the process;

    displayed on the page is all in a single line, without carriage returns.

    P10_MESSAGE is a hidden and protected

    The message of the database may be very large, so I need cart returns to display to the user

    Gus

    Gus C wrote:

    I tried the front line, does not work in Internet Explorer, but worked in FF.

    Unfortunately, users do not FF.

    Before I tried and it put everything on one line

    Any other suggestions please

    Set the Message of the success of the process:

    &P10_MESSAGE.
  • Using the procedure output parameter in the success message

    I have a page process that calls a procedure of database with 2 output parameters.

    The source of my page process looks like this:
    DECLARE
       --variables to hold output parameters
       matched_count NUMBER;
       unmatched_count NUMBER;
    BEGIN
       USP_MATCH_PROCESS (matched_count, unmatched_count);
    END;
    I would like to be able to display the value of the 2 output settings in the Message of success of the process for the process.

    Is there a simple way to do this or I have to create the hidden page items and complete these source code, then reference these? Or even better, can reference variables in the source directly from the success of the process Message?

    Hello

    You can use something like this: -.

    apex_application.g_print_success_message: = matched_count | » '|| unmatched_count;

    Concerning

    Paul

Maybe you are looking for

  • reset the time

    In the recent update to iTunes 12.4.0, I can not find where to reset the number of plays of a song. It used to be in the drop-down menu when I would do a right click on it, but is no longer...

  • How to find the bytes in hexadecimal string start

    Hi, I'm a freshman for Labview. I want to find the beginning bytes in Hex string. For example, 12 1A 00 34 1A 01 23... How can I get my data of 3 bytes of the hexadecimal string which starts at 1 'a '? Thank you for your help.

  • continious streaming to the mysql database

    Hello I have LabvVIEW and LV Database Connectivity Toolkit. I'm creating a test sequence and I need to log the results and data to a mysql database. I want to ask you your opinion on what will be the most effective approach to connect to the database

  • room mailbox

    I created addresses email on Server 2010 for 6 rooms.  people in society will send a meeting request to the address of the room, and if it is not already planned it will automatically accept the meeting request.  the calendar is in 15-minute segments

  • Error in homegroup

    I'm running a couple of old HP 625 computer laptop and I have had problems with the homegroup. I can not connect to any homegroup, because it tells me that I'm already in one. If I try to leave there is a message "Windows could not remove your form f