Divide the line into several columns

Hi all

I have a question where I want to divide the line into multiple columns based on the delimiter ' |'.

Staging of Table structure: People_STG, I have people in it.

Create table People_STG(col1 varchar2(4000));


Insert into People_STG(Emp_id|) User name | FirstName. LastName. JobTitle | hire_date | Location_id)


SELECT REGEXP_SUBSTR ( COL1, '[^,|]+', 1, 1) EMP_ID,
       REGEXP_SUBSTR ( COL1, '[^|]+', 1, 2) USERNAME,
       REGEXP_SUBSTR ( COL1, '[^,|]+', 1, 3) FIRSTNAME,
       REGEXP_SUBSTR ( COL1, '[^,|]+', 1, 4) LASTNAME,
       REGEXP_SUBSTR ( COL1, '[^,|]+', 1, 5) JOBTITLE,
       REGEXP_SUBSTR ( COL1, '[^,|]+', 1, 6) HIRE_DATE,
       REGEXP_SUBSTR ( COL1, '[^,|]+', 1, 7) LOCATION_ID
FROM PEOPLE_STG
WHERE length(regexp_replace(COL1, '[^|]', '')) = 14;

But I am facing a problem here, as in some lines, function is null, but when I run the above query, it is not recognizing the empty element and inserting Hire_date values of function and location_id in Hire_date where function is null.

for example: 1 | akash51 | Akaksh | C | 22/11/14 | 15

Here the function is null, so when I run top to divide query it will insert 11/22/14 in the function column and 15 in Hire_Date.

Please need help on this one.

Oracle Version: 11.2 g

Thanks in advance,

Akash.

There are different techniques to cope with this.  Is a simple...

SQL > ed
A written file afiedt.buf

1 with t as (select 1 | akash51 |) Akaksh | C | 22/11/14 | 15' as col1 of union double all the
2 Select 2 | akash52 | Akaksh | C | Jobs jobs | 23/11/14 | 15' of the double
3            )
4  --
5. end of test data
6  --
7 select trim (REGEXP_SUBSTR (COL1, ' [^, |] +', 1, 1)) EMP_ID,.
8 toppings (REGEXP_SUBSTR (COL1, ' [^, |] +', 1, 2)) USERNAME,.
9 garnish (REGEXP_SUBSTR (COL1, ' [^, |] +' 1, 3)) FIRSTNAME,
10 pads (REGEXP_SUBSTR (COL1, ' [^, |] +' 1, 4)) LASTNAME,.
11 garnish (REGEXP_SUBSTR (COL1, ' [^, |] +' 1, 5)) JOBTITLE,.
12 pads (REGEXP_SUBSTR (COL1, ' [^, |] +', 1, 6)) HIRE_DATE,.
13 garnish (REGEXP_SUBSTR (COL1, ' [^, |] +' 1, 7)) location_id
14 * from (select replace (col1, ' |)) ',' | as col1 of t)
SQL > /.

EMP_ID USERNAME FIRSTNAME LASTNAME, JOBTITLE HIRE_DATE LOCATION_I
---------- ---------- ---------- ---------- ---------- ---------- ----------
1 akash51 Akaksh C 22/11/14 15
2 akash52 Akaksh C Job 23/11/14 15

Tags: Database

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 13  when matched then update set a.col1 = b.col1
 14                             , a.col2 = b.col2
 15                             , a.col3 = b.col3
 16                             , a.col4 = b.col4
 17  when not matched then insert (a.col1) values (null);

3 rows merged.

SQL> select * from t;

COL1                           COL2                           COL3                           COL4                           COL5
------------------------------ ------------------------------ ------------------------------ ------------------------------ ------------------------------
adsdf                          fgrty                          erfth                          oiunth                         adsdf,fgrty,erfth,oiunth,okujt
x                              y                                                                                            x,y
a                              b                              c                              d                              a,b,c,d

3 rows selected.

SQL>

    Assuming you're on 9i...

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    Select 1 org_pk, org_nm 'ALL american, INC.' of any double union

    Select org_pk 2, org_nm "COMPANY A.G" Union double all the

    Select org_pk 3, org_nm "GROWTH FUND SPONSORS and SONS, Inc." of the double

    )

    Select * org;

    Result, I need is

    1. ALL THE

    1 american

    1, INC.

    2 A.G

    2 COMPANY

    3. THE GROWTH

    3 FUND

    3 SPONSORS

    3 and

    3 WIRES,

    3 INC.

    Thank you very much.

    You can use GROUP BY with LISTAGG or XMLAGG. And ordinalite allows to preserve order:

    with org as)

    Select 1 org_pk, org_nm 'ALL american, INC.' of any double union

    Select 2 org_pk, 'A.G COMPANY' org_nm of all the double union

    Select org_pk 3, org_nm "GROWTH FUND SPONSORS and SONS, Inc." of the double

    )

    Select org_pk,

    x.org_nm,

    x.o

    org,.

    XMLTable)

    "ora: tokenize(.,"").

    by the way ' ' | org_nm

    columns

    path of varchar2 (4000) to org_nm '.'.

    o for the ordinalite

    ) x

    where x.org_nm is not null

    /

    ORG_PK ORG_NM O
    ---------- ------------------------------ ----------
    1 ALL                                     2
    1 American 3
    1 ,INC                                    5
    2 A.G                                     2
    2 COMPANY 4
    3 GROWTH                                  2
    3 FUND                                    3
    3 4 SPONSORS
    3 and                                     5
    3 SONS,                                   6
    3 INC.                                    7

    11 selected lines.

    SQL >

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    SY.

  • Splits the string into two columns

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    < font color = "red" > /cfd/abc.html < / police > < font color = "blue" > 107 < / make >

    < font color = "red" > / night/aaa/page 1 < / police > < font color = "blue" > 107 < / make >

    < font color = "red" > / can/MLP/Page2 < / police > < font color = "blue" > 107 < / make >


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    Try this,

    SQL> WITH T
  2       AS (SELECT  '/cfd/abc.html,/night/aaa/Page1,/can/MLP/Page2|107 ' str FROM DUAL UNION ALL
  3           SELECT  '/cfd/def.html,/bbbb/bbbb/Page1,/lll/MLP/Page3|108 ' str FROM DUAL)
  4  SELECT REGEXP_SUBSTR ( str, '[^,|]+', 1, lvl) URL,
  5         REGEXP_SUBSTR ( str, '[^|]+', 1, 2) ID
  6    FROM T,
  7         (SELECT LEVEL lvl
  8            FROM (SELECT MAX (LENGTH (REGEXP_REPLACE ( str, '[^,]'))) mx FROM T)
  9          CONNECT BY LEVEL <= mx + 1)
 10   WHERE Lvl - 1 <= LENGTH (REGEXP_REPLACE ( str, '[^,]+'))
 11   order by id,lvl;

URL                                                ID
-------------------------------------------------- -------------------------------------------------
/cfd/abc.html                                      107
/night/aaa/Page1                                   107
/can/MLP/Page2                                     107
/cfd/def.html                                      108
/bbbb/bbbb/Page1                                   108
/lll/MLP/Page3                                     108

6 rows selected.

SQL>

    G.

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    3. Close the top resulting and substantive way.
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    281TC_View2TC_View_C
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    GROUP BY col2

    ORDER BY col2

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    Hi people,

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    "name select 'John', ' 7.3.2014' date_from, ' 13.3.2014 ' date_to, 'SICK DAY' reason for the double

    "" the name of Union select 'Mike', ' 28.3.2014 ' date_from, ' 2.4.2014 ' date_to, 'HOLIDAY' because of the double

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    "the name of Union select 'John', ' 9.3.2014 ' absence_date, 'SICK DAY' reason for the double

    "the name of Union select 'John', ' 10.3.2014 ' absence_date, 'SICK DAY' reason for the double

    "the name of Union select 'John', ' 11.3.2014 ' absence_date, 'SICK DAY' reason for the double

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    "the name of Union select 'John', ' 13.3.2014 ' absence_date, 'SICK DAY' reason for the double

    "the name of Union select 'Mike', ' 28.3.2014 ' absence_date, 'HOLIDAY' because of the double

    "the name of Union select 'Mike', ' 29.3.2014 ' absence_date, 'HOLIDAY' because of the double

    "the name of Union select 'Mike', ' 30.3.2014 ' absence_date, 'HOLIDAY' because of the double

    "the name of Union select 'Mike', ' 31.3.2014 ' absence_date, 'HOLIDAY' because of the double

    "the name of Union select 'Mike', ' 1.4.2014 ' absence_date, 'HOLIDAY' because of the double

    "the name of Union select 'Mike', ' 2.4.2014 ' absence_date, 'HOLIDAY' because of the double

    "the name of Union select 'Tom', ' 14.3.2014 ' absence_date, 'HOLIDAY' because of the double

    )

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    SQL > with t as)
    2. Select the name of 'John '.
    3, to_date ("'07.3.2014', ' dd.mm.yyyy") date_from
    4, to_date ("'13.3.2014', ' dd.mm.yyyy") date_to
    5, 'SICK DAY' reason
    6 double
    7 union select name "Mike".
    8, to_date ("'28.3.2014', ' dd.mm.yyyy") date_from
    9, to_date ("'02.4.2014', ' dd.mm.yyyy") date_to
    10 at 'HOLIDAY '.
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    12 union select name of "Tom."
    13, to_date ("'14.3.2014', ' dd.mm.yyyy") date_from
    14, to_date ("'14.3.2014', ' dd.mm.yyyy") date_to
    15, because of "HOLIDAY".


    16 double
    17       )
    18 select name
    19, date_from + (level 1) leave_date
    20, reason
    21 t
    22 connect
    23 by level<= date_to="" -="" date_from="" +="">
    24 and prior name = name
    25 and prior sys_guid() is not null
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    27 by name
    28, leave_date;

    NAME LEAVE_DAT REASON
    ---- --------- --------
    John 7 March 14 SICK DAYS
    John 8 March 14 SICK DAYS
    John 9 March 14 SICK DAYS
    John 10 March 14 SICK DAYS
    John 11 March 14 SICK DAYS
    John 12 March 14 SICK DAYS
    John 13 March 14 SICK DAYS
    Mike HOLIDAY 28 March 14
    Mike HOLIDAY 29 March 14
    Mike HOLIDAY 30 March 14
    Mike HOLIDAY March 31, 14
    Mike HOLIDAY April 1, 14
    Mike VACATION April 2, 14
    Tom March 14 14 HOLIDAY

    14 selected lines.

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