Download all dates for each day of a week
I need a VI that gives me the dates of the week. I use a calendar month to look at a database and fill two different graphs with the database values. A chart looks at the values of the specific day, I chose in the calendar, but the other graph looks like all the days of the week. To create this SQL query, I need to have all the dates this week.
I could build a function if I knew that the first and last date of the week. Anyone know an easy way to do this?
Use the Second to primitive time to convert your day to a cluster of time. One of the elements of the cluster is the day of the week that should allow you to easily find the end of the week (you can add 2 days and convert back or add 2 with the unit of the timestamp of origin).
Tags: NI Software
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BobDJ wrote:
Test data to https://apex.oracle.com/pls/apex/f?p=4550:1:0:
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WHERE ROWNUM<= case="" when="" coalesce(:request,'x')="" not="" like="" 'flow_excel_output%'="" then="" rownum="" else="" 3="">=>
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DAY ITEMS_PER_DAY
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2 a.day as the day,
3 b.items_per_day
4 of
5 (select trunc((to_date('01-JAN-2013','DD-MON-YYYY')-1) + rownum) as day
6 double
7 plug by rownum < = 10).
8 (select trunc (time_of_sale) day, sum (count (*)) (trunc (time_of_sale) order) as items_per_day
9 sales
10 group by trunc (time_of_sale)) b
11 where a.day = b.day [+] - replace by parentheses to avoid the formatting of the forum
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DAY ITEMS_PER_DAY
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Value null January 6, 13
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Value null January 9, 13
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(
SELECT TO_DATE (January 1, 2013 ', 'DD-MON-YYYY') + ROWNUM - 1 day YOU
OF the double
CONNECT BY ROWNUM<=>=>
)
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SUM (COUNT (s.id)) OVER (ORDER BY d.day) AS items_to_date
OF days_wanted d
S sale LEFT OUTER JOIN ON TRUNC (s.time_of_sale) = d.day
GROUP BY d.day
ORDER BY d.day
;
Note that we must use COUNT (s.id) instead of COUNT (*) here, because, given that it is evaluated once the outer join, COUNT (*) would be taken into account less than $ 1 a day, because the outer join ensures there will be at least 1 row in the game for each row in days_wanted, whether or not it matches anything in sales.
It wouldn't work using the old join syntax, too, but I suggest to use the ANSI syntax, especially for outer joins. It reduces the amount and the complexity of the coding, and which allows to reduce the number of errors. (Also, it avoids the problem of the display of this site.)
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