Cumulative total for each day - how to deal with nulls

I'm on 11.2.0.3. I want to write a query to calculate a running total of the incidents a day - this request will be used for an APEX line chart.

Sample table and data:

create table sales (
  id number primary key,
  time_of_sale date,
  item varchar2(20));


insert into sales values (1, to_date('02-JAN-2013','DD-MON-YYYY'), 'book');
insert into sales values (2, to_date('03-JAN-2013','DD-MON-YYYY'), 'candle');
insert into sales values (3, to_date('05-JAN-2013','DD-MON-YYYY'), 'bicycle');
insert into sales values (4, to_date('05-JAN-2013','DD-MON-YYYY'), 'football');
insert into sales values (5, to_date('07-JAN-2013','DD-MON-YYYY'), 'football');
insert into sales values (6, to_date('10-JAN-2013','DD-MON-YYYY'), 'elephant');
insert into sales values (7, to_date('10-JAN-2013','DD-MON-YYYY'), 'turtle');
insert into sales values (8, to_date('10-JAN-2013','DD-MON-YYYY'), 'book');
insert into sales values (9, to_date('10-JAN-2013','DD-MON-YYYY'), 'candle');
insert into sales values (10, to_date('10-JAN-2013','DD-MON-YYYY'), 'bicycle');
commit;

For each of the days between 1 January and 10 Jan I want to get the total functioning of the number of sales.

So the output l would like is:

DAY ITEMS_PER_DAY

--------- -------------

1ST JANUARY 13 0

JANUARY 2, 13 1

JANUARY 3, 13 2

JANUARY 4, 13 2

5 JANUARY 13 4

JANUARY 6, 13 4

JANUARY 7, 13 5

JANUARY 8, 13 5

JANUARY 9, 13 5

10 JANUARY 13 10

So even if there is no sale on January 4, we show the total of the previous day.

If I can create a series of dates using the:

select trunc((to_date('01-JAN-2013','DD-MON-YYYY')-1) + rownum) day 
from dual 
connect by rownum <= 10

And I can't the cumulative aid total:

select trunc(time_of_sale) as day, sum(count(*)) over (order by trunc(time_of_sale)) as items_per_day
from sales
group by trunc(time_of_sale)

Overall, it gives me:

SQL > select

2 a.day as the day,

3 b.items_per_day

4 of

5 (select trunc((to_date('01-JAN-2013','DD-MON-YYYY')-1) + rownum) as day

6 double

7 plug by rownum < = 10).

8 (select trunc (time_of_sale) day, sum (count (*)) (trunc (time_of_sale) order) as items_per_day

9 sales

10 group by trunc (time_of_sale)) b

11 where a.day = b.day [+] - replace by parentheses to avoid the formatting of the forum

12 order by a.day

13.

DAY ITEMS_PER_DAY

--------- -------------

1st January 13 null

JANUARY 2, 13 1

JANUARY 3, 13 2

Value null 4 January 13

5 JANUARY 13 4

Value null January 6, 13

JANUARY 7, 13 5

Value null January 8, 13

Value null January 9, 13

10 JANUARY 13 10

It's not exactly what I'm looking for. I played a bit with a lag, but had no success.

Any ideas?

Thank you

John

Hi, John,.

You want to do the SUM after the outer join, like this:

WITH days_wanted AS

(

SELECT TO_DATE (January 1, 2013 ', 'DD-MON-YYYY') + ROWNUM - 1 day YOU

OF the double

CONNECT BY ROWNUM<=>

)

SELECT d.day

SUM (COUNT (s.id)) OVER (ORDER BY d.day) AS items_to_date

OF days_wanted d

S sale LEFT OUTER JOIN ON TRUNC (s.time_of_sale) = d.day

GROUP BY d.day

ORDER BY d.day

;

Note that we must use COUNT (s.id) instead of COUNT (*) here, because, given that it is evaluated once the outer join, COUNT (*) would be taken into account less than $ 1 a day, because the outer join ensures there will be at least 1 row in the game for each row in days_wanted, whether or not it matches anything in sales.

It wouldn't work using the old join syntax, too, but I suggest to use the ANSI syntax, especially for outer joins. It reduces the amount and the complexity of the coding, and which allows to reduce the number of errors. (Also, it avoids the problem of the display of this site.)

Tags: Database

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Cumulative total for each day - how to deal with nulls

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