Excerpt of day, month, year

Similar Questions

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  Could you please tell me how to change the display of the date to display the day month year instead of month day year?

  HOW to: Change the Date, time, number, and currency value displays in Windows XP

  http://support.Microsoft.com/?kbid=307938

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• The date system in the taskbar indicates the year, month, day (as in the army). How can I read the day, month, year?

  The date system in the taskbar indicates the year, month, day (as in the army). How can I read the day, month, year?

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• Studio: Chart based on the day/month/year

  In the Studio, there is a requirement for us display the chart based on the day/month/year.

  Because the Date attribute does not appear as a Dimension in the graphics configuration list, I divided attribute date day/month/year attributes and inspiring that I generated a sample chart

  But now I am facing a problem

  Suppose that there are records for only July and Ms then the graph shows in July and Aug, it does not show in August.

  I agree that there is no record for August in my field of data which is the reason why Augustus is not displayed in the table. But according to our requirement, we must view August as well as with zero count.

  I'm curious to know if there is a way to do it.

  The idea behind the record calendar type is a secondary, new record type are you introduction that completes your registration type "sale."  The records you provided would be your 'sales' record type, not your type of registration of "calendar".  To use your example, your recordings of 'sale' would look like what provided you:

  =============== RECORD ==================

  ID: 1

  Sales_Amount: 1000

  Month: October

  RecordType: sale

  Date: 2012-10 - 01 T 00: 00:00.000Z

  day: 01

  year: 2012

  =============== RECORD ==================

  ID: 5

  Sales_Amount: 1000

  Month: December

  RecordType: sale

  Date: 2012-12 - 01 T 00: 00:00.000Z

  day: 01

  year: 2012

  ==========================================

  And your registration type "calendar" would be charged later.  I usually provide a single record of short for all day for this record type:

  =============== RECORD ==================

  ID: 1

  Month: October

  RecordType: calendar

  Date: 2012-10 - 01 T 00: 00:00.000Z

  day: 01

  year: 2012

  =============== RECORD ==================

  ID: 2

  Month: October

  RecordType: calendar

  Date: 2012-10 - T 02, 00: 00:00.000Z

  day: 02

  year: 2012

  ==========================================

  (and so on, one for each day until today... yawn)...

  =============== RECORD ==================

  ID: 790

  Month: July

  RecordType: calendar

  Date: 2013-07 - 31 T 00: 00:00.000Z

  day: 31

  year: 2013

  ==========================================

  Thus, when you write a statement of EQL as:

  RETURN foo AS SELECT

  Sum (Sales_Amount) AS "TotSales.

  GROUP BY month

  You will get a bucket of months for every month, where the record type "calendar" will not fail to offer a month when sales do not offer it... aka. Fill the "holes".

  HTH,

  Dan

  http://branchbird.com

• Please suggest how to convert number of days, months, years

  Dear all,

  I have a requirement, where to get a value of function, say 61 (in days).

  I want to display it in the report as, (60/30 + 1)

  Years months days

  0          2            1

  Please suggest.

  Thanks in advance.

  Kind regards

  Afzal.

  You could act as some sort of an astronomer: year - Wikipedia, the free encyclopedia

  Select: days of entry,

  floor (: days/365.25) years.

  Floor (mod(:Days,365.25) / (365.25 / 12)) months.

  ceil (mod (: days, 365.25/12)) days

  of the double

  but do not be surprised

  DAYS	YEARS	MONTHS	DAYS
  731	2	0	1
  730	1	11	30
  366	1	0	1
  365	0	11	31
  364	0	11	30
  92	0	3	1
  91	0	2	31
  90	0	2	30
  62	0	2	2
  61	0	2	1
  60	0	1	30
  32	0	1	2
  31	0	1	1
  30	0	0	30
  1	0	0	1

  Maybe the next version is more beautiful

  Select the days,

  Floor(Days / 365.25) years.

  Floor (mod (Days, 365.25) / (365.25 / 12)) months.

  round (mod (days, 365.25/12)) days

  periods

  DAYS	YEARS	MONTHS	DAYS
  731	2	0	1
  730	1	11	30
  366	1	0	1
  365	0	11	30
  364	0	11	29
  92	0	3	1
  91	0	2	30
  90	0	2	29
  62	0	2	1
  61	0	2	0
  60	0	1	30
  32	0	1	2
  31	0	1	1
  30	0	0	30
  1	0	0	1

  Concerning

  Etbin

• What is the date format used in the charts of Microsoft Support policy? Is the day/month/year or month/day/year?

  For example, the Date of beginning of life cycle shows 31/05/2001 (March 5) and the end of Support Date extended watch 07/12/2001 (12 July or December 7).

  The date format is month/date/year. This format is for the start date and end date for extended Support.
  In your example, the start date is May 31, 2001, and the end date would be July 12, 2001.

  I hope this helps.

  Marilyn

• Can I change the date format day/United States (month day year) in the United Kingdom (date month year)?

  When I consult databases via Firefox, the format of date/day is set at: day, month, year (AMERICAN style), while I need, day, month, year, I work in the United Kingdom and the 'bad' format is VERY confusing and could lead to errors and mistakes. IE has that format, but I don't want to return to using that.

  You use the English (United States) version of Firefox ESR 24.3.0. You can download the English version of (British) below:

  • http://www.Mozilla.org/Firefox/organizations/all/

  1. under Options - content - language, make sure that English/United Kingdom [en-us] is located at the top of the list.

  • Web content settings, pop ups, fonts and languages

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  • http://Windows.Microsoft.com/en-us/Windows/change-dates-times-currency-measurements-display

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• I have problems with D4.1 in Labview ' 09. It is said to determine the age of a person in years, when given the month in course, day, and year and month of birth of the person, day, and year

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• I want to collect rain for the day, month and year; Can what formula I use?

  I want to collect rain for the day, month and year; What formula or expression that I can use.

  I use a Rain Wise product that converts impulses to an analog value.  The rain wise device can be

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  What I would do is at each time increments of signal I would consider it as 0.01 then after reaching

  a period of time a day or a month, back to zero.

  Need some advice on this problem.

  How about you, using a counter to count the number of times where the signal is less than 0.01?

  For example,.

  Counter.Count = signal<=>

  The total number of rain is

  Counter * 10 + signal

  Use TimeOfDay or TimeOfWeek to reset the counter.

• Set the calendar to display day, month and year

  In addition to the time of day, my computer began giving the day of the week (Monday) only instead of day, month and year as it did before. Tried to go back to 29/12/2014 or something similar without success.  Any suggestions?

  Hello

  Sorry for the late reply and I appreciate your patience.

  User profile corruption might have caused the problem. As a solution, I suggest to create a new user profile and check if the date format displays the same thing.

  To do this, see the link below.

  http://Windows.Microsoft.com/en-us/Windows/fix-corrupted-user-profile#1TC=Windows-7.

  It will be useful. Just answer us with the State, and we will be happy to help you.

• split with day, month and year in a date

  Hi all

  I have this point of view

  with (id, dt) t (select 1, to_date('02/06/2010','MM/DD/YYYY') of all the double union)
  Select 2, to_date('11/29/2001','MM/DD/YYYY') of all the double union
  Select 3, to_date('02/06/2011','MM/DD/YYYY') of all the double union
  Select option 4, double to_date('10/10/2011','MM/DD/YYYY')
  )
  --
  -end of test data
  --
  SELECT id, dt
  floor (months_between(sysdate,dt)/12) years
  , floor (mod (months_between (sysdate, dt), 12)) months
  -The day is ambiguous because of the number of days in a different month
  -you could design your own algorithm to give the desired results, but it is a good approximation
  , floor (sysdate-(add_months (dt, floor (months_between (sysdate, dt))) as dys
  t
  /
  ID DT YEARS MONTHS DYS
  ---------- ----------- ---------- ---------- ----------
  1-6 FEBRUARY 2010 5 8 22
  2 29 NOVEMBER 2001 13 10 29
  3-6 FEBRUARY 2011 4 8 22
  4-10 OCTOBER 2011 4 0 18

  As a result, 26 years old, 26 months, 91 days.
  

  
  

  And subtract years, MONTHS and DYS as format

  erase years, from 1 to 12 months and the days of the 1 to 30 as

  91 days = 30 x 3 + 1 = > 1 day over 3 months

  26 months + 3 months = 29 months = > 24 months + 5 months = 2 years + 5 months

  and 26 years + 2 years = 28

  desire to result: 28 years, 5 months and 1 day.

  Is there a function that give me this result from the query above?

  Kind regards

  Gordan

  Hello Gordan,.

  I understand that you are the SUM of all the lines.

  Here are two ideas:

  -1 - using a date
  (a) SUM (TRUNC (sysdate) - dt)
  I would give you the total number of days.
  (b) adding the number of days to, for example, DATE ' 1900-01-01' would give another date...
  (c) simply subtract the years 1900 and it takes several years,
  subtract 1 from the month (1-12 from January to December) and you have the number of months
  subtract 1 from the day of the month (1-31) and you have the number of days.
  It is of course 'approximate' as the months do not have the same number of days...

  -2 - using only the number of days
  Maybe you want something else, for example: the total number of days divided by 365.25 for many years, the recall divided by 30 to get the number of months, the reminder being the number of days.

  (a) SUM (TRUNC (sysdate) - dt)

  I would give you the total number of days.

  (b) Division by 365.25 (le.25 is to take leap years into account, but you can choose for example "365")

  (c) number of reminder of days (total - years * 365.25): divided by 30 is the number of months

  (d) number reminder of days (total - years * 365.25 - months * 30): gives the number of days.

  The following two options with your test data (by chance, this gives the same result in this case)

  option 1:
  with (id, dt) t (select 1, to_date('02/06/2010','MM/DD/YYYY') of all the double union)
  Select 2, to_date('11/29/2001','MM/DD/YYYY') of all the double union
  Select 3, to_date('02/06/2011','MM/DD/YYYY') of all the double union
  Select option 4, double to_date('10/10/2011','MM/DD/YYYY')
  )
  target_date AS
  (SELECT DATE ' 1900-01-01' + SUM (TRUNC (sysdate) - t.dt) FROM t trgt)
  in_pieces AS
  (SELECT TO_NUMBER (TO_CHAR (td.trgt, 'YYYY')) - 1900 y
  , TO_NUMBER (TO_CHAR (td.trgt, 'MM')) - 1 m
  , TO_NUMBER (TO_CHAR (td.trgt, 'DD')) - 1 d
  Target_date TD
  )
  SELECT "result: ' |"
  TRIM (CASE WHEN ip.y = 0 THEN NULL
  WHEN ip.y = 1 THEN "1 year"
  Of OTHER TO_CHAR (ip.y) | "years".
  END |
  CASE WHEN ip.m = 0 THEN NULL
  WHEN ip.m = 1 THEN "1 month"
  Of OTHER TO_CHAR (ip.m) | 'months '.
  END |
  CASE WHEN ip.d = 0 THEN NULL
  WHEN ip.d = 1 THEN "1 day"
  Of OTHER TO_CHAR (ip.d) | 'days '.
  END
  )
  Of in_pieces ip
  ;
  result: 28 years, 4 months and 28 days

  option 2:

  with (id, dt) t (select 1, to_date('02/06/2010','MM/DD/YYYY') of all the double union)
  Select 2, to_date('11/29/2001','MM/DD/YYYY') of all the double union
  Select 3, to_date('02/06/2011','MM/DD/YYYY') of all the double union
  Select option 4, double to_date('10/10/2011','MM/DD/YYYY')
  )
  nb_days AS
  (SELECT SUM (TRUNC (sysdate) - t.dt) n t)
  , y AS
  (SELECT Nb.n, FLOOR (nb.n / 365.25) y nb_days n. b.)
  ym AS
  (SELECT y.n, y.y, FLOOR ((y.n-y.y * 365,25) / 30) FROM a)
  ymd AS
  (SELECT ym.y, ym.m, ym.n - ym.y * 365.25 - ym.m * ym FROM 30 d)
  SELECT "result: ' |"
  TRIM (CASE WHEN ymd.y = 0 THEN NULL
  WHEN ymd.y = 1 THEN "1 year"
  Of OTHER TO_CHAR (ymd.y) | "years".
  END |
  CASE WHEN ymd.m = 0 THEN NULL
  WHEN ymd.m = 1 THEN "1 month"
  Of OTHER TO_CHAR (ymd.m) | 'months '.
  END |
  CASE WHEN ymd.d = 0 THEN NULL
  WHEN ymd.d = 1 THEN "1 day"
  Of OTHER TO_CHAR (ymd.d) | 'days '.
  END
  )
  WAN
  ;
  result: 28 years, 4 months and 28 days

  Best regards

  Bruno Vroman.

• "Birthdays" Smart Collection (based on day/month but NOT the year)

  Hello.

  I came across a problem when trying to make some organizes on my photos...

  Is it possible to create a Smart Collection with "Date is" + "in the range" then use day/month only and excludes the year?

  Or just a simple "Date is" + "date specific minimum year '.

  What I'm trying to do, is to create a smart album that has pictures of all my children on/autour. of their birthdays. The eldest is 14 years old and I have four children, manual adding of all dates and keep them up to date in a year is - while it is certainly doable - a little pain there.

  Is there a way to do this with Lightroom?

  The only way to create a smart collection for this is to manually add each year the criteria smart collection.

  A simpler way is to use the John R. Ellis AnyFilter plug-in.

• How to convert days to years, months and days remaining

  Hi all
  I have the number of days for example: 398 days how
  convert 398 days to several years, and the number of months and days remaining
  398 days 1 year, 1 month and 2 days
  Concerning
  Jocelyne

  There is no correct answer.

  That's right! ;)

• How to get the Date, month, year of the DateTimePicker

  Hi, I am using the DateTimePicker.

  There are several question about this command:

  1. how to get the Date, month and year?

  -With the help of myDateTime.value, I get this string ' Wed May 08 14:45 ICT 2013 '-> I have to manually analyze this? Because I need in format yyyy/mm/dd. Or can set the format of dateTimePicker.value?

  2 format on dateTimePicker self (on the user interface) is d/m/YY, I can't change to another format?

  Thank you

  dateTimePicker.value return a QDateTime not a string.

  https://developer.BlackBerry.com/Cascades/reference/bb__cascades__datetimepicker.html#property-value

  See more:

  https://developer.BlackBerry.com/Cascades/reference/QDateTime.html#date

  https://developer.BlackBerry.com/Cascades/reference/QDate.html

  You can get

  day = dateTimePicker.value.date().day()
  month = dateTimePicker.value.date().month()
  year= dateTimePicker.value.date().year()
  dateYYYYMMDD = dateTimePicker.value.date().toString(Qt::ISODate)
  dateYYYYMMDD2 = dateTimePicker.value.date().toString("YYYY/MM/DD")
  dateYYYYMMDD3 = dateTimePicker.value.toString("YYYY/MM/DD")
  

• Writing a query that may require a pivot but include [month, year] in the column and RiskGrades, no aggregate?

  Hello

  new to oracle/mark. I need to write a query that will pull the customer details and on the columns, it will have the month-year: Jan2015, Feb2015... Dec2015.

  on the lines, it will contain the details of the client. the information it will provide are the categories of risk to each month.

  I create a query, but it uses a function to update and is very slow. There are approximately 3000 documents. An update of column required 15 minutes or even more. so an update of column takes 15 minutes * 9 to update until September.

  the best ways to manage this demand?

  my query is:

  UPDATE tmpRiskGrades one

  SET a.feb2015 =)

  Select l.risk_grade

  of rep_loanportfolio l

  where a.agreementno = l.agreeement_no AND l.dtuserdatetime = February 28, 2015 ")

  Certainly, that looks like a pivot base for me.  Assuming that dtuserdatetime is actually a date data type, something like that will not work in your version of non-recognition:

  Select customer_no, agreeement_no, customer_address, loan_type region,

  Max (case when dtuserdatetime = to_date (Jan 31, 2015 "," DD month yyyy ' "))

  end of the era risk_grade) jan2015,.

  Max (case when dtuserdatetime = to_date (February 28, 2015 "," DD month yyyy ' "))

  then risk_grade end) Feb2015,

  ...

  of rep_loanportfolio l

  where loan_type = "HOME LOAN" and

  account_status = 'LIVE' and

  dtuserdatetime between to_date (Jan 31, 2015 "," DD month yyyy ' ") and

  TO_DATE (31 Dec 2015 "," DD month yyyy ' ")

  Group of customer_no, agreeement_no, customer_address, region loan_type

  order of region loan_type, customer_no, agreeement_no, customer_address

  If you are on 11.2 or higher, you could look at the PIVOT keyword, which is a more concise expression of the same thing.

  John