explain the values for IO tablespace statspack &; file
10.2.0.2 aix 5.2 64 bitin the section Tablespace IO Stats & Stats of e/s of statspack and awr reports file can someone help to clear up some confusion that I have with the value of AV readings/s-AV Rd (ms). I'll be referring to certain values, I have one of my reports, more than an hour 1 snap shot period, with the first three columns being readings, av rd/s, av rd (ms) respectively for the two sections.
I have the following for the Tablespace IO.
PRODGLDTAI
466 879 130 3.9 1.0 8 443 2 0 0.0
For the e/s file, I have the following for each file in the tablespace.
PRODGLDTAI /jdb10/oradata/jde/b7333/prodgldtai04.dbf
32 113 530 2.6 1.0 0 1 302 0 0.0
PRODGLDTAI /jdb14/oradata/jde/b7333/prodgldtai03.dbf
30 107 878 1.6 1.0 1 898 1 0 0.0
PRODGLDTAI /jdb5/oradata/jde/b7333/prodgldtai01.dbf
32 114 234 5.8 1.0 2 834 1 0 0.0
PRODGLDTAI /jdb5/oradata/jde/b7333/prodgldtai02.dbf
36 131 237 5.2 1.0 1 2 409 0 0.0
From there I can calculate that there are on average 129.68 reads every second for the tablespace, and which corresponds to what is stated. But whence the rd (ms) av? If there are 1000 milliseconds in a second and there were 130 reads per second, which does not 7.6 ms by read?
AV Dr (ms), what exactly? That's how many milliseconds it takes on average to 1 lira? I read in the doc Oracle Performance Tuning should not be greater than 20. What exactly is this statistic? In addition, we are currently looking at the purchase of a SAN and we were told that the value should not be greater than 10, which is just a matter of opinion? These values would be little useless on the tablespaces and data files that are not very active over a period of hours of time?
Published by: PktAces on September 22, 2008 08:31
I replied to this post a few days ago and so I have a watch on the post - but my response seems to have disappeared.
Yes - "av rd (ms)" is the average time for a reading to be completed. Roughly speaking, it is "total time waiting for the read request" / "total number of read requests.
20 m/s may be based on the programming of schedules for older hardware (disks 10 000 rpm). If a manufacturer tells you that the average response time for an e/s (for example) is 6 m/s - which equals 160 e / s per second - so it is reasonable to assume that in a multi-user system with a reasonable degree of simultaneity that perceived for a user response time will be about double. (Read Cary Millsap on the theory of queues and Oracle to understand why).
So the 10 m/s is probably work around this figure of 6 m/s 2 x and enabling caching of the effects a bit. As a very rough indicator of 'it is unhealthy, if the average is more than 10', it's probably a good figure. But you can't be sure that the SAN is healthy if the figure is less than 10.
It is difficult – without knocking a SAN with tablescans and it will madly in readahead and will produce data very quickly to a single user, while sanctioning other users who make random IO. In contrast, that a cache of SAN can do a lot of work to protect an Oracle of real disk readings because an object is just enough used to stay in the cache of SAN when it can't stay in the Oracle cache. If medium-sized SAN can be very misleading.
When you enter the land of SAN, you must keep an eye on v$ event_histogram, v$ file_historam, v$ temp_histogram for a time gap of I/O as a better indicator of health.
In fact, your last comment about "rarely used" objects is a useful indicator. If something is rarely used, Oracle "physical block read" is probably is a real disc read - an indicator of data how fast can detach from the SAN.
Concerning
Jonathan Lewis
http://jonathanlewis.WordPress.com
http://www.jlcomp.demon.co.UK
"The greatest enemy of knowledge is not ignorance, it is the illusion of knowledge." Stephen Hawking.
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