Files catproc. SQL and catalog.sql
I am using oracle 10g recently that I managed two files catproc.sql and catalog files by connecting to sysAfter running these files in sys when I select
Select * from tab;
no lines have been returned
(1) these files will show any eeect on database
(2) to Toad when I connect to the Toad for data base is to show all the user sys tables
will there be an effect of the execution of these files
After running these scripts, you will need to create spfile from pfile and the startup pfile from this file file
is incorrect. Catproc.sql and Catalog.SQL don't change the values of instance parameter. The instance parameter files are useless to be recreated.
Hemant K Collette
Tags: Database
Similar Questions
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Hello
DB version: 10.2.0.4.0 cluster db. EA
Version of the OS: Win server 2008
by mistake one of our dba ran CATPROC.sql and CATALOG.sql scripts in our live production rac database.
After that issues rose and developers face invalid objects. We erased our users manually main invalid objects and it looks like everything is working well for the moment.
BUT when I checked object invalid status, he showed me some 600 disabled objects. I'm afraid in the future will come from unacceptable errors.
What should do? any suggestions? are we in danger? What are workarounds.
Thank you
You must connect a SR with Oracle's Support.
Hemant K Collette
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Creation of database without executing the script catproc.sql and catalog.sql
Hello
I created the database of towing without running catalog.sql and catproc.sql. Someone knows what's the downside to not run them?
ARMYou can run them at any time, and Yes, you must be connected as sysdba. In fact, it's in the scripts generated dbca.
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Sybrand Bakker
Senior Oracle DBA -
Can file ms sql MDF contain viruses?
Hello
can file ms sql MDF contain viruses?
If yes how can check/clean before putting it on your server?
nikos101 wrote:
can file ms sql MDF contain viruses?
Yes.
If yes how can check/clean before putting it on your server?
Install antivirus software. For example, ClamWin is free, and there is a free version of AVG. Download the latest antivirus software definitions.
Scan the MDF files. The virus usually corrupt the MDF file. So, I would not try to restore an infected file on the server, even after it has been cleaned. There are tools available to check the integrity of files MDF and even to repair. Search the Web.
There are two things you should not do. Do a virus scan on a file to a running instance of MS SQL MDF, or configure your anti-virus program's automatic protection function to include the files of MS SQL MDF. This is because the program antivirus and MS SQL can compete for the lock on these files. For more details, see Microsoft 'Guidelines for choosing to run antivirus software on computers that are running SQL Server'
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Can I transfer my photo files and catalog items on my old laptop to the elements on my new laptop by simply copying manually on? or is it best done important photo files using organizers "Import" function together with function catalog restore?
A response to clarify this would be appreciated
Photoshop Elements help / use Backup, Restore to move the catalog | Organizer | Elements of 6 or newer.
http://helpx.Adobe.com/Photoshop-elements/KB/backup-restore-move-catalog-Photoshop.html
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Moved the folder "Pictures" of Mac and catalog image files shows no images. Cannot navigate to the appropriate folder in 'Files' Panel and cannot rename the folder "Images". How can I reconnect catalog image files?
You opened an empty catalog.
You can try the following two steps to open the appropriate catalog file.
- Use the file-> open recent, open the list of all catalogs
- If this does not work, you will need to find the appropriate help for your operating system catalog file and double-click it to open it.
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How to generate Trace files in SQL * more
Hi friends,
How to generate Trace files in SQL * more?
I have no idea
Thank you
REDAhttp://www.orafaq.com/wiki/SQL_Trace
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2 questions related to saving files in SQL Developer, using the function "save under":
-Is it possible to implement (by default) the last directory used, rather than raise the user's home directory?
-Is it possible to define or implement default extensions for different types of files IE pkb/pks of packets, tpb/GST for types instead of .sql for everything?
Thanks :)demuire wrote:
2 questions related to saving files in SQL Developer, using the function "save under":-Is it possible to implement (by default) the last directory used, rather than raise the user's home directory?
N ° more useful option, is that it records recent directories in the list shortcut on the left to save in the dialog box.
Asked often before. Interestingly, the dialog box open the default file is the last used directory in session even if you start at HOME after each reboot.-Is it possible to define or implement default extensions for different types of files IE pkb/pks of packets, tpb/GST for types instead of .sql for everything?
No once again. I don't know if this has been requested, but it is something I would find useful. You can ask in Exchange. http://Apex.Oracle.com/pls/OTN/f?p=42626:37:289830270605633
Thanks :)
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Which is the size of the file through sql/sqlplus
Dear all
I have set up 10g database job sheduler that auto export dump file, I want to check the size of the file (using sql/Plsql) after completing the work on E:\dumps\01012008.dmp.
What function can I use, how can I do that.
Thank youYou set the directory correcly?
If so, it will be workfine...-bash-3.00$ ls -ltr VI.DAT -rw-r----- 1 orapps oinstall 41951232 Oct 21 12:11 VI.DAT SQL> DECLARE 2 ex BOOLEAN; 3 flen NUMBER; 4 bsize NUMBER; 5 BEGIN 6 utl_file.fgetattr('DIR1', 'VI.DAT', ex, flen, bsize); 7 IF ex THEN 8 dbms_output.put_line('File Exists'); 9 ELSE 10 dbms_output.put_line('File Does Not Exist'); 11 END IF; 12 dbms_output.put_line('File Length: ' || TO_CHAR(flen)); 13 dbms_output.put_line('Block Size: ' || TO_CHAR(bsize)); 14 END fgetattr; 15 / File Exists File Length: 41951232 Block Size: 4096
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My recovery file is full and more limit. How can I remove back unnecessary ups and delete files.
I tried below it gave me an error. Kindly tell me what steps to take to remove unnecessary files and add additional space to my recovery file.
Thanks in advance
RMAN > target /.
RMAN-00571: ===========================================================
RMAN-00569: = ERROR MESSAGE STACK FOLLOWS =.
RMAN-00571: ===========================================================
RMAN-00558: error occurred during parsing of order entry
RMAN-01009: syntax error: found 'target': expected an a: "advise, allow, a.
lter, backup, @, catalog, change, configure, connect, convert, copy, create, cro
sscheck, delete, drop, duplicate, leave, flashback, grant, host, import, list, mo
UNT, open, print, quit, collect, register, release, repair, replace, report, res
HE, restoration, resync, revoke, run, sending, game, show, stop, coil, sql, start
pass, carry, cancel the registration, update, validate, {,'
RMAN-01007: line 1 column 1 file: entry standard
RMAN > delete archivelog all;
RMAN-00571: ===========================================================
RMAN-00569: = ERROR MESSAGE STACK FOLLOWS =.
RMAN-00571: ===========================================================
RMAN-03002: failure of the delete command at 09/02/2014 20:48:19
RMAN-06171: not connected to the target database
RMAN >
Hello
If you could not ask about your db, you can watch in the log_archive_dest_1 parameter, which is in the init.ora file, to know where are your archived log files.
my previous post would not be the solution to your problem, if so you can manually delete the archived logs and then delivers the command of rman below
overlap archivelog all
Concerning
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There was an error opening this document. The file is damaged and cannot be repaired.
Greetings,
I searched the forums, and this mistake has been examined in the context of how to treat a damaged PDF file.
My question is a little different. The company that I am working has a tool to create what we call "knowledge base articles", i.e. product XML authoring with us help topics. They used this tool from 2008. Files can be attached to a topic. The XML files and attached PDF files is stored in a SQL database. Using the TOC Panel or the search function, relevant topics are retrieved.
When there is an attached PDF, users can view the PDF in the browser or download the file and open it locally.
The knowledge base has been moved from an environment of database SQL 2005 in Windows Server 2003 and IIS 6 for an environment database of SQL 2008 R2 to Windows Server 2008 R2, IIS 7.
Now that we have the following problem: in some subjects the downloaded PDF can't be opened and one error
"There is an error opening this document. The file is damaged and cannot be repaired. "is displayed. The curious is that some PDF files published this error, while others open without a problem. Source file all PDF files open without a hitch before they are downloaded.
Any advice or pointers would be very appreciated.
TIA, Donna
Donna,.
as you have probably read in a lot of discussions on this matter, this error message is usually correct, and the PDF file is damaged. As for how it gets damaged, it's something you need to know by poking around in your system. Here are a few general things that always apply when working with corrupt files:
The first thing I would do is open such a file corrupted in a text editor such as NotePad to see what it actually contains. Any valid PDF file must begin with '% PDF -' followed by a version number. If you don't see that in the first line, then you are not dealing with a PDF file and you know why you do not get the file saved in your knowledge base.
If this string is there, then you know that there a PDF file and the issue is somewhere in this file, and is where it gets much more complex. You will need a good understanding of the PDF specification to parse the file to see what is wrong with him.
If you're lucky, you'll actually have a file of length zero (which means also no PDF header). No valid PDF file cannot be zero bytes long. Your second chance case would you find in fact an HTML error in this file (instead of PDF content), that tells you the reason for the problem (but again, this depends on your system).
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DB file sequential read and read of the direct path
Hello
Could someone please clear my doubts about 'db file sequential read' and ' path direct reading. And help me understand the tkprof report correctly.
Please suggest if my understanding for scenario below is correct.
We have a 11.2.0.1 ' cluster 2 node rac version + asm' production and environment of his test environment that is a stand-alone database.
The query performs well in production compared to the test database.
The table is to have 254 + columns (264) with many lobs coulumns however LOB is not currently selected in the query.
I read in metalink this 254 table + column a intra-line-chaining, causing "db file sequential read" full table Scan.
Here are some details on the table which is similar to the prod and test, block size is 8 k:
What I understand less tkprof in production environment for a given session is:TABLE UNUSED BLOCKS TOTAL BLOCKS HIGH WATER MARK ------------------------------ --------------- --------------- --------------- PROBSUMMARYM1 0 17408 17407
1 - the request resulted in disk 19378 readings and 145164 consistent readings.
2 19378 disc bed, 2425 reads disc has given rise to the wait event 'db file sequential read'.
This statement is correct this disc remaining readings were "db file sequential reads" but real quick so didn't wait event tied to it?
3 - 183 'direct path read' there also. Is it because of the order by clause of the query?
The same query when ran in no no rac - asm test stand alone database has given below tkprof.SQL ID: 72tvt5h4402c9 Plan Hash: 1127048874 select "NUMBER" num from smprd.probsummarym1 where flag ='f' and affected_item = 'PAUSRWVP39486' order by num asc call count cpu elapsed disk query current rows ------- ------ -------- ---------- ---------- ---------- ---------- ---------- Parse 1 0.00 0.00 0 0 0 0 Execute 1 0.00 0.00 0 0 0 0 Fetch 1 0.53 4.88 19378 145164 0 0 ------- ------ -------- ---------- ---------- ---------- ---------- ---------- total 3 0.53 4.88 19378 145164 0 0 Misses in library cache during parse: 0 Optimizer mode: ALL_ROWS Parsing user id: SYS Rows Row Source Operation ------- --------------------------------------------------- 0 SORT ORDER BY (cr=145164 pr=19378 pw=0 time=0 us cost=4411 size=24 card=2) 0 TABLE ACCESS FULL PROBSUMMARYM1 (cr=145164 pr=19378 pw=0 time=0 us cost=4410 size=24 card=2) Elapsed times include waiting on following events: Event waited on Times Max. Wait Total Waited ---------------------------------------- Waited ---------- ------------ SQL*Net message to client 1 0.00 0.00 ges message buffer allocation 3 0.00 0.00 enq: KO - fast object checkpoint 2 0.00 0.00 reliable message 1 0.00 0.00 KJC: Wait for msg sends to complete 1 0.00 0.00 Disk file operations I/O 1 0.00 0.00 kfk: async disk IO 274 0.00 0.00 direct path read 183 0.01 0.72 db file sequential read 2425 0.05 3.71 SQL*Net message from client 1 2.45 2.45
Does this mean that:
1-here too, reads happen through "db file sequential read", but they were so fast that has failed to the wait event?
2. "direct path read," it's because of the order clause in the query. "
For trace files in the database Production and Test, I see that 'direct path read' is against the same data file that's stored table.SQL ID: 72tvt5h4402c9 Plan Hash: 1127048874 select "NUMBER" num from smprd.probsummarym1 where flag ='f' and affected_item = 'PAUSRWVP39486' order by num asc call count cpu elapsed disk query current rows ------- ------ -------- ---------- ---------- ---------- ---------- ---------- Parse 1 0.00 0.00 0 0 0 0 Execute 1 0.00 0.06 0 0 0 0 Fetch 1 0.10 0.11 17154 17298 0 0 ------- ------ -------- ---------- ---------- ---------- ---------- ---------- total 3 0.10 0.18 17154 17298 0 0 Misses in library cache during parse: 0 Optimizer mode: ALL_ROWS Parsing user id: SYS Rows Row Source Operation ------- --------------------------------------------------- 0 SORT ORDER BY (cr=17298 pr=17154 pw=0 time=0 us cost=4694 size=12 card=1) 0 TABLE ACCESS FULL PROBSUMMARYM1 (cr=17298 pr=17154 pw=0 time=0 us cost=4693 size=12 card=1) Elapsed times include waiting on following events: Event waited on Times Max. Wait Total Waited ---------------------------------------- Waited ---------- ------------ SQL*Net message to client 1 0.00 0.00 Disk file operations I/O 1 0.00 0.00 db file sequential read 3 0.00 0.00 direct path read 149 0.00 0.03 SQL*Net message from client 1 2.29 2.29
Then how come 'this direct path read' because of the order by clause of the query and would have been in sort field size or pga?
Or this direct path read extracts real PGA disk data, and "db file sequential read" do not extract data?
I know, it's 'direct path read' is wait event when data are asked in PGA drive or what kind segment or temp tablespace is used.
Here is the example of trace file in the Production database:
Here are the trace file for the test database:*** 2013-01-04 13:49:15.109 WAIT #1: nam='SQL*Net message from client' ela= 11258483 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1357278555109496 CLOSE #1:c=0,e=9,dep=0,type=1,tim=1357278555109622 ===================== PARSING IN CURSOR #1 len=113 dep=0 uid=0 oct=3 lid=0 tim=1357278555109766 hv=138414473 ad='cfc02ab8' sqlid='72tvt5h4402c9' select "NUMBER" num from smprd.probsummarym1 where flag ='f' and affected_item = 'PAUSRWVP39486' order by num asc END OF STMT PARSE #1:c=0,e=98,p=0,cr=0,cu=0,mis=0,r=0,dep=0,og=1,plh=1127048874,tim=1357278555109765 EXEC #1:c=0,e=135,p=0,cr=0,cu=0,mis=0,r=0,dep=0,og=1,plh=1127048874,tim=1357278555109994 WAIT #1: nam='SQL*Net message to client' ela= 2 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1357278555110053 WAIT #1: nam='ges message buffer allocation' ela= 3 pool=0 request=1 allocated=0 obj#=-1 tim=1357278555111630 WAIT #1: nam='enq: KO - fast object checkpoint' ela= 370 name|mode=1263468550 2=65610 0=1 obj#=-1 tim=1357278555112098 WAIT #1: nam='reliable message' ela= 1509 channel context=3691837552 channel handle=3724365720 broadcast message=3692890960 obj#=-1 tim=1357278555113975 WAIT #1: nam='ges message buffer allocation' ela= 2 pool=0 request=1 allocated=0 obj#=-1 tim=1357278555114051 WAIT #1: nam='enq: KO - fast object checkpoint' ela= 364 name|mode=1263468550 2=65610 0=1 obj#=-1 tim=1357278555114464 WAIT #1: nam='KJC: Wait for msg sends to complete' ela= 9 msg=3686348728 dest|rcvr=65536 mtype=8 obj#=-1 tim=1357278555114516 WAIT #1: nam='ges message buffer allocation' ela= 2 pool=0 request=1 allocated=0 obj#=-1 tim=1357278555114680 WAIT #1: nam='Disk file operations I/O' ela= 562 FileOperation=2 fileno=6 filetype=2 obj#=85520 tim=1357278555115710 WAIT #1: nam='kfk: async disk IO' ela= 5 count=1 intr=0 timeout=4294967295 obj#=85520 tim=1357278555117332 *** 2013-01-04 13:49:15.123 WAIT #1: nam='direct path read' ela= 6243 file number=6 first dba=11051 block cnt=5 obj#=85520 tim=1357278555123628 WAIT #1: nam='db file sequential read' ela= 195 file#=6 block#=156863 blocks=1 obj#=85520 tim=1357278555123968 WAIT #1: nam='db file sequential read' ela= 149 file#=6 block#=156804 blocks=1 obj#=85520 tim=1357278555124216 WAIT #1: nam='db file sequential read' ela= 155 file#=6 block#=156816 blocks=1 obj#=85520 tim=1357278555124430 WAIT #1: nam='db file sequential read' ela= 4826 file#=6 block#=156816 blocks=1 obj#=85520 tim=1357278555129317 WAIT #1: nam='db file sequential read' ela= 987 file#=6 block#=156888 blocks=1 obj#=85520 tim=1357278555130427 WAIT #1: nam='db file sequential read' ela= 3891 file#=6 block#=156888 blocks=1 obj#=85520 tim=1357278555134394 WAIT #1: nam='db file sequential read' ela= 155 file#=6 block#=156912 blocks=1 obj#=85520 tim=1357278555134645 WAIT #1: nam='db file sequential read' ela= 145 file#=6 block#=156920 blocks=1 obj#=85520 tim=1357278555134866 WAIT #1: nam='db file sequential read' ela= 234 file#=6 block#=156898 blocks=1 obj#=85520 tim=1357278555135332 WAIT #1: nam='db file sequential read' ela= 204 file#=6 block#=156907 blocks=1 obj#=85520 tim=1357278555135666 WAIT #1: nam='kfk: async disk IO' ela= 4 count=1 intr=0 timeout=4294967295 obj#=85520 tim=1357278555135850 WAIT #1: nam='direct path read' ela= 6894 file number=6 first dba=72073 block cnt=15 obj#=85520 tim=1357278555142774 WAIT #1: nam='db file sequential read' ela= 4642 file#=6 block#=156840 blocks=1 obj#=85520 tim=1357278555147574 WAIT #1: nam='db file sequential read' ela= 162 file#=6 block#=156853 blocks=1 obj#=85520 tim=1357278555147859 WAIT #1: nam='db file sequential read' ela= 6469 file#=6 block#=156806 blocks=1 obj#=85520 tim=1357278555154407 WAIT #1: nam='db file sequential read' ela= 182 file#=6 block#=156826 blocks=1 obj#=85520 tim=1357278555154660 WAIT #1: nam='db file sequential read' ela= 147 file#=6 block#=156830 blocks=1 obj#=85520 tim=1357278555154873 WAIT #1: nam='db file sequential read' ela= 145 file#=6 block#=156878 blocks=1 obj#=85520 tim=135727855515
Thanks & Rgds,*** 2013-01-04 13:46:11.354 WAIT #1: nam='SQL*Net message from client' ela= 10384792 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1357278371354075 CLOSE #1:c=0,e=3,dep=0,type=3,tim=1357278371354152 ===================== PARSING IN CURSOR #1 len=113 dep=0 uid=0 oct=3 lid=0 tim=1357278371363427 hv=138414473 ad='c7bd8d00' sqlid='72tvt5h4402c9' select "NUMBER" num from smprd.probsummarym1 where flag ='f' and affected_item = 'PAUSRWVP39486' order by num asc END OF STMT PARSE #1:c=0,e=9251,p=0,cr=0,cu=0,mis=0,r=0,dep=0,og=1,plh=1127048874,tim=1357278371363426 EXEC #1:c=0,e=63178,p=0,cr=0,cu=0,mis=0,r=0,dep=0,og=1,plh=1127048874,tim=1357278371426691 WAIT #1: nam='SQL*Net message to client' ela= 2 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1357278371426766 WAIT #1: nam='Disk file operations I/O' ela= 1133 FileOperation=2 fileno=55 filetype=2 obj#=93574 tim=1357278371428069 WAIT #1: nam='db file sequential read' ela= 51 file#=55 block#=460234 blocks=1 obj#=93574 tim=1357278371428158 WAIT #1: nam='direct path read' ela= 31 file number=55 first dba=460235 block cnt=5 obj#=93574 tim=1357278371428956 WAIT #1: nam='direct path read' ela= 47 file number=55 first dba=136288 block cnt=8 obj#=93574 tim=1357278371429099 WAIT #1: nam='direct path read' ela= 80 file number=55 first dba=136297 block cnt=15 obj#=93574 tim=1357278371438529 WAIT #1: nam='direct path read' ela= 62 file number=55 first dba=136849 block cnt=15 obj#=93574 tim=1357278371438653 WAIT #1: nam='direct path read' ela= 17 file number=55 first dba=136881 block cnt=7 obj#=93574 tim=1357278371438750 WAIT #1: nam='direct path read' ela= 35 file number=55 first dba=136896 block cnt=8 obj#=93574 tim=1357278371438855 WAIT #1: nam='direct path read' ela= 22 file number=55 first dba=136913 block cnt=7 obj#=93574 tim=1357278371438936 WAIT #1: nam='direct path read' ela= 19 file number=55 first dba=137120 block cnt=8 obj#=93574 tim=1357278371439029 WAIT #1: nam='direct path read' ela= 36 file number=55 first dba=137145 block cnt=7 obj#=93574 tim=1357278371439114 WAIT #1: nam='direct path read' ela= 18 file number=55 first dba=137192 block cnt=8 obj#=93574 tim=1357278371439193 WAIT #1: nam='direct path read' ela= 16 file number=55 first dba=137201 block cnt=7 obj#=93574 tim=1357278371439252 WAIT #1: nam='direct path read' ela= 17 file number=55 first dba=137600 block cnt=8 obj#=93574 tim=1357278371439313 WAIT #1: nam='direct path read' ela= 15 file number=55 first dba=137625 block cnt=7 obj#=93574 tim=1357278371439369 WAIT #1: nam='direct path read' ela= 22 file number=55 first dba=137640 block cnt=8 obj#=93574 tim=1357278371439435 WAIT #1: nam='direct path read' ela= 702 file number=55 first dba=801026 block cnt=126 obj#=93574 tim=1357278371440188 WAIT #1: nam='direct path read' ela= 1511 file number=55 first dba=801154 block cnt=126 obj#=93574 tim=1357278371441763 WAIT #1: nam='direct path read' ela= 263 file number=55 first dba=801282 block cnt=126 obj#=93574 tim=1357278371442547 WAIT #1: nam='direct path read' ela= 259 file number=55 first dba=801410 block cnt=126 obj#=93574 tim=1357278371443315 WAIT #1: nam='direct path read' ela= 294 file number=55 first dba=801538 block cnt=126 obj#=93574 tim=1357278371444099 WAIT #1: nam='direct path read' ela= 247 file number=55 first dba=801666 block cnt=126 obj#=93574 tim=1357278371444843 WAIT #1: nam='direct path read' ela= 266 file number=55 first dba=801794 block cnt=126 obj#=93574 tim=1357278371445619
Vijay911786 wrote:
Direct path readings can be done on the series tablescans in your version of Oracle, but if you have chained rows in the table and then Oracle can read read read the beginning of the line in the path directly, but must make a single block in the cache (the db file sequential read) to get the next part of the line.
It is possible that your production system has a lot of chained rows, while your test system is not. As corroboration (though not convincing) indicator of what you might notice that if you take (reads disc - db file sequential reads) - who might get you close to all the blocks direct read - the numbers are very similar.
I'm not 100% convinced that it's the answer for the difference in behavior, but worth a visit. If you can force and indexed access path in the table, do something like "select / * + index (use {pk}) * / max table (last_column_in_table)" and check the number of "table fetch continued lines" could be close to the number of db file sequential reads you. (There are other options for the counting of the chained rows that could be faster).
Concerning
Jonathan Lewis -
The error code is 800b0100 when he tried to update. Updates were the .net framework 3.5 SP1 and the upgrade to SP2. I ran the System File Checker, and the result is corrupted system files, but could not be repaired. The content of the log files is as below:
=================================
Preparation of control system was updated.
Binary version 6.0.6002.22202
Package Version 6.0
2009-11-19 00:47Checking Windows Service Packages
Checking of manifests package and catalogs
Checking package Watchlist
Watchlist checking
Checking packages
(f) MOTHER of CBS missing 0 x 00000002 servicing\packages\Package_for_KB948609_client_1~31bf3856ad364e35~x86~~6.0.6001.3053.mum
(f) MOTHER of CBS missing 0 x 00000002 servicing\packages\Package_for_KB948609_client~31bf3856ad364e35~x86~~6.0.6001.3053.mum
(f) MOTHER of CBS missing 0 x 00000002 servicing\packages\Package_for_KB948609~31bf3856ad364e35~x86~~6.0.6001.3053.mumControl components store
Summary:
Seconds executed: 3579
Found 3 errors
CBS MUM lack count: 3Unavailable repair files:
servicing\packages\Package_for_KB948609_client_1~31bf3856ad364e35~x86~~6.0.6001.3053.mum
servicing\packages\Package_for_KB948609_client~31bf3856ad364e35~x86~~6.0.6001.3053.mum
servicing\packages\Package_for_KB948609~31bf3856ad364e35~x86~~6.0.6001.3053.mum
servicing\packages\Package_for_KB948609_client_1~31bf3856ad364e35~x86~~6.0.6001.3053.cat
servicing\packages\Package_for_KB948609_client~31bf3856ad364e35~x86~~6.0.6001.3053.cat
servicing\packages\Package_for_KB948609~31bf3856ad364e35~x86~~6.0.6001.3053.catand the second log file is:
=================================
Preparation of control system was updated.
Binary version 6.0.6002.22202
Package Version 6.0
2009-10-05 14:49Checking Windows Service Packages
Checking of manifests package and catalogs
Checking package Watchlist
Watchlist checking
Checking packages
(f) MOTHER of CBS missing 0 x 00000002 servicing\packages\Package_for_KB948609_client_1~31bf3856ad364e35~x86~~6.0.6001.3053.mum
(f) MOTHER of CBS missing 0 x 00000002 servicing\packages\Package_for_KB948609_client~31bf3856ad364e35~x86~~6.0.6001.3053.mum
(f) MOTHER of CBS missing 0 x 00000002 servicing\packages\Package_for_KB948609~31bf3856ad364e35~x86~~6.0.6001.3053.mumControl components store
Summary:
Seconds executed: 1509
Found 3 errors
CBS MUM lack count: 3Unavailable repair files:
servicing\packages\Package_for_KB948609_client_1~31bf3856ad364e35~x86~~6.0.6001.3053.mum
servicing\packages\Package_for_KB948609_client~31bf3856ad364e35~x86~~6.0.6001.3053.mum
servicing\packages\Package_for_KB948609~31bf3856ad364e35~x86~~6.0.6001.3053.mum
servicing\packages\Package_for_KB948609_client_1~31bf3856ad364e35~x86~~6.0.6001.3053.cat
servicing\packages\Package_for_KB948609_client~31bf3856ad364e35~x86~~6.0.6001.3053.cat
servicing\packages\Package_for_KB948609~31bf3856ad364e35~x86~~6.0.6001.3053.cat=================================
Preparation of control system was updated.
Binary version 6.0.6002.22202
Package Version 6.0
2009-11-18 23:53Checking Windows Service Packages
Checking of manifests package and catalogs
Checking package Watchlist
Watchlist checking
Checking packages
(f) MOTHER of CBS missing 0 x 00000002 servicing\packages\Package_for_KB948609_client_1~31bf3856ad364e35~x86~~6.0.6001.3053.mum
(f) MOTHER of CBS missing 0 x 00000002 servicing\packages\Package_for_KB948609_client~31bf3856ad364e35~x86~~6.0.6001.3053.mum
(f) MOTHER of CBS missing 0 x 00000002 servicing\packages\Package_for_KB948609~31bf3856ad364e35~x86~~6.0.6001.3053.mumControl components store
Summary:
Seconds executed: 1237
Found 3 errors
CBS MUM lack count: 3Unavailable repair files:
servicing\packages\Package_for_KB948609_client_1~31bf3856ad364e35~x86~~6.0.6001.3053.mum
servicing\packages\Package_for_KB948609_client~31bf3856ad364e35~x86~~6.0.6001.3053.mum
servicing\packages\Package_for_KB948609~31bf3856ad364e35~x86~~6.0.6001.3053.mum
servicing\packages\Package_for_KB948609_client_1~31bf3856ad364e35~x86~~6.0.6001.3053.cat
servicing\packages\Package_for_KB948609_client~31bf3856ad364e35~x86~~6.0.6001.3053.cat
servicing\packages\Package_for_KB948609~31bf3856ad364e35~x86~~6.0.6001.3053.cat=================================
Preparation of control system was updated.
Binary version 6.0.6002.22202
Package Version 6.0
2009-11-19 00:47Checking Windows Service Packages
Checking of manifests package and catalogs
Checking package Watchlist
Watchlist checking
Checking packages
(f) MOTHER of CBS missing 0 x 00000002 servicing\packages\Package_for_KB948609_client_1~31bf3856ad364e35~x86~~6.0.6001.3053.mum
(f) MOTHER of CBS missing 0 x 00000002 servicing\packages\Package_for_KB948609_client~31bf3856ad364e35~x86~~6.0.6001.3053.mum
(f) MOTHER of CBS missing 0 x 00000002 servicing\packages\Package_for_KB948609~31bf3856ad364e35~x86~~6.0.6001.3053.mumControl components store
Summary:
Seconds executed: 3579
Found 3 errors
CBS MUM lack count: 3Unavailable repair files:
servicing\packages\Package_for_KB948609_client_1~31bf3856ad364e35~x86~~6.0.6001.3053.mum
servicing\packages\Package_for_KB948609_client~31bf3856ad364e35~x86~~6.0.6001.3053.mum
servicing\packages\Package_for_KB948609~31bf3856ad364e35~x86~~6.0.6001.3053.mum
servicing\packages\Package_for_KB948609_client_1~31bf3856ad364e35~x86~~6.0.6001.3053.cat
servicing\packages\Package_for_KB948609_client~31bf3856ad364e35~x86~~6.0.6001.3053.cat
servicing\packages\Package_for_KB948609~31bf3856ad364e35~x86~~6.0.6001.3053.catFree unlimited installation and compatibility support is available for Windows Vista, but only for Service Pack 2 (SP2). This support, initially planned to end on November 26, 2009, has been postponed until February 26, 2010, so move on! Availability of support chat or messaging differs depending on your location. Some questions may require that more support for which he is advanced a charge. Go to http://support.microsoft.com/oas/default.aspx?prid=13014&gprid=582034 & select appropriate category (i.e., download problem;) Installation problem; Problems after installing a service pack). ~ Robear Dyer (PA Bear) ~ MS MVP (that is to say, mail, security, Windows & Update Services) since 2002 ~ WARNING: MS MVPs represent or work for Microsoft
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Should I get rid of old files from Lightroom and start again?
I messed up download in Lightroom and about half of my photos and files "is not found." While Lightroom has been deleted when my PC was repaired, so my I just downloaded again. I want to download correctly this time. No pictures is currently in Lightroom.
I have the following locations of photo on my PC: my images, external hard drive (ED) 1 and (ED) 2. All have bits of catalogues Lightroom etc (not the photo files can I open) on them. I have a plan and want to know if it will work.
I'll make all my photos on ED1 outside of Lightroom. I'll remove Lightroom from my computer AND delete the "bits" containing photos of all three locations.
I can download Lightroom again and download my pictures inside of ED1. This way Lightroom will know where they are.
My plan will subsequently be to download all photos of ED 1. (How can I configure this?) I want to set up Lightroom to backup to ED2. (How do I do this?)
I would appreciate help as my previous attempts to solve the problem just make it worse!
I'll make all my photos on ED1 outside of Lightroom.
I assume that you know how to do it
I'll remove Lightroom from my computer AND delete the "bits" containing photos of all three locations. I then download Lightroom again
Completely useless. Open Lightroom, select file-> new catalogue and you will have an empty empty catalog to use. You must then import the ED1 photos using the Add option (MOVE or COPY, as appropriate)
My plan will subsequently be to download all photos of ED 1.
I guess you means importation and not download. In the import dialog box, select the option COPY and then under Destination (on the right side), you select the appropriate folder to import into on ED1.
I want to set up Lightroom to backup to ED2. (How do I do this?)
You can use the third-party backup software to achieve for the photos. You can use Lightroom itself to make backups of the catalog file (it is under the catalog settings).
Alternatively, you can tell Lightroom to make copies of your photos to ED2 to import, as explained here: https://helpx.adobe.com/lightroom/help/photo-video-import-options.html#back_up_photos_duri ng_import if you do this, you will still need to make regular backups of your catalog (via the option in the catalog settings) file
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target, auxiliary and catalog database
Hi gurus,
I need to have a few lights on the target, auxiliary and catalog databases.
especially difference between the auxiliary and the database catalog.
Kind regards
Manish
Hello
Your target is the database that you are backing up, and in the case of a duplicate database, it would be the source database. Example below is when I connect to the target database, which is what I want to save (note that below I sign in using the catalog in which case we'll use the controlfile and no catalog).
oracle:/home/oracle:testdb #> rman target / Recovery Manager: Release 11.2.0.3.0 - Production on Mon Feb 17 15:24:02 2014 Copyright (c) 1982, 2011, Oracle and/or its affiliates. All rights reserved. connected to target database: testdb (DBID=2759143361) RMAN>
The auxiliary database is the database which, in the case of a duplicate database, the database that you duplicate would be. So, for example, that if you configure a database ensure using the duplicate database (and maybe double active database database) the main database would be the target and the database pending would be the auxiliary.
The catalog database is when you use a RMAN catalog instead of using the control file... Note below to specify the catalog when you connect and it says 'connected to the datalog retrieval database' once you have connected that he did not in the example above when you signed in using the control file. In this case, the rman information is stored in the control as well as the datalog database file. (Control NB file is always the primary source").
oracle:/home/oracle:testdb #> rman target / catalog rman/password@rcat1 Recovery Manager: Release 11.2.0.3.0 - Production on Mon Feb 17 15:24:16 2014 Copyright (c) 1982, 2011, Oracle and/or its affiliates. All rights reserved. connected to target database: testdb (DBID=2759143361) connected to recovery catalog database RMAN>
There are several reasons why a catalogue database is used... for example:
(1) it can store scripts.
(2) you have a central repository for all of your databases.
(3) you are not limited as to how long you can store your backup information. Thie is determined by the controlfile_record_keep_time parameter when you use the controlfile and you type can be set quite high but then your controlfile can grow quite large as well.
Stor for more information on the recovery catalog, you can see below:
http://docs.Oracle.com/CD/E25054_01/backup.1111/e10642/rcmcatdb.htm
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