find all duplicates

Hello guys,.

I want to know how to find all duplicate of a set of data records, in my application a duplicate is a combination of two columns, I do not want to group them, I want to know all the records duplicates

example of

CREATE TABLE EMPLOYER
(
ID NUMBER (12).
SSN VARCHAR2 (BYTE 9),
WGE NUMBER (10,2).
ERR_flg VARCHAR2 (1 BYTE)
)

INSERT INTO EMPLOYER(ID,SSN,WGE) VALUES (1,222222222,2532)
INSERT INTO EMPLOYER(ID,SSN,WGE) VALUES (2,111111111,2352)
INSERT INTO EMPLOYER(ID,SSN,WGE) VALUES (3,555555555,232)
INSERT INTO EMPLOYER(ID,SSN,WGE) VALUES (4,555555555,232)

3RD AND 4TH RECORDS ARE DUPLICATED... I WANT TO SHOW THEM IN MY QUERY AND UPDATE THE ERR_FLG TO 1

Thank you

Hello

Here's a way to get the results of a query without grouping:

WITH     got_cnt        AS
(
     SELECT     id, ssn, wge
     ,     COUNT (*) OVER ( PARTITION BY  ssn
                              ,            wge
                      ) AS cnt
     FROM    employer
)
SELECT     id, ssn, wge
FROM     got_cnt
WHERE     cnt     > 1
;

Almost all of the functions of aggregation (such as COUNT) have analytical equivalents, which can produce the same results without collapsing the data in one row per group.
The PARTITION BY an analytical function of clause is the clause GROUP BY of an aggregate query.

However, the update, what is wrong with grouping?
You can use something like the query above as a subquery in an UPDATE statement, but you will get the same results more simply with GROUP BY:

UPDATE  employer
SET     err_flg     = '1'
WHERE     (ssn, wge)     IN (
                    SELECT    ssn, wge
                    FROM      employer
                         GROUP BY  ssn, wge
                         HAVING    COUNT (*)     > 1
                           )
;

Published by: Frank Kulash, 24 May 2010 15:00
Additional UPDATE... GROUP BY example

Tags: Database

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