Find ' [' and get the substring entered using regexp_substr()]

Hello

Select regexp_substr ("what a great day for (I YOU [ME] and HIM ',' [: ALNUM:] * [^ \ ()] *') double;")
As a result:
SQL > what a great day for

[but why this model does not work for ']' when I replace ' ([' with ']'?)
Select regexp_substr ("what a great day for (I YOU [ME] and HIM ',' [: ALNUM:] * [^ \]] *') double;")
As a result:
SQL > W

' {[I need to get a substring before or ' (',' [',' {', '}])', ']', or '}' in a string to give, this model works for '(',') ', ' {', '}' but not ' [' or ']'
What should be the boss? If ' [: ALNUM:] * [^ \ ()] *' is not correct?

Can anyone help?

Thank you
Fiona

Hi, Fiona,

Have you seen this part of my last post?

Frank Kulash wrote:
... If you want to use a literal hook closing ('] ') then it must be the first thing in the list attached hook (not counting the ^, if you use it, you are)

In a regular expression, if you want to say: "the set of all characters * except * ' {' and '}'", so it does not matter if you say

[^{}]

[^}{]

Most of the people (you and me included) seem to like the first better way, but the results are the same. It deosn to matter if the ' {' is listed before the '}', or if they are in reverse order. The Analyzer don't think you want to say something else anyway.

However, the parser will treat this expression

[^[]]

different than

[^][]

The first:

[^[]]

is interpreted as

'['          ||     -- Any character from this set:
   '^'          ||     --     all characters except
   '['          ||     --     left-bracket
']'          ||     -- (end of set description)
']'               -- followed immediately by a right-bracket

You want to support the right to part of the whole. The only way that the parser will know that the right-braket marks not the end of the game is to put the right first overall support, in other words, it must be the first character inside the pair of brackets that delimited the game, immediately after the ' ^' character, like this:

'['          ||     -- Any character from this set:
   '^'          ||     --     all characters except
   ']'          ||     --     right-bracket or
   '['          ||     --     left-bracket
']'               -- (end of set description)

or, as you're more likely to write it:

select      'What a good day for (YOU [ME] and {HIM}) and others'     AS orig_txt
,     REGEXP_REPLACE ( 'What a good day for (YOU [ME] and {HIM}) and others'
                 , '\[[^][]*\]'
                 )                         AS new_txt
from      dual
;

Output:

ORIG_TXT
---------------------------------------------------
NEW_TXT
-----------------------------------------------
What a good day for (YOU [ME] and {HIM}) and others
What a good day for (YOU  and {HIM}) and others

Tags: Database

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