Find most common value in a table of enums

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• Find the minimum value of the table in time...

  Firstly that it is not "find the min value in the table.

  It is:

  I have a table that changes its values at each iteration, and I want to compare the new values with previous values and make a new array with the minimum values...

  In C++, it would be like this:

  int main() {}

  int array [8];

  int min [8];

  int i;

  for (i = 0; i<>

  min [i] = 1000000; Initialize minimum table with a high value

  }

  {while (1)}

  Array = update_array ();

  for (i = 0; i<>

  If (array [i]<>

  min [i] = array [i];

  }

  }

  do things...

  }

  return 0;

  }

  IM new to labview and it always confuses me a lot...

  Thanks in advance.

  Using the function Max & Min regular (not table Max & min as you know) with tables and a good will of employment registry change.  Max Min &, as most of the digital functions, is polymorphic and works witt tables as well as scalars.

  Lynn

  

• maximum values of five table 2d

  Hi, I have a vi that reads in the values of a 2D array, and then uses this information. I currently use the vi 'Table Max and Min' to find the maximum values of the table. It can be beneficial for my application find the maximum of 5 or any other number of values in the table. My current plan is to use a loop that detects that the maximum value of the original array and then subtract this value and repeat the operation once 5 or greater. However, I believe that it is innefficient and can take a long time in a vi that must run pretty quickly. I would like suggestions. Thanks in advance.

  It would be a bit faster

  

  After overhaul at 1 d

  Sort the table (from the smallest to largest)

  Turn the tide (the biggest to the smallest now

  Get the highest values since the beginning

• PL/SQL loop to find the minimum value

  I want to find the minimum value from a table using the pl/sql loop

  I have data format below.

  1 ABC 2

  1 ABC 20

  1 ABC 500

  1 ABC 2000

  XYZ 2 250

  JKL 3 300

  MNP 3 350

  3 KLM 400

  I wrote the code below. His does not work. Please suggest.

  Set serveroutput on
  declare
  x number: = 3;
  y VARCHAR2 (3): = 'ABC ';
  fmin number: = 0;
  number of Fmax: = 0;
  Start
  for rec in (select sal from test
  where id = name and x = y) loop

  
  If rec.sal > fmin then
  fmin: = rec.sal;
  on the other
  FMAX: = rec.sal;
  fmin: = fmax.
  end if;
  end loop;
  dbms_output.put_line (Fmax);
  end;
  /

  I want to output 2 on top of code.

  Thanks in advance

  Why PL/SQL? SELECT MIN (SAL) OF TEST will be more rapid and much less coding. In any case:

  declare

  number of v_min_sal;

  Start

  for v_rec in a loop (select sal from emp)

  If nvl (v_min_sal, v_rec.sal + 1) > v_rec.sal

  then

  v_min_sal: = v_rec.sal;

  end if;

  end loop;

  dbms_output.put_line (' lowest salaray is "' |") v_min_sal | '"');

  end;

  /

  The lowest Salaray is "800".

  PL/SQL procedure successfully completed.

  SQL >

  SY.

• Find a value in a table

  Hi, I'm trying to find the index of a value in a table, I know that it is a VI called 'research in a 1 d table' but there is my problem: Let's say I'm looking the value 25 and in my series of measurement, there like 24.998 and 25.001 but not 25, this VI will not find the value 25 although he went close enough , so basically I try to inplanta a tolerance system making it able to find with precision +-3 or 4 on the index, doing someone something for this?

  Thanks for your time

  I wrote this for a similar job, but it could be used for your application.  Just use the vi attached in a loop to check "in range" and returns the index of the loop of the first occurrence.

  Hope this helps

  Ken

• find the closest value in table

  Hi all

  I need to find the values in the "C" line which is equal or close to the values 'A' in the 2D array, and then I want to show the values of 'B', corresponding to the values of 'C' in table 2D.

  How can I fix it?

  Thank you!

  

  0.9967 nearest value is 0.993807 in the 8 Cand in row B row, not 1. The differences are 2.893E - 3 and 3.300E - 3.

  Subtract each value from the table C. take the absolute value of the difference. To find the index of at least using Max & Min value of B. Using autoindexing array Index, create the output array.

  Lynn

• To find the nth higher/lower value in a table

  Hi all

  I have a question

  in the table a1(empid,sal) are the 2 columns

  EmpID sal

  100-5000

  105 7500

  110 3500

  087 11136

  14336 95

  I didn't want to write the query that will give me the 3rd highest salary. or generalized to find the nth more eleve/nieme the lowest value of the table.

  Note:-Rownum and Rowid must not be used

  Thank you

  Hello

  You can use a generic result of queries to find nth highest salary...

  Just put the value of N in the query, you will get the answer...

  Query:

  SELECT E1. Salary OF EMP E1 WHERE (N) = (SELECT COUNT (DISTINCT E2. Salary) OF EMP E2 WHERE E2. Salary > = E1. Salary);

  hope you got the answer...

  Check if it really helps...

  thanxx...

• How to find null values in the table

  Hi experts,
  
  my version is oracledb10g:
  
  I am doubted simple.
  
  for example:
  
  create table ex1 (e varchar2 (20));
  
  Insert ex1 (null).
  
  insert into ex1 (e)
  
  number of will be: 2
  
  I can easily find the value "e".
  
  so my question is:
  
  How can I find null values in the table and I want to remove the null values from the table.

  ADF 7 wrote:
  Hi experts,

  my version is oracledb10g:

  I am doubted simple.

  for example:

  create table ex1 (e varchar2 (20));

  Insert ex1 (null).

  insert into ex1 (e)

  number of will be: 2

  It depends on what you expect. If you issue count (*) you ask Oracle "how many lines there. If you issue a County () you ask Oracle 'how non null values for are there. "

  ADF 7 wrote:

  I can easily find the value "e".

  so my question is:

  How can I find null values in the table and I want to remove the null values from the table.

  delete from 
  where  is null;
  

  Ideally you would simply place a NOT NULL constraint on the column in question, thus prohibiting NULL values into the system (assuming that your business needs, it is that the column MUST always have a value).

• Need to find the common number

  Need to find a common number among all of the calls:
  
  
  
  Create table call (key id Number (15) not null, mobile_number number primary (10), other_party number (10), call_type varchar2 (10), the call_date_time date, number (15)) duration;
  
  
  insert into values of the call (1,9818764535,9899875643, 'IN', to_date (24 April 13 02:10:43 "," dd-MON-yy hh24:mi:ss'), 10);
  Insert in appeal values (2, 9897451236,9899875643, 'OUT', to_date (April 28, 13 08:11:13 "," dd-MON-yy hh24:mi:ss'), 20);
  Insert in appeal values (3, 9899917277,9899875643, 'IN', to_date (30 April 13 18:07:02 "," dd-MON-yy hh24:mi:ss'), 30);
  insert into values of the call (4,9818764535,9215478213, 'IN', to_date (1 May 13 02:11:13 "," dd-MON-yy hh24:mi:ss'), 40);
  Insert in appeal values (5, 9899917277,9215478213, 'IN', to_date (1 May 13 08:17:02 "," dd-MON-yy hh24:mi:ss'), 25);
  Insert in appeal values (6, 9897451236,9012451785, 'OUT', to_date (1 May 13 20:21:04 ',' dd-MON-yy hh24:mi:ss'), 67);
  
  
  
  Query criteria:
  
  common calling to the list of numbers that is in contact with the listed numbers.
  
  Mobile_number entry:
  9818764535
  9897451236
  9899917277
  
  
  exit number common
  
  Mobile another numberlength part Date_Time
  
  9818764535 9899875643 24 APRIL 13 02:10:43 10
  9897451236 9899875643 28 APRIL 13 08:11:13 20
  9899917277 9899875643 30 APRIL 13 18:07:02 30

  Hello

  One way is to encrypt the target in a table game or result, as above, knapen don't:

  WITH    input_number     AS
  (
       SELECT  9818764535 AS mobile_number  FROM dual    UNION ALL
         SELECT      9897451236                   FROM dual    UNION ALL
         SELECT      9899917277                FROM dual
  )
  SELECT     *     -- or list columns wanted
  FROM     call
  WHERE     mobile_number     IN (SELECT  mobile_number  FROM  input_number)
  AND     other_party     IN (SELECT  mobile_number  FROM  input_number)
  ;
  

• Assistance needed for the registration of the application and store the values in a table

  Hello

  Hope that this explanation is not confusing. I explained my application you want in the text below and also attached a skeleton VI + screenshot hoping that he will clarify

  I try to do a VI that does the following:
  1. some code (blue Subvi) runs every 200ms
  2. every 200ms, a random number is generated
  3. the random numbers are stored in a table in intervals of time s 0.8 ("iterations")
  4. at any time, the (blue Subvi) code needs to have access to the random numbers generated in 'the previous iteration.

  To clarify, the iterations are as follows:
  Iteration #1: 0 - 1.8 s
  Iteration #2: 2 - 2. 8 s
  Iteration #3: 3 - 3.8 s

  Iteration #4: 4 - 4.8 s
  ..
  And so on...

  So for each iteration: the blue (Subvi) needs to have access to the random numbers generated in the previous iteration, for example:

  Iteration #1 (0 - 1.8 s): The blue (Subvi) Gets an array that contains only the zero (random numbers are recorded for the first time)
  Iteration #2 (2s - 2 8 s): The code gets an array containing random numbers of iteration #1
  Iteration #3 (3 s - s 3.8): the code gets an array containing random numbers of iteration #2
  Iteration #4 (3 s - s 3.8): the code gets an array containing random numbers of iteration #3
  ..
  And so on...

  At any given time in time;
  -The code gets an array that contains all the random, recorded during the previous iteration numbers
  -Values since before her previous iteration are ignored and not stored anywhere

  Thus, for example, to the #7 iteration:

  -The values during the iteration #6 are made available to the code in the form of a table

  -Values of #1 to #5 iterations have been deleted and not stored anywhere

  It is important that all values since before recording the previous iteration are deleted because they are not necessary because VI actaual will work for a long period of storage of numbers a lot more than I have indicated here

  Screenshot of the skeleton VI:

  

  I tried to play with the paintings, the structures of the case and the registers at offset, but everytime I try I get something wrong

  The skeleton VI is also attached (Iteration_VI and Code_SubVI)

  Any suggestions?

  Thank you!

  Yes, I agree that you need help.  First of all, you really do need to learn more about LabVIEW - spend a few hours with the tutorials, such as those mentioned on the first page of the Forums.  Oops - links to the tutorials which had been present for years seem to have been moved "elsewhere" with August 2016 LabVIEW community reorganization.  But look for them...

  Here are a few screws that basically implement what I described above (with some minor modifications).  First of all, this is a Top level VI which runs at 5 Hz (200 msec waits).  It starts with an array of 5 elements of 0, then once per second, this is replaced by a table of random numbers generated by the Random 5-table sub - VI 5 elements.  Note that I do not use a loop timed - those who are really designed for LabVIEW RT, but use the simplest functions on the Palette of the timer.

  

  Can't you see how that works?  The array to initialize on the left begins you with a table of 5 elements of 0.  The Timer inside the loop, it runs at 5 Hz, 'Index' counts 1, 2, 3,... to tell you where you are, and 5 shows you everything that lives on the shift register.

  Now sub - VI Random 5-table is supposed to do the following - if she was called to 5, 10, 15,..., it must return a (new) array of 5 random numbers, otherwise, it must return the array that was passed in.  So if all "works", table 5 shows 0, 0, 0, 0, 0 for the first second, a table at random for the second second (which is not superfluous!), a different for the third random picture second and so on.  I have already said a way to build this, but I chose a slightly different method (equivalent).

  

  Whenever it is called, a new random element is generated and added at the end of a (growing) random table stored in the shift register.  If size become 5, we send this Random-table-of-5 out through Out table and reset the register shift to an empty array.

  The case by default (when the size is not equal to 5) is shown below - we just return the array of entry to and accumulate new random table in full growth.

  

  These code fragments extracted from VI.  If you have LabVIEW 2016 (see the "2016" at the top right of the image?  This shows that it is a snippet of code LabVIEW 2016), you can open a blank diagram and drag this image, where magic OR converts it to a VI.  Otherwise, the code yourself and try out it.

  Caution - it is designed to run once.  If you run the program of high level, a second time, you may find that the new Random 5 - table appears to 0.4 ", 1.4", 2.4"(instead of 1", 2 ", 3").  I leave as an exercise for understand you to (a) why he is and (b) fix the code.  If you can't do that, then move an another 3-4 hours with the LabVIEW tutorials (or start playing with this code, edit it in some small way and to understand how it works).

  Bob Schor

• Number of rows in each partition is displayed with a NULL value for a table partitioned in user_tab_partitions. Why?

  I created a table and partitioned on the date of the entry and added a local partitioned index.

  Now, I use a query to extract "num_rows" of user_tab_partitions to know the number of rows in each partition.

  Getting this value as null num_rows, wonder why?

  After looking to explain the Plan after interrogation ("select * from my_table1 where entry_date = 1 January 2015" ;))

  to find out if she actually partitioned table and its data in different partitions, I interpreted in effect because the query plan had a line like Partition_range (Single).

  My Question is:

  (a) is actually partitioned data (have I misinterpreted the Explain plan)

  (b) why is the num_rows null column in the query (Pasted below)

  (c) also in addition what difference it would have been if I had created a Global Index instead of the Local Index in my case?

  The following code Snippet:

  ----------------------------------------------------------------------------------------------

  create the table my_table1
  (
  roll_no number constraint my_table1_pk primary key,
  date of entry_date
  )
  partition of range (entry_date)
  (
  PARTITION data_p1 VALUES LESS THAN (TO_DATE (December 31, 2014 ',' DD-MM-YYYY ""));
  PARTITION data_p2 VALUES LESS THAN (MAXVALUE)
  );

  
  create an index only my_table1_indx on my_table1 (entry_date) local;

  ----------------------------------------------------------------------------------------------

  I now insert two lines:
  insert into my_table1 values (1, to_date ('01-01-2015', ' dd-mm-yyyy'));
  insert into my_table1 values (2, to_date('01-02-2015','dd-mm-yyyy'));

  ----------------------------------------------------------------------------------------------

  These have been inserted successfully, now using the query below shows num_rows column as null. I don't know why?

  SELECT table_name, num_rows, high_value, nom_partition
  Of user_tab_partitions
  where table_name = 'MY_TABLE1 '.
  ORDER BY table_name, nom_partition;

  ----------------------------------------------------------------------------------------------

  
  

  (a) is actually partitioned data (have I misinterpreted the Explain plan)

  Yes, it is partitioned. You can query this particular partition SELECT * FROM my_table1 (data_p1) PARTITION to check that.

  (b) why is the num_rows null column in the query (Pasted below)

  As already mentioned that you have not collected statistics.

  (c) also in addition what difference it would have been if I had created a Global Index instead of the Local Index in my case?

  In fact, you have created two types of indexes without knowing (can be)! One is not partitioned (although this column is not partition key) and another is partitioned (LOCAL). They are MY_TABLE1_PK and MY_TABLE1_INDX. You can check that USER_INDEXES.

  You can read this article to get an early jump on the partitioning of decision. Partition: Partition decisions

• The most common ideogram glyphs?

  Maybe this can be decided. Try to get a font via the localization process and I still find missing glyphs for the IDEOGRAM that I didn't create. Fortunately, less each iteration.

  Is there a reference for the more commonly used glyphs from fonts CYC list?

  I've included the Hiragana, Katakana and 72 of the unified IDEOGRAM ideograms. I hesitate to delve into the other UI CJK 20992 without going through a list or advice.

  Thanks in advance if anyone can point me in the right direction.

  Steve

  The most common CJK characters depends on the language or region. An obvious candidate is the ideogram meaning one, U + 4E00, located in the simpler East Asian regional character set standards. You choose the characters that are common in the whole of Asia of is more elementary standards of regional character, meaning GB 2312 (China), the Big Five (Taiwan), JIS X 0208 (Japan) and KS X 1001 (Korean) coding. Although no character codes are provided, this document can help narrow down the choices.

• table name not valid error when inserting values into a table

  I use the following statement to insert values into a table:
  
  curs. Execute ("INSERT INTO _ * '%s' * _ VALUES ((SELECT MAX (REC_ID) + 1 OF GSAP_MSG_IN), (SELECT MAX (gsap_msg_id) + 1 OF GSAP_MSG_IN), 'SHELLSAP', sysdate, '%s', EMPTY_BLOB(), 1, SYSDATE, EMPTY_BLOB (), SYSDATE)" %(*table_name*,file_extension)) ")
  
  whence table_name the following statement
  
  table_name = ' config.staging_db_tablesNames ['in_msgs]
  
  as I created a configuration file for all parameters that can change. The value of the table in the audit using a print command is correctly, but when put in the query above to run the insert statement gives an error. The following is the summary of comprehensive performance where you can see the table name as
  
  $ python gsapscnr.py
  Vote for the data files in/home/mh/inbox /...
  
  GSAP_MSG_IN
  Traceback (most recent call changed):
  File "gsapscnr.py", line 147, in it?
  poll_for_data()
  File "gsapscnr.py", line 86, in poll_for_data
  Sorter = load_details_first)
  File "gsapscnr.py", line 42, survey
  curs. Execute ("INSERT INTO '%s' VALUES ((SELECT MAX (REC_ID) + 1 OF GSAP_MSG_IN), (SELECT MAX (gsap_msg_id) + 1 OF GSAP_MSG_IN), 'SHELLSAP', sysdate, '%s', EMPTY_BLOB(), 1, SYSDATE, EMPTY_BLOB (), SYSDATE)" %(table_name,file_extension)) ")
  cx_Oracle.DatabaseError: ORA-00903: invalid table name
  
  Can anyone help with this problem please. I'm passing the value of the table in a bad way. Also if anyone can suggest a good tutorial for paythong programming using cx_Oracle.
  
  Concerning

  Print the SQL string that you establish, cut and paste it this output in SQL * more and see if it runs. This may show you that you should remove the single quotes around the name of the table %s in the Python file.

• How can I update this table with values from another table?

  Hello
  
  I have a table 'governed '. I want to replace the values in the column "regies.agent" by the value of the column "regies_personnes.id."
  As you can see the tables have a column of common values. IE regies.agent = regies_personnes.nom
  
  Table 'governed ':
  Insert into 'authorities' (AGENT) values ('Humberdot Alain");
  Insert into 'authorities' (AGENT) values ("Danard Patrick");
  
  Table 'regies_personnes ':
  Insert into REGIES_PERSONNES (NAME, ID) values ("Humberdot Alain", 1);
  Insert into REGIES_PERSONNES (NAME, ID) values ("Danard Patrick", 2);
  
  Before having it
  SQL > select agent of authorities;
  Humberdot Alain
  Patrick Danard
  
  After the update, the result should be
  SQL > select agent of authorities;
  1
  2
  
  Thank you for your kind reply.

  You can

  update regies r set agent = (select id from regies_persones p where r.agent = p.nom)
    where exists (select id from regies_persones p where r.agent = p.nom)
  

• Find the average value of a buffer

  Hello

  In my VI Panel, I have a digital control, a button and a digital display.

  When the user, enter a number in numerical order and press the button, the digital display should show the average value of all the past 5 values entered in the digital control, for example:

  1st entry: 10-online average = 10 (as sum = 10)

  2nd type: 0-online average = 5 (as sum = 10 + 0 = 10)

  3rd enter: 5-online average = 5 (you get the idea...)

  4 enter: 1-average online = 4

  5 enter: 14-online medium = 6

  6 enter: 2-online average = 4.4 (sum = 0 + 5 + 1 + 14 + 2 = 22, because the 1st value is thrown)

  How to write this VI?

  Thank you!!

  You can also use arrays to hold the data in a registry change and find the average value of the last five items.

  

  Good luck