find previous record

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• I can't find the recorded files recently in my document folder

  I can't find the recorded files recently in my document folder

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• Time machine can not read my previous record

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• I find these records long name with 20 or more charactors and inside them is nothing else than "mrt.exe" file. I find them in random places.

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• A document I had previously recorded on my flash drive. All of a sudden the paragraph symbol appeared at the beginning of each line in the document and in documents on flash drive

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• Error on push notifications "cannot find any record of application settings.

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• Find no records in an Excel sheet

  Hi all

  I am importing data from an excel file into oracle database. I wanted to know the number of records in an excel file and no columns using oracle webutil (Client_ole2). I received a web code that works very well, adding a NEM statement at the end of the file each time. Maybe it's not practical always, cannot ask user each time to add a statement of NEM, which in turn result in program to run infinitely.

  This is the code that is running

  DECLARE

  application Client_OLE2. Obj_Type;

  Client_OLE2 workbooks. Obj_Type;

  workbook Client_OLE2. Obj_Type;

  Client_OLE2 spreadsheets. Obj_Type;

  worksheet Client_OLE2. Obj_Type;

  worksheet2 Client_OLE2. Obj_Type;

  cell Client_OLE2. OBJ_TYPE;

  Client_OLE2 args. OBJ_TYPE;

  cell_value varchar2 (100);

  num_wrkshts NUMBER;

  wksht_name VARCHAR2 (250);

  EOD Boolean: = false;

  j integer: = 3;

  v_fName VARCHAR2 (250);

  worksheet_count number: = 0;

  BEGIN

  -Get the name of the file to open

  -v_fName: = "D:\MyDevelopment\Forms\Samples\WebUtil\Read_Excel\planets3.xls";

  v_fName: = WebUtil_File.File_Open_Dialog)

  directory_name = > "C:\". »

  -, file_name = > Get_Form_Property (:System.Current_form, Form_Name) |'. XLS

  , File_Filter = > null

  , Title = > 'Select customer filename to open.'

  );

  IF (v_fName IS NOT NULL) THEN

  -The following sets a communication with the excel worksheet

  -- --------------------------------------------------------------

  -Open the OLE application

  application: = Client_OLE2.create_obj ('Excel.Application');

  -Keep the hidden application

  Client_OLE2.set_property (application, 'Visible ','false ');

  workbooks: = Client_OLE2. Get_Obj_Property (application "Filing cabinets");

  args: = Client_OLE2. CREATE_ARGLIST;

  -Open the selected file

  -- ----------------------

  Client_OLE2.add_arg (args, v_fName);

  workbook: = Client_OLE2. GET_OBJ_PROPERTY (Workbooks, 'Open', args);

  Client_OLE2.destroy_arglist (args);

  worksheets: = Client_OLE2. GET_OBJ_PROPERTY (workbook, 'Worksheets');

  -Get the number of spreadsheets

  -- ------------------------

  num_wrkshts: = Client_OLE2. GET_NUM_PROPERTY (worksheets, 'Count');

  worksheet: = Client_OLE2. GET_OBJ_PROPERTY (application, 'activesheet');

  -Go to the first record

  go_block ('EXCEL_EXPORT_TABLE');

  premier_enregistrement;

  loop

  If: system.record_status <>'NEW' then

  create_record;

  end if;

  When the exit NEM;

  for 1.15 k loop - 15 frames / record - hard-code the length of the column

  args: = Client_OLE2.create_arglist;

  Client_OLE2.add_arg (args, j);

  Client_OLE2.add_arg (args, k);

  cell: = Client_OLE2.get_obj_property (spreadsheet calculation, 'Cells', args);

  Client_OLE2.destroy_arglist (args);

  If Client_OLE2.get_char_property (cell, 'Value') = 'null' then

  cell_value: = ";

  on the other

  cell_value: = nvl (Client_OLE2.get_char_property (cell, 'Value'), 0);

  end if;

  If upper (cell_value) = 'NEM' then - the loop runs until "NEM" are judged.

  Nem: = true;

  Message ('end of data');

  "exit";

  end if;

  Copy (cell_value, name_in ('system.cursor_item'));

  next_item;

  
  

  end loop; -for

  j: = j + 1;

  end loop;-main loop

  premier_enregistrement;

  -Release the handles object Client_OLE2

  IF (cell IS NOT NULL) THEN

  Client_OLE2.release_obj (cell);

  END IF;

  IF (spreadsheet IS NOT NULL) THEN

  Client_OLE2.release_obj (Worksheet);

  END IF;

  IF (spreadsheets IS NOT NULL) THEN

  Client_OLE2.release_obj (Worksheets);

  END IF;

  IF (worksheet2 IS NOT NULL) THEN

  Client_OLE2.release_obj (worksheet2);

  END IF;

  IF (workbook IS NOT NULL) THEN

  Client_OLE2.release_obj (Workbook);

  END IF;

  IF (workbooks IS NOT NULL) THEN

  Client_OLE2.release_obj (Workbooks);

  END IF;

  Client_OLE2. Invoke (application, 'Quit');

  Client_OLE2.release_obj (application);

  ON THE OTHER

  Message ("no file selected.'");

  message(' ');

  RAISE Form_Trigger_Failure;

  END IF;

  END;

  Please think it has no integrated to find no records and columns in excel file using oracle forms.

  Thank you and best regards,

  JaKes

  This change according to excel data file.

  for example, we also use this logic. because the first column in excel file still does not empty. It should be full.

  If any column of a raw material can be empty, one with just my solution can be

  v_all_column_str: = col_A_Value | col_B_Value | col_C_Value | col_D_Value |... col_n_value;

  if v_all_column_str is null, then--> you can tell, all of the columns of this vintage in excellent file is empty

• How do I report the results of the previous record to the next record in a query

  Hello

  For example if I have data of the table as.

  AC_CODE DATE CREDIT DEBIT

  ----------------------------------

  1001 15 APRIL 15 10

  1001 APRIL 25, 15 2

  1005 5 APRIL 15 100

  1005 8 APRIL 15 25

  ----------------------------------

  And I want to train as below, where, BALANCE = (previous record BALANCE) + CREDIT - DEBIT

  (assuming that NVL (, 0) for all columns)

  (assuming the BALANCE reset after change of AC_CODE)

  DATE AC_CODE CREDIT DEBIT BALANCE

  --------------------------------------------

  1001 15 APRIL 15 10 10

  1001 APRIL 25 15 2 8

  1005 5 APRIL 15 100 - 100

  1005 8 APRIL 15 25 - 75

  --------------------------------------------

  (AC_CODE ORDER, DATE)

  Of course, it can be reached using query of database function.  My question is, is it possible by using a query without involving all functions.

  Thank you

  -Anand

  Model clause could help you meet this goal...

  Note: There is a separate area for SQL, PL/SQL issues here in OTN and don't forget to provide insertion, create scripts for your sample data for a quick response

  with t as(select 1001 AC_CODE,to_date('15-APR-2015','DD-MON-yyyy') dt,10 credit,null debit from dual union all
            select 1001,to_date('25-APR-2015','DD-MON-yyyy'),null,2 from dual union all
            select 1005,to_date('05-APR-2015','DD-MON-yyyy'),null,100 from dual union all
            select 1005,to_date('08-APR-2015','DD-MON-yyyy'),25,null from dual
          )
      select ac_code
            ,dt
            ,credit
            ,debit
            ,balance
          from t
          model
              partition by (ac_code)
              dimension by (row_number() over(partition by ac_code order by dt) rn)
              measures (dt,credit,debit,0 as balance)
              rules
                  (
                      balance[any] = nvl(balance[cv()-1],0) + nvl(credit[cv()],0) - nvl(debit[cv()],0)
                  )
          ;
  

• How I've hidden the elements after the query when moving back to the previous record

  Hello world

  I create a form with the developer 6i and I use set_item_property(item_name,visivile,...), in post_change, in when_list_change relaxation too

  to hidden and activate certain elements.

  When I enter the data, everything works fine, when I do a request for enforcement to the data set and move to the next record every thing works fine, but

  When I want to go back to the previous record, the two triggers does not,

  could someone tell me where to put this code, so it can walk perfecty when I move to the next record or previous record

  best regards;

  You can use one - news - when? -Instance triggers (where? = point, Record, block, etc.).

  Craig...

• Have down loaded 2015 PS I find previous versions of PS remain on my computer it is possible to delete older versions?

  Having downloaded 2015 PS I find previous versions remain on the computer can they be deleted?

  Yes, feel free to remove them.

  Mylenium

• Getting value of an element in the previous record in a table

  Good afternoon

  I'll try to explain my problem:

  I have a block table points X, Y and Z (all are elements of database)...

  On the first record, the user is required to set the values for all the elements...

  For the rest of the records, the value of X must be the value of Z in the previous record.

  How I could do and what is the best way to do it?

  Thanks in advance.

  Daniel Guzzo

  OK, problem solved by myself:

  IF: System. CURSOR_RECORD! = 1 and: global .rec_changed = 0 THEN

  : global .rec_changed: = 1;

  PREVIOUS_RECORD;

  : global .fec_hasta: = to_char(:cret_prod_pol_renovacionesb.crpn_fe_hasta,'DD-MM-YYYY');

  NEXT_RECORD;

  : global .rec_changed: = 0;

  IF: global.fec_hasta is null THEN previous_record; end if;

  : cret_prod_pol_renovacionesb.crpn_fe_efectiva: = to_date(:global.fec_hasta,'DD-MM-YYYY');

  -MESSAGE(:global.fec_hasta);

  END IF;

  If anyone has a better solution, it will be welcome.

  Thank you

• calculate the balance depends on the previous record result

  Hello
  I have a requirement like calculating the balance depends on the previous record result. but I'm unable to accomplish by using select statement.
  

  Sample data:
  
  WITH T AS (SELECT 10 AMOUNT, 0.2 PERCENT  FROM DUAL
             UNION ALL 
             SELECT 11 AMOUNT, 0.3 PERCENT  FROM DUAL
             UNION ALL 
             SELECT 12 AMOUNT, 0.3 PERCENT  FROM DUAL
             UNION ALL 
             SELECT 13 AMOUNT, 0.3 PERCENT  FROM DUAL
             UNION ALL 
             SELECT 14 AMOUNT, 0.3 PERCENT  FROM DUAL
            )

  process:          
  10(AMOUNT)  *  0.2(PERCENT)  = 2
  11 - 2(Result of previous calculation) = 9
  12 - 9(Result of previous calculation) = 3
  13 -3(Result of previous calculation) = 10
  14 - 10(Result of previous calculation) = 4;

  required output.
   AMOUNT                 RESULT  
    10                          2
    11                          9
    12                          3
    13                         10
    14                          4

  Please, help me build the select statement.

  There is no order in the lines of the relational table. Only ORDER BY guarantees the order. So, even if the AMOUNT is increasing in your sample, I guess in life real amounts are in no particular order. If Yes, you need another column indicating the order of the lines:

  WITH T AS (
             SELECT 1 ID, 10 AMOUNT, 0.2 PERCENT  FROM DUAL UNION ALL
             SELECT 2 ID, 11 AMOUNT, 0.3 PERCENT  FROM DUAL UNION ALL
             SELECT 3 ID, 12 AMOUNT, 0.3 PERCENT  FROM DUAL UNION ALL
             SELECT 4 ID, 13 AMOUNT, 0.3 PERCENT  FROM DUAL UNION ALL
             SELECT 5 ID, 14 AMOUNT, 0.3 PERCENT  FROM DUAL
            )
  SELECT  AMOUNT,
          RESULT
    FROM  T
    MODEL
      DIMENSION BY(ID)
      MEASURES(AMOUNT,AMOUNT RESULT,PERCENT)
      RULES(
            RESULT[1]                  = RESULT[1] * PERCENT[1],
            RESULT[ID > 1] ORDER BY ID = RESULT[CV()] - RESULT[CV() - 1]
           )
    ORDER BY ID
  /
  
      AMOUNT     RESULT
  ---------- ----------
          10          2
          11          9
          12          3
          13         10
          14          4
  
  SQL> 
  

  If the AMOUNT is still growing:

  WITH T AS (
             SELECT 10 AMOUNT, 0.2 PERCENT  FROM DUAL UNION ALL
             SELECT 11 AMOUNT, 0.3 PERCENT  FROM DUAL UNION ALL
             SELECT 12 AMOUNT, 0.3 PERCENT  FROM DUAL UNION ALL
             SELECT 13 AMOUNT, 0.3 PERCENT  FROM DUAL UNION ALL
             SELECT 14 AMOUNT, 0.3 PERCENT  FROM DUAL
            )
  SELECT  AMOUNT,
          RESULT
    FROM  T
    MODEL
      DIMENSION BY(ROW_NUMBER() OVER(ORDER BY AMOUNT) ID)
      MEASURES(AMOUNT,AMOUNT RESULT,PERCENT)
      RULES(
            RESULT[1]                  = RESULT[1] * PERCENT[1],
            RESULT[ID > 1] ORDER BY ID = RESULT[CV()] - RESULT[CV() - 1]
           )
    ORDER BY ID
  /
  
      AMOUNT     RESULT
  ---------- ----------
          10          2
          11          9
          12          3
          13         10
          14          4
  
  SQL> 
  

  SY.

• Updated column by using a previous record value

  I have data in a table as follows:
  
  sequence ID
  1 100
  2 101
  102 3
  4 103
  4 104
  5 105
  6 106
  
  
  I need increment the value of the sequence of + 10 sequence of the previous record.
  Even if the first value of record sequence will start at only 1.
  i.e.
  sequence ID
  1 100
  10 of 101
  20 102
  30 of 103
  40 104
  50 of 105
  60 106
  
  Is it possible in a single query.

  Hello
  DDL and DML:

  CREATE TABLE test(col1 NUMBER, col2 NUMBER) 
  
  INSERT INTO test SELECT 100 col1, 1 col2 FROM DUAL UNION
  SELECT 101, 2 FROM DUAL UNION
  SELECT 102, 3 FROM DUAL UNION
  SELECT 103, 4 FROM DUAL UNION
  SELECT 104, 5 FROM DUAL UNION
  SELECT 105, 6 FROM DUAL UNION
  SELECT 106, 7 FROM DUAL
  

  The query:

  UPDATE test a SET col2=NVL((SELECT col2*10 FROM test b WHERE a.col2-1=b.col2),1)
  7 Rows Updated.
  
  SELECT * FROM test
  COL1 COL2
  100 1
  101 10
  102 20
  103 30
  104 40
  105 50
  106 60 
  

  Kind regards
  Lakshmi.

• MySQL display-only previous Record

  Hello, everyone:

  How is it possible to display the second record in a MySQL table rather than the current.

  Let me show you an example.

  
  

  MySQL

  UserAccount (table 1)

  user name, first name last name

  122 of John Smith

  Ferrari Enzo 145

  547 Jane Doe

  895 David Samuel

  account (table 2)

  First_name last_name logindate UserID
  

  122 John Smith 2011-01-28

  145 Enzo Ferrari 2011-01-12

  547 Unetelle 2011 - 01 - 27

  145 Enzo Ferrari 2011-01-10

  547 DOE 2010-12-22 (A-1 * note only for external reference)
  

  547 Unetelle 2010 - 12 - 20

  Now when I do a MySQL query to display on my PHP page I only want to show the Jane Doe the previous record in bold red.

  MySQL Query (* Note don't know how the code to display the previous record not current results only)
  

  SELECT useraccount.userid, useraccount.first_name, useraccount.last_name, account.logindate
  

  Useraccount ACCOUNT

  WHERE useraccount.userid = account.userid

  PHP page

  Hello Jane Doe, your previous login date was December 22, 2010 (a-1 * note only for external reference)

  Thank you for all your help.

  AdonaiEchad wrote:

  How is it possible to display the second record in a MySQL table rather than the current.

  Use the LIMIT clause with two numbers. The first specifies how many files to jump, the second how much you want to.

  SELECT useraccount.userid, useraccount.first_name, useraccount.last_name, account.logindate
  
  FROM useraccount account
  WHERE useraccount.userid = account.userid
  ORDER BY account.logindate DESC
  LIMIT 1,1
  

• Records of paint according to the previous record

  Hi all
  
  I need a bitch the foreground color of a record by a field in the previous record, I mean, if the current record contains the same data as the previous it should be blue, but it is different to be red.
  
  can anyone tell me how and in which trigger.
  
  THX!

  In addition Francis... If you block based on SQL query you can use the functions of LAG and LEAD in your SQL to get the previous values in the same line.