Find "the third Friday of the month.

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• where can I find the monthly subscription?

  where can I find the monthly subscription?

  Hey julietteh55830290,

  Before include files, make sure that they have been converted to PDF format.

  See this KB doc. Document Cloud Help | Adobe PDF package using.

  Kind regards

  Nicos

• To find the months and days between 2 dates

  Hello

  I want to find the months and days between 2 dates.

  For example.

  1 - Date: August 25, 2013

  2 - Date: October 23, 2013

  If we consider each month 30 days, it should give

  August 25, 2013 to August 30, 2013 = 6 days

  01-Sep-2013-30-Sep-2013 = 1 month

  October 23, 2013 to October 30, 2013 = 8 days

  Total = 1 month and 14 days.

  Kindly help as soon as possible.

  Thanks and greetings

  Suresh

  Assuming that d2 > d1,.

  where d)

  Select sysdate d1, sysdate + 56 double d2

  Union all select to_date (March 1, 2013 ',' dd-mon-yyyy "") d1, to_date (March 31, 2013 ',' dd-mon-yyyy ') d2 double

  Union all select to_date (5 February 2013 ',' dd-mon-yyyy ') d1, to_date (March 31, 2013 ',' dd-mon-yyyy "") double d2

  Union all select to_date (February 25, 2013 ',' dd-mon-yyyy "") d1, to_date (March 23, 2013 ',' dd-mon-yyyy ') d2 double

  Union all select to_date (February 25, 2013 ',' dd-mon-yyyy ') d1, to_date (March 31, 2013 ',' dd-mon-yyyy "") double d2

  Union all select to_date (August 2, 2013 ',' dd-mon-yyyy "") d1, to_date (29 October 2013 ',' dd-mon-yyyy ') d2 double

  Union all select to_date (February 1, 2013 ',' dd-mon-yyyy "") d1, to_date (May 31, 2013 ',' dd-mon-yyyy ') d2 double

  Union all select to_date (25 August 2013 ',' dd-mon-yyyy "") d1, to_date ('03-Sep-2013', 'Mon-dd-yyyy') d2 double

  Union all select to_date (July 30, 2013 ',' dd-mon-yyyy "") d1, to_date (August 31, 2013 ',' dd-mon-yyyy ') d2 double

  Union all select to_date (July 31, 2013 ',' dd-mon-yyyy ') d1, to_date (August 30, 2013 ',' dd-mon-yyyy "") double d2

  Union all select to_date (July 31, 2013 ',' dd-mon-yyyy ') d1, to_date (3 August 2013 ',' dd-mon-yyyy "") double d2

  Union all select to_date (3 July 2013 ',' dd-mon-yyyy "") d1, to_date (August 31, 2013 ',' dd-mon-yyyy ') d2 double

  Union all select to_date ('31-08-2013', ' dd-mm-yyyy'), to_date('05-10-2013','dd-mm-yyyy') of the double

  Union all select to_date ('05-02-2013', ' dd-mm-yyyy'), to_date('31-03-2013','dd-mm-yyyy') of the double

  Union all select to_date ('05-02-2013', ' dd-mm-yyyy'), to_date('05-03-2013','dd-mm-yyyy') of the double

  Union all select to_date ('05-02-2013', ' dd-mm-yyyy'), to_date('05-02-2013','dd-mm-yyyy') of the double

  )

  Select d1, d2,

  1 + 30 * trunc (months_between (d2, d1)) + LESS (extract (day of d2), 30)-LESS (excerpt (d1 day), 30)

  + CASE when extracted (d2 day)< extract(day="" from="" d1)="" then="" 30="" else="" 0="" end ="">

  d

  D1 D2 DAYSBETWEEN

  ----------- ----------- -----------

  October 10, 2013 5 December 2013 56

  March 1, 2013 30 March 31, 2013

  5 February 2013 March 31, 2013 56

  February 25, 2013 March 23, 2013 29

  February 25, 2013 March 31, 2013 36

  August 2, 2013 29 October 2013 88

  February 1, 2013 may 31, 2013 120

  August 25, 2013 03 - Sep-2013 9

  July 30, 2013 31 August 31, 2013

  July 31, 2013 August 30, 2013 31

  July 31, 2013 3 August 2013 4

  July 3, 2013 August 31, 2013 58

  31 August 2013 5 October 2013 36

  5 February 2013 March 31, 2013 56

  5 February 2013 March 5, 2013 31

  February 5, 2013 February 5, 2013 1

  In my view, which corresponds to your rules.

• OBIEE 11 g: how to find the 2nd Friday of the month

  Hello

  How to find the 2nd Friday of the month using the current date in obiee 11g.

  Thanks in advance.

  Kind regards

  MIT.

  Hey MIT,

  You can try with something like this:

  TIMESTAMPADD (SQL_TSI_DAY, TIMESTAMPADD (7 + 6-DAYOFWEEK (TIMESTAMPADD (SQL_TSI_DAY, 1-DAYOFMONTH (CURRENT_DATE), CURRENT_DATE))), (SQL_TSI_DAY, 1-DAYOFMONTH (CURRENT_DATE), CURRENT_DATE))

  It can still be improved to probably avoid transformations 1-2, but at least he does.

  You will need to check what return DAYOFWEEK in your environment for Friday (in mine Friday = 6) as if she does not return to Friday 6, you will need to adjust the formula.

  The idea is to find what day is the first day of the month, since then visit the first Friday (or just stay there if the first day is a Friday). This is done by the DAYOFWEEK 6 (first day of the month).

  And now, you just add more 7 days, so that's why there is a 7 + 6 - DAYOFWEEK (first day of the month) to make it easier to read and understand (instead of 13-...).

• To find the third Saturday of a month

  Hi all
  
  Y at - it a simple way to find the third Saturday of each month
  other than two queries below.
  
  < CODE >
  
  -The first code (No nested query)
  SELECT MAX (DECODE (LENGTH (TO_CHAR (LEVEL)), 1))
  , TO_DATE (TO_CHAR (SYSDATE, 'YYYYMM') |) '0' || TO_CHAR (LEVEL), 'YYYYMMDD')
  , TO_DATE (TO_CHAR (SYSDATE, 'YYYYMM') |) TO_CHAR (LEVEL), 'YYYYMMDD'))) THIRD_SAT
  OF THE DOUBLE
  WHERE DECODE (LENGTH (TO_CHAR (LEVEL)), 1).
  , TO_CHAR (TO_DATE (TO_CHAR (SYSDATE, 'YYYYMM') |)) '0' || TO_CHAR (LEVEL), 'YYYYMMDD'), "DY")
  , TO_CHAR (TO_DATE (TO_CHAR (SYSDATE, 'YYYYMM') |)) TO_CHAR (LEVEL), 'YYYYMMDD'), "DY")
  ) = 'SAT '.
  CONNECT BY LEVEL < 22
  
  
  --deuxieme code (a nested query)
  MAX SELECT THIRD_SAT (ALL_DATES)
  OF (MAX SELECTION (DECODE (LENGTH (TO_CHAR (LEVEL)), 1)))
  , TO_DATE (TO_CHAR (SYSDATE, 'YYYYMM') |) '0' || TO_CHAR (LEVEL), 'YYYYMMDD')
  , TO_DATE (TO_CHAR (SYSDATE, 'YYYYMM') |) TO_CHAR (LEVEL), 'YYYYMMDD'))) ALL_DATES
  OF THE DOUBLE
  CONNECT BY LEVEL < 22
  )
  WHERE TO_CHAR (ALL_DATES, 'DY') = 'SAT '.
  < code >
  
  
  Thank you and best regards,
  CDPRASAD

  Hello

  Tubby wrote:

  ME_XE?select next_day(trunc(sysdate, 'MM'), 'SATURDAY') + 14 from dual;
  
  NEXT_DAY(TRUNC(SYSDA
  --------------------
  21-AUG-2010 00 00:00
  
  1 row selected.
  
  Elapsed: 00:00:00.00
  

  Be careful! If the month happens to start Saturday, which returns the 4th Saturday, not the 3rd:

  select  next_day ( trunc ( DATE '2010-05-15'
                  , 'MM'
                  )
            , 'SATURDAY'
            ) + 14
  from      dual;
  
  NEXT_DAY(
  ---------
  22-MAY-10
  

  That's because NEXT_DAY always returns a DATE after (not the same as) its 1st argument.
  Do this instead:

  select  next_day ( trunc ( DATE '2010-05-15'
                  , 'MM'
                  ) + 13
            , 'SATURDAY'
            )           AS third_sat
  from      dual;
  
  THIRD_SAT
  ---------
  15-MAY-10
  

  or, if you need something that is independent of the NLS:

  select  next_day ( trunc ( SYSDATE
                  , 'MM'
                  ) + 13
            , TO_CHAR ( DATE '2010-07-31'     -- You can use any Saturday here
                   , 'Day'
                   )
            )           AS third_sat
  from      dual;
  
  THIRD_SAT
  ---------
  21-AUG-10
  

• find the 3rd Friday of the month at a given date

  How can 3rd Friday of the month at a given date? I can always spend the first day of the month as input
  
  for example, the effective date is 1 January 09. need to get the 3rd Saturday 16 January 09 (Jan has 5 Friday 02, 09, 16,23,30)
  
  entry date: 1 February 09, needed 20 February 09
  
  Published by: user520824 on April 1st, 2009 12:30

  How about you...

  select trunc(sysdate,'mm') + (6 - to_char(trunc(sysdate,'mm'),'d')) + 14 from dual;
  
  TRUNC(SYS
  ---------
  17-APR-09
  
  select trunc(to_date('01-JAN-09'),'mm') + (6 - to_char(trunc(to_date('01-JAN-09'),'mm'),'d')) + 14 from dual;
  
  TRUNC(TO_
  ---------
  16-JAN-09
  
  select trunc(to_date('01-FEB-09'),'mm') + (6 - to_char(trunc(to_date('01-FEB-09'),'mm'),'d')) + 14 from dual;
  
  TRUNC(TO_
  ---------
  20-FEB-09
  
  select trunc(to_date('01-MAR-09'),'mm') + (6 - to_char(trunc(to_date('01-MAR-09'),'mm'),'d')) + 14 from dual;
  
  TRUNC(TO_
  ---------
  20-MAR-09
  

• How to view the monthly/annual statistics in terms of time past/calories burned, broken down by each individual activity such as run elliptical/outside etc. Y at - it a third party application that can help me to collect and display these data?

  How to view the monthly/annual statistics in terms of time past/calories burned, broken down by each individual activity such as run elliptical/outside etc. Y at - it a third party application that can help me to collect and display these data?

  Hello

  It is not currently possible to review the data the application integrated in activity or training on this basis. If you want Apple to consider adding this feature, you can suggest here:

  https://www.Apple.com/feedback/watch.html

  However, health and fitness data from other sources, iPhone, and Apple Watch are registered and grouped within the health on iPhone app. These data can be exported, which you may find useful to track the cumulative progress and/or analyze your activity more in detail.

  IPhone app activity also has a button for sharing (top right of the screen) that allows to share data - including social media, Messages, Mail, Notes, and a printer.

  Include third-party applications that can be useful, for example:

  Access to QS

  -"Access your HealthKit data in a table so you can Explorer using numbers, Excel, R, or any other tool compatible CSV."

  - https://itunes.apple.com/gb/app/qs-access/id920297614?mt=8

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  Data can also be exported directly from the application of the health (Health Data > All - Share at the top button on the right).

  Check the descriptions and support resources for third party applications for supported details of import and data analysis features.

  More information:

  Use the activity on your Apple Watch - Apple Support

  Use of the workout on your Apple Watch - Apple Support

  http://www.Apple.com/watch/health-and-fitness/

• Find the first day of the third quarter of next year

  Hello

  I'm writing a sql to find "the first day of the third quarter of the year (from the current year) next»

  I am able to get the first and the last day of the current quarter:

  Select trunc (sysdate, 'Q'), trunc (add_months (sysdate, + 3), 'Q')-1 double

  But, how to find the first day of the third quarter of the year next (from the current year) based on any date entry (i.e. sysdate)

  for example if my entry date = 12/01/2001 should be released 07/01/2015

  If my entry date = 07/04/2005 should be released 07/01/2015

  If my entry date = 20/02/2013 should be released 07/01/2015

  ... etc.

  Thanks in advance

  Hello

  The 1st day of the 3rd quarter of next year is:

  ADD_MONTHS (TRUNC (SYSDATE, 'YEAR')

  18 = 12 + 6

  )

  TRUNC (SYSDATE, 'YEAR') is the 1st day of the 1st quarter of this year

  The first day of the new year is 12 months after that, and the first day of quarter 3 is another 6 months after that.

  user634169 wrote:

  ... But, how to find the first day of the third quarter of the year next (from the current year) based on any date entry (i.e. sysdate)

  for example if my entry date = 12/01/2001 should be released 07/01/2015

  If my entry date = 07/04/2005 should be released 07/01/2015

  If my entry date = 20/02/2013 should be released 07/01/2015

  ... etc.

  Thanks in advance

  You did some errors above?

  If the effective date in 2001, why is the output in 2015, not 2002?

  If the output is based only on the date of the day (currently in 2014), why even mention a start date?

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  Hello

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• Find the 2nd Sunday of each month in a report

  Hello

  I have the data of EMP_Name and Join_Date. I have to build a dashboard report where

  1. In the dashboard, there is a command prompt. If I select a year and a month then, the report is expected to show that the data of the respective month.
  2. This report will show the employees who joined the company only after the 2nd Sunday of each month until the end of the month.

  Inputs/suggestions, how to build it?

  Thanks in advance.

  You have a question, Yes... a SQL query... OBIEE do not mean SQL but LSQL, your query will be not really usable like this...

  You're right, it seems that when the first day of the month is a Saturday he jump 1 week...

  The correct formula for the 3rd Friday is:

  TIMESTAMPADD (SQL_TSI_DAY, (14 + 6-CASE WHEN DAYOFWEEK (TIMESTAMPADD (SQL_TSI_DAY, 1-DAYOFMONTH (CURRENT_DATE), CURRENT_DATE)) = 7 THEN 0 END ELSE DAYOFWEEK (TIMESTAMPADD (SQL_TSI_DAY, 1-DAYOFMONTH (CURRENT_DATE), CURRENT_DATE))), TIMESTAMPADD (SQL_TSI_DAY, 1-DAYOFMONTH (CURRENT_DATE), CURRENT_DATE))

  If instead of CURRENT_DATE you want to use your own column date just to replace in the formula and it works.

• How to find the first day of the month following two years one year from now?

  Hello

  I need to find the first day of the month following two years ago, based on the current date.

  For example: If today is the 31/08/2015 so I need to find the date range between 31/08/2015 and on 09/01/2013. How can I write an SQL which allows to automate this calculation instead of hard-coding the values. Please do help me out with this so that I can build the SQL that can produce the desired result.

  Thank you

  Dhilip

  find the start of the month - 2 years in advance, early - 2 years + 1 months in advance and go back 1

  Select trunc (add_months(sysdate,24), 'MM'), trunc (add_months(sysdate,25), 'MM') - 1 double;

• How to find the first Sunday and the second Saturday of each month

  Hi all

  How to find the first Sunday and the second Saturday of each month

  Thank you

  Oracle Database 11 g Enterprise Edition Release 11.1.0.7.0 - 64 bit Production

  994122 wrote:

  Hello

  I need to pass the months parameter how to do this? like Jan, Feb etc... (one of those)

  Do you have a procedure?

  Should you output only for the months you passed in the parameter?

  The easiest way is to set the parameter as date. When you go such as p_date as DATE ' 2014-10-01', then you can

  PROCEDURE two_dates)

  p_date IN DATE

  p_first_sunday DATE

  p_second_saturday DATE

  )

  IS

  BEGIN

  p_first_sunday: = NEXT_DAY (TRUNC (p_date, 'MM') - 1, TO_CHAR (DATE ' 2014-10-12', 'DAY'));

  p_second_saturday: = NEXT_DAY (TRUNC (p_date, 'MM') - 1, TO_CHAR (DATE ' 2014-10-11', 'DAY')) + 7;

  END two_dates;

  Or you describe what you need.

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