First day of a month
HelloCan someone help me to write a code when a random day is given a month, that the day should change automatically
in the first day of a month.
Can you give an example?
Do you mean the last day of the month for a random date?
Then you can simply use builltin Oracle LAST_DAY function:
SQL> select sysdate from dual
2 union
3 select last_day(sysdate) from dual;
SYSDATE
-------------------
03-05-2012 18:17:04
31-05-2012 18:17:04
Tags: Database
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How to get the first day of the month in the sql query.
SQL> select trunc(sysdate,'mm') first_day from dual; FIRST_DAY --------- 01-AUG-15 SQL> select trunc(sysdate,'month') first_day from dual; FIRST_DAY --------- 01-AUG-15 SQL> select trunc(sysdate,'mon') first_day from dual; FIRST_DAY --------- 01-AUG-15 SQL>
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Hello
Using oracle 11.2.0.3
A table with a column date
sample opening time data 04/08/2014-08:30 one single column, another column start date 04/02/2014
Want to have a sql that will go through an opening time table set on the first day of the month as well as existing time
for example expect times to be
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Code below will give the first day of the month
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{code}
Select trunc(start_time,'MM))
of customer_hours ch
{code}
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resp.
Select
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Published by: user12957777 on May 23, 2012 21:12How to find the first day of the month if the month format is like TO_CHAR(SYSDATE,'YYYYMM') Sanjay
There is no 'day' in this date format.
What you trying to do? What do you expect the result to look like?
Are you wanting to set a date for the first day of the month and year of your example?
SELECT TO_DATE(TO_CHAR(SYSDATE,'YYYYMM') || '01', 'YYYYMMDD') FROM DUAL;
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DB version: 10.2.0.4
Due to the nature of our the first working day of each month (like today 1 MS), the DB will be very busy.
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But the first day of every month (like today 1 MS), if it's a day of the week (Monday to Friday) we do not want this proc running between 08:00 and for dinner from 18:30.
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How can I implement this?
Edited by: user872043, Sep 1 2010 08:48Here is an example of using DBMS_SCHEDULER which should meet your needs:
Create schedules
BEGIN DBMS_SCHEDULER.CREATE_SCHEDULE ( schedule_name => 'every_5_schedule' , repeat_interval => 'FREQ=MINUTELY; BYMONTHDAY=2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31; INTERVAL=5; BYSECOND=0' , comments => 'Schedule to run every 5 minutes' ); DBMS_SCHEDULER.CREATE_SCHEDULE ( schedule_name => 'busy_hourly_schedule' , repeat_interval => 'FREQ=MINUTELY; BYMONTHDAY=1; BYHOUR=0,1,2,3,4,5,6,7,19,20,21,22,23; INTERVAL=5;' , comments => 'Schedule to run every 5 minutes except certain hours on the first of the month' ); DBMS_SCHEDULER.CREATE_SCHEDULE ( schedule_name => 'busy_6pm_schedule' , repeat_interval => 'FREQ=MINUTELY; BYMONTHDAY=1; BYHOUR=18; BYMINUTE=30,35,40,45,50,55' , comments => 'Schedule to run every 5 minutes from 6:30 - 7' ); END; /
There are three lists.
every_5_schedule - runs every 5 minutes for all the days that are not on the first day of the month
busy_hourly_schedule - runs every 5 minutes for the acceptable hours on the first day of the month
busy_6pm_schedule - retrieves the half hour from 6:30 - 7 on the first day of the month.Then, create your business:
Job creation
BEGIN DBMS_SCHEDULER.CREATE_JOB ( job_name => 'YOUR JOB' , job_type => 'PLSQL_BLOCK' , job_action =>'BEGIN YOURPROC; END;' , repeat_interval => 'EVERY_5_SCHEDULE, BUSY_HOURLY_SCHEDULE, BUSY_6PM_SCHEDULE' , enabled => TRUE , comments => 'Some comments' ); END; /
HTH!
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create or replace procedure minmax is
cursor minmax_cur is
Select min (hiredate), max in emp (hiredate);
number of v_minmonths;
number of v_maxmonths;
number of v_minyears;
number of v_maxyears;
x date of publication;
date of y;
Start
Open minmax_cur;
extraction minmax_cur
x, y;
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v_minyears: = extraction (year x);
While (x, y) loop
because me in 1... v_minmonths loop
If (v_minmonths < 12) then
v_minmonths: = v_minmonths + 1;
x: = x + 28.
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v_minyears);
on the other
v_minmonths: = 0;
v_minyears: = v_minyears + 1;
x: = x + 28.
end if;
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end loop;
minMax end;
and the results are
01/01/1981
01/02/1981
01/03/1981
..................
.........---
01/04/1987
01/05/1987
01/06/1987
01/07/1987
01/08/1987
01/09/1987
01/10/1987
01/11/1987 the problem is max (hiredate) is 5/23/1987...it must show up to 01/05/1987...
I get a few more months...
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find the first day of the month
Hello...
can u pls let me know how to find the first day of the month, if the number of months (for ex - OCT-10) is passed as input
Kind regardsI'm not sure that there is a function called FIRST_DAY().
SQL> SELECT first_day (SYSDATE) 2 FROM DUAL; SELECT first_day (SYSDATE) * ERROR at line 1: ORA-00904: "FIRST_DAY": invalid identifier SQL> SELECT TRUNC (SYSDATE, 'month') 2 FROM DUAL; TRUNC(SYS --------- 01-DEC-08 SQL>
I hope this helps.
Kind regards
Joice -
Function to retrieve the first day of the month.
Select (sysdate, 'IW') of double
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