Function to retrieve the first day of the month.

Select (sysdate, 'IW') of double

I know it takes the date of Monday. Is there a function like above that has the date of return to the first Monday of the month?

Thanks in advance.

Hello

NEXT_DAY is very convenient, but it is dependent on the NLS_DATE_LANGUAGE, and you cannot pass an argument to override that.
TRUNC (dt, 'IW') is not in the NLS settings, then you may prefer this:

TRUNC ( 6 + TRUNC (SYSDATE, 'MONTH')
      , 'IW'
      )          AS first_monday

1st Monday of the month is fixed to the Monday or before the 7th of the month.

Tags: Database

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First day of a month
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Can you give an example?
Do you mean the last day of the month for a random date?
Then you can simply use builltin Oracle LAST_DAY function:
```
SQL> select sysdate from dual
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SYSDATE
-------------------
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```

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```
SELECT  TO_CHAR (SYSDATE, 'Month')
FROM    dual;
```
product of the results of this
```
April
```
(if you use English) and
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```
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Oracle function to retrieve the records randomly

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First day of the month between 08:00 and 18:30

DB version: 10.2.0.4

Due to the nature of our the first working day of each month (like today 1 MS), the DB will be very busy.
We execute a proc purge planned Windows Scheduler every 5 minutes every day.

But the first day of every month (like today 1 MS), if it's a day of the week (Monday to Friday) we do not want this proc running between 08:00 and for dinner from 18:30.

So, I thought including the logic in the procedure itself.

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Edited by: user872043, Sep 1 2010 08:48

Here is an example of using DBMS_SCHEDULER which should meet your needs:

Create schedules

BEGIN
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        , comments        => 'Schedule to run every 5 minutes'
        );

        DBMS_SCHEDULER.CREATE_SCHEDULE
        ( schedule_name   => 'busy_hourly_schedule'
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        );
END;
/

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Then, create your business:

Job creation

BEGIN
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END;
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HTH!

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Hello

Yes, it's a monthly report, I received the task at hand.

So, all I need is every day of the previous month (even if there is no data for that day)

I was instructed to use the following code, but it does not return a value any:

DECLARE
   CURSOR CUR_LAST_DAY IS
      SELECT TO_CHAR (LAST_DAY (ADD_MONTHS (SYSDATE, -1) ), 'DD')
        FROM DUAL;
 
   VVA_LAST_DAY   VARCHAR2 (2);
   --
   VNU_JOUR       NUMBER       := 0;
BEGIN
   OPEN CUR_LAST_DAY;
 
   FETCH CUR_LAST_DAY
    INTO VVA_LAST_DAY;
 
   CLOSE CUR_LAST_DAY;
 
   WHILE VNU_JOUR <= TO_NUMBER (VVA_LAST_DAY) - 1
   LOOP
      VNU_JOUR := VNU_JOUR + 1;
   END LOOP;
END;
--CLOSE CUR_LAST_DAY
--DEALLOCATE CUR_LAST_DAY

-----
On the other end, I developed this code:

SELECT TO_CHAR(SYSDATE,'dd')
FROM DUAL
WHERE TO_CHAR(SYSDATE,'dd') >= to_char(to_date(to_char(ADD_MONTHS(SYSDATE, -1),'yyyy-mm')||'-01'),'yyyy-mm-dd')
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Which returns a null value. :(

Concerning

Hello
You want to retrieve whole days of the month last query... So here's...

SELECT
TO_DATE(LEVEL||'-'||TO_CHAR(ADD_MONTHS(SYSDATE,-1),'MON-YY'),'DD-MON-YY') COMP_DATE,
TO_CHAR(TO_DATE(LEVEL||'-'||TO_CHAR(ADD_MONTHS(SYSDATE,-1),'MON-YY'),'DD-MON-YY'),'DD') ONLY_DD,
TO_CHAR(TO_DATE(LEVEL||'-'||TO_CHAR(ADD_MONTHS(SYSDATE,-1),'MON-YY'),'DD-MON-YY'),'MM') ONLY_MM,
TO_CHAR(TO_DATE(LEVEL||'-'||TO_CHAR(ADD_MONTHS(SYSDATE,-1),'MON-YY'),'DD-MON-YY'),'YY') ONLY_YY
FROM DUAL
CONNECT BY LEVEL <= TO_NUMBER(TO_CHAR(LAST_DAY(ADD_MONTHS(SYSDATE,-1)),'DD'))

I'm not at the machine database so not tested.

But one thing do not forget that this forum only for reports, it is a separate SQL and pl/sql instance.
Function to retrieve all the days of the previous month.

-Clément

Published by: Graham on April 22, 2010 22:53
Spelling error

First day with the mobile and shatter proof - broken

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I bought Xperia double Z3, mobile is great and every thing,

In the first day of use, it fell out of my hand on the ground, I picked up there instantly, but I was surprised that the screen was kicked as he was struck by the big hammer!
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They said that the screen was not shock resistant break proof!

I send the local support of sony in Egypt and they replied "good luck with your repair!

How can a mobile screen get bashed like that from a simple fall, and what is the problem with people taking in charge of sony?

Someone knows how to climb to a higher level of support?

If there is, please share the link, there is no such thing as a "phone shatter proof". I'm sorry about your question, but you have 2 options, 1. with your Xperia local as Jean-Claude suggested or DIY 2, for the last dated, you will cancel your warranty, but it might be cheaper, just to buy the LCD screen online and follow this

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PL/SQL function to calculate the non-working days

Hello
I have the following pl/sql function which generates a number of days between two selected dates (i.e. excluding weekends). However, I also need to exclude specific holidays - day of Christmas etc. These holiday dates are stored in a table in our database (11 GR 2) called "HOLIDAY".
How can I integrate the holidays which is held in the table of holidays in the following query to exclude these dates as well? I know how to write a separate funtion pl/sql for a number of days between two dates using SELECT... BUT I can't work out how to bring together them in a single query.
Could someone show me how with the pl/sql / dates below please?
Example of HOLIDAY table below.
Thank you!
TP
```
create or replace
function WORKING_DAYS (pi_start_date in date, pi_end_date in date) return integer

is

v_start_date date :=pi_start_date;
v_end_date date:=pi_end_date;
v_count integer:=0;

begin

while v_start_date <= v_end_date
      loop
                        if to_char(v_start_date,'D') not in ('6','7')                    
                        then
                        v_count := v_count+1;                       
                        end if;
                       
                v_start_date:=v_start_date+1;
               
      end loop;
     
return v_count;

end;
```
```
(select '10-Apr-2013' as NWD from dual union all
select '06-May-2013' from dual union all
select '27-May-2013' from dual union all
select '26-Aug-2013' from dual union all
select '26-Dec-2013' from dual union all
select '25-Dec-2013' from dual union all
select '01-Jan-2014' from dual union all
select '18-Apr-2014' from dual union all
select '21-Apr-2014' from dual union all
select '05-May-2014' from dual union all
select '26-May-2014' from dual union all
select '25-Aug-2014' from dual union all
select '25-Dec-2014' from dual union all
select '26-Dec-2014' from dual) HOLIDAYS
```
Hello

the link is on MOSC, not OTN... Here's a copy:

This function calculates the number of days between two dates, ignoring weekends and holidays (if requested and if the holidays are stored in a table)

I give an example of table 'public_holiday' with sample data, but users must ensure that their table contains the relevant data (all holidays within the maximum range of use of the service)

CREATE TABLE public_holiday (calendar_day, DATE, text VARCHAR2 (30));

FUNCTION to CREATE or REPLACE nb_days (p_date_from IN DATE

p_date_to DATE by DEFAULT TRUNC (sysdate)

, p_public_holidays in CHAR DEFAULT 'Y '.

) RETURN NUMBER

DEFINE AUTHID

AS

/*********************************************************************/

/ * Author: Bruno Vroman * /.

/ * Created: 23-AUG-2012 * /.

/ * Last updated: 23-AUG-2012 * /.

/ * Object: to calculate the number of days between 2 dates, to the exclusion of * /.

/ * Saturday and Sunday, but also "holidays" If the * /.

/ * argument 'p_public_holidays' = 'Y ' * /.

/ * Support: p_date_from<= p_date_to                             ="">

/ * component ' hour min dry "ignored (just counting days) * /.

/* First step:                                                       */

/ * the calendar days between 2 days * /.

/ Remove 2 days for each "week" and 0 or 1 extra day * /.

/ * function to a condition "complex" mix day of first week * /.

/ * and the number of days when full remaining weeks are removed * /.

/ * (set up once for all, for example if there is 3 days and the * /)

(/ * first day is a Thursday, there is 1 "Sat/Sun" to subtract) * /.

/ * Second step: If 'p_public_holidays' = 'Y': other * /.

/ * days, do not count holidays.                         */

/ Holiday everyday are defined in a table "public_holiday" * /.

/ * Note: there may be holidays defined on Saturday/Sunday.       */

/*********************************************************************/

l_result NUMBER;

l_from DATE;

l_to DATE;

l_case tank (4);

BEGIN

l_from: = TRUNC (p_date_from);

l_to: = TRUNC (p_date_to);

l_case: = TO_CHAR (l_from, 'Dy', 'NLS_DATE_LANGUAGE = English').

To_char (MOD (l_to - l_from + 1, 7));

l_result: = l_to - l_from + 1

-TRUNC ((l_to-l_from + 1) / 7) * 2

-CASE

WHEN l_case IN ('Mon6', 'Tue5', 'Wed4', 'Thu3', 'Fri2'

, "Sat1", "Sun1", "Sun2', 'Sun3", "Sun4".

, "Sun5', 'Sun6.

)

THEN 1

WHEN l_case IN ('Tue6', 'Wed5', 'Wed6', 'Thu4', "Thu5"

, 'Thu6', 'Fri3', 'Fri4', 'Fri5', 'Fri6 '.

, "Sat2", "Sat3', 'Sat4', 'Sat5", "Sat6.

)

THEN 2

0 OTHERWISE

END

;

IF SUPERIOR (p_public_holidays) = "Y".

THEN

SELECT l_result - COUNT (*)

IN l_result

OF public_holiday p

WHERE p.calendar_day > = l_from

AND p.calendar_day<=>

AND SUBSTR (TO_CHAR (p.calendar_day

, "Dy".

'NLS_DATE_LANGUAGE = English'

)

, 1, 1 ) != 'S'

;

END IF;

RETURN l_result;

EXCEPTION

WHILE OTHERS

THEN

DBMS_OUTPUT. Put_line (' CTF nb_days (' |))

To_char (p_date_from, "MON-DD-YYYY"). ', ' ||

To_char (p_date_to, "MON-DD-YYYY"). ', ' ||

p_public_holidays | ' ) : ' || SQLERRM

);

LIFT;

END nb_days;

/

REM

REM example:

REM A) fill out the 'public_holidays '.

REM

TRUNCATE TABLE public_holiday;

INSERT INTO public_holiday VALUES (DATE ' 2012-01-01', ' new year (a Sunday)');

INSERT INTO public_holiday VALUES (DATE '' 2012-01-03, "for example");

REM (insert other days...)

COMMIT;

Call the function for some pairs of dates of REM B)

REM nb1: remove only Sat/Sun

REM nb2: also remove holidays

REM

ALTER SESSION SET nls_date_format ='Dy DD-MON-YY';

WITH some_dates AS

(SELECT DATE ' 2011-12-29'd dual FROM

UNION ALL SELECT DATE ' 2012-01-08' FROM dual

UNION ALL SELECT DATE ' 2012-01-10' FROM dual

)

SELECT d1.d 'FROM '.

, d2.d ' to THE '.

, nb_days (d1.d, d2.d, ' don't) nb1

, nb_days (d1.d, d2.d, 'Y') nb2

OF some_dates d1

some_dates d2

WHERE d1.d<=>

ORDER BY nb1, nb2, d1.d

;

GO TO NB1 NB2

------------- ------------- ---- ----

Monday, January 8, 12 Monday, January 8, 12 0 0

Friday, December 29, 11 Friday, December 29, 11 1 1

Wednesday, January 10, 12 Wednesday, January 10, 12 1 1

Monday, January 8, 12 Wednesday, January 10, 12 2 2

Friday, December 29, 11 Monday, January 8, 12 7 6

Friday, December 29, 11 Wednesday, January 10, 12 9 8

Hope that this could be useful, but note that this code has not been completely tested, so check and test before you trust it (in the case of any questions, please post a comment)

Bruno Vroman.

Best regards

Bruno

Function to return the number of days in a month?
In one of my rules, I need to allocate an amount of benefits based on the number of days remaining in the calendar month.

OPM does have a function that can provide me with the number of days in a calendar month?

Thank you very much
Isamu
It is not a direct function to do this, however, it can be done with a bit of messing around. The following rules you will get the number of days of the month of the date of the date

Basically, you get the first day of the month, add a month to the first day of the following month and then get the number of days between them, which will give you the number of days of the month of the date
```
the month = ExtractMonth(the date)
the year = ExtractYear(the date)
the start of the month =MakeDate(the year, the month, 1)
the start of the next month = AddMonths(the start of the month, 1)
The number of days in the month = DayDifference(the start of the month, the start of the next month)
```
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Retrieve the name of the function call
I have 2 function in the CFC, even calling another function in the same CFC.

IS anyway to get the name of the first function (the appellants) from the second?
OR
is there anyway inside a function to retrieve this name?
Sounds right up your alley:

http://www.bennadel.com/blog/406-determining-which-function-called-this-function-using-Col dFusion .htm

find the first day of the month
Hello...
can u pls let me know how to find the first day of the month, if the number of months (for ex - OCT-10) is passed as input

Kind regards
I'm not sure that there is a function called FIRST_DAY().
```
SQL> SELECT first_day (SYSDATE)
  2    FROM DUAL;
SELECT first_day (SYSDATE)
       *
ERROR at line 1:
ORA-00904: "FIRST_DAY": invalid identifier

SQL> SELECT TRUNC (SYSDATE, 'month')
  2    FROM DUAL;

TRUNC(SYS
---------
01-DEC-08

SQL> 
```
I hope this helps.

Kind regards
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Function to retrieve the first day of the month.

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