First value in ORDER MIN different BY

Hello

According to the docu NLS_SORT must determine the order of sort ORDER BY and MIN/MAX

Oracle Database 11 g Enterprise Edition Release 11.2.0.2.0 - 64 bit Production

SELECT *.
OF nls_session_parameters
Setting WHERE = "NLS_SORT.
OR a parameter = "NLS_COMP;

VALUE OF THE PARAMETER
----------- -------
NLS_SORT GERMAN
BINARY NLS_COMP

I therefore expect that I get the same first / min and last/max values of the following

Oracle Database 11 g Enterprise Edition Release 11.2.0.2.0 - 64 bit Production

WITH testdata as)
SELECT 'A' double UNION ALL c
SELECT 'B' c IN double UNION ALL
SELECT '0' c TO double UNION ALL
SELECT '1' c double UNION ALL
SELECT FROM c '2' double
)
SELECT MAX (c)
MIN (c)
OF testdata.

MAX (C) MIN (C)
------ ------
B 0

WITH testdata as)
SELECT 'A' double UNION ALL c
SELECT 'B' c IN double UNION ALL
SELECT '0' c TO double UNION ALL
SELECT '1' c double UNION ALL
SELECT FROM c '2' double
)
C SELECT
ASCII (c)
OF testdata
ORDER BY c;

C ASCII (C)
- ----------
A 65
B 66
0 48
1 49
2 50

So I read on the sort

Oracle Database 11 g Enterprise Edition Release 11.2.0.2.0 - 64 bit Production

ALTER SESSION SET NLS_SORT = "BINARY";

C ASCII (C)
- ----------
0 48
1 49
2 50
A 65

B 66

Now, I get the expected results, but I can't always explain why a linguistic sort order letters before numbers and why it's different to ORDER BY and MAX/MIN.

Concerning

Marcus

According to the docu NLS_SORT must determine the order of sort ORDER BY and MIN/MAX

OK, but you overlooked that part:

Accurate operators and the query clauses that obey to the NLS_SORT parameter depends on the value of the NLS_COMP parameter. If a clause or an operator does not comply to the NLS_SORT value, as determined by NLS_COMP , the collation used is BINARY .

In your example, MIN and MAX always use BINARY collation, unless NLS_SORT is set to a specific language and NLS_COMP is LINGUISTICS.

On the contrary, ORDER BY, always obeys the NLS_SORT setting regardless of the NLS_COMP parameter.

This summarizes what operator and SQL clause obeys what parameter:

Linguistic sorting and string search

Tags: Database

Similar Questions

How to find the value max and min for each column in a table 2d?

How to find the value max and min for each column in a table 2d?

For example, in the table max/min for the first three columns would be 45/23, 14/10, 80/67.

Thank you

Chuck,

With color on your bars, you should have enough experience to understand this.

You're a loop in the table already. Now you just need a function like table Max and min. loop. And you may need to transpose the table 2D.

mark the first value of a group

I get the following

16:57:28 >r
  1  with my_table as
  2       (
  3      select 'M082012' pera, to_number(10584338) snr, to_number(10) pnr, 'Beule' name, 'Anna' f_name from dual union all
  4      select 'M092012' pera, to_number(15965177) snr, to_number(15) pnr, 'Tester' name, 'Toni' f_name from dual union all
  5      select 'M082012' pera, to_number(14254501) snr, to_number(20) pnr, 'Wallen' name, 'Monika' f_name from dual union all
  6      select 'M082012' pera, to_number(10584339) snr, to_number(10) pnr, 'Beule' name, 'Anna' f_name from dual union all
  7      select 'M092012' pera, to_number(15965178) snr, to_number(10) pnr, 'Beule' name, 'Anna' f_name from dual union all
  8      select 'M012013' pera, to_number(10674833) snr, to_number(15) pnr, 'Tester' name, 'Toni' f_name from dual union all
  9      select 'M012013' pera, to_number(10674834) snr, to_number(15) pnr, 'Tester' name, 'Toni' f_name from dual union all
 10      select 'M012013' pera, to_number(10539210) snr, to_number(30) pnr, 'Klose' name, 'Werner' f_name from dual union all
 11      select 'M012013' pera, to_number(12345678) snr, to_number(50) pnr, 'Meier' name, 'Otto' f_name from dual union all
 12      select 'M012013' pera, to_number(22345789) snr, to_number(50) pnr, 'Meier' name, 'Otto' f_name from dual union all
 13      select 'M082012' pera, to_number(10584346) snr, to_number(77) pnr, 'Carl' name, 'Frank' f_name from dual union all
 14      select 'M062012' pera, to_number(10550971) snr, to_number(77) pnr, 'Carl' name, 'Frank' f_name from dual union all
 15      select 'M092012' pera, to_number(15965185) snr, to_number(77) pnr, 'Carl' name, 'Frank' f_name from dual union all
 16      select 'M082012' pera, to_number(10584352) snr, to_number(50) pnr, 'Meier' name, 'Otto' f_name from dual union all
 17      select 'M092012' pera, to_number(15965191) snr, to_number(80) pnr, 'Duster' name, 'Hucke' f_name from dual)
 18  select case when pera = 'M012013' then '*' end mark,
 19         pera, snr, pnr, name, f_name
 20  from (
 21        select pera, snr, pnr, name, f_name,
 22               max(case when pera = 'M012013' then 'Y' end)
 23                 over(partition by upper(name||f_name)) m_flag,
 24               count(*) over(partition by upper(name||f_name)) cnt
 25        from my_table
 26       )
 27  where m_flag = 'Y'
 28  and cnt > 1
 29* order by 4,5,6, to_number(substr(pera,4,4)||substr(pera,2,2)) desc

MARK  PERA           SNR        PNR NAME   F_NAME
----- ------- ---------- ---------- ------ ------
*     M012013   10674834         15 Tester Toni
*     M012013   10674833         15 Tester Toni
      M092012   15965177         15 Tester Toni
*     M012013   22345789         50 Meier  Otto
*     M012013   12345678         50 Meier  Otto
      M082012   10584352         50 Meier  Otto

I would like to mark only the first value in the group with an asterisk as follows.

MARK  PERA           SNR        PNR NAME   F_NAME
----- ------- ---------- ---------- ------ ------
*     M012013   10674834         15 Tester Toni
      M012013   10674833         15 Tester Toni
      M092012   15965177         15 Tester Toni
*     M012013   22345789         50 Meier  Otto
      M012013   12345678         50 Meier  Otto
      M082012   10584352         50 Meier  Otto

Perhaps this example might be useful for you. the code uses the same code that you published with additional analytical query to return the row grouping for the name, the NRP and columns pera. then use that line number to determine which will be placed at the first mark.

SQL>   with my_table as
  2         (
  3        select 'M082012' pera, to_number(10584338) snr, to_number(10) pnr, 'Beule' name, 'Anna' f_name from dual union all
  4        select 'M092012' pera, to_number(15965177) snr, to_number(15) pnr, 'Tester' name, 'Toni' f_name from dual union all
  5        select 'M082012' pera, to_number(14254501) snr, to_number(20) pnr, 'Wallen' name, 'Monika' f_name from dual union all
  6        select 'M082012' pera, to_number(10584339) snr, to_number(10) pnr, 'Beule' name, 'Anna' f_name from dual union all
  7        select 'M092012' pera, to_number(15965178) snr, to_number(10) pnr, 'Beule' name, 'Anna' f_name from dual union all
  8        select 'M012013' pera, to_number(10674833) snr, to_number(15) pnr, 'Tester' name, 'Toni' f_name from dual union all
  9        select 'M012013' pera, to_number(10674834) snr, to_number(15) pnr, 'Tester' name, 'Toni' f_name from dual union all
 10        select 'M012013' pera, to_number(10539210) snr, to_number(30) pnr, 'Klose' name, 'Werner' f_name from dual union all
 11        select 'M012013' pera, to_number(12345678) snr, to_number(50) pnr, 'Meier' name, 'Otto' f_name from dual union all
 12        select 'M012013' pera, to_number(22345789) snr, to_number(50) pnr, 'Meier' name, 'Otto' f_name from dual union all
 13        select 'M082012' pera, to_number(10584346) snr, to_number(77) pnr, 'Carl' name, 'Frank' f_name from dual union all
 14        select 'M062012' pera, to_number(10550971) snr, to_number(77) pnr, 'Carl' name, 'Frank' f_name from dual union all
 15        select 'M092012' pera, to_number(15965185) snr, to_number(77) pnr, 'Carl' name, 'Frank' f_name from dual union all
 16        select 'M082012' pera, to_number(10584352) snr, to_number(50) pnr, 'Meier' name, 'Otto' f_name from dual union all
 17        select 'M092012' pera, to_number(15965191) snr, to_number(80) pnr, 'Duster' name, 'Hucke' f_name from dual)
 18    select case when pera = 'M012013' and rn = 1 then '*' end mark,
 19           pera,
 20           snr,
 21           pnr,
 22           name,
 23           f_name
 24      from (select pera, snr, pnr, name, f_name,
 25                   row_number() over (partition by pera, pnr, name, f_name order by pera, pnr, name) rn
 26              from (select pera, snr, pnr, name, f_name,
 27                           max(case when pera = 'M012013' then 'Y' end)
 28                           over(partition by upper(name||f_name)) m_flag,
 29                           count(*) over(partition by upper(name||f_name)) cnt
 30                      from my_table)
 31                     where m_flag = 'Y'
 32                       and cnt > 1
 33             order by 4,5,6, to_number(substr(pera,4,4)||substr(pera,2,2)) desc)
 34    order by 4,5,6, to_number(substr(pera,4,4)||substr(pera,2,2)) desc;

MARK PERA           SNR        PNR NAME   F_NAME
---- ------- ---------- ---------- ------ ------
*    M012013   10674834         15 Tester Toni
     M012013   10674833         15 Tester Toni
     M092012   15965177         15 Tester Toni
*    M012013   22345789         50 Meier  Otto
     M012013   12345678         50 Meier  Otto
     M082012   10584352         50 Meier  Otto

6 rows selected

SQL>

Set the first value after the select statement
Hello

I have a problem here.

After you run the statement select, it'll come to me:

COM
DLY
EXC
NRD
RDY

My question: How can I set the first value instead of 'COM' in "EXC"?

Thank you.
Hello
Where you use this instead:
```
select *
from
(
select col_name
,case when col_name='EXC' then 1 else 0 end as "id"
from table_name
)
order by "id" desc
```

I have a column with two values, separated by a space, in each line. How to create 2 new columns with the first value in a column, and the second value in another column?

I have a column with two values, separated by a space, in each line. How do I create 2 new columns with the first value in one column and the second value in another column?

Add two new columns after than the original with space separated values column.

Select cell B1 and type (or copy and paste it here) the formula:

= IF (Len (a1) > 0, LEFT (A1, FIND ("", A1) −1), ' ')

shortcut for this is:

B1 = if (Len (a1) > 0, LEFT (A1, FIND ("", A1) −1), ' ')

C1 = if (Len (a1) > 0, Member SUBSTITUTE (A1, B1 & "", ""), "")

or

the formula of the C1 could also be:

= IF (Len (a1) > 0, RIGHT (A1, LEN (A1) −FIND ("", A1)), "")

Select cells B1 and C1, copy

Select cells B1 at the end of the C column, paste

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UNION ALL

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Oracle database: 11g

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end;

first value in multiple columns

 

Hi experts,

select * from (
select 1  col1,3 col2,5 col3 from dual 
union all
select 6  col1,5 col2,5 col3 from dual 
union all
select 2  col1,3 col2,5 col3 from dual 
union all
select 10  col1,3 col2,5 col3 from dual 
union all
select 11  col1,3 col2,5 col3 from dual )


I have to get the first value from the each rows:


first_value
-----------
1
6
2
10
11

Thanks in advance

Published by: 846773 on 11 January 2012 10:20

Or maybe he wants to say:

select coalesce(col1,col2,col3) first_value from (
select 1  col1,3 col2,5 col3 from dual
union all
select 6  col1,5 col2,5 col3 from dual
union all
select 2  col1,3 col2,5 col3 from dual
union all
select 10     col1,3 col2,5 col3 from dual
union all
select 11     col1,3 col2,5 col3 from dual )

accounting for null values.

Published by: BluShadow on January 11, 2012 15:44
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First value in ORDER MIN different BY

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