Flatten the recursive hierarchy

Similar Questions

• Flatten the recursive XML tree

  Hello
  
  I'm trying to parse some XML and flatten for further processing. Using a variation on the code in this post [url http://forums.oracle.com/forums/thread.jspa?threadID=2210708 & tstart = 0] (thanks odie_63!) I can get insofar as:
  

  CREATE TABLE xml_test OF XMLType;
  
  INSERT INTO xml_test
  VALUES(XMLType('<Node>Text<Condition>CondType1<From>XX</From>
      <To>YY</To>
    </Condition>
    <Node>Child1<Condition>CondType2<Type>0</Type>
        <Number>12,34,56,89,0012</Number>
      </Condition>
      <Node>Child2<Condition>CondType3<From>Mon</From>
          <To>Fri</To>
        </Condition>
        <Tariff>Fee<Price>50</Price></Tariff>
        <Tariff>Rate<Price>10</Price><Interval>60</Interval></Tariff>
      </Node>
      <Node>DefaultRate<Tariff>Fee<Price>5000</Price></Tariff></Node>
    </Node>
  </Node>'));
  
  COMMIT;
  
  SELECT x.*
  FROM xml_test xt,
       XMLTable(
       'declare function local:getID($e as node()) as xs:integer
        {
         for $i at $j in $d/descendant::*
         where $i is $e
         return $j
        }
        ; declare function local:getConditions($c as node()) as element()*
        {
         for $cond in $c/child::Condition
         return element r
         {
          element condtype1_from { if ($cond/text() = "CondType1") then $cond/From/text() else () },
          element condtype1_to {if ($cond/text() = "CondType1") then $cond/To/text() else ()},
          element condtype2_type { if ($cond/text() = "CondType2") then $cond/Type/text() else () },
          element condtype2_number {if ($cond/text() = "CondType2") then $cond/Number/text() else ()},
          element condtype3_from { if ($cond/text() = "CondType3") then $cond/From/text() else () },
          element condtype3_to {if ($cond/text() = "CondType3") then $cond/To/text() else ()}
         }
        }; declare function local:getTariff($tariff as node()) as element()*
        {
         for $t in $tariff/child::Tariff
         return element r
         {
           element fee_price {if ($t/text() = "Fee") then $t/Price/text() else ()},
           element rate_price {if ($t/text() = "Rate") then $t/Price/text() else ()},
           element rate_interval {if ($t/text() = "Rate") then $t/Interval/text() else ()}
         }
        }; declare function local:getChildren($e as node(), $pID as xs:integer?) as element()*
        {
         for $i in $e/child::Node
         let $ID := local:getID($i)
         let $c := local:getConditions($i)
         let $t := local:getTariff($i)
         return element r
         {
          element tag_id {$ID},
          element parent_tag_id {$pID},
          element tag_name {local-name($i)},
          element tag_text {$i/text()},
          element attr_list {string-join(for $j in $i/@* return concat(local-name($j),''="'',$j,''"'')," ")},
          element condtype1_from { $c/condtype1_from },
          element condtype1_to { $c/condtype1_to },
          element condtype2_type { $c/condtype2_type },
          element condtype2_number { $c/condtype2_number },
          element condtype3_from { $c/condtype3_from },
          element condtype3_to { $c/condtype3_to },
          element fee_price { $t/fee_price },
          element rate_price { $t/rate_price },
          element rate_interval { $t/rate_interval }
         }
          | local:getChildren($i,$ID)
        }; local:getChildren($d,())'
        passing xt.object_value as "d"
        columns tag_id        number        path 'tag_id',
                parent_tag_id number        path 'parent_tag_id',
                tag_name      varchar2(50)  path 'tag_name',
                tag_text      VARCHAR2(50)  path 'tag_text',
                attr_list     varchar2(4000) path 'attr_list',
                condtype1_from varchar2(100) path 'condtype1_from',
                condtype1_to varchar2(100) path 'condtype1_to',
                condtype2_type varchar2(100) path 'condtype2_type',
                condtype2_number varchar2(100) path 'condtype2_number',
                condtype3_from varchar2(100) path 'condtype3_from',
                condtype3_to varchar2(100) path 'condtype3_to',
                fee_price number path 'fee_price',
                rate_price number path 'rate_price',
                rate_interval number path 'rate_interval'
       ) x;

  Gives me

  TAG_ID                 PARENT_TAG_ID          TAG_NAME   TAG_TEXT     CONDTYPE1_FROM CONDTYPE1_TO CONDTYPE2_TYPE         CONDTYPE2_NUMBER     CONDTYPE3_FROM CONDTYPE3_TO FEE_PRICE              RATE_PRICE             RATE_INTERVAL          
  ---------------------- ---------------------- ---------- ------------ -------------- ------------ ---------------------- -------------------- -------------- ------------ ---------------------- ---------------------- ---------------------- 
  1                                             Node       Text         XX             YY                                                                                                                                                        
  5                      1                      Node       Child1                                   0                      12,34,56,89,0012                                                                                                      
  9                      5                      Node       Child2                                                                               Mon            Fri          50                     10                     60                     
  18                     5                      Node       DefaultRate                                                                                                      5000                                                                 

  I don't see how reach (whether via XML or SQL right - recursion or same PL/SQL) is how to flatten slightly further given the rules:
  < li > three types of node is node, Condition and price.
  < li > node A is always the starting point and can have zero, one or several Conditions and may have more than one node at the same level.
  < li > after the crossing of all nodes and Conditions will end one or two nodes in tariff.
  < li > I want to consolidate the conditions where they appear at different levels for a fee (to be delimited by a character, for example a 'C').
  < li > the "tag_text" should come together to form the unique path to the tariff.
  < li > A node that ends in a tariff grid is not all child nodes more of any type.
  
  The output I want aim (above) would be:

  TAG_ID                 PARENT_TAG_ID          TAG_NAME   TAG_TEXT                  CONDTYPE1_FROM CONDTYPE1_TO CONDTYPE2_TYPE         CONDTYPE2_NUMBER     CONDTYPE3_FROM CONDTYPE3_TO FEE_PRICE              RATE_PRICE             RATE_INTERVAL
  ---------------------- ---------------------- ---------- ------------------------- -------------- ------------ ---------------------- -------------------- -------------- ------------ ---------------------- ---------------------- ---------------------- 
  1                                             Node       /Text/Child1/Child2       XX             YY           0                      12,34,56,89,0012     Mon            Fri          50                     10                     60
  18                                            Node       /Text/Child1/DefaultRate  XX             YY           0                      12,34,56,89,0012                                 5000

  I would really, really appreciate any input on this one because I think I looked at it for far too long... I'm almost there still can not quite end the.
  
  Thank you very much
  
  Gareth.

  Hi Gareth,

  I want to consolidate the conditions where they appear at different levels for a fee (to be delimited by a character, for example a 'C').

  Could you give an example? It shall apply on the sample?

  Additional question:
  On the final output, you still need TAG_ID, PARENT_TAG_ID and TAG_NAME?

  If I understand what you're after, a quick way is to use a CONNECT BY clause directly on your existing query:

  SELECT sys_connect_by_path(x.tag_text, '/') as tag_text
       , sys_connect_by_path(x.condtype1_from, '/') as condtype1_from
       , sys_connect_by_path(x.condtype1_to, '/') as condtype1_to
       , sys_connect_by_path(x.condtype2_type, '/') as condtype2_type
       , sys_connect_by_path(x.condtype2_number, '/') as condtype2_number
       , sys_connect_by_path(x.condtype3_from, '/') as condtype3_from
       , sys_connect_by_path(x.condtype3_to, '/') as condtype3_to
       , x.fee_price
       , x.rate_price
       , x.rate_interval
  FROM xml_test xt,
       XMLTable(
       'declare function local:getID($e as node()) as xs:integer
        {
         for $i at $j in $d/descendant::*
         where $i is $e
         return $j
        }
        ; declare function local:getConditions($c as node()) as element()*
        {
         for $cond in $c/child::Condition
         return element r
         {
          element condtype1_from { if ($cond/text() = "CondType1") then $cond/From/text() else () },
          element condtype1_to {if ($cond/text() = "CondType1") then $cond/To/text() else ()},
          element condtype2_type { if ($cond/text() = "CondType2") then $cond/Type/text() else () },
          element condtype2_number {if ($cond/text() = "CondType2") then $cond/Number/text() else ()},
          element condtype3_from { if ($cond/text() = "CondType3") then $cond/From/text() else () },
          element condtype3_to {if ($cond/text() = "CondType3") then $cond/To/text() else ()}
         }
        }; declare function local:getTariff($tariff as node()) as element()*
        {
         for $t in $tariff/child::Tariff
         return element r
         {
           element fee_price {if ($t/text() = "Fee") then $t/Price/text() else ()},
           element rate_price {if ($t/text() = "Rate") then $t/Price/text() else ()},
           element rate_interval {if ($t/text() = "Rate") then $t/Interval/text() else ()}
         }
        }; declare function local:getChildren($e as node(), $pID as xs:integer?) as element()*
        {
         for $i in $e/child::Node
         let $ID := local:getID($i)
         let $c := local:getConditions($i)
         let $t := local:getTariff($i)
         return element r
         {
          element tag_id {$ID},
          element parent_tag_id {$pID},
          element tag_name {local-name($i)},
          element tag_text {$i/text()},
          element condtype1_from { $c/condtype1_from },
          element condtype1_to { $c/condtype1_to },
          element condtype2_type { $c/condtype2_type },
          element condtype2_number { $c/condtype2_number },
          element condtype3_from { $c/condtype3_from },
          element condtype3_to { $c/condtype3_to },
          element fee_price { $t/fee_price },
          element rate_price { $t/rate_price },
          element rate_interval { $t/rate_interval }
         }
          | local:getChildren($i,$ID)
        }; local:getChildren($d,())'
        passing xt.object_value as "d"
        columns tag_id           number        path 'tag_id',
                parent_tag_id    number        path 'parent_tag_id',
                tag_name         varchar2(50)  path 'tag_name',
                tag_text         varchar2(50)  path 'tag_text',
                condtype1_from   varchar2(100) path 'condtype1_from',
                condtype1_to     varchar2(100) path 'condtype1_to',
                condtype2_type   varchar2(100) path 'condtype2_type',
                condtype2_number varchar2(100) path 'condtype2_number',
                condtype3_from   varchar2(100) path 'condtype3_from',
                condtype3_to     varchar2(100) path 'condtype3_to',
                fee_price        number        path 'fee_price',
                rate_price       number        path 'rate_price',
                rate_interval    number        path 'rate_interval'
       ) x
  WHERE connect_by_isleaf = 1
  CONNECT BY prior tag_id = parent_tag_id
  START WITH parent_tag_id IS NULL
  ;
  
  TAG_TEXT                       CONDTYPE1_FROM   CONDTYPE1_TO   CONDTYPE2_TYPE   CONDTYPE2_NUMBER      CONDTYPE3_FROM   CONDTYPE3_TO    FEE_PRICE RATE_PRICE RATE_INTERVAL
  ------------------------------ ---------------- -------------- ---------------- --------------------- ---------------- -------------- ---------- ---------- -------------
  /Text/Child1/Child2            /XX//            /YY//          //0/             //12,34,56,89,0012/   ///Mon           ///Fri                 50         10            60
  /Text/Child1/DefaultRate       /XX//            /YY//          //0/             //12,34,56,89,0012/   ///              ///                  5000
   
  

  Here I used the SYS_CONNECT_BY_PATH function to aggregate the values in the pecking order. You can change the separator and use string manipulation functions more format the result.

  This can also be done directly in XQuery. So if you could answer the two questions above then I could show you how.

• How Windows Explorer can be configured to browse the folder hierarchy instead of behaving like a browser?

  I work with files in a folder tree.  I want to browse this folder hierarchy, just as I did in the original copy of Windows Explorer in Windows XP.  I want to use the arrow keys to navigate up and down, and when I'm in a folder and click the previous button, I want it to go up one level in the folder hierarchy, just like he used to.

  Now, when I hit the 'back' button, Windows Explorer behaves as a browserand goes to the last folder that I have read.

  It's so frustrating!  She interrupts my thought process and the movement of my work.  If I wanted to use a browser, I use Internet Explorer.

  How Windows Explorer can be configured to browse the folder hierarchy instead of behaving like a browser?  Remember the "unwebified" of Windows XP Windows Explorer version?  This is what I want so I can get back to work effectively.

  Windows Explorer 7 does not have the up button like XP, however, in the address bar you can select the folder in the hierarchy (sometimes called the trail of bread crumbs) to return.

  Windows 8 added the arrow pointing upwards.

• Problem with the Navigator hierarchy

  Hello

  I installed Navigator hierarchy according to the description in the installation guide, which is

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  2. installation of the navigation hierarchy (Scripts apply then pitch the series up)

  and all the results of running the script has been directed by the specified page.

  After installation, I went to tool > > Navigator hierarchy and nothing is displayed, the icon I got is 'Globe' instead of the one mentioned in the document, is there something I'm missing?

  Thank you

  I solved the problem and get the browser hierarchy as expected with all the expected results.

  I did as a result of things to solve the problem:

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  4. apply the hierarchy Denorm scripts, Service restarts and IISRest.

  5. installation Denorm Setup, restart the Service.

  6. application of browser scripts. Restart the service.

  7 installation installation and restart the Service.

• Is there a shortcut key for "Flatten Image"?  I just upgraded to CC and again it is not a shortcut for IT... Ugh.  Someone knows something to flatten the Image via the keyboard?

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  You can create your own sets of shortcuts - Edition > keyboard shortcuts.

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  What is the difference between the layers of the merger, flatten the layers & merge down?  How can I know which to use?

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• I need to check required fields, "flatten" the PDF and send PDF saved to the e-mail recipient. Is there a way to do this?

  I found flatten java script, but making my useless button and flatten the entire document.

  I also found that the actions of document to check

  for (var i = 0; i < this.numFields; i ++) {}

  fieldName var = this.getNthFieldName (i);

  field var = this.getField (fieldName);

  If (field.value.length == 0)

  {

  field.setFocus)

  App.Alert ("Field" fieldName + "is required.) Please enter a value. »)

  }

  }

  but I do still need to flatten + send to an e-mail recipient. Is it possible to do all these steps with just one button? Or save the form as being "read" only.

  IM currently using Acrobat XI

  Invoke the var = new Array ("AFieldName... 1','AFieldName... 2", ".....");

  var cFieldName = «»

  var ok = true
  for (var i = 0; i)< afields.length;="" i++)="">

  cFieldName = this.getField (aFields [i])
  If (cFieldName.value == "") {}

  OK = false
  cFieldName.setFocus)
  App.Alert ("field [" + cFieldName.name + "] is required. ') Please enter a value. »)

  }
  }

  If (ok == true) {}
  for (var i = 0; i)< this.numfields="" ;="" i++)="">
  var f = this.getField (this.getNthFieldName (i));
  If (f == null) continue;
  f.ReadOnly = true
  }

  this.mailDoc({)
  cTo: "[email protected]."
  bassujetti: "your subject...". »,
  CMSG: "dear...". »
  })
  }

• Flatten the data in, SELECT

  Oracle 11 g 2

  Linux Mint

  ==========

  In light of the following:

  create table grades_detail (school_year char (4),
  grade char(1),
  grade_desc 40,
  constraint pk_grades_detail primary key (school_year, grade));

  create table class_grades_detail (student, char (6),)
  school_year char (4),
  class1_grade char (1),
  class2_grade char (1),
  class3_grade char (1),
  class4_grade char (1),
  constraint pk_class_grades_detail primary key (student, school_year));

  
  insert into grades_detail values ('2013', 'A', 'Excellent');
  insert into grades_detail values ("2013", 'B', 'Good');
  insert into grades_detail values ("2013", 'C', 'Medium');
  insert into grades_detail values ('2013 ',' d ", 'Poor');
  insert into grades_detail values ("2013", 'F', 'Bankrupt');

  insert into class_grades_detail values ('1001', '2013', 'A', ",", ");
  insert into class_grades_detail values ('1002 ', ' 2013', ","B",",");
  insert into class_grades_detail values ('1003 ', ' 2013', ",", "C", ");
  insert into class_grades_detail values ('1004 ', ' 2013', ",",", ');
  insert into class_grades_detail values ('2005', '2013', 'A', ","C",");
  insert into class_grades_detail values ('2006', '2013', 'A', ",", 'F');
  insert into class_grades_detail values ('2007', '2013',' A ',' B', ",");
  insert into class_grades_detail values ('2008', "2013" ", would be", ", had ',");

  and given the following SQL code:

  Select class_grades_detail.student
  class_grades_detail.school_year
  class_grades_detail.class1_grade
  class_grades_detail.class2_grade
  class_grades_detail.class3_grade
  class_grades_detail.class4_grade
  grades_detail.grade_desc
  of class_grades_detail
  class_grades_detail.school_year left join grades_detail = grades_detail.school_year
  and (class_grades_detail.class1_grade = grades_detail.grade
  or class_grades_detail.class2_grade = grades_detail.grade
  or class_grades_detail.class3_grade = grades_detail.grade
  or class_grades_detail.class4_grade = grades_detail.grade);

  How 'flatten' the data to get a result like below?

  (Yes, I know the SQL above has not all the columns in gradeX_desc below, but that's what I'm aiming for - a column for each class descr.)  However, the SQL above will show you the data as it appears currently):

  student, school_year, class1_grade, grade1_desc, class2_grade, grade2_desc, class3_grade, grade3_desc, class4_grade grade4_desc

  1001 2013 A B excellent C good average poor D

  With the SQL above I have not (of course) get it.  Yes, I think to Swivel, but could not get this to work.  Even tried to DECODE.

  Any help would be appreciated.

     select distinct
              cgd.student, cgd.school_year,
               MAX(cgd.class1_grade) g1, MAX(gd1.grade_desc ) grade1,
               MAX(cgd.class2_grade) g2, MAX(gd2.grade_desc ) grade2,
               MAX(cgd.class3_grade) g3, MAX(gd3.grade_desc ) grade3,
               MAX(cgd.class4_grade) g4, MAX(gd4.grade_desc ) grade4
       from class_grades_detail cgd,
            grades_detail gd1,
            grades_detail gd2,
            grades_detail gd3,
            grades_detail gd4
      where gd1.school_year(+) = cgd.school_year
        and gd2.school_year(+) = cgd.school_year
        and gd3.school_year(+) = cgd.school_year
        and gd4.school_year(+) = cgd.school_year
        and gd1.grade(+) = cgd.class1_grade
        and gd2.grade(+) = cgd.class2_grade
        and gd3.grade(+) = cgd.class3_grade
        and gd4.grade(+) = cgd.class4_grade
     group by cgd.student, cgd.school_year
  

  STUDENT SCHOOL_YEAR G1 G2 G3 G4 GRADE4 GRADE3 GRADE2 GRADE1

  ------- ----------- -- ------------ -- ------------ -- ------------ -- ------------

  Good 1002 2013 B

  2006 2013 A F excellent Fail

  Good 2007-2013 has excellent B

  1004    2013                                                        D  Poor

  1001 2013 has excellent

  2008 2013 D D poor poor

  1003 2013 C average

  2005-2013 A C average excellent

  8 selected lines.

• In Adobe Acrobat Pro Version 11.0.0 XI - flatten the file is not editable even by Acrobat

  In Adobe Acrobat XI Pro Version 11.0.0 I use the option flatten under control up front, but when I return in the document using Acrobat and use the change text and Images, I am able to edit and delete items in the document. I also tried flattening Preview-> apply, but it does not work either. Finally, I tried to print the document in pdf format, but the same thing happens. If a document is flattened, it is not editable by any software, but it seems that if someone has Acrobat, they will be able to edit the pdf file I send them. Can you please tell me how I can really flatten a pdf file so that it is not editable by all?

  If you want editable by any software from Adobe, you can add security when you flatten the document.

• OBIEE 11 g with BI Apps EBS: how to load the Product hierarchy?

  Hi gurus,
  
  We are implementing BI 7.9.6.3 applications [OBIEE 11.1.1.1.5 with EBS modules].
  
  We have implemented all the configurations and mappings in Informatica. But after complete loading ETL. The Product hierarchy view all null.
  
  Currently, we are studying it. Anyone with experience points can we what are possible places to look for?
  
  Is this something that we need to set up SDE_Universal_ProductDimension of SDE_Universal_Adaptor. Currently, it is not configured.
  
  Any ideas will be greatly appreciated.
  
  Concerning
  Nathalie

  No you don't need to touch any of the mappings 'universal '.

  Check this Metalink note:

  Product hierarchy is not filled in OBIA 7.9.6 with EBS R12.1.1 as source [1110185.1 ID]

  So useful, pls mark as correct or useful

• Where can I find a tutorial on the folder hierarchy show?

  I have 11 items first, which is also the organizer of the program elements. And I also have Photoshop Elements 10. The organizer elements with video editing software, that's what I'm interested in good. I think that my folder hierarchy is not fair. I want to straighten but I don't know how. Can someone direct me to a tutorial on how to work with the folder hierarchy.

  This could be another issue, but it could be related to my confusion about the folder hierarchy in the Organizer. On June 10 I was copying some photos from my hard drive to the Organizer - probably a stupid thing to do. While I was doing this, the pictures folder (display and organize digital images) not is more took me to all my photos on the hard drive. The pictures folder's subfolders, Documents, music, Control Panel on the Windows 7 Desktop to the right of the menu stuff start.

  When I click on images now I get two files: Adobe and photos. The Adobe file has these values - size: 0 bytes; Contains: 0 files, 1 folder; Created the: Monday, June 10, 2013; Attributes: Read-only (applies only to files in the folder. I deleted the folder Adobe several times but he returns.

  What I really want to do, is to restore my folder image to its original state so that I have access to all the photos of my HDD immediately instead of clicking around these issues. Vaguely, I think that something I did to the folder hierarchy in the optimizer has messed up things on my computer.

  Of what you have listed here, it looks like you have moved your records photo up to a level... sort of. I don't know why computer appears in my images (or perhaps there is just one problem with the way you have indented the list here...). But it looks like you have a lot of your image files moved to the parent folder where one normally would expect them to be.

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  All this can be done in the elements Organizer, simply drag and drop a folder to move it from where it is at the location you want.

  For any questions with the help of the elements of first, you'll want to post in the forum first parts of responses: http://forums.adobe.com/community/premiere_elements

• TIFF of Import Options - flatten the layers into a single Image

  Hi all

  Running a script to open the files and convert them into another type. When it comes to a TIFF file type, called 'TIFF Import Options' dialog box opens. This window has a column of Options containing two pieces of music radio to "Convert layers to objects" and "flatten into a single Image. How to open the file with the whole "flatten the layers into a single image?

  Thank you

  OpenOptionsPhotoshop.preserveLayers = true;

• The recursive subquery factoring vs hierarchical query

  Experts,
  
  Here it is two queries, I'm executing using hierarchical of recursive subquery and new classical approach. Problem came out was different for the recursive subquery factoring, as this is not displayed parent-child approach, while forwards connect shows parent-child mode. Query 1, I use hierarchical as show good output parent-child, is approaching the 2 query displays all of the nodes of level 1 and then level 2 nodes. I want the query 2 output to be the same as query 1. change query 2 as required.
  
  Note: the output of the two queries post as in sqlplus and toad. Please copy and use in your command prompt.
  
  QUERY 1:
  
  with the hand in the form (select 1 id, name 'John', null, mgrid Union double all the)
  Select 2 id, the name of 'michael', null, mgrid Union double all the
  Select 3 id, the name of "peter", null, mgrid Union double all the
  Select 4 id, the name of "henry", 1 mgrid Union double all the
  Select 5 id, "nickname", mgrid 2 Union double all the
  Select 6 id, "pao" name, mgrid 3 of all the double union
  Select 7 id, the name of 'kumar', mgrid 3 of all the double union
  Select 8 id, the name 'parker', mgrid 3 of all the double union
  Select 9 id, the name of "mike", 5 double mgrid),
  Select lpad (' ', 2 *(level-1)). name, key start with mgrid level is null connect by prior id = mgrid.
  
  OUTPUT:
  
  LEVEL NAME
  ------------------------------ ----------
  John 1
  Henry 2
  Michael 1
  Nick 2
  Mike 3
  Stone 1
  PAO 2
  Kumar 2
  Parker 2
  
  9 selected lines.
  
  QUERY 2:
  
  with the hand in the form (select 1 id, name 'John', null, mgrid Union double all the)
  Select 2 id, the name of 'michael', null, mgrid Union double all the
  Select 3 id, the name of "peter", null, mgrid Union double all the
  Select 4 id, the name of "henry", 1 mgrid Union double all the
  Select 5 id, "nickname", mgrid 2 Union double all the
  Select 6 id, "pao" name, mgrid 3 of all the double union
  Select 7 id, the name of 'kumar', mgrid 3 of all the double union
  Select 8 id, the name 'parker', mgrid 3 of all the double union
  Select 9 id, the name of "mike", 5 double mgrid),
  / * Select lpad (' ', 2 *(level-1)). name, key start with mgrid level is null connect by prior id = mgrid. * /
  secmain (id, name, mgrid, hierlevel) as (select id, name, mgrid, 1 hierlevel of the main where mgrid is null
  Union of all the
  Select m.id, $m.name, m.mgrid, sm.hierlevel + 1 in m main join secmain sm on(m.mgrid=sm.id))
  cycle is_cycle set id 1 default 0
  Select lpad (' ', 2 *(hierlevel-1)). name, secmain hierlevel.
  
  OUTPUT:
  
  NAME HIERLEVEL
  ------------------------------ ----------
  John 1
  Michael 1
  Stone 1
  Henry 2
  Nick 2
  Parker 2
  Kumar 2
  PAO 2
  Mike 3
  
  9 selected lines.

  For example

  SQL> with main as(select 1 id,'john' name,null mgrid from dual union all
    2  select 2 id,'michael' name,null mgrid from dual union all
    3  select 3 id,'peter' name,null mgrid from dual union all
    4  select 4 id,'henry' name,1 mgrid from dual union all
    5  select 5 id,'nick' name,2 mgrid from dual union all
    6  select 6 id,'pao' name,3 mgrid from dual union all
    7  select 7 id,'kumar' name,3 mgrid from dual union all
    8  select 8 id,'parker' name,3 mgrid from dual union all
    9  select 9 id,'mike' name,5 mgrid from dual),
   10  secmain (id,name,mgrid,hierlevel) as
   11  (select id,name,mgrid,1 hierlevel from main
   12   where mgrid is null
   13   union all
   14   select m.id,m.name,m.mgrid,sm.hierlevel+1 from main m join secmain sm on(m.mgrid=sm.id))
   15  search depth first by name set seq
   16  cycle id set is_cycle to 1 default 0
   17  select lpad(' ',2*(hierlevel-1))||name name,hierlevel from secmain order by seq;
  
  NAME        HIERLEVEL
  ---------- ----------
  john                1
    henry             2
  michael             1
    nick              2
      mike            3
  peter               1
    kumar             2
    pao               2
    parker            2
  
  9 rows selected.
  
  SQL> 
  

  Published by: Dom Brooks on November 23, 2011 13:52
  Edited for the scope of the search and detection of cycle

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