FRM-40212: invalid value for < "the radio group name" >

Similar Questions

• FRM-40212: invalid value for the WIP_ENTITY_NAME field?

  Everyone in the face of this issue that the article on this subject is an element of the ATO. We created jobs, but in the face of this error when trying to move the transaction.

  Hello

  We have identified the problem.

  Some option enabled only for move transaction and transaction completion by application of ACEM. That is why all work unable to transit through order forms

  Thank you and best regards,

  S.Senthilkumar ITIL-Expert

• DEU-00014: invalid value for the setting, "include".

  Hi, I need to do an export of paintings from a schema and a particular query executed will apply to all the specified tables in "INCLUDE = TABLE: '('TBL1', 'TBL2') IN' in the command expdp.»
  
  Now, I get the question in this setting INCLUDE. I have about 200 paintings to be included and I add this parameter INCLUDE in a separate parameter with all table names 200 file in Informatics and with the help of this parameter file in the expdp command.
  
  Error message I get:
  DEU-00014: invalid value for the setting, "include".
  
  When I use the same process for 2 tables, this works very well. I think that there is a limit to the number of characters that can be used in the INCLUDE parameter. If so, then how do I use expdp to select only those 200 tables of 500 paintings in my diagram. I'd appreciate any help on this. Thank you.

  Hello

  I'm sure that the limit is 4000 characters, but there are fairly simple workaround.

  Create the table my_tabs (a varchar2 (30));
  insert into my_tabs values ('your_table_name');
  Repeat this step for each of your 200 tables

  include = TABLE: "in ((SELECT from MY_TABS)) '"

  You may need to mess you with the quote, but the value you were using is just an expression. It is only by using a different expression.

  Dean

• UDI-00014: invalid value for the parameter, "remap_tablespace".

  Hi all
  
  Windows 2003 Server
  Oracle 10g
  
  I'm doing a reorg, so I droped and recreated the schema. No w I want to import my datapump schema export, but it gives me an error:
  UDI-00014: invalid value for the parameter, "remap_tablespace".
  
  Here is my script:
  Impdp patterns of name of user and password = siebel directory = dpdir dumpfile = logfile schema_exp.dmp = schema_imp.log remap_tablespace = SBL_DATA:SBL_DATA, SBL_INDEX:SBL_INDEX State 60
  
  What I'm doing wrong, it makes me crazy, please help
  
  Published by: user11211037 on December 6, 2009 00:54

  Syntax and Description

  SCHEMAS = schema_name [,...]

  If you have the IMP_FULL_DATABASE role, you can use this parameter to perform a schema mode import by specifying one single schema other than your own or a list of schemas to import. First, schemas were created (if they do not already exist), including the system and the role of subsidies, the history of password and so on. Then all the objects contained in the imported patterns. Unprivileged users can only specify their own schemas. In this case, no information about the schema definition is imported, only the objects it contains.

  Hope you are clear.

  Concerning
  Asif Kabir

  -Mark your answer as correct/useful.

• Invalid value for the registry when opening pictures

  How to avoid the problem of the "invalid value for registry", in the first place?

  Separated from -.

  https://answers.Microsoft.com/en-us/Windows/Forum/windows_8-pictures/invalid-value-for-registry-when-opening-photos/531aea75-00b8-4C8D-a91a-87a6e439ab1c

  Hi Anthony,.

  Did you follow the troubleshooting steps suggested to solve the problem of the other link?

  I recommend you to define an application installed on the default computer to view the pictures and check if it helps.

  Refer to:

  Choose the apps Windows uses by default

  http://Windows.Microsoft.com/en-CA/Windows-8/choose-Programs-Windows-uses-default

  I hope this helps. If you have any other queries/issues related to Windows, write us and we will be happy to help you further.

• No default value for the security group

  Hi all
  
  I want to Group (SG) of security did not have a default value, so that users must select SG every time they check in new doc. At present, the default value for the SG is the 1st value, which can make the user forgot to change the SG and ultimately, check in with SG bad doc.
  
  Someone knows how to do this? Thanks in advance.
  
  d.s.

  Hello

  You can set ForceSecurityGroupChoice = true in config.cfg and restarts the CS to force users to choose security whenever they go to the archiving of documents.

  Thank you
  Srinath

• Invalid value for the cursor.xscale property

  I am creating a property node for "cursor.xscale", but when I try to write a numeric entry in it, it does not accept any value (at least all the values that I tried). An error indicating that the value is not valid. What is a valid value for this property and what exactly makes this this property (not a lot of documentation available I guess)

  the XScale property is a number from 0 to n - 1, where n is the number of scales X you have on your chart (usually 1).

  Here is an example of chart scales of X 3 and 2 cursor associated with the scale 'Time' and 'Time 2 "respectively.

  

  The reason why it is important, it is that the X values read you in the column 'X' cursor will be different depending on whether the cursor is associated with one or the other ladder, as you can see above.

  HTH.

• Invalid value for parameter error when the value is in the list of the parameters allowed

  I have a few documents with many styles of paragraphs which have been organized in groups. I have a simple script that aims to decouple these styles and remove groups now empty.

  Code:

  #target indesign
  
  
  var myDoc = app.activeDocument;
  
  
  if (myDoc.paragraphStyleGroups.length > 0)
  {
      myDoc.paragraphStyleGroups.everyItem().paragraphStyles.everyItem().move(LocationOptions.AT_END, myDoc);
  
  
      myDoc.paragraphStyleGroups.everyItem().remove();
  }    
  
  
  alert("Done")
  
  

  The error I get is (my highlighting):

  JavaScript error!

  Error number: 30477

  Error string: invalid value for the "reference" parameter of method "move". ParagraphStyle waited, ParagraphStyleGroup, CharacterStyle, CharacterStyleGroup, CellStyle, CellStyleGroup, TableStyle, TableStyleGroup, Document or application, but received Document.

  As you can see, my Pickle is my value is of a type allowed. This only happens in certain documents, and there is nothing that distinguishes these documents from those in which it works of course.

  One thing I noticed is that the error sometimes manifests a while to appear (a minute or two), but none of the styles have been moved once I click OK. So, I don't know if this is specific to a single style. I doubt it, just because other documents with the same style the value of work.

  Anyone can shed light on what this error can mean in this context? I have certainly an activeDocument, so what could cause a Document to a Document?

  Any help much appreciated!

  Hello

  It occurs when there are 2 or more models have the same name, probably.

  Jarek

• How to set the default value for the Group of radio buttons

  Hello
  Here's my situation.
  I have a form of HTML text. In the form, I have an element called "* drinks * ' and its options in the radio button group or coffee, tea. Now, I want to put a default value("NA") to the radio of drinks group. Is it feasible. If so, how. Advice would be useful. Thank you

  Hello!

  You can also set a default value in the radio unit of page article under the default setings. Here, you must put the result value (if you have static: Café;) One, the; B, NA; C you write C if you want NA default choice) of your radio.

  concerning

• Determine a value for each record for the whole group

  < < Sorry I pasted erroneous results earlier > >
  
  Hello
  
  I have a table (in production, join the many tables, but for simplicity, I created a table), which has a few related accounts grouped by ACCT_GRP_ID I have to write a SQL (not a PL/SQL), who should have all columns of this table and an extra column "FLAG". For GA_CD = BBC, FLAG must have a value of 'No Show', if the APP_DT of at least a recording with the group is less than the current year also all the records in the group will have a value of 'Show '. For the record no BBC FLAG must always be 'Show '.
  
  DDLS
  {code}
  CREATE TABLE ACCOUNTS
  (NUMBER OF ACCT_GRP_ID,
  GA_CD VARCHAR2 (10),
  AGNT_NAME VARCHAR2 (50).
  NUMBER OF CASE_NUM
  NUMBER OF FUND_AMT
  DATE OF APP_DT,
  STATUS VARCHAR2 (10));
  
  INSERT INTO ACCOUNT VALUES (1, 'BBC', 'SAMANTHA, JOSE, 12345, 234.33, 2 AUG 2008', ' PLACED');
  INSERT INTO ACCOUNT VALUES (1, 'BBC', 'SAMANTHA, JOSE, 12346, 331,13, 24 APR 2009', ' PLACED');
  INSERT INTO ACCOUNT VALUES (1, 'BBC', 'SAMANTHA, JOSE, 12347, 201,27, 13 FEB 2009', ' PLACED');
  INSERT INTO ACCOUNT VALUES (2, 'BBC', ' MARK, ROSS, 12348, 98.12, 31 MAY 2009', 'PLACE' ");
  INSERT INTO ACCOUNT VALUES (2, 'BBC', ' MARK, ROSS, 12349, 121.00, 25 JUNE 2009', 'PLACE' ");
  INSERT INTO ACCOUNT VALUES (2, 'BBC', 'BRAND, ROSS, 12350, 11.00, 27 JUNE 2009', 'CLOSED');
  INSERT INTO ACCOUNT VALUES (3, 'BBC', "RAJ MALIK", 12351, 89.00, 31 DEC 2008', 'PLACED');
  INSERT INTO ACCOUNT VALUES (3, 'BBC', "RAJ MALIK", 12352, 22.00, 26 OCT 2008', 'PLACED');
  INSERT INTO ACCOUNT VALUES (4, 'BBC', 'SHANE, WILLS', 12353, 443.00, 7 JUNE 2009', 'PLACE');
  INSERT INTO ACCOUNT VALUES (5, 'BBC', 'JANE, WALLACE, 12354, 74.00, 17 JAN 2009', ' PLACED');
  INSERT INTO ACCOUNT VALUES (NULL, 'BBC', 'ROSY, BETH', 12355, 124.00, 21 MAR 2009', 'PLACE');
  INSERT INTO ACCOUNT VALUES (NULL, 'STAR', 'TINA, WZWICK', 22330, 89.00, 31 DEC 2008', 'PLACED');
  INSERT INTO ACCOUNT VALUES (NULL, 'STAR', 'YANA, KORVIN', 27351, 22.00, 26 OCT 2008', 'PLACED');
  INSERT INTO ACCOUNT VALUES (NULL, 'STAR', 'SARA, YUI', 22352, 443.00, 7 JUNE 2009', 'PLACE');
  INSERT INTO ACCOUNT VALUES (NULL, 'STAR', 'MIKE, TROY, 22453, 74.00, 17 JAN 2009', ' PLACED');
  
  COMMIT;
  {code}
  
  Required result:
  {code}
  APP_DT GA_CD AGNT_NAME STATE BOITE_ FUND_ ACCT_ INDICATOR
  AMT NUM GRP_ID
  1 SAMANTHA, JOSE PLACE 12347 201.27 BBC 13/02/2009 no show
  1 SAMANTHA, JOSE PLACE 12346 331.13 BBC 24/04/2009 no show
  1 SAMANTHA, JOSE PLACE 12345 234.33 BBC 08/02/2008 no show
  MD2 BBC BRAND, ROSS CLOSED 12350 11 6/27/2009 see the
  MD2 BBC BRAND, ROSS PLACED 12349 121 6/25/2009 see the
  2 BRAND of BBC, ROSS PLACE 12348 98.12 show of 31/05/2009
  3 BBC RAJ MALIK not PLACED 12352 22 10/26/2008 no show
  3 BBC RAJ MALIK not PLACED 12351 89 12/31/2008 no show
  4 BBC SHANE, WILLS PLACE 12353 443 6/7/2009 see the
  5 BBC JANE, WALLACE PLACE 12354 74 1/17/2009 see the
  STARS of MIKE, TROY PLACED 22453 74 1/17/2009 see the
  See the BBC ROSE, BETH PLACED 12355 124 3/21/2009
  STAR SARA, YUI PLACED 22352 443 6/7/2009 see the
  TINA, WZWICK STAR PLACED 22330 89 12/31/2008 see the
  YANA STAR, KORVIN PLACED 27351 22 10/26/2008 see the
  {code}
  
  As in the results Group 1 has a record with the date of 2008 for the whole group getting 'No Show'. Group 2 has all the records this year, so he gets the 'Show '.
  Help, please!
  
  Published by: Kuul13 on June 25, 2009 13:31
  
  Published by: Kuul13 on June 25, 2009 13:43
  I think I'm really having a BAD BAD day... Sorry again... I don't need the domain TOT_FUND_AMT...

  Hello

  Thanks for posting the DDL and DML statements. This helps a lot.

  I don't understand the output, however. Do you want to really two rows of output for each row in the table? The tot_fund_amt is copied from somewhere else? More important still, the results do not include the new flag column. Isn't the point of all of this question? It's good to describe how the indicator is calculated, but you have to show, too.

  I think you want analytical MIN function to find the first app_dt in each group, like this:

  SELECT  a.*
  ,     CASE
            WHEN  ga_cd = 'BBC'
            AND   MIN (app_dt) OVER ( PARTITION BY  ga_cd
                                        ,              acct_grp_id
                                      )  < TRUNC (SYSDATE, 'YYYY')
                  THEN  'No Show'
                  ELSE  'Show'
       END     AS flag
  FROM     accounts   a
  ;
  

  Output:

  . ACCT
    _GRP GA                     CASE     FUND
     _ID _CD  AGNT_NAME         _NUM     _AMT APP_DT     STATUS FLAG
  ------ ---- --------------- ------ -------- ---------- ------ -------
       1 BBC  SAMANTHA, JOSE   12345   234.33 08/02/2008 PLACED No Show
       1 BBC  SAMANTHA, JOSE   12346   331.13 04/24/2009 PLACED No Show
       1 BBC  SAMANTHA, JOSE   12347   201.27 02/13/2009 PLACED No Show
       2 BBC  MARK, ROSS       12348    98.12 05/31/2009 PLACED Show
       2 BBC  MARK, ROSS       12349   121.00 06/25/2009 PLACED Show
       2 BBC  MARK, ROSS       12350    11.00 06/27/2009 CLOSED Show
       3 BBC  RAJ, MALIK       12351    89.00 12/31/2008 PLACED No Show
       3 BBC  RAJ, MALIK       12352    22.00 10/26/2008 PLACED No Show
       4 BBC  SHANE, WILLS     12353   443.00 06/07/2009 PLACED Show
       5 BBC  JANE, WALLACE    12354    74.00 01/17/2009 PLACED Show
         BBC  ROSY, BETH       12355   124.00 03/21/2009 PLACED Show
         STAR TINA, WZWICK     22330    89.00 12/31/2008 PLACED Show
         STAR SARA, YUI        22352   443.00 06/07/2009 PLACED Show
         STAR MIKE, TROY       22453    74.00 01/17/2009 PLACED Show
         STAR YANA, KORVIN     27351    22.00 10/26/2008 PLACED Show
  

  Note that the NULL acct_grp_id is a group. PARTITION BY acct_grp_id is of course necessary, but we must also, PARTITION BY ga_cd all non-BBC lines will be included in this group. In other words, we are unwilling reported as 'No Show', all ROSY just because TINA or JANA had an early app_dt.

• ORA-01839: invalid date for the specified month

  Hello
  
  I don't know if this is the right place for posting this... but I got the following errors in my alert log file (10.2.0.1)
  
  Errors in the fichier.../bdump/xxx_j000_23928.trc
  ORA-12012: error on auto work 8888
  ORA-01839: invalid date for the specified month
  
  in the trace file:
  NAME OF THE ACTION: (AUTO_SPACE_ADVISORY_JOB) 2009-03-30 22:00:02.313
  NAME OF THE MODULE: (DBMS_SCHEDULER) 2009-03-30 22:00:02.313
  SERVICE NAME: (SYS$ USERS) 2009-03-30 22:00:02.313
  ID OF THE SESSION: (194,87) 2009-03-30 22:00:02.313
  2009-03-30 22:00:02.313
  ORA-12012: error on auto work 8888
  ORA-01839: invalid date for the specified month
  
  The problem is the date is not valid for the specified month, my question is how do I solve this problem. This is a newly created database.
  
  I have only 2 jobs (some from dba_jobs) and there is no 8888.
  
  2 jobs I have are:
  
  THE WORK INTERVAL WHICH
  1 + 1/240 sysdate unlock;
  trunc (sysdate) 2 + 7 + 3/24 dbms_stats.gather_schema_stats ('db_name');
  
  
  Please help. Thank you.
  
  Published by: user10427867 on March 31, 2009 12:00

  The work is probably assigned a group of windows, probably MAINTENANCE_WINDOW_GROUP. The task will run in this window. Try these queries.

  select schedule_name
  from dba_scheduler_jobs
  where job_name = 'AUTO_SPACE_ADVISOR_JOB';
  
  select next_start_date
  from dba_scheduler_window_groups
  where window_group_name = 'MAINTENANCE_WINDOW_GROUP';  -- or the value returned by the first query if different
  

  Since it is a work of Oracle supplied, I recommend you contact Oracle support. The trace file contains other useful information?

• Drive error 'invalid' value for registry when opening PDF files.

  Original title: Hi,.

  I use windows 8 pro.

  When I try to open the PDF files.

  Drive does not work. That is, the invalid value for registry.

  Any suggestions?

  From the desk of
  Press the Windows key + R
  Type WSReset.exe and press OK

  http://Windows.Microsoft.com/en-us/Windows-8/what-troubleshoot-problems-app

  Method 3:

  
  You can try to run Apps Troubleshooter

  Download and run the troubleshooter modern UI App and check.

  http://download.Microsoft.com/download/F/2/4/F24D0C03-4181-4E5B-A23B-5C3A6B5974E3/apps.diagcab

  Please use the following links as reference:

  http://Windows.Microsoft.com/en-us/Windows-8/what-troubleshoot-problems-app

• Problem with the Radio Group

  Apex 4.2

  Theme 21

  Firefox

  I created my group of radio as follows

  

  

  My LOV only has values of Y and N, but on my page, the radio group is displayed as

  

  I expected to see all three in a line

  Gus

  fac586 wrote:

  Workarounds would be to include the option zero in the definition of LOV, or use a dynamic action of jQuery to move the first cell of the second row and delete the first.

  A circumvention of jQuery to change the layout of the radio group table is:

  $('fieldset#P3_X tbody tr:first-child td')
    .prependTo('fieldset#P3_X tbody tr:last-child')
    .parent()
    .prev()
    .remove();
  

  where P3_X is the name of the group element.

• Is there a default value for the color management in PSE10? Beautiful photos from iPhoto, but blur with elements. I need help with this before as I consider that the upgrade to PSE13 and beyond.

  Is there a default value for the color management in PSE10? Beautiful photos from iPhoto, but blur with elements. I need help with this before as I consider that the upgrade to PSE13 and beyond.

  Printing which forms an angle seems ok, but one that is horizontally seems faded, incomplete.

  I was wondering if I saved a layer somewhere and set it as a default value.

  If you group the layers, you will be left with a single layer, thus spreading your concern.

  Suggest that you do the following:

  1. Make sure you have the latest drivers for your printers
  2. Reset the default preferences.

  Hold the Alt, Ctrl + Shift keys when you click the icon to open the items. When asked if you want to delete the settings file, say Yes.

  Items nearby and let regenerate the file.

• Multiple values for the same column in the columns of diffétent in the same row?

  Hi all
  I wonder how you can display different values for the same column in different columns on the same line. For example, using a CASE statement, I can:
  
  CASE WHEN CODE IN ('1 ', ' 3') THEN COUNT (ID) AS 'Y '.
  CASE WHEN CODE NOT IN ('1 ', am') THEN COUNT (ID) AS "N".
  
  Yes, that will produce two columns but will produce null values to empty and also two separate registers.
  
  
  Any ideas?
  
  Thank you

  Are you sure that this code works for you?

  Select ID
           ,CASE WHEN MODE_CODE IN ('1', '3') THEN COUNT( No) END as "Fulltime"
           ,CASE WHEN MODE_CODE NOT IN ('1', '3') THEN COUNT( No ) END  as "Other"
  From table
  group by ID
  

  I guess the code above fails because MODE_CODE is not in your group by?

  My suggestion would be to put the CASE in the COUNT:

  Select ID
           ,COUNT(CASE WHEN MODE_CODE IN ('1', '3') THEN No END) as "Fulltime"
           ,COUNT(CASE WHEN MODE_CODE NOT IN ('1', '3') THEN No END)  as "Other"
  From table
  group by ID
  

  CASE expressions return no. when the respective conditions are true and NULL otherwise.
  COUNTY will have non-null values.