Full table on the right outer join scan

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• He had to know the right outer join using...

  He had to know the right outer join using...

  For example: first query left outer join for the emp table: SELECT EMPNO, ENAME, D.DEPTNO FROM EMP E, Department D WHERE the E.DEPTNO = D.DEPTNO)

  Second query left outer join for the Dept table: SELECT EMPNO, ENAME, D.DEPTNO FROM EMP E, Department D WHERE the D.DEPTNO = E.DEPTNO)

  In the example above I just Exchange where condition condition to get an outer join of two table with a left outer join itself. Wat is use right outer join, instead, I can swap the status of table name for the result. Please suggest...

  Hello

  chan001 wrote:

  He had to know the right outer join using...

  For example: first query left outer join for the emp table: SELECT EMPNO, ENAME, D.DEPTNO FROM EMP E, Department D WHERE the E.DEPTNO = D.DEPTNO)

  Second query left outer join for the Dept table: SELECT EMPNO, ENAME, D.DEPTNO FROM EMP E, Department D WHERE the D.DEPTNO = E.DEPTNO)

  In the example above I just Exchange where condition condition to get an outer join of two table with a left outer join itself. Wat is use right outer join, instead, I can swap the status of table name for the result. Please suggest...

  The two examples above use the old syntax outer join of Oracle. (I guess there should be a sign inside the parentheses, e.g.. +)

  ...  WHERE E.DEPTNO = D.DEPTNO (+)

  )

  The LEFT OUTER JOIN and RIGHT OUTER JOIN terms apply only to the ANSI join syntax, e. g.

  .

  .. FROM EMP E

  DEPT LEFT OUTER JOIN D ON E.DEPTNO = D.DEPTNO

  As Blushadow said above, there's no real point in having LEFT OUTER JOIN and RIGHT OUTER JOIN;  What you can do with one (or a combination of both) can be done with the other.  Most people use LEFT OUTER JOIN systematically and never use RIGHT OUTER JOIN.

  There are situations where using a combination of the two would mean a little less striking, but only a little less and this kind of situation is very common, and one may wonder if the somewhat shorter code is more specific.  I suggest that forget you RIGHT OUTER JOIN.

• Right outer join

  There are four tables:
  
  Family
  Parent
  Child
  Grandchild
  
  Ideally, they have all documents, such as
  
  F1 - P1 - C1 - G1
  F2 - P2 - C2 - G2
  F3 - P3 - C3 - G3
  
  But sometimes,.
  
  F1 - P1 - C1 - null
  F2 - P2 - null - null
  F3 - P3 - null - null
  
  For the case of the latter, maybe I need to right outer join. If it's between two tables, the right outer join is easier. But among the four tables, inner family join parent, child of the outer join, then the big kid outer join. Maybe even this has been done? If an outer join in this case is not relevant, what other options are available?
  
  
  Thank you
  
  (ORACLE 11.2)

  Hello

  As Salomon, said

  FROM  p  LEFT  OUTER JOIN c
  

  means exactly the same thing that

  FROM  c  RIGHT OUTER JOIN p
  

  Everything you do with LEFT OUTER JOIN you could also do with RIGHT OUTER JOIN, and vice versa. If either one did not exist, you may do whatever you want with the other. In practice, it's just what's happening: most of the people always use LEFT OUTER JOIN and never use a RIGHT OUTER JOIN.

  You can have a series of outer joins cascading. If I understand your problem, a particular family may or may not have parents that belongs to him. If there are relatives, then you want to show the family with his parents to realteaed, but if there are no parents, so you want to show the family anyway. Similarly, you want to show parents whether or not they have children, and the children or not all my grandchildren are related to them. In general, which is written like this:

  ...
  FROM           family          f
  LEFT OUTER JOIN      parent          p    ON  p.family_id  = f.family_id
  LEFT OUTER JOIN      child          c    ON  c.parent_id  = p.parent_id
  LEFT OUTER JOIN      grandchild  g       ON  g.child_id   = c.child_id
  

  You can have a situation where (for example) a child is related to a family, but the child has no parent? In this case, you can still use LEFT OUTER JOIN, but join conditions would be different.

• left and right outer join

  Hi gurus,

  Left outer join:

  -------------------

  Select * from A LEFT OUTER JOIN B on A.col = B.col;

  by definition, a left outer join brings the rows that match the join condition and lines not corresponding to table A.

  My question here is "corresponding to B and no matching rows in A" is that nothing, but... SELECT * FROM A;

  can someone pls clarity...

  Thank you.

  Imagine that you had:

  TableA

  COLUMN1 COLUMN2

  'A'                1

  'B'                2

  'C'                3

  TABLEB

  COLUMN1 COLUMN2

  'A'                 'X1'

  'A'                 'X2'

  'B'                 'Y'

  'D'                 'Z'

  SELECT * FROM TABLEA;

  A 1

  B 2

  C 3

  Now, if you want to join (first column is either in table A or B, (deuxieme from tableA, third table B)

  SELECT * FROM TABLEA A JOIN TABLEB B ON (A.COLUMN1 = B.COLUMN1)

  A 1 X 1

  A 1 X 2

  B 2 Y

  SELECT * FROM TABLE LEFT B EXTERNAL ON (A.COLUMN1 = B.COLUMN1) JOIN TABLE

  A 1 X 1

  A 1 X 2

  B 2 Y

  C 3 {null}

  SELECT * FROM TABLE A TABLE RIGHT OUTER JOIN B (A.COLUMN1 = B.COLUMN1)

  A 1 X 1

  A 1 X 2

  B 2 Y

  D {null} Z

  SELECT * FROM TABLE A TABLE FULL OUTER JOIN B (A.COLUMN1 = B.COLUMN1)

  A 1 X 1

  A 1 X 2

  B 2 Y

  C 3 {null}

  D {null} Z

  HTH

• Difference between Inner join and right outer join...

  Which is precisely the difference between an Inner join and right outer join...

  JOIN INTERNAL:-to return all rows from the two tables where there is a football game. That is to say. the table resulting from all the rows and columns will have values.

  AND

  RIGHT OUTER JOIN:-Returns all rows in the second table, even if there is no match in the first table.

• Reg: Diff between Right Join and Right Outer Join

  Dear all,

  Kindly help me to find the difference between the two queries below where the results are the same.

  SELECT * FROM emp RIGHT JOIN dept WE emp.deptno = dept.deptno;

  
  SELECT * FROM emp RIGHT OUTER JOIN dept WE emp.deptno = dept.deptno;

  Thank you

  Both are same

• Looking for right outer join help

  Hello

  Can anyone help me re - write the query using right below outer join (join ansi) instead of using the (+) symbol.

  Select cd.sku_id waitm,

  Decode (cl.invn_lock_code, NULL, 'OH', cl.invn_lock_code) WLOCN,

  Sum (CD.actl_qty) WQOH

  cd, a.case_lock cl, a.case_hdr ch, a.item_master im a.case_dtl

  where cd.case_nbr = ch.case_nbr

  and cl.case_nbr (+) = ch.case_nbr

  and cd.sku_id = im.sku_id

  and ch.stat_code < = '64'

  Cd.sku_id group,

  IM.sku_brcd,

  Decode (cl.invn_lock_code, NULL, 'OH', cl.invn_lock_code)

  order of cd.sku_id

  Kind regards

  Gannu

  Maybe something like this:

  of a.case_dtl cd

  Join a.case_hdr ch on (cd.case_nbr = ch.case_nbr)

  Join a.item_master im on (cd.sku_id = im.sku_id)

  join a.case_lock cl left (cl.case_nbr = ch.case_nbr)

  where ch.stat_code<=>

  I know you asked for right outer join, but I tend to write like that.  You can certainly change if you wish.

• Get the error invalid identifier in the left outer join

  I wrote a query and get the invalid identifier error during execution:
  the exact error is: ORA-00904: "D". "" ACCT_NO ": invalid identifier
  This query is not able to access the parent table alias in the subquery of the left outer join.
  
  This is the query:
  SELECT D.PROD_DESC_TX, BASE. ASSET_NUM, BASE. PROD_ID, BASE.NAME
  OF TABLE1 D
  LEFT OUTER JOIN
  (
  SELECT ASSET_NUM, PROD_ID, B.SID
  FROM TABLE2 E
  JOIN IN-HOUSE TABLE3 HAS IT E.PROD_ID = A.ROW_ID
  JOIN INTERNAL TABLE 4 C ON A.PAR_PROD_INT_ID = C.ROW_ID
  INTERNAL TABLE5 JOIN B ON C.ROW_ID = B.PAR_ROW_ID
  AND B.TYPE = 'VALUE '.
  AND B.NAME = 'VALUE '.
  WHERE E.ASSET_NUM = ((CASE WHEN LTRIM (RTRIM (D.BANK_NO)) = '021 ' THEN '021' ELSE ' 020' END) |) LTRIM (RTRIM (D.APPL_CD)). LTRIM (RTRIM (D.ACCT_NO)))
  ) BASE ON ((CASE WHEN LTRIM (RTRIM (D.BANK_NO)) = '021 ' THEN '021' ELSE ' 020' END) |) LTRIM (RTRIM (D.APPL_CD)). LTRIM (RTRIM (D.ACCT_NO))) = BASE. ASSET_NUM
  WHERE D.BANK_NO = 'VALUE '.
  AND D.APPL_CD = 'VALUE '.
  AND D.ACCT_NO = 'VALUE '.
  
  Edited by: user648525 13 Sep, 2011 01:21

  I can easily look at your request at this time (using my iPhone on a train).

  But trying out this line in the WHERE (the one with the invalid reference) clause in the main query.

  Who is... in the view of inline, use only the logic of the join (the clauses).

  Overflow the filtering logic (WHERE clause) to the main request. You may need to select some additional inline view columns to make these references work.

• Motorcycle deny non-American owners the right to join the PNM

  Like other owners of non-us I HAV been denied the right to join the feedback of Motorola (MFN) network.

  This confirms the thought racist and discriminating motorcycle against the owners other than the United States.

  
  

• left outer join and the where clause for the table to the right

  I want to join two tables a and b, where a is a must and b is a result set in option. When I use a left outer join to a to b, I want to achieve:
  
  1. Select a single column, two columns of b (not the join columns)
  2 - even if theres no friendly on the join column does not return data from one.
  3. If there is a match applies when the criteria on column b (table in option)
  
  so, how can I avoid no_data_found in this case? When I apply where criteria for b, so it does not return the data from one, which is a must.

  Sounds like a regular outer join to me...

  select a.col1, b.col2, b.col2
  from   tableA a
         left outer join tableB b
         on (a.id = b.id and b.colX = 'X')
  

• Modeling of the left outer join

  Hello world

  I'm tender hand to you guys for a modeling help

  I have a FACT, the customers, the Dim_Date and CUST_ADDRESS of tables to model

  Fact and the client are joined through CUST_ID

  FACT and DATE are joined through DATE_ID

  CUST_ADDRESS must be attached to the top of the model through CUST_ID, DATE_ID and this join must be Left outer because sometimes the address does not exist or is not current, which means DATE_ID could be different between Dim_Date and CUST_ADDRESS

  If it were to join internal, model would have been easy, because of the outside left that I am unable to model, it's pretty good.

  Application under
  Select D.DATE, C.CUST_NAME, CA. ADDRESS, F.AMOUNT
  Of
  F FACT
  JOIN THE
  CUSTOMER C
  ON C.CUST_ID = F.CUST_ID
  JOIN THE
  DIM_DATE D
  ON F.DATE_ID = D.DATE_ID
  LEFT OUTER JOIN
  CUST_ADDRESS CA
  ON C.CUST_ID = CA. CUST_ID AND C.DATE_ID = D.DATE_ID

  Thanks in advance

  When I add the CUSTOMER and in FACT LTS CUST_ADDRESS

  Stop it!

  Don't add CUSTOMER and CUST_ADDRESS in the FACT of LTS. Why would add you to the LTS DO?

  You design a management model: CUSTOMER is a dimension and it has its own logical table this logic table join with a logical join in the activity diagram. Ditto for CUST_ADDRESS.

  So the change, I missed earlier is CUST_ADDRESS contains no Cust_ID (ACTUALLY existing), but contains a Cust_NO, and the table to translate Cust_NO in Cust_ID is CUSTOMER?

  No problem...

  Let's start with a new alias of CUSTOMER (to keep more simple to understand at the moment), call as you want, but this new alias will be the link between the FACT and CUST_ADDRESS.

  In LTS of the dimension 'Address', you have CUST_ADDRESS initially, add an inner join on the new alias that you created in the LTS of the CUSTOMER. So now your 'Address' logical dimension contains the Cust_NO and Cust_ID and this will make the join to FACT.

  Between CUST_ADDRESS and the CLIENT, you can keep an inner join, because the target is not not for get the address of the customer, but is having the Cust_ID in the address line.

  Give it a try at that.

  But do not add these tables in the LTS, they are logical dimensions.

• Comparing the same outer join column.

  Hello
  
  I have the following query.
  

  SELECT Replens.Date1               AS date1,
    Replens.USER_ID                  AS Operator1,
    Picks.USER_ID                    AS Operator1,
    Users.Time                       AS Logged_in_hours,
    Replens.Quantity                 AS Pallet_replened,
    SUM(Replens.Quantity/Users.Time) AS Replen_rate,
    Picks.Quantity                   AS Cases_picked,
    SUM(Picks.Quantity/Users.Time)   AS Pick_rate
  FROM
    (SELECT libclientreports.getshift(itl.dstamp) Date1,
      ITL.USER_ID,
      COUNT(ITL.tag_id) Quantity
    FROM INVENTORY_TRANSACTION ITL
    WHERE ITL.code                                     = 'Replenish'
    AND TO_CHAR(itl.dstamp, 'DD-Mon-YYYY HH24:MI:SS') >= '01-Mar-2010 06:00:00'
    AND TO_CHAR(itl.dstamp, 'DD-Mon-YYYY HH24:MI:SS') <= '01-Mar-2010 18:00:00'
    GROUP BY libclientreports.getshift(itl.dstamp),
      ITL.USER_ID
    ORDER BY ITL.USER_ID,
      libclientreports.getshift(itl.dstamp)
    ) Replens,
    (SELECT libclientreports.getshift(itl.dstamp) Date1,
      ITL.USER_ID,
      SUM(ITL.update_qty) Quantity
    FROM INVENTORY_TRANSACTION ITL
    WHERE ITL.to_loc_id                                = 'CONTAINER'
    AND TO_CHAR(itl.dstamp, 'DD-Mon-YYYY HH24:MI:SS') >= '01-Mar-2010 06:00:00'
    AND TO_CHAR(itl.dstamp, 'DD-Mon-YYYY HH24:MI:SS') <= '01-Mar-2010 18:00:00'
    GROUP BY libclientreports.getshift(itl.dstamp),
      ITL.USER_ID
    ORDER BY ITL.USER_ID,
      libclientreports.getshift(itl.dstamp)
    ) Picks,
    (SELECT USER_ID,
      SUM(LibClientReports.getLoggedInHours (USER_ID, to_date('01-Mar-2010 06:00:00', 'DD-Mon-YYYY HH24:MI:SS'), to_date('01-Mar-2010 18:00:00', 'DD-Mon-YYYY HH24:MI:SS')) )/60 TIME
    FROM APPLICATION_USER
    GROUP BY USER_ID
    ) Users
  WHERE Users.Time != '0'
  AND Users.USER_ID = Picks.USER_ID (+)
  AND Users.USER_ID = Replens.USER_ID (+)
  GROUP BY Replens.Date1,
    Replens.USER_ID,
    Picks.USER_ID,
    Users.Time,
    Picks.Quantity,
    Replens.Quantity
  ORDER BY Replens.USER_ID,
    Replens.Date1

  The problem I have is with the operator1 columns, I've done outer joins on the Users table that contains all users that will be returned in the tables of the peaks and Replens.
  However, I want to merge this operator1 into one column. For example, here is the current data, I have for the two columns of the operator 1;
  

  Operator1       Operator1_1
  
  D9AGY19             D9AGY19
  D9BEELB             D9BEELB
  D9FULOPS     (null)
  D9GAWKOWA     D9GAWKOWA
  D9LIDDING     D9LIDDING
  D9NOWAKS     D9NOWAKS
  (null)             D9AGY10
  (null)             D9AGY13
  (null)             D9AGY15
  (null)             D9AGY17

  And here is the data I want to see;
  

  Operator1
  
  D9AGY19
  D9BEELB
  D9FULOPS
  D9GAWKOWA
  D9LIDDING
  D9NOWAKS
  D9AGY10
  D9AGY13
  D9AGY15
  D9AGY17

  Notice the USER_ID to replace the values (null).
  
  Could someone please explain to me how to make this happen? If you want more information please let me know.
  
  
  Kind regards
  
  SM.

  This should do if Op1 and Op1_1 are always the same or one or the other is null. If both are filled and have different values, then it will not work:

  nvl(Replens.USER_ID, Picks.User_ID) as                  AS Operator1
  

• Take ownership and Grant full control to the "Right click" Admin options appearing suddenly

  Nice day

  My organization has experienced a weird event from last week. Some of our remote workstations in our stores have begun to have the options of 'Take Ownership' and 'Admin 'total control' Grant become available when a click with the right button on files and folders on these workstations. Neither myself, nor the other employee IT made no changes to these machines in question. No new parameters, no new software, they are the Point of sale and are generally left alone. I did some research and can't find anything that may have caused this intentionally. Of course, our concern is the security of these machines, and whether or not they have been compromised. Analysis of the nature report various nothing. I saw that a registery cvhange can remove it, but I still need the source of change.

  Get help maybe why this has happened to a few workstations would be very appreciated. I'm sorry if this question has been asked and more if its been answered. I spent some time digging around and can't find an answer. Thank you for your time and consideration in this matter. And do not hesitate to ask questions. They are WIndows 7 Pro machines with the latest updates.

  Thank you

  Hello

  
  Thank you for visiting Microsoft Community.

  I suggest you to post your query on our TechNet Forums social as this question right here.

  Please refer to the reference to the link below to send your request:
  https://social.technet.Microsoft.com/forums/Windows/en-us/home?category=w7itpro

  
  Hope this information helps.

  Thank you.

  Sincerely,
  Ankit Rajput

• How can I change the table in the right format?

  I need to change the following table to be sorted in numerical order (from right to left and from top to bottom)

  If you don't see the image of the table is as follows

  {[0,1,17,2,3,20,4,5,6,7,8,26,27,14,29,15]

  [0,9,0,10,19,0,21,11,12,13,25,0,0,28,0,30]

  [0,16,0,18,0,0,33,22,23,24,35,0,0,36,0,37]

  [0,31,0,32,0,0,0,34,0,0,0,0,0,0,0,0]} (sorry for these people in math there for formatting)...

  I need the table above are revealed as such

  {[0,1,0,2,3,0,4,5,6,7,8,0,0,0,0,0]

  [0,9,0,10,0,0,0,11,12,13,0,0,0,14,0,15]

  [0,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30]

  [0,31,0,32,0,0,33,34,0,0,35,0,0,36,0,37]}

  Does anyone have an idea what I could do in LabVIEW that can address this issue?

  Kind regards

  Mark

  
  

• How to re - sample a table at the right time?

  I have a DAQ that returns data for each layer as a vector line (table 1-D), as the sampling rate is defined by the user, so I know the dt between each data point in the table.  I take 1000 samples at 10 kHz.  However, when I draw this picture on a waveform graph, the time scale goes from 0 to 1000 (the index of the item) instead of 0 to 0.1 s (time).  I need to get this dt incorporated into data, so when I draw it appears correctly, vs time and so I can perform an FFT to obtain the frequency content.

  Use the waveform to transform your data waveforms.  One of the entries is Y (your data), another is dt (time/sample).  You probably don't care the T0.  You can then take the table of waveforms for the chart and the time will be there for you.