FULLT OUTER JOIN on two different selects

Similar Questions

• Diff "full outer join" is going. "(+)" SELECT syntax?

  As far as I know there are two ways to set an outer join:
  
  Select... from tab1 external t1 full join tab2 t2 on t1.id = t2.id;
  or:
  SELECT... from tab1 tab2 t2, t1 where t1.id = t2.id (+)
  
  They are absolutely equivialent?
  
  Who are the most common one?
  
  Who serve as well on other databases (DB2, MySQL)?
  
  Can I put an additional WHERE clause at the end of the first statement:
  
  SELECT... from tab1 t1 outer join t2 on t1.id = t2.id tab2 complete WHOSE...;

  Select... from tab1 external t1 full join tab2 t2 on t1.id = t2.id;

  It's FULL OUTER JOIN

  SELECT... from tab1 tab2 t2, t1 where t1.id = t2.id (+)

  It's LEFT OUTER JOIN.

  They are quite different.

  FULL OUTER JOIN - retrieves all the rows from tab1 and tab2

  LEFT OUTER JOIN - gets all the tab1 and lines than the line that matches the join condition of tab2.

  Here is a simple test.

  create table tab1(id integer)
  /
  create table tab2(id integer)
  /
  begin
    insert into tab1 values(1);
    insert into tab1 values(2);
    insert into tab1 values(3);
  end;
  /
  begin
    insert into tab2 values(3);
    insert into tab2 values(4);
    insert into tab2 values(5);
  end;
  /
  Select t1.id, t2.id
    from tab1 t1 full outer join tab2 t2
      on t1.id =t2.id
  /
  Select t1.id, t2.id
    from tab1 t1, tab2 t2
   where t1.id = t2.id(+)
  /
  

  Run it and see the result.

• He had to know the right outer join using...

  He had to know the right outer join using...

  For example: first query left outer join for the emp table: SELECT EMPNO, ENAME, D.DEPTNO FROM EMP E, Department D WHERE the E.DEPTNO = D.DEPTNO)

  Second query left outer join for the Dept table: SELECT EMPNO, ENAME, D.DEPTNO FROM EMP E, Department D WHERE the D.DEPTNO = E.DEPTNO)

  In the example above I just Exchange where condition condition to get an outer join of two table with a left outer join itself. Wat is use right outer join, instead, I can swap the status of table name for the result. Please suggest...

  Hello

  chan001 wrote:

  He had to know the right outer join using...

  For example: first query left outer join for the emp table: SELECT EMPNO, ENAME, D.DEPTNO FROM EMP E, Department D WHERE the E.DEPTNO = D.DEPTNO)

  Second query left outer join for the Dept table: SELECT EMPNO, ENAME, D.DEPTNO FROM EMP E, Department D WHERE the D.DEPTNO = E.DEPTNO)

  In the example above I just Exchange where condition condition to get an outer join of two table with a left outer join itself. Wat is use right outer join, instead, I can swap the status of table name for the result. Please suggest...

  The two examples above use the old syntax outer join of Oracle. (I guess there should be a sign inside the parentheses, e.g.. +)

  ...  WHERE E.DEPTNO = D.DEPTNO (+)

  )

  The LEFT OUTER JOIN and RIGHT OUTER JOIN terms apply only to the ANSI join syntax, e. g.

  .

  .. FROM EMP E

  DEPT LEFT OUTER JOIN D ON E.DEPTNO = D.DEPTNO

  As Blushadow said above, there's no real point in having LEFT OUTER JOIN and RIGHT OUTER JOIN;  What you can do with one (or a combination of both) can be done with the other.  Most people use LEFT OUTER JOIN systematically and never use RIGHT OUTER JOIN.

  There are situations where using a combination of the two would mean a little less striking, but only a little less and this kind of situation is very common, and one may wonder if the somewhat shorter code is more specific.  I suggest that forget you RIGHT OUTER JOIN.

• Query of queries: error when you try to fake Left Outer Join

  Hello

  I'm trying to reproduce a left outer join, combining two query of queries using a method I find here

  However, I get an error message...

  Here is the code I use...

  < cfquery dbtype = "query" name = "qry" >
  SELECT *.
  OF returnQry, returnQry2
  WHERE returnQry.mediumImage = returnQry2.mediumImage
  ORDER BY returnQry.name
  < / cfquery >
  
  < name cfquery = "returnQry3", dbtype = "#application.mx #" >
  SELECT *.
  OF trackmeanings t
  < / cfquery >

  < cfquery dbtype = "query" name = "endQry" >
  SELECT name, nameRcd, mediumImage, comments COUNT (sMessage)
  OF qry, returnQry3
  WHERE qry.name = returnQry3.sNameTrack
  
  UNION
  
  SELECT name, nameRcd, mediumImage, comments COUNT (sMessage)
  OF qry, returnQry3
  WHERE #qry.name # NOT IN (#QuotedValueList (returnQry3.sNameTrack) #)
  GROUP BY name, nameRcd, mediumImage
  < / cfquery >

  When I try to use the query output in a page, I get the error message "incorrect conditional expression, waiting for an a [as |]» null | between | in | "comparison condition.

  Anyone have any ideas?

  Thank you very much

  The items in the list should be cited.  Since you are using quotedvaluelist, it's weird that they aren't.  However, if you use cfqueryparam, list = Yes, you should have better luck.  Among other things, it will protect you against the apostrophe in names.

• [8i] need help with full outer join combined with a cross join...

  I can't understand how to combine a full outer join with a different type of join... is it possible?
  
  Here are some create table and insert for examples of database:

  CREATE TABLE     my_tab1
  (     record_id     NUMBER     NOT NULL     
  ,     workstation     VARCHAR2(4)
  ,     my_value     NUMBER
       CONSTRAINT my_tab1_pk PRIMARY KEY (record_id)
  );
  
  INSERT INTO     my_tab1
  VALUES(1,'ABCD',10);
  INSERT INTO     my_tab1
  VALUES(2,'ABCD',15);
  INSERT INTO     my_tab1
  VALUES(3,'ABCD',5);
  INSERT INTO     my_tab1
  VALUES(4,'A123',5);
  INSERT INTO     my_tab1
  VALUES(5,'A123',10);
  INSERT INTO     my_tab1
  VALUES(6,'A123',20);
  INSERT INTO     my_tab1
  VALUES(7,'????',5);
  
  
  CREATE TABLE     my_tab2
  (     workstation     VARCHAR2(4)
  ,     wkstn_name     VARCHAR2(20)
       CONSTRAINT my_tab2_pk PRIMARY KEY (workstation)
  );
  
  INSERT INTO     my_tab2
  VALUES('ABCD','WKSTN 1');
  INSERT INTO     my_tab2
  VALUES('A123','WKSTN 2');
  INSERT INTO     my_tab2
  VALUES('B456','WKSTN 3');
  
  CREATE TABLE     my_tab3
  (     my_nbr1     NUMBER
  ,     my_nbr2     NUMBER
  );
  
  INSERT INTO     my_tab3
  VALUES(1,2);
  INSERT INTO     my_tab3
  VALUES(2,3);
  INSERT INTO     my_tab3
  VALUES(3,4);

  And, the results that I want to get:

  workstation     sum(my_value)     wkstn_name     my_nbr1     my_nbr2
  ---------------------------------------------------------------
  ABCD          30          WKSTN 1          1     2
  ABCD          30          WKSTN 1          2     3
  ABCD          30          WKSTN 1          3     4
  A123          35          WKSTN 2          1     2
  A123          35          WKSTN 2          2     3
  A123          35          WKSTN 2          3     4
  B456          0          WKSTN 3          1     2
  B456          0          WKSTN 3          2     3
  B456          0          WKSTN 3          3     4
  ????          5          NULL          1     2
  ????          5          NULL          2     3
  ????          5          NULL          3     4

  I tried a number of different things, google my problem and no luck yet...

  SELECT     t1.workstation
  ,     SUM(t1.my_value)
  ,     t2.wkstn_name
  ,     t3.my_nbr1
  ,     t3.my_nbr2
  FROM     my_tab1 t1
  ,     my_tab2 t2
  ,     my_tab3 t3
  ...

  So, what I want, it's a full outer join of t1 and t2 on workstation and a cross join of one with the t3. I wonder if I can't find examples of it online because it is not possible...
  
  Note: I'm stuck dealing with Oracle 8i
  
  Thank you!!

  Hello

  The query I posted yesterday is a little more complex that it should be.
  My_tab2.workstation is unique, there is no reason to make a separate subquery as mt1. We can join my_tab1 to my_tab2 and get the SUM in a subquery.

  SELECT       foj.workstation
  ,       foj.sum_my_value
  ,       foj.wkstn_name
  ,       mt3.my_nbr1
  ,       mt3.my_nbr2
  FROM       (     -- Begin in-line view foj for full outer join
            SELECT        mt1.workstation
            ,        SUM (mt1.my_value)     AS sum_my_value
            ,        mt2.wkstn_name
            FROM        my_tab1   mt1
            ,        my_tab2   mt2
            WHERE        mt1.workstation     = mt2.workstation (+)
            GROUP BY   mt1.workstation
            ,        mt2.wkstn_name
                          --
                  UNION ALL
                          --
            SELECT      workstation
            ,      0      AS sum_my_value
            ,      wkstn_name
            FROM      my_tab2
            WHERE      workstation     NOT IN (     -- Begin NOT IN sub-query
                                             SELECT      workstation
                                     FROM      my_tab1
                                     WHERE      workstation     IS NOT NULL
                                   )     -- End NOT IN sub-query
         ) foj     -- End in-line view foj for full outer join
  ,       my_tab3  mt3
  ORDER BY  foj.wkstn_name
  ,       foj.workstation
  ,       mt3.my_nbr1
  ,       mt3.my_nbr2
  ;
  

  Thanks for posting the CREATE TABLE and INSERT statements, and very clear expected results!

  user11033437 wrote:
  ... So, what I want, it's a full outer join of t1 and t2 on workstation and a cross join of one with the t3.

  She, exactly!
  The trickiest part is when and how get SUM (my_value). You could address the question of exactly what my_tab3 must be attached to a cross that's exactly what should look like the result set of the full outer join between my_tab1 and my_tab2 to. To do this, take your desired results, remove columns that do not come from the outer join complete and delete duplicate rows. You will get:

  workstation     sum(my_value)     wkstn_name
  -----------     -------------   ----------
  ABCD          30          WKSTN 1
  A123          35          WKSTN 2
  B456          0          WKSTN 3
  ????          5          NULL          
  

  So the heart of the problem is how to get these results of my_tab1 and my_tab2, which is done in the subquery FOJ above.

  I tried to use auto-documenté in my code names. I hope you can understand.
  I could spend hours explaining the different parts of this query more in detail, but I don't know that I would lose some of that time, explain things that you already understand. If you want an explanation of the specific element (s), let me know.

• Bug in outer join syntax?

  I use Oracle 10.2, and I think I found a bug in what is allowed for the outer join syntax. Specifically, I am allowed to specify "outer join" without specifying if it's left, right, or full outer join. It behaves as an inner join.
  
  The documents show that the type_de_jointure is optional, but does not allow the 'outside' keyword be used alone: http://download.oracle.com/docs/cd/A97630_01/server.920/a96540/statements_103a.htm#2126207
  
  Small example:

  create table TABLE_A (ID number(10) primary key, VALUE_A varchar2(50));
  create table TABLE_B (ID number(10) primary key, VALUE_B varchar2(50));
  insert into TABLE_A (ID, VALUE_A) values (1, 'abc');
  insert into TABLE_A (ID, VALUE_A) values (2, 'def');
  insert into TABLE_A (ID, VALUE_A) values (3, 'ghi');
  insert into TABLE_B (ID, VALUE_B) values (2, 'jkl');
  insert into TABLE_B (ID, VALUE_B) values (3, 'mno');
  insert into TABLE_B (ID, VALUE_B) values (4, 'pqr');
  commit;
  select ID, VALUE_A from TABLE_A;
  select ID, VALUE_B from TABLE_B;
  select ID, VALUE_A, VALUE_B from TABLE_A join TABLE_B using (ID);
  select ID, VALUE_A, VALUE_B from TABLE_A full outer join TABLE_B using (ID);
  select ID, VALUE_A, VALUE_B from TABLE_A outer join TABLE_B using (ID);

  The release of the last three selects shows that the OUTER JOIN behaves as a simple JOIN, rather than return a syntax error or at least behave like a FULL OUTER JOIN (this is where the absence of a syntax error is misleading):
  

  SQL> select ID, VALUE_A, VALUE_B from TABLE_A join TABLE_B using (ID);
  
          ID VALUE_A                                            VALUE_B
  ---------- -------------------------------------------------- --------------------------------------------------
           2 def                                                jkl
           3 ghi                                                mno
  
  SQL> select ID, VALUE_A, VALUE_B from TABLE_A full outer join TABLE_B using (ID);
  
          ID VALUE_A                                            VALUE_B
  ---------- -------------------------------------------------- --------------------------------------------------
           1 abc
           2 def                                                jkl
           3 ghi                                                mno
           4                                                    pqr
  
  SQL> select ID, VALUE_A, VALUE_B from TABLE_A outer join TABLE_B using (ID);
  
          ID VALUE_A                                            VALUE_B
  ---------- -------------------------------------------------- --------------------------------------------------
           2 def                                                jkl
           3 ghi                                                mno
  
  SQL> 

  Y at - there somewhere that I can tell you that?

  If you have a supported Oracle agreement you can save a Service request with Oracle, but they can answer that this is not a bug. The problem is that the 'outside' keyword in your 3rd example is treated as an alias for TABLE_A because it is not considered as a reserved keyword.

  with table_a as (
  select 1 as id, 'abc' as value_a from dual union all
  select 2 as id, 'def' as value_a from dual union all
  select 3 as id, 'ghi' as value_a from dual
  
  )
  , table_b as (
  select 2 as id, 'jkl' as value_b from dual union all
  select 3 as id, 'mno' as value_b from dual union all
  select 4 as id, 'pqr' as value_b from dual
  )
  select ID, outer.VALUE_A, VALUE_B from TABLE_A outer join TABLE_B using (ID);
  
  ID                     VALUE_A VALUE_B
  ---------------------- ------- -------
  2                      def     jkl
  3                      ghi     mno
  

  If you query the view RESERVED_WORDS of V$ it will tell you what keywords are reserved.

  select * from V$RESERVED_WORDS where keyword in ('OUTER', 'SELECT','USING');
  
  KEYWORD                        LENGTH                 RESERVED RES_TYPE RES_ATTR RES_SEMI DUPLICATE
  ------------------------------ ---------------------- -------- -------- -------- -------- ---------
  USING                          5                      N        N        N        N        N
  OUTER                          5                      N        N        N        N        N
  SELECT                         6                      Y        N        N        N        N
  

  You'll get a similar result, if you tried

  select ID, VALUE_A, VALUE_B from TABLE_A using join TABLE_B using (ID);
  

  Kind regards
  Bob

• LEFT OUTER JOIN SYNTAX?

  Connected to:
  Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - Production 64-bit
  With partitioning, OLAP, Data Mining and Real Application Testing options
  
  When I run:
  SELECT ACCF. SPECIMEN_ID as ACC_ID,
  ACCF. PREFIX,
  ACCF. SPECIMEN_NBR as ACC_NBR,
  RP. PHYSICIAN_ID as REFPHY_BUS_KEY,
  ACCF. SIGNOUTLOC,
  THE. Location_id as LAB_BUS_KEY,
  ACCF. COLLDATE as ACC_SPCMN_COLL_DT_ID,
  ACCF. ACDATE as ACC_CREATED_DT_ID,
  ACCF. SODATEORIG as ACC_ORIG_SIGNOUT_DT_ID,
  ACCF. SODATE as ACC_SIGNOUT_DT_ID
  OF ACC_FACT_WS ACCF.
  REFPHY_WS RP,
  THE LAB_WS
  WHERE ACCF. BLINK = RP. PHYSICIAN_ID
  AND ACCF. ACDATE > to_date('2010-06-17','YYYY-MM-DD')
  AND ACCF. PREFIX = A '
  AND ACCF. SIGNOUTLOC = (LOUISIANA). LOCATION_ID
  
  It works fine, but I really have an outer join on LAB_WS.
  When I run with an outer join, I get:
  SQL > SELECT ACCF. SPECIMEN_ID as ACC_ID,
  2 ACCF. PREFIX,
  3 ACCF. SPECIMEN_NBR as ACC_NBR,
  4. PR PHYSICIAN_ID as REFPHY_BUS_KEY,
  5 ACCF. SIGNOUTLOC,
  6. THE. Location_id as LAB_BUS_KEY,
  ACCF 7. COLLDATE as ACC_SPCMN_COLL_DT_ID,
  ACCF 8. ACDATE as ACC_CREATED_DT_ID,
  ACCF 9. SODATEORIG as ACC_ORIG_SIGNOUT_DT_ID,
  ACCF 10. SODATE as ACC_SIGNOUT_DT_ID
  11 ACC_FACT_WS ACCF,
  12 REFPHY_WS RP
  13 LEFT OUTER JOIN LAB_WS ON ACCF. SIGNOUTLOC = (LOUISIANA). LOCATION_ID
  14. WHERE ACCF. BLINK = RP. PHYSICIAN_ID
  15 AND ACCF. ACDATE > to_date('2010-06-17','YYYY-MM-DD')
  16 AND ACCF. PREFIX = A ';
  LEFT OUTER JOIN LAB_WS ON ACCF. SIGNOUTLOC = (LOUISIANA). LOCATION_ID
  *
  ERROR on line 13:
  ORA-00904: "ACCF. "" SIGNOUTLOC ": invalid identifier
  
  The previous query shows ACCF. SIGNOUTLOC is not the problem.
  What is the problem and how to fix it?
  Note: the syntax of the old outer join is not an option. The query will be finally 9 outer joins.
  
  Thank you
  Jon Jacobs

  Hello

  You are mixing syntax to join Oracle with ANSI, which is sometimes delicate.
  Best is to use a unique syntax, for example ANSI:

  ...
  FROM ACC_FACT_WS ACCF
       JOIN REFPHY_WS RP ON ACCF.CLIN = RP.PHYSICIAN_ID
       LEFT OUTER JOIN LAB_WS LA on ACCF.SIGNOUTLOC = LA.LOCATION_ID
  WHERE ACCF.ACDATE > to_date('2010-06-17','YYYY-MM-DD')
  AND ACCF.PREFIX = 'D'
  

• Left join between two tables using two different conditions

  I have following three tables with their data, as shown below.
  
  CREATE TABLE TIREMASTERPROCESS_TEMP
  (
  PRODUCTIONCODE TANK (12 BYTES),
  FIELDNAME CHAR (12 BYTES),
  DATACHR VARCHAR2 (60 BYTE),
  REVISIONNO TANK (3 BYTES),
  DATANUM NUMBER (9.4)
  )
  Whether the table c. and its sample data are like
  
  FIELDNAME DATACHR REVISIONNO DATANUM PRODUCTIONCODE
  AB No. Nch 1 100 0
  AB No. Nch 1 108 0
  AB No.-of-Nch 1 1 0
  Ass42 teased dishes 1 0
  Ass42 BTDrumNo1 BTD-051 1 0
  AB53 BTDrumNo1 BTD-051 104 0
  
  
  CREATE TABLE materialcode
  (
  UPPERMATERIALCODE CHAR (20),
  PROCESSNO TANK (3),
  PROCESSADOPTDATE TANK (9)
  
  )
  Whether the table b. and its sample data are like
  
  UPPERMATERIALCODE PROCESSNO PROCESSADOPTDATE
  Ass42 1 20120717
  AB53 108 20121121
  111 20111104 AS05
  104 20120928 AS30
  
  
  CREATE TABLE BUILDINGSCHEDULEMASTER
  (
  BUILDINGSIZE TANK (5 BYTES),
  GTCODE FLOAT (4 BYTES),
  TIREPERCART NUMBER (3.0).
  BUILDINGLOT NUMBER (3.0)
  )
  Whether table and its sample data are like
  
  BUILDINGSIZE GTCODE TIREPERCART BUILDINGLOT
  AB42A 4 12 ass42
  AB53A 4 88 AB53
  AS30A AS30 4 80
  BF03A 1 90 BF03
  
  
  Now, I need to get some data in these fields by using the suite of mappings.
  
  « PR_ » || Trim (a.BUILDINGSIZE) | ' / MPL2' Processid,--PRIMARY KEY
  TO_DATE (substr (NVL(b.PROCESSADOPTDATE,'19800101'), 7, 2) |) » /'|| SUBSTR (NVL(b.PROCESSADOPTDATE,'19800101'), 5, 2) | » /'|| SUBSTR (NVL(b.PROCESSADOPTDATE,'19800101'), 1, 4). (' 01:00:00 ',' dd-mm-yyyy hh24:mi:ss') starteff, to_date (SUBSTR (NVL(b.PROCESSADOPTDATE,'19800101'), 7, 2) |) » /'|| SUBSTR (NVL(b.PROCESSADOPTDATE,'19800101'), 5, 2) | » /'|| SUBSTR (NVL(b.PROCESSADOPTDATE,'19800101'), 1, 4). (' 01:00:00 ',' dd-mm-yyyy hh24:mi:ss') startDate.
  b.PROCESSNO revisioncodeid,
  a.BUILDINGLOT tirepercart ,
  CASE WHEN c.FIELDNAME = 'BTDrumNo1' then c.DATACHR end drumtype1.
  BOX WHEN (trim (C.DATACHR) = '1' and trim (C.FIELDNAME) = "No. Nch") and THEN click 'YES '.
  ANOTHER 'NO '.
  END may-BUG,
  case
  When c.FIELDNAME = 'Wavy'
  AND c.DATACHR = 'Use' THEN on 'YES '.
  When c.FIELDNAME = 'Wavy'
  AND c.DATACHR <>'Use' THEN 'NO '.
  fine wavy
  
  
  Now for the tables A and B I have the simple join as condition
  
  a.GTCODE = b.UPPERMATERIALCODE
  
  But I have to use two different left join conditions to join the table B and C to calculate the RESP fields according to the condition.
  Now, I have to use
  
  (trim (b.UPPERMATERIALCODE)). » -'|| Trim (b.PROCESSNO) = Trim (c.PRODUCTIONCODE) | » -'|| Trim (c.REVISIONNO)
  
  condition to get the data for the WAVY and DRUMTYPE1 fields.
  
  But at the same time, I have to use
  
  substr (Trim (b.UPPERMATERIALCODE), 1, 2). » -'|| Trim (b.PROCESSNO) = Trim (c.PRODUCTIONCODE) | » -'|| Trim (c.REVISIONNO)
  
  conition to derive the CHAFER field.
  
  And for this reason I am come so many duplicates and do not correct results for JUNEBUG, WAVY, DRUMTYPE1, and STARTDATE field.
  
  I need some advice as how can I do so that I get the correct results without duplicates for the PRIMARY KEY.
  
  Thank you
  
  Mahesh

  It would have been easier to answer if you gave us your example query that gives incorrect results - which both show us what you are doing and give us a starting point.
  Insert instructions for data, rather than only the data would have helped too, making it more quick to test this point.
  You do not show what you have done with your two outer join criteria, but I think you need to list TIREMASTERPROCESS_TEMP in your query twice, with alias names. Here's what I did:

  select a.BUILDINGSIZE, a.GTCODE, b.PROCESSNO ,  c1.FIELDNAME, c1.DATACHR, C2.FIELDNAME, C2.DATACHR
  , CASE WHEN c1.FIELDNAME='BTDrumNo1' then c1.DATACHR end drumtype1
  , CASE WHEN (trim(c2.DATACHR) = '1' and trim(c2.FIELDNAME) = 'No-of-Nch') THEN 'YES' ELSE 'NO' END CHAFER
  , case when c1.FIELDNAME='Wavy' AND c1.DATACHR='Use' THEN 'YES'
         when c1.FIELDNAME='Wavy' then 'NO' else null end wavy
  from BUILDINGSCHEDULEMASTER        A
  join materialcode b on a.GTCODE=b.UPPERMATERIALCODE
  left outer join TIREMASTERPROCESS_TEMP c1
     ON trim(b.UPPERMATERIALCODE)||'-'||trim(b.PROCESSNO) = trim(c1.PRODUCTIONCODE)||'-'||trim(c1.REVISIONNO)
  left outer join TIREMASTERPROCESS_TEMP c2
     ON substr(trim(b.UPPERMATERIALCODE),1,2)||'-'||trim(b.PROCESSNO) = trim(c2.PRODUCTIONCODE)||'-'||trim(c2.REVISIONNO)
  

  C1 is an alias for the TIREMASTERPROCESS_TEMP line which is necessary for drumtype1 and wavy, c2 is an alias for the TIREMASTERPROCESS_TEMP line required for JuneBug. There was some minor errors in your calculations of field I tried to correct.

  The results are:

  BUILD GTCO PRO FIELDNAME    DATACHR    FIELDNAME    DATACHR    DRUMTYPE1  CHA WAV
  ----- ---- --- ------------ ---------- ------------ ---------- ---------- --- ---
  AB53A AB53 108                         No-of-Nch    1                     YES
  AB42A AB42 1   BTDrumNo1    BTD-051    No-of-Nch    1          BTD-051    YES
  AB42A AB42 1   Wavy         NotUse     No-of-Nch    1                     YES NO
  AS30A AS30 104                                                            NO
  

  Hope this helps,
  David

• using outer joins if the two column is null? Use only (+)

  Hi all

  create the table xxc_tr_num (tl_number number, tr_no number tl_no_id);

  insert into xxc_tr_num values (123,100,222);

  insert into xxc_tr_num values (124,100,333);

  create the table xxc_od_tab (tl_number number, tl_id number);

  insert into xxc_od_tab values (123,001);

  insert into xxc_od_tab values (null, null);

  create table xxc_oth_tab (name varchar2 (10), number of tl_id);

  insert into xxc_oth_tab values('abc',,001);

  insert into xxc_oth_tab values (null, null);

  Wait it out put

  tr_no tl_no_id name

  100 222 abc

  100 333

  using outer joins if the two column is null? use only please of outer joins

  And I tried to use outer joins on both tl_id column but not get values and I use have County (tr_no ) > 1

  Rajesh123 wrote:

  Thank you Kiss it is not possible to use having clause?

  You need to understand the functioning of the group. If you will not be asked this question.

  Check this box

  SQL> select tr_no,
    2         tl_no_id,
    3         count(*)
    4    from xxc_tr_num a,
    5         xxc_od_tab b,
    6         xxc_oth_tab c
    7   where a.tl_number = b.tl_number(+)
    8     and b.tl_id = c.tl_id(+)
    9   group
   10      by tr_no
   11       , tl_no_id;
  
       TR_NO   TL_NO_ID   COUNT(*)
  ---------- ---------- ----------
         100        333          1
         100        222          1
  

  See what returns the count? You have grouped according to TR_NO and TL_NO_ID. You must take into consideration the TL_NO_ID just put COUNT (TR_NO) does not increase the NUMBER of the whole group. To get the NUMBER on the whole group, I used the analytical function and did. Like this, see the number of the analytical function here

  SQL> select tr_no,
    2         tl_no_id,
    3         count(*),
    4         count(*) over(partition by tr_no)
    5    from xxc_tr_num a,
    6         xxc_od_tab b,
    7         xxc_oth_tab c
    8   where a.tl_number = b.tl_number(+)
    9     and b.tl_id = c.tl_id(+)
   10   group
   11      by tr_no
   12       , tl_no_id;
  
       TR_NO   TL_NO_ID   COUNT(*) COUNT(*)OVER(PARTITIONBYTR_NO)
  ---------- ---------- ---------- ------------------------------
         100        222          1                              2
         100        333          1                              2
  

  So to answer your question, yes you can't do in the HAVING clause...

• How can I select the first date (at least) and the corresponding date of two different tables source?

  I have 2 tables, INVOICE and INVOICE_REFNUM similar to below. I'm writing a query that withdrawing the first date (less) for a single record remaining the two tables. Each table records the receipt of invoices, but according to the source of the received invoice some may reside in INVOICE_REFNUM and others the INVOICE table. I also use DECODE on the topic of INVOICE_SOURCE, when the date less is taken from the INVOICE table that contains that field, so if the date is in the field INVOICE_REFNUM DECODE is not necessary. Example:

  INVOICE (table)

  INVOICE_GID INVOICE_SOURCE INSERT_DATE

  ABC. AVRT123 I HAVE 11/03/2012-15:49:32

  ABC. CNWY234 G 12/03/2012 14:07:30

  ABC. UPGF678 M 15/03/2012 20:21:54

  INVOICE_REFNUM (table)

  INVOICE_GID INVOICE_REFNUM_QUAL INVOICE_REFNUM_VALUE INSERT_DATE

  ABC. AVRT123 SOURCE ACS 11/03/2012 14:49:32

  ABC. CNWY234 SOURCE CSA 12/03/2012 13:07:30

  ABC. UPGF678 SOURCE ACS 15/03/2012 21:21:54

  My decode statement is: DECODE ("INVOICE_SOURCE, 'I', 'IDE', 'G', ' Auto-Pay", ', 'Manual')

  If I were to write a query on these two tables, the output will resemble the following:

  INVOICE_GID INVOICE_SOURCE INSERT_DATE

  ABC. AVRT123 ACS 11/03/2012 14:49:32

  ABC. CNWY234 ACS 12/03/2012 13:07:30

  ABC. UPGF678 Manual 15/03/2012 20:21:54

  I worked on it for 2 days, and I was able to pull a date by using the following SQL code, but cannot determine how to extract the corresponding source:

  SELECT THE LEAST (GLOGOWNER. INVOICE_REFNUM. INSERT_DATE, GLOGOWNER. THE INVOICE. INSERT_DATE) AS 'DATE OF THE INVOICE.

  GLOGOWNER. THE INVOICE. INVOICE_GID,

  DECODE (GLOGOWNER. THE INVOICE. INVOICE_SOURCE, 'I', 'IDE', 'G', 'Auto-Pay', ', 'Manual').

  GLOGOWNER. INVOICE_REFNUM. INVOICE_REFNUM_VALUE

  OF GLOGOWNER. INVOICE

  LEFT JOIN GLOGOWNER. INVOICE_REFNUM

  ON GLOGOWNER. THE INVOICE. INVOICE_GID = GLOGOWNER. INVOICE_REFNUM. INVOICE_GID

  WHERE GLOGOWNER. INVOICE_REFNUM. INVOICE_REFNUM_VALUE = "ACS."

  AND GLOGOWNER. INVOICE_REFNUM. INVOICE_REFNUM_QUAL_GID = 'SOURCE '.

  AND GLOGOWNER. THE INVOICE. INVOICE_TYPE = 'I '.

  ORDER OF GLOGOWNER. THE INVOICE. INVOICE_GID

  Any help is greatly appreciated!

  Best regards

  -Adam

  Hello

  Is that what you want?

  SELECT i.invoice_gid

  CASE

  WHEN ir.insert_date<= i.insert_date ="" then ="">

  WHEN i.invoice_souce = 'I' and THEN 'EDI '.

  WHEN i.invoice_souce = 'G' THEN 'debit '.

  WHEN i.invoice_souce = am' THEN 'manual '.

  END AS invoice_source

  , The LEAST (i.insert_date, ir.insert_date) AS insert_date

  I have the Bill OF

  JOIN invoice_refnum ON i.invoice_gid = ir.invoice_gid ir

  WHERE ir.invoice_refnum_value = 'ACS '.

  AND ir.invoice_refnum_qual_gid = 'SOURCE '.

  AND i.invoice_type = 'I '.

  ORDER BY i.invoice_gid

  ;

  There is no reason to do an outer join if you only want the lines with specific values anyway.

  What happens if the 2 tables have exactly the same invoice_date?  The query above takes the invoice_source of invoice_refnum in this case, but that can easily be changed.

  Or the other of the insert_dates can be NULL?

  I hope that answers your question.

  Otherwise, thank you post a small example data (CREATE TABLE and only relevant columns, INSERT statements) for all of the tables involved and also after the results you want from these data (otherwise what you have already posted).

  Explain, using specific examples, how you get these results from these data.

  Always say what version of Oracle you are using (for example, 11.2.0.2.0).

  See the FAQ forum: https://forums.oracle.com/message/9362002#9362002

• How do the query select outer join to a report of the APEX

  Hi all
  
  I'm Ann.
  
  I have a select statement that is used to calculate statistics for a month (October 2012 in this example)
  Select ph.phase_number
  sum ((case
  WHEN ph.date_finished IS NULL or ph.date_finished > last_day (TO_DATE (' ' Oct 2012 ', ' MY YYYY' "))
  THEN last_day (TO_DATE (' ' Oct 2012 ', ' MY YYYY' "))
  Of OTHER ph.date_finished
  END)
  (-ph.date_started + 1) / count (def.def_id) as avg_days
  Ph phase_membership
  inner join court_engagement this on ph.mpm_eng_id = ce.engagement_id
  join in-house defendant def on ce.defendant_id = def.def_id
  where def.active = 1
  and ph.date_started < = last_day (TO_DATE (' ' Oct 2012 ', ' MY YYYY' "))
  and ph.active = 1
  and UPPER (ce.court_name) LIKE '% '.
  Rollup Group (phase_number)
  ;
  
  The result is as below
  Phase_Number AVG_DAYS
  Phase One 8.6666666666666667
  Phase two 14.6
  Phase three 12
  11.4615365
  
  I have another list of selection mainly the list of months between two date value.
  Select to_char (which_month, 'LUN YYYY') as display_month
  de)
  Select add_months (to_date (' ' August 2012 ', ' MY YYYY' "), rownum-1) which_month
  of object
  where
  rownum < = months_between (to_date (' ' Oct 2012 ', ' MY YYYY' "), add_months (to_date (' ' August 2012", "MY YYYY"), - 1))
  order of which_month)
  
  The query result is as below
  
  DISPLAY_MONTH
  
  AUGUST 2012
  SEP 2012
  OCT 2012
  
  Is it possible I can join these two select statement above to generate a comparable result:
  
  Days of month Phase number Avg
  August 2012 Phase One 8.666
  Sep 2012 Phase One 7.66
  Oct 2012 Phase One 5,66
  August 2012 Phase two 8.666
  Sep 2012 Phase two 7.66
  Oct 2012 Phase two 5,66
  August 2012 Phase three 8.666
  Sep 2012 Phase three 7.66
  Oct 2012 Phase three 5,66
  
  Or
  Days of month Phase number Avg
  August 2012 Phase One 8.666
  August 2012 Phase two 7.66
  August 2012 Phase three 5,66
  Sep 2012 Phase One 8.666
  Sep 2012 Phase two 7.66
  Sep 2012 Phase three 5,66
  Oct 2012 Phase One 8.666
  Oct 2012 Phase two 7.66
  Oct 2012 Phase three 5,66
  
  And it can be controlled by Phase number or month.
  My other colleague suggested I should use a left outer join, but after having tried many ways, I'm still stuck.
  
  I tried select is
  Select a.display_month, b.* in)
  Select to_char (which_month, 'LUN YYYY') as display_month
  de)
  Select add_months (to_date (' ' August 2012 ', ' MY YYYY' "), rownum-1) which_month
  of object
  where
  rownum < = months_between (to_date (' ' Oct 2012 ', ' MY YYYY' "), add_months (to_date (' ' August 2012", "MY YYYY"), - 1))
  order which_month)) a left outer join
  
  (Select to_char (ph.date_finished, 'MY YYYY') as join_month, ph.phase_number)
  sum ((case
  WHEN ph.date_finished IS NULL or ph.date_finished > last_day (TO_DATE (a.display_month, 'MY YYYY'))
  THEN last_day (TO_DATE (a.display_month, 'MY YYYY'))
  Of OTHER ph.date_finished
  END)
  (-ph.date_started + 1) / count (def.def_id) as avg_days
  Ph phase_membership
  inner join court_engagement this on ph.mpm_eng_id = ce.engagement_id
  join in-house defendant def on ce.defendant_id = def.def_id
  where def.active = 1
  and ph.date_started < = last_day (TO_DATE (a.display_month, 'MY YYYY'))
  and ph.active = 1
  and UPPER (ce.court_name) LIKE '% '.
  To_char (ph.date_finished, 'MY YYYY'), group (phase_number) rollup) b
  On a.display_month = b.join_month
  
  but then I get an error
  SQL error: ORA-00904: "A." "" DISPLAY_MONTH ": invalid identifier
  
  I need to view a report on the APEX with option for people to download at least format CSV.
  Already 1 inteactive report in the page, so I don't think adds another interactive report without using the iframe trick.
  
  If any of you have any ideas, please help.
  
  Thank you very much.
  
  Ann

  Hello Ann,.

  Frank has done a very good job. I am also impressed.

  Is in regard to your correction to his question, the problem is on this replacement you did

  last_day(TO_DATE(am.which_month,'MON YYYY'))
  

  AM.which_month is already a date type, and you don't need to convert it to this day.
  Here is the correct way:

  last_day(am.which_month)
  

  There are also sometimes with the data you've posted have no line for this month. So I also added a function NVL to display 0 under avg_days for these cases.

  Here is my corrected query:

  DEFINE startmonth = "Aug 2012";
  DEFINE endmonth   = "Oct 2012";
  WITH  all_months  AS
  (
     SELECT ADD_MONTHS(to_date('&startmonth','MON YYYY'), ROWNUM-1) AS which_month
     ,      ADD_MONTHS(to_date('&startmonth','MON YYYY'), ROWNUM  ) AS next_month
     from all_objects
     where
     rownum <= months_between(to_date('&endmonth','MON YYYY'), add_months(to_date('&startmonth','MON YYYY'), -1))
  )
  SELECT TO_CHAR (am.which_month, 'Mon YYYY')  AS month
       , ph.phase_number
       , NVL(sum ( (CASE
                   WHEN ph.date_finished IS NULL OR ph.date_finished > last_day(am.which_month)
                   THEN last_day(am.which_month)
                   ELSE ph.date_finished
                END
               ) - ph.date_started + 1
             ) / count(def.def_id), 0) as avg_days
    FROM all_months am
         LEFT OUTER JOIN  a_phase_membership  ph  PARTITION BY (ph.phase_number)
            ON  am.which_month <= ph.date_started
            AND am.next_month  >  ph.date_started
            AND ph.date_started <= last_day(am.which_month)  -- May not be needed
            AND ph.active = 1
         LEFT OUTER JOIN  a_engagement  ce
            ON  ph.mpm_eng_id = ce.engagement_id
            AND ce.court_name IS NOT NULL  -- or something involving LIKE
         LEFT OUTER join  a_defendant     def
            ON  ce.defendant_id = def.def_id
            AND def.active = 1
   GROUP BY ROLLUP(phase_number, am.which_month)
   ORDER BY  am.which_month
          ,  ph.phase_number
  ;
  
  The output is:
  MONTH    PHASE_NUMBER           AVG_DAYS
  -------- -------------------- ----------
  Aug 2012 PHASE ONE                     0
  Aug 2012 PHASE THREE                   0
  Aug 2012 PHASE TWO                     0
  Sep 2012 PHASE ONE                    12
  Sep 2012 PHASE THREE                   1
  Sep 2012 PHASE TWO                     9
  Oct 2012 PHASE ONE                     8
  Oct 2012 PHASE THREE                   0
  Oct 2012 PHASE TWO                    14
           PHASE ONE                    11
           PHASE THREE                   1
           PHASE TWO                  11.5
                                9.71428571
  

  I don't know if that's really what you want. In the case check it and let me know.

  Kind regards.
  Al

• Join of two tables in two different schemas

  Hi all
  
  I have an obligation to join two tables on two different schemas. How to join these two tables in the object view.
  
  Thanks in advance.
  
  Concerning
  Kaushik Guillaumin

  You can do just that using schema name in the +' view object.table name ' + according to the query object and also grant select the another schema to this schema user

  ex
  you need schem is test and another Act you need to a view object based on the test to join a table on shcema Act

  you write semply object sql view code:

  Act.table name

  and you can also give him select statement on Bill schem table to test

  concerning

• Different Outer Join query result

  Hi all
  
  Under query gives the expected result
  
  
  Select DECODE (FPOVR. PROFILE_OPTION_VALUE,
  NULL, FPOVS. PROFILE_OPTION_VALUE, FPOVR. ZZ PROFILE_OPTION_VALUE)
  OPS FND_PROFILE_OPTIONS, FND_PROFILE_OPTION_VALUES FPOVR,.
  FND_PROFILE_OPTION_VALUES FPOVS where 1 = 1 and FPOVS. LEVEL_ID (+) = 10001
  and FPOVS. LEVEL_VALUE (+) = 0
  and FPOVS. PROFILE_OPTION_ID (+) IS FRENCH POLYNESIA. PROFILE_OPTION_ID
  and FPOVR. (+) LEVEL_ID = 10003 and FPOVR. LEVEL_VALUE (+) = 21533
  and FPOVR. PROFILE_OPTION_ID (+) IS FRENCH POLYNESIA. PROFILE_OPTION_ID
  and fpo.profile_option_name = 'GL_SET_OF_BKS_ID. '
  
  
  But the following query does not give the expected result.
  
  
  Select DECODE (FPOVR. PROFILE_OPTION_VALUE,
  NULL, FPOVS. PROFILE_OPTION_VALUE, FPOVR. ZZ PROFILE_OPTION_VALUE)
  OPS FND_PROFILE_OPTIONS, FND_PROFILE_OPTION_VALUES FPOVR,.
  FND_PROFILE_OPTION_VALUES FPOVS where 1 = 1 and FPOVS. LEVEL_ID (+) = 10001
  and FPOVS. LEVEL_VALUE (+) = 0
  and FPOVS. PROFILE_OPTION_ID (+) IS FRENCH POLYNESIA. PROFILE_OPTION_ID
  and FPOVR. (+) LEVEL_ID = 10003 and FPOVR. LEVEL_VALUE = 21533
  and FPOVR. PROFILE_OPTION_ID (+) IS FRENCH POLYNESIA. PROFILE_OPTION_ID
  and fpo.profile_option_name = 'GL_SET_OF_BKS_ID. '
  
  Difference between them is a join with external FPOVR. LEVEL_VALUE and hard coded value. Why these query above return different results even if the outer join is made with hard coded in value?
  
  Thank you
  SK

  SK says:
  Hi all

  Under query gives the expected result

  Select DECODE (FPOVR. PROFILE_OPTION_VALUE,
  NULL, FPOVS. PROFILE_OPTION_VALUE, FPOVR. ZZ PROFILE_OPTION_VALUE)
  OPS FND_PROFILE_OPTIONS, FND_PROFILE_OPTION_VALUES FPOVR,.
  FND_PROFILE_OPTION_VALUES FPOVS where 1 = 1 and FPOVS. LEVEL_ID (+) = 10001
  and FPOVS. LEVEL_VALUE (+) = 0
  and FPOVS. PROFILE_OPTION_ID (+) IS FRENCH POLYNESIA. PROFILE_OPTION_ID
  and FPOVR. (+) LEVEL_ID = 10003 and FPOVR. LEVEL_VALUE (+) = 21533
  and FPOVR. PROFILE_OPTION_ID (+) IS FRENCH POLYNESIA. PROFILE_OPTION_ID
  and fpo.profile_option_name = 'GL_SET_OF_BKS_ID. '

  But the following query does not give the expected result.

  Select DECODE (FPOVR. PROFILE_OPTION_VALUE,
  NULL, FPOVS. PROFILE_OPTION_VALUE, FPOVR. ZZ PROFILE_OPTION_VALUE)
  OPS FND_PROFILE_OPTIONS, FND_PROFILE_OPTION_VALUES FPOVR,.
  FND_PROFILE_OPTION_VALUES FPOVS where 1 = 1 and FPOVS. LEVEL_ID (+) = 10001
  and FPOVS. LEVEL_VALUE (+) = 0
  and FPOVS. PROFILE_OPTION_ID (+) IS FRENCH POLYNESIA. PROFILE_OPTION_ID
  and FPOVR. (+) LEVEL_ID = 10003 and FPOVR. LEVEL_VALUE = 21533
  and FPOVR. PROFILE_OPTION_ID (+) IS FRENCH POLYNESIA. PROFILE_OPTION_ID
  and fpo.profile_option_name = 'GL_SET_OF_BKS_ID. '

  Difference between them is a join with external FPOVR. LEVEL_VALUE and hard coded value.

  In fact, the difference is that the condition relating to FPOVR. LEVEL_VALUE to 21533 is part of the outer join condition in the first query, but it is not in the second query.

  Why these query above return different results even if the outer join is made with hard coded in value?

  When you say

  FPOVR.LEVEL_VALUE(+) = 21533
  

  (with a sign +) only the lines of fpovr with level_value = 21533 will join the other table. If there is no such line in fpovr, then a row of output will be generatedd for each row in the other table anyway.
  When you say

  FPOVR.LEVEL_VALUE = 21533
  

  (without a sign +) then the outer join is made using the other conditions, which may result in some lines of the other table who appear in the result set with NULL in places where the values of fpovr would normally appear. Then when the join is complete, the condition is applied, and all these lines with the NULL value instead of fpovr.level_value are deleted because they do not meet the condition "FPOVR. LEVEL_VALUE = 21533 ". The effect is identical to an inner join.

  When you use the old rating of outer join (i.e. with signs +), if any condition involving the fpovr table has a + sign, and then all of the conditions involving table fpovr must have a + sign, otherwise the result will be the same if none of the conditions were a sign +.

• outer join: difference between two queries

  Below two queries which should give the same results in my opinion. I want that all records of u_protocol and the pval.u_protocol_variable_value value if necessary.
  
  Why the outer join in query2 does not work as in query1?
  
  
  Query1:

  select p.u_protocol_id, i.u_protocol_variable_value
  from lims_sys.u_protocol p,
  (
     select pval.u_protocol_id, pval.u_protocol_variable_value
     from lims_sys.u_protocol_variable pvar, lims_sys.u_protocol_value_user pval
     where pvar.u_protocol_variable_id = pval.u_protocol_variable_id
     and pvar.name = 'VALUE_Protocol_Group'
  ) i   
  where p.u_protocol_id  = i.u_protocol_id (+)

  Query2:

  select prt.u_protocol_id, pval.u_protocol_variable_value
  from lims_sys.u_protocol prt, lims_sys.u_protocol_variable pvar, lims_sys.u_protocol_value_user pval
  where pvar.u_protocol_variable_id = pval.u_protocol_variable_id
  and prt.u_protocol_id = pval.u_protocol_id (+)
  and pvar.name = 'VALUE_Protocol_Group'

  Hello

  When you perform an outer join, all conditions on the tables in option must be outer join conditions. Otherwise, the effect is an inner join.
  There is one exception: cascade of outer joins, external-junction b of a and c is outside attached to b. In this case, in the b - c join only columns of c are marked with the sign +.

  Re - write to obtain the same results as query1, query2 like this:

  select  prt.u_protocol_id
  ,      pval.u_protocol_variable_value
  from     lims_sys.u_protocol          prt
  ,      lims_sys.u_protocol_variable     pvar
  ,      lims_sys.u_protocol_value_user pval
  where     pvar.u_protocol_variable_id (+)     = pval.u_protocol_variable_id     -- cascading outer join
  and     prt.u_protocol_id           = pval.u_protocol_id (+)
  and     pvar.name (+)               = 'VALUE_Protocol_Group'     -- (+) added
  ;
  

  I find the syntax ANSI easier to use for all the joins and much easier for outer joins.

• Problem using Extract IMAQ. Don't not out two different images

  Hi, I am using the multiple functions of extract IMAQ for some parts of the image of the webcam, then using color extracted from function to get values of RGB. The problem is that two functions extract IMAQ give the same image on its out port. The extract of diagram of block and VI are attached below. Also, please let me know if there is a better way to do this. I need to expand this later to extract parts of the image instead of two different about 40 - 50 RGB values below.

  

  It's happened because IMAQ Images transferred by references. You must provide images of different destination for each extraction:

  

  Andrey.