LEFT OUTER JOIN SYNTAX?
Connected to:Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - Production 64-bit
With partitioning, OLAP, Data Mining and Real Application Testing options
When I run:
SELECT ACCF. SPECIMEN_ID as ACC_ID,
ACCF. PREFIX,
ACCF. SPECIMEN_NBR as ACC_NBR,
RP. PHYSICIAN_ID as REFPHY_BUS_KEY,
ACCF. SIGNOUTLOC,
THE. Location_id as LAB_BUS_KEY,
ACCF. COLLDATE as ACC_SPCMN_COLL_DT_ID,
ACCF. ACDATE as ACC_CREATED_DT_ID,
ACCF. SODATEORIG as ACC_ORIG_SIGNOUT_DT_ID,
ACCF. SODATE as ACC_SIGNOUT_DT_ID
OF ACC_FACT_WS ACCF.
REFPHY_WS RP,
THE LAB_WS
WHERE ACCF. BLINK = RP. PHYSICIAN_ID
AND ACCF. ACDATE > to_date('2010-06-17','YYYY-MM-DD')
AND ACCF. PREFIX = A '
AND ACCF. SIGNOUTLOC = (LOUISIANA). LOCATION_ID
It works fine, but I really have an outer join on LAB_WS.
When I run with an outer join, I get:
SQL > SELECT ACCF. SPECIMEN_ID as ACC_ID,
2 ACCF. PREFIX,
3 ACCF. SPECIMEN_NBR as ACC_NBR,
4. PR PHYSICIAN_ID as REFPHY_BUS_KEY,
5 ACCF. SIGNOUTLOC,
6. THE. Location_id as LAB_BUS_KEY,
ACCF 7. COLLDATE as ACC_SPCMN_COLL_DT_ID,
ACCF 8. ACDATE as ACC_CREATED_DT_ID,
ACCF 9. SODATEORIG as ACC_ORIG_SIGNOUT_DT_ID,
ACCF 10. SODATE as ACC_SIGNOUT_DT_ID
11 ACC_FACT_WS ACCF,
12 REFPHY_WS RP
13 LEFT OUTER JOIN LAB_WS ON ACCF. SIGNOUTLOC = (LOUISIANA). LOCATION_ID
14. WHERE ACCF. BLINK = RP. PHYSICIAN_ID
15 AND ACCF. ACDATE > to_date('2010-06-17','YYYY-MM-DD')
16 AND ACCF. PREFIX = A ';
LEFT OUTER JOIN LAB_WS ON ACCF. SIGNOUTLOC = (LOUISIANA). LOCATION_ID
*
ERROR on line 13:
ORA-00904: "ACCF. "" SIGNOUTLOC ": invalid identifier
The previous query shows ACCF. SIGNOUTLOC is not the problem.
What is the problem and how to fix it?
Note: the syntax of the old outer join is not an option. The query will be finally 9 outer joins.
Thank you
Jon Jacobs
Hello
You are mixing syntax to join Oracle with ANSI, which is sometimes delicate.
Best is to use a unique syntax, for example ANSI:
...
FROM ACC_FACT_WS ACCF
JOIN REFPHY_WS RP ON ACCF.CLIN = RP.PHYSICIAN_ID
LEFT OUTER JOIN LAB_WS LA on ACCF.SIGNOUTLOC = LA.LOCATION_ID
WHERE ACCF.ACDATE > to_date('2010-06-17','YYYY-MM-DD')
AND ACCF.PREFIX = 'D'
Tags: Database
Similar Questions
-
Former Outer Join syntax on constants
Hello
Can someone please tell me why the below two queries are performing differently. How to join a constant by using the old syntax used.
Also, how is 3 different query of query 2?
CREATE TABLE T1 (X VARCHAR2 (10), B INTEGER);
CREATE TABLE T2 (Y VARCHAR2 (10), B INTEGER);
INSERT INTO T1 VALUES('XXX',10);
INSERT INTO T1 VALUES('XXX',10);
INSERT INTO T1 VALUES('XXX',10);
INSERT INTO T1 VALUES('YYY',20);
INSERT INTO T1 VALUES('YYY',20);
INSERT INTO T1 VALUES('YYY',20);INSERT INTO T2 VALUES('AAA',10);
INSERT INTO T2 VALUES('BBB',20);Query 1
SELECT T1.*, T2.* FROM T1 LEFT JOIN T2
ON T1. B = T2. B
AND T1. B = 20
-OUTPUT
=========
BBB YYY 20 20
BBB YYY 20 20
BBB YYY 20 20
NULL NULL 10 XXX
NULL NULL 10 XXX
NULL NULL 10 XXX
Query 2
SELECT T1.*, T2.* FROM T1, T2
ON T1. B (+) = T2. B
AND T1. B ( + ) = 20;
OUTPUT
=======
BBB YYY 20 20
BBB YYY 20 20
BBB YYY 20 20
Request 3
SELECT T1.*, T2.* FROM T1, T2
ON T1. B (+) = T2. B
ET T2. B ( + ) = 20;
-OUTPUT
=========
BBB YYY 20 20
BBB YYY 20 20
BBB YYY 20 20
NULL NULL 10 XXX
NULL NULL 10 XXX
NULL NULL 10 XXX
Thank you and best regards,
Mathieu
Hi, nada.
967250 wrote:
Hello
My apologies for errors in queries.
Please find the three queries
QUERY1
SELECT T1.*, T2.*
T1 LEFT JOIN T2
ON T1. B = T2. B
AND T1. B = 20;QUERY2
SELECT T1.*, T2.*
FROM T1, T2
WHERE T1. B = T2. B ( + )
AND T1. B (+) = 20;QUERY3
SELECT T1.*, T2.*
FROM T1, T2
WHERE T1. B = T2. B ( + )
AND T2. B (+) = 20;Query 1 and 3 produce the same results. I want to know is what is the difference between Q2 and (T1 or T3)
Thank you
Mathieu
In the query above 1, t1 is the required table (LEFT OUTER JOIN means the table on the LEFT is needed, and the other table is optional).
Query 3 is the way to do the same in the old notation.
If you use the old notation of outer join, the + sign is used by reference to the table as an option. It should always apply for t1 or t2, not sometimes one and sometimes the other, which is what you do in the application 2. In the State:
T1. B = T2. B ( + )
you say that t2 is optional; in the other condition
T1. B (+) = 20
you say that t1 is optional. I don't know why that does not raise an error. Apparently, it is just to ignore the sign in this last condition.
-
Left Outer Join help...
Hello world
I'm still trying to learn the SQL, and I can not specifically with the left outer join. I normally join tables using equijoin, but I don't get the right data set returns, and designed with the help of a left or right outer join would solve the problem...
Here is my SQL that works properly with 1 left outer join. I build the slow query in the SQL following, you will see where I see the error. I don't expect you to understand the data and the columns, I'm trying to join, I think the problems I encounter are related to syntax, and I hope that you can find where are my syntax errors.
Select
s.Name as "Pseudonym,"
SV.view_name as "name of the view.
s_view. Name
Of
s s_screen,
s_screen_view sv
outer join left s_view
WE (sv.view_name = s_view.name)
where
SV.screen_id = ' 1-866 A - 1X3LU' and
s.ROW_ID = sv.screen_id and
s.repository_id = ' 866 A-1-1"and
s_view.repository_id = ' A-1-1 866 ";
Here is the SQL code where I encounter the following error...
Error:
ORA-00904: "SV". "" View_name ": invalid identifier
00904, 00000 - '% s: invalid identifier '.
* Cause:
* Action:
Error on line: column 14: 7
Problematic SQL:
Select
s.Name as "Pseudonym,"
SV.view_name as "name of the view.
s_view. Name,
s_applet. Name as Applet
-b.SID like "name of the cmdlet.
Of
s s_screen,
s_screen_view sv,
wti s_view_wtmpl_it
outer join left s_view
WE (sv.view_name = s_view.name)
outer join left s_applet
WE (wti.name = s_applet.name)
where
SV.screen_id = ' 1-866 A - 1X3LU' and
s.ROW_ID = sv.screen_id and
s.repository_id = ' 866 A-1-1"and
s_view.repository_id = ' A-1-1 866 ";
Thanks in advance for your help.
Chris
> ORA-00904: "S_VIEW_WEB_TMPL." "" ROW_ID ": invalid identifier
I don't see this table in your FROM clause.
-
Hi all
11.2.0.1
I have two 2 left outer join in my application, but I got errror
Ths is supported?
It is something like:
Select tab1, b.col1, a.col1, c.col1 one
LEFT OUTER JOIN tab2 b
ON a.id = b.id;
LEFT OUTER JOIN tab 3 c
ON a.id = c.id;
My syntax is correct? I got the error ora-942.
Help, please...
Thank you
Then use script below
SELECT A.ACRNUMBER AS ACR_NO, A.LASTNAME, A.GIVENNAME AS FIRSTNAME, A.MIDDLENAME, A.BIRTHDATE, A.GENDER,NLV2(F.COUNTRYID3,'XXX'), A.PROBSTAYLENGTH AS PROB_STAY_LENGHT,A.SECTIONISSUED AS SECTION_ISSUED, A.RESIDENCECERTIFICATENUMBER AS RESIDENCE_CERTIFICATE_NO, A.ACTIVESTATUS AS STATUS, B.CLIP IMAGE AS PHOTO, C.SIGBMP AS SIGNATURE,D.CARDISSUErNUMBER AS CARD_NO, D.CARDEXPIRYDATE AS CARD_VALIDITY, D.CARDSERIALNUMBER AS CARD_SERIAL_NO, D.CARDISSUEDATE AS CARD_DATE_ISSUED, nvl2( d.CARDSERIALNUMBER,'0','1') AS CARD_STATUS From Acrmaster A Inner Join Pictures B On A.Acrnumber=B.Acrnumber Inner Join Signature C On B.Acrnumber=C.Acrnumber Inner Join Acrcarddetails D On C.Acrnumber=D.Acrnumber Left Outer Join Acrblockcarddetails E On (D.Acrnumber=E.Acrnumber And D.Cardserialnumber=E.Cardserialnumber) Left Outer Join Countrymaster_Lk F ON A.NATIONALITY=F.ID
You have error here:
left outer join ACRBLOCKCARDDETAILS E
Left Outer join Countrymaster_Lk F on d.acrnumber = e.acrnumber and d.CARDSERIALNUMBER = e.CARDSERIALNUMBER and A.NATIONALITY = F.ID
Concerning
Mr. Mahir Quluzade
-
Hello
I am in charge of the migration of a SQL Server 2000 database to Oracle 11 g, under what I also migrate some predefined queries, that my client has. However I can't seem to get the syntax right and it keeps failing. Could you please help me? Thank you.
Query:
The fields are correct, but I get not found when expected in FROM clause.SELECT *,(select r.recsolins from gx.repara r where r.percod=c.percod and r.concod=c.concod and r.rectpo='I' and r.recsts='F' and r.grppercod=10 and r.recnro=(select max(t.recnro) from gx.repara t where t.percod=c.percod and t.concod=c.concod and t.rectpo='I' andt.recsts='F' ) ) as NROID FROM gx.CONABO c, gx.abonad a LEFT OUTER JOIN gx.CALLES y ON y.dptocod=10 and y.ciucod=524 and y.CALCOD=A.AboCalEsq1, LEFT OUTER JOIN gx.CALLES Z ON z.dptocod=10 and z.ciucod=524 and z.CALCOD=A.AboCalEsq2 ,gx.calles x WHERE c.PERCOD in (10,60) and CONSTSHAB in ('C','D','P') and a.percod=c.percod and a.abocod=c.abocod and x.dptocod=10 and x.ciucod=524 and x.calcod=abocal order by c.percod,c.concod;
Published by: n on June 5, 2012 13:47
-
using (+) or left outer join
Dear Expert;
I've been playing by using the two symbol... and realized that they do the same thing... Is it true...? or am I wrong.
Thank you.Hello
user13328581 wrote:
Dear Expert;I've been playing by using the two symbol... and realized that they do the same thing... Is it true...? or am I wrong.
They all have two outer joins. The + rating was the original way to do it in Oracle. LEFT, RIGHT, and FULL OUTER JOIN introduced in Oracle 9, but the old way is still supported.
There are some situations (such as an outer join complete and outer-join a table to two different tables) that are better with the ANSI syntax (it's LEFT OUTER JOIN). It is possible to get the same results using +, but it must be combersome and/or inefficient workarounds. I suggest that you use always LEFT OUTER JOIN (or FULL OUTER JOIN, or, on occasions RIGHT OUTER JOIN). I think that you will find it easier and less error-prone.
-
Bug in outer join syntax?
I use Oracle 10.2, and I think I found a bug in what is allowed for the outer join syntax. Specifically, I am allowed to specify "outer join" without specifying if it's left, right, or full outer join. It behaves as an inner join.
The documents show that the type_de_jointure is optional, but does not allow the 'outside' keyword be used alone: http://download.oracle.com/docs/cd/A97630_01/server.920/a96540/statements_103a.htm#2126207
Small example:
The release of the last three selects shows that the OUTER JOIN behaves as a simple JOIN, rather than return a syntax error or at least behave like a FULL OUTER JOIN (this is where the absence of a syntax error is misleading):create table TABLE_A (ID number(10) primary key, VALUE_A varchar2(50)); create table TABLE_B (ID number(10) primary key, VALUE_B varchar2(50)); insert into TABLE_A (ID, VALUE_A) values (1, 'abc'); insert into TABLE_A (ID, VALUE_A) values (2, 'def'); insert into TABLE_A (ID, VALUE_A) values (3, 'ghi'); insert into TABLE_B (ID, VALUE_B) values (2, 'jkl'); insert into TABLE_B (ID, VALUE_B) values (3, 'mno'); insert into TABLE_B (ID, VALUE_B) values (4, 'pqr'); commit; select ID, VALUE_A from TABLE_A; select ID, VALUE_B from TABLE_B; select ID, VALUE_A, VALUE_B from TABLE_A join TABLE_B using (ID); select ID, VALUE_A, VALUE_B from TABLE_A full outer join TABLE_B using (ID); select ID, VALUE_A, VALUE_B from TABLE_A outer join TABLE_B using (ID);
Y at - there somewhere that I can tell you that?SQL> select ID, VALUE_A, VALUE_B from TABLE_A join TABLE_B using (ID); ID VALUE_A VALUE_B ---------- -------------------------------------------------- -------------------------------------------------- 2 def jkl 3 ghi mno SQL> select ID, VALUE_A, VALUE_B from TABLE_A full outer join TABLE_B using (ID); ID VALUE_A VALUE_B ---------- -------------------------------------------------- -------------------------------------------------- 1 abc 2 def jkl 3 ghi mno 4 pqr SQL> select ID, VALUE_A, VALUE_B from TABLE_A outer join TABLE_B using (ID); ID VALUE_A VALUE_B ---------- -------------------------------------------------- -------------------------------------------------- 2 def jkl 3 ghi mno SQL>
If you have a supported Oracle agreement you can save a Service request with Oracle, but they can answer that this is not a bug. The problem is that the 'outside' keyword in your 3rd example is treated as an alias for TABLE_A because it is not considered as a reserved keyword.
with table_a as ( select 1 as id, 'abc' as value_a from dual union all select 2 as id, 'def' as value_a from dual union all select 3 as id, 'ghi' as value_a from dual ) , table_b as ( select 2 as id, 'jkl' as value_b from dual union all select 3 as id, 'mno' as value_b from dual union all select 4 as id, 'pqr' as value_b from dual ) select ID, outer.VALUE_A, VALUE_B from TABLE_A outer join TABLE_B using (ID); ID VALUE_A VALUE_B ---------------------- ------- ------- 2 def jkl 3 ghi mno
If you query the view RESERVED_WORDS of V$ it will tell you what keywords are reserved.
select * from V$RESERVED_WORDS where keyword in ('OUTER', 'SELECT','USING'); KEYWORD LENGTH RESERVED RES_TYPE RES_ATTR RES_SEMI DUPLICATE ------------------------------ ---------------------- -------- -------- -------- -------- --------- USING 5 N N N N N OUTER 5 N N N N N SELECT 6 Y N N N N
You'll get a similar result, if you tried
select ID, VALUE_A, VALUE_B from TABLE_A using join TABLE_B using (ID);
Kind regards
Bob -
Oracle: Use LEFT OUTER JOIN, but convert the data to an external list
Hello, all,.
I know it can be done; I just don't remember how I got it done, oh there are so many years.
Assumes that the tables exist for groups and individuals. People can belong to several groups.
SELECT g.groupName, p.lastName || ', ' || p.firstName as fullName FROM groups g LEFT OUTER JOIN groupPersonAssociation gpa ON gpa.groupID = g.groupID LEFT OUTER JOIN person p ON p.personID = gpa.personID ORDER BY g.groupName, fullName
This gives us:
Group One Alpha, Daniel Group One Bravo, Charles Group One Charlie, Chuck Group Two Beta, Alpha Group Two Delta, Bonnie Group Three Echo, Bunny Group Three Golf, Samuel Group Three November, Stan
How word the SQL to get the data as:
Group One Alpha, Daniel | Bravo, Charles | Charlie, Chuck Group Two Beta, Alpha | Delta, Bonnie Group Three Echo, Bunny | Golf, Samuel | November, Stan
V/r,
^_^
I finally thought to it. I was using incorrect keywords on Google.
SELECT g.groupName, LISTAGG(p.lastName || ', ' || p.firstName,' | ') WITHIN GROUP (ORDER BY g.groupName) "fullName" FROM groups g LEFT OUTER JOIN groupPersonAssociation gpa ON ggpa.groupID = g.groupID LEFT OUTER JOIN person p ON p.personID = gpa.personID GROUP BY g.groupName ORDER BY g.groupName, fullName
Just in case someone else is going through this same desire.
HTH,
^_^
-
Hi all
I use under version
Connected to Oracle Database 11g Express Edition Release 11.2.0.2.0
SQL > SELECT E.ENAME,.
2 D.DEPTNO,
3 D.LOC
4. TO EMP E,.
DEPT 5 D
6. WHERE = E.DEPTNO D.DEPTNO (+);
ENAME, DEPTNO LOC
---------- ------ -------------
DALLAS SMITH 20
ALLEN 30 CHICAGO
WARD 30 CHICAGO
20 DALLAS JONES
MARTIN 30 CHICAGO
BLAKE 30 CHICAGO
CLARK 10 NEW YORK
SCOTT 20 DALLAS
THE 10 NEW YORK KING
TURNER 30 CHICAGO
20 DALLAS ADAMS
JAMES 30 CHICAGO
FORD 20 DALLAS
MILLER 10 NEW YORK
40 BOSTON
15 selected lines
-----------------------------------------------------------------------------------------------------------------------------
SQL > SELECT E.ENAME,.
2 D.DEPTNO,
3 D.LOC
4. TO EMP E
5 LEFT OUTER JOIN
D 6 DEPT
7. THE E.DEPTNO = D.DEPTNO;
ENAME, DEPTNO LOC
---------- ------ -------------
MILLER 10 NEW YORK
THE 10 NEW YORK KING
CLARK 10 NEW YORK
FORD 20 DALLAS
20 DALLAS ADAMS
SCOTT 20 DALLAS
20 DALLAS JONES
DALLAS SMITH 20
JAMES 30 CHICAGO
TURNER 30 CHICAGO
BLAKE 30 CHICAGO
MARTIN 30 CHICAGO
WARD 30 CHICAGO
ALLEN 30 CHICAGO
14 selected lines
My doubt is both are same query is the same, is in ansi format and is in the format of the Oracle,.
but the results are different.
For the first query null is coming for unmatched records in the dept table
but in the second query, it does not come
Thank you
Hello
2947022 wrote:
Hi all
I use under version
Connected to Oracle Database 11g Express Edition Release 11.2.0.2.0
SQL > SELECT E.ENAME,.
2 D.DEPTNO,
3 D.LOC
4. TO EMP E,.
DEPT 5 D
6. WHERE = E.DEPTNO D.DEPTNO (+);
ENAME, DEPTNO LOC
---------- ------ -------------
DALLAS SMITH 20
ALLEN 30 CHICAGO
WARD 30 CHICAGO
20 DALLAS JONES
MARTIN 30 CHICAGO
BLAKE 30 CHICAGO
CLARK 10 NEW YORK
SCOTT 20 DALLAS
THE 10 NEW YORK KING
TURNER 30 CHICAGO
20 DALLAS ADAMS
JAMES 30 CHICAGO
FORD 20 DALLAS
MILLER 10 NEW YORK
40 BOSTON
15 selected lines
-----------------------------------------------------------------------------------------------------------------------------
SQL > SELECT E.ENAME,.
2 D.DEPTNO,
3 D.LOC
4. TO EMP E
5 LEFT OUTER JOIN
D 6 DEPT
7. THE E.DEPTNO = D.DEPTNO;
ENAME, DEPTNO LOC
---------- ------ -------------
MILLER 10 NEW YORK
THE 10 NEW YORK KING
CLARK 10 NEW YORK
FORD 20 DALLAS
20 DALLAS ADAMS
SCOTT 20 DALLAS
20 DALLAS JONES
DALLAS SMITH 20
JAMES 30 CHICAGO
TURNER 30 CHICAGO
BLAKE 30 CHICAGO
MARTIN 30 CHICAGO
WARD 30 CHICAGO
ALLEN 30 CHICAGO
14 selected lines
My doubt is both are same query is the same, is in ansi format and is in the format of the Oracle,.
but the results are different.
For the first query null is coming for unmatched records in the dept table
but in the second query, it does not come
Thank you
In fact, these requests are not the same.
The first is to find all the lines of the Department, with the corresponding lines of PGE (when there are). This is equivalent to «FROM dept LEFT OUTER JOIN emp...» ».
The second is to find all the rows in the emp of the lines of the Department (when there are any). This is equivalent to «...» WHERE e.deptno = d.deptno (+).
-
Bad result in a left outer join in 12.1.0.2
Hallo,
We discovered a strange behaviour in a query. The query provides values in a column of outer join where there is no corresponding value in the table is attached to the outside.
When you expand this request by the "ORDER BY" then this query gives the correct result.
Example:
SQL > desc tb_a
Name Null? Typ
-------------------------------------------- ----------------------------
ID NOT NULL NUMBER (19)SQL > desc tb_b
Name Null? Typ
-------------------------------------------- ----------------------------
CLOSED NOT NULL NUMBER (1)
ID NOT NULL NUMBER (19)CCS_APPLICATION@icw01> select * from tb_a where id in (4148,4141,4195);
ID
----------
4148
4141
4195CCS_APPLICATION@icw01> select * from tb_b where id in (4148,4141,4195);
INTERNAL ID
---------- ----------
4148 0CCS_APPLICATION@icw01> SELECT
2 b.id AS b_id,
3 a.id AS a_id,
4 b.closed AS b_closed
5
6 tb_a a
7 LEFT OUTER JOIN tb_b b ON a.id = b.id
8 WHERE a.id IN (4148, 4195, 4141)
9 ORDER BY ASC a.id
10;B_ID ALLOCATION A_ID B_CLOSED
---------- ---------- ----------
4141
4148 4148 0
4195CCS_APPLICATION@icw01> SELECT
2 b.id AS b_id,
3 a.id AS a_id,
4 b.closed AS b_closed
5
6 tb_a a
7 LEFT OUTER JOIN tb_b b ON a.id = b.id
8 WHERE a.id IN (4148, 4195, 4141)
9 - ORDER BY ASC a.id
10;B_ID ALLOCATION A_ID B_CLOSED
---------- ---------- ----------
4148 4148 0
4141 4141
4195 4195instance parameter:
VALUE OF TYPE NAME
------------------------------------ ----------- ------------------------------
compatible string 12.1.0.2.0
optimizer_features_enable string 12.1.0.2
After ""alter system set optimizer_features_enable = ' 11.2.0.4 ';" the query provides the correct result in both cases (ordered and unordered).
Now the final question: is this a bug?
1480970 wrote:
Hallo! Yes, I searched the Support of Oracle. I found some similar entries, but not an exact match. To fix some issues
with 12.1.0.2.
There is another interesting clue when look you on the execution plan:
Note
-----
-the dynamic statistics used: dynamic sampling (level = 2)
- This is an adaptation plan
We have disabled (= FALSE) optimizer_adaptive_features and the query provides the correct values.
This could be a solution for us.
Looks like a pretty tight match for bug 18430870, even if it affects the two 12.1.0.1 and 12.1.0.2, which contradicts the Martin trial against 12.1.0.1.
The description of the bug mentions disabling "_projection_pushdown" (set to false) should also be a viable solution, perhaps if you want to give that a try and see if it is a different bug or not.
There are also a number of one-time fixes already available for download, maybe your version / platform is already covered, if the bug applies.
Randolf
-
Hi Experts,
I have a requirement that says - see the chart for the past 10 days, regardless the presence data table in fact.
Lets consider an example - Time_dim product, are my dimension tables, Purchase_Order is my fact table.I did it for external Purchase_Order in left RPD with TIME_DIM and inner join with the PRODUCT table. and execution of query of exit-
Select T.Date, P.item, count (distinct PO.order_no)
TIME_DIM t, PRODUCT P, PURCHASE_ORDER PO
where T.date_key = PO.date_key
and P.item = in. agenda
and P.item = 'laptop ';The query generated by OBIEE left outer join, but when the condition P.item = "Notebook" included in the query, and if there are no orders for this product in one of the date, that date will not come in the result set.
the query to be generated by the OBIEE is-
Select T.Date, PO.item, count (distinct PO.order_no)
TIME_DIM t,.
(SELECT P.ITEM, IN. ORDER_NO
PRODUCT P, PO PURCHASE_ORDER
WHERE P.item = in. agenda
and P.item = 'Laptop') IN.
WHERE T.date_key = PO.date_key (+);How to design the RPD to achieve this. All pray to advise on this. Thanks in advance.
Thank you
ChantalHello
You are on 11.1.1.7?
I would say that your condition can be made without using external and maintenance of product and the standard between the FACT dimension, time inner join join.
If you enable your property analysis OBIEE "Include Null values" will automatically return all the elements of time and product matching your filter (so you'll need to add a filter on 'Date' to limit it to the last 10 days or you will have a unique day of your time dimension).
If you filter then on "Laptop", even if there is not a single value in order for "Laptop" in the last 10 days, he will be there on the screen.
Easy, clean and you keep your inner join between the facts and Dimensions.
Take a look at this example, I just did on SampleApp 406:
Selection of 12 months (year 2010) and a customer (id = 89) and income. The model has only an inner join. I activate the option "Include Null values" and here is the result.
A line with cells only empty because there is not a single revenue for customer 89 in 2010. This is exactly your condition.
Honestly, do not touch your model using the outer join, you will have more side effects than benefits. Every single scan will do the outer join and you'll have a lot of data 'empty' return of the DB (more large data set containing just the null values) and probably you need the outer join in 15 to 25% of your analysis.
Keep things simple, it will be faster and easier to maintain.
-
Modeling of the left outer join
Hello world
I'm tender hand to you guys for a modeling help
I have a FACT, the customers, the Dim_Date and CUST_ADDRESS of tables to model
Fact and the client are joined through CUST_ID
FACT and DATE are joined through DATE_ID
CUST_ADDRESS must be attached to the top of the model through CUST_ID, DATE_ID and this join must be Left outer because sometimes the address does not exist or is not current, which means DATE_ID could be different between Dim_Date and CUST_ADDRESS
If it were to join internal, model would have been easy, because of the outside left that I am unable to model, it's pretty good.
Application under
Select D.DATE, C.CUST_NAME, CA. ADDRESS, F.AMOUNT
Of
F FACT
JOIN THE
CUSTOMER C
ON C.CUST_ID = F.CUST_ID
JOIN THE
DIM_DATE D
ON F.DATE_ID = D.DATE_ID
LEFT OUTER JOIN
CUST_ADDRESS CA
ON C.CUST_ID = CA. CUST_ID AND C.DATE_ID = D.DATE_IDThanks in advance
When I add the CUSTOMER and in FACT LTS CUST_ADDRESS
Stop it!
Don't add CUSTOMER and CUST_ADDRESS in the FACT of LTS. Why would add you to the LTS DO?
You design a management model: CUSTOMER is a dimension and it has its own logical table this logic table join with a logical join in the activity diagram. Ditto for CUST_ADDRESS.
So the change, I missed earlier is CUST_ADDRESS contains no Cust_ID (ACTUALLY existing), but contains a Cust_NO, and the table to translate Cust_NO in Cust_ID is CUSTOMER?
No problem...
Let's start with a new alias of CUSTOMER (to keep more simple to understand at the moment), call as you want, but this new alias will be the link between the FACT and CUST_ADDRESS.
In LTS of the dimension 'Address', you have CUST_ADDRESS initially, add an inner join on the new alias that you created in the LTS of the CUSTOMER. So now your 'Address' logical dimension contains the Cust_NO and Cust_ID and this will make the join to FACT.
Between CUST_ADDRESS and the CLIENT, you can keep an inner join, because the target is not not for get the address of the customer, but is having the Cust_ID in the address line.
Give it a try at that.
But do not add these tables in the LTS, they are logical dimensions.
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Help for a LEFT OUTER JOIN query
Hello, all,.
I'm having some trouble setting up an Oracle 11 g Server SQL query, and I could use some help.
Let's say tableA is blogs; tableC is comments for blog entries; tableB is the associative array:
tableA blogID blogTitle blogBody dateEntered 1 This is a test More text... 2016-05-20 11:11:11 2 More testing Still more! 2016-05-19 10:10:10 3 Third charm!! Blah, blah. 2016-05-18 09:09:09
tableC commID userID userText dateEntered 10 Bravo I like it! 2016-05-20 11:21:31 11 Charlie I don't! 2016-05-20 11:31:51 12 Alpha Do it again! 2016-05-19 10:20:30 13 Bravo Still more? 2016-05-19 10:30:50 14 Charlie So, what? 2016-05-19 10:35:45 15 Bravo Blah, what? 2016-05-18 09:10:11 16 Alpha Magic number! 2016-05-18 09:11:13
tableB blogID commID 1 10 1 11 1 12 2 13 2 14 3 15 3 16
I'm trying to get blogID, blogTitle, blogBody and the number of comments for each blog entry. But, since I'm on to_char() for date and COUNT (commID) for the total number of comments, I am not "a group by expression.
Here is an example of pseudo-SQL of what I'm trying.
SELECT a.blogID, a.blogTitle, a.blogBody, to_char(a.dateEntered,'YYYY-MM-DD HH24:MI:SS') as dateEntered, COUNT(c.commID) as total FROM tableA a LEFT OUTER JOIN tableB b ON b.blog_ID = a.blog_ID LEFT OUTER JOIN tableC c ON c.commID = b.commID WHERE a.blogID = '1' GROUP BY blogID, blogTitle, blogBody ORDER BY to_date(dateEntered,'MM-DD-YYYY HH24:MI:SS') desc
I'm sure it's something simple, but I just DO NOT see it. Can you help me?
V/r,
^_^
Try:
GROUP BY a.blogID, a.blogTitle, a.blogBody, to_char(a.dateEntered,'YYYY-MM-DD HH24:MI:SS')
See you soon
Eddie
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Why left outer join with a table gives me more lines?
Hi gurus,
I can see "view_a" and a table 'table_a '.
view_a a county of 100 lines. Now, when I left outer join that discovers with a 'table_a', I expect all 100 lines.
However, I'm more than 100 lines. Is it still possible?
Also even to analyze these situations, how can I move forward?
Because it is very high volumn of sight and takes longer to run.
Select count (*) view_a, view_b
where view_a.col1 = view_b.col1 (+)
and view_a.col2 = view_b.col2 (+);
Thank you
I can see "view_a" and a table 'table_a '.
view_a a county of 100 lines. Now, when I left outer join that discovers with a 'table_a', I expect all 100 lines.
However, I'm more than 100 lines. Is it still possible?
Also even to analyze these situations, how can I move forward?
Because it is very high volumn of sight and takes longer to run.
Select count (*) view_a, view_b
where view_a.col1 = view_b.col1 (+)
and view_a.col2 = view_b.col2 (+);
Which is not necessarily related to the use of an outer join.
Just join of two tables in general will give you more rows of one table has.
Scott DEPT table contains ONE row for deptno = 10
The EMP table has THREE rows of deptno = 10
The number of rows you plan if you join two tables using an equi-join?
Three - what is MORE lines the DEPT table has for deptno = 10
Select * from Department where deptno = 10
DEPTNO, DNAME, LOC
10, ACCOUNTING, NEW YORKSelect * from emp where deptno = 10
MGR, EMPLOYMENT ENAME, EMPNO, HIREDATE, SAL, COMM, DEPTNO
7782, CLARK, MANAGER, 7839, 6/9/1981,2450, 10
7839, KING, PRESIDENT, 17 NOVEMBER 00, 10
7934, MILLER, CLERK, 7782, 23 JANUARY 00: 10Select dept.*, emp.*
Department, emp
where dept.deptno = 10
and dept.deptno = emp.deptnoDEPTNO, DNAME, LOC, EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO_1
10, ACCOUNTING, NEW YORK, 7782, CLARK, MANAGER, 7839, 6/9/1981,2450, 10
10, ACCOUNTING, NEW YORK, 7839, KING, PRESIDENT, 17 NOVEMBER 00, 10
10, ACCOUNTING, NEW YORK, 7934, MILLER, CLERK, 7782, 23 JANUARY 00: 10So if these are the lines ONLY in the table EMP and DEPT the query would give you THREE lines despite the DEPT table only ONE line.
No do you expect? You get ALL the child rows that belong to the parent company. Otherwise, how could it possibly work?
The OUTER join includes lines where the parent row exists but there is NO child line as others have shown.
Outer joins
Outer join extends the result of a simple join. Outer join returns all rows that satisfy the join condition and also returns some or all rows in a table for which no line of the other meet the join condition.
Get more lines to exist in one of the paintings is a basic necessity. It usually has NOTHING to with the question of whether you have an outside to join or not.
See the section on the JOINTS in the Oracle documentation
http://docs.Oracle.com/CD/B28359_01/server.111/b28286/queries006.htm
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Hi all
I have 3 tables A, B, C
Create table a (varchar2 (100)) of the currency;
insert into a values (GBp);
insert into a values (GBP);
insert into a values (GBX);
Create table B (varchar2 (100) currency, number);
insert into B values (GBP, 61.1);
Create a table (minor_currency varchar2 (100), major_currency varchar2 (100));
insert into values of C (GBp, GBP);
insert into values of C (GBX, GBP);
I need to get the rate table B by linking the A with the currency as a condition of joining. (left outer join)
For currencies which are not in table B, table should be attached with C minor currency-based
and get the major_currency and join with table B
Ex:
something like this:
Select B.rate from A, B, C
WHERE (A.currency = B.currency or (A.currency = C.minor_currency and B.currency = C.major_currency)
O/P: for GBp and GBX currency, I need to get the rate as 61.1 in table B, but B currency is GBP. So I need to get the major_currecny for GBp, GBX table C and join with the table B
Thank you
Sasi
Hi all
Thanks for your time. Its done
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