Function to validate the hour

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  GusC wrote:

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  Hello

  I use the version of database Oracle 11.2.1. I would like to calculate the number of minutes of work between the two dates where working hours are Monday - Thursday from 08:45 to 17:00 and Friday from 08:45 to 16:30

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/

  Can anyone help?

  Hello

  Think about what you do.

  sliderrules wrote:

  SELECT TO_CHAR (DATE ' 1-1-1' + business_end_time, 'HH24:MI:SS')-TO_CHAR (DATE ' 1-1-1' + business_start_time, 'HH24:MI:SS') * 24 * 60

  of time_dim

  where full_date = July 1, 2013.

  AND working_day = 'Y ';

  The following error is returned:

  ORA-01722: invalid number

  The time is converted to character reslting with this error. Is there a better way to subrtacting types of data INTERVAL DAY (1) SECOND (2) (business_end_time - business_start_time)

  To_char, as its name implies, returns a string of characters.  You say that

  TO_CHAR (...) - TO_CHAR (...) * 24 * 60

  If you ask for the string returned by the 2nd TO_CHAR be multiplied by 24.  Does make any sense to you?

  Maybe you wanted to do the subtraction first, which would be

  (TO_CHAR (...) - TO_CHAR (...)) * 24 * 60

  but still would be a mistake, because you can't subtract a string to another string (or anything else).

  .

  Last Friday, I proposed this:

  SELECT SUM (LESS (end_dt, v_end_dt)

  -Most GREAT (start_dt, v_start_dt)

  ) * 24 * 60...

  where start_dt and end_dt were the DATE in the table columns, as the value returned by TO_DATE (08 11 July 2013:45 ', "DD-Mon-YYYY HH24").

  If I understand correctly, you would store stores rather 3 columns: full_date (a DATE, where the time part is 00:00:00) as well as business_start_time and business_end_time (the two INTERVAL DAY TO SECOND).  In this case, you can modify the code above to say:

  SELECT SUM (LESS (full_date + business_end_time, v_end_dt)

  -GREATEST (full_date + business_start_time, v_start_dt)

  ) * 24 * 60...

  You can add a DATE at an INTERVAL;  the result will be a DATE.  There is no need to convert anything to a data type to the other.

• Add the hours and minutes so far

  Hello
  I need to write a function that has two input parameters.
  Parameter1 = > Date data type, the value is in GMT.
  Parameter1 = > string value that indicates the time difference and it has the following format.
  
  GMT (sign) HH24Mi
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  I wrote a simple code but cannot make it work. I would like to know if there is another way to do it.
  

  create or replace
  Function         F_FUNCTION_NAME(dt date,timeZoneOffset   in   varchar2)
  return date
  As
      offset  varchar2(9);    
  Begin
      Offset := (To_Char(Substr(Substr(Timezoneoffset,4),0,Length(Substr(Timezoneoffset,4))-2)||':'||Substr(Substr(Timezoneoffset,4),-2)));
      return Dt + interval Offset hour to minute;
  End;

  Thank you.

  Hello

  Delete GMT and use the colon between the hours and minutes in this way:

  ALTER SESSION SET nls_date_format='DD-MON-YYYY HH24:MI:SS';
  
  SELECT SYSDATE
       , CAST (CAST (SYSDATE AS TIMESTAMP WITH TIME ZONE) AT TIME ZONE '+4:00' AS DATE) offset_date
    FROM DUAL;
  
  SYSDATE                OFFSET_DATE
  ---------------------- ----------------------
  06-MAR-2013 12:08:01   06-MAR-2013 15:08:01  
  

  Kind regards.
  Al

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  Thank you in advance for any help you can provide.

  Hello

  Where do you set this variable: d?

  var now = new Date();

  var m = now.getMinutes ();

  var h = now.getHours ();

  or

  var d = new Date();

  var m = d.getMinutes ();

  var h = d.getHours ();

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  Hello

  use a validation of type "Function returning a Boolean" and the following code:

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  marcusinfla wrote:

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