Get multiple values in a select statement in a variable to a procedure

Hello

I'm trying to craete a procedure where the entry of the procedure will be a similar string "a, b, c, d" and output the values of a table that matches the value separated by commas of in sting.

For this.

create table test (varchar2 (10)) nm;

Insert test values ('a');

Insert test values ('b');

Insert test values ('c');

Insert test values (');

Select * from test;

------

one

Now I'm doing a procedure where the parameter will be the column values NM of TEST table in a string separated by commas like "a, b, c, d, x, l" there could be false values also.

The procedure will return only the values that are adapted with column NM from the TEST table for this I created this procedure.

create or replace procedure p_test (p_nm IN varchar2 / *, THE sys_refcursor p_out * /)

number of l_len;

l_val varchar2 (10);

l_val1 varchar2 (10);

Start

l_len: = length (p_nm);

-dbms_output.put_line (l_len);

Start

because me in 1.l_len

loop

Select REGEXP_SUBSTR (p_nm, ' ([^,] *)(,|$)', 1, I, NULL, 1) in double l_val;

-dbms_output.put_line (l_val);

-Open p_out for

Select * into l_val1 of test where nm = l_val;

dbms_output.put_line (l_val1);

output when l_len is null;

end loop;

exception

When no_data_found then

null;

end;

exception

while others then

dbms_output.put_line (' error reason :'||) SQLERRM |' :'|| error code SQLCODE);

end;

EXECUTE p_test ('a, b, c, d, q, w');

OUTPUT-

one

This procedure gives me out as I need, but I need to get this in a variable which should be OUT the parameter of this procedure will be called by the JAVA for our application.

As I already tried to use the refcursor (see the commented part), but it gives me no output during a call there.

Its a call to this procedure when I use the refcursor (removing comments).

declare

l_out sys_refcursor;

l_val varchar2 (20);

l_str varchar2 (20): = 'a, b, c, d;

Start

p_test (l_str, l_out);

loop

extract the l_out in l_val;

dbms_output.put_line (l_val);

dbms_output.put_line ('a');

When the output l_out % notfound;

end loop;

end;

So here I am stuck with that, how to get the result of multiple or I'm missing something here and if there is a better approach to this requirement as I come with that so I'm sharing it here.

OR if someone can tell me what is the problem with this package-

create or replace package p_test_api

type t_rec is rendered (name varchar2 (200));

type t_tab is table of index by pls_integer t_rec;

procedure p_pest_proc (p_nm in varchar2, p_out to t_tab);

end p_test_api;

create or replace package body p_test_api

procedure p_pest_proc (p_nm in varchar2, p_out to t_tab)

number of l_len;

l_val varchar2 (10);

l_val1 varchar2 (10);

Start

l_len: = length (p_nm);

Start

because me in 1.l_len

loop

Select REGEXP_SUBSTR (p_nm, ' ([^,] *)(,|$)', 1, I, NULL, 1) in double l_val;

dbms_output.put_line (l_val);

Select * bulk collect into p_out test where nm = l_val;

output when l_len is null;

end loop;

exception

When no_data_found then

null;

end;

exception

while others then

dbms_output.put_line (' error reason :'||) SQLERRM |' :'|| error code SQLCODE);

end p_pest_proc;

end p_test_api;

CALL THIS PACKAGE-

declare

l_out p_test_api.t_tab;

l_str varchar2 (20): = 'a, b, c, d;

Start

P_TEST_API. P_PEST_PROC (l_str, l_out);

dbms_output.put_line ('b');

because me in 1.l_out.count

loop

dbms_output.put_line ('a');

dbms_output.put_line (l_out (i). (Name)

dbms_output.put_line ('a');

When the output l_out.count = 0;

end loop;

dbms_output.put_line ('a');

end;

It won't loop

I am using-

Oracle Database 11 g Enterprise Edition Release 11.2.0.1.0 - 64 bit Production

Thank you

First of all, get rid of it WHEN OTHERS like William already noted. If you do not want to use the collections:

SQL > create or replace
function f_test () 2
3 p_nm varchar2
4 )
5 return varchar2
6 is
v_result 7 varchar2 (4000);
Start 8
9. Select listagg (nm, ',') within the Group (nm control)
10 in v_result
11 test
where the 12 «,» | p_nm | ',' like '%', | NM | ',%';
13 return v_result;
14 end;
15.

The function is created.

SQL > start
2 dbms_output.put_line (f_test ('a, b, c, d, x, w'));
3 end;
4.
a, b, c and d

PL/SQL procedure successfully completed.

SQL >

SY.

Tags: Database

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1     2     Reversed     -200     06/01/2009
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2     2     Reversed     -200     05/01/2009
2     3     Applied     300     06/01/2009
2     4     Reversed     -400     06/01/2009
2     4     Reversed     400     06/01/2009
2     5     Applied     500     07/01/2009

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'2323123525241',
'1231231231234'

in the process, I have to do a lot of copy and pasting that seems to take a long time.

So, is there a way to make the process of sql pl serial passed to me as an excel file or is there any other alternative methods can I use?
TABLE EXTERNAL research

To parse a string value in a Select statement by using features of characters
I need to put a single space between the last number and the first character in a string. These channels will always begin with a number. For example, the string can be:
```
555B11#1A MAIN ST.
```
I have to return the following:
```
555 B11#1A MAIN ST.
```
Note the space after the 555 and before the B. The rest of the chain must remain the same. Is it possible is a Select SQL statement, using the features of character?

Any help would be greatly appreciated.
Sharpe says:
Indeed, it works. Thank you!
```
1  SELECT REGEXP_REPLACE ('555B11#1A MAIN ST.', '([[:digit:]])([[:alpha:]])', '\1 \2', 1, 1)     AS
2* FROM    dual
SQL> /

NEW_ADDR
-------------------
555 B11#1A MAIN ST.

SQL>
{code)

Can you help me understand what the pattern parameter '([[:digit:]])([[:alpha:]])' means and what it is doing exactly?  
```
Sure. I was waiting to see if that expression really worked on your complete data before explaining. An explanation of the code that works is more generally more instructive than an explanation of the code that does not work, and you will only need to maintain code that works.

[[: digit:]] means just that: all the digits ' 0 'to 9'. I could have used \d, as Solomon has done.
[[: alpha:]] means any alphabetical character. You want to just insert a space, when a digit is immmdiately letter, followed by one on the right? In other words, if there is already a space after the first group of numbers, I guess that you do not want to add another space.

And that means parameter replacement '\1 \2' and what he does exactly?

Put the expressions inside parentheses above allows to refer to the exact substring match using Backreferences . The backreference \1 refers to the part of the pattern that starts with 1 ' ('. left \2 backreference refers to the alternative ground that begins with the 2nd '('. gauche Dans l'exemple, vous avez donné, le patron de (digit) (letter) which was first a '5 b', then '\1' means '5' and '\2' is 'B'.))
Thus, the 2nd argument says "seek a model made up molasses maximum figure, followed immediately by a letter".
The 3rd argument says 'replace this template with the same number you found, then a space, then the same letter you have found'.
The 5th argument said only change the 1st occurrence of the pattern. The default is to change each of them, but that would have changed 1 'a' to ' 1' later in the string, and you said that you didn't want that.
The 4th argument is the default value; We do not have ' really need, except that we cannot pass the 5th argument without passing the argument 4th in front of her (at least not in the versions of Oracle that I use).

Set the first value after the select statement
Hello

I have a problem here.

After you run the statement select, it'll come to me:

COM
DLY
EXC
NRD
RDY

My question: How can I set the first value instead of 'COM' in "EXC"?

Thank you.
Hello
Where you use this instead:
```
select *
from
(
select col_name
,case when col_name='EXC' then 1 else 0 end as "id"
from table_name
)
order by "id" desc
```

Get multiple values in a select statement in a variable to a procedure

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