get the known absolute path url path

Similar Questions

• I get the error access path/file execution error ' 75 "you try to start a product.

  I get the error access path/file execution error ' 75 "you try to start a product. How will I know which file it is trying to access. Is there a log or something?

  Hello

  1. when exactly you get this error message?

  2 have you made any changes to the computer before the show?

  Please provide more information on the issue so that we can better help you.

  In the meantime, make the boot minimum troubleshooting and check if the problem persists.

  How to configure Windows XP to start in a "clean boot" State

  http://support.Microsoft.com/kb/310353

  Note:

  How to configure Windows to use a Normal startup state

  After you have used the boot is a way to solve your problem, you can follow these steps to configure Windows XP to start normally.

  1. Click Startand then click run.
  2. Type msconfig and click OK.
     The System Configuration utility dialog box appears.
  3. Click the general tab, click Normal Startup - load all device drivers and services, and then click OK.
  4. When you are prompted, click restart to restart the computer.

• Get the answer from a url - vCO workflow

  Hello

  Is possible to get the answer to a url if a vCO workflow? I want to check the status of keepalive on a Web server to see if the instance is running or not. All I want is to hit the url, say ""https://webserverfqdn:port/keepalive.html/"and analysis the answer to understand the Web server is running." I don't want SSH to the Server Web query status. It is very before starlight in javascript using xmlHTTPRequest. But, how can I do this using vRO?

  Thank you

  Here you go:

  var website = new URL("https://webserverfqdn:port/keepalive.html");
  var content = website.getContent();
  

  Now 'content' is a string that contains your Web site content that you can now analyze as you wish.

• Try to get the JSX execution path ($.filePath does not)

  I'm trying to get the location of the directory of the current script (main.jsx of my Panel).
  I tried to use $.filePath without success...

  Alert($.) FilePath);
  Returns undefined or int

  var thisFile = new File($.fileName);
  Alert (thisFile);

  Returns /c/Program%20Files/Adobe/Adobe%20Photoshop%20CC%202015

  var thisFile = new File($.fileName).parent;

  alert (thisFile .fsName);

  Returns C:\Program Files\Adobe\Adobe Photoshop CC 2015

  What I am doing wrong?
  I need to get the path of the currently executing script file if I do .parent for its folder name and obtaining an apparent folder name where I have a few things to recover. I run this in my main.jsx - file.

  Found the solution!

  By running this code in the javascript of your extension file, you will get the path:

  var csInterface = new CSInterface();
  var extensionRoot = csInterface.getSystemPath(SystemPath.EXTENSION) + "/jsx/";
  alert(extensionRoot);
  

  Credits goes to Barranca of Davide

• How to get the extension installation path?

  Hello

  This is the right forum to see if the CEP for Photoshop CC extensions 2014? If not, please be kind enough to point me to the correct forum.

  If so, how can I get the full path to the Directory installed extension?

  for example: C:\Program Files (x 86) \Common Files\Adobe\CEP\extensions\com.example.extension

  I tried to get ExtendScript using Folder.commonFiles and adding the rest of the way.

  But it gives C:\Program Files\Common Files, even if our extension is in C:\Program Files (x 86) \Common Files.

  Thank you!

  Use CSInterface. There are several constants that have different paths associated with them:

  CEP-resources/CSInterface.js to master · Adobe-CEP/CEP-Resources · GitHub

• Is there a way to get the list of open URL of file (.dmp) incident, mdmp [NOT BE]

  Hello

  My Firefox session crashed, which was little in private meetings. I have the mdmp (.dmp file) dump file saved. Is there anyway that I can get the list of URLS open in private in windows.

  If so, how to read the file OR open it for debugging.

  Kind regards
  bnrsubs

  All data are kept in memory during the session in incognito mode and will never be saved on the hard disk, so these data are available for normal use and things like restore closed tabs and windows and cookies still function as in a normal session, but this data is deleted from all the private browsing mode Windows Open (tabs) are closed.

• When you back up my files to a new hard drive, getting the error "destination path too long".

  Hello

  Today I was backing up my files on a new hard drive that I bought a week ago, and during the copy, I received the message following 'destination path too long ".
  And the file name is actually short "crouch" here is a snap of the image:

  http://imgkeep.com/0ij23kby74dn.html

  I don't know what to do!

  Original title: destination path too long?

  The key factor is not the name of the file itself, but the total length of the file name and the path of the folder.

  The help files for the application that you are using could tell you how long the total combination of the file-file may be [some more older can be limited to 255 characters, but I was not able to discover the current constraints].

• How to get the external Bitmap of URL object

  Hi all!

  I'm a developer starting with components of BlackBerry, I try to get a Bitmap of the outer object
  URL, but my getImage method does not work correctly. I think that the problem lies in the getImage method. just at the moment where I try to
  create form of Bitmap bytes. Note: J2me with the Image object, that it works!

  could someone help me please?

  Sorry for my bad English & thank you for helping me!

  Code:

  SerializableAttribute public class MainForm extends form {}

  private String url = "http://user-xxxx/json.js";
  private String [] imageURLs = new String [5];

  public MainForm() {}

  try {}
  getJSON (url);
  } catch (IOException e) {}
  e.printStackTrace ();
  }

  try {}
  Add (GetImage(this.imageURLs[0]));
  } catch (Exception e) {}
  e.printStackTrace ();
  }
  }

  Public Sub getJSON (String url) throws IOException {}
  StringBuffer sb = new StringBuffer();
  InputStream is = null;
  HttpConnection hc = null;
  try {}
  long bytesLength = 0;
  int ch = 0;
  HC = (HttpConnection), Connector.open (url);
  is = hc.openInputStream ();
  bytesLength = hc.getLength ();
  If (bytesLength! = - 1) {}
  for (int i = 0; i)< byteslength;="" i++)="">
  If ((ch = is.read (())! = - 1) {}
  SB. Append ((Char) ch);
  }
  }
  } else {}
  While ((ch = is.read (())! = - 1) {}
  bytesLength = is.available ();
  SB. Append ((Char) ch);
  }
  }
  parseJSON (sb.toString ());
  } {Finally
  is. Close();
  HC. Close();
  }
  }

  {} public void parseJSON (String sb)
  try {}
  JSONObject jo = new JSONObject (sb);
  If (jo! = null) {}
  JSONObject channel = jo.getJSONObject ("channel");
  If (channel! = null) {}
  JSONArray points = channel.getJSONArray("item");
  If (items! = null) {}
  for (int i = 0; i)< items.length();="" i++)="">
  JSONObject point = items.getJSONObject (i);
  this.imageURLs [i] = item.getString ("image");
  }
  }
  }
  }
  } catch (Exception e) {}
  e.printStackTrace ();
  }
  }

  I think that the problem lies in this method.

  public BitmapField getImage (String url) throws Exception {}
  InputStream inputStream = Connector.openInputStream (url) (InputStream);
  Bitmap image = null;
  BitmapField bf = null;
  try {}
  ByteArrayOutputStream Baos = new ByteArrayOutputStream();
  int ch;
  While ((ch = inputStream.read ())! = - 1) {}
  Baos.Write (ch);
  }
  Byte [] imageData = baos.toByteArray ();
  Image = Bitmap.createBitmapFromBytes (imageData, 0, imageData.length, 1);
  BF = new BitmapField (image);
  } {Finally
  If (inputStream! = null)
  inputStream.close ();
  }
  return (bf == null? null: bf);
  }

  public String [] getImageURLs() {}
  Return this.imageURLs;
  }

  }

  Finally my fatal mistake was in archive JSON, I change the URL of the images of http://localhost/image.jpg to
  http://user-xxx/image.jpg (MDS - CS available in http://localhost URL: 8080 /), and now it works!

  Ted and arkadyz, your suggestions have been very helpful for me, thank you very much!

  Final code:

  Class MainMIDlet

  Import net.rim.device.api.ui.UiApplication;

  SerializableAttribute public class MainMIDlet extends UiApplication {}

  public MainMIDlet() {}
  MainForm mf = new MainForm();
  pushScreen (mf);
  }

  Public Shared Sub main (String [] args) {}
  MainMIDlet mm = new MainMIDlet();
  mm.enterEventDispatcher ();
  }
  }

  Class MainForm

  import java.io.ByteArrayOutputStream.
  import java.io.IOException;
  import java.io.InputStream;

  Import javax.microedition.io.Connector;
  Import javax.microedition.io.HttpConnection;

  Import org.json.me.JSONArray;
  Import org.json.me.JSONObject;

  Import net.rim.device.api.system.EncodedImage;
  Import net.rim.device.api.ui.component.BitmapField;
  Import net.rim.device.api.ui.component.LabelField;
  Import net.rim.device.api.ui.container.MainScreen;

  SerializableAttribute public class MainForm extends form {}

  private String url = "http://user-xxx/json.js";
  private String [] jsonTitles = new String [5];
  private String [] jsonImages = new String [5];
  private LabelField lf = null;
  private BitmapField bf = null;

  public MainForm() {}

  try {}
  getJSON (url);
  } catch (IOException e) {}
  e.printStackTrace ();
  }

  LF = getLabelField(this.jsonTitles[0]);
  Add (LF);

  try {}
  BF = getBitmapField(this.jsonImages[0]);
  } catch (Exception e) {}
  e.printStackTrace ();
  }
  Add (BF);

  }

  Public Sub getJSON (String url) throws IOException {}
  StringBuffer sb = new StringBuffer();
  InputStream is = null;
  HttpConnection hc = null;
  try {}
  long bytesLength = 0;
  int ch = 0;
  HC = (HttpConnection), Connector.open (url);
  is = hc.openInputStream ();
  bytesLength = hc.getLength ();
  If (bytesLength! = - 1) {}
  for (int i = 0; i)< byteslength;="" i++)="">
  If ((ch = is.read (())! = - 1) {}
  SB. Append ((Char) ch);
  }
  }
  } else {}
  While ((ch = is.read (())! = - 1) {}
  bytesLength = is.available ();
  SB. Append ((Char) ch);
  }
  }
  parseJSON (sb.toString ());
  } {Finally
  is. Close();
  HC. Close();
  }
  }

  {} public void parseJSON (String sb)
  try {}
  JSONObject jo = new JSONObject (sb);
  If (jo! = null) {}
  JSONObject channel = jo.getJSONObject ("channel");
  If (channel! = null) {}
  JSONArray points = channel.getJSONArray("item");
  If (items! = null) {}
  for (int i = 0; i)< items.length();="" i++)="">
  JSONObject point = items.getJSONObject (i);
  this.jsonTitles [i] = item.getString ("title");
  this.jsonImages [i] = item.getString ("image");
  }
  }
  }
  }
  } catch (Exception e) {}
  e.printStackTrace ();
  }
  }

  public getLabelField (String title) {} LabelField
  LabelField lf = new LabelField (title);
  return of lf;
  }

  public BitmapField getBitmapField (String url) throws IOException {}
  InputStream is = Connector.openInputStream (url) (InputStream);
  BitmapField bf = null;
  try {}
  ByteArrayOutputStream Baos = new ByteArrayOutputStream();
  int ch;
  While ((ch = is.read (())! = - 1) {}
  Baos.Write (ch);
  }
  imageData Byte = baos.toByteArray ();
  BF = new BitmapField (EncodedImage.createEncodedImage (imageData, 0,))
  (imageData.length) .getBitmap ());
  } {Finally
  If (is! = null) {}
  is. Close();
  }
  }
  return (bf == null? null: bf);
  }

  }

• get the variable in a URL returned

  Hello, I have a url returned by a payment Center, and I need to use the information to make the variables of

  for example

  www.website.com/Cancel.php?OrderID=969 & Currency = GBP & amount = 0% 2E01 & PM = & Acceptance = & Status = 1 & = CARDNO & ED = & CN = & TRXDATE = 06% 2F03% 2F13 & PAYID = 719527322 & NCERROR = & BRAND = & IP = 86% 2E130% 2E167% 2F 99 and SHASIGN 8D01371831130CFADEB12345678911391FD8332D6B

  so I need the

  $orderID

  $currency

  $amount

  etc...

  How this is done?

  Thanks in advance

  You use the _GET table to retrieve the query string values. http://www.php.net/manual/en/reserved.variables.get.php

  Jonathan, please bookmark the guide to php: http://www.php.net/manual/en/index.php

  It should be your first stop for basic PHP info.

• The application's command line arguments get the path to the file in windows Explorer

  Hello

  I am trying to open a file with my labview application .exe, so I thought that windows was sending the file path double clicked in Explorer solutions in the form of argument, but all I get is the name of my exe file.

  

  Does anyone know how to set up windows or the application to get the double click path from the Explorer, which has the file extension has already been associated with my exe?

  Thank you!

  I'm not sure I understand, but I think you want your Labview program to open another file, as a file of perimeter?

  Have three basic choices.

  Hardcode the path with file name in your program http://zone.ni.com/reference/en-XX/help/371361K-01/glang/path_constant/

  Use the file open vi and for the user to select the file to open http://zone.ni.com/reference/en-XX/help/371361J-01/glang/file_dialog/

  Write your program to accept a http://digital.ni.com/public.nsf/allkb/17C3AD70493CE0208625666A00763364 command line argument

• How to get the full path using HTP. PRINT ("&lt;" input type = "file")...

  Hello everyone,
  
  I'm working on downloading the page file to another using the package HTP, but whenever I submit the form, it takes only the file name without the full path.
  for example:
  If I sent 'c:\dir\a.txt', the other page receives the parameter file as 'a.txt ".
  
  
  the code is here
  
  
  Download of the PROCEDURE (appno in varchar2, wsct in varchar2) AS
  
  
  
  l_real_name VARCHAR2 (1000);
  
  
  
  
  BEGIN
  
  
  
  
  HTP.htmlopen;
  HTP.headopen;
  HTP.title ("Test Upload'");
  HTP.headclose;
  HTP.bodyopen;
  HTP.header (1, 'Test Upload');
  HTP.print ('< form action = "https://ssltrng.uaeu.ac.ae/trng/document_api.upload1" method = "get" >');
  HTP.print (' download file: < input type = "file" name = "file" >)
  ');
  HTP.print ('< input type = "submit" value = "Upload" >');
  HTP.print ('< activated >');
  HTP.bodyclose;
  HTP.htmlclose;
  
  
  Download END;
  
  the other page see so
  
  file is "water lilies.jpg".
  
  Thank you
  
  Published by: dtabed on March 30, 2011 01:02

  For Internet Explorer 8 and later versions, you must set a security setting to get the full qualified path: see http://msdn.microsoft.com/en-us/library/ms535128.aspx.

  For other browsers, there could be a similar setting.

• How can we get the list of files in a folder?

  Hi all

  My plugin has a list of .ai files in the user interface of the folder C:\Program Files\Adobe\Adobe Illustrator CS4\Plug - ins\Illustrator Filters\MyPlugin.

  Also, if we put 'MyFile.ai' in the folder 'MyPlugin', then the user interface should display the MyFile (file name) in a drop-down list box.

  I want to get the list of files in the folder "MyPLugin".

  Download the plugins to HAVE

  AI::filepath pluginsFolder.

  sAIFolders-> FindFolder (kAIPluginsFolderType,

  fake , pluginsFolder);

  MyPlugin folder

  AI::UnicodeString MyPluginFolder (pluginsFolder.GetFullPath ());

  MyPluginFolder.append (ai::UnicodeString ("\\Illustrator Effects\\Myplugin\\"));

  Here I get the my full path of the folder plugin in "MyPluginFolder".

  Now, this file, I want to get the list of files that I placed?

  What are the APIs available in artificial intelligence to get the list of files in a folder?
  

  If you want to enumerate files in a directory, you have to use the OS APIs. I does not provide for this. There are different ways to find important files/directories related to AI, but nothing else.

  The APIs to do this in the operating system are usually pretty easy to use but. Annoying if you try to hit Mac and Windows, but a little care in the design of your interface and hide the worst.

• How do you get the path of the data store or the URL of a virtual disk in vRealize Orchestrator?

  I need to eager zero a virtual disk while building a virtual machine. I found the eagerZeroVirtualDisk_Task() under VcVirtualDiskManager function, which takes in 2 parameters:

  name - (String) the name of the disk, is a path to the data store or a URL pointing to the virtual disk that needs to be inflated.

  Data Center - (VcDatacenter) if the name is a path of data store, the data center for the path of the data store. Not necessary when called directly on ESX. If not specified on a call to VirtualCenter, the name must be a URL.

  How can I get the correct path of data store given the virtual disk? I intend to iterate through the features of the virtual machine to get the disks.

  Thank you!

  Actually figured out how to get the path of the data store, and how a drive zeros. In case it is useful to share the code here:

  var vimHost = vm.vimHost; VM instanceof VCVirtualMachine

  var vDiskMgr = vimHost.virtualDiskManager;

  for each disk

  var features = vm.config.hardware.device;

  for each {(dev var in devices)

  dev.backing contains a lot of useful things...

  If (dev instanceof VcVirtualDisk) {}

  a disc!

  var dsPath = dev.backing.fileName;

  System.log ("path of disk:" + dsPath);

  Data var Center =

  System.getModule('com.vmware.library.vc.datastore').getDatacenterForDatastore (dev.backing.datastore);

  var vcTask = vDiskMgr.eagerZeroVirtualDisk_Task (dsPath, datacenter);

  wait

  var waitResult =

  System.getModule('com.vmware.library.vc.basic').vim3WaitTaskEnd (vcTask, true, 5);

  }

  }

• How to get the absolute path to a file in photoshop extended?

  Hello

  I try to send a file via an entry inside an extension of Photoshop. But how can I get the absolute path to this file inside the computer?

  Thanks in advance

  I don't know what you mean by sending a file. Do you want to open a file in PS or do I have to declare the path for support for the extension file? With javascript, you must define a variable. In Win it should look like:

  var file = new File('/c/images/myfile.psd');
  

  or

  var myScript = new File(app.path + '/Presets/Scripts/myJavascript.jsx');
  

• CP8 Question: can I get the current URL path in a variable?

  Hello

  I want to get the current. HTM path and name of the file into a variable.

  An example would be http://mycompanyserver/training/health_and_safety/infection_prevention.htm

  I created a user variable called myurl

  In slide 1 to the output, I used some javascript I found on the internet var myurl = window.location.pathname;

  On slide 2, I set a text caption to display the myurl

  I published and took my server project.

  The result was an empty box of legend.

  Please, someone could suggest what I should use.

  (I don't want to use the Captivate system variable $$cpInfoProjectName$ $ like is not what I want)

  Thank you

  Peter

  Cardiff (cold, covered, wind and rain. A dark day)

  In Wales

  UK.

  Run this onSlideEnter of the first slide:

  If (window.cpAPIInterface)

  {

  window.cpAPIInterface.setVariableValue ('myurl', document.location.href)

  }