Get the number of CountItems by group in CS5 extended

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• Get the number of elements in the header in GroupDataModel

  Hey everybody!

  I wonder how to get the number of items in each topic in a GroupDataModel. Here's a code, where headerCount would be the number of items in each section:

  ListView {
              dataModel: _app.dataModel
  
              layout: StackListLayout {                    headerMode: ListHeaderMode.Sticky            }
  
              listItemComponents: [
                  ListItemComponent {
                      type: "header"
  
                      Container {
                          Label {                            text: ListItemData + " " + headerCount                        }
                      }
                  },
                  ListItemComponent {
                      type: "item"
  
                      Container {
                          Label {                            text: ListItemData.cardName                        }
                      }
                  }
              ]
          }
  

  Also here is the code of applicationui.cpp, where it defines the datamodel. It's using GroupDataModel.

  void ApplicationUI::initDataModel()
  {
      // Note: The Group Data Model is joining this objects tree as a child (for memory management)
      m_dataModel = new GroupDataModel(this);
      m_dataModel->setSortingKeys(QStringList() << "cardType");
      m_dataModel->setGrouping(ItemGrouping::ByFullValue);
  }
  

  Hope that makes sense. If you have any questions, let me know!

  This will help you

  https://developer.BlackBerry.com/native/reference/Cascades/bb__cascades__GroupDataModel.html#functio...

  Your header looks like this

  ListItemComponent {
      type: "header"
  
      Container {
          id: rootItem
          Label {
              text: ListItemData + " " + rootItem.ListItem.view.dataModel.childCount(rootItem.ListItem.indexPath)
          }
      }
  }
  ..............
  

  It may be useful

• get the number in the declaration of DBMS

  Hello everyone,

  my friend, I create the following code, but I've always faced a problem to display the result of County all the

  the code is:

  ------------------------------

  I insert a count (*) to get the number of employees

  but he keep get only '1' to the last of the result in the following way:

  DETAILS OF THE EMPLOYEE:

  YJOSEPH5 | YOUSEFJOSEPH | 15 NOVEMBER 15

  HYOUSEF10 | HASSANYOUSEF | 15 NOVEMBER 15

  HYOUSEF17 | HASSANYOUSEF | 15 NOVEMBER 15

  HYOUSEF14 | HASSANYOUSEF | 15 NOVEMBER 15

  HYOUSEF16 | HASSANYOUSEF | 15 NOVEMBER 15

  COUNT: 1

  the code

  ------------------------------------

  DECLARE
  V_USER_ID VARCHAR2 (50);
  NUMBER OF V_EMP_NO;
  V_FIRST_NAME VARCHAR2 (30);
  V_LAST_NAME VARCHAR2 (30);
  DATE OF V_REG_DATE;
  NUMBER OF V_COUNT;
  V_SQL_SATEMENTS VARCHAR2 (1000);
  NCOUNT THE NUMBER;
  CURSOR C IS SELECT USER_ID, EMP_NO, FIRST_NAME, LAST_NAME, REG_DATE, COUNT (*) FROM EMP
  USER_ID, FIRST_NAME, LAST_NAME, EMP_NO, REG_DATE GROUP;
  BEGIN
  OPEN C;
  SELECT COUNT (*) FROM NCOUNT FROM USER_TABLES WHERE TABLE_NAME = 'EMP ';
  IF (NCOUNT < = 0) THEN
  V_SQL_SATEMENTS: =' CREATE TABLE EMP)
  USER_ID VARCHAR2 (40) PRIMARY KEY,.
  NUMBER OF EMP_NO,
  FIRST NAME VARCHAR2 (30),
  VARCHAR2 (30) LAST_NAME,.
  DATE OF REG_DATE)';
  
  RUN IMMEDIATELY "DROP TABLE EMP;
  IMMEDIATELY RUN V_SQL_SATEMENTS;
  END IF;

  SELECT NVL (MAX (EMP_NO), 0) + 1
  IN V_EMP_NO
  YOUSEF. EMP;
  INSERT YOUSEF. EMP (USER_ID, EMP_NO, FIRST_NAME, LAST_NAME, REG_DATE)
  VALUES (SUBSTR (: LAST NAME, 1, 1) |: LAST_NAME |) V_EMP_NO, V_EMP_NO,:FIRST_NAME,:LAST_NAME,TO_DATE(SYSDATE,'DD-MON-YY'));
  DBMS_OUTPUT. PUT_LINE (' DETAILS OF THE EMPLOYEE: "");
  LOOP
  EXTRACT THE C IN V_USER_ID, V_EMP_NO, V_FIRST_NAME, V_LAST_NAME, V_REG_DATE, V_COUNT;
  WHEN THE EXIT %C NOTFOUND;

  DBMS_OUTPUT. PUT_LINE (V_USER_ID |'|) ' || V_FIRST_NAME | V_LAST_NAME |' | ' || V_REG_DATE);
  END LOOP;
  DBMS_OUTPUT. PUT_LINE ("COUNT:" | "|") V_COUNT);

  CLOSE C;
  END;
  /

  ALL FRIENDS,

  THANKS FOR EVERY BODY,

  I JUST FOUND THE RIGHT WAY TO DO

  FOR THOSE WHO WANT TO SEE:

  -----------------------------------------------------------

  DECLARE
  V_USER_ID VARCHAR2 (50);
  NUMBER OF V_EMP_NO;
  V_FIRST_NAME VARCHAR2 (30);
  V_LAST_NAME VARCHAR2 (30);
  DATE OF V_REG_DATE;
  NUMBER OF V_COUNT;
  V_SQL_SATEMENTS VARCHAR2 (1000);
  NCOUNT THE NUMBER;
  CURSOR C IS SELECT USER_ID, FIRST_NAME, LAST_NAME, EMP_NO FROM EMP REG_DATE;
  BEGIN
  SELECT COUNT (*) IN THE EMP V_COUNT;
  OPEN C;
  SELECT COUNT (*) FROM NCOUNT FROM USER_TABLES WHERE TABLE_NAME = 'EMP ';
  IF (NCOUNT<=0)>
  V_SQL_SATEMENTS: =' CREATE TABLE EMP)
  USER_ID VARCHAR2 (40) PRIMARY KEY,.
  NUMBER OF EMP_NO,
  FIRST NAME VARCHAR2 (30),
  VARCHAR2 (30) LAST_NAME,.
  DATE OF REG_DATE)';
                                           
  RUN IMMEDIATELY "DROP TABLE EMP;
  IMMEDIATELY RUN V_SQL_SATEMENTS;
  END IF;

  SELECT NVL (MAX (EMP_NO), 0) + 1
  IN V_EMP_NO
  YOUSEF. EMP;
  INSERT YOUSEF. EMP (USER_ID, EMP_NO, FIRST_NAME, LAST_NAME, REG_DATE)
  VALUES (SUBSTR (: LAST NAME, 1, 1) |: LAST_NAME |) V_EMP_NO, V_EMP_NO,:FIRST_NAME,:LAST_NAME,TO_DATE(SYSDATE,'DD-MON-YY'));
  DBMS_OUTPUT. PUT_LINE (' DETAILS OF THE EMPLOYEE: "");
  LOOP
  EXTRACT THE C IN V_USER_ID, V_EMP_NO, V_FIRST_NAME, V_LAST_NAME, V_REG_DATE;
  WHEN THE EXIT %C NOTFOUND;

  DBMS_OUTPUT. PUT_LINE (V_USER_ID |'|) ' || V_FIRST_NAME | V_LAST_NAME |' | ' || V_REG_DATE);

  END LOOP;

  CLOSE C;
  DBMS_OUTPUT. PUT_LINE ("COUNT:" | "|") V_COUNT);

  END;
  /

• How do I get the number of minutes each

  Oracle DB 10
  
  Hi all
  
  
  I have using this query to get the number of records retrieved by the simultaneous min program,
  
  SELECT count (distinct b.attribute2)
  oe_order_headers_all a, oe_order_lines_all b
  where a.header_id = b.header_id
  and b.flow_status_code = 'AWAIT_QUINTIQ_BOOK. '
  and to_Char (b.last_update_date, 'DD-MON-YYYY HH24:MI:SS'), between January 19, 2011 02:00:01 ' AND
  JANUARY 19, 2011 02:00:02 '
  
  This allows to get the number of records retrieved in a min.
  
  How to find the count of the last 10 minutes, IE 1 mins County 2.00 to 2.10
  
  
  Thanks and greetings
  Srikkanth.M

  This South for minute work wise County:

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• Requirement of Beeping - how to get the number of combination of several columns

  Hi gurus, Experts and all,.
  
  Help me please how this code to the BEEP.
  
  I need to get the number of each combination of 6 columns if the combination is repeated.
  
  Columns example: number team responsible for Group Type reason
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  GroupA Team1 H2 M2 T1 loss 1
  GroupB Team2 H2 M3 T2 won 1
  GroupB Team2 H3 M3 T2 loss 2
  
  Thank you very much
  
  Jean Paul
  BEEP newbie
  
  Published by: user10955574 on October 28, 2010 20:15
  
  Published by: user10955574 on October 29, 2010 03:06

  I sent you the file. Check your mailbox.

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  AMT for Linux: Version 11.2.0.1.0 - Production

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  2621671 wrote:

  Hi all

  My need is to get the number of the day of the week - any national local is used.

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  ...

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