Get the number of days in a month based on the month and year of fields

Similar Questions

• How to get the maximum number of days in a month?

  How to get the maximum number of days in a month?

  I use a dateField. where I can get the month. Now, I want to get the maximum number of days in a month.

  How can I get it?

  Please help me. and thanks in advance... []

  NET. RIM. Device.API.util
  Class DateTimeUtilities

  getNumberOfDaysInMonth (int month, int year)
  Returns the number of days in the specified month

  It took me like 10 seconds to find it in the API, I guess you spent more time writing the post...

• Get the number of days, months and year

  Hi all
  
  I'm using OBIEE 11 g. I have a line of dash for year (2010, 2011, etc.) and months (Jan, Feb,..., Dec). How can I get the number of days in a given month and year in my report?
  
  For example, if I choose to Jan & 2011, I'd get 31 and 356. And if I choose Feb & 2011, I would get 28 and 356.
  
  Thank you!

  I have something more good option here... Try to use this

  DAYOFMONTH (TIMESTAMPADD (SQL_TSI_DAY, DAYOFMONTH (CURRENT_DATE) *-1, TIMESTAMPADD (SQL_TSI_MONTH, 1, CURRENT_DATE)))

  This will give you the days for the month in progress (Oct 2011) after calculating the last day of each month... Similary dynamically pass the value Date or month... You will need to modify this function but shud be simple. Hope this helps :)

• Get the first and the last day of the month...

  Hi friends,
  
  I'm trying to get the first and last day of a month and wants to implement that in the following code:
  
  SELECT COALESCE (Date_A, Date_B, Date_C)
  OF the double
  
  Here Date A and B are in Format DD MM YYYY (March 14, 2008)
  and Date like MM YYYY (March 2008)
  
  How can I get the Date_C as of March 1, 2008, OR March 31, 2008 if Date A and B are NULL?
  
  Thank you!
  
  Published by: user11095386 on April 23, 2009 10:45

  Hello

  In my previous message, I thought that you were starting with strings like ' 03 12 2009"and you want to display in the form of" 12 March 2009'.» If what you have is just the opposite, then simply reverse strings format in my first message. Add a comma, if you want, in the format string.
  I think that's what you want:

  COALESCE ( TO_CHAR ( TO_DATE ( Date_A, 'fmMonth DD YYYY'), 'MM DD YYYY')
           , TO_CHAR ( TO_DATE ( Date_B, 'fmMonth DD YYYY'), 'MM DD YYYY')
           , TO_CHAR ( TO_DATE ( Date_C, 'fmMonth YYYY'),    'MM DD YYYY')
           )
  

  Notice how, on the 3rd line, TO_DATE is called without DD in the format string:

  TO_DATE ( Date_C, 'fmMonth YYYY')
  

  When you do so, by default the day the 1st of the month, so that's all you need to do to convert the VARCHAR2 'March 2009' at the DATE of March 1, 2009.

  If you would like the last day of the month, not the first, when Date_C is selected, then use LAST_DAY:

  COALESCE ( TO_CHAR ( TO_DATE ( Date_A, 'fmMonth DD YYYY'), 'MM DD YYYY')
           , TO_CHAR ( TO_DATE ( Date_B, 'fmMonth DD YYYY'), 'MM DD YYYY')
           , TO_CHAR ( LAST_DAY ( TO_DATE ( Date_C
                                            , 'fmMonth YYYY'
                              )
                       )
               , 'MM DD YYYY'
               )
           )
  

• I want to collect rain for the day, month and year; Can what formula I use?

  I want to collect rain for the day, month and year; What formula or expression that I can use.

  I use a Rain Wise product that converts impulses to an analog value.  The rain wise device can be

  "the value measure up to 1", 5", or 10".  I will be setting the unit at 10 inches in increments of 0.01 inch.

  What I would do is at each time increments of signal I would consider it as 0.01 then after reaching

  a period of time a day or a month, back to zero.

  Need some advice on this problem.

  How about you, using a counter to count the number of times where the signal is less than 0.01?

  For example,.

  Counter.Count = signal<=>

  The total number of rain is

  Counter * 10 + signal

  Use TimeOfDay or TimeOfWeek to reset the counter.

• Get the firstday and last month lastday

  Hello
  
  How to get the first and last day of the last month?
  
  I've used this, but it returns January 1, 2010
  
  FirstDay:
  Select TRUNC (SYSDATE, 'year') of double
  
  LASTDAY:
  Select LAST_DAY (ADD_MONTHS (SYSDATE-1)) of the double

  You're close

  SQL> select TRUNC(ADD_MONTHS (SYSDATE, -1),'month') fom,
    2         LAST_DAY(ADD_MONTHS (SYSDATE,-1)) eom
    3  from dual;
  
  FOM       EOM
  --------- ---------
  01-DEC-09 31-DEC-09
  

  John

• Set the calendar to display day, month and year

  In addition to the time of day, my computer began giving the day of the week (Monday) only instead of day, month and year as it did before. Tried to go back to 29/12/2014 or something similar without success.  Any suggestions?

  Hello

  Sorry for the late reply and I appreciate your patience.

  User profile corruption might have caused the problem. As a solution, I suggest to create a new user profile and check if the date format displays the same thing.

  To do this, see the link below.

  http://Windows.Microsoft.com/en-us/Windows/fix-corrupted-user-profile#1TC=Windows-7.

  It will be useful. Just answer us with the State, and we will be happy to help you.

• How to get the second and third weekend of every month over a period of time?

  Hello

  No idea how to get the second and third weekend of every month on a given period without use of CLAUSE?

  Thanks in advance.

  Try it below,

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  THEN ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)) + 1

  WHERE TO_CHAR (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), 'DY') = 'Sun '.

  THEN ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)) + 6

  Of OTHER NEXT_DAY (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), "SAT") + 1

  END as second_weekendday,

  BOX WHEN TO_CHAR (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), 'DY') = 'SAT '.

  THEN ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)) + 7

  WHERE TO_CHAR (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), 'DY') = 'Sun '.

  THEN ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)) + 7

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  END AS third_weekendday

  FROM (SELECT SYSDATE startdate,

  SYSDATE + 300 enddate

  THE DOUBLE)

  CONNECT BY LEVEL<=>

• get the month and year of date type

  Hi all
  I need to get the month and year of type date.
  
  For example

  select to_date('2011-01-17', 'yyyy-mm-dd') from dual;

  Required result:

  01-2011

  Any ideas?
  
  Thanks in advance,
  Bahchevanov.

  select to_char(to_date('2011-01-17', 'yyyy-mm-dd'),'mm-yyyy') from dual;
  

  HTH

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  with values like Apr.-2008
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  can I get the distinct month and year separated

  i tried select to_date(entry_date_fin,'MM') FROM  xyz  doesnt wrk

  kindly guide me

  Although you are (wrongly, IMO) storage of dates as strings, just use string manipulation...

  SQL> with t as (select 'FEB-2008' as txt from dual)
    2  --
    3  select substr(txt,1,3) as mnth
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  for example, the date is 18/09/2012, but I want to just insert 09/2012 as a parameter. If I want to insert only one setting, I can do... But I have problem when I want to insert two parameters...

  Lina saleh wrote:
  I already try before that and he invites me error like this...
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  Is a reserved keyword.

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