get the month and year of date type

Similar Questions

• to get the month and year separated

  Hello
  
  I have the entry_date_fin of column (type of data-varchar2 (8))
  
  with values like Apr.-2008
  Feb-2009 etc.
  
  can I get the distinct month and year separated

  i tried select to_date(entry_date_fin,'MM') FROM  xyz  doesnt wrk

  kindly guide me

  Although you are (wrongly, IMO) storage of dates as strings, just use string manipulation...

  SQL> with t as (select 'FEB-2008' as txt from dual)
    2  --
    3  select substr(txt,1,3) as mnth
    4        ,substr(txt,5) as yr
    5  from t
    6  /
  
  MNT YR
  --- ----
  FEB 2008
  
  SQL>
  

• Get the number of days in a month based on the month and year of fields

  I have a column in my form which lists the days in a month. I want to configure a hidden field that calculates the total number of days in a month, based on the month and year of the field inputs. The number of days will determine what appears on the column. For example, if I put 4 months, and 2016 in the field of the year, I get 30 in the hidden field. Thus, on the column 'Day', I'll have numbers 1-30. Or if I put 2 months and 2016 in the field of the year, I get the 29 in the hidden field. If the numbers 1-29 appears in the column 'day '.

  Found this on some forum javascript code:

  //Month is 1 based
function daysInMonth(month,year) {
   return new Date(year, month, 0).getDate();
}

//July
daysInMonth(7,2009); //31
//February
daysInMonth(2,2009); //28
daysInMonth(2,2008); //29

  I do not know how to convert this code in JavaScript to adobe and don't really know how to use it. All I know how to do is to configure the field values for the field month and year as variables. I am a novice programmer and would appreciate it really all the help I can get. Thank you in advance!

  The code seems to be JavaScript and runs as needed by using the JavaScript console.

  I would like to consider making more general code, so if you have a date string that includes at least the month and year we could just call the function and get the number of days for that month.

  The following script will calculate the number of days in a month, by using at least the month and year values can display the result on the JavaScript console and all of the value field for the field that has this code as the custom calculation Script.

  function daysInMonth (oDate) {}
  return new Date (oDate.getFullYear (), oDate.getMonth () + 1, 0) .getDate ();
  }

  nMonth var = this.getField("Month").valueAsString; get the value of month;
  nYear var = this.getField("Year").valueAsString; get the value of the year;

  Event.Value = "";

  If (nMonth! = "" & nYear!) = "") {}
  var MyDate = util.scand ("' / mm/yyyy ', nMonth +" / "+ nYear); convert to date object;
  var nDaysInMonth = daysInMonth (MyDate); get the number of days;

  Console.Open (); Open the JavaScript console;

  Console.clear(); clear the console;

  Console.println ("Days in" + nMonth + ":" + nDaysInMonth); show days in month;

  Event.Value = nDaysInMonth; Set the value of the field;

  }

• Hide the 0 before the month and year

  I m using this query to generate the sequence

       SELECT     TO_CHAR (SYSDATE, 'MM')
                           || TO_CHAR (SEQ.NEXTVAL)
            || TO_CHAR (SYSDATE, 'YY')
            
        FROM   DUAL;

  The result is
  

  0612109

  06 is the month
  121 is the sequence
  09 is the year
  
  I want to hide 0 before the month and the year also.
  
  Looks like this
  
  * 61219 *.

  if here Month is 10 and year is 2010
  
  then It will display
  1021110
  

  Try this

  SQL> SELECT     ltrim(TO_CHAR(to_date('12-10-2010','dd-mm-yyyy'), 'MM'),'0')
    2       || TO_CHAR (SEQ.NEXTVAL)
    3            || ltrim(TO_CHAR (to_date('12-10-2010','dd-mm-yyyy'), 'YY'),'0') format_date
    4           FROM   DUAL;
  
  FORMAT_DATE
  --------------------------------------------
  1026010
  

• Today's date in the month and year

  Dear experts,
  
  I have a year and the number of the day, I wanted to identify the date
  ex: number of days = 203 year = 2009
  Date: 22/07/2009
  
  Please advice the best way possible to achieve.
  
  Thank you

  Dear user!

  Please try this code.

  SELECT TO_DATE(2032009, 'DDDYYYY') as dateval
  FROM   dual;
  
  DATEVAL
  -------------------
  22.07.2009 00:00:00
  

  This figure first three are the day number and the last four digits are the year. The DDD format will give you the day and the month as JJ.MM. YYYY format join the year your date. To do this, try:

  SELECT TO_DATE(2032008, 'DDDYYYY') as dateval
  FROM   dual;
  
  DATEVAL
  -------------------
  21.07.2008 00:00:00
  

  Yours sincerely

  Florian W.

  Published by: Florian W. the 22.07.2009 08:40

• How to get the month previous year?

  Hello

  I have to get the previous year three-months of the effective date, but I have a problem since the beginning of the year and it's because I set the incorrect query.

  I mean:

  I wrote this query

  SELECT TO_CHAR(SYSDATE,'YYYYMM')-1, 2-TO_CHAR(SYSDATE,'YYYYMM'), TO_CHAR(SYSDATE,'YYYYMM')-3

  FROM DUAL;

  in order to get (on mars):

  201502, 201501, 201412

  but unfortunately, I get:

  201502, 201501, 201500

  Can you help me?

  Thanks in advance!

  Hello

  Here's one way:

  SELECT TO_CHAR (ADD_MONTHS (SYSDATE-1), "YYYYMM") AS the m1

  , TO_CHAR (ADD_MONTHS (SYSDATE-2), "YYYYMM") AS m2

  , TO_CHAR (ADD_MONTHS (SYSDATE,-3), "YYYYMM") M3

  DOUBLE;

• Aggregation of week, month, and year to date

  Nice day
  
  I have a requirement which led to thinking me where I summarize the value of sales at three levels - year_to_date, month_to_date and week_to_date. It's easy for me to represent the annual and monthly version, I need to do a bit of logic to get the weekly Variant.
  
  The function definitions are
  
  year_to_date: sum up the record sales since January 1 to sysdate
  month_to_date: summarize all record sales of the 1st of the current month to sysdate
  week_to_date: summarize all record sales of 12: 00 a.m. Monday in the current week to sysdate
  
  Is that they are all these functions sql oracle to achieve? I googled and also search for the oracle 10g R2 sql reference and did not find what I was looking for? Does anyone know a web reference where I could find a solution.
  
  
  table definition
  =============
  
  ID number (6)
  date of trans_date
  number of sales_value (15: 4)
  receipt_no varchar2 (20)
  
  
  Thank you

  SQL> create table mytable (id,trans_date,sales_value,receipt_no)
    2  as
    3  select 1, date '2009-07-01', 10, 'A' from dual union all
    4  select 2, date '2010-01-01', 20, 'B' from dual union all
    5  select 3, date '2010-04-01', 30, 'C' from dual union all
    6  select 4, date '2010-09-02', 40, 'D' from dual union all
    7  select 5, date '2010-09-11', 50, 'E' from dual union all
    8  select 6, date '2010-09-13', 60, 'F' from dual union all
    9  select 7, date '2010-09-13', 70, 'G' from dual
   10  /
  
  Table created.
  
  SQL> select sum(sales_value) ytd
    2       , sum(case trunc(trans_date,'mm') when trunc(sysdate,'mm') then sales_value end) mtd
    3       , sum(case trunc(trans_date,'iw') when trunc(sysdate,'iw') then sales_value end) wtd
    4    from mytable
    5   where trans_date >= trunc(sysdate,'y')
    6  /
  
         YTD        MTD        WTD
  ---------- ---------- ----------
         270        220        130
  
  1 row selected.
  

  Kind regards
  Rob.

• Error definition day LOV based on the month and year

  Select ' 1 ', ' 01' day_aff union double val
  ...
  Select '29', ' 29 "double where '29' < = to_char (last_day (to_date ('01.' |)))" '02'. '.' || (((', 'dd.mm.yyyy')), 'jj') union
  Select '30', ' 30 "double where '30' < = to_char (last_day (to_date ('01.' |)))" '02'. '.' || (((', 'dd.mm.yyyy')), 'jj') union
  Select '31', '31' from dual where '31' < = to_char (last_day (to_date ('01.' |))) '02'. '.' || (((', 'dd.mm.yyyy')), 'jj')
  order by 2
  
  That works well.
  
  If I replace '02' by: P10_MONTH & P10_MONTH. or v ('P10_MONTH') and 2008 by: P10_YEAR & P10_YEAR. or v ('P10_YEAR'), I get the following error on the creation of LOV (in shared components or LOV section of the element):
  
  LOV query is not valid, a display and a return value is needed, the column names must be different. If your query contains a query online, the first CLAUSE in the SQL statement must not belong to the query online.
  
  No work around?
  
  Igor

  Hi Igor,.

  I think it's the | in the SQL that is causing the problem. You can get around this by the presence of a hidden page element which is calculated at the point of process before header which calculates the first day of the selected month.

  I did it on this page: [http://apex.oracle.com/pls/otn/f?p=35917:16]

  In addition, you can simplify your SQL statement to something like:

  SELECT LEVEL d, LEVEL r
  FROM DUAL
  CONNECT BY LEVEL <= TO_NUMBER(TO_CHAR(LAST_DAY(TO_DATE(v('P16_FIRSTDATE'),'DD/MM/YYYY')),'DD'))
  

  (P16_FIRSTDATE is the element that contains the calculated date)

  Andy

• Query to get the numbers and percent by date range

  11g version.
  
  Hello
  
  I have the following data in the format
  

  Opty_Id        creation_date               user          accepted_flag 
  
  1         01-mar-2013                  ryan                  N
  2         02-mar-2013                  sam                   Y
  3         02-mar-2013                  ryan                   Y
  .
  .
  .

  I want to get all the charges and % of all users who have accepted_flag the value n. basically, users who have not yet accepted in the format of Opty_id.
  

  ageing             count        Percentage
  0-20 days          1                 10%(this will offcourse depend on the total number of opty id and then out of that how many did not accept within the given period.
  21-40 days        0                  0%
  41-60 days        0                  0%

  The column of aging is creation_date, basically, how much body id, were created between now and 20 days, 21-40 and 41-60 days and have not yet accepted (accept the flag = N)
  
  
  Any help please.
  
  Thank you
  Ryan

  I get other results

  with t as (select 1 as opty_id, to_date('01/03/2013','DD/MM/YYYY') as date_created, 'ryan' as auser, 'N'  as accepted_flag from dual union all
             select 2, to_date('02/03/2013','DD/MM/YYYY'), 'sun', 'Y' from dual union all
             select 3, to_date('03/02/2013','DD/MM/YYYY'), 'sun', 'Y' from dual union all
             select 4, to_date('02/01/2013','DD/MM/YYYY'), 'ryan', 'N' from dual union all
             select 5, to_date('03/01/2013','DD/MM/YYYY'), 'tom', 'Y' from dual)
  
  select
   decode(grp,1,0,grp*20-19)
   ||'-'||
   grp*20
   ageing
  ,sum(case accepted_flag when 'N' then 1 else 0 end) count
  ,sum(case accepted_flag when 'N' then 1 else 0 end)
  /sum(sum(case accepted_flag when 'N' then 1 else 0 end)) over () Percentage
  from
  (select
   ceil(decode((trunc(sysdate) - date_created),0,1,trunc(sysdate) - date_created)/20) grp
  ,date_created
  ,accepted_flag
  from  t
  )
  group by
  grp
  
  AGEING     COUNT     PERCENTAGE
  "0-20"     "1"     "0,5"
  "21-40"     "0"     "0"
  "41-60"     "0"     "0"
  "61-80"     "1"     "0,5"
  

  Published by: chris227 on 04.03.2013 03:41
  Modified according to response below

• How to find the sum of the month and year of a date

  Hi all
  
  I want to find the sum of the date
  for example, 10 November 2010 I need to find (11-2010).
  
  Please help me

  You can use the extract function...

  SQL> select extract(month from systimestamp)+extract(year from systimestamp) from dual;
              EXTRACT(MONTHFROMSYSTIMESTAMP)+EXTRACT(YEARFROMSYSTIMESTAMP)
                                      ------------------------------------------------------------
                                                          2021
  

  Concerning
  Renjith Malet

• problem to insert only month and year instead of the full date

  select b.penjara_id, p.penj_lokasi, a.no_daftar, b.episod, b.nama1,to_char(a.trkh_mula_prl,'dd/mm/yyyy') as trkh_mula_prl, to_char(bulan_proses,'mm/yyyy') as bulan_proses,
          b.epd, b.lpd
  from prl_daftar_proses a, senarai_pesalah b, penjara p
  
  where a.no_daftar=b.no_daftar
  and a.episod=b.episod
  and b.penjara_id = p.penjara_id
  and a.setuju_jplp is null
  and a.bulan_proses between to_date(:FROM,'dd/mm/yyyy') and to_date(:TO,'dd/mm/yyyy')
  
  
  order by b.penjara_id, a.bulan_proses,a.no_daftar

  Hi, can someone help me how I can register only the month and year of the value which have full day in the database?
  
  for example, the date is 18/09/2012, but I want to just insert 09/2012 as a parameter. If I want to insert only one setting, I can do... But I have problem when I want to insert two parameters...

  Lina saleh wrote:
  I already try before that and he invites me error like this...
  "name of the invalid host/identification variable.

  Change the name of the connection variable to: from_date and: to_date

  Is a reserved keyword.

• How to set the filter criteria for the month and the year to aid in the timestamp input field?

  Hello

  I use jdev 11.1.2.3.

  I have a problem with the generation of reports, I have a report table that is in the form of VO (query based) and I want to search this table in the month and year of the basic

  but in this table (query) This timestamp field of having value based on... How to do a search with the name of the month and year only... Here I totally use vo base query to generate a

  reports... Anyone can guide me.

  Thank you.

  I want to create a drop-down list for month + year as an executable parameters with bind variable no matter what idea this subject, my attribute here is TimestampFormat.

  Then add to your sql query something like:

  WHERE extract (your_timestamp_column MONTHS) =: monthBindVar

  OR an extract (YEAR your_timestamp_column) =: yearBindVar

  and add monthBindVar and yearBindVar as a bind variable to your view object.

  Then you can use it as a ExecuteWithParams operation (or manually set these bind variables and execute the query)

  Dario

• Get the number of days, months and year

  Hi all
  
  I'm using OBIEE 11 g. I have a line of dash for year (2010, 2011, etc.) and months (Jan, Feb,..., Dec). How can I get the number of days in a given month and year in my report?
  
  For example, if I choose to Jan & 2011, I'd get 31 and 356. And if I choose Feb & 2011, I would get 28 and 356.
  
  Thank you!

  I have something more good option here... Try to use this

  DAYOFMONTH (TIMESTAMPADD (SQL_TSI_DAY, DAYOFMONTH (CURRENT_DATE) *-1, TIMESTAMPADD (SQL_TSI_MONTH, 1, CURRENT_DATE)))

  This will give you the days for the month in progress (Oct 2011) after calculating the last day of each month... Similary dynamically pass the value Date or month... You will need to modify this function but shud be simple. Hope this helps :)

• Get the name and the data type into an object?

  Hello

  I would like to know if there is a way to get the names and the types of data encapsulated in an object of labview?

  For example, let's say I make a simple object, called myObject to be commonplace, with private data: myObjectName (string), myObjectValue (int 32) (etc.)

  So, how to build a method to return the type of the data of myObjectValue, or infact back the names and types of all data in the object field, which could be a lot?

  Thank you

  Paul.

  
  

• How can I order a list first for the year and sort the months each year?

  Hello

  I created a report that lists a number of items grouped by month, although elements it since 2012 so together and you spend your order is strange because the groups to report on 2 months.

  example:

  2013 - 01-50

  01/2012 - 56

  02/2013 - 45

  02/2012 - 54

  .

  .

  .

  How do I ordernar first a year and and sort the months each year?

  Sort by DATE... not VARCHAR2

  It is a thing of database, not an APEX.

  In your select statement to the report, the column for DATE information must be one data type DATE or another...

  MK

  PS - TRUNC (a_date_column, 'MONTH')