Get the position of the selected layer and anchor

Similar Questions

• How to get the selected text in a TextInput

  Hallo. I have a textinput, and when the event doubleclick on a part of the text is sent, I need to get the selected text, and then save it in a string... How can I do?

  THX

  Max

  Hi Maximist,

  Below is the code snippet to get the selected text in TextInput on double click event:

  http://www.Adobe.com/2006/mxml '.

  Layout = "vertical".

  verticalAlign = "middle".

  backgroundColor = "white" >

  Import mx.controls.Alert;

  private void textInput_doubleClick(evt:MouseEvent):void {}

  Alert.Show (String (evt.target.text) .slice (evt.target.selectionBeginIndex, evt.target.select ionEndIndex));

  }

  ]]>

  Text = "the Bullfighter is out the path of the bull charge at the last moment, drawing the cheers of the spectators."

  doubleClickEnabled = "true".

  doubleClick = "textInput_doubleClick (event); "/ >

  Hope this will help you.

  Thanks and greetings

  ------------------------------------------------------------------------------------

  Pooja Kuber | [email protected] | www.infocepts.com

  ------------------------------------------------------------------------------------

• How to get the selected DataGrid item?

  Hello
  
  I have a datagrid
  
  < mx:DataGrid = "10" XY = dataProvider "36" = "{acEmaillist}" width = "319" >
  < mx:columns >
  < mx:DataGridColumn headerText = "Full name" dataField = "cn" width = "150" / >
  < mx:DataGridColumn headerText = "Email" dataField = "mail" width = "150" / >
  < / mx:columns >
  < / mx:DataGrid >
  
  I want to select a name, click it, get the selected name and save it in a string variable. Please let me know how to get the selected name when I click it. Thank you very much.
  
  M

  This code can help.

  
  http://www.Adobe.com/2006/mxml"width ="100% ">
  
  Import mx.controls.DataGrid;
  Import mx.events.ListEvent;

  [Bindable]
  private var nameStr:String;

  public void getName(event:ListEvent):void {}
  var dg:DataGrid = DataGrid (event.target);
  nameStr = dg.selectedItem.cn;
  }
  ]]>
  
  
  
  Bob Smith
  [email protected]
  
  
  Ted Alan
  [email protected]
  
  
  Fred Tobs
  [email protected]
  
  

  
  
  
  
  
  
  
  

• Get the "selected lines" value after sql custom query in the database adapter

  We execute a custom query in a database adapter. With other technologies (JDBC, etc.) the result of a query produces not only a game but the number of lines selected results. For example, the output of the script of Oracle SQL Developer will display something like:
  
  9999 selected lines
  
  at the end of the output of the script.
  
  I would like to obtain this value for a BPEL process. Of course, I could run a 2nd interview whose where clause is identical to the first, but select count (*) instead. However, it is not only ineffective but (in rare circumstances in an active database) could be the problem.
  
  It is not obvious to the novice BPEL how to get the selected value and the result set row in an Invoke. Is this possible?

  Maybe it's not the only solution - but this is how I did in the past.

  After step to invoke the adapter, use a step of the having-right/copy to fill a variable of integer type BPEL using the xpath count function...

  
  
  
  
  
  

  That should affect the number of records returned by the query.

  I hope this helps.

  Rod.

  Published by: Tunnels of Rod on December 15, 2009 13:16

• Help, please! I can't select the shape I drew with the pentool again... I have the selected layer, but there is no sign of my new shape in my path Panel?  I have been sitting here for days literally and simply cannot make it appear the race that I created

  HI - can help I'm going crazy! !

  I drew a shape with the tool pen (which took me Age..) and I go back an image that I imported, I cannot select once again it.  I can see it in red, but I'm not able to select once again it.  I have the selected layer, but there is no sign of it in my Panel of traces at all.  I tried clicking on the direct Selection tool (about 100 times), I tried the Brush tool.  I've tried everything.  The same thing happened to me the other day...    Please can someone help!  Tania

  It's the plug technique on the subject:

  Using Photoshop | Manage paths

  It contains this point under manage paths:

  When using a shape or pen tool to create a work path, the new path appears as the work path in the tracks Panel. The work path is temporary; You must save it to avoid losing its contents.

  OK, the red, you mentioned is a Stoke you added. Then quick mask is not involved.

• I have the move tool and the selected layer...

  but for some reason, I can't text to line up anywhere. The alignment buttons act as if they are grayed out. Is there something that I am missing?

  There are at least two selected layers (the text layer and the background layer) or the text layer and a selection (i.e. Select all...) for alignment controls and buttons to activate and go down the text of the document.

• keyboard shortcut. (period) disable the classification in the selected layer

  I can't get my keyboard shortcut to disable the selected layer of ranking to work. Windows has the same Mac keyboard shortcut and I'm Windows.

  I use full screen and want to turn off a layer classification but cannot. I have to go back to the main panels and turn off the eyeball for the selected layer.

  Is it me who can not get this keyboard shortcut from. (period) to work?

  If I go on my pad and think that the. (period) is there, I find myself remove the selected layer using what, in my view, could be the. (period) there.

  This keyboard shortcut was reassigned and I use a pdf of Speedgrade obsolete reference? But this one is 10/12/2014.

  Everything could find your question! Re-entered Sg, played with touches of 'standard' period and paved num. Then tried to turn the NumLock... then, rather than being a temp power gimbal, the period key just to delete the layer selected. Not like a rocker... just delete the layer. Had to go back to history (Ctrl/Com - H) back on my bed.

  Then... you can check the status of your caps lock...

  Neil

• How to get the selected layers?

  Hi, how can I use the SDK for a list of the layers that are selected by the user when the plugin is activated?

  Let's talk terminology.

  an "activation" on a layer effect is not really the process of events.

  When an effect is used firstly to æ session, this is the function GlobalSetup()

  is called.

  This is the most 'activated' like thing in the effect by applying the process.

  This function is called only once per session (in general) and data

  allocated to it is shared between all instances.

  then, whenever a new instance is applied, the specific instance

  Function SeqeunceSetup() is called.

  It is the only clue you get tell you that a new instance is created.

  Unfortunately, in the course of this appeal you still cannot check the layer on which

  the effect will be applied, as at that time there AE still because preparations

  and has not done this topic yet. (try to get the effect layer will

  give an error)

  so when you say "on" I'm assuming you mean "applied".

  If an instance of the effect is already present in an economy effect, you get not one

  Call of SequenceSetup(), but a SequenceResetup() call instead. (or Unflatten())

  now, to detect if another instance is present on a layer, you must analyze

  This layer effects and check each because it is installed a key. (and match

  to you, of course)

  you will need to use:

  AEGP_GetLayerNumEffects

  AEGP_GetLayerEffectByIndex

  AEGP_GetInstalledKeyFromLayerEffect

  and now you hit the real problem.

  an effect cannot remove another effect of the same layer, sure it is. It will be

  very probably launch an error message as AE manages all the layer effects

  and suddenly; y an is missing.

  You can solve that by using a CEAP separated with a slow hook and make the

  deletion, or all just throwing your own message to the user by saying

  You cannot have two and set a flag on the second instance of turn it off

  process.

• Problem with 'Create new Extrusion of the selected layer' CC 2014

  Hello, I am experienced with Photoshop but I'm new to 3D text in Photoshop.  I type the text and convert it to a form.  When I choose to create new Extrusion of the selected layer I get the dialog, I don't see in tutorials.  It says "you are about to create a 3D layer.  You want to switch to the 3D workspace?  Yes/No, do not display again. "Which one should I use for the 3D text?

  If I choose Yes, all the panels disappear and the content in the tool options bar (Ribbon?) just under the menu bar disappears.  I have to restart Photoshop to get back on the tool options.  What could I do it wrong?

  Thanks - Dave

  I just chose 'No' and don't look at back.  I love my workspace, just as it is and doesn't prefer Photoshop to change for me in this case especially.

  You bring up the 3D Panel yourself via the window - 3D.  I think it's a good alternative for the Actions Panel, because I don't have any currently working in the 3D world.

  You'll want to see easily if you are working on 3D are 3D Panel and panel properties, among a few others.

  Regarding return your workspace as you like it...  Note the small switch near the upper right of the main window of Photoshop.  That can be used to select a workspace.  I suggest that you experiment and familiarize yourself with the concept of workspaces.  You can set your own and save it with a name, and that can really be useful.

  -Christmas

• How to get the outline color and size of the rectangle?

  Hi all

  I'm developing an extension for CS5 and higher (including the CC version). I want to get the outline color and size of a rectangle. I was able to do in CS5. But I noticed that in the version of the CC, there are two ways in which the user can apply to a stroke. One is by applying the effect in the layer Style, and the other through the properties panel. I am able to get the values of time in my script, if it is applied through layer Style, but I can't do it in the other scenario.

  How are these two different traits and how do I get the outline color and size if it is applied via the properties panel using script?

  Thank you!

  Here's what I have so far. It takes more work, but I don't think that's never very accurate.

  function toggleOtherLayersVisibility() {
      var desc = new ActionDescriptor();
          var list = new ActionList();
              var ref = new ActionReference();
              ref.putEnumerated( charIDToTypeID('Lyr '), charIDToTypeID('Ordn'), charIDToTypeID('Trgt') );
          list.putReference( ref );
      desc.putList( charIDToTypeID('null'), list );
      desc.putBoolean( charIDToTypeID('TglO'), true );
      executeAction( charIDToTypeID('Shw '), desc, DialogModes.NO );
  };
  function liveShapeFillEnabled( enable ) {// boolean
      var desc = new ActionDescriptor();
          var ref = new ActionReference();
          ref.putEnumerated( stringIDToTypeID('contentLayer'), charIDToTypeID('Ordn'), charIDToTypeID('Trgt') );
      desc.putReference( charIDToTypeID('null'), ref );
          var shapeDesc = new ActionDescriptor();
              var styleDesc = new ActionDescriptor();
              styleDesc.putInteger( stringIDToTypeID('strokeStyleVersion'), 2 );
              styleDesc.putBoolean( stringIDToTypeID('fillEnabled'), enable );
          shapeDesc.putObject( stringIDToTypeID('strokeStyle'), stringIDToTypeID('strokeStyle'), styleDesc );
      desc.putObject( charIDToTypeID('T   '), stringIDToTypeID('shapeStyle'), shapeDesc );
      executeAction( charIDToTypeID('setd'), desc, DialogModes.NO );
  };
  function dupeVisibleMerged() {
      var desc = new ActionDescriptor();
      desc.putBoolean( charIDToTypeID('Dplc'), true );
      executeAction( charIDToTypeID('MrgV'), desc, DialogModes.NO );
  };
  function loadTransparency(){
      var desc = new ActionDescriptor();
          var ref = new ActionReference();
          ref.putProperty( charIDToTypeID( "Chnl" ), charIDToTypeID( "fsel" ) );
      desc.putReference( charIDToTypeID( "null" ), ref );
          var ref1 = new ActionReference();
          ref1.putEnumerated( charIDToTypeID( "Chnl" ), charIDToTypeID( "Chnl" ), charIDToTypeID( "Trsp" ) );
      desc.putReference( charIDToTypeID( "T   " ), ref1 );
      executeAction( charIDToTypeID( "setd" ), desc, DialogModes.NO );
  };
  function getLiveShapeStrokeInfo(){
      var doc = app.activeDocument;
      var lyr = doc.activeLayer;
      liveShapeFillEnabled( false );
      toggleOtherLayersVisibility();
      doc.artLayers.add();
      dupeVisibleMerged();
      var bounds = doc.activeLayer.bounds;
      var horzCenter = (bounds[2]-bounds[0])/2;
      var vertCenter = (bounds[3]-bounds[1])/2;
      lyr.visible = false;
      var sampler = doc.colorSamplers.add([bounds[0]+UnitValue(.5,'px'),bounds[1]+vertCenter]);
      sizeObject.color = sampler.color;
      loadTransparency();
      doc.selection.select([
                              [bounds[0],bounds[1]+vertCenter],
                              [bounds[0]+horzCenter,bounds[1]+vertCenter],
                               [bounds[0]+horzCenter,bounds[1]+vertCenter+UnitValue(1,'px')],
                               [bounds[0]+UnitValue(1,'px'),bounds[1]+vertCenter+UnitValue(1,'px')]],SelectionType.INTERSECT);
  
      sizeObject.size = doc.selection.bounds[2]-doc.selection.bounds[0];
  };
  var sizeObject = {};
  app.activeDocument.suspendHistory('Get Live stroke info','getLiveShapeStrokeInfo()');
  executeAction( charIDToTypeID('undo'), undefined, DialogModes.NO );
  sizeObject.size;
  

• How can I get the exact time and date on my FAX LOG

  I have a new HP Officejet 6500 has more on my Dell Inspiron Windows XP computer.  How can I get the exact time and date on my FAX log?

  Hi FrederickFrank7,

  Journal of faxes would just follow the time of your printer. Please set the time and date of your printer.

  I am an employee of HP.
  Please indicate the position that solved your problem as "acceptable Solution".

• error reported from the transport layer and the error description was impossible to extract

  Hi, can someone please explain how to get rid of the pop-up message when the computer starts up:
  error reported from the transport layer and the error description could not be found! the message has been lost
  Windows XP Virgin internet net gear wireless. I searched on the internet - nothing except suggestions, this is the internet
  connections but is not working okay I tried microsoft fix
  Thank you john

  Hi, I just started to use the hard drive that had the problem, it's still there. The problem is with the raid card. (no problem on other drives) In system config, starting there are two enteries: SATARAIDS and silcfg. I checked the SATARAIDS, rebooted

  missing message. I deleted all the files SATARAIDS and silcfg. my computer, properties, hardware - deleted. deleted the folder in program files. did a scan to remove any files or file fragments on the raid drivers. I did not know I had lefe the cd in the drive for the raid drivers I have in yesterday. I rebooted.
  after reboot, there not says found new hardware "raid card" perhaps because the disc was in the drive and it automatticly installed drivers. FIXED
  NO MORE ANNOYING MESSAGE

• How to get the selected row in a programmatic table of the ADF (table generated from a bean)

  Hi all

  
  

  We use JDeveloper Studio Edition Version 12.1.3.0.0 and deployed on GlassFish Server Open Source Edition 3.1.2.2 (build 5) and connect to the SQLServer database.

  
  

  How to get the selected line in a programmatic (using a SortableModel custom not a display object) ADF table (generated from a bean)?

  
  

  We are trying to get the selected row in a bean of a programmatic ADF table to retrieve data based on the selected line.

  
  

  Any idea?
  

  Well, you can use selectionListener to set the selected line to a variable of bean (but this bean must be in extended view or some superiors)

  Something like this: http://www.awasthiashish.com/2015/07/get-selected-row-singlemultiple-from.html

  Dario

• How to remove each layer except the selected layer?

  Hello

  I would like to delete all layers including the background sets and layer except for the selected layer.

  It seems easy to first, but it stops... I tried in several ways; What I am doing wrong?

  #target photoshop
  cTID = function(s) { return app.charIDToTypeID(s); };
  sTID = function(s) { return app.stringIDToTypeID(s); };
  
  app.bringToFront();
  var doc = app.activeDocument;
  var currentLayer = doc.activeLayer; // remember the selected layer
  var selectedlayername = currentLayer.name;
  currentLayer.move( activeDocument, ElementPlacement.PLACEATBEGINNING );  
  
    function DeleteLayer(layername) {  var desc1 = new ActionDescriptor();
      var ref1 = new ActionReference();   ref1.putName(cTID('Lyr '), layername);
      desc1.putReference(cTID('null'), ref1);     var list1 = new ActionList();
      list1.putInteger(17);  desc1.putList(cTID('LyrI'), list1);  executeAction(cTID('Dlt '), desc1, DialogModes.NO);
    };
  
  function DeleteBackground() { var desc1 = new ActionDescriptor();  var ref1 = new ActionReference();   ref1.putProperty(cTID('Lyr '), cTID('Bckg')); desc1.putReference(cTID('null'), ref1);     var list1 = new ActionList();     list1.putInteger(1);   desc1.putList(cTID('LyrI'), list1);    executeAction(cTID('Dlt '), desc1, DialogModes.NO); };
  
  function initial () {
  for(var i = 0 ; i < doc.layers.length;i++){    if (doc.layers[i].isBackgroundLayer == true ) {  DeleteBackground();} }
  var layerNum = doc.layers.length;
  for(var  s = 1 ; s <= layerNum;s++){
     if ( doc.layers[s].name != selectedlayername ) {   
         DeleteLayer (doc.layers[s].name);
         }
     else if ( doc.layers[s].name == selectedlayername ) {
         }
     }
  }
  
  initial();
  

  Thank you

  Best regards.

  Hi arteangelus,

  Try this Code...

  #target photoshop
  var docRef = app.activeDocument;
  var layName = docRef.activeLayer.name
  var l = Number(docRef.layers.length)+1;
  while(--l){
      if(docRef.layers[l-1].name!=layName && docRef.layers[l-1].name!="Background"){
          docRef.layers[l-1].remove();
      }
  else{continue;}
  }
  

  -yajiv

• [MAF] How to get the user name and password after login?

  Hi Experts,

  I have a call to REST where it requires identification information of the user (uname and password) to identify the data that belongs to who.

  Authentication has been made with OAuth.

  I believe that there is an API to get the user name and password in the CRG

  See you soon,.

  Hendry

  Hello.

  You don't need to manipulate the credentials yourself in code. MAF will propagate the logon cookie or inject the identification information in the HTTP header if cookies are not supported.

  To do this, you must select the purchase option of cookie from the server connection Include in REST in the dialog box create a connection Login MAF , such as discussed here:

  http://docs.Oracle.com/middleware/maf210/mobile/develop/MAF-securing.htm#ADFMF23732

  In addition, you must attach the policy of security appropriate to the connection, as explained here:

  http://docs.Oracle.com/middleware/maf210/mobile/develop/MAF-Web-services.htm#ADFMF23697

  Best regards

  Frédéric Desbiens

  Senior Product Manager

  Mobility and Cloud oracle

  Twitter: @BlueberryCoder

  blog: http://blogs.oracle.com/blueberry