Get the problem when configuring Application adapt to Weblogic

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  In the "performance" tab, it is written that ' * 1729: 42000: java.sql.SQLException: ORA-01729: database link name expected. "
  
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  Hello

  You ' r are welcome.

  Please close the points wire and assign (useful/correct) to each thread accordingly you think.

  Thank you
  G

• get the problem when starting native/cascades beta sdk - "QML preview is not available.

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  I recvd a phone call yesterday telling me I had a computer at risk with the help of the same IP address or ID in China.  I thought it was a hoax.  They said they came from Microsoft, but when I tried to recall today, there was a message stating that the Group was not available.  Then I get on my computer and get the label "there is an IP address conflict" and I panic, what happens if someone in China is using my computer?  How can I stop this?  I ran antivirus and anything analyses.    Help, please?

  To resolve IP conflicts restart all computers, peripheral and the router at the same time.  Chances are it will fix

  Microsoft (or any other reliable service)'ll never call you cold.  They have no idea if your computer is in danger, a virus or anything else.  Calls are cold almost always a scam.

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  original title: WiFi

  I can't connect to the network wirelessly with my Emachines eM350 portable because I get the automatic Wireless Configuration error, see Article 871122.

  I use a Huawei E585. I simply want to clamp it alll in the tray.

  Remember - this is a public forum so never post private information such as numbers of mail or telephone!

  Ideas:

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  • Error messages
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  What is the exact error message received when the problem occurs?

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  Auditor of file system (CFS) scan to fix all of the corrupted system files. To do this, follow the steps in the following link:

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  http://support.Microsoft.com/kb/929833 

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  Hi catherinegood,

  1. When did you start to question?

  2. you remember to make changes to the computer before this problem? Hope this information is useful.

  This is error occurs when Norton scan, then you can check with Norton and check:

  Check the link for the support of Norton:

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  http://www.Symantec.com/support/index.jsp

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  Note: When you perform the analysis, there are risks of data loss you can take a backup of important data before performing analysis.

  Check out the link:

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• AnyConnect 4.1 - cannot get the secure gateway configuration

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• to get the total value as application even if item_number is added

  Hi all
  
  I have the following query with me
  

  SELECT   SUM (  (NVL (f.calc_cement_sk, f.calc_amount) * NVL (f.item_price, 0)
                  )
                - (  NVL (f.calc_cement_sk, f.calc_amount)
                   * NVL (f.item_price, 0)
                   * (NVL (f.dis_per, 0) / 100)
                  )
               ) total,
           h.slurry_type, h.stage_id, h.slurry_vol_actual
      FROM xxnp_opn_joblog_est_002 f,
           xxnp_opn_joblog_001 j,
           xxnp_opn_joblog_slurry_003 h,
           qp_secu_list_headers_v qw
     WHERE j.opn_job_desc = 'K/D/KD43/UG187/1338/D/0211/1'
       AND f.opn_joblog_001_id = j.opn_joblog_001_id
       AND j.contract = qw.NAME
       AND h.opn_joblog_001_id = j.opn_joblog_001_id
       AND h.opn_joblog_007_id = f.opn_joblog_007_id
       AND h.opn_joblog_006_id = f.opn_joblog_006_id
  GROUP BY h.stage_id, h.slurry_type, h.slurry_vol_actual

  the result I get is
  
  
  SLURRY_TYPE TOTAL STAGE_ID SLURRY_VOL_ACTUAL
  9,562.59 lead 1 490
  2,184.84 1 80 tail
  1,091.73 reload 1 56
  3,431.64 tail 2 100

  when i add f.item_number to the above query as shown below
  
  SELECT   SUM (  (NVL (f.calc_cement_sk, f.calc_amount) * NVL (f.item_price, 0)
                  )
                - (  NVL (f.calc_cement_sk, f.calc_amount)
                   * NVL (f.item_price, 0)
                   * (NVL (f.dis_per, 0) / 100)
                  )
               ) total,f.item_number,
           h.slurry_type, h.stage_id, h.slurry_vol_actual
      FROM xxnp_opn_joblog_est_002 f,
           xxnp_opn_joblog_001 j,
           xxnp_opn_joblog_slurry_003 h,
           qp_secu_list_headers_v qw
     WHERE j.opn_job_desc = 'K/D/KD43/UG187/1338/D/0211/1'
       AND f.opn_joblog_001_id = j.opn_joblog_001_id
       AND j.contract = qw.NAME
       AND h.opn_joblog_001_id = j.opn_joblog_001_id
       AND h.opn_joblog_007_id = f.opn_joblog_007_id
       AND h.opn_joblog_006_id = f.opn_joblog_006_id
  GROUP BY h.stage_id, h.slurry_type, h.slurry_vol_actual,f.item_number
  
  
  the field total gets split and gives value corresponding to each item_number
  
  i am giving the ouptut for stage 1

  ITEM_NUMBER TOTAL SLURRY_TYPE STAGE_ID SLURRY_VOL_ACTUAL
  5011.5 1020101001 lead 1 490
  1308.93 1020102002 lead 1 490
  127.215 1020111001 lead 1 490
  138.92 1020112001 lead 1 490
  686 1020113001 lead 1 490
  550,5 1020113002 lead 1 490
  1739.52 1020222010 lead 1 490
  1517.1 1020101001 1 80 tail
  379.5 1020102003 1 80 tail
  83.2 1020103001 1 80 tail
  166.53 1020104001 1 80 tail
  38.511 1020111001 1 80 tail
  1064,7 1020101001 reload 1 56
  27,027 1020111001 reload 1 56
  
  
  If we add up the values in the total field to the head, tail, charge that we get 9562.59,2184.84,1091.73 respectively
  
  kindly Guide
  to get the total value as application even if item_number is added
  thanking in advance

  Hello

  You can do this by enclosing it with another selection

  select
  total, slurry_type, stage_id, slurry_vol_actual,
  sum(total) over (partition by slurry_type, stage_id, slurry_vol_actual) from (
  your actual select
  )
  

  concerning

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