Group feature is not allowed

Similar Questions

• ORA-00934: Group feature is not allowed here

  CREATE or REPLACE PROCEDURE First(
  date1 IN Date,
  date2 IN Date
  )
          AS
  
  date3 employee.start_date%TYPE;
  date4 employee.start_date%TYPE;
  
  Begin
  select min(start_date) into date3 from employee where start_date between date1 AND date2;
  END;
  /

  Above procedure is completed successfully
  
  But when I changed the query to
  
  Select min (start_date) date3, max (start_date) in date4 of employee where start_date between date1 AND date2.
  then I get the error message
  ORA-00934: Group feature is not allowed here.
  Why this error happens during execution, but on sqlplus query is executed successfully.
  I checked this in oerr ora-00934 but not able to understand what measures should be taken

  select min(start_date)
  ,      max(start_date)
  into   date3
  ,      date4
  from   employee
  where  start_date between date1 AND date2;
  

• PL/SQL: ORA-00934: Group feature is not allowed here

  Hello
  
  I write a PL/SQL procedure. The structure is like:
  
  SET SERVEROUTPUT ON;
  CREATE or REPLACE procedure abc
  
  IS
  v_total_ip_rec number (14);
  v_total_op_rec number (14);
  v_total_rec number (14);
  
  
  BEGIN
  SELECT SUM (CASE
  WHEN < condition 1 >
  THEN 1
  0 OTHERWISE
  END
  ) in v_total_ip_rec.
  SUM (CASE
  WHEN < condition 2 >
  THEN 1
  0 OTHERWISE
  END
  ) in v_total_op_rec.
  SUM (1) in v_total_rec
  OF A, B
  WHERE A.Col1 = B.Col1;
  
  EXCEPTION
  WHILE OTHERS THEN
  raise_application_error (-20001,' an error has occurred - ' |) SQLCODE |' - ERROR - ' | SQLERRM);
  END;
  
  
  When I run this procedure it gives me following error:
  "PL/SQL: ORA-00934: Group feature is not allowed here."
  
  Someone has an idea?
  
  Any help would be appreciated.
  
  Thank you.

  Should I have any special role?

  Have you checked if synonyms exist for tables?
  Please check in this order:

  #1-synonymes appropriate
  #2-appropriate privileges
  #3-appropriate roles

• Group feature is not allowed here

  Hello
  
  I have a problem running the following sql command, I know that the error is the count function, but I don't know how to solve this problem. Can you please help me solve this problem.
  (I like to select titles that have more than 2 authors).
  
  Separate select titles.title_id, titles.title_name, titles.publisher_ID
  authors, titles, and author_titles
  where titles.title_ID = author_titles.title_id
  and author_titles.au_id = authors.au_id and count (authors) > 2
  ORDER BY titles.title_id DESC;
  
  Thank Yoy

  Hello

  You group by expression is absent from the columns you have in your select statement

    SELECT titles.title_id,
           titles.title_name,
           titles.publisher_ID    FROM authors, titles, author_titles
     WHERE titles.title_ID = author_titles.title_id
           AND author_titles.au_id = authors.au_id
  GROUP BY titles.title_id, titles.title_name, titles.publisher_ID
    HAVING COUNT ( * ) > 2
  ORDER BY titles.title_id DESC;
  

  Concerning
  OrionNet

• In FF5.0 this tab groups feature does not work: ' once you have created your first group, the of the tab group button will be added to the right end of the Strip to tabs to give you a one-click way to return to your groups.»

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• I get a msg that says that my firewall is not enabled, when I try and turn it on, it says that my group policy is not allowing me to turn it on. How can I activate some group policy is disabled, so my firewall work?

  I searched around for group policy, but no luck.

  A reinstall is quite often the fastest way to solve a problem.  Your hard drive will be completely erased in the process, it will be necessary to back up your personal files beforehand.  An external USB drive is good for this.  Also, you will need to reinstall all the applications that came with the computer.  If you use the Encrypting File System (EFS), make sure you back up your certificates as well or you will lose access to all your encrypted files - even if saved. (Encrypted files usually appear with names in green).

  A "repair install" which does not erase your drive might also be possible, but if you have installed SP2, SP3, IE7 or IE8 you bought your machine, you should read the following article:

  "How to perform a Windows XP repair installation, if a later version of Internet Explorer is installed"
    <>http://support.Microsoft.com/kb/917964 >

  HTH,
  JW

• Help with error - 934 group function is not allowed here

  Hey there will, I'm having problems with a request and just does not know how to do it without error.

  I'm trying to get all the employee emerging infectious diseases that have less than 2 number max of DID (dependants) in the table.

  It's my current query

  SELECT Employee.LName. ' ' || Employee.Fname as Full_Name, Employee.EID

  The left outer JOIN employee depends on Employee.EID = Dependent.EID

  Having Count (DID)--2 > ((select Max (N) as From (SELECT Employee.EID, Count (DID) As N FROM Employee Inner Join Dependent On Employee.EID = Dependent.EID group by Employee.EID, Count (DID))) N)

  Order of Employee.Lname, Employee.Fname

  Which gives me an error on column 4, no matter what I do. If I remove the Count (DID) in the group by clause (which I tried it earlier), it gives me a is not an error of the function of single group...

  The most frustrating thing is that

  Select Max (N) as From (SELECT Employee.EID, Count (DID) As N FROM Employee Inner Join Dependent On Employee.EID = Dependent.EID group by Employee.EID) N

  Works perfectly, but because it's a mission, I have to do in one step (no substeps/views)

  Any help?

  Thank you very much

  Hello

  ac981e5d-D10A-4520-BF42-23a894d04fb7 wrote:

  Ok. I'm taking your code in a view... I get this.

  and there is an orange underscore and a text of the error that says

  Select incoherent list in group by... change the group by clause of e.fname, e.lname, e.eid, count, max

  Which isn't what either the Oracle database would do.  Everything about orange (or any other color) sounds like it is caused by a front-end that could be interacting with Oracle.  In addition, the Oracle error messages always come with a 3-letter-5 code, as ORA-00933.

  under the selection internal (first medium)

  You have deleted the WITH clause.  The parser can recognize the error when it has reached the first left parenthesis.

  Create view AS A10T2

  (

  SELECT e.lname. ' ' || e.fname AS full_name

  e.eid

  (D.) AS this_group_count

  MAX (COUNT (d.)) ON (AS highest_group_count)

  E employee

  LEFT OUTER JOIN dependent d ON e.eid = d.eid

  GROUP BY e.lname, e.fname, e.eid

  )

  SELECT full_name

  eid

  Of aggregate_results

  WHERE this_group_count > = highest_group_count - 2

  ORDER BY full_name

  You need the WITH to define this clause means "AGGREGATE_RESULTS":

  Create view AS A10T2

  WITH aggregate_results AS

  (

  SELECT e.lname. ' ' || e.fname AS full_name

  ...

  Why do you have an ORDER BY clause in a view?   (It is probably not cause of your errors, just make the inefficient view)

  Command line error: column 5: 23

  Error report-

  SQL error: ORA-00933: SQL not correctly completed command

  00933 00000 - "not correctly completed SQL command.

  * Cause:

  * Action:

  This is another indication that some front is getting involved.  Looks like your front-end reports the exact Oracle error message, "0RA-00933" and then builing it's own error code, "00933. 00000 ", on this basis.  ORA-00933 is a reasonable mistake to wait if you omit the line ' WITH the aggregated results AS.  Once again, until I can actually run your code, I can't test it, and I can't run your code until you post CREATE TABLE and INSERT statements for some examples of data, or change the problem to use commonly available tables, such as those in the scott schema.

  and when I try my code

  CREATE VIEW A10T2 AS

  SELECT Employee.LName. ' ' || Employee.Fname as Full_Name, Employee.EID

  The left outer JOIN employee depends on Employee.EID = Dependent.EID

  Seen (Count (DID)) + 2 > (select Max (N) From (SELECT Employee.EID, Count (DID) As "N" FROM Employee Inner Join Dependent On Employee.EID = Dependent.EID group by Employee.EID))

  Order of Employee.Lname, Employee.Fname

  I get

  Command line error: column 2: 8

  Error report-

  SQL error: ORA-00937: not a function of simple-group

  00937 00000 - 'not a single-group function.

  * Cause:

  * Action:

  Then the orange underscore even under my inner ("select employee. EID, Count (DID) as "N" ") says to change the Group of Employee.eid, Count (DID)

  I just don't understand why he tells me to group them by Count (DID)?

  Isn't that what you did in your original post, and I have explained in answer #2?  If you continue to repeat the same mistake, you can expect continue to get the same error.  Given that you have a code, you know causes an error, do you think really that what makes a vision will cause the error to disappear?

  The inner query works fine on its own...

  Right; It's the outer query where you are missing the GROUP BY clause.

• calculate the forms feature will not allow me to check a box

  I use Adobe Acrobat X Pro.  In the forms, using the calculate function, I can't verify or check a box to

  Some people have this problem and can get around by clicking close boxes, and others use the keyboard (space to toggle a check box, tab/arrows up/down in the list). Others find the simplified field notation more convenient, and I almost always use the custom JavaScript option.

• ORA-00934: function of group not allowed error when creating index

  ORA-00934: Group feature is not allowed here
  

  create index idx_emp on emp(max(install_time))

  Hello

  Daniel wrote:
  ORA-00934: Group feature is not allowed here

  create index idx_emp on emp(max(install_time))
  

  It's true. It is documented in the Manual of the SQL language

  Restrictions on Function-based Indexes 
  
  Function-based indexes are subject to the following restrictions:
  ...
  The column_expression cannot contain any aggregate functions.
  

  MAX is an aggregate function.

  What problem are you trying to solve? If you could create an index like this, how would you use it?
  Explain what you need to do, and someone will help you find a good way to do it.

• ISE 1.3 not allow authentication based on the group network

  ISE 1.3

  MS AD 2008R2

  Two groups: all employees, all students

  Problem: Students employee network connection

  I have two wireless networks, STUDENTS and EMPLOYEES. In ISE, I have two strategies for approval for these networks. In an effort prior to keep students to connect to the network employee, I set the permission policy:

  Employee: If (Wireless_802.1X AND AD1:ExternalGroups is equal to mydomain/accounts/all employees AND the AD1:ExternalGroups NOT_EQUALS mydomain/students/all students) then: Employee_Profile

  Unfortunately, it did not work. Students have their own username and password in AD and each faculty and staff member. I checked that students are using their identification and employee network connection information. Conversely, I can connect to the student network using the credentials of the employee. The main problem is with the students, employee network, they use all the applicable DHCP scope addresses.

  I need to not allow the network connection used by students and the network of students by employees.

  Any help would be appreciated!

  Kevin

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• The Group Policy settings do not allow the use of a PIN code at startup Bitlocker Windows 8

  Hello

  I hope you can help.

  I tried to implement the encryption on my new laptop Lenovo Twist with windows 8, but get the following error.

  ERROR: An error has occurred (code 0 x 80310060):
  Group Policy settings do not allow the use of a PIN code start. Please choose a
  other BitLocker startup option.

  I tried to change local policy settings...

  1. Go to Local computer policy > Computer Configuration > administrative templates > Windows components > Bitlocker Drive Encryption > Operating System Drives
  2. Open the key require additional start authentication
  3. Activate this key, then assign the require startup PIN with TPM TPM configure startup PIN

  .. .but always not the same error.

  Help, please. He drives me crazy!

  Hello

  Thanks for choosing Microsoft Community to post your question!

  According to your description, it seems that you have problems with activation PIN code on startup.

  Refer to the suggestions from this link and check.

  http://social.technet.Microsoft.com/forums/en/w7itprosecurity/thread/c3b5e90d-89fd-4e95-AF97-723b045eb41b

  For more help, I suggest you ask your question in the TechNet Forum. http://social.technet.Microsoft.com/forums/en-us/w8itprosecurity/threads

• I subscribed to Pack Adobe and not only there me not allowed to do what I need it to do, he charged me the 9.99 and cannot me access to the subscription describes additional features. Worse, it is - I can't see it in my plans to UNSUBSCRIBE.

  I subscribed to Pack Adobe and not only there me not allowed to do what I need it to do, he charged me the 9.99 and cannot me access to the subscription describes additional features. Worse, it is - I can't see it in my plans on my Adobe account to UNSUBSCRIBE. Help! How can I unsubscribe?

  Hello

  An answer depends on where you bought the subscription for.  Please take a look at your purchase confirmation email.

  (a) Apple App Store

  Contact Apple - Apple Support support

  iTunes - account & billing - Apple Support

  (b) Google Play Store

  Subscriptions on Google Play - game Google Help

  (c) adobe web site

  Cancel your subscription or membership. Acrobat, services Cloud of Document PDF

  If none of the above answers your question, please contact Adobe customer service directly.  Sorry for the inconvenience.

• The submenu stack does not allow for the pictures stacked in the Organizer features 13 8.1 on windows

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  Please press Ctrl + D to go to the older grid, and now the battery option must be enabled.

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• Not allowing a value for a selection in a Select list

  Version 4.1.1.00.23

  Hello

  I created a Select list to display projects within a Department (that we call groups).

  A group will have projects, however, more than one group may have a project with the same name.

  If my application for the display of the list select the data in a hierarchical format like this:

  Group 1

  Proj Grp 1

  Proj Grp 1

  Proj Grp 1

  Proj Grp 1

  proj Grp 3

  Group 2

  Proj Grp 1

  Proj Grp 1

  Proj Grp 2

  Proj Grp 2

  Group 3

  Proj Grp 1

  Proj Grp 2

  proj Grp 3

  What I'm looking for, it's to NOT allow 'Group' level to be selected in the list. Only allow the level of project to be selected values.

  The query is:

  WITH t
       AS (SELECT 'Group: ' || vg.group_name name
                 ,vg.group_id
                 ,NULL id
                 ,1 AS weight
           FROM   vertical_group vg
           WHERE (vg.group_id = :P100_GROUP OR :P100_GROUP = 0)
           UNION ALL
           SELECT '....' || project_name
                 ,group_id
                 ,project_id
                 ,2 AS weight
           FROM   tbs_projects
           WHERE  status IN ('Pipeline'
                            ,'Planned - Partially Funded'
                            ,'Planned'
                            ,'Execution') AND
                  ( :P100_RYG_PROJECT = 0 OR :P100_RYG_PROJECT = ryg_proj_id ) AND
                  ( group_id = :P100_GROUP OR :P100_GROUP = 0 ))
  SELECT name
        ,id
  FROM   t
  ORDER BY group_id
          ,weight
          ,name
  
  

  Can someone help me with this?

  Is there additional information that I can provide?

  Thank you

  Joe

  HTML optgroup element is used for the structure select of the lists in this way. Select standard lists the APEX and LOVs do not have support for generating optgroup of the items in the lists of options, but point of plug-ins with this feature are available.

  See the documentation for more information on the use of plug-ins.

• Authentication features - why not a GetAllGroupsUserIsIn()

  Hello!
  
  Is there a reason why it is not a feature that would allow a programmer empty all groups a user is in? For me as a programmer, I want to see which groups our network admin added a given user. For example, a GetAllGroupsUserIsIn (AndreP) might return a list of these groups that I am. Ideal for debugging, etc. Is this possible?

  Thank you. I just downloaded a big SWC called ntsecurity.cfc that does exactly what I need.