Grouping records
Hi allI have this table
WITH taba
AS (SELECT 83573 AS id, 135433 AS pe_rule_id, 46493 AS uc_id
FROM DUAL
UNION ALL
SELECT 83574 AS id, 135433 AS pe_rule_id, 46512 AS uc_id
FROM DUAL
UNION ALL
SELECT 83557 AS id, 137004 AS pe_rule_id, 47277 AS uc_id
FROM DUAL
UNION ALL
SELECT 83558 AS id, 139647 AS pe_rule_id, 47277 AS uc_id
FROM DUAL
UNION ALL
SELECT 83571 AS id, 144804 AS pe_rule_id, 46493 AS uc_id
FROM DUAL
UNION ALL
SELECT 83572 AS id, 144804 AS pe_rule_id, 46512 AS uc_id
FROM DUAL)
SELECT *
FROM taba
I need to get all records with MIN (ID), that have the same group uc_id records.Return:
135433 46493
46512 135433
137004 47277
For example, 2 = 144804 pe_rule_id records have both the same uc_id as the chronogram pe_rule_id = 135433 2. In this case, I need only the records pe_rule_id = 135433
This is just one example. I may have records with 3 or more uc_id diferent to the same pe_rule_id.
Can you help me please?
Thank you
Filipe Almeida
Do you mean min (pe_rule_id)?
Like this?
SQL> ed
Wrote file afiedt.buf
1 WITH taba
2 AS (SELECT 83573 AS id, 135433 AS pe_rule_id, 46493 AS uc_id
3 FROM DUAL
4 UNION ALL
5 SELECT 83574 AS id, 135433 AS pe_rule_id, 46512 AS uc_id
6 FROM DUAL
7 UNION ALL
8 SELECT 83557 AS id, 137004 AS pe_rule_id, 47277 AS uc_id
9 FROM DUAL
10 UNION ALL
11 SELECT 83558 AS id, 139647 AS pe_rule_id, 47277 AS uc_id
12 FROM DUAL
13 UNION ALL
14 SELECT 83571 AS id, 144804 AS pe_rule_id, 46493 AS uc_id
15 FROM DUAL
16 UNION ALL
17 SELECT 83572 AS id, 144804 AS pe_rule_id, 46512 AS uc_id
18 FROM DUAL)
19 select pe_rule_id, uc_id
20 from taba where pe_rule_id in (
21 SELECT min(pe_rule_id)
22 FROM taba
23 group by uc_id
24* having count(*) > 1)
SQL> /
PE_RULE_ID UC_ID
---------- ----------
137004 47277
135433 46512
135433 46493
Published by: BluShadow on August 3, 2011 13:26
p.s. Thanks for providing data in an easy to use format. :)
Tags: Database
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Could have given arranged at will to make my point more clear for you. Here you go:
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I get this
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Thanks in advance,
Raj.Hello
This is called a Query Top - N .
How do you determine which line of each group you want to display?
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Experts
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declare
v_rg_id recordgroup: = NULL;
Number of V_errorcode;
v_rg_salmth varchar2 (30): = "MONTHS";
Begin
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OF THE DOUBLE
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UNION
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OF THE DOUBLE
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You want to always 2 rows for each order_id exit or you want sometimes 1 or 3 or more?
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insert into orders_tb (order_id, order_date) values ('1001 ', to_date('13-JAN-2014','DD-MON-YYYY'));
insert into orders_tb (order_id, order_date) values ('1001 ', to_date('19-JAN-2014','DD-MON-YYYY'));
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(
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ORDER BY order_date
RANGE BETWEEN 10.000001 MORE
AND UNBOUNDED FOLLOWING
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OF got_next_date
START WITH order_date = start_date
CONNECT BY order_date = next_date PRIOR
AND order_id = order_id PRIOR
;
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ORDER_ID, ORDER_DATE
-------- -----------
1001 December 31, 2013
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Gurus,
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The desired output is a user consolidated without additional records...select distinct created_by, count(created_by) receipt_count, null deliver_count from wms_transaction where creation_date > sysdate-10 and transaction_type = 'RECEIPT' group by created_by union select distinct created_by, null rec_count, count(created_by) deliver_count from wms_transaction where creation_date > sysdate-10 and transaction_type = 'DELIVER' group by created_by order by receipt_count CREATED_BY RECEIPT_COUNT DELIVER_COUNT -------------------- ----------------------- ------------------------ SPRECKO 4 HKUMAR 4 SPRECKO 10 HKUMAR 856
Someone there all of the recommendations? I give the points to obtain useful and accurate responses (someone always comments on the points system when I write that ;-))CREATED_BY RECEIPT_COUNT DELIVER_COUNT -------------------- ----------------------- ------------------------ SPRECKO 4 10 HKUMAR 4 856
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Published by: sreese on April 25, 2013 14:23
Published by: sreese on April 25, 2013 14:23Hello
You can do it with a pivot:
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It will be much more effective than a UNION.
The query above works in Oracle 8.1 or more. From Oracle 11, you can also use SELECT... PIVOT.
I hope that answers your question.
If not, post a small example data (CREATE TABLE and only relevant columns, INSERT statements) and also publish outcomes from these data.
Explain, using specific examples, how you get these results from these data.
Always say what version of Oracle you are using (for example, 11.2.0.2.0).
See the FAQ forum {message identifier: = 9360002}Published by: Frank Kulash on 25 April 2013 14:37
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Hi all
This is our requirement.
We must combine records with time.
for example: period = 3
TABLE: XX_SALES
---------------------------------------------
XDATE XQTY
---------------------------------------------
10 5/1/2012
20 2/5/2012
3/5/2012 30
4/5/2012 60
12 2012/5/7
8/5/2012 23
45 8/5/2012
100 12/5 / 2012
5/2012/13 55
5/2012/15 99
== >
---------------------------------------------
XDATE XQTY
---------------------------------------------
1/5/2012 10-> 5/1/2012 Group (5/1/2012 ~ 3/5/2012)
2/5/2012 20-> 5/1/2012 Group (5/1/2012 ~ 3/5/2012)
3/5/2012 30-> 5/1/2012 Group (5/1/2012 ~ 3/5/2012)
4/5/2012 60-> Group 5/2012/4 (4/5/2012 ~ 2012/5/6) *.
7/5/2012 12-> Group 5/2012/7 (5/7/2012 ~ 9/5/2012) *.
8/5/2012 23-> Group 5/2012/7 (5/7/2012 ~ 9/5/2012) *.
8/5/2012 45-> Group 5/2012/7 (5/7/2012 ~ 9/5/2012) *.
5/2012/12 100-> Group 5/12/2012 (2012/5/12 ~ 14/5/2012) *.
13/5/2012 55-> Group 5/12/2012 (2012/5/12 ~ 14/5/2012) *.
5/15/2012 99-> Group 5/15/2012 (15/5/2012 ~ 5/17/2012) *.
After amount to combine with period = 3, the result will be
---------------------------------------------
XDATE_G XQTY_G
---------------------------------------------
60 1/5/2012
4/5/2012 60
2012/5/7 80
12/5/2012 155
5/2012/15 99
Here's the example script
We can solve this problem by using the loop now:create table XX_SALES(XDATE DATE, XQTY Number); insert into XX_SALES VALUES(to_date('20120501','YYYYMMDD'),10); insert into XX_SALES VALUES(to_date('20120502','YYYYMMDD'),20); insert into XX_SALES VALUES(to_date('20120503','YYYYMMDD'),30); insert into XX_SALES VALUES(to_date('20120504','YYYYMMDD'),60); insert into XX_SALES VALUES(to_date('20120507','YYYYMMDD'),12); insert into XX_SALES VALUES(to_date('20120508','YYYYMMDD'),23); insert into XX_SALES VALUES(to_date('20120508','YYYYMMDD'),45); insert into XX_SALES VALUES(to_date('20120512','YYYYMMDD'),100); insert into XX_SALES VALUES(to_date('20120513','YYYYMMDD'),55); insert into XX_SALES VALUES(to_date('20120515','YYYYMMDD'),99);
to find the XDATE_G and it's rank in the loop and the XQTY in the range of the sum.
Is it possible to solve this problem by using analyze sql?DECLARE V_DATE_FROM DATE := NULL; V_DATE_TO DATE := NULL; V_QTY_SUM NUMBER := 0; CURSOR CUR_DATE IS SELECT DISTINCT XDATE FROM XX_SALES ORDER BY XDATE; BEGIN FOR REC IN CUR_DATE LOOP IF V_DATE_TO IS NULL OR REC.XDATE > V_DATE_TO THEN V_DATE_FROM := REC.XDATE; V_DATE_TO := REC.XDATE + 3 - 1; SELECT SUM(XQTY) INTO V_QTY_SUM FROM XX_SALES WHERE XDATE >= V_DATE_FROM AND XDATE <= V_DATE_TO; DBMS_OUTPUT.PUT_LINE(TO_CHAR(V_DATE_FROM, 'YYYYMMDD') || '-----qty: ' || TO_CHAR(V_QTY_SUM)); END IF; END LOOP; END;
Thanks in advance,
Best regards
Zhxiang
Published by: zhxiangxie on April 26, 2012 14:41 fixed the grouping expected dataThere was an article about a similar problem in Oracle Magazine recently:
http://www.Oracle.com/technetwork/issue-archive/2012/12-Mar/o22asktom-1518271.html
See the section on the 'grouping beaches '. They needed a total cumulative who started once the total reaches a certain amount.
You need a total cumulative which starts again when the date changes to group and the dates of beginning and end of each group must be determined dynamically.
This can be done with the analytical functions.
Here is a solution-based 'code listing 5', the solution MODEL, which is recommended in the article.
SELECT FIRST_DATE, SUM(XQTY) SUM_XQTY FROM ( SELECT * FROM xx_sales MODEL DIMENSION BY(ROW_NUMBER() OVER(ORDER BY XDATE) RN) MEASURES(XDATE, XDATE FIRST_DATE, XQTY) RULES( FIRST_DATE[RN > 1] = CASE WHEN XDATE[CV()] - FIRST_DATE[CV() - 1] >= 3 THEN xdate[cv()] ELSE FIRST_DATE[CV() - 1] END ) ) GROUP BY first_date ORDER BY first_date; FIRST_DATE SUM_XQTY --------------------- -------- 2012/05/01 00:00:00 60 2012/05/04 00:00:00 60 2012/05/07 00:00:00 80 2012/05/12 00:00:00 155 2012/05/15 00:00:00 99
If you 9i, there is no function model. In this case, I can give you a solution using START WITH / CONNECT BY that does not work as well.
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Hi all
I'm banging my head on the wall with this one. I have a query that displays the result in the form of two columns, it works fine.
I have a problem when I try to use "group"for the field DSC1 doesn't show duplicates." He transforms the output in column 2, column 3 and column 4 spots white all along.
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<! - start the 2-column output table - >
< table border = "0" width = "90%" border = "0" align = "center" cellpadding = "5" cellspacing = "5" >
< cfset newrow = false< b >
< cfoutput query = "getProduct" group = "DSC1" >
< cfif newrow EQ "true" >
< b >
< / cfif >
< td >
#DSC1 #.
< cfif DSC2 NEQ "" > "".
< br >
#DSC2 #.
< / cfif >< br >
< a href = "DetailsList.cfm? ID = #getProduct.ID # & litm = #getProduct.LITM #" > VIEW < /a > DETAILS
< table >
< cfif getProduct.currentRow MOD 2 EQ 0 >
< /tr >
< cfset newrow = true >
< cfelse >
< cfset newrow = false >
< / cfif >
< / cfoutput >
< /tr >
< /table >The currentRow always property will count the number or records in the record setting loop, if you their output or not.
Since you are not the output values for each record in the Recordset, you must count the itterations yourself.
Put a meter of itteration before the
loop. Update the counter at the top of the
loop. OR on newer versions of CF
Reset the counter in the true clause of the
block, where you also define new line. > Then use the variable in the iit instead the currentRow property to determine the number of items have been posted.
**** OR ****
You could do a simple SQL command does not get duplicates first and then use a loop of
simple without any of the grouping and additional logic that you do. SELECT DISTINCT * FROM ecitm WHERE DSC1 <> ' ' ORDER BY DSC1 #DSC1# -
using 'like' in the group record query
Hello
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I want to list all the names of a table like 'a % ';
query: select name, id (id) to_char of test_name where name like 'a % ';
but I'm not able to give a quote unique in the query.
Is it possible to do?
Published by: Tuts009 on May 9, 2010 01:38In order to use it in this way:
str := :list4||'%'; rg_id := Create_Group_From_Query( rg_name, 'SELECT name,to_char(id) id from test_name where name like ''' || str || '''');
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Hello
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RG_ID RecordGroup;
status NUMBER;
the_rowcount NUMBER;
BEGIN
RG_ID: = find_group ('emp');
status: = Populate_Group ("emp");
the_rowcount: = Get_Group_Row_Count (rg_id);
MESSAGE (the_rowcount);
end;better compliance
skyniazi -
Group records in a Select statement
I want to know, if I can do this with a single select:
I have a table where I have some information with a collar-date:
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-------
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A B C 03/2001
B B C 02/2001
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A B C 03/2000
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Any ideas?
-------
A B C 10/2001
B B C 02/2001
A B C 03/2000Rumburak wrote:
It is not a simple question group. Look at my example. The DateCol is the validity of a combination.If this is not a simple GROUP BY, then what is? Please explain what you are trying to do.
That means each line of output represent?
Why do you want 3 production lines and not 1 or 2, or 4 or 5?
Why some production lines have distinct values in col1, col2 and col3, and others do not?It is possible that you wanted something like this:
WITH got_nums AS ( SELECT col1, col2, col3 , datecol , ROW_NUMBER () OVER ( PARTITION BY col1, col2, col3 ORDER BY datecol ) AS group_num , ROW_NUMBER () OVER ( ORDER BY datecol) AS overall_num FROM tbl ) SELECT col1, col2, col3 , TO_CHAR ( MAX (datecol) , 'MM/YYYY' ) AS datecol_month_year FROM got_nums GROUP BY col1, col2, col3 , overall_num - group_num ORDER BY MAX (datecol) DESC ;
but at least I understand the problem, I can only guess. Guess, this isn't a very effective way to work.
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Using the function count with grouped records
Hi all
This seems like it should be very easy, but I still have to find a simple way to do it.
Suppose I want to count the possibilities which are grouped by Sales Rep at run time I filter this list with a parameter for sales stage and created date.
I've simplified this greatly, but here's what my setup looks like now:
Sales representative*-Count* _
<? for-each-group: opportunity [SalesStage = param1 and creation > param2]; /SalesRep? >
<? SalesRep? >-<? count (current - group (available))? >
<? end for each group -? >
_ Total
The only solution I have to get my grand total so far is to create a variable and permanently keep a total that I will then display in the Total column. It all works, it seems that there should be an easier way, want to do a simple count (Id) for a total general. But given that the Total amount will appear after the end of each group-, I lose the filter that has been applied to the group so that the count is not valid.
Ideas of the experts?
Thank you!To get the total general
useparam2]/Id)?>
Since you have not mentioned the complete xml code, I assumed, as the root.
If this isn't the case, put the full path from the root.If you give some xml examples and explain the output you want, we can fix it immediately.
go through these too... something can be drawn from here.
http://winrichman.blogspot.com/search/label/summation%20In%20BIP
http://winrichman.blogspot.com/search/label/BIP%20Vertical%20sum -
Hi all! I have a difficult situation when I'm BI project.
I have the folder with 3 interactive dashboards. 2 it is hidden.
When I see the top of my BI Windows I see the name of my file, and when I click on it in the menu I can change my dashboard only. But I need to see the name of the folder. I want to see the name of the dashboard immediately when a log on.
More of him in my account dashboard hidden above the window, I see the name of the folder. And when I click on it nothing not.
Please help me. He is very impotent for me.
PS Sorry for my English.Fedor,
Try to change the permissions on your dashboard. Give permission on the dashboard that you want the user to see when it connects will hide automatically other dashboards.
-Red
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Is there a limitation of length of sql in a record group?
Record group contains 4 by union funcion sql statement. When this sql statement longer than 4000 characters then the record group do not allow me to add an additional column to another.
My question is, is there a limitation of length of sql that record the group support?
Developer 10g suit.
Thanks in advance.
As you have discovered that there is a limit in the form designer, on what size the SQL statement may be in the property Query Group Record in your record group. Unfortunately, the forms for the Query Group property help topic Record does not that there is a limit or the limit.
If your request does not fit into the Group Record Query property, you can try to use the integrated Create_Group_From_Query() to fill in your group. Another option would be to create views in your database, and then select the view in the Query property group Record.
If you opt to try the method of Create_Group_From_Query(), just set your Group Record in the navigation of the object by using a SELECT statement (your column names) twice and then programmatically remove the Group and re-create it with the high - Create_Group_From_Query (). See the help topic for the function integrated for a code example.
Craig...
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A function can be called record group - Oracle Form 6i.
Hi all
I want to create query based LOV in Oracle Form 6i.
The query I have use of the record group is as follows:
SELECT DISTINCT
Nr.rec_locator AS rec_locator,
car.car_dte AS car_date,
Get_car_info(:CON.) REF_NO) AS car_number
Car_list_entries CAR
contact_details cdt,
name_records nr
WHERE car.car_id = cdt.car_id
AND cdt.nr_id = nr.id
AND cdt.con_ref_no =: CON. REF_NO
/ * Get_car_info (x NUMBER) is a function of form * /.
This generates an error:
It is said
FRM-12001 (impossible to create the Group Record (check your query)
Kindly guide how can I use the function of form to achieve the desired result.
Thank you very much
Anoop.
Hi Anoop,
I can assure you that the issue is not because of the called function of the record group.
I used the query showing the value of the function; but one thing you should keep in mind is:
If you create a new item not related in a based lov to sql expression that
return a character data type, and if the element related to the used in the function
is generated with a size of 0, then the item not related is generated
with a size of 4000 and a compilation of the form failed with error FRM-30187
the solution to this problem is: lov property > column specification > columns one will be having a greater length and 2000 it set its 2000 which is the maximum value. Then it won't work.
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