Oracle BI group records

Hi all! I have a difficult situation when I'm BI project.
I have the folder with 3 interactive dashboards. 2 it is hidden.
When I see the top of my BI Windows I see the name of my file, and when I click on it in the menu I can change my dashboard only. But I need to see the name of the folder. I want to see the name of the dashboard immediately when a log on.
More of him in my account dashboard hidden above the window, I see the name of the folder. And when I click on it nothing not.
Please help me. He is very impotent for me.

PS Sorry for my English.

Fedor,

Try to change the permissions on your dashboard. Give permission on the dashboard that you want the user to see when it connects will hide automatically other dashboards.

-Red

Tags: Business Intelligence

Similar Questions

FILL MONTHS DYNAMICALLY IN THE ITEM VIA ORACLE FORMS GROUP RECORDING LIST

Experts
I have a query in oracle forms. I need to fill Last_Month, Current_Month & Next_month based on Sys_Date in the list box. I am able to get the values in SQL if I run the query below, but when I use the version of Oracle Forms 10.1.2.0.2, I could not get the values of Mr. can you please guide me where I'm wrong.
declare
v_rg_id recordgroup: = NULL;
Number of V_errorcode;
v_rg_salmth varchar2 (30): = "MONTHS";
Begin
v_rg_id: = find_group (v_rg_salmth);
If id_null (v_rg_id) then
v_rg_id: = create_group_from_query (v_rg_salmth,
"WITH (AS MONTH_COUNTER)
SELECT LEVEL 2 AS ID
OF THE DOUBLE
CONNECT BY LEVEL = 2
UNION
SELECT LEVEL AS ID
OF THE DOUBLE
CONNECT BY LEVEL = 0
)
SELECT TO_CHAR (ADD_MONTHS (TO_CHAR (SYSDATE), ID), MONTH) AS MONTH_COUNTER MONTHS ');
v_errorcode: = populate_group (v_rg_id);
If v_errorcode = 0 then
message ("record group filled with data");
on the other
message ("V_errorcode is:" | ") v_errorcode);
end if;
End if;
populate_list('MASTER.) MONTH, v_rg_id);
end;

The rather complicated query, try

SELECT ADD_MONTHS (SYSDATE-1) TO DOUBLE

UNION ALL

SELECT SYSDATE DOUBLE

UNION ALL

SELECT THE DOUBLE ADD_MONTHS(SYSDATE,1)

BTW. to use a query to populate a list, you must select two values, a label and a value, check it fill listitems dynamically - Andreas Weiden - on Oracle

SQL to group records and apply logic to pick up a record of each group

Hi friends,

I am looking for a query group records on some columns in a table and then each group I want to take just a single folder according to certain rules.

Could have given arranged at will to make my point more clear for you. Here you go:

CREATE TABLE AD_LIST
(
  FILE_NAME             VARCHAR2(50 BYTE),
  ACTIVITY_START        DATE,
  ACTIVITY_END          DATE,
  DIVISION              VARCHAR2(50 BYTE),
  ITEM_CODE             VARCHAR2(50 BYTE),
  MULT                  NUMBER,
  RETAIL                NUMBER,
  AD_PAGE               VARCHAR2(1 BYTE),
  FORECAST              NUMBER,
  MEMO                  VARCHAR2(50 BYTE)
  );

INSERT INTO AD_LIST VALUES ('FILE_1','01-APR-2010','15-APR-2010','B',1111,5,10,'A',10,'This must be in my result');
INSERT INTO AD_LIST VALUES ('FILE_1','01-APR-2010','15-APR-2010','B',1111,1,1,'B',15,'Must not be in my result');
INSERT INTO AD_LIST VALUES ('FILE_1','01-APR-2010','15-APR-2010','B',1111,6,15,'C',11,'Must not be in my result');

INSERT INTO AD_LIST VALUES ('FILE_1','16-APR-2010','30-APR-2010','N',1111,4,20,'D',40,'Must not be in my result');
INSERT INTO AD_LIST VALUES ('FILE_1','16-APR-2010','30-APR-2010','N',1111,5,15,'E',30,'Must not be in my result');
INSERT INTO AD_LIST VALUES ('FILE_1','16-APR-2010','30-APR-2010','N',1111,1,2,'F',20,'This must be in my result');

CREATE TABLE PAGE_RANK
(
  AD_PAGE VARCHAR2(1 BYTE),
  RANK NUMBER
);

INSERT INTO PAGE_RANK VALUES ('A',1);
INSERT INTO PAGE_RANK VALUES ('B',2);
INSERT INTO PAGE_RANK VALUES ('C',3);
INSERT INTO PAGE_RANK VALUES ('D',4);
INSERT INTO PAGE_RANK VALUES ('E',5);
INSERT INTO PAGE_RANK VALUES ('F',6);
COMMIT;

SELECT * FROM AD_LIST

FILE     ACTIVITY     ACTIVITY          ITEM               AD
NAME     START          END          DIV     CODE     MULT     RETAIL     PAGE     FORECAST     MEMO
-----     --------     ---------     ---     ----     ----     -----     ----     ------     -----------------------     
FILE_1     4/1/2010     4/15/2010     B     1111     5     10     A     10     This must be in my result
FILE_1     4/1/2010     4/15/2010     B     1111     1     1     B     15     Must not be in my result
FILE_1     4/1/2010     4/15/2010     B     1111     6     15     C     11     Must not be in my result
FILE_1     4/16/2010     4/30/2010     N     1111     4     20     D     40     Must not be in my result
FILE_1     4/16/2010     4/30/2010     N     1111     5     15     E     30     Must not be in my result
FILE_1     4/16/2010     4/30/2010     N     1111     1     2     F     20     This must be in my result

Now, the AD_LIST table I want to group records based on FILE_NAME, ACTIVITY_START, ACTIVITY_END, DIVISION, ITEM_CODE.
So, in my example here, we have 2 grouped recordset based on the specified columns.

Also, we have a table, PAGE_RANK, who has a rank corresponding to each issue of ad_page. 1. This is a rank higher than 2. This is why page ad 'A' takes precedence over 'B '. The same for all the other pages of ads.

Now, we need to choose an announcement of each ad group in determining page ad rank higher within the Group and the value of mult and retail should be replaced by the value that has min(retail/mult). So, using the above data we will have with the full-page ad = 'A' and ad = page had ' as final results since they have the highest grade of advertising page in their group.
The value of values mult and details of ad_page 'A' = min (10/5, 1/1, 15/6) = 1,1(mult,retail).
The value of values mult and detail of ad_page would be ' = min (20/4, 15/5, 2/1) = 1,2(mult,retail).

Finally I have this query below

SELECT a.file_name,
       a.activity_start,
       a.activity_end,
       a.division,
       a.item_code,
       FIRST_VALUE (a.mult) OVER (PARTITION BY a.file_name, a.activity_start, a.activity_end, a.division, a.item_code ORDER BY (a.retail /
                                                                                                                                a.mult))
                                                                                                    mult,
       FIRST_VALUE (a.retail) OVER (PARTITION BY a.file_name, a.activity_start, a.activity_end, a.division, a.item_code ORDER BY (a.retail /
                                                                                                                                  a.mult))
                                                                                                  retail,
       FIRST_VALUE (a.ad_page) OVER (PARTITION BY a.file_name, a.activity_start, a.activity_end, a.division, a.item_code ORDER BY (b.RANK))
                                                                                                 ad_page,
       a.forecast,
       a.memo                                                                                                 
  FROM ad_list a, page_rank b
 WHERE a.ad_page = b.ad_page

This query is giving me all the records, but with the values of what I wanted in the columns Ad_Page, Mult, and retail.
How can I take only one of each group.

I get this

FILE     ACTIVITY     ACTIVITY          ITEM               AD
NAME     START          END          DIV     CODE     MULT     RETAIL     PAGE     FORECAST     MEMO
-----     --------     ---------     ---     ----     ----     -----     ----     ------     -----------------------     
FILE_1     4/1/2010     4/15/2010     B     1111     1     1     A     15     Must not be in my result
FILE_1     4/1/2010     4/15/2010     B     1111     1     1     A     10     This must be in my result
FILE_1     4/1/2010     4/15/2010     B     1111     1     1     A     11     Must not be in my result
FILE_1     4/16/2010     4/30/2010     N     1111     1     2     D     20     This must be in my result
FILE_1     4/16/2010     4/30/2010     N     1111     1     2     D     30     Must not be in my result
FILE_1     4/16/2010     4/30/2010     N     1111     1     2     D     40     Must not be in my result

But I want this

FILE     ACTIVITY     ACTIVITY          ITEM               AD
NAME     START          END          DIV     CODE     MULT     RETAIL     PAGE     FORECAST     MEMO
-----     --------     ---------     ---     ----     ----     -----     ----     ------     -----------------------     

FILE_1     4/1/2010     4/15/2010     B     1111     1     1     A     10     This must be in my result
FILE_1     4/16/2010     4/30/2010     N     1111     1     2     D     20     This must be in my result

I have to run this query for thousands of such combination of group.
Hope someone can shed some light on this query.

Thanks in advance,
Raj.

Hello

This is called a Query Top - N .

How do you determine which line of each group you want to display?
If this is the line with forecasts as low, then:

WITH   got_r_num     AS
(
SELECT a.file_name,
       a.activity_start,
       a.activity_end,
       a.division,
       a.item_code,
       FIRST_VALUE (a.mult) OVER (PARTITION BY a.file_name, a.activity_start, a.activity_end, a.division, a.item_code ORDER BY (a.retail /
                                                                                                                                a.mult))
                                                                                                    mult,
       FIRST_VALUE (a.retail) OVER (PARTITION BY a.file_name, a.activity_start, a.activity_end, a.division, a.item_code ORDER BY (a.retail /
                                                                                                                                  a.mult))
                                                                                                  retail,
       FIRST_VALUE (a.ad_page) OVER (PARTITION BY a.file_name, a.activity_start, a.activity_end, a.division, a.item_code ORDER BY (b.RNK))
                                                                                                 ad_page,
       a.forecast,
       a.memo,
       ROW_NUMBER () OVER ( PARTITION BY  a.file_name
                               ,                  a.activity_start
                   ,            a.activity_end
                   ,            a.division
                   ,            a.item_code
                   ORDER BY       a.forecast
                 )      AS r_num
  FROM ad_list a, page_rank b
 WHERE a.ad_page = b.ad_page
)
SELECT file_name,
       activity_start,
       activity_end,
       division,
       item_code,
       forecast,
       mult,
       retail,
       ad_page,
       memo
FROM   got_r_num
WHERE  r_num     = 1
;

If it is something else, then change the ORDER BY clause in the ROW_NUMBER function.

Group records between trade unions

Gurus,

It's been a while since I formatted in SQL, but I have developed the following query, which gives me the result below:

     select distinct created_by, count(created_by) receipt_count,  null deliver_count
     from  wms_transaction
     where creation_date > sysdate-10
     and   transaction_type = 'RECEIPT'
     group by  created_by
   union
     select distinct created_by,  null rec_count,  count(created_by) deliver_count
     from  wms_transaction
     where creation_date > sysdate-10
     and   transaction_type = 'DELIVER'
     group by created_by   
     order by receipt_count

CREATED_BY    RECEIPT_COUNT     DELIVER_COUNT
--------------------   -----------------------     ------------------------
SPRECKO                    4
HKUMAR                     4
SPRECKO                                            10
HKUMAR                                           856

The desired output is a user consolidated without additional records...

CREATED_BY    RECEIPT_COUNT     DELIVER_COUNT
--------------------   -----------------------     ------------------------
SPRECKO                    4                       10
HKUMAR                     4                     856

Someone there all of the recommendations? I give the points to obtain useful and accurate responses (someone always comments on the points system when I write that ;-))

Thank you
Scott

Published by: sreese on April 25, 2013 14:23

Published by: sreese on April 25, 2013 14:23

Hello

You can do it with a pivot:

select    created_by
,        count ( CASE
                  WHEN  transaction_type = 'RECEIPT'
                THEN  created_by
            END
          )     as receipt_count
,        count ( CASE
                  WHEN  transaction_type = 'DELIVER'
                THEN  created_by
            END
          )     as deliver_count
from      wms_transaction
where        creation_date    > sysdate - 10
and          transaction_type IN ('DELIVER', 'RECEIPT')
group by  created_by
;

It will be much more effective than a UNION.

The query above works in Oracle 8.1 or more. From Oracle 11, you can also use SELECT... PIVOT.

I hope that answers your question.
If not, post a small example data (CREATE TABLE and only relevant columns, INSERT statements) and also publish outcomes from these data.
Explain, using specific examples, how you get these results from these data.
Always say what version of Oracle you are using (for example, 11.2.0.2.0).
See the FAQ forum {message identifier: = 9360002}

Published by: Frank Kulash on 25 April 2013 14:37

Group records with time
Hi all

This is our requirement.

We must combine records with time.

for example: period = 3
TABLE: XX_SALES
---------------------------------------------
XDATE XQTY
---------------------------------------------
10 5/1/2012
20 2/5/2012
3/5/2012 30
4/5/2012 60
12 2012/5/7
8/5/2012 23
45 8/5/2012
100 12/5 / 2012
5/2012/13 55
5/2012/15 99

== >
---------------------------------------------
XDATE XQTY
---------------------------------------------
1/5/2012 10-> 5/1/2012 Group (5/1/2012 ~ 3/5/2012)
2/5/2012 20-> 5/1/2012 Group (5/1/2012 ~ 3/5/2012)
3/5/2012 30-> 5/1/2012 Group (5/1/2012 ~ 3/5/2012)
4/5/2012 60-> Group 5/2012/4 (4/5/2012 ~ 2012/5/6) *.
7/5/2012 12-> Group 5/2012/7 (5/7/2012 ~ 9/5/2012) *.
8/5/2012 23-> Group 5/2012/7 (5/7/2012 ~ 9/5/2012) *.
8/5/2012 45-> Group 5/2012/7 (5/7/2012 ~ 9/5/2012) *.
5/2012/12 100-> Group 5/12/2012 (2012/5/12 ~ 14/5/2012) *.
13/5/2012 55-> Group 5/12/2012 (2012/5/12 ~ 14/5/2012) *.
5/15/2012 99-> Group 5/15/2012 (15/5/2012 ~ 5/17/2012) *.

After amount to combine with period = 3, the result will be
---------------------------------------------
XDATE_G XQTY_G
---------------------------------------------
60 1/5/2012
4/5/2012 60
2012/5/7 80
12/5/2012 155
5/2012/15 99

Here's the example script
```
 
create table XX_SALES(XDATE DATE, XQTY Number);
insert into XX_SALES VALUES(to_date('20120501','YYYYMMDD'),10);
insert into XX_SALES VALUES(to_date('20120502','YYYYMMDD'),20);
insert into XX_SALES VALUES(to_date('20120503','YYYYMMDD'),30);
insert into XX_SALES VALUES(to_date('20120504','YYYYMMDD'),60);
insert into XX_SALES VALUES(to_date('20120507','YYYYMMDD'),12);
insert into XX_SALES VALUES(to_date('20120508','YYYYMMDD'),23);
insert into XX_SALES VALUES(to_date('20120508','YYYYMMDD'),45);
insert into XX_SALES VALUES(to_date('20120512','YYYYMMDD'),100);
insert into XX_SALES VALUES(to_date('20120513','YYYYMMDD'),55);
insert into XX_SALES VALUES(to_date('20120515','YYYYMMDD'),99);
 
```
We can solve this problem by using the loop now:
to find the XDATE_G and it's rank in the loop and the XQTY in the range of the sum.
```
DECLARE
  V_DATE_FROM DATE := NULL;
  V_DATE_TO   DATE := NULL;
  V_QTY_SUM   NUMBER := 0;
  CURSOR CUR_DATE IS
    SELECT DISTINCT XDATE FROM XX_SALES ORDER BY XDATE;
BEGIN
  FOR REC IN CUR_DATE LOOP
    IF V_DATE_TO IS NULL OR REC.XDATE > V_DATE_TO THEN
      V_DATE_FROM := REC.XDATE;
      V_DATE_TO   := REC.XDATE + 3 - 1;
      SELECT SUM(XQTY)
        INTO V_QTY_SUM
        FROM XX_SALES
       WHERE XDATE >= V_DATE_FROM
         AND XDATE <= V_DATE_TO;
      DBMS_OUTPUT.PUT_LINE(TO_CHAR(V_DATE_FROM, 'YYYYMMDD') ||
                           '-----qty: ' || TO_CHAR(V_QTY_SUM));
    END IF;
  END LOOP;
END;
```
Is it possible to solve this problem by using analyze sql?

Thanks in advance,
Best regards
Zhxiang

Published by: zhxiangxie on April 26, 2012 14:41 fixed the grouping expected data
There was an article about a similar problem in Oracle Magazine recently:

http://www.Oracle.com/technetwork/issue-archive/2012/12-Mar/o22asktom-1518271.html

See the section on the 'grouping beaches '. They needed a total cumulative who started once the total reaches a certain amount.

You need a total cumulative which starts again when the date changes to group and the dates of beginning and end of each group must be determined dynamically.

This can be done with the analytical functions.

Here is a solution-based 'code listing 5', the solution MODEL, which is recommended in the article.
```
SELECT FIRST_DATE, SUM(XQTY) SUM_XQTY FROM (
  SELECT * FROM xx_sales
  MODEL DIMENSION BY(ROW_NUMBER() OVER(ORDER BY XDATE) RN)
  MEASURES(XDATE, XDATE FIRST_DATE, XQTY)
  RULES(
    FIRST_DATE[RN > 1] =
      CASE WHEN XDATE[CV()] - FIRST_DATE[CV() - 1] >= 3
      THEN xdate[cv()]
      ELSE FIRST_DATE[CV() - 1]
      END
  )
)
GROUP BY first_date ORDER BY first_date;

FIRST_DATE            SUM_XQTY
--------------------- --------
2012/05/01 00:00:00         60
2012/05/04 00:00:00         60
2012/05/07 00:00:00         80
2012/05/12 00:00:00        155
2012/05/15 00:00:00         99
```
If you 9i, there is no function model. In this case, I can give you a solution using START WITH / CONNECT BY that does not work as well.

BlackBerry smartphone how to change view Contact to see category / group records only

Hi everyone, just got my first BlackBerry.

The Bold (9000) is the best screen.

To be honest, I was anti-BlackBerry when they first came out.

Did not like the feel of plastic.

Now that the "BOLD" is here, and for some time, finally I turned.

After using it for only a week, I must say, I am very impressed and now intend to continue to use it.

I will also continue to have a second very basic phone.

I thought that most of the things, even added many additional services, most of them style of Google.

SE BIS, soon change BES to access our new SBS Exchange work.

Even some of the most difficult functions, services and settings can be solved for me.

I do not work in a dealership take Optus, mainly focused on business.

On the issue...

Is it possible to get your hands (first / default) connect with view to display the 'files' only category.

I really wish I could open my contacts, select my category, then search.

For me, it would be so much easier.

For example. CONTACTS-Office-Steve

or CONTACTS-family-MOM

or CONTACTS-friends-David

or CONTACTS-Optus-Wireless Technical Support

This would save search me, especially since some contacts may have a different name, then I expect first (for example, 'hundreds' of Optus numbers, can be 'Pre-activation ULL' or 'Fixed installation support line')

I guess he will have to show contacts that have not been assigned to a group (category).

If these contacts have been enumerated below the category records, it would be ideal (for me).

Perhaps, even if there was a possibility to classify them with the records of the category FIRST then all contacts in alpha?

I know that a contact can be assigned to several categories (very useful).

If this isn't an option, are there any recommended additional applications that can do this?

I hope as clean and efficient as BlackBerry original aps.

A few years ago, I used a Windows based mobile/PDA.

To get more out of it, I also installed several aps SPB.

Ultimately if an additional access point is required and is not free (IE must buy), it would really need a trial period.

Thanks to anyone for ANY Advisor.

I'm happy to be part of a more professional group.

Ian

This option as a view is not available on the BlackBerry, and I'm not aware of any third-party application to do, there could be.

One option would be to name all your groups in such a way that they would appear first in your Contact list.

As instead of naming a group of 'Friends', you would be the name "." See list Friends"with a period at the beginning, which will force this group name to the top of the Contact.

How to insert the output in the Oracle database table records

Nice day
I have two tables (table A and table B) in my oracle database I created a process for mapping from Table A duplicate records to Table B, and the result (reports) must be inserted into the Table B. I can't make this process. Can someone help me please.
Thank you and best regards,
Muhammed Faraz

Hi Muhammed,

You will need create an export job and set up a new job as a result. Take a look in the help topic "export data" as he will explain the different options [Add/Remove and insert/etc.].

Thank you

Nick

Group records as well as frequent mailers

Hi people,
I'm looking at a scenario where I would like to group the dates together (for the most part, we assume they are similar and close enough dates and so probably on the same date) when they are close together. The idea is to eliminate the possible duplicates.
Create table scripts and INSERT into the table:
```
create table orders_tb (order_id varchar2(4), order_date date);

insert into orders_tb (order_id,order_date) values ('1001',to_date('31-DEC-13','DD-MON-RR'));
insert into orders_tb (order_id,order_date) values ('1001',to_date('02-JAN-14','DD-MON-RR'));
insert into orders_tb (order_id,order_date) values ('1001',to_date('06-JAN-14','DD-MON-RR'));
insert into orders_tb (order_id,order_date) values ('1001',to_date('12-JAN-14','DD-MON-RR'));
insert into orders_tb (order_id,order_date) values ('1002',to_date('02-FEB-14','DD-MON-RR'));
insert into orders_tb (order_id,order_date) values ('1002',to_date('02-MAR-14','DD-MON-RR'));
insert into orders_tb (order_id,order_date) values ('1002',to_date('02-MAR-14','DD-MON-RR'));
```
If I ran the following SELECT statement, I would get 6 entries:
```
select distinct order_id, order_date from orders_tb order by order_id, order_date;
```
However, for the most part, I would like to Order ID 1001 subject only two records. The rule for including dates, that is all the dates to be within 10 days of the date of MIN.
```
1001 31-DEC-2013
1001 12-JAN-2014
```
Regarding the command ID 1002, he will tell you that the dates are very far.
```
1002 02-FEB-2014
1002 02-MAR-2014
```
Any help would be greatly appreciated.
Thank you!

Hello

You want to always 2 rows for each order_id exit or you want sometimes 1 or 3 or more?

You can test it with a little more data sample that test situations like these. For example, in addition to the sample data that you posted:

insert into orders_tb (order_id, order_date) values ('1001 ', to_date('13-JAN-2014','DD-MON-YYYY'));

insert into orders_tb (order_id, order_date) values ('1001 ', to_date('19-JAN-2014','DD-MON-YYYY'));

insert into orders_tb (order_id, order_date) values ('1001 ', to_date('25-JAN-2014','DD-MON-YYYY'));

insert into orders_tb (order_id, order_date) values ('1003 ', to_date('01-JAN-2014','DD-MON-YYYY'));

insert into orders_tb (order_id, order_date) values ('1003 ', to_date('10-JAN-2014','DD-MON-YYYY'));

Here's one way:

WITH got_next_date AS

(

SELECT DISTINCT

order_id, order_date

MIN (order_date) over (PARTITION BY order_id) AS start_date

MIN (order_date) over (PARTITION BY order_id

ORDER BY order_date

RANGE BETWEEN 10.000001 MORE

AND UNBOUNDED FOLLOWING

), Next_date

Of orders_tb

)

SELECT order_id, order_date

OF got_next_date

START WITH order_date = start_date

CONNECT BY order_date = next_date PRIOR

AND order_id = order_id PRIOR

;

Output (including the sample data, I added):

ORDER_ID, ORDER_DATE

-------- -----------

1001 December 31, 2013

1001 12 January 2014

1001 January 25, 2014

1002 February 2, 2014

1002 2 March 2014

1003 1 January 2014

Need help with Oracle SQL merge records according to date and term dates

Hi all

I need help to find this little challenge.

I have groups and flags and effective dashboards and dates of term against these indicators according to the following example:

GroupName	Flag_A	Flag_B	Eff_date	Term_date
Group_A	THERE	THERE	20110101	99991231
Group_A	N	N	20100101	20101231
Group_A	N	N	20090101	20091231
Group_A	N	N	20060101	20081231
Group_A	N	THERE	20040101	20051231
Group_A	THERE	THERE	20030101	20031231
Group_B	N	THERE	20040101	99991231
Group_B	N	THERE	20030101	20031231

As you can see, group_A had the same combination of (N, N) flag for three successive periods. I want to merge all the time periods with the same indicators in one. Where entry into force will be the most early (underlined) time period and end date will be later (underlined)

So the final result should look like this:

GroupName	Flag_A	Flag_B	Eff_date	Term_date
Group_A	THERE	THERE	20110101	99991231
Group_A	N	N	20060101	20101231
Group_A	N	THERE	20040101	20051231
Group_A	THERE	THERE	20030101	20031231
Group_B	N	THERE	20030101	99991231

Thanks for your help

Here's the DDL script

drop table TMP_group_test;

create table TMP_group_test (groupname varchar2 (8))

, flag_a varchar2 (1)

, flag_b varchar2 (1)

, eff_date varchar2 (8)

, term_date varchar2 (8)

);

insert into TMP_group_test values ('Group_A', 'Y', 'Y', ' 20110101 ', ' 99991231');

insert into TMP_group_test values ('Group_A', 'n', ' n ', ' 20100101 ', ' 20101231');

insert into TMP_group_test values ('Group_A', 'n', ' n ', ' 20090101 ', ' 20091231');

insert into TMP_group_test values ('Group_A', 'n', ' n ', ' 20060101 ', ' 20081231');

insert into TMP_group_test values ('Group_A', 'n', 'Y', ' 20040101 ', ' 20051231');

insert into TMP_group_test values ('Group_A', 'Y', 'Y', ' 20030101 ', ' 20031231');

insert into TMP_group_test values ('Group_B', 'n', 'Y', ' 20040101 ', ' 99991231');

insert into TMP_group_test values ('Group_B', 'n', 'Y', ' 20030101 ', ' 20031231');

commit;

Post edited by: user13040446

It is the closest, I went to the solution

I create two rows;

Rnk1: partition by group name, order of eff_date / / desc: this grade will sort the records of the most recent and handed to zero for each group\

Rnk2: (dense) partition by group name, flag_A, flagb: this grade for each combination of group\flag gives a number so that they are classified as "families".

Then I use the function analytic min

Min (eff_date) more (partition of GroupName, rnk2): the idea is that, for each Member of the same family, the new date is the min of the family (and the max for the date of the term), at the end I just need separate so that the duplicates are gone

Now the problem. As you can see from the query below, records of 1 and 6 (as identified by rownum) are identified in the same family, because they have the same combination of flag, but they are not successive, so everyone must keep its own date of entry into force.

If only I can make the distinction between these two that would solve my problem

Query:

Select rowNum,GroupName, flag_a, flag_b, eff_date, term_date, rnk1, rnk2

, min (eff_date) more than (partition by GroupName rnk2( ) min_eff

(

Select rowNum,

GroupName , flag_a , flag_b , eff_date , term_date

rank() more than (partition by GroupName stopped by eff_date desc) rnk1

DENSE_RANK() more than (partition by GroupName order by flag_A flag_B ( ) rnk2

de dsreports . tmp_group_test

) order by rowNum

Hello

user13040446 wrote:

Hi KSI.

Thanks for your comments, you were able to distinguish between these lines highlight, but lost lines 2,3,4 which are supposed to have the same date min = 20060101.

Please see the table wanted to see the final result I want to reach

Thanks again

This first answer is basically correct, but in the main query, you want to use the function MIN, not the analytical function aggregation and GROUP BY columns with common values, like this:

WITH got_output_group AS

(

SELECT GroupName, flag_a, flag_b, eff_date, term_date

ROW_NUMBER () OVER (PARTITION BY GroupName

ORDER BY eff_date

)

-ROW_NUMBER () OVER (PARTITION BY GroupName, flag_a, flag_b)

ORDER BY eff_date

) AS output_group

OF tmp_group_test

)

SELECT GroupName, flag_a, flag_b

MIN (eff_date) AS eff_date

MAX (term_date) AS term_date

OF got_output_group

GROUP BY GroupName, flag_a, flag_b

output_group

ORDER BY GroupName

eff_date DESC

;

The result I get is

GROUP_NA F F EFF_DATE TERM_DAT

-------- - - -------- --------

Group_A Y 20110101 99991231 Y

N Group_A 20101231 20060101 N

Group_A N 20051231 20040101 Y

Group_A Y Y 20031231-20030101

Group_B N Y 99991231 20030101

which is what you asked for.

Grouping records

Hi all

I have this table

WITH taba
        AS (SELECT   83573 AS id, 135433 AS pe_rule_id, 46493 AS uc_id
              FROM   DUAL
            UNION ALL
            SELECT   83574 AS id, 135433 AS pe_rule_id, 46512 AS uc_id
              FROM   DUAL
            UNION ALL
            SELECT   83557 AS id, 137004 AS pe_rule_id, 47277 AS uc_id
              FROM   DUAL
            UNION ALL
            SELECT   83558 AS id, 139647 AS pe_rule_id, 47277 AS uc_id
              FROM   DUAL
            UNION ALL
            SELECT   83571 AS id, 144804 AS pe_rule_id, 46493 AS uc_id
              FROM   DUAL
            UNION ALL
            SELECT   83572 AS id, 144804 AS pe_rule_id, 46512 AS uc_id
              FROM   DUAL)
SELECT   *
  FROM   taba

I need to get all records with MIN (ID), that have the same group uc_id records.
Return:
135433 46493
46512 135433
137004 47277

For example, 2 = 144804 pe_rule_id records have both the same uc_id as the chronogram pe_rule_id = 135433 2. In this case, I need only the records pe_rule_id = 135433

This is just one example. I may have records with 3 or more uc_id diferent to the same pe_rule_id.

Can you help me please?
Thank you

Filipe Almeida

Do you mean min (pe_rule_id)?

Like this?

SQL> ed
Wrote file afiedt.buf

  1  WITH taba
  2          AS (SELECT   83573 AS id, 135433 AS pe_rule_id, 46493 AS uc_id
  3                FROM   DUAL
  4              UNION ALL
  5              SELECT   83574 AS id, 135433 AS pe_rule_id, 46512 AS uc_id
  6                FROM   DUAL
  7              UNION ALL
  8              SELECT   83557 AS id, 137004 AS pe_rule_id, 47277 AS uc_id
  9                FROM   DUAL
 10              UNION ALL
 11              SELECT   83558 AS id, 139647 AS pe_rule_id, 47277 AS uc_id
 12                FROM   DUAL
 13              UNION ALL
 14              SELECT   83571 AS id, 144804 AS pe_rule_id, 46493 AS uc_id
 15                FROM   DUAL
 16              UNION ALL
 17              SELECT   83572 AS id, 144804 AS pe_rule_id, 46512 AS uc_id
 18                FROM   DUAL)
 19  select pe_rule_id, uc_id
 20  from taba where pe_rule_id in (
 21     SELECT   min(pe_rule_id)
 22     FROM   taba
 23     group by uc_id
 24*    having count(*) > 1)
SQL> /

PE_RULE_ID      UC_ID
---------- ----------
    137004      47277
    135433      46512
    135433      46493

Published by: BluShadow on August 3, 2011 13:26
p.s. Thanks for providing data in an easy to use format. :)

Output and group records into several column format problem

Hi all
I'm banging my head on the wall with this one. I have a query that displays the result in the form of two columns, it works fine.
I have a problem when I try to use "group"for the field DSC1 doesn't show duplicates." He transforms the output in column 2, column 3 and column 4 spots white all along.
Someone knows how can I get it to display 2 columns of output and does not show in double DSC1 fields? The following are examples of what is happening:

1 example of what he does without group (note to Apple is twice, which is not):
Apples apples
Orange peaches
banannas grapes
What I need to do (only show each DSC1 once and continue with the format of two columns) :
oranges apples
Fisheries banannas
grapes
Here is the code I use:
< cfquery name = "getProduct" datasource = "mydb" >
SELECT * from ecitm
WHERE DSC1 <>' '
order by DSC1
< / cfquery >
<! - start the 2-column output table - >
< table border = "0" width = "90%" border = "0" align = "center" cellpadding = "5" cellspacing = "5" >

< cfset newrow = false
< b >
< cfoutput query = "getProduct" group = "DSC1" >

< cfif newrow EQ "true" >
< b >
< / cfif >
< td >
#DSC1 #.
< cfif DSC2 NEQ "" > "".
< br >
#DSC2 #.
< / cfif >
< br >
< a href = "DetailsList.cfm? ID = #getProduct.ID # & litm = #getProduct.LITM #" > VIEW < /a > DETAILS
< table >

< cfif getProduct.currentRow MOD 2 EQ 0 >
< /tr >
< cfset newrow = true >
< cfelse >
< cfset newrow = false >
< / cfif >

< / cfoutput >
< /tr >
< /table >

The currentRow always property will count the number or records in the record setting loop, if you their output or not.

Since you are not the output values for each record in the Recordset, you must count the itterations yourself.

Put a meter of itteration before the loop.

Update the counter at the top of the loop.

OR on newer versions of CF

Reset the counter in the true clause of the block, where you also define new line. >

Then use the variable in the iit instead the currentRow property to determine the number of items have been posted.

**** OR ****

You could do a simple SQL command does not get duplicates first and then use a loop of simple without any of the grouping and additional logic that you do.
```
SELECT DISTINCT *
     FROM ecitm
     WHERE DSC1 <> ' '
     ORDER BY DSC1




     #DSC1#
     

    
```

using 'like' in the group record query
Hello

(Forms 6i)
I dynamically create a record group.

Then to when a new trigger for a list item.
I want to list all the names of a table like 'a % ';

query: select name, id (id) to_char of test_name where name like 'a % ';

but I'm not able to give a quote unique in the query.
Is it possible to do?

Published by: Tuts009 on May 9, 2010 01:38
In order to use it in this way:
```
str := :list4||'%';
rg_id := Create_Group_From_Query( rg_name,
                           'SELECT name,to_char(id) id from test_name where name like ''' || str || '''');
```

record group records
How to count the records in the record group?
Hello
Get_Group_Row_Count is used to count the records in the record group.

DECLARE
RG_ID RecordGroup;
status NUMBER;
the_rowcount NUMBER;
BEGIN
RG_ID: = find_group ('emp');
status: = Populate_Group ("emp");

the_rowcount: = Get_Group_Row_Count (rg_id);
MESSAGE (the_rowcount);
end;

better compliance
skyniazi

Group records in a Select statement

I want to know, if I can do this with a single select:

I have a table where I have some information with a collar-date:

Column1  Column2  Column3  DateCol

-------

A        B        C        10/2001

A        B        C        03/2001

B        B        C        02/2001

B        B        C        01/2001

A        B        C        03/2000

Now, I want to bring together the combination of col1-3, but in chronological order. This should be the result:

Column1  Column2  Column3  DateCol

-------

A        B        C        10/2001

B        B        C        02/2001

A        B        C        03/2000

Any ideas?

Rumburak wrote:
It is not a simple question group. Look at my example. The DateCol is the validity of a combination.

If this is not a simple GROUP BY, then what is? Please explain what you are trying to do.
That means each line of output represent?
Why do you want 3 production lines and not 1 or 2, or 4 or 5?
Why some production lines have distinct values in col1, col2 and col3, and others do not?

It is possible that you wanted something like this:

WITH     got_nums     AS
(
     SELECT     col1, col2, col3
     ,     datecol
     ,     ROW_NUMBER () OVER ( PARTITION BY  col1, col2, col3
                               ORDER BY          datecol
                       )                    AS group_num
     ,     ROW_NUMBER () OVER ( ORDER BY      datecol)     AS overall_num
     FROM     tbl
)
SELECT       col1, col2, col3
,       TO_CHAR ( MAX (datecol)
              , 'MM/YYYY'
            )          AS datecol_month_year
FROM       got_nums
GROUP BY  col1, col2, col3
,            overall_num - group_num
ORDER BY  MAX (datecol)               DESC
;

but at least I understand the problem, I can only guess. Guess, this isn't a very effective way to work.

Using the function count with grouped records
Hi all

This seems like it should be very easy, but I still have to find a simple way to do it.

Suppose I want to count the possibilities which are grouped by Sales Rep at run time I filter this list with a parameter for sales stage and created date.
I've simplified this greatly, but here's what my setup looks like now:

Sales representative*-Count* _
<? for-each-group: opportunity [SalesStage = param1 and creation > param2]; /SalesRep? >
<? SalesRep? >-<? count (current - group (available))? >
<? end for each group -? >
_ Total

The only solution I have to get my grand total so far is to create a variable and permanently keep a total that I will then display in the Total column. It all works, it seems that there should be an easier way, want to do a simple count (Id) for a total general. But given that the Total amount will appear after the end of each group-, I lose the filter that has been applied to the group so that the count is not valid.

Ideas of the experts?
Thank you!
To get the total general
use
```
param2]/Id)?>
```
Since you have not mentioned the complete xml code, I assumed, as the root.
If this isn't the case, put the full path from the root.

If you give some xml examples and explain the output you want, we can fix it immediately.

go through these too... something can be drawn from here.
http://winrichman.blogspot.com/search/label/summation%20In%20BIP
http://winrichman.blogspot.com/search/label/BIP%20Vertical%20sum

Oracle BI group records

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