Help in the Search Condition in the SQL query

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• Need help in the sql query

  Hi all

  Here is the sql query,

  Select papf.employee_number,

  -papf.full_name, ppa.effective_date, pp.payroll_name,

  PET.element_name,

  PIV. Name input_value,

  prrv.result_value

  -, ppa.payroll_action_id, ppa.time_period_id

  Of

  Apps.pay_payroll_actions App,

  pay_assignment_actions AAP,

  pay_payrolls_f pp,

  pay_run_results prr,

  prrv pay_run_result_values,

  pay_input_values_f piv,

  animal pay_element_types_f,

  Apps.per_all_assignments_f ADP,

  Apps.per_all_people_f women's wear

  -where ppa.payroll_action_id =: payroll_action_id - give your payroll_action_id

  where ppa.payroll_id =: payroll_id

  and ppa.payroll_action_id =: payroll_action_id

  - and paa.assignment_action_id =: assignment_action_id

  and ppa.payroll_action_id = paa.payroll_action_id

  and ppa.payroll_id = pp.payroll_id

  and paa.assignment_action_id = prr.assignment_action_id

  and prr.run_result_id = prrv.run_result_id

  and prrv.input_value_id = piv.input_value_id

  and piv.element_type_id = pet.element_type_id

  and paaf.assignment_id = paa.assignment_id

  and paaf.person_id = papf.person_id

  and trunc (sysdate) between pp.effective_start_date and pp.effective_end_date

  and trunc (sysdate) between pet.effective_start_date and pet.effective_end_date

  and trunc (sysdate) between piv.effective_start_date and piv.effective_end_date

  and trunc (sysdate) between paaf.effective_start_date and paaf.effective_end_date

  and trunc (sysdate) between papf.effective_start_date and papf.effective_end_date

  - and papf.employee_number = '1'

  - and ppa.effective_date = July 22, 2014"

  and pet.element_name in ('Local Mission allowance', "Compensation of Mission International")

  order by 1.3

  The result is:

  Employee_number Element_Name Input_Value Result_value

  1 compensation of Mission international day amount 1000

  1 compensation of international Mission Distance days 4

  1 value to pay compensation of 1200 International Mission

  1 International Mission allowance Start Date 01/01/2014

  1 compensation of Mission international day amount 800

  1 compensation of international Mission Distance days 10

  1 International Mission allowance pay value 2000

  1 International Mission allowance Start Date 01/02/2014

  1 compensation of Mission local day amount 500

  1 compensation of local Mission Distance days 10

  1 Mission allowance paid local value 1000

  1 compensation of local Mission Start Date 01/11/2014

  Desired output:

  Employee_number Element_Name Day_Amount Distance_Days Pay_Value Start_Date

  1 compensation of international Mission 1000, 1200 4 2014/01/01

  1

  International Mission allowance

  800

  10

  2000

  01/02/2014

  1

  Mission local compensation

  500

  10

  1000

  01/11/2014

  Please suggest.

  INSERT statement:

  TOGETHER TO DEFINE

  Insert into APPS. PER_ALL_PEOPLE_F

  (EMPLOYEE_NUMBER, NOM_ELEMENT, INPUT_VALUE, RESULT_VALUE)

  Values

  ('1', 'International Mission allowance', 'Day amount', '1000');

  Insert into APPS. PER_ALL_PEOPLE_F

  (EMPLOYEE_NUMBER, NOM_ELEMENT, INPUT_VALUE, RESULT_VALUE)

  Values

  ('1', 'International Mission allowance', 'Day amount', '1000');

  Insert into APPS. PER_ALL_PEOPLE_F

  (EMPLOYEE_NUMBER, NOM_ELEMENT, INPUT_VALUE, RESULT_VALUE)

  Values

  ('1', 'International Mission allowance', 'number of orders', '196');

  Insert into APPS. PER_ALL_PEOPLE_F

  (EMPLOYEE_NUMBER, NOM_ELEMENT, INPUT_VALUE, RESULT_VALUE)

  Values

  ('1', 'International Mission allowance', 'number of orders', '195');

  Insert into APPS. PER_ALL_PEOPLE_F

  (EMPLOYEE_NUMBER, NOM_ELEMENT, INPUT_VALUE, RESULT_VALUE)

  Values

  ('1', 'International Mission allowance', ' Distance days, 4 ");

  Insert into APPS. PER_ALL_PEOPLE_F

  (EMPLOYEE_NUMBER, NOM_ELEMENT, INPUT_VALUE, RESULT_VALUE)

  Values

  ('1', 'International Mission allowance', ' Distance days, 1 ");

  Insert into APPS. PER_ALL_PEOPLE_F

  (EMPLOYEE_NUMBER, NOM_ELEMENT, INPUT_VALUE, RESULT_VALUE)

  Values

  ("1', 'International Mission allowance', 'employee Category", "scale of employment medical cities");

  Insert into APPS. PER_ALL_PEOPLE_F

  (EMPLOYEE_NUMBER, NOM_ELEMENT, INPUT_VALUE, RESULT_VALUE)

  Values

  ("1', 'International Mission allowance', 'employee Category", "scale of employment medical cities");

  Insert into APPS. PER_ALL_PEOPLE_F

  (EMPLOYEE_NUMBER, NOM_ELEMENT, INPUT_VALUE, RESULT_VALUE)

  Values

  ('1', 'International Mission allowance', 'Class level', 'G3');

  Insert into APPS. PER_ALL_PEOPLE_F

  (EMPLOYEE_NUMBER, NOM_ELEMENT, INPUT_VALUE, RESULT_VALUE)

  Values

  ('1', 'International Mission allowance', 'Class level', 'G3');

  Insert into APPS. PER_ALL_PEOPLE_F

  (EMPLOYEE_NUMBER, NOM_ELEMENT, INPUT_VALUE, RESULT_VALUE)

  Values

  ('1', 'International Mission allowance', 'class of employment, ' ');

  Insert into APPS. PER_ALL_PEOPLE_F

  (EMPLOYEE_NUMBER, NOM_ELEMENT, INPUT_VALUE, RESULT_VALUE)

  Values

  ('1', 'International Mission allowance', 'class of employment, ' ');

  Insert into APPS. PER_ALL_PEOPLE_F

  (EMPLOYEE_NUMBER, NOM_ELEMENT, INPUT_VALUE, RESULT_VALUE)

  Values

  ('1', 'International Mission allowance', 'Country of Mission', ' 3003 - Kuwait ");

  Insert into APPS. PER_ALL_PEOPLE_F

  (EMPLOYEE_NUMBER, NOM_ELEMENT, INPUT_VALUE, RESULT_VALUE)

  Values

  ('1', 'International Mission allowance', 'Country of Mission', ' 2004 - Canada ");

  Insert into APPS. PER_ALL_PEOPLE_F

  (EMPLOYEE_NUMBER, NOM_ELEMENT, INPUT_VALUE, RESULT_VALUE)

  Values

  ('1', 'International Mission allowance', ' Mission days, 4' ");

  Insert into APPS. PER_ALL_PEOPLE_F

  (EMPLOYEE_NUMBER, NOM_ELEMENT, INPUT_VALUE, RESULT_VALUE)

  Values

  ('1', 'International Mission allowance', ' Mission days, 3' ");

  Insert into APPS. PER_ALL_PEOPLE_F

  (EMPLOYEE_NUMBER, NOM_ELEMENT, INPUT_VALUE, RESULT_VALUE)

  Values

  ('1', 'compensation of Mission international","End of Mission Date"' 2014/07/10 00:00:00 ');

  Insert into APPS. PER_ALL_PEOPLE_F

  (EMPLOYEE_NUMBER, NOM_ELEMENT, INPUT_VALUE, RESULT_VALUE)

  Values

  ('1', 'compensation of Mission international","End of Mission Date"' 2014/07/19 00:00:00 ');

  Insert into APPS. PER_ALL_PEOPLE_F

  (EMPLOYEE_NUMBER, NOM_ELEMENT, INPUT_VALUE, RESULT_VALUE)

  Values

  ('1', 'compensation of Mission international", 'Mission Start Date', ' 2014/07/07 00:00:00 ');

  Insert into APPS. PER_ALL_PEOPLE_F

  (EMPLOYEE_NUMBER, NOM_ELEMENT, INPUT_VALUE, RESULT_VALUE)

  Values

  ('1', 'compensation of Mission international", 'Mission Start Date', ' 2014/07/17 00:00:00 ');

  Insert into APPS. PER_ALL_PEOPLE_F

  (EMPLOYEE_NUMBER, NOM_ELEMENT, INPUT_VALUE, RESULT_VALUE)

  Values

  ('1', 'International Mission allowance', 'value of pay', '3000');

  Insert into APPS. PER_ALL_PEOPLE_F

  (EMPLOYEE_NUMBER, NOM_ELEMENT, INPUT_VALUE, RESULT_VALUE)

  Values

  ('1', 'International Mission allowance', 'value of pay', '4000');

  00:00 ');

  Insert into APPS. PER_ALL_PEOPLE_F

  (EMPLOYEE_NUMBER, NOM_ELEMENT, INPUT_VALUE, RESULT_VALUE)

  Values

  ('70', 'Local Mission allowance', 'number of orders', '45');

  Insert into APPS. PER_ALL_PEOPLE_F

  (EMPLOYEE_NUMBER, NOM_ELEMENT, INPUT_VALUE, RESULT_VALUE)

  Values

  ('70', 'Local Mission allowance', 'number of orders', "456789");

  Insert into APPS. PER_ALL_PEOPLE_F

  (EMPLOYEE_NUMBER, NOM_ELEMENT, INPUT_VALUE, RESULT_VALUE)

  Values

  ('70 ', 'local Mission allowance', ' away days '0' ");

  Insert into APPS. PER_ALL_PEOPLE_F

  (EMPLOYEE_NUMBER, NOM_ELEMENT, INPUT_VALUE, RESULT_VALUE)

  Values

  ('70 ', 'local Mission allowance', ' Distance days, 1 ");

  Insert into APPS. PER_ALL_PEOPLE_F

  (EMPLOYEE_NUMBER, NOM_ELEMENT, INPUT_VALUE, RESULT_VALUE)

  Values

  ('70 ', 'local Mission allowance', 'Provided food', 'Y');

  Insert into APPS. PER_ALL_PEOPLE_F

  (EMPLOYEE_NUMBER, NOM_ELEMENT, INPUT_VALUE, RESULT_VALUE)

  Values

  ('70', 'compensation of local Mission","Accommodation provided", 'Y');

  Insert into APPS. PER_ALL_PEOPLE_F

  (EMPLOYEE_NUMBER, NOM_ELEMENT, INPUT_VALUE, RESULT_VALUE)

  Values

  ('70', 'compensation of local Mission","Accommodation provided", 'Y');

  Insert into APPS. PER_ALL_PEOPLE_F

  (EMPLOYEE_NUMBER, NOM_ELEMENT, INPUT_VALUE, RESULT_VALUE)

  Values

  ('70 ', "local Mission allowance", "Mission City", "AL MEDINA");

  Insert into APPS. PER_ALL_PEOPLE_F

  (EMPLOYEE_NUMBER, NOM_ELEMENT, INPUT_VALUE, RESULT_VALUE)

  Values

  ('70 ', "local Mission allowance", "Mission City", "RIYADH");

  Insert into APPS. PER_ALL_PEOPLE_F

  (EMPLOYEE_NUMBER, NOM_ELEMENT, INPUT_VALUE, RESULT_VALUE)

  Values

  ('70 ', 'local Mission allowance', ' Mission days, 4' ");

  Insert into APPS. PER_ALL_PEOPLE_F

  (EMPLOYEE_NUMBER, NOM_ELEMENT, INPUT_VALUE, RESULT_VALUE)

  Values

  ('70 ', 'local Mission allowance', ' Mission days, 5' ");

  Insert into APPS. PER_ALL_PEOPLE_F

  (EMPLOYEE_NUMBER, NOM_ELEMENT, INPUT_VALUE, RESULT_VALUE)

  Values

  ('70', 'Local Mission allowance', 'End of Mission Date' ' 2014/06/16 00:00:00 ');

  Insert into APPS. PER_ALL_PEOPLE_F

  (EMPLOYEE_NUMBER, NOM_ELEMENT, INPUT_VALUE, RESULT_VALUE)

  Values

  ('70', 'Local Mission allowance', 'End of Mission Date' ' 2014-06-14 00:00:00 ');

  Insert into APPS. PER_ALL_PEOPLE_F

  (EMPLOYEE_NUMBER, NOM_ELEMENT, INPUT_VALUE, RESULT_VALUE)

  Values

  ('70', 'Local Mission allowance', 'Mission Start Date', ' 2014/06/13 00:00:00 ');

  Insert into APPS. PER_ALL_PEOPLE_F

  (EMPLOYEE_NUMBER, NOM_ELEMENT, INPUT_VALUE, RESULT_VALUE)

  Values

  ('70', 'Local Mission allowance', 'Mission Start Date', ' 2014/06/10 00:00:00 ');

  Thank you very much in advance.

  Kind regards

  Afzal.

  So then... something like this:

  SELECT employee_number

  element_name

  MAX (decode (input_value, 'Day amount', result_value)) AS day_amount

  MAX (decode (input_value, 'Days of Distance', result_value)) AS Distance_Days

  , MAX (decode (input_value, 'Value of pay', result_value)) AS Pay_Value

  MAX (decode (input_value, 'Start Date', result_value)) AS Start_Date

  from (SELECT papf.employee_number

  pet.element_name

  piv.NAME input_value

  prrv.result_value

  prrv.run_result_id

  OF apps.pay_payroll_actions App

  pay_assignment_actions PAA

  pay_payrolls_f pp

  pay_run_results prr

  pay_run_result_values prrv

  pay_input_values_f piv

  pay_element_types_f pet

  apps.per_all_assignments_f ADP

  apps.per_all_people_f women's wear

  -where ppa.payroll_action_id =: payroll_action_id - give your payroll_action_id

  WHERE ppa.payroll_id =: payroll_id

  AND ppa.payroll_action_id =: payroll_action_id

  - and paa.assignment_action_id =: assignment_action_id

  AND ppa.payroll_action_id = paa.payroll_action_id

  AND ppa.payroll_id = pp.payroll_id

  AND paa.assignment_action_id = prr.assignment_action_id

  AND prr.run_result_id = prrv.run_result_id

  AND prrv.input_value_id = piv.input_value_id

  AND piv.element_type_id = pet.element_type_id

  AND paaf.assignment_id = paa.assignment_id

  AND paaf.person_id = papf.person_id

  AND trunc (sysdate) BETWEEN pp.effective_start_date AND pp.effective_end_date

  AND trunc (sysdate) BETWEEN pet.effective_start_date AND pet.effective_end_date

  AND trunc (sysdate) BETWEEN piv.effective_start_date AND piv.effective_end_date

  AND trunc (sysdate) BETWEEN paaf.effective_start_date AND paaf.effective_end_date

  AND trunc (sysdate) BETWEEN papf.effective_start_date AND papf.effective_end_date

  AND pet.element_name IN ('local Mission allowance', 'International Mission'))

  GROUP BY employee_number

  element_name

  run_result_id

  ;

  You should get your desired result.

  Roger

• Help of the SQL query.

  Hello
  
  It's my first table REPORT
  
  report as)
  Select 'vendor_1' vendor, to_date('1/1/2012','DD/MM/YYYY') supply_date, "customer_1" as a customer, "item_1" like item1, 110 as cost of double union all
  Select 'vendor_1' vendor, to_date('1/3/2012','MM/DD/YYYY') supply_date, "customer_1" as a customer, "item_1" like item1, 120 as cost of double union all
  Select 'vendor_1' vendor, to_date('1/3/2012','MM/DD/YYYY') supply_date, "customer_1" as a customer, "item_1" like item1, 130 as cost of double union all
  Select 'vendor_1' vendor, to_date('1/4/2012','MM/DD/YYYY') supply_date, "customer_1" as a customer, "item_1" like item1, 140 as cost of double union all
  Select 'vendor_1' vendor, to_date('1/10/2012','MM/DD/YYYY') supply_date, "customer_1" as a customer, "item_1" element, 200as cost of double union all
  Select 'vendor_1' vendor, to_date('1/23/2012','MM/DD/YYYY') supply_date, "customer_1" as a customer, "item_1" as point 0 as the cost of dual union all
  Select 'vendor_1' vendor, to_date('1/6/2012','MM/DD/YYYY') supply_date, "customer_2" as a customer, "item_1" like item1, 160 as cost of double union all
  Select 'vendor_1' vendor, to_date('1/7/2012','MM/DD/YYYY') supply_date, "customer_2" as a customer, "item_1" like item1, 170 as cost of double union all
  Select 'vendor_1' vendor, to_date('1/8/2012','MM/DD/YYYY') supply_date, "customer_2" as a customer, "item_1" like item1, 180 as cost of double union all
  Select 'vendor_1' vendor, to_date('1/9/2012','MM/DD/YYYY') supply_date, "customer_2" as a customer, "item_1" like item1, 190 as cost of double union all
  Select 'vendor_1' vendor, to_date('1/20/2012','MM/DD/YYYY') supply_date, "customer_2" as a customer, "item_1" like item1, 300 as cost of double)
  
  
  
  
  
  
  IT'S MY SECOND TABLE: TEMP_WEEK
  
  WITH temp_week (s)
  SELECT January 1, 2012 to 07/01/2012 ' AS the week of all the double union
  SELECT August 1, 2012 to 14/01/2012 ' AS the week of all the double union
  January 15, 2012 to 21/01/2012 ' AS the week of all the double union
  SELECT January 22, 2012 to 28/01/2012 ' AS the week of all the double union
  (SELECT 29 January 2012 to 31/01/2012 ' WEEK of double)
  
  
  To find weekly sales that I wrote query below:
  
  SELECT week, supplier, customer, SUM (cost)
  (SELECT week, supplier, customer, TOTAL costs (cost)
  FROM (SELECT BOX
  WHEN TO_NUMBER (TO_CHAR (TRUNC (supply_date), 'DD')) BETWEEN 1 AND 7 MAY
  January 1, 2012 to 07/01/2012 '
  WHEN TO_NUMBER (TO_CHAR (TRUNC (supply_date), 'DD')) BETWEEN 8 AND 14 MAY
  14/01/2012, 1 August 2012'
  WHEN TO_NUMBER (TO_CHAR (TRUNC (supply_date), 'DD')) BETWEEN 15 AND 21 THEN
  January 15, 2012 to 21/01/2012 '
  WHEN TO_NUMBER (TO_CHAR (TRUNC (supply_date), 'DD')) BETWEEN 22 AND 28 and THEN
  January 22, 2012 to 28/01/2012 '
  WHEN TO_NUMBER (TO_CHAR (TRUNC (supply_date), 'DD')) BETWEEN 29 AND 31 MAY
  29 January 2012 to 31/01/2012 '
  END
  week, supplier, customer, cost
  REPORT)
  GROUP BY week, supplier, customer
  UNION ALL
  SELECT tw.week, vendor, customer or 0
  (SELECT week, supplier, customer, TOTAL costs (cost)
  FROM (SELECT BOX
  WHEN TO_NUMBER (TO_CHAR (TRUNC (supply_date), 'DD')) BETWEEN 1 AND 7 MAY
  January 1, 2012 to 07/01/2012 '
  WHEN TO_NUMBER (TO_CHAR (TRUNC (supply_date), 'DD')) BETWEEN 8 AND 14 MAY
  14/01/2012, 1 August 2012'
  WHEN TO_NUMBER (TO_CHAR (TRUNC (supply_date), 'DD')) BETWEEN 15 AND 21 THEN
  January 15, 2012 to 21/01/2012 '
  WHEN TO_NUMBER (TO_CHAR (TRUNC (supply_date), 'DD')) BETWEEN 22 AND 28 and THEN
  January 22, 2012 to 28/01/2012 '
  WHEN TO_NUMBER (TO_CHAR (TRUNC (supply_date), 'DD')) BETWEEN 29 AND 31 MAY
  29 January 2012 to 31/01/2012 '
  END
  week, supplier, customer, cost
  REPORT)
  GROUP BY week, supplier, customer), temp_week tw)
  GROUP BY week, supplier, customer
  ORDER BY supplier, customer, week;
  
  
  with above query I get below output:
  
  
  with output voltage)
  Select January 1, 2012 to 07/01/2012 ' week, 'vendor_1' as a provider, "customer_1" as a customer, 500 as cost of double union all
  Select August 1, 2012, to 14/01/2012 ' week, 'vendor_1' as a provider, "customer_1" as a customer, 200 as cost of double union all
  Select January 15, 2012 to 21/01/2012 ' week, 'vendor_1' as a provider, "customer_1" as a customer, 0 as the cost of dual union all
  Select January 22, 2012 to 28/01/2012 ' week, 'vendor_1' as a provider, "customer_1" as a customer, 0 as the cost of dual union all
  Select the 29 January 2012 to 31/01/2012 ' week, 'vendor_1' as a provider, "customer_1" as a customer, 0 as the cost of dual union all
  Select January 1, 2012 to 07/01/2012 ' week, 'vendor_1' as a provider, "customer_2" as a customer, 330 as costs of double union all
  Select August 1, 2012, to 14/01/2012 ' week, 'vendor_1' as a provider, "customer_2" as a customer, 370 as cost of double union all
  Select January 15, 2012 to 21/01/2012 ' week, 'vendor_1' as a provider, "customer_2" as a customer, 300 as cost of double union all
  Select January 22, 2012 to 28/01/2012 ' week, 'vendor_1' as a provider, "customer_2" as a customer, 0 as the cost of dual union all
  Select the 29 January 2012 to 31/01/2012 ' week, 'vendor_1' as a provider, "customer_2" as a customer, double cost of 0)
  
  Clearly, I used cross join. But I want to get the same result with another way. I don't want to use cross join and Union
  
  Please help me in this.

  What you desire can be accomplished using the outer join partitioned.
  The documentation shows an example of [url http://docs.oracle.com/cd/E11882_01/server.112/e26088/statements_10002.htm#i2177515] this way to fill the gaps in the data.

  Here's how you can use it in your case:

  SQL> with report as (
    2     select 'vendor_1' as vendor,to_date('1/1/2012','DD/MM/YYYY') supply_date, 'customer_1'as customer,'item_1' as item1, 110 as
  cost from dual union all
    3     select 'vendor_1' as vendor,to_date('1/3/2012','MM/DD/YYYY') supply_date,'customer_1'as customer, 'item_1' as item1,120 as c
  ost from dual union all
    4     select 'vendor_1' as vendor,to_date('1/3/2012','MM/DD/YYYY') supply_date, 'customer_1'as customer, 'item_1' as item1,130 as
  cost from dual union all
    5     select 'vendor_1' as vendor,to_date('1/4/2012','MM/DD/YYYY') supply_date,'customer_1'as customer, 'item_1' as item1,140 as c
  ost from dual union all
    6     select 'vendor_1' as vendor,to_date('1/10/2012','MM/DD/YYYY') supply_date, 'customer_1'as customer, 'item_1' as item ,200as
  cost from dual union all
    7     select 'vendor_1' as vendor,to_date('1/23/2012','MM/DD/YYYY') supply_date, 'customer_1'as customer, 'item_1' as item,0 as co
  st from dual union all
    8     select 'vendor_1' as vendor,to_date('1/6/2012','MM/DD/YYYY') supply_date,'customer_2'as customer, 'item_1' as item1,160 as c
  ost from dual union all
    9     select 'vendor_1' as vendor,to_date('1/7/2012','MM/DD/YYYY') supply_date,'customer_2'as customer, 'item_1' as item1,170 as c
  ost from dual union all
   10     select 'vendor_1' as vendor,to_date('1/8/2012','MM/DD/YYYY') supply_date,'customer_2'as customer, 'item_1' as item1,180 as c
  ost from dual union all
   11     select 'vendor_1' as vendor,to_date('1/9/2012','MM/DD/YYYY') supply_date,'customer_2'as customer,'item_1' as item1,190 as co
  st from dual union all
   12     select 'vendor_1' as vendor,to_date('1/20/2012','MM/DD/YYYY') supply_date,'customer_2'as customer,'item_1' as item1,300 as c
  ost from dual
   13  ), weeks as (
   14     select to_date('1/1/2012','DD/MM/YYYY') + (level-1)*7 week_start
   15          , to_date('1/1/2012','DD/MM/YYYY') + (level-1)*7 + 6 week_end
   16          , level week_pseudo_id
   17       from dual
   18     connect by level <= 5 /* substitute desired number of weeks */
   19  )
   20  --
   21  -- end-of-test-data
   22  --
   23  select to_char(max(weeks.week_start),'DD/MM/YYYY')
   24         || ' to ' ||
   25         to_char(max(weeks.week_end),'DD/MM/YYYY') week
   26       , vendor
   27       , customer
   28       , nvl(sum(cost),0) cost
   29    from report
   30   partition by (vendor, customer)
   31   right outer join weeks
   32         on weeks.week_start <= report.supply_date
   33         and weeks.week_end >= report.supply_date
   34   group by
   35         vendor
   36       , customer
   37       , week_pseudo_id
   38   order by
   39         vendor
   40       , customer
   41       , week_pseudo_id
   42  /
  
  WEEK                     VENDOR   CUSTOMER         COST
  ------------------------ -------- ---------- ----------
  01/01/2012 to 07/01/2012 vendor_1 customer_1        500
  08/01/2012 to 14/01/2012 vendor_1 customer_1        200
  15/01/2012 to 21/01/2012 vendor_1 customer_1          0
  22/01/2012 to 28/01/2012 vendor_1 customer_1          0
  29/01/2012 to 04/02/2012 vendor_1 customer_1          0
  01/01/2012 to 07/01/2012 vendor_1 customer_2        330
  08/01/2012 to 14/01/2012 vendor_1 customer_2        370
  15/01/2012 to 21/01/2012 vendor_1 customer_2        300
  22/01/2012 to 28/01/2012 vendor_1 customer_2          0
  29/01/2012 to 04/02/2012 vendor_1 customer_2          0
  
  10 rows selected.
  

  I have redesigned weeks of date columns for the join which will probably perform better and can possibly use indexes.
  I assume that you have no time portion in your supply_date data? If you do, then week_end will need to be modified.

• Help to the SQL query.

  I have a table 'departments' with the following fields:
  dep_id, parent_dep_id.
  1 5
  2
  3 4
  4
  5 2
  
  How can I write SQL to return the department (division) parent of higher level for each Department:
  dep_id, div_id
  1 2
  2 2
  3 4
  4 4
  5 2
  
  Thank you.

  SQL> create table t (dep_id,parent_dep_id)
    2  as
    3  select 1, 5 from dual union all
    4  select 2, null from dual union all
    5  select 3, 4 from dual union all
    6  select 4, null from dual union all
    7  select 5, 2 from dual
    8  /
  
  Tabel is aangemaakt.
  
  SQL>  select dep_id
    2        , max(connect_by_root dep_id) keep (dense_rank last order by level) div_id
    3     from t
    4  connect by prior dep_id = parent_dep_id
    5    group by dep_id
    6  /
  
      DEP_ID     DIV_ID
  ---------- ----------
           1          2
           2          2
           3          4
           4          4
           5          2
  
  5 rijen zijn geselecteerd.
  

  Kind regards
  Rob.

• Help in the Sql query

  Hi all

  I have a requirement to get all the items contained in the link of the item for the two States of 2 payroll.

  I also want to recover what elements exist only in unique payroll.

  Case 1: Item exists in both States to pay.

  Case 2: Item exists in only one of the payroll.

  Item: XX_ELEMENT

  Element_id = 140

  Payroll_id 1 = 40

  payroll_id 2 = 50

  Example table:

  element_id Payroll_id

  140                    40

  140                    50

  140                    60

  141                    40

  Desired output:

  Element on the payroll

  140 40,50 (or ' the two States of payroll)

  141                    40

  Here is the code I am trying.

  SELECT DISTINCT

  LINK. PAYROLL_ID,

  PAF. PAYROLL_NAME,

  ELEMENT_LINK_ID,

  PF. ELEMENT_TYPE_ID,

  LINK. LINK_TO_ALL_PAYROLLS_FLAG,--IN('Y','N')

  PTL. ELEMENT_NAME ARABIC,

  PF. ELEMENT_NAME ENGLISH

  LINK PAY_ELEMENT_LINKS_F,

  PAY_ELEMENT_TYPES_F_TL PTL,

  PAY_ELEMENT_TYPES_F PF,

  PAF PAY_ALL_PAYROLLS_F

  WHERE PF. ELEMENT_TYPE_ID = 140 AND

  PAF. PAYROLL_ID (+) IS LINK. PAYROLL_ID

  AND PF. ELEMENT_TYPE_ID = PTL. ELEMENT_TYPE_ID

  AND PF. ELEMENT_TYPE_ID (+) IS LINK. ELEMENT_TYPE_ID

  AND THE PTL. LANGUAGE = "AR".

  AND TRUNC (SYSDATE) BETWEEN PF. EFFECTIVE_START_DATE AND PF. EFFECTIVE_END_DATE

  AND (TRUNC (SYSDATE) BETWEEN PAF. EFFECTIVE_START_DATE AND OF THE PAF. EFFECTIVE_END_DATE OR LINK. PAYROLL_ID IS NULL)

  AND TRUNC (SYSDATE) BETWEEN LINK. EFFECTIVE_START_DATE AND LINK. EFFECTIVE_END_DATE

  AND THE LINK. PAYROLL_ID IN (40,50)

  Kind regards

  Afzal.

  Once you have your set of element_id and payroll_id you can use count (distinct) to get the number of different values of payroll_id by element_id. Something like

  Select element_id, count (distinct payroll_id) cnt, max (payroll_id) max_pr the subquery by element_id group

  You can then use a decoding against the column of the cnt to display 'two' or max_pr.

  You haven't posted your version of Oracle, but if you are on at least 11.2.0.1 then you can also use listagg on the separate set of element_id and payroll_id

• Clarification of the SQL query in 2 day + Guide APEX

  I worked through the Oracle Database Express Edition 2 day + Application Express Developer's Guide, and try to decipher the SQL query in Chapter 4 (building your app).

  The code is:

  SELECT d.DEPARTMENT_ID,

  d.DEPARTMENT_NAME,

  (select count (*) from oehr_employees where department_id = d.department_id)

  "Number of employees", he said.

  substr (e.first_name, 1, 1) |'. ' || Select 'Name Manager',

  c.COUNTRY_NAME 'place '.

  OEHR_DEPARTMENTS d,

  E OEHR_EMPLOYEES

  OEHR_LOCATIONS l,

  C OEHR_COUNTRIES

  WHERE d.LOCATION_ID = l.LOCATION_ID

  AND l.COUNTRY_ID = c.COUNTRY_ID

  AND e.department_id = d.DEPARTMENT_ID

  AND d.manager_id = e.employee_id

  AND instr (superior (d.department_name), superior (nvl (:P2_REPORT_SEARCH,d.department_name))) > 0)

  I don't know exactly what is happening in the last line. I think I understand what the different functions but I'm not clear on the use of the: P2_REPORT_SEARCH string.

  What does this string? This code simply checking that d.department_name isn't NA?

  I have SQL experience but am not very familiar with the Oracle PL/SQL implementation. Can someone please give me a brief breakdown that check is doing in the context of the overall query? The application seems to work even if the conditional statement is not included.

  Thank you.

  2899145 wrote:

  Thanks for the reply. I apologize if the information I added was incomplete. The code came from the day 2 + Application Express (version 4.2) Developer Guide.

  In the section 'your own Application of 4 Buuilding' https://docs.oracle.com/cd/E37097_01/doc.42/e35122/build_app.htm#TDPAX04000 , they describe the creation of a report

  page that includes the "manager_id" and 'location_id '. The SQL query, I pasted above extracted from the data in other tables to substitute the real 'name of the Manager' and 'rent '.

  for the corresponding ID values. It makes sense, and the part of the SQL query that explicitly doing this makes sense.

  However, given that the document is a guide for the development of the APEX, I guess the command:

  AND instr (upper (d.department_name), upper (nvl (:P2_REPORT_SEARCH,d.department_name))) > 0

  done something valuable, and I do not recognize what is exactly the value.

  From a practical point of view why would I need to include this conditional statement?  Which only added to the application?

  Looking at the guide in question, it is clear that the

  AND instr(upper(d.department_name),upper(nvl(:P2_REPORT_SEARCH,d.department_name)))>0
  

  the line is completely unnecessary in the context of this tutorial, and it can be removed. The search in the tutorial app page is implemented by using a report filter interactive rather than a P2_REPORT_SEARCH element, which does not seem to exist at all. (It's a quirk of the APEX that bind variable references to non-existent items are replaced with NULL silently rather than exceptions). I thought that perhaps it would be legacy code a version of the tutorial prior to the introduction of interactive reports at the APEX 3.1, but I can't find explicit instructions to create such an element of filter in the 3.0 tutorial. I guess it must have been automatically generated by the application wizard when you create a standard report page.

  If you do not want to see the effect he would have (as described in the post above), leave it in the source report, add a text element of P2_REPORT_SEARCH, and a button "submit" on page 2 and experimenting to find different values of the element and clicking on the submit button...

• Failed to parse the SQL query by user

  Hi all
  
  in my application, I have a piece of text with a button "submit". In this article, I type a name and a report after the element region show me the result (s). This works for all my users (> 2000) perfectly, but that users become an error in the area of the report:
  
  Failed to parse the SQL query:
  ORA-01403: no data found
  
  We try this with the same searchstring on the same computer/browser. If I connected the result is ok, if the logged on user, the error message appears. If I try this on the user's computer with me connected, ok result. If the user try this on another pc, error results.
  
  I have a production and a developer workspace. In the developer workspace the user can try this perfectly without errors. That in the space of productive work, clear the error.
  
  The SQL-Select in the ist verry simple reprirt:
  
  Select id
  name
  raum
  table
  where instr (upper (name), upper (:P60_SEARCH)) > 0
  
  However, all users can use this search box with report perfectly, only this one user has the error. There is no restrictions on this point or a State.
  
  Can someone help me?

  Hi Carsten,

  I don't think that there is a way to do it.

  Could you please mark the correct and useful answers in this thread? Otherwise I'll never get near Andy ;) :)

  Denes Kubicek
  ------------------------------------------------------------------------------
  http://deneskubicek.blogspot.com/
  http://www.Opal-consulting.de/training
  http://Apex.Oracle.com/pls/OTN/f?p=31517:1
  ------------------------------------------------------------------------------

• Use the DECODE and RIGHTEOUS in the sql query

  Friends...

  Could someone help with DECODE and sql RIGHT or similar function?

  I'm doing below in the SQL query

  1. DECODE any process with s.process = 1234 to replace with JAVA
  2. RIGHT: Removes all characters after ' @' sign

  SQL query:

  SELECT s.osuser, s.machine, DECODE(s.process, '1234', 'JAVA', right(s.process,charindex('@',s.process)-1)) s.process FROM v$session; 

  for example

  EXAMPLES of data

  User, machine, process

  John, mac1, 1234

  Mike, mac2, 567@mac2

  Julie, mac3, 890

  
  

  The result of the SAMPLE:

  User, machine, process

  John, mac1, JAVA

  Mike, mac2, 567

  Julie, mac3, 890

  Thanks in advance

  Thanks guys... I am overwhelmed with all these answers and support on this forum, I received...

  I have combined Solomon and Frank response to achieve accurate result...

  with the answers of Solomon he displayed empty process when there is ' @' sign

  Frank's response showed it process with sign @ the end... so I added '-1' in the end.»

  SELECT s.osuser,

  s.machine,

  DECODE)

  s.Process,

  "1234", "JAVA",

  substr)

  s.Process,

  1,

  InStr)

  s.Process | '@',

  '@'

  ) - 1

  )

  ) process

  V $ session s

  /

• Cannot create the SQL query view object

  I'm having a lot of trouble to create a display of a SQL object.
  
  The query is as follows:
  
  Select CalBruker.BRUK_ID,
  CalBruker.EMAIL,
  CalBruker.ETTERNAVN,
  CalBruker.PASSORD,
  CalBruker.DATO_OPPRETTET,
  CalBruker.AKTIV,
  CalBruker.FORNAVN,
  CalBruker.ROLL_ROLL_ID,
  CalBruker.AVDE_AVDE_ID,
  CalRoller.NAVN,
  CalRoller.ROLL_ID,
  CalAvdelinger.NAVN AS NAVN1,
  CalAvdelinger.AVDE_ID,
  CalRoller.BESKRIVELSE,
  CalForlag.NAVN AS NAVN2,
  CalForlag.FORL_ID,
  CalAvdelinger.navn,
  CalForlag.navn AS BrukForlag,
  CalBruker.FRIEKS_PROSENT_GRENSE,
  CalBruker.LOGIN_NAVN
  Of CAL_BRUKER CalBruker, CAL_ROLLER CalRoller, CAL_AVDELINGER CalAvdelinger, CAL_FORLAG CalForlag
  Where CalBruker.ROLL_ROLL_ID = CalRoller.ROLL_ID AND CalBruker.AVDE_AVDE_ID = CalAvdelinger.AVDE_ID AND CalAvdelinger.FORL_FORL_ID = CalForlag.FORL_ID
  
  
  If I create a new view object and paste the SQL query in there, I get no automatic attribute mappings, and I can't understand how I'm supposed to map the attributes manually.
  
  Basically, I get a display without her attributes object.
  
  JDeveloper version 11.1.2.0

  Help if you give alias names in your columns?
  Something like:

  Select CalBruker.BRUK_ID BRUK_ID,
  EMAIL CalBruker.EMAIL,
  CalBruker.ETTERNAVN ETTERNAVN,
  ...

• What can be the SQL query for this requirement?

  Hello
  I have a table with the fields like this:
  
  ID DESC PARENT
  01 02 ABC
  02 01 ABC1
  03 01 ABC2
  04 02 ABC4
  
  
  In the table above column PARENT refers to the column ID, but actually in the SQL query, I want to have ID DESC and PARENTDESC (i.e., desc ID value corresponding)
  
  Output real I need is
  
  SELECT ID, DESC? from table where ID = someValue. Now, if I provided ID = 01 then output should be like this:
  
  ID DESC PARDESC
  ABC1 ABC 01
  
  
  Can anyone help on what may be the required sql query?
  
  Published by: bootstrap on April 29, 2011 06:15

  SELECT T1.ID, T1. DESC, T2. / / DESC
  FROM TABLEA T1, T2 TABLEA
  WHERE T1.ID = '01'
  AND T2.ID = T1. PARENT;

• Report with the sql query area

  Hello
  
  I have a region in relation to the sql query. There are two regions in the page. Top of page, the user enters data and after that second data enterd to see the region, which is related region
  based on a sql query.
  
  Now, when this page is opned, because the user has not entered anything, region report shows the message "no data found". Is it possible to remove this message or
  may I have conditionally disaply region report IE if data are inserted only region report is dispalyed.
  
  Thank you

  Hello

  You can use conditions for example "Exists (SQL query returns at least one row).

  Kind regards
  Jari

• date picker default value appears only not in the sql query

  Hello
  
  I have a page as a table with a query similar to the following:
  
  Select emp_name, salary of emp_table where (hire_date) trunc = trunc (to_date (:P42_START_DATE))
  
  where P42_START_DATE is the name of a date picker.
  
  I put the date picker, "only when the current value in session state is null" and the value of being "select trunc (next_day(sysdate,'MON')-7) from dual;"-essentially the Monday of the current week, the type of source. I updated the date to 5 selector and the sequence of the region 10. Now, when I opened this page, no data gets pulled. I checked the source of the page and the value of the entry date picker is used to "November 17, 2008", but is not somehow reflected in the sql query.
  
  Data get retrieved if I put manually the date in the date picker, but I would like that it by default on Monday of this week. What I am doing wrong?
  
  Thank you

  Hello

  >
  "Article 1 of the Expression value is NULL" where is expression 1
  P42_START_DATE
  >

  Yes, that's correct - No. colon is required here as we don't not using the item as a variable binding, just name for the condition. In my tests, I put the calculation for:

  Name of article: P31_HIREDATE (put your P42_START_DATE here instead)
  Type: SQL query
  Point calculation: before header
  Calculation: SELECT TO_CHAR (TRUNC (SYSDATE, 'DAY'), 'DD-MON-RR') FROM DUAL

  My report SQL statement is:

  SELECT EMPNO,
  ENAME,
  HIREDATE
  FROM EMP
  WHERE NVL(HIREDATE, TRUNC(SYSDATE)) < TO_DATE(:P31_HIREDATE,'DD-MON-RR')
  

  My datepicker object has no special parameters - so:

  Name: P31_HIREDATE
  Display: Date Picker (DD-MON-RR)
  Source: Only when...
  Source type: static...
  The source value or expression: (empty)
  Default: (empty)

  And that's what I did to get: http://htmldb.oracle.com/pls/otn/f?p=55041:31

  Change the date that you like or click Reset to clear the cache (the calculation will be then reset the date to the current date and refiltrer the report)

  Andy

• Classic report shows wrong "could not parse the SQL query: ORA-00942" error after migrating app to the new environment

  After migrating my APEX 4.1 application to a new environment, one classic report displays a "cannot parse the SQL query: ORA-00942: table or view does not exist" error when the page is displayed. Change the region to report SQL source to somehow (e.g., remove spaces, changing the order of the variables in the WHERE clause) immediately solves the problem, but by returning to the source of the region causes the report error again (the source region valid code without error, however).

  Throw the error message:

  Select v.id,

  v.Col1

  of view_vw v

  where (: P1_FILTER is null or)

  v.col2 = :P1_FILTER)

  Do not throw error:

  Select v.id,

  v.Col1

  of view_vw v

  where (:P1_FILTER is null or)

  v.col2 = :P1_FILTER)

  Changing the order of column in the report has the same effect; i.e. He arranges, but return back to the original column order causes the error to display.

  It's as if a cached result for the correct select statement used by the report is displayed. However, the application does not use the caching of page/region. Any ideas of what could be the cause?

  He solved. Ultimately, all that was necessary was to clear the DB cache using:

  alter system flush shared_pool;

• Table error ' can not analyze the SQL query!

  Hi all

  I created a view on my database called VIEW_MEMBER_PARTIC_PROJECTS

  If I run a query showing the results of the view:

  SELECT * FROM VIEW_MEMBER_PARTIC_PROJECTS

  I get the following data

  Projects	Participants
  1	31 S
  2	41
  3	19
  4	3
  5	3
  6	1
  7	2

  Now, I wanted to represent this diagram in the APEX so I created a graphic region and entered the Source query generator and the manufacturer produces the following code

  Select null, label projects, value1 Participant link

  of "SCHEMANAME." "" VIEW_MEMBER_PARTIC_PROJECTS ".

  With this code, I get an error:

  Cannot parse the SQL query!

  Select the link null, label projects, value1 "SCHEMANAME Participant." "" VIEW_MEMBER_PARTIC_PROJECTS ".

  Some queries can be run when you run your application, if your query is syntactically correct, you can save your query without validation (see options below the source of the query).

  The code looks OK, but I do not see to save options as the error code is mentioned.

  No one knows how to fix this?

  Thank you

  JaReg wrote:

  I finally found the problem.

  I looked at the code for the view and changed the start of:

  CREATE OR REPLACE FORCE EDITIONABLE VIEW "SCHEMANAME." "" VIEW_MEMBER_PARTIC_PROJECTS "("Participant","Projects")

  AS

  TO

  CREATE OR REPLACE VIEW "SCHEMANAME." "" VIEW_REPEAT_PARATIC ".

  AS

  And that seemed to fix it. I'm not entirely sure why though.

  The view was created using the quoted identifiers for column names. This makes them sensitive and means that they must always be referenced using double quotes. In the absence of quotation marks, Oracle is not case insensitive and automatically converts all uppercase identifiers. The application of graph:

  Select the link null, label projects, value1 "SCHEMANAME Participant." "" VIEW_MEMBER_PARTIC_PROJECTS ".

  has therefore been interpreted by Oracle:

  SELECT THE LINK NULL, LABEL, VALUE1 "SCHEMANAME PARTICIPANT PROJECTS." "" VIEW_MEMBER_PARTIC_PROJECTS ".

  and PROJECTS and PARTICIPANT columns were not recognized because the columns defined for the view have been 'Participant' and 'projects '. The graphic request should have been:

  Select the link null, the label of "Projects", "Participant" value1 "SCHEMANAME." "" VIEW_MEMBER_PARTIC_PROJECTS ".

  As you have now discovered, quoted identifiers are a source of nothing but obscure bugs and should never be used for database objects. He also pointed out the reason why you should always use a standardized, form tiny, coding style as it is faster to type, easy to read and less prone to errors.

• Export as .xls. Classic report type: SQL (body of function from PL/SQL returning the SQL) query

  Hey guys,.

  I'm using version 4.2.6 apex. The theme is 26.

  IM also using Listener Oracle APEX.

  I can print my classic report in PDF or CSV format.

  But I need to export it as a .xls extension.

  Report type: SQL (body of function from PL/SQL returning the SQL) query

  I need is like this cause my 'where' clause type is dynamic.

  Look at using this method: Tom's Blog: a non-standard export excel 2010 (.xlsx)

  I do something similar for downloads to excel in my projects...

  Thank you

  Tony Miller
  Software LuvMuffin
  Ruckersville, WILL

• How to select only the part by using the sql query

  Hello

  I have the task to retrieve only the integral of the input text by using the sql query.

  The entry is as follows

  Entry for the price setting

  $12.5 (FYI without space)

  $ 12.5 (FYI single space)

  $ 12.5 (double space FYI)

  $12.5 (FYI multiple space)

  $12.5 (FYI multiple space)

  Output expected of 12.5

  The price is the type varchar2 column in the store_price table.

  Please let me know how to achieve this.

  Thanks in advance.

  If this is always the case that you get a $ followed by a number of places, you can use something like:

  Select to_number (ltrim ('$ 12.5',' $')) DOUBLE

  or

  SELECT ltrim ('$ 12.5',' $') OF double

  but take care of your nls_numeric_character settings if they are defined so that, for example, a comma is the decimal separator, you will have a problem.

  HTH