What can be the SQL query for this requirement?

Similar Questions

• How can I write the SQL query for this requirement?

  Hello
  
  I have a table that looks like this:
  
  NAME | ANNUAL |     VALUE
  ==== | ====== | =====
  execno |     480.     000004
  step |      480.     0400
  SCNA |     480. cd_demo
  System |     480.     D47-010
  type |     480.     step
  free_text |     480.     stage 400
  rbare |     480.     RBA-1
  execno |     482. 000004
  SCNA |     482. cd_demo
  System |     482.     D47-010
  free_text |     482.     step 300
  step |          482.          0300
  type |      482.     step
  rbare |     482.     RBA-1
  execno |     483.     000001
  type |     483.     step
  rbare |     483.     rke1
  SCNA |     483.     rke10
  step |     483.     0240
  
  Now, say that I want to fetch ONLY annual with execno = '000004' and '400' = step and scna = "cd_demo" and system = "d47-010' and type = 'step', how to write SQL code?
  At first, it seemed like a simple writing query but I've been struggling with it for hours without success. I must admit though that I'm not strong in SQL :-)
  There, can anyone help? Please...
  
  Thanks in advance.
  
  Emmanuel
  
  Published by: user12138559 on October 30, 2009 03:05

  Hi, Emmanuel.

  Welcome to the forum!

  Here's a way to do what you asked:

  SELECT       doc_id
  FROM       table_x
  GROUP BY  doc_id
  HAVING       SUM (CASE WHEN name = 'execno' AND value = '000004'  THEN 1 END) > 0
  AND       SUM (CASE WHEN name = 'step'   AND value = '400'     THEN 1 END) > 0
  AND       SUM (CASE WHEN name = 'scna'   AND value = 'cd_demo' THEN 1 END) > 0
  AND       SUM (CASE WHEN name = 'system' AND value = 'd47-010' THEN 1 END) > 0
  AND       SUM (CASE WHEN name = 'type'   AND value = 'step'    THEN 1 END) > 0
  ;
  

  If you think that a WHERE clause would be used, but WHERE does apply to a single line. You need a condition that checks several rows in the same group.
  WHEN has an effect something like WHERE.

  Published by: Frank Kulash, October 30, 2009 06:26

  This solution assumes that (name, annual) is unique.

• How to make the simple query for this scenario... ?

  Hello:
  
  Dummy table provided for simplicity.
  
  It's my database table (Table_A)
  
  Date1 | Plane1 | Category | Duration | Fees
  01/01/2011 | A | Gold | 5. 2
  01/01/2011 | C | Money | 4. 11
  01/01/2011 | B | Gold | 6. 2
  01/01/2011 | D | Gold | 2. 4
  01/01/2011 | B | Gold | 3. 5
  01/01/2011 | A | Money | 4. 8
  01/01/2011 | B | Gold | 1. 3
  
  I need to write a query to get the result below:
  
  Date1 | Plane1 | Sum_Duration | Sum_Charge | Sum_Gold_Duration | Sum_Gold_Charge | Sum_Silver_Duration | Sum_Silver_Charge
  01/01/2011 | A | 9. 10. 5. 2. 4. 8
  01/01/2011 | B | 10. 10. 10. 10. 0 | 0
  01/01/2011 | C | 4. 11. 0 | 0 | 4. 11
  01/01/2011 | D | 2. 4. 2. 4. 0 | 0
  
  This query will provide the 1st four columns:
  
  SELECT Date1,
  base1,
  Sum (Duration) Sum_Duration,
  Sum (load) Sum_Charge
  FROM TABLE_A
  GROUP BY date1, rarateplan
  
  But I need to know how to get the rest of the columns (i.e. Summary according to categories; from 5 to 8 columns)? Is this can be done in a single query without writing subqueries?
  
  Please let me know, (with code), the best way.
  
  Thank you-
  Tanvir

  Use like this:

  SELECT Date1,
  base1,
  Sum (Duration) Sum_Duration,
  Sum (load) Sum_Charge,
  SUM (decode(Category,'Gold',duration,0)) Sum_Gold_Duration,
  SUM (decode(Category,'Gold',charge,0)) Sum_Gold_charge,
  SUM (decode(Category,'Silver',duration,0)) Sum_Silver_Duration,
  SUM (decode(Category,'Silver',charge,0)) Sum_Silver_charge
  FROM TABLE_A
  GROUP BY date1, rarateplan

  Published by: SANT007 on August 11, 2011 11:04

• If an entry is a constant range, is a tool that can make the exit choose for this number

  I don't really know if it has a name, but I want to capture a constant between 0 and 7. I wish there will be 8 outputs, and according to the value of the entry, the corresponding output is selected. The output could be 1.0 or T/F. I think I could achieve the same goal with a lot of programming, but I was wondering if it was already a tool.  Thank you.

  Index table will do what you want.  Just all your outings possible in an array and index on any element you want.

• What is the best solution for this idea...

  I have a task I'm trying to test and understand what would be the best solution for this, any recommendations would be appreciated.

  Devices at your fingertips:

  -2 ESXi hosts

  -1 iSCSI SAN OpenFiler (new just installed the app)

  2 ESXi hosts run a small amount of virtual machines that are all in the same domain.  I want to have a file server (or a repository somewhere) that houses a folder with easily accessible software (OS, Office, etc.) on the field.

  According to me, that if I made a virtual machine with a large hard drive and share the software, this would not be the best way because it would be dependent on the OS.  Someone has talked about doing a separte VMDK for it and then install it on the operating system on the virtual machine. This way I could always remove the and mount it somewhere else.

  It seems a bit weird to me that the software within this "shared folder" will also be sitting on the data store (if I create a virtual machine and need to use the OS/etc).  Not that doubles the space for the same software (in the comments, then the data store)?

  What is the best approach to make this action which can be accessed at the prompt (mostly windows) in the field?

  What is the best way to stay away the software doubles in action and on the data store?

  Please forgive me if I put interpereted your question.

  The problem you seem to face is that you must mount the ISOs of VMS software and physical systems that are on the field.

  (please, correct me if I'm wrong on this)

  If this is the case, then the best way to do would be to create sharing NFS on the openfiler, if you use openfiler to main databases also then he would be better for sharing this was separated to prevent the other help to be able to tamper with the VMDK and VMX files for your virtual machines.

  This could then be mounted in ESX to access the ISOs. While being easy to install on Linux and Windows machines to access the ISOs.

  If you have questions about NFS mounting in windows, so, this link may help

  http://sagehacks.WordPress.com/2009/01/21/HOWTO-mount-NFS-shares-under-Windows-7

  If you are needing to access the VMs software and it is mainly the downloading ISOs then th ISO directly to the data store is possible.

  This allows you to use ESX to mount the ISO on the virtual machine.

  On the point that the software will use double disk space when you install the software on a machine virtual car will be on the network share and the VMDK virtual machines in the data store. That's right, and that's by design.

  Each virtual machine under ESXI is 'independent' (http://www.vmware.com/virtualization/virtual-machine.html)

  This means that each virtual computer must have its own copy of the application.

  This perspective reflection of each virtual machine as a separate system of 'physical '. They interact with each other as if they were physical systems.

  Each VMDK resembles a physical hard disk. Being accessible (in most configurations) 1 VM at a time.

  So if you had a set of physical systems connected to a domain and I wanted to install an application on each one, then each would have its own local copy of the application. It's the same thing with virtual machines.

  However

  If you configure a set of physical machines so that you run the software from a network share. It is possible to do the same thing using virtual machines using the exactly the same configuration. However, the chiefs more associated to this are important in both cases.

  Concerning

  Cyclooctane

• What use of the WWAN CARD for latitude E6440

  I have a latitude E6440
  What can use a mini-map for this laptop?

  Thank you

  Hi danduongpho,

  Thanks for the post! The Latitude E6440 is compatible with the broadband MOBILE of Dell 5570 card, have the drivers written by our engineers for this material:

  Compatibility: Card wireless Dell 5570 HSPA + (42mbps network) Mobile Broadband

  Systems

  • Latitude E6440

  Operating systems

  • MS Windows 7 32-bit
  • MS Windows 7 64 bit
  • MS Windows 8 32-bit
  • MS Windows 8 64-bit
  • MS Windows 8.1 32-bit
  • MS Windows 8.1 64-bit

  http://www.Dell.com/support/home/us/en/04/drivers/DriversDetails?driverId=YNYT0&FILEID=3397439438&osCode=W764&ProductCode=latitude-e6440-laptop&LanguageCode=en&CategoryID=cm

  Kind regards

• I have adobe photoshop elements 9. I changed Windows 8.1 for windows 10. Now it doesn't work. When I trty to reinstall the software, windows will uninstall it. I habe no icon on the desktop to start the program. For this purpose I can't use it. What I hav

  I have adobe photoshop elements 9. I changed Windows 8.1 for windows 10. Now it doesn't work. When I trty to reinstall the software, windows will uninstall it. I habe no icon on the desktop to start the program. For this purpose I can't use it. What should I do? Thanks for your help. Wolf-Eberhard

  Check your installed programs and so PES 9 is listed, uninstall it by using uninstall.

  Then clean by http://www.adobe.com/support/contact/cscleanertool.html

  Restart your computer, and then reinstall pse 9.

• I made a site with Muse and now the plugin youtube is blocked. What can be the reason for this?

  I made a site for my school with Muse. Now, I want to add some videos on the site. The youtube plugin will not work. It is said the plugin is blocked. What can be the reason?

  Hello

  Some associates of the son,

  Impossible to incorporate and view YouTube videos to Muse: 'plugin blocked. "

  plugin blocked to ship video youtube html?

  Let me know if you have any question.

• SQL query for the region of the tree

  Hello

  I was wondering if someone is able to help me work on a SQL query, to format the data in the table required in a part of the tree... I've never used a tree and I'm fighting to get the right data (if possible).

  The data in the table looks like this:

  

  I want to put it in a tree, using level 1 level6 with a final layout that would look like this:

  

  As you can see, the data are formatted in level6 down in the tree, but are filled in the table from level 1. Not all of the columns will be filled, so level2 for anyone 4 (France) is the equivalent of level in the tree like level6 to person 1 (Spain).

  This is Apex 4.2.5

  Oracle 11.2.0.3.0

  Sample data:

  CREATE TABLE employees
     ( employee VARCHAR2(100),
       level1 VARCHAR2(100),
       level2 VARCHAR2(100),
       level3 VARCHAR2(100),
       level4 VARCHAR2(100),
       level5 VARCHAR2(100),
       level6 VARCHAR2(100)   
     );
  
  INSERT INTO employees (employee, level1, level2, level3, level4, level5, level6) VALUES ('Person1','Team One','Recruitment','Human Resources','Fictituous Company','Murcia','Spain');
  INSERT INTO employees (employee, level1, level2, level3, level4, level5, level6) VALUES ('Person2','Team Four','Testing','IT','Big Corporate','Hanover','Germany');
  INSERT INTO employees (employee, level1, level2, level3, level4, level5, level6) VALUES ('Person3','Big Corporate','Hanover','Germany', null, null, null);
  INSERT INTO employees (employee, level1, level2, level3, level4, level5, level6) VALUES ('Person4','Brittany','France', null, null, null, null);
  INSERT INTO employees (employee, level1, level2, level3, level4, level5, level6) VALUES ('Person5','Team Three','Testing','IT','Big Corporate','Hanover','Germany');
  INSERT INTO employees (employee, level1, level2, level3, level4, level5, level6) VALUES ('Person6','Public Relations','Government Agency','Brittany','France', null, null);
  
  

  Added example given.

  Hello

  Apex-user wrote:

  Thanks Frank, this is a good example, I can work with that! Your assumptions are correct.

  A question I came, however, is that I have a data segment that comes across poorly formatted so to speak... where only the lower levels (1-2, etc.) have been filled from the bottom up.

  An example of this data would be:

  1. INSERT INTO employees (employee, level 1, 2, level3, level4, level5, level6) VALUES ('Person7', 'One Team', 'Test', null, null, null, null);

  As you can see that if you rerun the select, the test team is now duplicated, both at the level of the root in the tree as it should.

  You are not sure if the sql can be adjusted to account for this, or if it's too hard?

  It is obviously a question of data and I am trying to solve this separately (extracted data from another system out of my control).

  Thank you!

  Sorry, I'm confused.

  You say that my assumptions were correct.  What includes supported that "If test ' occurs under 'IT' in a row, then the extent of the 'Testing' occurs, it must be under"IT "?  Right after you say that assumptions are correct, you give an example where 'Testing' occurs under 'IT' to a single line, but it is not less 'IT' to another line and where is 'One Team' under 'Testing' in a line, but is 'One Team' under 'Recruitment' in another row.

  When a situation like this occurs, how you cope?  Whenever you have a problem, please post the exact results you want from the given sample data, and an explanation of how you get these results.  If you don't know about what would be the ideal results, or if you are flexible on the exact results, then at least give an example and explain your reasons.

  Maybe you want to change the got_parent of subquery like this:

  WITH unpivoted_data AS

  (

  SELECT *.

  Employees

  UNPIVOT (node_name

  FOR lvl (level1 AS 1

  level2 AS 2

  level3 AS 3

  level4 AS 4

  level5 AS 5

  level6 AS-6

  )

  )

  )

  got_parent AS

  (

  SELECT c.node_name

  MIN (p.node_name) AS a parent

  Of unpivoted_data c

  LEFT OUTER JOIN unpivoted_data p ON p.employee = c.employee

  AND p.lvl = c.lvl + 1

  GROUP BY c.node_name

  )

  SELECT LPAD (' ' ')

  2 * (LEVEL - 1)

  ) || Node_name AS entity

  OF got_parent

  START WITH parent IS NULL

  Parent = node_name PRIOR CONNECTION

  ;

  In this way, if 'Test' is current 'IT' in one line, but not under what in another line, whether under would consider the 'IT' request and not to be a root.  If 'One Team' sudden 'Testing' in a line, but under "Recruitment" in another line, it will be (arbitrarily) consider it under "recruitment".

• Single SQL query for the analysis of the date of customs declaration under the table of Stock codes

  Dear all,

  
  

  Please tell us a single SQL query for the below,
  

  We have a Table of Stock as shown below,

  STOCK_TABLE

   

  ITEM_CODE (item code)

  BAT_NO

  (lot no.)

  TXN_CODE

  (transaction code)

  DOC_NO

  (number)

  BOE_DT

  (date of the customs declaration)

  I1

  B1

  I1

  I2

  I3

  B70

  I4

  B80

  I5

  B90

  T102

  1234

  JULY 2, 2015

  I6

  B100

  We have to find the date of customs declaration (i.e. the date when the items have come under this particular table) for items that are not attached to any document (that is, who have TXN_CODE, DOC_NO and BOE_DT fields with a NULL value).

  For each item in the table of actions, which is not attached to any document, the customs declaration date is calculated as follows.

  1. If (code section, lot number) combination is present under HISTORY_TABLE, the date of customs declaration will receive the UPDT_DT, the transaction code (TXN_CODE) is an IN or transactions (which can be analyzed from the TRANSACTIONS table).

  2. If (code section, lot number) combination is NOT currently at the HISTORY_TABLE (or) the transaction code respective to item - batch number combination code is an operation then customs declaration date will be the date of the document (DOC_DT) that we receive from one of the 3 tables IN_TABLE_HEAD that contains the element of that particular lot.

• If the case 1 and case 2 fails, our customs declaration date will be the last date of document (DOC_DT) that we receive from one of the 3 tables IN_TABLE_HEAD containing that particular item and the BAT_NO in expected results will be that corresponding to this document, as appropriate, to another NULL.

• If the case 1 or case 2 is successful, the value of the last field (in the output expected, shown further below) BATCH_YN will be 'Y', because it fits the lot. Otherwise it will be 'n'.

HISTORY_TABLE

 

ITEM_CODE

BAT_NO

TXN_CODE

DOC_NO

UPDT_DT

I1

B1

T1

1234

JANUARY 3, 2015

I1

B20

T20

4567

MARCH 3, 2015

I1

B30

T30

7890

FEBRUARY 5, 2015

I2

B40

T20

1234

JANUARY 1, 2015

TRANSACTION

 

TXN_CODE	TXN_TYPE
T1	IN
T20

OFF

T30

ALL THE

T50

IN

T80

IN

T90

IN

T60

ALL THE

T70

ALL THE

T40

ALL THE

IN_TABLE_HEAD_1

 

H1_SYS_ID (primary key)

TXN_CODE

DOC_NO

DOC_DATE

H1ID1

T1

1234

JANUARY 1, 2015

H1ID2

T70

1234

FEBRUARY 1, 2015

IN_TABLE_ITEM_1

 

I1_SYS_ID

H1_SYS_ID

(foreign key referencing H1_SYS_ID in IN_TABLE_HEAD_1)

ITEM_CODE

I1ID1

H1ID1

I1

I1ID2

H1ID1

I100

I1ID3

H1ID2

I3

IN_TABLE_BATCH_1

 

B1_SYS_ID

TXN_CODE                DOC_NO (now in IN_TABLE_HEAD_1)

BAT_NO

B1ID1

T1

1234

B1 / can be empty

B1ID2

T70

1234

B70

IN_TABLE_HEAD_2

 

H2_SYS_ID (primary key)

TXN_CODE

DOC_NO

DOC_DATE

H2ID1

T30

4567

FEBRUARY 3, 2015

H2ID2

T60

1234

JANUARY 3, 2015

IN_TABLE_ITEM_2

 

I2_SYS_ID	H2_SYS_ID (foreign key referencing H2_SYS_ID in IN_TABLE_HEAD_2)	ITEM_CODE
I2ID1	H2ID1

I1

I2ID2

H2ID1

I200

I2ID3

H2ID2

I2

IN_TABLE_BATCH_2

 

B2_SYS_ID

I2_SYS_ID

(foreign key referencing I2_SYS_ID in IN_TABLE_ITEM_2)

BAT_NO

B2ID1

I2ID1

B30 / null

B2ID2

I2ID2

B90

B2ID2

I2ID3

B60

IN_TABLE_HEAD_3

 

H3_SYS_ID (primary key)	TXN_CODE	DOC_NO	DOC_DATE
H3ID1

T50

1234

JANUARY 2, 2015

H3ID2

T80

1234

JANUARY 3, 2015

H3ID3

T90

1234

JANUARY 4, 2015

H3ID4

T40

1234

AUGUST 5, 2015

IN_TABLE_ITEM_3

 

I3_SYS_ID

H3_SYS_ID

(foreign key referencing H3_SYS_ID in IN_TABLE_HEAD_3)

ITEM_CODE

BAT_NO

I3ID1

H31D1

I2

B50

I3ID2

H3ID2

I4

B40

I3ID3

H3ID3

I4

I3ID4

H3ID4

I6

There is no IN_TABLE_BATCH_3

Please find below the expected results.

OUTPUT

 

ITEM_CODE

BAT_NO

TXN_CODE

DOC_NO

BOE_DT

BATCH_YN

I1

B1

T1

1234

JANUARY 3, 2015

THERE

I1

B30

T30

7890

FEBRUARY 5, 2015

N

I2

B60

T60

1234

JANUARY 3, 2015

N

I3

B70

T70

1234

FEBRUARY 1, 2015

THERE

I4

T90

1234

JANUARY 4, 2015

N

I6

T40

1234

AUGUST 5, 2015

N

Controls database to create the tables above and insert the records.

CREATE TABLE stock_table()item_code VARCHAR2()80),bat_no VARCHAR2()80),txn_code VARCHAR2()80),

doc_no VARCHAR2 (80), boe_dt DATE );

INSERT EN stock_table

   VALUES ('I1', 'B1', '', '', '');

INSERT EN stock_table

   VALUES ('I1', '', '', '', '');

INSERT IN stock_table

   VALUES ('I2', '', '', '', '');

INSERT EN stock_table

   VALUES ('I3', 'B70', '', '', '');

INSERT EN stock_table

   VALUES ('I4', 'B80', '', '', '');

INSERT EN stock_table

   VALUES ('I5', 'B90', 'T102', '1234', '02-JUL-2015');

INSERT EN stock_table

   VALUES ('I6', 'B100', '', '', '');

SELECT *

FROM stock_table










 

CREATE TABLE history_table()item_code VARCHAR2()80),bat_no VARCHAR2()80),txn_code VARCHAR2()80),

doc_no VARCHAR2 (80), updt_dt DATE );

INSERT IN history_table

   VALUES ('I1', 'B1', 'T1', '1234', '03-JAN-2015');

INSERT IN history_table

   VALUES ('I1', 'B20', 'T20', '4567', '03-MAR-2015');

INSERT IN history_table

   VALUES ('I1', 'B30', 'T30', '7890', '05-FEB-2015');

INSERT IN history_table

   VALUES ('I2', 'B40', 'T20', '1234', '01-JAN-2015');

SELECT *

FROM history_table










 

CREATE TABLE transaction1()txn_code VARCHAR()80),txn_type VARCHAR()80));




INSERT INTO transaction1

   VALUES ('T1', 'IN');




INSERT INTO transaction1

   VALUES ('T20', 'OUT');

INSERT INTO transaction1

   VALUES ('T30', 'ALL');

INSERT INTO transaction1

   VALUES ('T40', 'ALL');

INSERT INTO transaction1

   VALUES ('T50', 'IN');

INSERT INTO transaction1

   VALUES ('T60', 'ALL');

INSERT INTO transaction1

   VALUES ('T70', 'ALL');

INSERT INTO transaction1

   VALUES ('T80', 'IN');

INSERT INTO transaction1

   VALUES ('T90', 'IN');

SELECT *

FROM transaction1










 

CREATE TABLE in_table_head_1()h1_sys_id VARCHAR2()80) PRIMARY KEY,txn_code VARCHAR2()80),

doc_no VARCHAR2 (80), doc_dt DATE );

CREATE TABLE in_table_head_2()h2_sys_id VARCHAR2()80) PRIMARY KEY,txn_code VARCHAR2()80),

doc_no VARCHAR2 (80), doc_dt DATE );

CREATE TABLE in_table_head_3()h3_sys_id VARCHAR2()80) PRIMARY KEY,txn_code VARCHAR2()80),

doc_no VARCHAR2 (80), doc_dt DATE );

 

INSERT IN in_table_head_1

   VALUES ('H1ID1', 'T1', '1234', '01-JAN-2015');

INSERT IN in_table_head_1

   VALUES ('H1ID2', 'T70', '1234', '01-FEB-2015');

INSERT IN in_table_head_2

   VALUES ('H2ID1', 'T30', '4567', '03-FEB-2015');

INSERT IN in_table_head_2

   VALUES ('H2ID2', 'T60', '1234', '03-JAN-2015');

INSERT IN in_table_head_3

   VALUES ('H3ID1', 'T50', '1234', '02-JAN-2015');

INSERT IN in_table_head_3

   VALUES ('H3ID2', 'T80', '1234', '03-JAN-2015');

INSERT IN in_table_head_3

   VALUES ('H3ID3', 'T90', '1234', '05-JAN-2015');

INSERT IN in_table_head_3

   VALUES ('H3ID4', 'T40', '1234', '05-AUG-2015');










 

CREATE TABLE in_table_item_1()i1_sys_id VARCHAR2()80) PRIMARY KEY,

h1_sys_id VARCHAR2 (80) REFERENCES in_table_head_1()h1_sys_id),item_code VARCHAR2()80));

CREATE TABLE in_table_item_2()i2_sys_id VARCHAR2()80) PRIMARY KEY,

h2_sys_id VARCHAR2 (80) REFERENCES in_table_head_2()h2_sys_id),item_code VARCHAR2()80));

CREATE TABLE in_table_item_3(i3_sys_id VARCHAR2(80) PRIMARY KEY,

h3_sys_id VARCHAR2 (80) REFERENCES in_table_head_3()h3_sys_id),item_code VARCHAR2()80),

bat_no VARCHAR2 (80));

 

INSERT IN in_table_item_1

   VALUES ('I1ID1', 'H1ID1', 'I1');

INSERT IN in_table_item_1

   VALUES ('I1ID2', 'H1ID1', 'I100');

INSERT IN in_table_item_1

   VALUES ('I1ID3', 'H1ID2', 'I3');

INSERT IN in_table_item_2

   VALUES ('I2ID1', 'H2ID1', 'I1');

INSERT IN in_table_item_2

   VALUES ('I2ID2', 'H2ID1', 'I200');

INSERT IN in_table_item_2

   VALUES ('I2ID3', 'H2ID2', 'I2');

INSERT IN in_table_item_3

   VALUES ('I3ID1', 'H3ID1', 'I2','B50');

INSERT IN in_table_item_3

   VALUES ('I3ID2', 'H3ID2', 'I4','B40');

INSERT IN in_table_item_3

   VALUES ('I3ID3', 'H3ID3', 'I4','');

INSERT IN in_table_item_3

   VALUES ('I3ID4', 'H3ID4', 'I6','');

SELECT *

FROM in_table_item_1

SELECT *

FROM in_table_item_2

SELECT *

FROM in_table_item_3










 

CREATE TABLE in_table_batch_1()b1_sys_id VARCHAR2()80) PRIMARY KEY,

txn_code VARCHAR2 (80), doc_no VARCHAR2 (80), bat_no VARCHAR2 (80));

CREATE TABLE in_table_batch_2()b2_sys_id VARCHAR2()80) PRIMARY KEY,

i2_sys_id VARCHAR2 (80) REFERENCES in_table_item_2()i2_sys_id),bat_no VARCHAR2()80));

 

INSERT IN in_table_batch_1

   VALUES ('B1ID1', 'T1', '1234', 'B1');

INSERT IN in_table_batch_1

   VALUES ('B1ID2', 'T70', '1234', 'B70');

INSERT IN in_table_batch_2

   VALUES ('B2ID1', 'I2ID1', 'B30');

INSERT IN in_table_batch_2

   VALUES ('B2ID2', 'I2ID2', 'B90');

INSERT IN in_table_batch_2

   VALUES ('B2ID3', 'I2ID3', 'B60');

Please advise a solution for the same.

Thank you and best regards,

Séverine Suresh

very forced (question subfactoring used to allow easy testing/verification - could work with these test data only)

with

case_1 as

(select s.item_code,

s.bat_no,

h.txn_code,

h.doc_no,

h.updt_dt boe_dt,

cases where s.bat_no = h.bat_no then 'Y' else ' n end batch_yn.

cases where h.txn_code is not null

and h.doc_no is not null

and h.updt_dt is not null

then 'case 1' '.

end refers_to

from (select item_code, bat_no, txn_code, doc_no, boe_dt

of w_stock_table

where bat_no is null

or txn_code is null

or doc_no is null

or boe_dt is null

) s

left outer join

w_history_table h

On s.item_code = h.item_code

and s.bat_no = h.bat_no

and exists (select null

of w_transaction1

where txn_code = nvl (s.txn_code, h.txn_code)

and txn_type in ('IN', 'ALL')

)

),

case_2 as

(select s.item_code,

NVL (s.bat_no, h.bat_no) bat_no.

NVL (s.txn_code, h.txn_code) txn_code.

NVL (s.doc_no, h.doc_no) doc_no.

NVL (s.boe_dt, h.updt_dt) updt_dt.

cases where s.bat_no = h.bat_no then 'Y' else ' n end batch_yn.

cases where h.txn_code is not null

and h.doc_no is not null

and h.updt_dt is not null

then 'case 2'.

end refers_to

from (select item_code, bat_no, txn_code, doc_no, boe_dt

of case_1

where refers_to is null

) s

left outer join

w_history_table h

On s.item_code = h.item_code

and exists (select null

of w_transaction1

where txn_code = nvl (s.txn_code, h.txn_code)

and txn_type in ('IN', 'ALL')

)

and not exists (select null

of case_1

where item_code = h.item_code

and bat_no = h.bat_no

and txn_code = h.txn_code

and doc_no = h.doc_no

and updt_dt = h.updt_dt

)

),

case_31 as

(select s1.item_code,

NVL (S1.bat_no, W1.bat_no) bat_no.

NVL (S1.txn_code, W1.txn_code) txn_code.

NVL (S1.doc_no, W1.doc_no) doc_no.

NVL (S1.updt_dt, W1.doc_dt) updt_dt.

cases where s1.bat_no = w1.bat_no then 'Y' else ' n end batch_yn.

cases where w1.txn_code is not null

and w1.doc_no is not null

and w1.doc_dt is not null

then "case 31'.

end refers_to

from (select item_code, bat_no, txn_code, doc_no, updt_dt, batch_yn, refers_to

of case_2

where refers_to is null

) s1

left outer join

(select i1.item_code, h1.txn_code, h1.doc_no, h1.doc_dt, b1.bat_no

of w_in_table_item_1 i1

inner join

w_in_table_head_1 h1

On i1.h1_sys_id = h1.h1_sys_id

inner join

w_in_table_batch_1 b1

On h1.txn_code = b1.txn_code

and h1.doc_no = b1.doc_no

) w1

On s1.item_code = w1.item_code

),

case_32 as

(select s2.item_code,

NVL (S2.bat_no, W2.bat_no) bat_no.

NVL (S2.txn_code, W2.txn_code) txn_code.

NVL (S2.doc_no, W2.doc_no) doc_no.

NVL (S2.updt_dt, W2.doc_dt) updt_dt.

cases where s2.bat_no = w2.bat_no then 'Y' else ' n end batch_yn.

cases where w2.txn_code is not null

and w2.doc_no is not null

and w2.doc_dt is not null

then "case 32'.

end refers_to

from (select item_code, bat_no, txn_code, doc_no, updt_dt, batch_yn, refers_to

of case_2

where refers_to is null

) s2

left outer join

(select i2.item_code, h2.txn_code, h2.doc_no, h2.doc_dt, b2.bat_no

of w_in_table_item_2 i2

inner join

w_in_table_head_2 h2

On i2.h2_sys_id = h2.h2_sys_id

inner join

w_in_table_batch_2 b2

On i2.i2_sys_id = b2.i2_sys_id

) w2

On s2.item_code = w2.item_code

),

case_33 as

(select s3.item_code,

w3.bat_no,

NVL (S3.txn_code, w3.txn_code) txn_code.

NVL (S3.doc_no, w3.doc_no) doc_no.

NVL (S3.updt_dt, w3.doc_dt) updt_dt.

cases where s3.bat_no = w3.bat_no then 'Y' else ' n end batch_yn.

cases where w3.txn_code is not null

and w3.doc_no is not null

and w3.doc_dt is not null

then "case 33'.

end refers_to

from (select item_code, bat_no, txn_code, doc_no, updt_dt, batch_yn, refers_to

of case_2

where refers_to is null

) s3

left outer join

(select i3.item_code, h3.txn_code, h3.doc_no, h3.doc_dt, i3.bat_no

of w_in_table_item_3 i3

inner join

w_in_table_head_3 h3

On i3.h3_sys_id = h3.h3_sys_id

) w3

On s3.item_code = w3.item_code

)

Select item_code, bat_no, txn_code, doc_no, boe_dt, batch_yn

of case_1

where refers_to is not null

Union of all the

Select item_code, bat_no, txn_code, doc_no, updt_dt, batch_yn

of case_2

where refers_to is not null

Union of all the

Select item_code, bat_no, txn_code, doc_no, updt_dt, batch_yn

from (select item_code, bat_no, txn_code, doc_no, updt_dt, batch_yn,

ROW_NUMBER() over (partition by item_code of updt_dt desc order) rn

from (select item_code, bat_no, txn_code, doc_no, updt_dt, batch_yn

of case_31

where refers_to is not null

Union of all the

Select item_code, bat_no, txn_code, doc_no, updt_dt, batch_yn

of case_32

where refers_to is not null

Union of all the

Select item_code, bat_no, txn_code, doc_no, updt_dt, batch_yn

of case_33

where refers_to is not null

)

)

where rn = 1

ITEM_CODE	BAT_NO	TXN_CODE	DOC_NO	BOE_DT	BATCH_YN
I1	B1	T1	1234	JANUARY 3, 2015	THERE
I1	B30	T30	7890	FEBRUARY 5, 2015	N
I2	B60	T60	1234	JANUARY 3, 2015	N
I3	B70	T70	1234	FEBRUARY 1, 2015	THERE
I4	-	T90	1234	JANUARY 5, 2015	N
I6	-	T40	1234	AUGUST 5, 2015	N

Concerning

Etbin

• Table error ' can not analyze the SQL query!

  Hi all

  I created a view on my database called VIEW_MEMBER_PARTIC_PROJECTS

  If I run a query showing the results of the view:

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  1	31 S
  2	41
  3	19
  4	3
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  6	1
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  JaReg wrote:

  I finally found the problem.

  I looked at the code for the view and changed the start of:

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  AS

  TO

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  AS

  And that seemed to fix it. I'm not entirely sure why though.

  The view was created using the quoted identifiers for column names. This makes them sensitive and means that they must always be referenced using double quotes. In the absence of quotation marks, Oracle is not case insensitive and automatically converts all uppercase identifiers. The application of graph:

  Select the link null, label projects, value1 "SCHEMANAME Participant." "" VIEW_MEMBER_PARTIC_PROJECTS ".

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• I have a HP officejet V40 and have lost the driver cd could you let me know an address where I can download a free driver for this please? thanks___Andydeee __many.,.

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  Ideas:

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  For example if I have a demo table with 4 columns (A, B, C, D) DEMO.
  
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  1 5P8
  1 5 P O
  1-5-9
  1 8 9
  1     D     *     /
  2 8 33 P
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  Try this:

  SQL> select * from tab;
  1 5 9 3
  1 5 P 8
  1 5 P O
  1 D 5 9
  1 D 8 9
  1 P 8 3
  1 P O O
  
  7 rows selected.
  
  SQL> select a,b from
  (select r,a,b from
  ( select to_char(rownum)||'a' r, 'A' a,'B' b from
          (select distinct a, b from tab order by a,b))
          union
  ( select to_char(rownum)||'c' r, 'C' c,'D' d from
          (select distinct a, b from tab order by a,b))
  union
  ( select to_char(rownum)||'b' r, a,b from
  (select distinct a, b from tab order by a,b))
  union
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  ( select to_char(rownum)||'d' r, a,b from
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  tab
  where parent.a=tab.a and
  parent.b=tab.b
  ) order by r
  ;
  A B
  1 5
  C D
  9 3
  P 8
  P O
  A B
  1 D
  C D
  5 9
  8 9
  A B
  1 P
  C D
  8 3
  O O
  

• Is there a way I can personally verify my I Pad Pro to see if it has been refurbished, because I paid the FULL PRICE $$$ for this but have not begun it upwards again and I have a suspicion, it is refurbished? Can I bring to an APPLE STORE and have it chec

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  Makes you think about the iPad Pro you received is a refurb?

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• What is the maximum memory for this computer what kind

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  UTC/GMT is 20:35 on Saturday, May 26, 2012