Help needed on complex sql resolution

Similar Questions

• HELP: Need to code SQL to bulk move

  I use Oracle 11.2, there are two tables tb_base, tb_hist as follows:
  
  tb_base (number (5) id, varchar2 (16) tag, the timestamp pavers (6));
  tb_hist (id number (5), histTs timestamp (6), timestamp (6) the cobblestones, tag varchar2 (16));
  
  tb_base 1, "beard", 20/12/2012
  1, 'bbb', 08/12/2012
  1, "ccc", 12/30/2012
  2, 'aaa', 11/29/2012
  2, 'vvv', 28/11/2012
  
  All I need is to move the record iteration with the same id from tb_base to tb_hist as a result:
  
  tb_base 1, "ccc", 12/30/2012
  2, 'aaa', 12/29/2012
  
  tb_hist 1, "beard", 20/12/2012, 20/12/2012
  1, "bbb", 2012/12/08, 08/12/2012
  2, "vvv", 2012/11/28, 28/11/2012
  
  Any suggestion on the SQL to perform this task?
  
  Thank you

  Copy the historical records of TB_HIST:

  INSERT INTO tb_hist
  (id
  ,histts
  ,setts
  ,tag)
  SELECT id,
         setts,
         setts,
         tag
  FROM   tb_base a
  WHERE EXISTS (SELECT 1
                FROM  (SELECT id,
                              MAX(setts) OVER (PARTITION BY id) max_setts
                       FROM   tb_base) b
                WHERE  b.id         = a.id
                AND    b.max_setts != a.setts)
  

  Remove the historical records of TB_BASE:

  DELETE tb_base a
  WHERE EXISTS (SELECT 1
                FROM  (SELECT id,
                              MAX(setts) OVER (PARTITION BY id) max_setts
                       FROM   tb_base) b
                WHERE  b.id         = a.id
                AND    b.max_setts != a.setts)
  

• [help needed] Several insert - SQL statement

  Hello

  This is my table:

  {code}

  create table test

  (

  Identification number,

  DS varchar (6).

  start_date date

  );

  {code}

  There is data in the table.

  {code}

  Insert test values (1, 'DS1982', TO_DATE ('01.03.2014 ',' DD.)) MM YYYY'));

  Insert test values (2, 'DS1982', TO_DATE ('01.04.2014 ',' DD.)) MM YYYY'));

  Insert test values (3, 'DS1982', TO_DATE ('01.05.2014 ',' DD.)) MM YYYY'));

  Insert test values (4, 'DS1982', TO_DATE ('01.06.2014 ',' DD.)) MM YYYY'));

  Insert test values (1, 'DS1999', TO_DATE ('11.04.2014 ',' DD.)) MM YYYY'));

  Insert test values (2, 'DS1999', TO_DATE ('11.05.2014 ',' DD.)) MM YYYY'));

  Insert test values (3, 'DS1999', TO_DATE ('11.06.2014 ',' DD.)) MM YYYY'));

  Insert test values (4, 'DS1999', TO_DATE ('11.07.2014 ',' DD.)) MM YYYY'));

  Insert test values (1, 'DS0009', TO_DATE ('21.01.2014 ',' DD.)) MM YYYY'));

  Insert test values (2, 'DS0009', TO_DATE ('21.02.2014 ',' DD.)) MM YYYY'));

  Insert test values (3, 'DS0009', TO_DATE ('21.03.2014 ',' DD.)) MM YYYY'));

  {code}

  I have to query all records from the table that has:

  Max (start_date) whitin ID and DS culoms.

  So, I have to insert in the record in the table for each DS to condition:

  Each record will be inserted with incremented id whithin DS

  each record inserted must be "newer" than previous 1 month.

  Integration goes up to to_char (sysdate, mm) = to_char (start_date, 'mm').

  Resoult for DS1982 has so (records to insert):

  Insert test values (5, 'DS1982', TO_DATE ('01.07.2014 ',' DD.)) MM YYYY'));

  Insert test values (6, 'DS1982', TO_DATE ('01.08.2014 ',' DD.)) MM YYYY'));

  Insert test values (7, 'DS1982', TO_DATE ('01.09.2014 ',' DD.)) MM YYYY'));

  Insert test values (8, 'DS1982', TO_DATE ('01.10.2014 ',' DD.)) MM YYYY'));

  Insert test values (9, 'DS1982', TO_DATE ('01.11.2014 ',' DD.)) MM YYYY'));

  Insert test values (10, 'DS1982', TO_DATE ('01.12.2014 ',' DD.)) MM YYYY'));

  Insert test values (11, 'DS1982', TO_DATE ('01.01.2015 ',' DD.)) MM YYYY'));

  Insert test values (12, 'DS1982', TO_DATE ('01.02.2015 ',' DD.)) MM YYYY'));

  Insert test values (13, 'DS1982', TO_DATE ('01.03.2015 ',' DD.)) MM YYYY'));

  Insert test values (14, 'DS1982', TO_DATE ('01.04.2015 ',' DD.)) MM YYYY'));

  all together for DS1982

  Insert test values (1, 'DS1982', TO_DATE ('01.03.2014 ',' DD.)) MM YYYY'));

  Insert test values (2, 'DS1982', TO_DATE ('01.04.2014 ',' DD.)) MM YYYY'));

  Insert test values (3, 'DS1982', TO_DATE ('01.05.2014 ',' DD.)) MM YYYY'));

  Insert test values (4, 'DS1982', TO_DATE ('01.06.2014 ',' DD.)) MM YYYY'));

  Insert test values (5, 'DS1982', TO_DATE ('01.07.2014 ',' DD.)) MM YYYY'));

  Insert test values (6, 'DS1982', TO_DATE ('01.08.2014 ',' DD.)) MM YYYY'));

  Insert test values (7, 'DS1982', TO_DATE ('01.09.2014 ',' DD.)) MM YYYY'));

  Insert test values (8, 'DS1982', TO_DATE ('01.10.2014 ',' DD.)) MM YYYY'));

  Insert test values (9, 'DS1982', TO_DATE ('01.11.2014 ',' DD.)) MM YYYY'));

  Insert test values (10, 'DS1982', TO_DATE ('01.12.2014 ',' DD.)) MM YYYY'));

  Insert test values (11, 'DS1982', TO_DATE ('01.01.2015 ',' DD.)) MM YYYY'));

  Insert test values (12, 'DS1982', TO_DATE ('01.02.2015 ',' DD.)) MM YYYY'));

  Insert test values (13, 'DS1982', TO_DATE ('01.03.2015 ',' DD.)) MM YYYY'));

  Insert test values (14, 'DS1982', TO_DATE ('01.04.2015 ',' DD.)) MM YYYY'));

  I hope someone can help me with this problem!

  Thank you!

  This...

  SELECT the id + id LEVEL,

  DS,

  Start_date ADD_MONTHS (start_date, Level)

  Of

  (SELECT ds,

  Max (ID) id,

  Date_début Max (start_date)

  OF the test

  GROUP BY ds)

  CONNECT BY LEVEL<=>

  AND PREREQUISITES ds = ds

  AND PRIOR DBMS_RANDOM. VALUE IS NOT NULL.

  Thank you

  Ann

• I use Windows Vista and that you need to download SQL Server 2005 Express Service Pack 4. I get an error code of 64 C. Please tell me what to do?

  I use Windows Vista and that you need to download SQL Server 2005 Express Service Pack 4. I get an error code 64 C help, please.

  Hello

  I suggest you to try the steps below and check if it helps.

  Method 1: Try to reset components to update Windows from the following link, which would help you to install the updates of windows. http://support.Microsoft.com/kb/971058

  Method 2: If the problem persists, then try to set up your computer in a clean boot state, and check to see if the same problem happens.

  By setting your boot system minimum state helps determine if third-party applications or startup items are causing the problem.

  How to troubleshoot a problem by performing a clean boot in Windows Vista or Windows 7:
  http://support.Microsoft.com/kb/929135

  Note: After the boot minimum troubleshooting step, follow step 7 in the link provided to return the computer to a Normal startup mode.

  Method 3: Also try to install the updates manually from the link below.

  http://www.Microsoft.com/download/en/details.aspx?displaylang=en&ID=184

  You can also consult the following link for more information:

  Troubleshoot problems with installing updates.

  http://Windows.Microsoft.com/en-us/Windows-Vista/troubleshoot-problems-with-installing-updates

  Hope this information is useful.

• Unable to play the video due to the incompatible program and need to change the resolution

  Hi, I just bought BBC Get Active in French.  I live in France and I have Windows 8.1.  Video on this CD does not work, or not the speech, and he tells me that the program is incompatible. Having said that, also, I need to change the resolution of screen 1600 x 900, that only about 800 x 600 but when I do the screen becomes too small and the program returns to a large screen at 800 x 600.  He mentions the help of Vista or XP but as Windows 8.1 is more advanced I expect him to be just as compatible.  I changed the country of origin of the CD in the UK and hoped that that would solve the problem but no luck.

  Does anyone have a solution for me please?  I'm a child of 74 years, and not quite abreast with the technical jargon so its simplest form would be appreciated.

  Meg

  Original title: BBC GET INTO WINDOWS FRENCH INCOMPATIBILITY 8.1?

  Sunday,

  Hello again, just to make it count that I finally solved myself the problem by reinstalling QuickTime 6 in version 7, but I think the problem was to DO NOT to install it via the program itself, but to install itself as a separate installation, I think I read this somewhere in the course of my research, but at this point I could not remember which way I had installed it.  Hope this will help someone else in the future.

  Kind regards

  Meg

• Help needed on the export of the Photo App

  I'm a photo hobbyest with thousands of photos stored in my Mac using the Photos app. I already saved them on Time Machine and iCloud. However, I try to upload some on an external hard drive but can't.  The Photo app continues to CHANGE the resolution of my images when I export them.  Here is what happens...

  • I have uploaded a JPEG of 5 MB in the Photo app earlier this year.
  • Now, I'm ready to take a copy of this picture on my external hard drive.
  • If I just move the original photo to the Photo app on my counter top, the resolution GOES from 5MB to 2.1 MB.
  • If I export 'The Original unmodified' I lose all the changes that I made in the Photo app.
  • If I export the 'High' quality jpeg image, it DROPS my resolution of 2.1 MB.
  • If I export the photo to the "Maximum" quality jpeg, it INCREASES my resolution to 14.3 MB!
  • I found NO WAY to download my original photo size!

  Question... How to export or copy an image from within the app of the Photo on an external hard drive with the resolution of the EXACT SAME as it is?

  Thank you!

  You first need to understand the resolution - the file size is not resolution - the resolution concerns the dimensions in pixels of the image - file to a JPEG file size is determined by the compression you choose - compression of the image does not change the dimensions in pixels of all - compression removes the donnΘes form the pictures and all JPEG in theory is inferior finial an uncompressed image as TIFF - but for practically all the uses, it does not matter

  When you export a modified version of the photo you create a new file that contains the image and the size of the files is determined by the selections you make and has no resolution at all to the original file

  Photos has limited control over file size - ir you want a file size, then export a copy of very high quality (maximum or even a TIFF uncompressed) and use another program that gives you more control to compress in the JPEG compression you want

  But at the end of the day the size of the file is really no different and it is very likely that the big JPEG will give you the same results as an uncompressed TIFF

  LN

• When I right click of my mouse I do not get the properties option. I need to increase the resolution to fit a bigger screen.

  When I right click of my mouse I do not get the properties option. I need to increase the resolution to fit a bigger screen.

  It's not real estate in Vista customize. Then look at the last option.

• Please can someone help, need password CNU9497P2C

  I have the same problem and its driving me crazy... I need the BIOS password because I can't access to this

  [number of Series edited by Moderator]

  Please can someone help, need password

  HP MINI CQ10

  Sweb try.

  e9lovox27e

  3rd letter tiny L.

  4th and 6th letter lowercase o.

  Use this code to go into the BIOS.

  Disable all passwords that are enabled.

  If demand for CURRENT password using this code.

  Request NEW password just press ENTER.

  If asked to hit just to CHECK password to enter.

  Save and exit.

  REO

  I must inform you that these services are not endorsed by HP, and that HP is not responsible for any damages that may occur to your system using these services. Please be aware that you do so at your own risk.

• Need a logic sql to insert from one table to another

  I have a table ( TABLEA ) as follows:

  type_id level 
  -------------
  
  1       7 
  2       4 
  

  I would like to insert above values in another table ( TABLEB ) through DML so it looks like so:

  seq_id type_id name    order level 
  -----------------------------------
  
  1     1       display  1     7 
  2     1       header   2     
  3     1       detail   3     
  4     2       display  1     4 
  5          2          header    2
  6         2           detail      3    
  

  Looks like a very complex sql is necessary, for which I have no knowledge of :-).

  Hello

  97a5a09d-76e1-4fc7-8113-80b4705be7f4 wrote:

  I have a table ( TABLEA ) as follows:

  type_id level 
  -------------
  
  1       7 
  2       4 
  

  I would like to insert above values in another table ( TABLEB ) through DML so it looks like so:

  seq_id type_id name    order level 
  -----------------------------------
  
  1     1       display  1     7 
  2     1       header   2     
  3     1       detail   3
  4     2       display  1     4
  5          2          header    2
  6         2           detail      3    
  

  Looks like a very complex sql is necessary, for which I have no knowledge of :-).

  So, for each line in tablea, you want to INSERT 3 rows in tableb, is that at the time?

  One way to do that is to tablea to join of a table (or the result set) with 3 rows, like cntr below:

  INSERT INTO tableb (seq_id type_id, row_name, row_order, lvl)

  WITH cntr AS

  (

  SELECT LEVEL AS row_order

  OF the double

  CONNECT BY LEVEL<=>

  )

  SELECT ROW_NUMBER () OVER (ORDER BY a.type_id

  c.row_order

  ) - or sequence_name. NEXTVAL

  a.type_id

  Case c.row_order

  WHEN 1 THEN 'display '.

  WHEN 2 THEN 'head '.

  WHEN 3 THEN «details»

  END

  c.row_order

  Case c.row_order

  WHEN 1 THEN a.lvl

  END

  FROM tablea a

  CROSS JOIN cntr c

  ;

  If you would care to post CREATE TABLE and INSERT for your tables (as it exists before the UPDATE), then I could test this.

  NAME is not a very good column name, but it is nowhere near as bad as the ORDER or LEVEL.  I called ROW_NAME, ROW_ORDER and LVL columns instead.

• Please, help me to query SQL Construct.

  
  Hi Experts,

  Could you please help me to query SQL Construct.  Please find the details

  HOSTNAME HOSTTYPE DEM R1 R2
  RS123 P ABC 24.5 265,5

  RS123 P CYC 24.5 265,5

  RS123 P ADDS 24.5 265,5

  RS123 P ADE 24.5 265,5

  RS123 P SRC 24.5 265,5

  EXPECTED RESULTS

  HOSTNAME      HOSTTYPE                              MNE                                                                      R1          R2
  RS123 P ABC, CYC, ADD, ADE, CBC 24.5 265,5

  Concerning

  See you soon

  with t as)

  Select "RS123' hostname 'P' hosttype, 'ABC' dem, 24.5 r1, r2 265,5 Union double all the

  Select 'RS123', 'P', "CYC", 24.5, 265,5 double Union all

  Select 'RS123', 'P', 'ADD', 24.5, 265,5 double Union all

  Select "RS123', 'P', 'ADE', 24.5, 265,5 double Union all

  Select 'RS123', 'P', 'SRC', 24.5, 265,5 double

  )

  Select the host name,

  HostType,

  RTrim (XMLAGG (XmlElement(e,MNE,','). (Extract ('//Text ()')), ',') DEM,.

  R1,

  R2

  t

  Group hostname,

  HostType,

  R1,

  R2

  /

  HOSTN H DEM R1 R2
  ----- - -------------------- ---------- ----------
  RS123 P ABC, CBC, ADE, ADD, CYC 24.5 265,5

  SQL >

  SY.

• help on editing a SQL

  DELETE FROM my_table t1
      WHERE rowid NOT IN ( SELECT min(rowid) 
                           FROM my_table t2
                           GROUP BY key_value1 );

  I want to delete duplicates of records in MY_TABLE and table itself contains about 45 million documents. KEY_VALUE1 is whole and indexed.
  
  Can someone help me change this SQL to make it faster and more efficient?
  
  Appreciated.

  For very large delete operations, it is generally faster to insert values to keep in another table. Then truncate the original table and rename or reinsert the maintained values.

  example not tested

  insert into t1_temp
  select * from my_table t1
  WHERE rowid IN ( SELECT min(rowid)
                           FROM my_table t2
                           GROUP BY key_value1 );
  
  truncate table t1;
  
  insert into t1 select * from t1_temp;
  
  truncate table t1_temp;
  

  Be aware that a truncate command will do an implicit validation. So do not run without good test.

  Published by: Sven w. March 9, 2011 19:21

• Need help to write a SQL query complex

  I have the source tabe as below
  
  -> SOURCE_TABLE
  

  NAME     CUST_ID     SVC_ST_DT     SVC_END_DT 
  TOM        1               31/08/2009      23/03/2011 
  DOCK       2               01/01/2004      31/05/2010 
  HARRY      3               28/02/2007      31/12/2009 

  I want to load as target table below
  -> TARGET_TABLE
  

  NAME     CUST_ID                     SVC_ST_DT      SVC_END_DT 
  TOM      1           31/08/2009      31/12/2009 
  TOM      1           01/01/2010      31/12/2010 
  TOM      1           01/01/2011      23/03/2011 
  DOCK      2           01/01/2004      31/12/2004 
  DOCK      2           01/01/2005      31/12/2005 
  DOCK      2           01/01/2006      31/12/2006 
  DOCK      2           01/01/2007      31/12/2007 
  DOCK      2           01/01/2008      31/12/2008 
  DOCK      2           01/01/2009      31/12/2009 
  DOCK      2           01/01/2010      31/05/2010 
  HARRY      3           28/02/2007      31/12/2007 
  HARRY      3           01/01/2008      31/12/2008 
  HARRY      3           01/01/2009      31/12/2009 

  Is it possible to write a SQL query that returns the data in the same way above the target table.
  
  Published by: AChatterjee on April 30, 2012 07:14
  
  Published by: AChatterjee on April 30, 2012 07:14

  Or like this...

  SQL> ed
  Wrote file afiedt.buf
  
    1  with t as (select 'TOM' as NAME, 1 as CUST_ID, date '2009-08-31' as SVC_ST_DT, date '2011-03-23' as SVC_END_DT from dual union all
    2             select 'DOCK', 2, date '2004-01-01', date '2010-05-31' from dual union all
    3             select 'HARRY', 3, date '2007-02-28', date '2009-12-31' from dual)
    4  --
    5  -- end of test data
    6  --
    7  select name, cust_id, svc_st_dt, svc_end_dt
    8  from (
    9        select name
   10              ,cust_id
   11              ,greatest(svc_st_dt, add_months(trunc(svc_st_dt,'YYYY'),yr*12)) as svc_st_dt
   12              ,least(svc_end_dt, add_months(trunc(svc_st_dt,'YYYY'),(yr+1)*12)-1) as svc_end_dt
   13        from t
   14             cross join (select rownum-1 as yr
   15                         from   dual
   16                         connect by rownum <= (select extract(year from max(svc_end_dt)) - extract(year from min(svc_st_dt)) + 1 from t)
   17                        )
   18       )
   19  where svc_st_dt <= svc_end_dt
   20* order by 2, 3
  SQL> /
  
  NAME     CUST_ID SVC_ST_DT            SVC_END_DT
  ----- ---------- -------------------- --------------------
  TOM            1 31-AUG-2009 00:00:00 31-DEC-2009 00:00:00
  TOM            1 01-JAN-2010 00:00:00 31-DEC-2010 00:00:00
  TOM            1 01-JAN-2011 00:00:00 23-MAR-2011 00:00:00
  DOCK           2 01-JAN-2004 00:00:00 31-DEC-2004 00:00:00
  DOCK           2 01-JAN-2005 00:00:00 31-DEC-2005 00:00:00
  DOCK           2 01-JAN-2006 00:00:00 31-DEC-2006 00:00:00
  DOCK           2 01-JAN-2007 00:00:00 31-DEC-2007 00:00:00
  DOCK           2 01-JAN-2008 00:00:00 31-DEC-2008 00:00:00
  DOCK           2 01-JAN-2009 00:00:00 31-DEC-2009 00:00:00
  DOCK           2 01-JAN-2010 00:00:00 31-MAY-2010 00:00:00
  HARRY          3 28-FEB-2007 00:00:00 31-DEC-2007 00:00:00
  HARRY          3 01-JAN-2008 00:00:00 31-DEC-2008 00:00:00
  HARRY          3 01-JAN-2009 00:00:00 31-DEC-2009 00:00:00
  
  13 rows selected.
  

• Need help: complex SQL statement

  Select segment3, 0 "other income."
  , 0 "Sales Services".
  , 0 "staff costs".
  , 0 "other staff costs".
  , 0 'Deputy '.
  , 0 'trip '.
  , 0 "collaborator".
  , 0 'training '.
  , 0 'capital '.
  , nvl (round (sum (nvl(PERIOD_ACTIVITY_A,0) + nvl(PERIOD_ACTIVITY_E,0) + nvl(PRDOPEN_A,0) + nvl(PRDOPEN_E,0)), 0), 0) "Overhead"
  , 0 "financial expenses".
  of PAN. SNP_OP_DETAIL@OFA
  where segment3 = x.new_cc and period_name = p_period
  and segment2 in (select acc_t from the CRP_REPORT_ACCT_DETAIL_T where group_id = 10)
  Group of segment3
  
  Please, I do not understand select segment3, 0 'other income'... There is no column called 0, what is the 0s in the select statement?
  
  Secondly, I don't understand PAN. SNP_OP_DETAIL@OFA

  Means says:
  Select segment3, 0 "other income."
  , 0 "Sales Services".
  , 0 "staff costs".
  , 0 "other staff costs".
  , 0 'Deputy '.
  , 0 'trip '.
  , 0 "collaborator".
  , 0 'training '.
  , 0 'capital '.
  , nvl (round (sum (nvl(PERIOD_ACTIVITY_A,0) + nvl(PERIOD_ACTIVITY_E,0) + nvl(PRDOPEN_A,0) + nvl(PRDOPEN_E,0)), 0), 0) "Overhead"
  , 0 "financial expenses".
  of PAN. SNP_OP_DETAIL@OFA
  where segment3 = x.new_cc and period_name = p_period
  and segment2 in (select acc_t from the CRP_REPORT_ACCT_DETAIL_T where group_id = 10)
  Group of segment3

  Please, I do not understand select segment3, 0 'other income'... There is no column called 0, what is the 0s in the select statement?

  0 'other income' means to select a literal value of 0 (zero) with an alias of "other income". double quotes preserve the space and upper/lower case in the alias. This alias (in space) will be difficult to use because of the so called space later.

  Secondly, I don't understand PAN. SNP_OP_DETAIL@OFA

  PAN is probably a schema, SNP_OP_DETAIL a table or view and @OFA there is a link of database indicating the table in a different database

• Help Needed in SQL query

  Hi all
  
  Required clarification of Oracle sql
  
  Example table:
  
  EmpNo empname mgr_id hire_date deptno salary Job
  
  7788 SCOTT ANALYST 7566 3000 APRIL 19, 87 20
  7902 7566 3000 3 DECEMBER ANALYST FORD 81 20
  7934 MILLER COMMITTED JANUARY 7782 1300 23 82 10
  7900 7698 DECEMBER 3, CLERK JAMES 81 950 30
  7369 SMITH COMMITTED 7902 17 DECEMBER 20 800 80
  7876 ADAMS 7788 1100 23 MAY CLERK 87 20
  
  
  Need of ' single / one ' sql for this statement of the obligation:
  
  There will be 2 dropdown boxes (1 - work list, 2nd - empno) in the form in which the next set of results is expected
  
  (1) when the user selects the value of the 1st drop down box (employment) as "ANALYST", leaving the second dropdown not selected, the expected result is 2 (No. lines for this work)
  (2) when the user selects the value of the 1st drop-down list (job) as "ANALYST" and the value in the 2nd drop-down box like 7902, the expected result is 1 (no lines for this job and empno)
  
  SQLs I tried on my side (given below) gave the expected result and do please help me fix this
  
  Select count (1) in the scott.emp where job = 'ANALYST' and (empno =: empno or empno is null);
  
  Please help for this requirement. Any help is deeply appreciated.
  
  Thank you
  Zakari

  1007144 wrote:

  SQLs I tried on my side (given below) gave the expected result and do please help me fix this

  Select count (1) in the scott.emp where job = 'ANALYST' and (empno =: empno or empno is null);

  You check "IS NULL" on EMPNO clolumn. You should check on the value passed: EMPNO. It should be

  select count(1) from scott.emp where job='ANALYST' and ( empno = :empno or :empno is null ) ;
  

  Published by: JAC on May 21, 2013 19:32
  Hope that the: value of EMPLOYMENT is required...

• Need help in writing the SQL CASE or DECODE statement

  Hi experts,
  
  I need to write a SQL select order_num, cntry_cde, prod_id and Qty by joining order_num on PROD_ORDER and PROD_ORDER_TXT.
  
  Here is my sample data
  
  PROD ORDER_
  order_num Prod_id Qty cntry_cde
  100 US A1 5
  101 US 10 A2
  102 IN A3 4
  103 TO THE A4 9
  104. IN A5 3
  
  PROD ORDER_TXT_
  cntry_cde Prod_id order_num
  100 US A1
  101 US A2
  102 NZ A3
  103 TO THE A4
  A5 104
  
  Here's the requirement,
  
  (1) if the cntry_cde in PROD_ORDER is the same as cntry_cde in PROD_ORDER_TXT then select PROD_ORDER.cntry_cde (orders 100, 101, 103)
  (2) if they are different, choose PROD_ORDER_TXT (order 102, to THE NZ <>) country code
  (3) if they are different and PROD_ORDER_TXT.cntry_cde is null, I can't use it like cntry_cde in my report (order 104). It happenend just because of bad data to the source.
  I can't avoid it. Then just use the cntry_cde of PROD_ORDER
  
  Expected results
  100 US A1 5
  101 US 10 A2
  102 NZ A3 4 - changed in NZ
  103 TO THE A4 9
  104. IN A5 3 - IN retained as PROD_ORDER_TXT.cntry_cde is null
  
  
  instructions for creation and insertion of sample table are lower than
  
  create the table prod_order
  (number of order_num,
  cntry_cde CHAR (2),
  prod_id VARCHAR2 (6).
  number of quantity)
  
  create the table prod_order_txt
  (number of order_num,
  cntry_cde CHAR (2),
  prod_id VARCHAR2 (6))
  
  insert into prod_order values (100, 'WE', 'A1', 5);
  insert into prod_order values (101, 'WE', 'A2', 1);
  insert into prod_order values (102, ' to THE ', 'A3', 4);
  insert into prod_order values (103, ' to THE ', 'A4', 9);
  insert into prod_order values (104, 'IN', 'A5', 3);
  
  
  
  insert into prod_order_txt values (100, 'WE', 'A1');
  insert into prod_order_txt values (101, 'WE', 'A2');
  insert into prod_order_txt values (102, 'NZ', 'A3');
  insert into prod_order_txt values (103, ' to THE ', 'A4');
  insert into prod_order_txt values (104, 'A5', NULL);
  
  commit;
  
  Thank you for your help in advance
  
  Published by: manon March 28, 2012 13:39