Help on the game of query results

Similar Questions

• Help returns the array of query results

  Hi all... Pretty new to this so please forgive my ignorance. Running Oracle 11 g, trying to return results as in the example I give below. I don't know how the Sport field will have unique values, and I don't know how many unique values the year field is seen in the data. Does anyone have recommendations/suggestions?
  
  The structure of the table is:
  Year of sport
  Baseball 10-11
  Football 10-11
  Football 11-12
  Football 11-12
  Football 11-12
  Baseball 11-12
  
  The result should be sports in each year and should be grouped by year but shown as columns so:
  (GROUP OF the year)
  1, baseball 1, Football
  2, 1, Football Soccer 1, Baseball
  
  
  I hope that makes sense. Thanks for any help!
  ... Kaelon

  Does anyone have recommendations/suggestions?

  Maybe something like:

  SQL> with t as (
   select 'Baseball' sport, '10-11' year from dual union all
   select 'Football', '10-11' from dual union all
   select 'Football', '11-12' from dual union all
   select 'Football', '11-12' from dual union all
   select 'Soccer',   '11-12' from dual union all
   select 'Baseball', '11-12' from dual
  )
  --
  --
  select year, listagg(cnt || ', ' || sport, ' ') within group (order by cnt desc) sports from (
  select count(*) cnt, sport, year from t
  group by sport, year)
  group by year
  /
  YEAR    SPORTS
  ------- ----------------------------------------
  10-11   1, Baseball 1, Football
  11-12   2, Football 1, Baseball 1, Soccer       
  
  2 rows selected.
  

  ?

• Trying to download a game that won't play, I asked for help on the game site and they start saying "click on start and then"Run". Try as I might I can't find "run". Any suggestions

  I am unable to find the 'run' which, according to the website of the game should be pinned to my button 'start '. Any ideas?

  I am unable to find the 'run' which, according to the website of the game should be pinned to my button 'start '. Any ideas?

  It is an older version of windows.  In 7 or Vista, click Start, and then use the search box - enter the article they say "run" and press ENTER.

• limit the number of query results for content Presenter CMIS

  Hi dear,
  
  I have a problem. I added content present on my page in Jdev ide, not at run time. And I need a query including the limitation of the number of results.
  
  My query is: ${' SELECT * from ora: t:IDC:GlobalProfile WHERE the ora: p:xRegionDefinition =-"CSGMNEWS_REGDEF\" ORDER BY ora: p:dInDate DESC'}
  
  
  I just want to add a number parameter.
  
  Can you help me please? How can I limit the number of results?
  
  Kind regards
  
  Yacouba
  
  Published by: erdo on 21.Mar.2013 18:37

  Hello.

  Content Presenter has a setting (maxResults) to set the maximum returned results:

  Sample:
  
  xmlns = "http://xmlns.oracle.com/adf/controller/binding" Refresh 'ifNeeded' = >
  
  
  
  
  
  
  
  

  When you add your CP to a page at design time, you can access the pageDefinition and provide more values for attributes of CP.

  I hope this help you.

  Kind regards.

• the case-insensitive query results

  I got a help from 11g with the suite of version information
  
  Oracle Database 11g Enterprise Edition Release 11.1.0.7.0 - Production
  PL/SQL Release 11.1.0.7.0 - Production
  CORE Production 11.1.0.7.0
  AMT for 32-bit Windows: Version 11.1.0.7.0 - Production
  NLSRTL Version 11.1.0.7.0 - Production
  
  The result of the query are case-sensitive
  
  Ex: Select * from Table_1 where column like '% new % ';
  
  result: News
  
  But do not go back NEWS News or news

  The result of the query are case-sensitive

  But you want the results to be case-insensitive?
  Well, then you can use:

  Select * from Table_1 where lower(column) like '%news%';
  

  And use a function based index.

• How to speed up the time to query result

  When executing the following query, the result comes after 22 seconds.
  
  How I minimize this time? Please suggest.
  

  SELECT DISTINCT
         PERIOD_NO,
         ITEM_CODE,
         ITEM_NAME,
         SUM(CASE WHEN LEVEL_TYPE IN 'SUB ZONE' THEN WD_FORECAST_QTY_BU / CNV / ML ELSE 0 END)TOT_FRCST
  FROM   SHEET_HEAD, SHEET_DETAIL, ITEM_DETAIL
  WHERE  WH_SYS_ID = WD_WH_SYS_ID 
  AND    ITEM_CODE = WD_ITEM_CODE(+)
  AND    PERIOD_NO BETWEEN :PERIOD1 AND :PERIOD2
  AND    WH_REVISION_NO = 0 
  AND    WH_LEVEL_CODE NOT IN (SELECT WH_LEVEL_CODE FROM SHEET_HEAD WHERE WH_REVISION_NO = 1)
  GROUP BY   ITEM_CODE, ITEM_NAME, WH_PERIOD_NO

  Sanjay

  Hello

  with speed suggest it would be always be expirement with indexing on parameters, after that first scans all what is currently happening in what concerns analyses of full table etc. which are "more expensive."

  Level of the specific actions on your code, that what follows comes out too expensive; -

  AND    WH_LEVEL_CODE NOT IN (SELECT WH_LEVEL_CODE FROM SHEET_HEAD WHERE WH_REVISION_NO = 1)
  

  Here, I would see if you can rewrite, perhaps with a left join / auto join to achieve the same ends, compare the timings, you might be surprised.

  Kind regards

  Robert.

• Help of the complex select query (Group by)

  Hello
  I am in need of your help to create a unique select query for the data in the table below and whose output requies. I use oracle 10g on RHEL 5 version.
  
  create table bustour (number of bussno (4), start_date date, number (2)) passenger;
  ALTER session set nls_date_format = "dd-mm-yyyy";
  insert into bustour values (4123, April 10, 2009 ", 20);
  insert into bustour values (4123, may 10, 2009 ", 25);
  insert into bustour values (4123, may 10, 2009 ', 18);
  insert into bustour values (4123, June 10, 2009 ', 15);
  
  insert into bustour values (6138, March 10, 2009 ', 16);
  insert into bustour values (' 6138, March 10, 2009 ", 19);
  insert into bustour values (6138, April 10, 2009 ', 22);
  insert into bustour values (' 6138, April 10, 2009 ", 13);
  
  insert into bustour values ("4123, July 10, 2009 ', 23);
  insert into bustour values (4123, August 10, 2009 ", 27);
  insert into bustour values (4123, November 10, 2009 ', 15);
  
  insert into bustour values (6138, may 10, 2009 ', 16);
  insert into bustour values (6138, may 10, 2009 ', 13);
  insert into bustour values (6138, may 10, 2009 ', 18);
  insert into bustour values (' 6138, may 10, 2009 ", 24);
  insert into bustour values (6138, July 10, 2009 ", 20);
  insert into bustour values (6138, August 10, 2009 ", 18);
  

  SQL> select * from bustour;
  
      BUSSNO START_DATE PASSENGERS
  ---------- ---------- ----------
        4123 04-10-2009         20
        4123 05-10-2009         25
        4123 05-10-2009         18
        4123 06-10-2009         15
        6138 03-10-2009         16
        6138 03-10-2009         19
        6138 04-10-2009         22
        6138 04-10-2009         13
        4123 07-10-2009         23
        4123 08-10-2009         27
        4123 11-10-2009         15
  
      BUSSNO START_DATE PASSENGERS
  ---------- ---------- ----------
        6138 05-10-2009         16
        6138 05-10-2009         13
        6138 05-10-2009         18
        6138 05-10-2009         24
        6138 07-10-2009         20
        6138 08-10-2009         18
  
  17 rows selected.
  
  I want query output as below :
  
  Bussno  start_date      end_Date   totalpassengers   maxpessenger  maxpassdate
  4123    04-10-09        06-10-09          78              25         05-10-09
  6138    03-10-09        04-10-09          70              22         04-10-09 
  4123    07-10-09        11-10-09          65              27         08-10-09
  6138    05-10-09        08-10-09         109              24         05-10-09

  So that we can know on what particular travel calendar, we have obtained maximum passengers and the date. (For calculating % of bonus driver)
  
  Please help me to write the query.
  
  Best regards
  Nisha

  OK, something like this:

  with my_tab as (select 1 id, 4123 busno, to_date('04/10/2009', 'dd/mm/yyyy') start_date, 20 passengers from dual union all
                  select 2 id, 4123 busno, to_date('05/10/2009', 'dd/mm/yyyy') start_date, 25 passengers from dual union all
                  select 3 id, 4123 busno, to_date('05/10/2009', 'dd/mm/yyyy') start_date, 18 passengers from dual union all
                  select 4 id, 4123 busno, to_date('06/10/2009', 'dd/mm/yyyy') start_date, 15 passengers from dual union all
                  select 5 id, 6138 busno, to_date('03/10/2009', 'dd/mm/yyyy') start_date, 16 passengers from dual union all
                  select 6 id, 6138 busno, to_date('03/10/2009', 'dd/mm/yyyy') start_date, 19 passengers from dual union all
                  select 7 id, 6138 busno, to_date('04/10/2009', 'dd/mm/yyyy') start_date, 22 passengers from dual union all
                  select 8 id, 6138 busno, to_date('04/10/2009', 'dd/mm/yyyy') start_date, 13 passengers from dual union all
                  select 9 id, 4123 busno, to_date('07/10/2009', 'dd/mm/yyyy') start_date, 23 passengers from dual union all
                  select 10 id, 4123 busno, to_date('08/10/2009', 'dd/mm/yyyy') start_date, 27 passengers from dual union all
                  select 11 id, 4123 busno, to_date('11/10/2009', 'dd/mm/yyyy') start_date, 15 passengers from dual union all
                  select 12 id, 6138 busno, to_date('05/10/2009', 'dd/mm/yyyy') start_date, 16 passengers from dual union all
                  select 13 id, 6138 busno, to_date('05/10/2009', 'dd/mm/yyyy') start_date, 13 passengers from dual union all
                  select 14 id, 6138 busno, to_date('05/10/2009', 'dd/mm/yyyy') start_date, 18 passengers from dual union all
                  select 15 id, 6138 busno, to_date('05/10/2009', 'dd/mm/yyyy') start_date, 24 passengers from dual union all
                  select 16 id, 6138 busno, to_date('07/10/2009', 'dd/mm/yyyy') start_date, 20 passengers from dual union all
                  select 17 id, 6138 busno, to_date('08/10/2009', 'dd/mm/yyyy') start_date, 18 passengers from dual)
  -- end of mimicking your data; use SQL below:
  select busno,
         min(start_date) start_date,
         max(start_date) end_date,
         sum(passengers) total_passengers,
         max(passengers) max_passengers,
         max_pass_date
  from   (select id,
                 start_date,
                 busno,
                 passengers,
                 distance,
                 max(start_date) keep (dense_rank first order by passengers desc) over (partition by distance, busno) max_pass_date
          from   (select id,
                         start_date,
                         busno,
                         passengers,
                         -- using tabibitosan method, borrowed from Aketi Jyuuzou
                         dense_rank() over (order by id) -
                            row_number() over (partition by busno order by id) distance
                  from   my_tab))
  group by busno, distance, max_pass_date
  order by min(id)
  
       BUSNO START_DATE END_DATE   TOTAL_PASSENGERS MAX_PASSENGERS MAX_PASS_DATE
  ---------- ---------- ---------- ---------------- -------------- -------------
        4123 04/10/2009 06/10/2009               78             25 05/10/2009
        6138 03/10/2009 04/10/2009               70             22 04/10/2009
        4123 07/10/2009 11/10/2009               65             27 08/10/2009
        6138 05/10/2009 08/10/2009              109             24 05/10/2009   
  

• Help - run the extended CO query?

  Read the many threads on the topic prior to this announcement, but im still stuck.
  
  I extended a sowing controller, to display text msgStyle seeded as a link under certain conditions.
  I want to take is:
  
  If (condition true) {//set the text msg destination uri} otherwise do nothing
  
  To implement the condition, I have to make a request to check if this value exists in the table. I have not any Vo attached to achieve this.
  I could create a custom VO and attach it to AM programaticaly? One last thing - AM attached to this seeded page is am root.
  I read that AM root should not be extended.
  
  How can I achieve this?

  Hello

  For this, you can use dynamic VO, create VO, and run the query.

  Kind regards
  Out Sharma

• LifeCam Cinema: After installing LifeCam 3.0 (many files), no "Microsoft LifeCam" program appears in START / all programs. Looking for a "LifeCam help" on the C drive, no results

  "New hardware found", and "your new hardware is ready to use" I don't know how

  The minimum requirements are met. If by chance, anything to cause a problem, Setup wouldn't let you continue when you went first to install the software.

  Try to install the latest version of the driver package and software Windows XP 32/64 - bit from Microsoft here:
  http://download.Microsoft.com/download/6/6/6/6663B667-3D5E-4637-A615-80EC6BA1E4AC/LifeCam3.0.exe
  Let us know after the installation of what is happening,
  Thank you!

  Ryan Thieman
  Microsoft Answers Support Engineer
  Visit our Microsoft answers feedback Forum and let us know what you think.

• Number to reach the desired with query result...

  Here some pseudocode tables and data to show my problem:
  

  CREATE TABLE temp (name_home varchar2(25), name_away varchar2(25), id integer);
  INSERT INTO temp
  VALUES ('a','b',1,1);
  INSERT INTO temp
  VALUES ('c','a',1,3);
  INSERT INTO temp
  VALUES ('e','a',1,4);
  INSERT INTO temp
  VALUES ('c','a',1,6);
  INSERT INTO temp
  VALUES ('d','e',1,5);
  INSERT INTO temp
  VALUES ('b','a',1,7); 

  Desired output of table

          NAME_HOME     NAME_AWAY     ID     SEQ
  
  
       a            b             1     1
          b            a             1     7
       c            a             1     3
       c            a             1     6
       e            a             1     4
       d            e             1     5

  NOTE
  My table contains millions or lines like this, idea would be a solution that would be enough for a table containing millions of combos like those above.
  
  
  I want to display the data with the following by order:
  
  (1) records where any combination of a value of data in "name_home" and "name_away" appears more than one time first (record e.i. with seq 1.7)
  (2) sequence number CSA
  
  So, for seq 1 and 7, it does not matter to me that 'a' and 'b' switch between name_home and name_away, they must appear first because a combo of a and b in the same record appears more than once and the number of seq of one of the files is smaller than any of the seq in the accounts rendered by 'c' and 'a '. I hope that makes sense.
  
  Published by: user652714 on November 17, 2010 16:04

  Fixed, when I read until the end :)

  select
  t.*,
  count(*) over(partition by greatest(name_home,name_away),least(name_away,name_home)) cnt,
  first_value(seq) over(partition by greatest(name_home,name_away),least(name_away,name_home) order by seq) min_seq
  from temp t
  order by cnt desc,min_seq asc
  

  NAME_HOME     NAME_AWAY     ID     SEQ     CNT     MIN_SEQ
       a     b     1     1     2     1
       b     a     1     7     2     1
       c     a     1     3     2     3
       c     a     1     6     2     3
       e     a     1     4     1     4
       d     e     1     5     1     5
  

  Kind regards
  Sayan M.

  Published by: xtender on 18.11.2010 11:49

• run immediately and the set of query results

  Hi gurus,
  
  I want to create a series of paintings on the fly using run immediately.
  the table_names are stored in another table work_table.
  
  
  run immediately (select 'create table' | table_name |) '(id int)' of
  * (select table_name in work_tables)); *
  
  
  This will raise error.
  
  ORA-06550: line 1, column 18:
  PLS-00103: encountered the symbol "SELECT" at the expected in the following way:
  
  (en) - + new case mod not null < an ID >
  < between double quote delimited identifiers of > < a variable binding >
  
  
  instead of using a cursor to run one by one is the lines an alternative solution?
  
  Thank you very much
  Charles

  May not know why you want to do it in a single statement, anyway:

  SQL> select * from work_tables;
  
  TABLE_NAME
  ------------------------------
  x1
  x2
  
  SQL> declare
    2  str varchar2(32000);
    3  begin
    4    for r in (select table_name from work_tables) loop
    5      str := str || 'execute immediate ''create table ' || r.table_name || '( id int )''; ' ;
    6    end loop;
    7
    8    execute immediate 'begin '||str||' end;';
    9
   10  end;
   11  /
  
  PL/SQL procedure successfully completed.
  
  SQL> desc x1
   Name                                                        Null?    Type
   ----------------------------------------------------------- -------- ------------------------------
   ID                                                                   NUMBER(38)
  
  SQL> desc x2
   Name                                                        Null?    Type
   ----------------------------------------------------------- -------- ------------------------------
   ID                                                                   NUMBER(38)
  

  Max
  http://oracleitalia.WordPress.com

  Published by: Massimo Ruocchio, February 18, 2010 15:03

• Select the format of query results

  SELECT * FROM srm_application_data WHERE application_id = '242564';
  
  Returns
  
  app_id question_name data
  ------ ------------- -----
  242564 FirstName qreq
  242564 StaffID 12314
  242564 of State VIC
  242564 o ' Connel of suburbs
  
  I want that data to be presented as
  
  First name 242564 qreg staffId 12314 State VIC Subrub o ' Connel

  the path q & d:

   select id
        , wm_concat (name||' '||data)
     from test
    group by id
   ;
  

  as in

  SQL> with test as
    2  (
    3  select 242564 id, 'FirstName' name, 'qreq' data from dual union all
    4  select 242564 id, 'StaffID', '12314'            from dual union all
    5  select 242564 id, 'State', 'VIC'                from dual union all
    6  select 242564 id, 'Suburb', 'o''connel'         from dual
    7   )
    8   select id
    9        , wm_concat (name||' '||data)
   10     from test
   11    group by id
   12   ;
  
          ID
  ----------
  WM_CONCAT(NAME||''||DATA)
  ------------------------------------------------------------------------
      242564
  FirstName qreq,StaffID 12314,State VIC,Suburb o'connel
  

• Query results pane should display the entire XML following the execution of the query

  Hi, I'm trying to get the xml output results returned in sqldeveloper returned in full.

  they are truncated to.

  I tried the trick / * xml * / but that is implemented in the form xml cdata codes and other structures of nickname.

  Select xmlserialize (DOCUMENT

  XMLELEMENT ("root",

  XMLAttributes ('http://www.millicom.com' as 'xmlns'),

  XMLAGG)

  XMLELEMENT ("line",

  XMLFOREST (U.username,

  U.user_id,

  U.PASSWORD,

  U.ACCOUNT_STATUS,

  U.LOCK_DATE,

  U.EXPIRY_DATE,

  U.DEFAULT_TABLESPACE,

  U.TEMPORARY_TABLESPACE,

  U.CREATED,

  U.PROFILE,

  U.INITIAL_RSRC_CONSUMER_GROUP,

  U.EXTERNAL_NAME,

  U.PASSWORD_VERSIONS,

  U.EDITIONS_ENABLED,

  U.AUTHENTICATION_TYPE)))

  AS CLOB DASH)

  from dba_users U

  CROSS JOIN (select 1 of the double connect by level < = 10);

  Thanks for any help you can offer.

  
  

  JM

  Hi jm,

  In the line of query results, did scroll all the way to the right, then click twice on the «...» "at the end of the line to open the cell editor?

  So again, who does not show all the XML, it may be a problem with the version of the ojdb6.jar in use (11.2.0.3 client or later is required), or whether or not the JDBC OCI/thickness is used.  Read the following discussion: retrieve XMLTYPE based on very slow saved schema

  Kind regards

  Gary

  SQL development team

• When I try to open the games on my Windows 7 system, I get the executable file to the games error message has stopped working.

  When I try to open the games on my Windows 7 system, I get the executable file to the games error message has stopped working. I tried several times to load the games following the indications for help but the games is not accessible. My computer is a remanufactured unit that was on the lease are there steps I can take to solve problems?  Thank you

  Original title: frustrated in New York

  The problem seems to be the igdumd64.dll:

  Fault Module name: igdumd64.dll
  Fault Module Version: 8.15.10.1749
  Timestamp of Module error: 4a5bdf54

  The igdumd64.dll is a component of the Intel graphics driver and seems to be an older version then try to update the graphic driver Intel.

  You could try the manufacturer of the computer for an updated driver, or use the following utility for intel to check a generic version:

  http://www.Intel.com/p/en_US/support/detect

• Ask help - please help me get the expected defined in a query result

  Dear all,

  Help with your suggestions and advice. Please see the bottom of the screenshots for the planned result sets.

  create table shift_dt 
  (name varchar2(20),
  shift_start date,
  shift_end date);
  
  insert into shift_dt values ('Brian',to_date('01-01-2015 09:10:00','dd-mm-yyyy hh24:mi:ss'), to_date('01-01-2015 22:10:00','dd-mm-yyyy hh24:mi:ss'));
  insert into shift_dt values ('Brian',to_date('02-01-2015 09:10:00','dd-mm-yyyy hh24:mi:ss'), to_date('04-01-2015 00:00:00','dd-mm-yyyy hh24:mi:ss'));
  insert into shift_dt values ('Brian',to_date('04-01-2015 00:00:00','dd-mm-yyyy hh24:mi:ss'), to_date('05-01-2015 15:20:00','dd-mm-yyyy hh24:mi:ss'));
  insert into shift_dt values ('Brian',to_date('06-01-2015 10:00:00','dd-mm-yyyy hh24:mi:ss'), to_date('06-01-2015 23:20:00','dd-mm-yyyy hh24:mi:ss'));
  insert into shift_dt values ('Brian',to_date('07-01-2015 11:00:00','dd-mm-yyyy hh24:mi:ss'), to_date('09-01-2015 00:00:00','dd-mm-yyyy hh24:mi:ss'));
  insert into shift_dt values ('Brian',to_date('09-01-2015 00:00:00','dd-mm-yyyy hh24:mi:ss'), to_date('10-01-2015 22:00:00','dd-mm-yyyy hh24:mi:ss'));
  
  select * from shift_dt;
  
  
  

  Select * from shift_dt;

  

  Expected result set: -.

  

  I compare date of shift_end with the next date of shift_start of the day. If the dates made 12 am (IE 00:00:00), then I ignore and display the next shift end date available as displayed in the screen game result. Please see the screen set outcome turned for more details.

  Please help get the results you want in the SQL query

  Kind regards

  Souls

  Hello

  Here's one way:

  WITH got_new_grp AS

  (

  SELECT name, shift_start, shift_end

  CASE

  WHEN shift_start = TRUNC (shift_start)

  AND shift_start = LAG (shift_end) OVER (ORDER BY shift_start)

  THEN 0

  1. OTHER

  END AS new_grp

  OF shift_dt

  )

  got_grp AS

  (

  SELECT name, shift_start, shift_end

  SUM (new_grp) OVER (ORDER BY shift_start) AS grp

  OF got_new_grp

  )

  SELECT MIN (name) DUNGEON (DENSE_RANK FIRST ORDER BY shift_start)

  As a name

  MIN (shift_start) AS shift_start

  MAX (shift_end) AS shift_end

  OF got_grp

  GROUP BY grp

  ORDER BY shift_start

  ;

  Output (from the full sample data):

  NAME SHIFT_START SHIFT_END

  -------------------- ---------------- ----------------

  01/01/2015 Brian 09:10 01/01/2015 22:10

  Brian 02/01/2015 09:10 01/05/2015 15:20

  Brian 06/01/2015 10:00 01/06/2015 23:20

  Brian 07/01/2015 11:00 10/01/2015 22:00

  Brian 01/02/2015 15:00 02/02/2015 00:00

  Brian 02/02/2015 11:00 02/02/2015 17:00

  Brian 03/02/2015 00:00 03/02/2015 08:00

  Brian 02/05/2015 15:30 06/02/2015 07:30

  Brian 07/02/2015 23:30 10/02/2015 00:30

  I guess that shift_start is unique.

  It's finally a GROUP BY problem: we want to show the first shift_start and the last shfit_end of a group of 1 or more lines.  The tricky part is to identify the groups.  If I understand the problem, line X is grouped with the previous line X-1 if shift_start on the X line is midnight and is equal to shift_end on line X-1.  The above query uses the LAG analytic to see if each line begins a new group or not and the analytic function SUM to see how many groups have already begun (and therefore, which group each line entry belongs.)

  I still don't understand why you 'Corrected name of Anne in Brian' and not vice versa.  I guess the name to display in each group is the name of the first row in the Group (i.e. the line with the shift_start earlier).