Help with the query to return the results of the group in the table?

Hello
Im a total noob, so please be nice...!

I'm looking around a table contains a column of WORD and a WORD_TYPE_ID column.
Words can have the same type_id.

What I'm trying to do is to write a query that will return the longest word for each word_type_id.
I tried for hours to get it and everything seems to get is two error messages or just the longest word in the whole WORD column.

Is the furthest I can get before things break down...

Select Word
table
where
Length (Word) =
(
Select
Max (length (Word))
table
)

Any help on this or if I could be pointed in the right direction it would be greatly appreciated.

Thank you

Hello

Welcome to the forum!

Here's one way:

SELECT    word_type_id
,       MIN (word) KEEP (DENSE_RANK LAST ORDDER BY LENGTH (word))     AS longest_word
FROM       table_x
GROUP BY  word_type_id;

If there be a tie in some word_type_id (i.e. 2 or more words have exactly the same length, which is the longest in this group) the expression above will return the first one alphabetically. (This is what means here MIN.)

Published by: Frank Kulash, 11 August 2009 13:56

You almost had it.
As you have noticed, you get the longest line across the table. This is because your subquery was watching the entire table.
If you to correlate the subquery to the row in the main table, as shown below, you can get the longest word in each group:

select  word
from     table     m                              -- m for main
where      length (word) = (
                            select  max (length(word))
               from     table
               where     word_type_id  = m.word_type_id     -- New
               );

Tags: Database

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    '& State',

    '& zip'

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    number of v_issuecount;

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    end reader_bookissue;

    Start

    Select book_name, b.book_id avl_now_flag v_book_name, v_book_id, v_avl_now_flag of the book b, book_availability b where b.book_id = ba.book_id and ba.book_id = p_book_id;

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    Start

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    commit;

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    number of v_extradays;

    number of v_latefee_total;

    number of v_latefee_per_book;

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    p_latefee_total: = v_latefee_total;

    dbms_output.put_line ('The total AMT for not returned books' | p_latefee_total);

    end late_fee;

    end lib_01;

    Hello

    I checked the first 10 lines after the beginning and I could count already several errors.

    Is it an exercise or a real code, you must provide?

    Kind regards.

    Alberto

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