need help with the query, thx
HelloI need a little help with the query I have to write;
the table has 4 columns:
col1 col2 col3 col4
emp_name empl_id salary year
content of data:
col1 col2 col3 col4
smith 12 1200 1999
smith 12 1340 2000
smith 12 1500 2001
jones 13 1550 1999
jones 13 1600 2000
aron 14 1200 2002
what I am asking is the following result: salary according to the latest available yeari.e.
smith 12 1500 2001
jones 13 1600 2000
aron 14 1200 2002
ID appreciate some guidance on how to achieveThank you
Rgds
select *from
(select col1, col2,col3, col4,row_number() over(partition by col1 order by col4 desc) rn from
) where rn=1
Tags: Database
Similar Questions
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Need help with the query (transpose)
Hello experts, please help here - 11 g Oracle, attribute APA APB are fixed values and can be hard coded in query
Need to transpose these data. Max(decode.. perd les données en sortie à cause de la condition de Max.)
Entry:
Name | Attribute | Value
A1 APP 10
A1 PDB 11
A1 APA 20
A1 PDB 21
A2 BPA 13
A2 BPB 14
Expected results:
Name AttVal1 AttVal2
A1 10 11
13 14 A2
20 21 A1
Hello
Here's one way:
WITH relevant_columns AS
(
SELECT name
value
CASE
WHEN the attribute ("APA", "BPA") THEN 1
WHEN the attribute ("PDB", "BPB") THEN 2
END AS c_num
ROW_NUMBER () (PARTITION BY NAME, attirbute
Value of ORDER BY
) AS r_num
FROM table_x
)
SELECT name, attval1, attval2
OF relevant_columns
PIVOT (MAX (value)
FOR c_num IN (1 AS attval1
2 UNDER attval2
)
)
ORDER BY r_num, name
;
If you would care to post CREATE TABLE and INSERT statements for your sample data, and then I could test this.
Why do you want to
NAME ATTVAL1 ATTVAL2
---- ------- -------
A1 10 11
20 21 A1
in the results, rather than
NAME ATTVAL1 ATTVAL2
---- ------- -------
10 21 A1
20 11-A1
? You would be satisfied to one or the other?
Depending on your answer, you may need to modify the analytical ORDER BY clause in the ROW_NUMBER function.
-
Need help with the query. Help, please
Hey everyone, need your help. Thank you in advance. In my view, there is function Pivot. Just do not know how to use this function. I have the query that works. The result is:
11-111-1111 Vlad 16505 01/04/2013 5 August 13 dental plan pre-tax amount 29,65
11-111-1111 Vlad 16505 01/04/2013 dental pre-tax 5 August 13 Plan level EE + SP
11-111-1111 16505 Vlad 01/04/2013 5 August 13 pre-tax Option TOP dental plan
11-111-1111 Vlad 16505 01/04/2013 5 August 13 pre-tax dental care plan pay the value
11-111-1111 16505 Vlad 01/04/2013 dental pre-tax 5 August 13 Plan period Type
11-111-1111 Vlad 16505 01/04/2013 amount pre-tax medical Plan of 5 August 13 149
11-111-1111 Vlad 16505 01/04/2013 5 August 13 pre-tax Medical Plan level EE + SP
11-111-1111 Vlad 16505 01/04/2013 5 August 13 pre-tax Plan medical Option MED
11-111-1111 Vlad 16505 01/04/2013 5 August 13 plan pre-tax pay value
11-111-1111 16505 Vlad 01/04/2013 5 August 13 pre-tax Medical Plan period Type
11-111-1111 Vlad 16505 01/04/2013 5 August 13 pre-tax Plan PPO medical Plan
11-111-1111 Vlad 16505 01/04/2013 5 August 13 Vision Plan amount 5.94 pre-tax
But I need the result to be
Amount of SSN ID name item level Option PayValue period Type
11-111-1111 Vlad 16505 01/04/2013 null null high of 5 August 13 pre-tax Dental Plan 29,65 EE + SP
11-111-1111 Vlad 16505 01/04/2013 null null MED 5 August 13 149 medical plan pre-tax EE + SP
11-111-1111 Vlad 16505 01/04/2013 Vision Plan before taxes of 5 August 13
Select distinct
' 11-111-1111 "as ssn,
WOMEN'S WEAR. Employee_number,
"Vlad" as EMPLOYEE_FULL_NAME,
TO_CHAR (papf.start_date, "MM/DD/YYYY") as Date_Of_Hire
a.effective_start_date,
PETF.element_name,
pivf. Name,
peevf.screen_entry_valueOf
PER_all_PEOPLE_F women's wear
per_assignments_f A
pay_element_types_f petf
pay_element_links_f pelf
PAY_ELEMENT_ENTRIES_F penf
PAY_ELEMENT_ENTRY_VALUES_F peevf
pay_input_values_f pivf
WHERE
PETF.element_name ('Dental Plan before taxes', 'Medical Plan before taxes', "Vision Plan before taxes")
and petf. ELEMENT_TYPE_ID = pelf. ELEMENT_TYPE_ID
and (trunc (sysdate) BETWEEN pelf. EFFECTIVE_START_DATE AND pelf. EFFECTIVE_END_DATE)
and (pelf. ELEMENT_LINK_ID = penf. ELEMENT_LINK_ID and a.assignment_id = penf. ASSIGNMENT_ID)
and (trunc (sysdate) BETWEEN penf. EFFECTIVE_START_DATE AND penf. EFFECTIVE_END_DATE)
and penf. ELEMENT_ENTRY_ID = peevf. ELEMENT_ENTRY_ID
and peevf. INPUT_VALUE_ID = pivf. INPUT_VALUE_ID
AND papf.employee_number IS NOT NULL
AND A.assignment_type = 'E '.
AND A.person_id = papf.person_id
and papf.effective_end_date > sysdate
and a.effective_end_date > sysdate
and (trunc (sysdate) BETWEEN women's wear. EFFECTIVE_START_DATE AND women's wear. EFFECTIVE_END_DATE)
and a.effective_start_date = (select MAX (effective_start_date) from PER_ASSIGNMENTS_f where assignment_id = a.assignment_id)
and a.assignment_id = 42643
and a.assignment_status_type_id = '1'
order of petf.element_name;Change with your query
SELECT * FROM (select distinct)
' 11-111-1111 "as ssn,
WOMEN'S WEAR. Employee_number,
"Vlad" as employee_full_name,
TO_CHAR (papf.start_date, "MM/DD/YYYY") as date_of_hire
a.effective_start_date,
PETF.element_name,
pivf. Name,
peevf.screen_entry_value
Of
PER_all_PEOPLE_F women's wear
per_assignments_f A
pay_element_types_f petf
pay_element_links_f pelf
PAY_ELEMENT_ENTRIES_F penf
PAY_ELEMENT_ENTRY_VALUES_F peevf
pay_input_values_f pivf
WHERE
PETF.element_name ('Dental Plan before taxes', 'Medical Plan before taxes', "Vision Plan before taxes")
and petf. ELEMENT_TYPE_ID = pelf. ELEMENT_TYPE_ID
and (trunc (sysdate) BETWEEN pelf. EFFECTIVE_START_DATE AND pelf. EFFECTIVE_END_DATE)
and (pelf. ELEMENT_LINK_ID = penf. ELEMENT_LINK_ID and a.assignment_id = penf. ASSIGNMENT_ID)
and (trunc (sysdate) BETWEEN penf. EFFECTIVE_START_DATE AND penf. EFFECTIVE_END_DATE)
and penf. ELEMENT_ENTRY_ID = peevf. ELEMENT_ENTRY_ID
and peevf. INPUT_VALUE_ID = pivf. INPUT_VALUE_ID
AND papf.employee_number IS NOT NULL
AND A.assignment_type = 'E '.
AND A.person_id = papf.person_id
and papf.effective_end_date > sysdate
and a.effective_end_date > sysdate
and (trunc (sysdate) BETWEEN women's wear. EFFECTIVE_START_DATE AND women's wear. EFFECTIVE_END_DATE)
and a.effective_start_date = (select MAX (effective_start_date) from PER_ASSIGNMENTS_f where assignment_id = a.assignment_id)
and a.assignment_id = 42643
and a.assignment_status_type_id = '1')
PIVOT (MAX (screen_entry_value) FOR (name) TO ("Amount" AS 'Amount', 'level' AS 'level', 'Option High' AS 'High Option', 'Pay the value' AS 'Value to pay', 'Period of Type' AS 'Type period'))
order by element_name;
(GOLD)
SELECT ssn,
Employee_number,
employee_full_name,
date_of_hire,
effective_start_date,
element_name,
Max (decode (Name, 'Amount', screen_entry_value)) 'amount. "
Max (decode (Name, 'Level', screen_entry_value)) 'level ',.
MAX (DECODE (name, "High Option", screen_entry_value)) "High Option",
MAX (DECODE (name, 'Value of pay', screen_entry_value)) 'value of pay. "
MAX (DECODE (name, 'Period Type', screen_entry_value)) 'period of Type '.
FROM (select distinct)
' 11-111-1111 "as ssn,
WOMEN'S WEAR. Employee_number,
"Vlad" as employee_full_name,
TO_CHAR (papf.start_date, "MM/DD/YYYY") as date_of_hire
a.effective_start_date,
PETF.element_name,
pivf. Name,
peevf.screen_entry_value
Of
PER_all_PEOPLE_F women's wear
per_assignments_f A
pay_element_types_f petf
pay_element_links_f pelf
PAY_ELEMENT_ENTRIES_F penf
PAY_ELEMENT_ENTRY_VALUES_F peevf
pay_input_values_f pivf
WHERE
PETF.element_name ('Dental Plan before taxes', 'Medical Plan before taxes', "Vision Plan before taxes")
and petf. ELEMENT_TYPE_ID = pelf. ELEMENT_TYPE_ID
and (trunc (sysdate) BETWEEN pelf. EFFECTIVE_START_DATE AND pelf. EFFECTIVE_END_DATE)
and (pelf. ELEMENT_LINK_ID = penf. ELEMENT_LINK_ID and a.assignment_id = penf. ASSIGNMENT_ID)
and (trunc (sysdate) BETWEEN penf. EFFECTIVE_START_DATE AND penf. EFFECTIVE_END_DATE)
and penf. ELEMENT_ENTRY_ID = peevf. ELEMENT_ENTRY_ID
and peevf. INPUT_VALUE_ID = pivf. INPUT_VALUE_ID
AND papf.employee_number IS NOT NULL
AND A.assignment_type = 'E '.
AND A.person_id = papf.person_id
and papf.effective_end_date > sysdate
and a.effective_end_date > sysdate
and (trunc (sysdate) BETWEEN women's wear. EFFECTIVE_START_DATE AND women's wear. EFFECTIVE_END_DATE)
and a.effective_start_date = (select MAX (effective_start_date) from PER_ASSIGNMENTS_f where assignment_id = a.assignment_id)
and a.assignment_id = 42643
and a.assignment_status_type_id = '1')
GROUP BY ssn, employee_number, employee_full_name, date_of_hire, effective_start_date, NOM_ELEMENT
order by element_name;
-
Need help with the query to get the County
Hello
Oracle 10 g 2 10.2.0.3 - 64 bit
I want back the number of accounts with two different types of funds (say A and B). Some accounts hold only one of the two funds, and some support both. I want to get the counts like this:
- account held funds - has only
- accounts holding funds-B only
- accounts holding the Fund-A and B funds
Here is what I started with but need assistance to meet the requirement above:
select count(distinct acct.bkoff_acct_no ) accounts_holding_fund_A from xe_account acct, xec_tal_investment_mandate iman, xec_tal_asset_allocation alloc, xe_benchmark bmark, xe_benchmark_usage bu, xe_object_description xod, xec_asset_class cls where iman.mandate_status_cd='A' and cls.asset_class_cd = alloc.asset_class_cd and iman.mandate_id = alloc.mandate_id and acct.account_id = iman.object_id and iman.object_type_cd = 'ACCT' and iman.mandate_id = xod.object_id and xod.field_nm='XEC_TAL_INVESTMENT_MANDATE.COMMENT_TXT' and xod.language_cd = 'E' and acct.acct_status_cd = 'O' and bu.object_type_cd(+) = 'TMAA' and bu.object_id(+) = alloc.asset_allocation_id and bmark.benchmark_id(+) = bu.benchmark_id and alloc.resp_txt like '%fund-A%'
And suppose that the Fund-B has resp_txt like ' % of Fund-B»
Please suggest.
Concerning
Hello
Here is another way, it is easier to adapt to different jobs and different numbers of jobs:
WITH got_distinct_jobs AS
(
SELECT DISTINCT deptno, job
FROM scott.emp
WHERE job IN ("ANALYST", "CLERKS") - or what
)
got_job_list AS
(
SELECT LISTAGG (job, ",") THE Group (ORDER BY work) AS job_list
OF got_distinct_jobs
GROUP BY deptno
)
SELECT job_list
COUNT (*) AS num_departments
OF got_job_list
GROUP BY job_list
;
This shows all the combinations of the jobs listed in the WHERE clause of got_distinct_jobs. You don't need to change anything else in the query. There may be any number of jobs.
Output:
JOB_LIST NUM_DEPARTMENTS
------------------------------ ---------------
CLERK 2
ANALYST, CLERK 1
-
Need help with the query using the aggregation
If I have a table, defined as follows:
CREATE TABLE range_test
(
range_id NUMBER (20) NOT NULL,
rank of char (1) NOT NULL,
lower_bound_of_range NUMBER (5.2) NOT NULL,
upper_bound_of_range NUMBER (5.2) NOT NULL,
received_date_time_stamp SYSTIMESTAMP NOT NULL DEFAULT TIMESTAMP
);
And I wanted to query the table to find the range associated with the last line inserted for each 'class' (for example 'A', 'B', 'C', etc.), how would I go about this?
I want something like the following, but I know that it will not work right:
SELECT
grade,
lower_bounding_of_range,
upper_bounding_of_range,
Max (received_date_time_stamp)
Of
range_test GROUP BY received_date_time_stamp;
Thanks for your help... I am frustrated with this one and I think that it should be possible without having to use the PL/SQL (i.e. the functions of SQL aggregation or subqueries should work).Perhaps something along the lines of...
SQL> ed Wrote file afiedt.buf 1 select deptno, empno, ename, hiredate 2 from emp 3* order by deptno, empno SQL> / DEPTNO EMPNO ENAME HIREDATE ---------- ---------- ---------- -------------------- 10 7782 CLARK 09-JUN-1981 00:00:00 10 7839 KING 17-NOV-1981 00:00:00 10 7934 MILLER 23-JAN-1982 00:00:00 20 7369 SMITH 17-DEC-1980 00:00:00 20 7566 JONES 02-APR-1981 00:00:00 20 7788 SCOTT 19-APR-1987 00:00:00 20 7876 ADAMS 23-MAY-1987 00:00:00 20 7902 FORD 03-DEC-1981 00:00:00 30 7499 ALLEN 20-FEB-1981 00:00:00 30 7521 WARD 22-FEB-1981 00:00:00 30 7654 MARTIN 28-SEP-1981 00:00:00 30 7698 BLAKE 01-MAY-1981 00:00:00 30 7844 TURNER 08-SEP-1981 00:00:00 30 7900 JAMES 03-DEC-1981 00:00:00 14 rows selected. SQL> ed Wrote file afiedt.buf 1 select deptno, empno, ename, hiredate 2 from ( 3 select deptno, empno, ename, hiredate 4 ,row_number() over (partition by deptno order by hiredate desc) as rn 5 from emp 6 ) 7 where rn = 1 8* order by deptno, empno SQL> / DEPTNO EMPNO ENAME HIREDATE ---------- ---------- ---------- -------------------- 10 7934 MILLER 23-JAN-1982 00:00:00 20 7876 ADAMS 23-MAY-1987 00:00:00 30 7900 JAMES 03-DEC-1981 00:00:00 SQL>
-
need help with the query: (Frank)
Hi Frank,.
I have the oracle 8 database.
I have the following table with the data structure:
TABLE P (PID, PNAME, COLOR)
PRIMARY KEY: PID
CAT TABLE (SID, PID, COST)PID Pname Color p1........... Red P2................. green p3............... blue p4 .................. red
KEY: SID MAIN + PID
KEY REFERENCE: SID REFERENCE S.SID
PID P.PID REFERENCES
now my question is:Sid Pid COst.... S1 P1 S2 P2 S3 P3 S1 P4 S2 p1 S3 p1
I want to find the SIDS of suppliers that provide a red and a green part
for this I used the following query, but it gives the result worng...
can help me please in this way to get this...
select sid from cat where pid in (select pid from p where color= 'red' union select pid from p where color = 'gren') group by sid having count(pid) >= 2
Hello
Jojo wrote:
Hi Frank,.It would be nice if someone with a different name helped you? Do not restrict yourself by addressing someone in particular in your subject line or the first message.
I have the oracle 8 database.
I have the following table with the data structure:TABLE P (PID, PNAME, COLOR)
PRIMARY KEY: PIDPID Pname Color p1........... Red P2................. green p3............... blue p4 .................. red
CAT TABLE (SID, PID, COST)
KEY: SID MAIN + PID
KEY REFERENCE: SID REFERENCE S.SID
PID P.PID REFERENCESSid Pid COst.... S1 P1 S2 P2 S3 P3 S1 P4 S2 p1 S3 p1
now my question is:
I want to find the SIDS of suppliers that provide a red and a green partfor this I used the following query, but it gives the result worng...
can help me please in this way to get this...
select sid from cat where pid in (select pid from p where color= 'red' union select pid from p where color = 'gren') group by sid having count(pid) >= 2
You don't like what is the number of lines with a pid; If you had 20 rows all said 'p1', that would be good enough. The number of distinct colors of the whole ('red', 'green') is what is important.
Avoid the UNION when there is a simple alternative. The UNION tends to be slow.You can use a join instead, like this:
SELECT c.sid FROM cat c , p WHERE p.pid = c.pid AND p.color IN ('red', 'green') GROUP BY c.sid HAVING COUNT (DISTINCT p.color) = 2 ;
If you would care to post CREATE TABLE and INSERT statements for the sample data and the results that you want from this data, then I could test this.
Published by: Frank Kulash, January 10, 2011 15:25
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Need help with the query string manipulation
Hello
With the help of 10.1.0.4.2
Given a table called PREFIX_CODES that contains a column called PREFIX_CODE
with the following data:
PREFIX_CODE - VARCHAR2 (20)
-------------------
AAA
BENAMER
CARTER
and another table called SUBSCRIBERS with a column called SUBSCRIBER_ID
with the following data:
SUBSCRIBER_ID - VARCHAR2 (30)
---------------------
BBBB-123456
AAA-444444
DD-2222222
EEEE-888888
Is there a query that will pull all the SUBSCRIBER_ID that begin with
each of the PREFIX_CODES? The following query is not valid, but it
This will give you an idea of what I'm trying to do:
SELECT SUBSCRIBER_ID
SUBSCRIBERS
WHERE AS SUBSCRIBER_ID (SELECT PREFIX_CODE |) » %'
OF PREFIX_CODES)
Using the data from above, I would like that the query to return:
BBBB-123456
AAA-444444
Thanks for your help!Hello
Welcome to the forum!
You were on the right track. To find if a given subscriber corresponds to any prefix_code, you can do an EXISTS subquery:
SELECT subscriber_id FROM subsribers s WHERE EXISTS ( SELECT NULL FROM prefix_codes WHERE s.subscriber_id LIKE prefix_code || '%' ) ;
This will tell you if at least a prefix code. It won't tell you exactly how many, or what they were.
Your message, I'm guessing that there may be more than one, and you can deduct the subscriber_id itself, then the above query should work for you. -
Need help with the query logic
I have 2 tables.
Table Tb1:
THE PLAN_ID PARENT_PLAN_ID ARGUMENT
Value null P1
P1 P2
P3 P2
P4 P1
Table tb2:
THE PLAN_ID ACTIVITY_ID PICKING ARGUMENT
P2 A1 5000
P2 A2 5000
P2 A3 5000
P3 A1 10000
P3 A2 10000
P4 A1 4000
I need to find the sum of the value of reduction of the workforce for each PLAN_ID which is parent root. In the case above, this is the argument PLAN_ID P1 (WHERE PARENT_PLAN_ID IS NULL). Please note that the value of the downsizing is repeated in the tb2 table. For example, the PLAN_ID P2 argument, the value of the downsizing is 5000 and not 5000 + 5000 + 5000.
The result of the output for the above data must be
THE ARGUMENT PLAN_ID DRAWDOWN
P1 19000
Published by: user10566312 on October 30, 2012 12:30with t as ( select t1.plan_id,t1.parent_plan_id,max(t2.DRAWDOWN) DRAWDOWN from tb1 t1,tb2 t2 where t1.plan_id = t2.plan_id(+) group by t1.plan_id,t1.parent_plan_id ) select plan_id,sum(drawdown) drawdown from( select connect_by_root plan_id as plan_id, nvl(DRAWDOWN,0) DRAWDOWN from t start with parent_plan_id is null connect by parent_plan_id = prior plan_id ) group by plan_id ; PLAN_ID DRAWDOWN ------- -------- P1 19000
Published by: JAC on October 30, 2012 13:23
-
NEED HELP WITH THE QUERY, NEED MORE RECENT FILE ONLY
Hi all
That is,
I have an assignment I need to find agents that allow players to break the rules.
So far, I have 41 results, in which there are 4 principles and 24 footballers and football player even beat more than one rule or the rule more than once.
What I need now is to make arrangements so that every footballer appears once n matter how many times they have broken the rules.
I have
SELECT
t.transfer_time | ' ' || a.first_name | ' ' || a.last_name | ' ' || f.first_name | ' ' || f.last_name | ' ' || f.footballer_id | ' ' || t.transfer_id
Of
agents a, t transfers, footballers f, footballers_fees fo
WHERE
a.agent_id = t.broker_id
AND
t.footballer_id = f.footballer_id
AND
f.footballer_id = fo.footballer_id
AND
(RULE 1 BROKEN AND RULE 2 BROKEN
OR
RULE 1 BROKEN AND ARTICLE 2 DOES NOT DECOMPOSE
OR
RULE 1 DOES NOT DECOMPOSE AND RULE 2 BROKEN)
GROUP BY
t.transfer_time | ' ' || a.first_name | ' ' || a.last_name | ' ' || f.first_name | ' ' || f.last_name | ' ' || f.footballer_id | ' ' || t.transfer_id
ORDER BY
t.transfer_time | ' ' || a.first_name | ' ' || a.last_name | ' ' || f.first_name | ' ' || f.last_name | ' ' || f.footballer_id | ' ' || t.transfer_id
;
(I did not type the SQL code to rules 1 and 2 but I know it works)
Now, I need not to show that every footballer once they broke rule and more than once or not.
I was looking at the screen nearly enough hours 10 and any help or ideas would be greatly appreciated
Thank you all :)Hello
Welcome to the forum!
Whenever you have a problem, please post a small example of data (CREATE TABLE and INSERT statements) so that people who want to help you can recreate the problem and test their ideas. You don't have to display a large amount of data. In this case, it seems that 2 to 10 lines for each table could give a good picture of the problem.
After the results that you want samples fropm, and explain how you get those resulting from these data.
Always tell what version of Oracle you are using.The ideal outcome would be just what you '; Re I get now, but with some deleted rows and only 1 line by left footballer? If so, do a subquery on the original query, and then add somehting like
, ROW_NUMBER () OVER (PARTITION BY f.footballer_id ORDER BY NULL) AS r_num
in the SELECT clause.
then, in the main query, display only linesWHERE r_num = 1
ROW_NUMBER requires an ORDER byclause of analytics. If you ORDER BY a constant (e.g. NULL) then what line gets number 1 will be arbitrary. If you care who lines for a given player is numbered 1 (and therefore included in the final output), then adjust the analytical ORDER BY clause. (You the title mentions "most recent record only", so if the dt column indicates whether a line is "newer" than another, you can "ORDER BY dt DESC".)
I know this response is vague in places. Without a concrete example (CREATE TABLE and instructions INSERT for examples of data and outcomes from these data), that's the best I can do.
-
Need help with the query using the AVG function
First post here.
I am a student taking a SQL class and I can't find a query.
I think I'm close to get it, but I can not quite all the way there.
Three tables are involved in this problem. Here is a list of the tables and the areas concerned:
Problem:orders table: order# shipstate orderitems table: order# isbn quantity (How many copies of book purchased on that order) books table: isbn retail (retail price of book)
I want to get an average of "total amount" by shipstate.
For example, in these tables, there are 8 records of the State of Florida.
However, there are only 5 unique order # for this State.
The amount of detail * quantity for these 8 disks (or 5 orders) is $345,10
Now to get my average $345,10 should be divided by 5. (number of unique commands)
In the following query it divides this $345,10 8. (number of records)
How to make this request to divide by the number of unique order # rather than the number of records?
According to me, once I get this part down, I can understand the rest of the problem.SELECT shipstate, AVG(quantity * retail) FROM orders JOIN orderitems USING (order#) JOIN books USING (isbn) GROUP BY shipstate HAVING SUM(quantity * retail) =ANY (SELECT SUM(quantity * retail) FROM books JOIN orderitems USING (isbn) JOIN orders USING (order#) GROUP BY shipstate)
The end result, I need, is to find all the individual commands that have a "total amount due" that is greater than the 'average amount due' for this state of clients.
Any help, suggestions or comments welcome.
MattYour average take into account the shipstate (8 disks), you can do that for the expected results.
With some examples of input data it would be easier, but here a try:SELECT shipstate, sum(quantity * retail)/count(distinct order#) FROM orders JOIN orderitems USING (order#) JOIN books USING (isbn) GROUP BY shipstate;
Nicolas.
delete the alias
Edited by: N. Gasparotto on October 3, 2008 19:28 -
Need help with the query of the Recordset
I need some major help please. Getting really frustrated here. My search page, if I do not fill in all fields and press SUBMIT, all records in the Recordset are displayed. Why? I have a default value ".". There should be no match. I don't understand. Can someone explain it to me?
Help me obi - wan!I've recoded the entire page and now I want to. What I found myself doing this the $_GET at the beginning of the page and then for my request, I changed it "entered value". I think I can be on the right track.
-
Need help with the query and output
I have a table that contains a list of property and each an asset contains a category field, each an asset can have several categories assigned, then the category column is filled in a list (for example, 14, 16, 17, 19).
The values are based on a table of categories using the primary key as a reference number (for example 14 = keyboards, 16 = Trackballs, etc..)
I tried to understand how the power of categories so that when the category is displayed, the list will appear under the name of the category as opposed to the non referenced.
example:
< name cfquery = "qIndex" datasource = "#appDSN #" >
SELECT Asset.Reference, Asset.AssetName, Asset.Category
Assets
WHERE category LIKE ' %#URL. Category #% '
< / cfquery >
< cfoutput query = "qIndex" >
#Asset.Reference # < br / >
#Asset.AssetName # < br / >
#Asset.Category #.
< / cfoutput >
Exhibition:
AD_987738
Keyboard XYZ
11, 14, 17, 18
Table for categories are:
CatID = primary key
Category = category name
CatImage = header Image
Thanks for any help.Finally figured this out. Had to insert an intermediate query within the output to filter each record, otherwise he was out the results of the first record only and repeat.
SELECT *.
Assets
WHERE category LIKE ' %#URL. Category #% '
SELECT the CATEGORY, AssetID
Assets
WHERE assetID = #qIndex.AssetID #.
Category category WHERE CatID IN (#catids #)
Category:#qCat.Category #,
#qIndex.Asset #.
#qIndex.Reference #.
Thanks again for the help.
Paul -
Oracle Version: 11.2.0.2.0
I need assistance with the output of the query. Here is the table.
With Tbl_Nm as
(
Select 'ABC1' SYSTEM_ID, REGION 'US', 'CHI' SUB_REGION 4000 BALANCE, to_date('1-JUN-2012 10:45:00 am', 'dd-mon-yyyy hh:mi:ss am') LAST_UPD_TIME, 'A' FLAG of union double all the
Select 'PQR2', 'UK', 'LN', 2000, To_Date('1-JUL-2012 10:46:00 am', 'dd-mon-yyyy hh:mi:ss am'), has ' starting from dual Union All
Select 'ABC1', 'IND","MAMA", 3500, To_Date('1-AUG-2012 11:47:00 am', 'dd-mon-yyyy hh:mi:ss am'), 'A' from dual Union All
Select "LMN3", "US", "NJ", 2500, To_Date('1-SEP-2012 09:49:00 am', 'dd-mon-yyyy hh:mi:ss am'), 'A' from dual Union All
Select "PQR2", "UK", "MC", 2600, To_Date('1-OCT-2012 04:45:00 am', 'dd-mon-yyyy hh:mi:ss am'), 'A' from dual Union All
Select 'ABC1', 'US', 'NY', 3200, To_Date('1-OCT-2012 06:45:00 am', 'dd-mon-yyyy hh:mi:ss am'), has ' starting from dual Union All
Select "LMN3", "UK", "BT", 2400, To_Date('1-NOV-2012 07:45:00 am', 'dd-mon-yyyy hh:mi:ss am'), has ' From Dual
)
Select * from tbl_nm
I need the output below.
PQR2 UK MC 2600 1 OCTOBER 2012 04:45
ABC1 US NY 3500 October 1, 2012 06:45
LMN3 UK BT 2500 November 1, 2012 07:45
The need the disc according to this system_id flagged as "A". But if the last disc of 'd' then it must show that the amount, but the file should be displayed in 'A '.
I've tried a few and got stuck. Help, please. Not able to get a balance '.
This question is a bit similar to needing help with a query result
With Tbl_Nm as
(
Select 'ABC1' System_Id, region 'US', 'CHI' Sub_Region, 4000 balance, To_Date('1-JUN-2012 10:45:00 am', 'dd-mon-yyyy hh:mi:ss am') Last_Upd_Time, 'A' flag of double Union All
Select 'PQR2', 'UK', 'LN', 2000, To_Date('1-JUL-2012 10:46:00 am', 'dd-mon-yyyy hh:mi:ss am'), has ' starting from dual Union All
Select 'ABC1', 'IND","MAMA", 3500, To_Date('1-AUG-2012 11:47:00 am', 'dd-mon-yyyy hh:mi:ss am'), 'A' from dual Union All
Select "LMN3", "US", "NJ", 2500, To_Date('1-SEP-2012 09:49:00 am', 'dd-mon-yyyy hh:mi:ss am'), 'A' from dual Union All
Select "PQR2", "UK", "MC", 2600, To_Date('1-OCT-2012 04:45:00 am', 'dd-mon-yyyy hh:mi:ss am'), 'A' from dual Union All
Select 'ABC1', 'US', 'NY', 3200, To_Date('1-OCT-2012 06:45:00 am', 'dd-mon-yyyy hh:mi:ss am'), has ' starting from dual Union All
Select "LMN3", "UK", "BT", 2400, To_Date('1-NOV-2012 07:45:00 am', 'dd-mon-yyyy hh:mi:ss am'), has ' From Dual
)
Select System_Id, region, Sub_Region, Balance, Last_Upd_Time of Tbl_Nm T1
where t1. Last_Upd_Time = (select max (Last_Upd_Time) in the Tbl_Nm T2 where T1.) SYSTEM_ID = T2. SYSTEM_ID)
So maybe you'd then
ORDER BY DECODE(flag,'D',9,1) ASC...
to get the Ds at the end of the list.
or
ORDER BY CASE WHAT flag = has ' (your other filters) AND then 9 or 1 end CSA,...
HTH
-
Need help with the installation of an adapter of graphics Super Palit GeForce 9500GT - 512 MB - DDR2 SDRAM in a M2N68 motherboard (narra6). Should I disable the onboard graphics in the bios? When the card is installed, no VGA work outs and the PC does not start. Checked and recontroler implementation of the card in the PCI slot. PC is a desktop HP G5200uk PC. Windows 7 operating system.
Hello
The link below is a guige to install a video card in your Pc. In particular, it seems that you will have to perhaps specify the location of the new card in the bios and save this change before you install the new card - see step 4 in the guide on the link below. If your new card fits into the PCI Express x 16 slot, you will need to define PCI Express in the bios and save the changes.
http://support.HP.com/us-en/document/c01700855
Kind regards
DP - K
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