Hexadecimal format string

Similar Questions

• Hexadecimal, binary string.

  I have 33 bytes of data in hexadecimal format and do not know how he analysis of eleven pieces of 24 bits of binary data. I tried different configurations of hexadecimal string, number and Type of Casting, but have not yet been successful. I would like a table with 11 elements, each consisting of 24 - bit binary.

  The entry is formatted as such:

  (Hexadecimal display)
  4445 4647 4849 4A4B 4C4D 5051 5253 5455 5657 5859 5A5B 5C5D 5E5F 6061 AAAB AC 4E4F

  Please let me know if more info is needed, thank you for the help!

  There is not a 24-bit data type, so you will need to store them U32. You need to "pad" of your data so that it can fit.

  

• format string IF (always kHz)

  Hello

  I'm reading values from rates to sample different RF bands DBL and using the value to create a file header to store binary data complex 32IQ to the file. I use the format based on string to do, but I still want to be represented in kHz, the sampling frequency and I have not thought of a way to force it is always the case. I use a format string of %.3p which, for sampling rate as 13125 and 400000 he returns 13,125 k and 400,000 k respectively, and that's what I want. However, one of my groups is 3750000 Hz and the format to a string returns Mr. 3,750, I would come back 3750,000 k instead. Does anyone have any ideas on how I might accomplish this?

  Thank you

  Tim

  If you divide the value by 1000 dbl and then apply the format to a string with the specifier %.3f you the kHz value.

  Ben

• formatted string

  I have different strings in my project, for example:

  12.4432615352312

  I want that all these channels have 2 decimal places, so 12.44; How can I do this? I was looking for 'Format value function' and also 'format as string' (format string), but without success.

  Thank you

  Here's a very easy way

  

  Although there is probably a method using reg expressions without the intermidiatry changing double.

  Craig

• Digital format in 0.000E + 0 in format string

  How to format a digital DBL double 0.000E + 0-shaped, functional screws?

  Do I need a REGEX for string format?

  Thank you

  Alan

  saintalan94 wrote:

  How to format a digital DBL double 0.000E + 0-shaped, functional screws?

  You just need 'in Format string' function with the correct entry of STRING of FORMAT .

  

• BUG: Date/Time Format string with %D in the format string crashes LabVIEW

  Do %D in the format string 'Format string DateTime' blocks LabVIEW 2009 SP1, as shown in this code snippet.  Should I use instead of %D %d but an incorrect format string should not crash LabVIEW.

  

  Fixed in 2010.

• chain number by "scan value" format string "%.3f" doesn'work

  I had a little problem.

  "To convert a string to a number, I use the function"scan value"with '%.3f' for the ' format string"connector. I would get a 3 digit number. But this doesn't work with the parameter "%.3f.

  Thank you.

  Please check the syntax of using LV Format specifier. There is a table that describes the purpose of each specifier. When you read in the description "when you use a function in shape", the specifier is applied to the number-> string, when you read "when you use a sweep feature", the specifier applies to the String-> number. The syntax of width element applies to both situations, the. Element of syntax accuracy does not work.

• Unit to the Format string

  Hi all

  If a control already has a unit, and move us to a format based on the string, its does not display is not the same exact unit. For example, under control has 'g' unit, while the format string has unit "kg".

  

  1. Is it possible to do the format to a string take the exact unit specified in the control?
  2. Is there a way to delete unit in the format based on the string, even if the digital order entry has a specified unit?

  Attachment VI to 2010.

  Thank you

  Knockaert

  Not automatically, no. The problem is that the designation of the unit in effects only control how data is displayed in a particular control. When wire you a value with units in a format to the node of the chain, it will express the value of the base unit for the wire.

  Mike.

• problems by analyzing a date format string...

  Hi all, I'm having a hard time to convert a date into a string.
  
  I was using to_char but after much research, I thought that it would be better to use convert so I do:
  
  SELECT CONVERT (VARCHAR (8), 'November 19, 2012', 112) twice;
  
  Where the specifications for 112 is YYYYMMDD but I get the error "ORA-00936: lack of expression ', guess is cause Oracle do not know how to read the string to be converted.
  
  How can I convert a YYYYMMDD string format string of the form dd mmm yyy (as described above)?
  
  Thanks in advance,

  It seems that your search will lead you to a SQL Server thread. SQL Server uses arbitrary numbers to represent date formats. Oracle does not - the number 112 is irrelevant for Oracle.

  In Oracle, you convert a date to a string using the function TO_CHAR

  SELECT to_char( date '2012-11-19', 'YYYYMMDD' )
    FROM dual
  

  Of course, this assumes that you start with a date (like I do with my date literal). If you start with a string representing a date and you want to convert it to a string that represents the same date in a different format, you will need to use a TO_DATE and a TO_CHAR to convert the original string to a date and date on another string

  SELECT to_char( to_date( '19 Nov 2012', 'DD Mon YYYY' ), 'YYYYMMDD' )
    FROM dual
  

  Justin

• literal does not format string when collecting in bulk.

  Hello
  should work with 10.2 DB.
  

    1  declare
    2    type vcArray is table of varchar2(10);
    3    type vdateArray is table of date;
    4    l_group#   vcArray;
    5    l_status vcArray;
    6    l_date vdateArray;
    7    cursor c is select to_char(sysdate, 'YYYYMMDD_HH24MISS') data, GROUP# , status from v$log;
    8  begin
    9  open c;
   10  loop
   11     fetch c bulk collect into l_date, l_group# , l_status;
   12     for i in 1..l_date.count
   13     loop
   14      dbms_output.put_line('l_date: ' || l_date(i));
   15     end loop;
   16     exit when c%notfound;
   17  end loop;
   18  close c;
   19* end;
  declare
  *
  ERROR at line 1:
  ORA-01861: literal does not match format string
  ORA-06512: at line 11

  Just try to display loop a few output of v$ log view :).
  Concerning
  GregG

  Hello

  GregG says:
  Hello
  should work with 10.2 DB.

  1  declare
  2    type vcArray is table of varchar2(10);
  3    type vdateArray is table of date;
  4    l_group#   vcArray;
  5    l_status vcArray;
  6    l_date vdateArray;
  7    cursor c is select to_char(sysdate, 'YYYYMMDD_HH24MISS') data, GROUP# , status from v$log;
  8  begin
  9  open c;
  10  loop
  11     fetch c bulk collect into l_date, l_group# , l_status;
  12     for i in 1..l_date.count
  13     loop
  14      dbms_output.put_line('l_date: ' || l_date(i));
  15     end loop;
  16     exit when c%notfound;
  17  end loop;
  18  close c;
  19* end;
  declare
  *
  ERROR at line 1:
  ORA-01861: literal does not match format string
  ORA-06512: at line 11
  

  Just try to display loop a few output of v$ log view :).
  Concerning
  GregG

  To_char, as the name suggests, returns a VARCHAR2, c.data is therefore a VARCHAR2, but you try to store it in an array of DATEs.
  Do not use TO_CHAR. In fact, there is no need to use a column for that at all, because SYSDATE will always be the same.

  Try something like this:

  declare
      type vcArray is table of varchar2(10);
      l_group#   vcArray;
      l_status vcArray;
      cursor c is select GROUP# , status from v$log;
      run_time DATE;
    begin
    open c;
    loop
       run_time := SYSDATE;
       fetch c bulk collect into l_group# , l_status;
       for i in 1..l_group#.count
       loop
        dbms_output.put_line('run_time: ' || run_time);
       end loop;
       exit when c%notfound;
    end loop;
    close c;
  end;
  /
  

  Published by: Frank Kulash on 12 March 2012 10:26
  Added example.

• SQLERRM: ORA-01861: literal does not match the format string

  Here's what I want to do.
  
  Select to_char (to_date (estimatedshipdate, 'DD-MM-AA'), 'YDDD')
  of cram_stg
  where estimatedshipdate = 14 January 11 ';
  
  TO_CHAR (TO_DATE(ESTIMATEDSHIPDATE,'MM-DD-YY'), 'YDDD')
  -----------------------------------------------------
  1014
  
  
  1 selected lines
  
  
  I want to convert the shipping date is DD-MM-AA YDDD, but in my program:
  
  v_est_ship_date varchar2 (10);
  
  ESTIMATEDSHIPDATE VARCHAR2 (10) in a TABLE
  
  v_est_ship_date: = to_char (to_date (CRAM_PTCLICK_REC.estimatedshipdate, 'DD-MM-AA'), 'YDDD');
  
  I get this problem
  
  SQLERRM: ORA-01861: literal does not match the format string
  
  
  I want to assign the result of the function to_char to v_ext_ship_date. What I am doing wrong? Thank you.

  Hello

  It's just one of the reasons for which the storage of dates as VARCHAR2 columns is a bad idea.
  Apparently, some (maybe just one) this column values is not the right format. To find malformed (the kind that cause the ORA-01861) values, you can do something like this:

  SELECT  primary_key
  ,     estimatedshippingdate
  FROM     cram_stg
  WHERE     TRANSLATE ( estimatedshippingdate
              , '012345678'
              , '999999999'
              ) != '99-99-99'
  ;
  

  It intercepts any mistakes as the 32nd day of the month (let alone ' 02-29-11'). See the next thread of a way to do this:
  Re: How to select valid dates only

• Getting ORA-01861: literal does not match format string whith 2 passes DATE

  Not exactly a complete Newbie, but not an expert either but it left me speechless...
  
  I have two DATE columns in two different tables.
  In a select statement I compare these two in the where clause.
  
  ... and
  Table1. Column1 = table2.column1
  
  I then get
  
  ORA-01861: literal does not match the format string (and toad has highlighted the second column)
  
  I made a selection on the two tables to have a look at the values and found that, the values in a table (Toad), has this format: YYYYMMDD but in the other select table produces a column of values in the format YYYY-MM-DD
  
  I've made a desc on the two paintings and confirmed that the two are DATE columns...
  
  I've never seen different date formats in the same database... Thinking about it now (I'm home and can not verify) the two tables could be in different schemas... Different schemas can display different date formats?
  
  In any case, I tried to_date ([column] on the two (in the where clause) and got that a nonnumeric value has been found where a numeric value has been planned (this time for the first column).)
  
  So I guess I ask how come two different date formats and how to find the nonnumeric value in table 1 which contains lines of 5.8 million
  
  Any tips/ideas/tips?

  Please check back when you get back to work... I can almost guarantee you that one (if there is not both) of these columns is NOT a data type DATE (or timestamp).

  Or if they are, you are actually handled in a view or query to convert to this type of data.

• Failed to run backup using the format string

  Hi all
  
  Need help with RMAN, my problem as below:
  
  RMAN > run {}
  2 > level 1 incremental backup cumulative
  3 > format "D:\ora\rmanbackup\RCKLGC_INC < % s: T: %p % _ > .dbf.
  4 > tag data base 'DAILY_DATAFILES ';
  {5 >}
  
  From backup 29 June 09
  allocated channel: ORA_DISK_1
  channel ORA_DISK_1: SID = 145 type device = DISK
  channel ORA_DISK_1: starting from compressed data file backup set incremental level 1
  channel ORA_DISK_1: specifying datafile (s) in the backup set
  Enter a file 00005 name = E:\ORA\ORADATA\RCKLGC\MGMT = datafile number. DBF
  Enter a file name 00002 = E:\ORA\ORADATA\RCKLGC\UNDOTBS01 = datafile number. DBF
  Enter a file name 00006 = E:\ORA\ORADATA\RCKLGC\MGMT_ECM_DEPOT1 = datafile number. DBF
  Enter a number of file datafile = 00001 name = E:\ORA\ORADATA\RCKLGC\SYSTEM01. DBF
  Enter a number of file datafile = 00003 name = E:\ORA\ORADATA\RCKLGC\SYSAUX01. DBF
  Enter a file name 00007 = E:\ORA\ORADATA\RCKLGC\DATAFILE\O1_MF_RMAN_DAT_4M9QWZT5_ = datafile number. DBF
  Enter a number of file datafile = 00004 name = E:\ORA\ORADATA\RCKLGC\USERS01. DBF
  channel ORA_DISK_1: starting piece 1 to 29 June 09
  RMAN-00571: ===========================================================
  RMAN-00569: = ERROR MESSAGE STACK FOLLOWS =.
  RMAN-00571: ===========================================================
  RMAN-03009: failure of the backup command on the channel ORA_DISK_1 at 2009-06-29 18:20:49
  ORA-19504: cannot create the file '< _1097:20090629:1 > D:\ORA\RMANBACKUP\RCKLGC_INC. DBF. "
  ORA-27040: create file error, cannot create the file
  04002 - OSD: could not open the file
  S/O-error: (123 OS) the file name, directory name or volume label syntax is incorrect.
  
  ----------------------------------------
  
  If I set the format by default %U work string. Can someone help me? The sting of format I used on the database under Linux works fine without any problems.

  Hi faisal.badrom,
  Can you be more specific on the 'format string to meet backup requirement standards "?
  Are you allowed to jump ">".< :"="">
  If you can use:

  format 'D:\ora\rmanbackup\RCKLGC_INC_%s_%T_%p.dbf '.

  Or to extend it again with the name of the database:

  format 'D:\ora\rmanbackup\RCKLGC_INC_%s_%T_%p_%d.dbf '.

  to meet the standard?

  Kind regards

  Tycho

  Edited by: tychos on June 30, 2009 01:33

• Transform a string that displays hex data in normal format, in a string that has the same data in hexadecimal format

  I have a string of arbitrary length - say, 1AB1C0 - normal format. I would like to have a function that takes this string in and generates the same accurate, but in hexadecimal characters. If the entry will read 1AB1C0 in the normal string format, and the output will read 1AB1C0 as a hexadecimal string.

  I'm doing this because I found that the terminal works better if I send the bytes string hexadecimal vs as an array of U8. Furthermore, I handle a lot of byte stream in my program and I find the chain tools less cumbersome to use against the array of bytes to analysis of analysis tools - however, they operate only on strings as they appear in normal mode. So I have reasons in different parts of my program to have the channel under conditions normal vs formats hexadecimal; but I can't understand anyway elegant remotely to cast from one to the other.

  CraigRem wrote:

  If the entry will read 1AB1C0 in the normal string format, and the output will read 1AB1C0 as a hexadecimal string.

  Well, you must sweep the bytes of the string formatting hexagonal two at a time for a digital U8 and then cast to a string. There are several ways to do it, here are the two possibilities. (Sure to use the correct representation as Mkae labels).

  

  (I still don't understand your reasoning why you need).

• How can I convert a string of hexadecimal values to a string in hexadecimal format programmatically?

  Is there a way to convert a string in the following format:

  1400010107070D0305006A01...           ('Normal view' string)

  by programming to:

  1400 0101 0707 0D 03 05006A 01...      (Striing "Hex display")

  I need to calculate a CRC16 value.

  See attached screws

  Thank you.

  Here is exactly what we have suggested.