How bitmap development give the coordinates?

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• is it possible to tell me how I can make program in labview that take black and with image pixels and give the coordinates of black or white pixels again to me.

  Hello everyone

  is it possible to tell me how I can make program in labview that take black and with image pixels and give the coordinates of black or white pixels again to me.

  It depends on the image and the module LabVIEW available to you. LabVIEW can open bitmap and png files and convert them into tables: if it's really a monochromatic (depth of 1 bit) you get a table 2D boolean, T for white, F for black. Just look at the index of the item to its details (don't forget that LabVIEW does not use the order of rows and columns, so you must transpose and reflect the table). If you have a 24 bit bitmap, the table will contain the color in hexadecimal synthesis (000000 for black, FFFFFF is white and so on); Yet once, you simply check if the element of the array correspond to your requirements and get its index.

  With the vision that you module con open other pictures and perform advanced on them without convert them into tables. Anyway, you can just type the extension of your image using LabVIEW and see what you get.

  Here is a code snippet to open a monochromatic image

  

• How do develop you the whole structure in windows eaployer

  How do develop you the whole structure in windows eaployer

  Hello

  See the following articles:

  How to customize the Windows Explorer views in Windows XP

  Description of the Simple in Windows XP folder view

• How can I give the permission to open the files after a complete transfer of an MBA

  I transferred my old macbook 2008 an MBA from 2014 and user files cannot be opened because I do not have permissions. How can I give permission - I'm the admin.

  The usual way to transfer content to a new Mac is to use the installation wizard: move your content to a new Mac - Apple Support. Which warp any permissions issue that can come from other file transfer methods.

• How do I give the answers of my modem in a VI after each command that I send it so that I can see and document his actions?

  Hello colleagues LabVIEW'ers!

  I created a program that will interview a modem which is connected to the serial port on my pc.  I use the VISA starting functions by the serial port set it up and then I plugged into the function WRITE, then the BYTES to the PORT, then the READ function and finally the CLOSE function.  The problem statement is as follows:

  ~ How do they give answers of my modem in the VI after each command, I send it so I can see his actions and ultimately to report query out of it?

  Furthermore, I don't know if my commands syntax is correct.  Otherwise, I used a program called cygwin interface and a single command, I used is "ssh root@"ipaddress"[enter] This brings me to my modem connection control.  The cygwin command syntax would work with my labVIEW VI? If not, then how can I know what the command syntax to use to query my modem to LabVIEW?

  Additional information

  Modem - modem Satellite 'Evolution '.

  Version of LabVIEW - Professional 8.6.1

  Method of communication - Serial Port

  I appreciate all the assistance of those to receive, and I also hope that responses to this question are many who come through it.

  It seems that you have some apples and oranges here. Cygwin is a Linux for Windows environment. It gives you a bit of Linux look-and-feel in Windows. SSH is a secure, shell, which is a network protocol, not RS - 232. The serial port is a different interface. It may or may not have the same commands that you use on ssh - the manual will tell you that.

  Regarding the serial interface that you want to do, it looks like you want to just do something like what did the old LVTerm . You can give that VI a test to see if it does what you want.

• How can I get the coordinates of the using block (TextFrame) text me please!

  MyApp as new Illustrator.Application Dim
  As Illustrator.Document Dim MyDoc
  myDoc = myApp.ActiveDocument
  Dim textRef = myDoc.TextFrames.Add

  
  For each ArtPageItems in myDoc.PageItems

  
  If TypeName (ArtPageItems) = "TextFrame" Then

  "=It is necessary to get the coordinates of the text block and to get closer to the subject (ie the text)="

  On the other
  End If
  Next

  for details of do

  If TypeName (ArtPageItems) = "TextFrame" Then

  x = ArtPageItems.Left

  y = ArtPageItems.Top

  On the other

• Follow the sliders on 4 screens 2D in SIGHT - but how can I get the coordinates to display for each instead of just the active screen

  If DIADEM will bother to follow the cursor on all pages in a journal, I think that there is a NON-SCRIPT way to view the values of Y for all.

  My graphics are aligned to the x-axis (couple), 4 - poster (1 for each rpm, HP, power and efficiency), and 2D 10 parcels on each of 4 screens in DIADEM 2010.

  Shows that the box show the active screen coordinates and others are grayed out.  I played a bit with the "cursor settings", but which generates the same although I add appears in the dialog box "coordinated".  I guess it may have something to do with making it automatic, but I see no way to change this and how I assign it to a channel?

  On another note, I want to be able to synchronize all 4 graphs to be on the same plot (legend) track above and read the same data.  So if parcel 1 is selected in the display of RPM, then the other, three will also be on field 1.  I guess it had to be done programmatically, but if not, I'm all ears.

  Hi Tweedy-

  No, you cannot use the .NET code directly in tiara.  I don't know what is the point in suggesting it, because it would require a significant change to be able to use a similar code in DIAdem.

  Have you tried to use the legends of the VIEW?  Expand the legend for each graph, and then double-click the legend, how you can configure what information is displayed on each curve.  By default, the legend displays the name of curve, curve units, X-Position (the cursor) and (the slider) Y-Position.  Do not hesitate to complete or the contract depending on your preference.

  After having developed each legend, switch to slider Curve and you should be able to see the Y Position of each curve, fully synchronized.

  

• How can I give the entire Muse site to the customer.

  My images for a site of Muse are scattered all over my computer. How can I save everything in a folder to give my client computer to continue. Any help would be appreciated.

  I think the question is obvious, from the typical users of Muse : they put all kinds of files, also Photoshop files. So the problem is mainly on things which are 'before' available to the Muse , not after.

• How can we give the values of the variable

  Oracle Forms6i
  
  Hai All
  
  I'm generating a daily presence on the teams. In what I wrote an ifelse condition it work successfully and but he gets only 350 line on 800.
  
  I declared a variable and I need to know how to assign values to the variable Pls tell the steps to follow. I did it correctly, but there is a logic error in my code. Let give me a few steps to solve the problem
  
  My code is
  
  declare
  t_in varchar2 (25);
  t_out varchar2 (25);
  
  cursor cur_test is
  Select * from dail_att where intimate = t_in and outtime = t_out;
  -in t_in, t_out dail_att;
  
  Start
  loop
  go_block ('TEST_SRI');
  PREMIER_ENREGISTREMENT;
  
  If: bartime between 0145 and then 0630
  Update dail_att set = outtime: bartime where barcode =: bar code
  and ATTEND_DATE =: bardate-1 and intimate are zero and outtime is not null;
  elsif: bartime between 0630 and 0900 or: bartime between 1130 and 1230 or
  : bartime between 1700 and 1800 and t_in is null then
  insert into dail_att(barcode,intime,attend_date)
  values(:Barcode,:Bartime,:bardate);
  
  elsif: bartime > 1645 and t_in is not null and t_out is null then
  Update dail_att set = outtime: bartime where barcode =: bar code
  and ATTEND_DATE =: BARDATE and respondent are not null and outtime has the value null.
  
  end if;
  WHEN THE OUTPUT: SYSTEM. LAST_RECORD = "TRUE" OR: BAR CODE IS NULL;
  NEXT_RECORD;
  END LOOP;
  forms_ddl ('commit');
  exception
  while others then
  forms_ddl ('rollback');
  message(SQLERRM|| dbms_error_Text);
  message(SQLERRM|| dbms_error_Text);
  end;
  
  
  Concerning
  
  Srikkanth.M

  use you make of your variables t_in and t_out I guess you want before loading with the values they have in the current row of the cursor... I tried to offer you a way to assign a value to your [another post | http://forums.oracle.com/forums/thread.jspa?threadID=1019382&tstart=15]... see if this helps

  Kind regards

  Luca

• UB12: When I create a part, how can I give the 3D appearance a ring shape (coil)?

  Hello

  My circuit uses a custom coil: 12.13 mm outside radius, inside radius 11,13 mm, height 1. 00 mm.  I tried to make this shape in UB by drawing a circle of radius of 11.63 mm with a thickness of 1 mm.  Then in the 3D settings, I did the height of offset 0mm and 1 mm.  This gave me an object round solid with good height and diameter.  I figured out that if i select Create hole, it will create a depth in the center of the diameter of the circle.

  So, I did a turn on the 3D layer with the same RADIUS as the inner radius of the coil.  I put that to create holes.  The I made another circle on the 3D layer with a radius of RADIUS outside of the coil and solid to define.   Then I selected the two circles and looked at the tab 3D of the Properties dialog box.  I again had a solid object.  How can I be subject to smaller radius with the hole in it the RADIUS substitution more large object without a hole in it, then it is combined a form of ring?

  Or, there may be a better way to make this form of ring?  Of course, this reel surrounds a bunch of components on a PCB, so when you are finished, the 3D view of the coil to "reveal" details on the circuit board in the center of the coil (components, printing, etc.).

  Hi,

  I don't know if that's what you want to do, but take a look at the attachment.  I placed two circles on the 3D layer, 12.13 mm and the other for 11,13 mm.  The inner circle, I put the size equal to the outside circle and I checked the option box 'hole', also on the "Hardware" tab, I did the color of the inner circle that is different than the outer circle.  When you look at the 3D preview, this part looks like a ring.

  When you open my file, click the componnet and select change > implementing change to show what I did.

• How to develop all the rows of the table of the tree when the page loads?

  Hi all

  I have tree than VO mere reference of table... I want to expand all table tree rows when the page loads... I already have initially developed property to true... but it only runs from first line of tree...

  Any help would be great-Jey

  In the backbean and that:

    private RowKeySetTreeImpl ps = new RowKeySetTreeImpl(true);
  
    public void setPs(RowKeySetTreeImpl ps)
    {
      this.ps = ps;
    }
  
    public RowKeySetTreeImpl getPs()
    {
      return ps;
    }
  

  In the jspx set table tree as disclosedRowKeys

• How they simply give the rotoscoped object?

  For the first time, using AE. Need for beautiful smooth cut human composite on BG.

  Learned how to get my mov in, use the Roto brush etc until I see a good clean image layer and composition of windows.

  Go make it and have used lossless and lossless with alpha and get the video full of the original.

  What Miss me?
  Thanks for the basic instructions!

  Patrick

  Select the transparency option from view in the comp window. You should see a checkerboard background. Now, make sure that the active camera is selected. now rendered using the lossless with Alpha predefined in the queue made. If bring you the film made in After Effects, it will have a transparent background. If you watch the movie in any media player, they will have a black background because it's players normal.media does not understand and use alpha channels.

• How can I get the coordinates in the coordinate system of the layer by the iterate?

  I found the function iterate position(x,y) tell me isn't fair sometimes.

  In fact, it happens when the upper part of the layer is negative. The 'y' is in the system(maybe?) of coordination model but not the layer. In a Word, the position with y = 0 is not the top.

  
  

  Specifically, I had the card of the color of a layer. I am able to get the color of each pixel in the layer. But I can not set the color for one when I use 'Browse', because there is a lag.

  
  

  Am I supposed to get the offset? Is it possible to directly access the whole layer if I use an iteration function?
  

  Therefore the offset in game indeed.

  AE will decrease the buffer increments of 20% and not for every pixel that

  going out of sight. It is not really related to the upper left corner,

  It's all about what part of your layer buffer is not visible.

  There is also a 'iterate the shift feature. Check it out. Perhaps it will be

  save you a few difficulties.

  Friday, December 19, 2014 at 2:45, Hinanawi Tenshi [email protected]>

• Drop-down menu in the table of cells - how to develop across the width of column?

  Hello!

  A customer migrate their 2 400 forms of old JetForms as PDF (LiveCycle Designer) and would like to keep the same functionality, so that it is used in the old platform. However, some of the old tool features do not seem to be present in LiveCycle.

  Suppose that a drop down menu in a table cell, containing the elements whose lengths are larger than the column of the table. In JetForm, when you open the drop-down menu that spans the columns to display all of its content, do not cut the contents of the drop-down list.

  I tried this in LiveCycle, but the drop down menu gets cut and its content is limited to the column in the table (where the drop-down menu below) width.

  Is there a way to bypass this limitation, even if I use scripts?

  Thank you for all the ideas!

  Marcos

  Hi Marcos,

  I don't think you will get this works reliably in a table

  Niall

• How to obtain the coordinates of the cursor in a field in 3D?

  I have a land in 3D with discrete points. The cursor is indicated and broken so that I can move the cursor to select a point to the nearest point. I was wondering how can I get the coordinates of the cursor in the 3D plot so that I can point to the point (change the size or shape) which the cursor is located. I wasn't able to find coordinates using nodes property. Any suggestions will be appreciated. Thank you.

  Xueliang

  Is this working from home?

  This thread offers advice for hwo to use 3d graphics.

  http://forums.NI.com...=161218#M161218

  This an apperntly has an example to enter the values of the slider.

  http://forums.NI.com...=108612#M108612

  Ben