How can I compare the value of column within the COUNT() function?

I want to compare the value of the column within the COUNT() function as below how ever it gives me the error. I want to calculate the percentage, how can I do this task?
Thank you.


SELECT department_id
, COUNTY (salary < 250000) / COUNT (*)
OF plch_employees
GROUP BY department_id
ORDER BY department_id;
SELECT  department_id.
        COUNT(CASE WHEN salary < 250000 THEN 1 END) / COUNT(*)
  FROM  plch_employees
  GROUP BY department_id
  ORDER BY department_id
/

SY.

Tags: Database

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