How extracted records where the "COUNT (Col1) > 1.

Similar Questions

• Drawing from records where the number of records of unique ID > = 6

  I have a table that contains the address information for everyone in the system. It has many areas, although I have included only a few in the create table query below for brevity. The PIDM uniquely identifies each record as belonging to a person especially in the database. A person can have multiple addresses in the table, although normally, we do not allow them to have more than one active address of a particular ATYP_CODE. Yet once again, I do it here for brevity. What I have to do is to shoot all the records for each PIDM, but only when there are > = 6 records by PIDM. The user does not care if the data is rotated (I can do this part if necessary). Pulling on the actual data is not the issue. I just need a little help to find how to get only the records of PIDMs with six or more records in the table. So, according to the sample data below, records for PIDM 12345 and 34567 are those which should be in the output, but those of PIDM 23456 should not.
  

  DROP TABLE SPRADDR;
  
  CREATE TABLE SPRADDR
  (PIDM              NUMBER(8),
   ATYP_CODE     VARCHAR2(2 CHAR),
   STREETLINE1   VARCHAR2(60 CHAR),
   CITY              VARCHAR2(60 CHAR),
   STATE              VARCHAR2(2 CHAR),
   ZIP              VARCHAR2(10));
  
  INSERT INTO SPRADDR VALUES (12345,'PR','1 MAIN','CANFIELD','OH','44406');
  INSERT INTO SPRADDR VALUES (12345,'MA','1 MAIN','CANFIELD','OH','44406');
  INSERT INTO SPRADDR VALUES (12345,'BU','1 MAIN','CANFIELD','OH','44406');
  INSERT INTO SPRADDR VALUES (12345,'PR','2 MAIN','CANFIELD','OH','44406');
  INSERT INTO SPRADDR VALUES (12345,'MA','3 MAIN','CANFIELD','OH','44406');
  INSERT INTO SPRADDR VALUES (12345,'PR','4 MAIN','CANFIELD','OH','44406');
  INSERT INTO SPRADDR VALUES (23456,'PR','1 MAIN','KENT','OH','44240');
  INSERT INTO SPRADDR VALUES (23456,'MA','1 MAIN','KENT','OH','44240');
  INSERT INTO SPRADDR VALUES (23456,'BU','1 MAIN','KENT','OH','44240');
  INSERT INTO SPRADDR VALUES (34567,'PR','1 MAIN','CANFIELD','OH','44406');
  INSERT INTO SPRADDR VALUES (34567,'MA','1 MAIN','CANFIELD','OH','44406');
  INSERT INTO SPRADDR VALUES (34567,'BU','1 MAIN','CANFIELD','OH','44406');
  INSERT INTO SPRADDR VALUES (34567,'PR','2 MAIN','CANFIELD','OH','44406');
  INSERT INTO SPRADDR VALUES (34567,'MA','3 MAIN','CANFIELD','OH','44406');
  INSERT INTO SPRADDR VALUES (34567,'PR','4 MAIN','CANFIELD','OH','44406');
  INSERT INTO SPRADDR VALUES (34567,'PR','6 MAIN','CANFIELD','OH','44406');
  
  COMMIT;

  I would be very happy any help you might be able to provide. I'm sure it's easy, but I've done so far has not worked, and I'm not including the code, I've tried because it is quite fishy and not working do not at all.
  
  Thank you
  Michelle Craig
  Data Coordinator
  Admissions and transfer systems
  Kent State University

  PIDM 12345 and 34567 are those who should.

  Why 12345? It is repeated 6 times where you asked > 6. In any case:

  SQL> select  *
    2    from  (
    3           select  s.*,
    4                   count(*) over(partition by pidm) cnt
    5             from  spraddr s
    6          )
    7    where cnt > 6
    8    order by pidm
    9  /
  
        PIDM AT STREETLINE1     CITY                 ST ZIP               CNT
  ---------- -- --------------- -------------------- -- ---------- ----------
       34567 PR 1 MAIN          CANFIELD             OH 44406               7
       34567 MA 1 MAIN          CANFIELD             OH 44406               7
       34567 BU 1 MAIN          CANFIELD             OH 44406               7
       34567 PR 2 MAIN          CANFIELD             OH 44406               7
       34567 MA 3 MAIN          CANFIELD             OH 44406               7
       34567 PR 4 MAIN          CANFIELD             OH 44406               7
       34567 PR 6 MAIN          CANFIELD             OH 44406               7
  
  7 rows selected.
  
  SQL> select  *
    2    from  (
    3           select  s.*,
    4                   count(*) over(partition by pidm) cnt
    5             from  spraddr s
    6          )
    7    where cnt >= 6
    8    order by pidm
    9  /
  
        PIDM AT STREETLINE1     CITY                 ST ZIP               CNT
  ---------- -- --------------- -------------------- -- ---------- ----------
       12345 PR 1 MAIN          CANFIELD             OH 44406               6
       12345 MA 1 MAIN          CANFIELD             OH 44406               6
       12345 BU 1 MAIN          CANFIELD             OH 44406               6
       12345 PR 2 MAIN          CANFIELD             OH 44406               6
       12345 MA 3 MAIN          CANFIELD             OH 44406               6
       12345 PR 4 MAIN          CANFIELD             OH 44406               6
       34567 PR 1 MAIN          CANFIELD             OH 44406               7
       34567 MA 1 MAIN          CANFIELD             OH 44406               7
  
        PIDM AT STREETLINE1     CITY                 ST ZIP               CNT
  ---------- -- --------------- -------------------- -- ---------- ----------
       34567 BU 1 MAIN          CANFIELD             OH 44406               7
       34567 PR 2 MAIN          CANFIELD             OH 44406               7
       34567 MA 3 MAIN          CANFIELD             OH 44406               7
       34567 PR 4 MAIN          CANFIELD             OH 44406               7
       34567 PR 6 MAIN          CANFIELD             OH 44406               7
  
  13 rows selected.
  
  SQL>  
  

  SY.

  Published by: Solomon Yakobson on 10 may 2012 10:02

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• Select only records where the column values are not all equal to zero

  Hi everyone, it seems so easy, but it has left me speechless on the research in a way that is clean, easy to achieve. I know when someone replies, I'm going to kick me. So, let's assume this is what I have:
  

  with mytable as (
  select 'Type 1' as itemtype, 'JAN' as monthname, 0 as theval from dual union all
  select 'Type 1' as itemtype, 'FEB' as monthname, 1 as theval from dual union all
  select 'Type 1' as itemtype, 'MAR' as monthname, 5 as theval from dual union all
  select 'Type 1' as itemtype, 'APR' as monthname, 1 as theval from dual union all
  select 'Type 1' as itemtype, 'MAY' as monthname, 4 as theval from dual union all
  select 'Type 1' as itemtype, 'JUL' as monthname, 0 as theval from dual union all
  select 'Type 1' as itemtype, 'AUG' as monthname, 0 as theval from dual union all
  select 'Type 1' as itemtype, 'SEP' as monthname, 1 as theval from dual union all
  select 'Type 1' as itemtype, 'OCT' as monthname, 7 as theval from dual union all
  select 'Type 1' as itemtype, 'NOV' as monthname, 1 as theval from dual union all
  select 'Type 1' as itemtype, 'DEC' as monthname, 2 as theval from dual union all
  
  select 'Type 2' as itemtype, 'JAN' as monthname, 0 as theval from dual union all
  select 'Type 2' as itemtype, 'FEB' as monthname, 0 as theval from dual union all
  select 'Type 2' as itemtype, 'MAR' as monthname, 0 as theval from dual union all
  select 'Type 2' as itemtype, 'APR' as monthname, 0 as theval from dual union all
  select 'Type 2' as itemtype, 'MAY' as monthname, 0 as theval from dual union all
  select 'Type 2' as itemtype, 'OCT' as monthname, 0 as theval from dual union all
  select 'Type 2' as itemtype, 'NOV' as monthname, 0 as theval from dual union all
  select 'Type 2' as itemtype, 'DEC' as monthname, 0 as theval from dual
  )
  select
    itemtype,
    sum (case monthname when 'JAN' then theval else 0 end) as JAN,
    sum (case monthname when 'FEB' then theval else 0 end) as FEB,
    sum (case monthname when 'MAR' then theval else 0 end) as MAR,
    sum (case monthname when 'APR' then theval else 0 end) as APR,
    sum (case monthname when 'MAY' then theval else 0 end) as MAY,
    sum (case monthname when 'JUN' then theval else 0 end) as JUN,
    sum (case monthname when 'JUL' then theval else 0 end) as JUL,
    sum (case monthname when 'AUG' then theval else 0 end) as AUG,
    sum (case monthname when 'SEP' then theval else 0 end) as SEP,
    sum (case monthname when 'OCT' then theval else 0 end) as OCT,
    sum (case monthname when 'NOV' then theval else 0 end) as NOV,
    sum (case monthname when 'DEC' then theval else 0 end) as DEC
  from mytable
  group by itemtype
  order by itemtype

  I need an external application around it or something which will select only 'Type 1'... that is, if all months are each equal to zero, do not include the record in the result set.
  
  In summary to get a total of zero is not an option, because I could have-15 and + 15 in different columns, in which case, the recording should be displayed.
  
  Something as simple as... 'not the case (oct = 0 and 0 nov and dec = 0...) at the end is all it seems to me necessary. I thought to add a case for each column clause, but that seems not very effective. Ideas?
  
  Thanks in advance!
  Mark
  
  Edit... I know not what follows will work using the MINUS operator, but my actual query is really huge, and I don't want to have to write it twice...
  {code}
  Select
  ItemType,
  sum (case monthname when "JAN" then Val else 0 end) such as JAN,.
  sum (case when monthname 'FEB', then Val 0 otherwise end) by Feb.
  sum (case when monthname 'MAR', then Val 0 otherwise end) like MARS,
  sum (case monthname when "APR" then Val else 0 end) as APR.
  sum (case when monthname 'MAY', then Val else 0 end) either.
  sum (case when monthname "JUN", then Val 0 otherwise end) as JUN.
  sum (case monthname when "JUL" then Val else 0 end) as JUL,.
  sum (case monthname when "AUG" then Val else 0 end) as AUG.
  sum (case monthname when "MS" then Val else 0 end) as MS.
  sum (case monthname when "OCTS" then Val else 0 end) OCT.
  sum (case monthname when "NOV" then Val else 0 end) as NOV.
  sum (case monthname when 'DEC' then Val else 0 end) as DEC
  FROM MyTable
  Group of itemtype
  
  less
  
  Select
  ItemType,
  Jan, Feb, mar, Apr, may, June, July, August, Sept, oct, nov, dec
  de)
  Select
  ItemType,
  sum (case monthname when "JAN" then Val else 0 end) such as JAN,.
  sum (case when monthname 'FEB', then Val 0 otherwise end) by Feb.
  sum (case when monthname 'MAR', then Val 0 otherwise end) like MARS,
  sum (case monthname when "APR" then Val else 0 end) as APR.
  sum (case when monthname 'MAY', then Val else 0 end) either.
  sum (case when monthname "JUN", then Val 0 otherwise end) as JUN.
  sum (case monthname when "JUL" then Val else 0 end) as JUL,.
  sum (case monthname when "AUG" then Val else 0 end) as AUG.
  sum (case monthname when "MS" then Val else 0 end) as MS.
  sum (case monthname when "OCTS" then Val else 0 end) OCT.
  sum (case monthname when "NOV" then Val else 0 end) as NOV.
  sum (case monthname when 'DEC' then Val else 0 end) as DEC
  FROM MyTable
  Group of itemtype
  )
  where (oct = 0 & nov = 0 and dec = 0 and jan = 0 and 0 = Feb and mar = 0
  apr = 0 and may = 0 and = 0 jun and Jul = 0 and aug = 0 and Ms = 0
  )
  order of itemtype
  {code}
  
  Change again... OK, I guess that I am answering my own question here, but I think that by using a WITH to write the main request once clause and then selecting * twice using the MINUS operator between where the second query is where (oct = 0, etc.) is what I need. If anyone has better suggestions, please let me know! Here's the logic of nickname for what I come up with to date...
  
  {code}
  WITH mainquery as (select all)
  Select * from mainquery
  less
  Select * from mainquery where (oct = 0, nov = 0, etc...)
  {code}
  
  Thanks again!
  Mark
  
  Published by: user455268 on March 1, 2012 19:13
  
  Published by: user455268 on March 1, 2012 19:16

  Hello

  You can do it with a HAVING clause:

  select
    itemtype,
    sum (case monthname when 'JAN' then theval else 0 end) as JAN,
    sum (case monthname when 'FEB' then theval else 0 end) as FEB,
    sum (case monthname when 'MAR' then theval else 0 end) as MAR,
    sum (case monthname when 'APR' then theval else 0 end) as APR,
    sum (case monthname when 'MAY' then theval else 0 end) as MAY,
    sum (case monthname when 'JUN' then theval else 0 end) as JUN,
    sum (case monthname when 'JUL' then theval else 0 end) as JUL,
    sum (case monthname when 'AUG' then theval else 0 end) as AUG,
    sum (case monthname when 'SEP' then theval else 0 end) as SEP,
    sum (case monthname when 'OCT' then theval else 0 end) as OCT,
    sum (case monthname when 'NOV' then theval else 0 end) as NOV,
    sum (case monthname when 'DEC' then theval else 0 end) as DEC
  from mytable
  group by itemtype
  HAVING      MIN (theval)     != 0
  OR      MAX (theval)     != 0
  order by itemtype
  ;
  

  If the values are all 0, then the MIN and MAX will be 0.
  If the MIN or MAX is not 0, the values are all 0.

  This assumes that the combination (itemtype, monthname) is unique, because it is in your sample data.
  If this is not the case, start with a subquery that GROUPs BY itemtype, monthname, so that when you get to the main request, this combination will be unique.

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  Hello

  select EMPNO, SAL from EMP
  
  7369     800
  7499     1600
  7521     1250
  7566     2975
  7654     1250
  7698     2850
  7782     2450
  7788     3000
  7839     5000
  7844     1500
  7876     1100
  7900     950
  7902     3000
  7934     1300

  I need to find all the empno all together (sum) is equal in early 2000 by lowest SAL
  IF the sum is below 2000, I can then take an empno, also if, then, the sum will be longer than 2000
  It's
  800 +.
  950 + = 1750
  1100 +.
  = 2850
  I can get the first empno 3 discs = (7369,7900,7876)
  
  If I want to compare with 1750 instead of 2000, I get only two first empno = (7369,7900)
  
  How can he do?
  
  Thanks in advance

  SQL> select empno, sal
    2    from (
    3  select empno, sal, sal1, nvl(lag(sal1) over(order by sal),0) lsal
    4    from (select EMPNO, SAL, sum(sal) over(order by sal) sal1 from EMP))
    5  where lsal <2000
    6  /
  
       EMPNO        SAL
  ---------- ----------
        7369        800
        7900        950
        7876       1100
  
  SQL> select empno, sal
    2    from (
    3  select empno, sal, sal1, nvl(lag(sal1) over(order by sal),0) lsal
    4    from (select EMPNO, SAL, sum(sal) over(order by sal) sal1 from EMP))
    5  where lsal <1750
    6  /
  
       EMPNO        SAL
  ---------- ----------
        7369        800
        7900        950
  

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