How to associate a lov level requires a default value of default UI.

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• How to disable the LOV values based on the State of some?

  Hello

  I have a requirement like this.

  (1) LOV Field (1), when I get a value here then based on the query I get two new values and assign to another two LOV Fields (2,3) and then disable them. However, when I enter the value in the field LOV (1) based on one of the conditions I won't have no default value then LOV fields must be enabled so that the user can select the values of LOV.

  (2) now an another LOV domain (4) when I go here again, then again two fields a LOV (5), and the free text field must be filled in.

  To do this, I wrote the logic in the following way:

  (1) get the LOV box-1 value and deriving the new values and set the session Variable to 1 and then refresh the Page. Now in PR get the Variable from Session 1 and assigning new values to LOV fields 2 and 3 and then using the property Setdisabled I deactivation.

  (2) getting the value of LOV field-4 and then drifting two new values and set the session Variable-2 and refresh the Page. Now in PR get Session-2, and then set the new values for the LOV-5 field and free text. But once the Page Refreshed and assigning values, values that we have given in the Point 1 in the LOV-2 fields, 3 turn white and field's get activated.

  Can you please let me how to achieve this? and also why the values are empty when I implement Point-2.

  Thank you
  Clarriiza

  Clarriiza,

  This VO have no matter what right SQL query, so even if you run the VO by using vo.executeQuery (), you will not get all the lines in the VO.

  So in the PR you need createRow and insert VO (otherwise your page no mistake) the below blog can be considered as an example.

  Reference: Oracle tips of Johny: OAF: how to create a PVO and use for Spel link in Oracle Application Framework

  On top of which is explained in the blog above, you set the values for the attributes of the useful, likely to set the value for the other LOV.

  I hope this helps.

  See you soon

  AJ

• How to calculate what bandwidth is required for a site of Dataguard

  Hello
  
  We are running 11 g R2 RAC two nodes on windows 2008 R2 servers. We intend to build Dataguard site with the plug of the same or higher. For this reason, could someone please let me know that, how can I calculate the bandwidth required for site-based dataguard
  
  activity in our production environment? Is there any kind of method to help I can calculate the requirment of current bandwidth for my database of production in Mbps?
  
  Any help would be appreciated!

  Handle: 53637
  Status level: Rookie (25)
  Join date: June 26, 2003
  Messages total: 559
  Total issues: 61 (46 pending)
  Name shan
  Rental Australia
  Consultant Oracle occupation

  Also, try to close your message please

• How to find the child level for each table in a relational model?

  Earthlings,
  
  I need your help, and I know that, "Yes, we can change." Change this thread to a question answered.
  
  So: How to find the child level for each table in a relational model?
  
  I have a database of relacional (9.2), all right?
  

  .
       O /* This is a child who makes N references to each of the follow N parent tables (here: three), and so on. */
      /↑\ Fks
     O"O O" <-- level 2 for first table (circle)
    /↑\ Fks
  "o"o"o" <-- level 1 for middle table (circle)
     ↑ Fk
    "º"

  Tips:
  -Each circle represents a table;
  -Red no tables have foreign key
  -the picture on the front line of tree, for example, a level 3, but when 3 becomes N? How is N? That is the question.
  
  I started to think about the following:
  
  First of all, I need to know how to take the kids:

  select distinct child.table_name child
    from all_cons_columns father
    join all_cons_columns child
   using (owner, position)
    join (select child.owner,
                 child.constraint_name fk,
                 child.table_name child,
                 child.r_constraint_name pk,
                 father.table_name father
            from all_constraints father, all_constraints child
           where child.r_owner = father.owner
             and child.r_constraint_name = father.constraint_name
             and father.constraint_type in ('P', 'U')
             and child.constraint_type = 'R'
             and child.owner = 'OWNER') aux
   using (owner)
   where child.constraint_name = aux.fk
     and child.table_name = aux.child
     and father.constraint_name = aux.pk
     and father.table_name = aux.father;

  Thought...
  We will share!
  
  Thanks in advance,
  Philips
  
  Published by: BluShadow on April 1st, 2011 15:08
  formatting of code and hierarchy for readbility

  Have you looked to see if there is a cycle in the graph of dependence? Is there a table that has a foreign key to B and B has a back of A foreign key?

  SQL> create table my_emp (
    2    emp_id number primary key,
    3    emp_name varchar2(10),
    4    manager_id number
    5  );
  
  Table created.
  
  SQL> ed
  Wrote file afiedt.buf
  
    1  create table my_mgr (
    2    manager_id number primary key,
    3    employee_id number references my_emp( emp_id ),
    4    purchasing_authority number
    5* )
  SQL> /
  
  Table created.
  
  SQL> alter table my_emp
    2    add constraint fk_emp_mgr foreign key( manager_id )
    3         references my_mgr( manager_id );
  
  Table altered.
  
  SQL> ed
  Wrote file afiedt.buf
  
    1   select level lvl,
    2          child_table_name,
    3          sys_connect_by_path( child_table_name, '/' ) path
    4     from (select parent.table_name      parent_table_name,
    5                  parent.constraint_name parent_constraint_name,
    6                  child.table_name        child_table_name,
    7                  child.constraint_name   child_constraint_name
    8             from user_constraints parent,
    9                  user_constraints child
   10            where child.constraint_type = 'R'
   11              and parent.constraint_type = 'P'
   12              and child.r_constraint_name = parent.constraint_name
   13           union all
   14           select null,
   15                  null,
   16                  table_name,
   17                  constraint_name
   18             from user_constraints
   19            where constraint_type = 'P')
   20    start with child_table_name = 'MY_EMP'
   21*  connect by prior child_table_name = parent_table_name
  SQL> /
  ERROR:
  ORA-01436: CONNECT BY loop in user data
  

  If you have a cycle, you have some problems.

  (1) it is a NOCYCLE keyword does not cause the error, but that probably requires an Oracle version which is not so far off support. I don't think it was available at the time 9.2 but I don't have anything old enough to test on

  SQL> ed
  Wrote file afiedt.buf
  
    1   select level lvl,
    2          child_table_name,
    3          sys_connect_by_path( child_table_name, '/' ) path
    4     from (select parent.table_name      parent_table_name,
    5                  parent.constraint_name parent_constraint_name,
    6                  child.table_name        child_table_name,
    7                  child.constraint_name   child_constraint_name
    8             from user_constraints parent,
    9                  user_constraints child
   10            where child.constraint_type = 'R'
   11              and parent.constraint_type = 'P'
   12              and child.r_constraint_name = parent.constraint_name
   13           union all
   14           select null,
   15                  null,
   16                  table_name,
   17                  constraint_name
   18             from user_constraints
   19            where constraint_type = 'P')
   20    start with child_table_name = 'MY_EMP'
   21*  connect by nocycle prior child_table_name = parent_table_name
  SQL> /
  
         LVL CHILD_TABLE_NAME               PATH
  ---------- ------------------------------ --------------------
           1 MY_EMP                         /MY_EMP
           2 MY_MGR                         /MY_EMP/MY_MGR
           1 MY_EMP                         /MY_EMP
           2 MY_MGR                         /MY_EMP/MY_MGR
  

  (2) If you try to write on a table and all of its constraints in a file and do it in a valid order, the entire solution is probably wrong. It is impossible, for example, to generate the DDL for MY_EMP and MY_DEPT such as all instructions for a table come first, and all the instructions for the other are generated second. So even if NOCYCLE to avoid the error, you would end up with an invalid DDL script. If that's the problem, I would rethink the approach.

  -Generate the DDL for all tables without constraint
  -Can generate the DDL for all primary key constraints
  -Can generate the DDL for all unique key constraints
  -Can generate the DDL for all foreign key constraints

  This is not solidarity all the DOF for a given in the file object. But the SQL will be radically simpler writing - there will be no need to even look at the dependency graph.

  Justin

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  Follow these steps to delete the recorded data (form) in a drop-down list:

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• How can I check the levels of ink on deskjet 2050 on Windows 8?

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  If you do not have the full features software download and follow HP printer Installation Wizard to obtain and install the latest version of the software automatically:

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  I have a BB Curve 9300.

  epiczizi wrote:

  Hello

  my Blackberry is stuck on BBM how to associate your Blackberry ID and I don't know what to do

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  I have a BB Curve 9300.

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