How to calculate the sum of the values of some columns in a table

Similar Questions

• How to set the value of a column in a table according to another column?

  Hello world!
  
  I use Apex 4.1.
  My question is how can I set the value of a column in a table according to another column?
  I have a table and when I insert the value in the column content, I want to change this value in the note column with the note, which is generated with pl/sql function (function of string returned if the typed value is in the range).
  
  I tried to use javascript as

   $('input[name=f02]').live('change', function(){
  if($(this).val()!='1'){
  $('input[name=f03]').val("test")}
  }); 

  for the development of the column note to test if the value typed in the content of the column is not 1, but this code assigns the value to all the lines and I need to set only the specified line.
  
  Can someone give me a hint in any way to do this if possible?
  
  Kind regards
  drama9346

  You will need create a process on your page type PLSQL and develop this process "we demand" of the page. In this process, you can run the PLSQL you need. That is to say to retrieve the note value as described in your PC:

  and when I insert the value in the column content, I want to change this value in the note column with the note, which is generated with pl/sql function (function of string returned if the typed value is in the range).

  In this process, you must provide a return value of the call, and you can do this by using htp.p. Example:

  DECLARE
     --putting x01 in a var to simplify
     l_test_var VARCHAR2(200) := apex_application.g_x01;
     l_return VARCHAR2(200);
  BEGIN
     -- a simplistic test
     IF LENGTH(l_test_var) BETWEEN 10 AND 20 THEN
        l_return := 'String is between 10 and 20';
     END IF;
  
     --this will write l_return to the buffer, and the ajax callback will receive this
     htp.p(l_return);
  END;
  

  And the code that I wrote above, which is javascript, would need to go where your current code is that binds to the onchange event. The result should be that, when a change is made to this element, an ajax request is made on the server. When the call is finished, it will be the value returned in the item you want.

• How to replace the value of a column in a table based on the value in the second column?

  Hi, I would like to find in a table 2D for values that meet certain criteria (for example, a column< 0.98).=""  based="" on="" which="" rows="" meet="" this="" criteria,="" i="" want="" to="" replace="" the="" values="" in="" a="" different="" column="" of="" the="" array="" (change="" to="" 'nan'="" so="" that="" the="" values="" will="" not="" be="" included="" in="" any="" calculations="" on="" that="" column,="" for="" example="" the="" finding="" the="" mean).=""  i've="" attached="" a="" sample="" .csv="" file.=""  if="" the="" values="" in="" column="" 3="" (index="" 2)="" are="" less="" than="" 0.980="" (or="" some="" other="" user="" defined="" value),="" then="" the="" value="" in="" column="" 2="" (index="" 1)="" should="" be="" replaced="" with="" nan.=""  can="" someone="" help="" out="" with="" this="" search="" and="" replace="">

  Thank you

  Keith

  (using LV 2009 SP1)

  A few quick hits.

  You can merge the two for loops

  You have not need one of the constants 1 and 2 in the index table.  They will solve automatically when you expand on the index picture, once you have wired to 0 in the column index.

  It seems a lot of handling additional table spent unnecessarily.

  See below.  I did not try to duplicate your code to see how it actually works, but I believe that I have attached will give the same result with less steps.

  

• To build the waveform.vi function how to calculate the value of dt

  Dear all

  Please guide me How to calculate the value of dt according to waveform.vi of construction

  My sampling rate is 25000 and I take 200000 samples.

  Kind regards

  Muhammad Irfan

  It's all simple arithmetic. The inverse of the sampling frequency power of samples is then the dt or the time between samples the number of samples is not relevant.

• How to get the value of a column in sql query?

  Hi, anyone knows how to get the value of a column in sql query?

  Here is my code, the value must be 1350079224397 in my PB, but I get 0

  QString query ("SELECT version FROM db_version");

  QVariant result = sda.execute (query);
  QVariantMap versionMap = result.toList () such () .toMap ();
  If (! versionMap.IsEmpty ())
  {
  qDebug()<"Version: "=""><>
  }

  OK, I have the solution

  QString query ("SELECT version as version FROM db_version");

• How to capture the value of type column report

  It would be a great help that you might suggest the following
  
  (i) Java script that I wrote on the standard status column (in a tabular report) fails.
  This happens because of the standard status column, if I use the text field then called Javascript function and showing correct results.
  
  Now, here, I want to know how to capture the value of the column standard report, since javascript fails due to
  the column values of standard report unrecognized.
  
  Example:
  
  Columns of the report as a table:
  ```````````````````
  Standard report column: salary
  TextField report column: new treatment
  Report column standards: difference
  
  I've written the javascript on column New_salary function which returns the value of the salary column to calculate the difference.
  
  For this column of report types, the javascript function does not work, that is to say, it does not show the difference., since it is not read
  the value of the column Salary (which is the Standard type of report column)
  Once I have change the Salary column to text (display as saved state) javascript field works fine.
  
  All entries on how to capture the standard value of the column, so that I can access the value of the javascript function.
  
  Thanks in advance
  Vijay

  Hi Vijay - I had problems with the forum as well (and my workspace OTN so)!

  You have two questions, I think.

  First of all, that the old wage is not an input element, you can not get to it by referring to an ENTRY tag. you will need to change that to something like:

  var s1 = d[k-1].firstChild.nodeValue;
  

  This means that there is nothing else in the cell apart from the text - as in < td > < table > 123. If there is something else there that stops you getting the value using the above, you can go through these nested tags referring to objects further firstChild-

  var s1 = d[k-1].firstChild.firstChild.nodeValue;
  

  As I don't see your page, you need to check yourself to see firstChild how much you need. This example assumes that you had something like: < td > < b > 123 < /b > < table >

  Second, the values of s and s1 are strings. You must convert these numbers to be able to perform calculations. You have two javascript functions to do this: ('string') parseFloat and parseInt ('string'). One contains decimals, the other is not - but know that one is not very accurate (it can change "123.456' in ' 123.455999999995' or something similar - not very good! '").

  So, your calculation should be:

  var diff = parseInt(s) - parseInt(s1);
  

  Andy

• How to extract the values of XMLTYPE column,

  SQL > create table temporary global xmtype_tab (xmlfile xmltype);
  
  SQL > select * from all_directories;
  
  SYS RESTOREDIR/home / / dbimptask /.
  
  insert into xmtype_tab values (xmltype (dbms_xslprocessor.read2clob ('RESTOREDIR ','LAS_SETUP.xml ')));
  
  1 line of creation.
  
  SQL > select * from xmtype_tab;
  
  XMLFILE
  --------------------------------------------------------------------------------
  <? XML version = "1.0"? >
  rowset <>
  < ROW >
  < DATA_CAPTURE_ON > 1 < / DATA_CAPTURE_ON >
  
  
  How to extract the values inside each tag?
  
  
  XML file has the following data...
  
  
  rowset <>
  < ROW >
  < DATA_CAPTURE_ON > 1 < / DATA_CAPTURE_ON >
  < > 9600 BAUD_RATE < / BAUD_RATE >
  < ACK_TIMEOUT > 1 < / ACK_TIMEOUT >
  < TUBE_TRAVEL_LIMIT > 4 < / TUBE_TRAVEL_LIMIT >
  < SEND_SID_TIMEOUT > 1 < / SEND_SID_TIMEOUT >
  < INDEX_Q_TIMEOUT > 2 < / INDEX_Q_TIMEOUT >
  < HW_HANDSHAKING > 1 < / HW_HANDSHAKING >
  < / ROW >
  < / LINES > ';
  
  I use the Oracle 10.2.0.3 version...

  Why does this work?

  You are missing the tag of the ROWSET:

  select extractvalue (xmlfile, '/ROWSET/ROW/BAUD_RATE') baud_rate
    from xmltype_tab
   where existsnode (xmlfile, '/ROWSET/ROW/BAUD_RATE') = 1;
  

• Single request for the display of all, but the values of 1 column for all tables

  Hello
  
  All tables have the column SYS_CREATION_DATE.
  But I don't want to not display the value of this column
  
  Can anyone suggest a way in which I could achieve this?
  
  Oracle version: 11 GR 1 material
  OS: SunOS
  
  
  See you soon,.
  Malika
  
  Published by: user9131570 on July 6, 2010 19:57

  user9131570 wrote:
  @Tubby

  I * table-wise display the values of all but 1 columns (SYS_CREATION_DATE) in my database.*

  I need it to compare to another data base for all these values.

  I would like to make a wild guess at what you are getting.

  In view of these two tables

  create table emp
     (empid number,
      empname varchar2(15),
      empaddr   varchar2(15),
      sys_creation_date date);
  --
  create table dept
     (deptid number,
      deptmgr varchar2(10),
      sys_creation_date date);
  

  you want to combine somehow

  select empid,
           empname,
           empaddr
  from emp;
  

  with

  select deptid,
           deptmgr
  from dept;
  

  in a single sql statement?

• How to calculate the value of the parameter in siebel.

  Hi all
  
  I am new to this world of siebel.
  I want to set the value of my settings.
  How I calculate that which is appropriate and value which is the maximum for the parameters.
  
  
  Thank you

  I assume you mean Max and Max MT Server tasks.

  Please read the following on Supportweb: how to set the parameters of Max and Max MT Server tasks for the object Siebel Manager? [476018.1 ID]

• How to pass the value of a column to a variable to be used in another analysis

  Hello

  I'm on OBIEE 11.1.1.7.1.

  I have the following problem.

  I have DISCOVERED called analysis. It has just a column with the result. Simple. Assume that the answer is 2500

  I have another scan which has two other columns, namely GOLD and LOANS. I want to calculate the total DISCOVERED + GOLD + READY.

  That's why I need to pass the value of 2500 of the first analysis of the second analysis via a variable.

  I can not add all three of them in the same analysis there are various filters for OVERDRAFT, and the application of these filters on the GOLD and LOANS gives the desired result. I tried to add filters in the column of the overdraft, but that doesn't seem to work.

  Any help will be greatly appreciated.

  I'll give you an example. I hope that you will mark for my time...

  Hope that you will be aware of how to combine a similar request.

  in the first criterion you have

  Goldprice Loanamount year 0

  Second criterion

  Year 0 0 Overdraftamount

  the two maintain the necessary filters.

  Add a column of result (option you can see in the topic area pane) that add all three columns. You can choose the columns. formula will come something like below

  saw_1 + saw_2 + saw_3

  Thank you

  AJ

• How to update the table by using the value of a column in a table field

  Hi all
  use APEX4.1,
  I have a tabular presentation based on the HOLIDAY table, it contains the following fields,

  Leave_id
  Employee_name
  No_of_days
  Status

  Here's the column LOV updateable status.
  Lov includes 2 values IE APPROVE and REJECT
  
  and I have another Table called LEAVE_HISTORY, it contains the following fields.

  Emp_name
  status

  Here whenever the ststus is updated (click the button SUBMIT) in tabular form should also be updated in the LEAVE_HISTORY of the SITUATION of the table column.
  
  I tried the following in the process of "WE SUBMIT AFTER CALCULATIONS AND VALIDATIONS,"

  begin
  update LEAVE_HISTORY set status= status where upper(employee_name)=upper(emp_name);
  end;

  but it is not kept up-to-date,
  When we updated through forms we can use something like this,

  update LEAVE_HISTORY set status= :P200_status where upper(employee_name)=upper(:P_200_emp_name);  <----here we are referring page item i.e (:P_200_emp_name)

  as the code above, how to run the columns in a table?
  Thank you.

  Hi Gurujothi,

  Try this,

  begin
  update LEAVE_HISTORY
  set status= :STATUS
  where upper(Emp_name)=upper(:EMPLOYEE_NAME);
  end;
  

  Brgds,
  Max

• How to send the values in a column of "report" instead of a "part of the Page?

  Hello
  
  Here's my case: two pages A and B.
  A page is used to display each employee of a selected service.
  Page B is used to create / modify employees.
  
  I create a button page which redirects to page B.
  By default, page B is empty (from course to fill in the blanks to create a new employee).
  
  However, there are 2 values I want to send to page B (I want to fill in some blanks in advance): the service and the Manager ID ID (there is a Department Manager).
  -I managed with the service ID because it is a page element and in the "Action when click on the button" button I filled "Set these Items"-> agenda of Page B "with the values"-> about a Page A day.
  -I am confused with the ID of eating because it is not a page element, but a report column and there is nothing to do like I did for the service in the button ID to create.
  
  I'm a bit lost cause I don't know how transfer/send this value to the second page.
  
  Do you have any idea?
  
  Thanks again for your time!
  
  BR
  
  Ulrich

  "Cleared Cache to Page 4, when an employee existing is being changed."

  Where did you get that? >

  On page 3, region staff, the report Employee ID attribute

  See Empty the Cache under the link column

  Glad to have helped.

  Jeff

• With CVI SQL Toolkit, how to add the new variable param column in a table.

  Dear all:

  I used the CVI Sql toolkit to create a database, but now I don't know how to add a new column to a table in variable param.

  I know, to add a column with the name of constant column could be down by below:

  DBImmediateSQL ((hdbc, "alter table table1 add column1 char [100]");

  But if Column1 is a param variablae how can I write the code? Please advise?  It will be appreciated if you could give me an example.

  Best regards!

  HI -.

  If you look at the parameters that you pass to the SQL function, you can see that the second parameter is a string constant. In your code, you can create an array of characters (string). You can then use sprintf to programmatically determine what will be the contents of this variable. In the function call, you can put the variable instead of the literal string, and you will have a customizable SQL statement.

  Hope this helps-

  John M

• How to create the partition on a column in a table on a daily basis

  Hi all
  I wrote a query that does not, I have a column of varchar type, and I want to create the partition of the table on that column based daily interval. but ist is in error...
  
  my query is...
  
  create the table user_detail
  (username varchar2 (50))
  The user ID number,
  country varchar2 (25).
  accupation varchar2 (100),
  company varchar2 (100),
  joindate varchar2 (14))
  partition by range (joindate)
  INTERVAL (NUMTOYMINTERVAL (1, 'DAY'))
  (PARTITION newone VALUES LESS THAN (to_date (April 13, 19 ', 'aa-mm-dd')));
  
  
  error is:
  
  Error from the 1 in the command line:
  create the table user_detail
  (username varchar2 (50))
  The user ID number,
  country varchar2 (25).
  accupation varchar2 (100),
  company varchar2 (100),
  joindate varchar2 (14))
  partition by range (joindate)
  INTERVAL (NUMTOYMINTERVAL (1, 'DAY'))
  (PARTITION newone VALUES LESS THAN (to_date (April 13, 19 ', 'aa-mm-dd')))
  Error in the command line: 1 column: 0
  Error report:
  SQL error: ORA-14751: type of invalid data for the partitioning column of a partitioned table interval
  
  
  Can I create partition on the varchar data type?

  On ORA11gR1 it works:

  --virtual column
  CREATE TABLE TEST(joindate VARCHAR2(14), part_joindate AS (to_date(joindate,'dd.mm.yyyy'))) partition by range (part_joindate)
  INTERVAL(NUMTOYMINTERVAL(1, 'YEAR'))
  (PARTITION newone VALUES LESS THAN (to_date('2013-04-19', 'yyyy-mm-dd')))
  ;
  
  INSERT INTO TEST(joindate) VALUES('19.04.2013');
  SELECT * FROM TEST;
  
  DROP TABLE TEST;
  --aux column
  CREATE TABLE TEST(joindate VARCHAR2(14), part_joindate AS (to_date(joindate,'dd.mm.yyyy'))) partition by range (part_joindate)
  INTERVAL(NUMTOYMINTERVAL(1, 'YEAR'))
  (PARTITION newone VALUES LESS THAN (to_date('2013-04-19', 'yyyy-mm-dd')))
  ;
  
  INSERT INTO TEST(joindate) VALUES('19.04.2013');
  SELECT * FROM TEST;
  
  DROP TABLE TEST;
  

  Published by: spajdy on April 19, 2013 14:58

• How to get the name constraintlist and column in a table?

  Hello
  
  
  can someone please tell me how to get the type of constraint, and it is imposed on the names of columns in a table.
  
  
  
  
  Thank you
  Nico

  Hello

  Use the two tables:

  select * from all_constraints
  
  select * from ALL_CONS_COLUMNS
  

  Sorry SY, you were faster than me...

  Published by: user11268895 on August 19, 2010 13:27