How to choose the Department with employees in the same line?
Hello world
I need to make this request,
Suppose we have 2 departments with n used on each Department
I need to select the departments with only 2 employees in the same line, example here
Department | Name of Department | Employee1 | Employee2 |
---|---|---|---|
10 | HUMAN RESOURCES | Marc | Steve |
20 | HE | Paul | |
30 | New Department | ||
40 | Finance | Jean | Michael |
This query below did not work because it only displays the first employee, but I need to display 2 employees (same as the above table)
select deptno, (select ename from emp, dept where rownum =1 and emp.deptno = dept.deptno) employee1, (select ename from emp, dept where rownum = 2 and emp.deptno = dept.deptno) employee2 from dept;
...
I did this, but with the function returning the Emp2Dep1 Emp1Dep1
function get_ename(p_dept number,p_col number) return varchar2 is v_ename varchar2(4000); v_first boolean := true; BEGIN select ename into v_ename from ( select ename, rownum as rn from ( select ename from emp ,dept where emp.deptno = p_dept order by 1 asc ) ) where rn = p_col; return v_ename; END;
and simply put
select get_ename(deptno ,1 ) employee1, get_ename(deptno ,2 ) employee2 from dept;
Is there a better way to do it?
NB: database 11g
Thank you
Select the Department, employee1, employee2
(select Department, name, cnt
(name, department, row_number (select) at the NTC (partition by order of the Department by null)
employees
)
where NTC<=>=>
)
Pivot (max (name) of the cnt (1 as employee1, 2 as employee2))
order by Department
DEPARTMENT | EMPLOYEE1 | EMPLOYEE2 |
---|---|---|
10 | Marc | Steve |
20 | Paul | - |
30 | - | - |
40 | Jean | Michael |
50 | Alpha | Beta |
Concerning
Etbin
Tags: Database
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