How to compare the 3 values in table
Hi all
This is my first post so be tolerant
I need to find "bad values" in the table, it will be easier to explain with example:
I have a table like this: 0 0 0 0 0 0 0 0 5 0 0 0 0<- so="" "5"="" is="" the="" bad="" value,="" my="" method="" is="" to="" check="" two="" of="" nearby="" values="" so="" x(i-1)="0," x(i)="5" x(i+1)="0," and="" if="" checked="" value="" is="" more="" than="" 25%="" bigger="" or="" smaller="" it="" should="" be="" replaced="" by="" average="" of="">->
example: 0 1 2 3 4 9 6 7 8<- bad="" value="" is="" 9,="" and="" result="" of="" my="" filter="" should="" be="" (4+6)/2="">->
I did it using the formula node (not 20% and no way, but the point is the same) and it works but now I want to do without C and I had a lot of problems because of the size of the array memory is 10000.
I joined thah vi and signal, you can test that it works very well
Thank you
Mike
MeeHow wrote:
... What is the problem?
Because the first incorrect value is the point of 2780, because it is also disabled because the average of neighbour is biased by the incorrect value to 2781.
You could jut blindly replace all values with the value that has the lowest absolute value among the three points that we have. Here's a quick project, seems pretty good, but it really depends what you want.
Tags: NI Software
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